1-11 Exercise 3: Prefix of a string

0 like 0 dislike
9.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 9.1k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
*     *    *  **    ** ** *   *****
** ***      *   *    ***     *   ***** * * *   ** **  ***   
    {
   *   *  *   ** *  ****  ***           *   ** *  * *    (i=0; i<=strlen(string2)-1;i++)
 **** *  *    **** * ** *  * * * ****  ** *   **  *
* ****  *  *   ** * ***  * * **  *  *** * **    * * *  ** *    ****** ****** **  ***** (string2[i]==string1[i])
 *     * * ***** ** * ** **   *     *  ***  *  **  *** *   **    * *******
*  * *   * ** *  *  *** **      * **   *** *   * ****  *  *    ** * * ***** *** *** *   *** ****   **  
**  * *   *     * **   *   * *  **** * *** * **     *****  **** * *  *  * * 
  ****   ****  *  ***** * **  * * * *  *** ** *    **
* ** *   ** **  * *     *** * ******  ***** ***   ** **      * *
* *** * ** ** **  * * *   **   *  **** ** * *    *   *   * 
 * ***   * * * ** ***   * * *   **** *****   *  ** ** *    **     * **  *  *     *   * * **** * * is a prefix of %s", string2, string1);
**  *  ** *   *     * *  *** *  **  *    *** ** *  ***
** * * ** * *  *** * * ** *  * * *** **   *  * *  **    
 *** **** * *  * * ** * **  **   * ****** * ** **   * 
** **** ** **** **  * *    **** * * ** * ** *   *  *      *  * * ***   * ** ****    **   ** * * **   is not a prefix of %s", string2, string1);
**   *** * * ****      *  ** *  *     * * **  *** 
    }
*****  *   ** * ***    *    ***  *     *** **    *  *   *  *
    {
* *** ** ** *   ** ***      *  *   *** * * *   ***    (i=0; i<=strlen(string1)-1;i++)
*  **** *       ** *** ** **  *   * *   **  ***   *   ***** 
** ** *  *   **   **  * ****  *** ********* ** **   **** * ** **    **** ** *  * ***  (string2[i]==string1[i])
*  * **     *   * *** ***    *** **  *  *    ***  *  *** **  * * ****** * **  * ***
*  ****   ** * * *     **  **  * *    *  **     * * ** *   ** * *   *   * *    ******   *  * * * ***    **  ***  **
* *   **   **** * **  * *  ** *** * *  **     * *   *  * ***   * ** ** *    * 
** *** * ****   ** ***  * ** * * *** * **  ***  ** **   * * 
  * * * ****    **    ** *    **   *  *  ****   ***     **
   * *  *  ****** *    *     **       ***** *** ***    
  ***  *** * *   * **   *  ***** * * **** **  ***  ****   *  *   ******  *      ******* *   is a prefix of %s", string1, string2);
* * *** *   ***        ***    * * *       *** ** ****** **   
* **    *  * ***  **  **  ** *  *    *****     *****   
 ** *  **  * * *****   ** * **  * *** ** ** *  ***** * 
**   * ** * * ** *    * ****    * *  ** *    *****   * * *  * **  *  ** **  ***   **  **  is not a prefix of %s", string1, string2);
   * ** * * **  * **   **   *   *   * ***  * ***** * 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 *   *   ***  * ** * ***** * * * ** *    %s", chaine1,chaine2);
***** **     *    *  ** ** ** ** * *  *
* *  * ******* * ****   *  ** 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
 *   *   *  *   *   ****  lenght1,lenght2,c;
*   *** *  ** **    **  * *   b[100];
*      * *   *  **** * ** ***** * a[100];
 ** *     *    *  * * **  *** * *  d[100];
   ***** **   *  *  **    *** *      * *   *****   
* ** **** ** ** ****  * * ** *    * ** **** * * * ** 
 ** ****   **  ** **  *** *   **** 
**   **** ***  **   *  ***  * ***     *
***  * *  **  *   *   * ******   ***   *   
 **** ** ** **   * * *  **  * * * *
**  * **  * ** *  *  ****  **** ****  *  *****  **   *  *** * is a prefix of %s",a,b);
* *   * *    *      ***     **  
***  ** * ******    *  ** 
** ***    ** ** **  * * * * *
*** *   *  *  * **  *  ** **  **        ** ** * ** **      *  **   **  is not a prefix of %s",a,b);
***      * *  ***     * * ***** 
 *** *  ***    *  *  *   **  * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *  *    * * *    
#include    **    **  * 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
*   ******  * * i;
* **  ** * *  * ** **** *
  {
     * *  **  * **** ***** ** * ** *     A[i]!='\0' && A[i]!=B[i]   )
*** ** ** *  *** ****  **   * **  *** *  ** *********  *     * * *   **  * 0;
 *  ** **  * ** *** *** *  ***  *  *        * * 
 ** *       ** *  ***  *  *** ***  * *   **    *  **  *  * * ** **  * * * 
  }
*** **  *    **** ** * 1;
}


int main()
{
  ** *****   *** ** ********  a[n],b[n],c[n];
 ** * *   *  *     * * * **  i;
  * ****   *  * * * *  ** *    ** **   *  ****
  * ******      *  ****** **  * * *      *  * *
**** *** **   * * **  ***  (aa(a,b)){
  **    **** **  * *       *** *  ** ** ** ****  **** **  **  ***  *** * * * ** 
  *    * ** * **  * *   ***  ***** * **   ** * * **   *** ** *      *   *  ** **** * ** 
* ** * ***** *  *   *  **** ** * *** **  **** * *   **  **    *** ***** *** * *** ** **   **** *** ***   ***** *  * *
*     *  *******  *   * *   ****** * ***** * *  *   ** *** * *  *  **** ***  ***

* *  *  * *     * *   ***   *** *  * ** ***   **  **** 
* *     ***  ***** * **  ***  ** *  * *** **   *  *** ** *    ***  * is a prefix of %s",c,b);
******  *   *  **  ****** 
 ** **   * ***   **** ***  
  ** *   * * ** * ** *** * *  *   * * *  * ****   **  * * ** *  * **  *    is not a prefix of %s",a,b);
*   * *****  **    * **   ** *  * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  **** ** ***
*     *    * ** ***  * *  
int main (){
char *  * ** *
char      ** * 
    *  ** *** string1: * ** *
       **  **  *   *  *     ***
* ** *  *  ** string2:  ** **  * *
 *  *** *  *   **** 
  ** **  **  ***  *  
 *** * ** *    ***    *  ** * * ** *   *   is *  **   * of  **   *  * ***  * ** 
else
***** *  * ** * * *    *    ** ** * **   is not prefix of  *       *** ** *  *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** ******  ** *
#include   **   * ** ** 
#include **  **  ** * **
#include  * *****  *  ****
int prefix(char p[],char s[])
{
****   *      ** * ** **** * *    ***       ***
* *  **     *  * ***  * ** * * ***   0;
     *  ** ***** **** if * *   *  * *  **  ** 
   ***   * **  ***    ** *** 1;
* *  *******  ** **** **  *
* * ** *** * ***  * *** *   * 0;
}

int main()
{
* * *  ******* *** *   p[999],s[999];
  * * *   ** * *  **** ***   **  **  *   
* * *  *    ***   **  * * *  * *** *****  *

***  ** ***   *  * *** ** *** **
**** ***   *   * *** * ***  ***  ** ** is a prefix of %s",p,s);
* ** **  *    **** ** *
 * *    *  * **  *** *  ** **** * ***** ** is not a prefix of  *  **   **

 ****   ***  *   *    ***    0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *   *** *    
int main()
{
* * **   ***  ** *   * * *  *** length1,length2,c;
** * *  ** * * *      *** ***** ****  a[100];
***  **  ** ** * *   *** *  *****  b[100];
**    ***  **    * *    * *      * d[100];
         ******** ** * * * ** *    ** 
 * ** ***** *  ****    *** ****  * ***    * *
**   **  *   ** ** * *****   * **   ****  **  
* **  ***  *  **  * *   **** *** *  ** *
if (strcmp(a,d)==0)
  **  ********* *********  
   *  ** * **      ** ** ** ** *** ***** **  *  * **   ** * *  is a prefix of %s",a,b);
   * **   *      *   * *****  *  
   **  **  *  ***    ** * **  
 * ** *   *   ***    **  **
 ** * ****** *** *  ****   *  * *    * ***    ****    **     is not a prefix of %s",a,b);
 * * *       **** **** *   * **
 * *   *     * *  *  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  **     * *
#include * *** *  * *  

int prefix (char ** ** * str2[])
{
***** ** ** ****** ** * ** * length=0,  *    **
  ***  * *  ** ** ****
*     ******    *  *  *   *** * * * = ** * **  ***   
 ** * * ***  **** *  *         
  *   *** **** ***  *     * * ** * **** *** * * 
 *  *  *   *   ** ***********   * **   *  *
**  *  *     * * * * **  ***  *  if      *    *
**    *  *****    ***            * ** *** **    *    *    **  
** *   * ****      * * ****  *  ****   }
   *  *          ** **  *** * ** * ***
* * *  *   *  * *  ******  (count == length)
  *****  *  **   * *    **  ***   * * *  1;
**  *  ****** *   * ****  else     *    0;   * ******     *** * 
   *  ********  * *  *  * **  
}
int main(void)
{
*  *   ***  * ***  **** **  *    *** *  *   
  ** * * ** ****** ** * * **
  *  *  ***  * * **** *  *  *  **  ***  *** ** * ** str1, str2);

* *  * **** * * * ** *** *     **  * * 
 *  *     *  {
* **  **** *  ** ** ** * *  * *  **   **  *  * *  ** *  * *   is a prefix of *  *** str1, str2);
**  *  **  *** *** **   *  
*    ***   ** ***  *** *  
   ** *** *  *  *   *  *  ** *** * **   * ** *  ****  *        **  is not a prefix of   * ****  * str1, str2);

*     * * **  *****  ***     * 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  *  * * * 
#include   ***   *** *
#include *  * ***  * *  

int main()
{
 * * *     *   * **  **  ** * *** prefix[100];
    * **      *   * **     * * word[100];
 *    ****  **   ***  * *   **  %s", prefix, word);
*** *   * * *** *     *****  i;
* **  *  *** ** *** * *   *** * = 0; i< strlen(prefix); ++i)
  *   *  * ***** **   **   ** *
 ****  * ** * *  * ** * ****  *****  *****    * **  **    ***  
**  ***  ****   *   *    ***  * ****  **** **  *** *    *
 ** * ** *    * * **  **    *   * *    * ** * *  *         **   *  ***     ** **    *     is not a prefix of %s", prefix, word);
 ** **    **  * **** **    * **      *** ** * ** * *  *  *****  *  *  *** **     ** * ** 0;
***   ** *    ** *       **    *     * *   * *      *
     *** * ***     ***  **   *
 ***** *   *** * *** * ***  ** ** *** ** is a prefix of %s", prefix, word);
    *       *** *  * *** ***  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  *** ** ***
#include    *    * *  ** 
#include   *   * ****  

int main()
{
*  * ******   * ** *    ***  *  prefix[100];
* * * **** *** *  *   * *  word[100];
 ****    *    *        *  * ***** * **  %s", prefix, word);
* *  ** * *       ** * **  i;
**  ** **** ***** ***  * *** * = 0; i< strlen(prefix); ++i)
***** ******  *  ** *  
         *    *   ***     ** *      *** **  ******  *  **      **** *
  *  *** * *****  *   *** ** *    *** **** **** * *** 
*** * *   **  *** **       **   * *    *****  *     ** *    *  *** ***     *** *  *   ***    is not a prefix of %s", prefix, word);
*** *  * ****  **********  *   **  ** ** ** * ***   **** * ** ***  * * ****  *  0;
 * *   *  *      **  ** * ***** * * * ***   *  * *  ***** 
 ***** *  * ** *  ***     * * 
** **  *       ** * **    * *   ** * **  * is a prefix of %s", prefix, word);
 *  * * * ** * *   *   *** * **** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  * ** * * *    ** ** *
  **        ********
* * ***   **  ** * *** *

int main()
{
 **** *  *  * ** * * char *  ****  
**  **   ******* char   * **
** ** * ****    **  ** *  ******** **    word);
*** **  *** * int i;
* *        *  for(i = 0;   * *    * **    **  ++i)
  ** **** *   * *   {
   * *  *   *   *  * *          * *  *** * 
*** * *  *  *        ***  ****   {
*   **   *   *   *   **   ** **   *  *  *   *****   **  is not a **** of **   **   word);
**  ** * * **  *  *  * ***  ** ** *  **  *** *  * 0;
   ****  ** **   * *  * * }
* **    *** * }
*  ** *  * ** *  **   * *   * is a prefix of          * ** word);
 *    **  *  ** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.232
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 13.2k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 8.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 12.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users