1-11 Exercise 3: Prefix of a string

0 like 0 dislike
9.6k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 9.6k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
* * *  *  * **  **   * *   
  *  * ** *  *** *  *  *** ** ***** ***    ** *   **  **
    {
* * **    ** **       * * *** *  *  *  * *  *   **  *** (i=0; i<=strlen(string2)-1;i++)
 * *****  **     *    * ******  * *** *  ** ****  **
 * *   *     * *     ***  *   *  * ** **  *  *  **** ******  * * ****  * *** ****   (string2[i]==string1[i])
**  *   *  * *   **    *    ** *   ***********  *   ******** ***      *   * *****
  *      * ** *** *   *****   ***  **** **   * ****  *  ***** **    *  **      ** *     **       ** ** 
 * ** ****** ****  * *   ***** *** * * ****  **  **   **** ***     ** * **  
 ****  **   ** *  *    *    **  *  ** **  *** **** *** *   
*    * * * **** * *   * **** **** * ** *  * *   ***   *  ****
******   **  **** * *  ** * * **  ** ** * * **      ****
   *  ***   * *  * ** *** ** * * *   *  *       ** * * **   **** *  *** * *  *        *   ** *  is a prefix of %s", string2, string1);
 *** * ***  *      * ** * *   *  *   **** * *   *  * 
   ******* *** *  * *** *** **** *  * **  *    **** **  ***** 
   *  *  ** *  ** **  *     ** *  *  ***     *  *** 
*** *** *   **  * ***** ***** * ***    **   * * *   * ** ****    * * * *    ***  *  ****   *  is not a prefix of %s", string2, string1);
   * *** *      *   ** *     ** * ***   *   *  *** ** *
    }
**      * *            ****      **  * ** **     *      * *
    {
**** * ***  **** * *   *         * *   ***   ** *** (i=0; i<=strlen(string1)-1;i++)
* *  *  *** *** ********** ** ** *   ***  *  **** 
 ***** ** *   * * ****   ***    *     * ** **  *** *    ***  * **  *     (string2[i]==string1[i])
     *  *   **  ***   *  **  ** * **** *    * *  ***  *    *** ***   * **** * ******* ** *
*  *** **   * * ****** * **  * *    ** **  **  *  ** *      * * **** ****  *  **    ******** ***     *  *  *  
*  *  *   *  * ***    * * **   **    ** ***   * ** *   *      *    ** *     ** * ***
*** **      * ***  * *  ***  * *** ** * *** ***   ******
   *******  * *  *  ****   ** *      ***     * ***      *
  *  * ***** **   ***  * *    **  ******     * ** * ***     
    ***** ***   *  *     * ** **     *  **** *    *    *   * ****    *  *     * * ** **  *   is a prefix of %s", string1, string2);
  *   *****  *    ** **** * *     * ****    ****  * ***   *
 *** * **** *   * * *  ***  *   ***  * *   * * **
   ***  ***   **  *     *   *** * ***   ** *  *   ** * 
* **** * * * *   * * * ** *   * *  **** * *  ***** ******** **** *   **   **   **** **  *** ** is not a prefix of %s", string1, string2);
* ** * * **  *** * ****   **    **** ***   *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
*** ** *  * ****     **  *   *      *   %s", chaine1,chaine2);
  **  ** *  **   * *  * *  *  ** ** * * **  *
 **   **  ***  ** * **     * * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
  **  *   * *     ***  ***** lenght1,lenght2,c;
* * ***  * * ** ***      ****      b[100];
     **  ** ** **  * *  *   a[100];
 * *  *    *  * *  ******* **    d[100];
***     ****** *  *  *   **  * *   * ** *** *** * ** *   
 ****  ** * *    * *  ** * **  ** ** *  *** ** *
 ***   * *****   *   ****   **  ** ****
     *****    **  * *   * ** *       **   * *
 ** *  *   ***  **    ***  **  * *  *** ***
 *  *  ** ****** * * **   ** * 
** **     ***   *   *  *** **   *   * ** * * ** * *   is a prefix of %s",a,b);
****  * ** ****    ***** *
    ****** *   * **** *    ** *  
 *** * ** * *  *  *  ***
*** * * *** *  **  *** *** **  *      ******    * ** * **  **** ***  is not a prefix of %s",a,b);
** *    *    *   * *  ****** **
 *  * ** **  ** ** *  * *    * *  **  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include       ** ** *    *
#include **  *  **       *  
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
  **  *     *    i;
****   * * * * *  *    *   *  
  {
*  ** ** **  ** ***   ****** *** *   *  * *  A[i]!='\0' && A[i]!=B[i]   )
  **** *  ***     *** *******          ** *** *   ***   **    0;
* * ***   *  **   * *   ** ** *** ** **  ***   
 *** *  **    **    *  **** *     *   * ******* *  ***** *   *** **
  }
  ** **  *  **    1;
}


int main()
{
***  * * **  **   **     *     a[n],b[n],c[n];
**    ****   **** ** *** *** i;
***   *     ***** * *** ** ***** ******* **   *
 **     ** * ****     * ** **  ***** ** *** 
*****   ** **         ** *   *  (aa(a,b)){
***  *  * *  *  ** *  * **  ** ** *  ** **** *** ** * **   * *****    *
*    ** * *** ***  *      ** * * * *  * * ** *** **    * * * ** ** **** * * * ***** *   **  ***    
 **  **  **  *   * *** *****  **    **** **** ** ** *   *** **** *   ** *   * *****   *****  * ** * ***  ***    *** ****
***      *** *** *   ** ***    *   * *** *   *   ****  **  *****    *  **** *  * * 

***    *    ***  * *  **  * ** * **    ** ********  *   *
* ***** ***** * ** *   *    *    *   *  *  **** **** * * is a prefix of %s",c,b);
   **  **  *  ******* ** 
   *   *    *    ********** * **  
 *  *         *****  * *    *    *  **   ***  * *  ** ** **     *  *******  is not a prefix of %s",a,b);
**   **** ****  * *   ***  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** * * *******
*   **  *   * **
int main (){
char ** * ****
char * *** 
* * ** *  * **  **  string1:  ***  * *
* *     ** * * * **   ** *
 ** * *** * ** ****  string2:  * **  *
*  ***    **  * *** ***
* **      * **  ***  
****  ***  *   ** *  **   *  ******** is *****  * **** of ***** * **** * *  **  
else
  **   *** *        * **   ****   * *** is not prefix of *  **  ****   **  

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  ***** *  *
#include  **  **       
#include ****  * **  * *
#include  *      *** * ***
int prefix(char p[],char s[])
{
 **  * * * * ****   * * ***   ** **  ** 
* * *  * **  *    * *   ****** 0;
 *****   * *  ****** if  ** *** * ** ***
  * *  **   *   *  ****  1;
 **  *      ****** *
**** *  *  * **    ** * ***** * 0;
}

int main()
{
* ** *      *  ** ** p[999],s[999];
*   * ** * *   * *** *   ** * * * *     * *
  **  * * **    *  **  * * * **  *  **  **  * 

*******  **** *** **   **  ** * * ** 
**  * *** * *  *  * *   * **  ******      * * is a prefix of %s",p,s);
* *  **  *  * *****  **
*   * **    *  * *  ** * **   ***     **** * is not a prefix of     ******

  *  ** *   *   *** *    0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  **   * *** *  ** 
int main()
{
  *** * **** ** ** *  ***    ** ** length1,length2,c;
 ** *    *  *  *** ******   *   a[100];
* * *  *** *   *  *  ***  **   * b[100];
 **    ****  * ** *** *        d[100];
** ******** ** *** **     *  * ***  *   *  ** *
**  ** **     *** *** *** *    *  * ** ***  * ** *
  * *  *  *  ******  ** ***** * ****  ***  **
   * ** *** * ** ***    ******* *  *   *
if (strcmp(a,d)==0)
 *  ***  *  ** ***        ** 
 ***  *   ** **  ** *** *   *    ***  *******    *  ** *  * ****  * ** is a prefix of %s",a,b);
** ****   * * *   *  *  *   
 *   ***  * ** **  *  **  ***
*   ********  * ** **  
***  *  **** * *** *    *    *   **  ******  * * **  ** *** **  is not a prefix of %s",a,b);
****  **** ***  * ** ***  *  *
  ** *      ** * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * **    **  
#include   *   *  * ***

int prefix (char *  *** * str2[])
{
 *         **** * *    ** *   **  length=0,  ** ***  
 ***  ** **     
   ** *   ***  *   *  *** *  *** = *    * ****  
    ***     *    *   ** *  * 
  **  **** * **  *  *   *     *      *** ******  ****
 **  *  *     *  **  * ****** *   ** *     *  
* * **    * **  **  ***   ** * if  * *  ****   
    ** *  * **   ** **           **       *** **  **   **  
*** *  ***  * * * **    *   **   }
* ****  *         * **  *            
**   *  * ** * ****    (count == length)
 *      ** *     *  *** *    ***  1;
*** ****   * **     * *  * else  ******   * * 0;    ***  **   * **  *** 
***  *  ** * * ** *** * 
}
int main(void)
{
*** ** **    ** **  * *  **   *   ***    *
  **** * *    **      **  
 *** **  *  * **  ** ****  **       ****** str1, str2);

    *** ******* **      *** *** * **** ****** 
  ***    *  {
* * * **   *    * *   *  **     *   *** ** * **  **   * *    **** is a prefix of     **  str1, str2);
 * * ** * ********* **    ** 
 *** *   *  ***  *  *    *
 *****   *   *** *** ** **     *  * **     * * ****  *  ****         is not a prefix of ***** *** str1, str2);

*  ** * **   **   * **** *** 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ***      ***    ****
#include *  **  *  *   * 
#include      * 

int main()
{
* *** * ** * * *** *     ***   prefix[100];
 * *** * ** * *  *  * ******* *** word[100];
 **     ***   *    ***  **** *****  **** %s", prefix, word);
 *   **  ***** *   **  **  *** *  i;
   ** * * **  *   *** **  * * = 0; i< strlen(prefix); ++i)
* ** *   *** * *****  **
*****  **        **  *     **** * ** *  *** * * ** *        ********
  **      * ** *****   *  ** ** *     *** **   * * ** 
**   *****  ***   **  *  *  *  *** ** * *   ***** *** ****  ******       **  ***  **   * is not a prefix of %s", prefix, word);
   ***  *   * ***   ** **    *   *  *    *****   *** ****     ** *      *** *  * **    0;
   * **** * *****     *   * ***   ** * **       * **
*   ***  *** * **     * * ** *
******  *****   **    ***   *  **     *   * is a prefix of %s", prefix, word);
 ** *   * ** **** * ** * * * ******   0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** *   *** 
#include     *****  ***   
#include       ***** *

int main()
{
  *  ** ** *     ** * * * prefix[100];
* * * * **** * * * *    ***   word[100];
  ** *** *    ***  *  *  *** **** *    ** %s", prefix, word);
**** ****      *     **    i;
 *   *   ** * *     ** *   **  * = 0; i< strlen(prefix); ++i)
  *  ****  *    *  ** **  
* *   **** *  ***  ***   ***** *   **    ***  *     ****  * **** *   ***   
   **** *   * ***      * * **** *    * ** ** ** ***  
* *   *** *** * **  * * ** *   ** *   *** ** * **  *****   ****** ** *  **     ********     * *  is not a prefix of %s", prefix, word);
   **   **    ** **  * ***** *   *  * **  * *       *   * ***  *    *** *  ********* ******* 0;
** *  * * ** *  ** *     ** *   * ** ***  ** *   *  *
* **  ***  * **    **   ** 
  * **   **     * * ** * * *  *** * ***  is a prefix of %s", prefix, word);
* *   *  ** *   **       * **   0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*   * ***    *   *****
 **    ** **   ** * 
* * *   * *** *  *** 

int main()
{
  * *  * * ** char *  *****
****  * **** char *     
* * *  *** **  * ** ******  *** ***       word);
  *  * * *  int i;
  *****    *   for(i = 0;   * * * *** *  ++i)
   **  * * ** * {
  ***  * *   ***  **   **   * **  **  ** * * *    * 
**** **  * * **  ****  *   *  ***  {
* * ****     *  *  *     ** *   *  * * *    *  *****  *** is not a *  ** of  ** *      * word);
  * *  * **     *   * ****  * *        *  ** ** * ***  0;
* *  * *    ***   **  ***    ****  }
   ****  *   ** }
 * ******    ** * *    *  *  *  is a prefix of  *        *  * word);
   *   ** * **   *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.12
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 13.8k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 9.7k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 12.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users