1-11 Exercise 3: Prefix of a string

0 like 0 dislike
8.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 8.3k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include  ***  ***  * *  
#include  ** *  *      

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
 ***** ***      *   **   *
 
    ***  **        * *   *  * **    *   *   ** **** *  *
*    * *** **  *     ** * * *  
*  * *  ***  ***    ** *    *       *  **   *  * *** * **  **   == s2[i])
  ** ***    * ** *  ****   * *  **      * * **  ******
**** *** **** *   *** **   **  ** * ** * * *** *** *     ** * ** **  * ** 
**    ***  * ***     *****  ** *** * * * * **  * ****
 
 *  * *****  ** ******* ***** ** 
 
 **  ******    *     *** ***  *** **   * == length)
 * ** **   * ** ****   *    * *** *** 
** ** *****  * ** ** * ****      ** *  ***  *   *   * *   ** ***  ** is a prefix of %s",s1,s2);
 * ***  ****  *** *******     ** ** 
 
* * * ** * *** * * ***  * ** * ***  **** 
  *****    **    **  ** * *   *  * 
 *   *  **** *      *   * *  * ***  *   ** *    * ** ***   * ******  **   ** is not a prefix of %s",s1,s2);
  *     **  *  ***      * ***
 return 0;
* ** **** * **   **    * *   * **
 }

int main(void)
{
  * ****  ****  * ** **  s1[100];
   ** *   *  ** * **    *** *** s2[100];
* *  **     **** * * * *  *   *  i,j;
*  *** *** *  **  ***  *
 * **** *** ** *    *    * ****** *    *    s1);
**** ** **  *     **  **** * * *  *  *  **** ****** s2);
**   *** *   *   **  *  **   
***** **   * **   **** *  *** * *
 **   * *  **   *  *   * *   * 
** * *** ** *   * *** *  ****   * *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *    **  ***   
#include    ** **** **  ** 

int prefix (char st1[],char st2[]){
    ** *** ** ******   *  * *  len=0, i, cnt=0;
***** ** *   *** *  *  * *  
****  *     *** *   * **** **  = (unsigned)strlen(st1);
*     * * *****  * *** *  
 *   *  * * * ** *  * * * (i=0;i<len;i++)
 *  ****  * *  * ** *** ** *
**      *   *  (st1[i]==st2[i]){
 ** *****  * **   ******  **** ***  * * ** * ***   ** **  ***  *  * * **** * *  ***** **   *  
*  *  ******* *** ***  ***    *** **    * **** * 
** *  * *  ***  *   * **** * * *
 ***  *** * **  ***   ******** (cnt == len){
   *  **** ****        ** ** * * **  *** *****   *  *** *   1;
*** * **  *    * ** ** *
   * ***  * * **  **   * *
  **   ** *    ** ** ****  *   * 0;
* * *  **   * *** *** ** 
}

int main(void) {
* * **  *  ** *     ** *   *   st1[256];
**  ***** *   *  *    * **   * * st2[256];
**   * * *** * * ****     * * ** **   * *  * *** *   st1);
   **  *  * * **  *  *   ** * *** ** ****** ** st2);

   *  * *     *** *  *   *  ***  (prefix(st1,st2)){
 * ** * *    *     * *  * **** *****      **     ** ***  ***** * * ** is a prefix of %s", st1, st2);
***** * * * **   *  **  **
*  ** *     ********    **   
* * ** * ** *  ********  * *   *    ** *****   *  *  * * ***   * **** is not a prefix of %s", st1, st2);

*****  **  **  **  ****    *  * 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
**  ** * *      * * * *** * *  *  *    **       
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
* ***** *       *  * ** *   *** ** **  ******  *   **
  **   ** **    *     *** ** * * ** ** *** *      *  **   *** ** * **** *  **** *    
   *  * ** *   * *       * * * * ****      * * * ****  *   **   *** **  *** ***** ****   * * * *  * * *
*  * **** *** **** ****  ***     * ***** ***  * * * ******** * *  *  * *****    ********** *** *****    ** * **  ******* *  *   *** **** * is not a prefix of %s",a,b);
        * * **********  ***  *****  *  ****   *  ** *    ** *** ** **  *** *** * * *   * *** *     ** * **** *****   * * *   ***  ** ** * 
 *     *  * ****   ****** ******     * **    **    ** ** ** **   ** *  *** ** * **      *** ***
      * *    ** ** * ****   * **** **   ***  **    *  **    *   * *  * * *  ***    * * *  * 
* ******* *   *** * ** * * **  *  ** * * *    ** ** **   ** *   **  * **   ** * ** *** * *   **   *     **   
* *  *  * *** **** **** ** *   **  * *  * * *  *    * ** *** **  *   * *  * **   *  *   ***    * *  * *** ** * *** **  *****  ***      *** *     is a prefix of %s",a,b);
  * ** *   * *    ** **        ***** *   * **  ** *  * * ** ** * *  **   ****** ***    *  *      *****   ***    *  * * *  **    * * * *  *  **
* *  *** * ***   **     *    *  ** ** *** ***  **** *    **** *  *   ** *********** * *   *  ****  *****        *
*  **     ** *      **  ***** * * *** ** * ***  ** ****




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
  *  * *     ***** ** ** *  * *    **   ****** **  **
* **  **  *  ** ****      ******    *  *****

*** *** **  ** ****    **     *  *  * ****      ** ** *****  *  *****   *  0)
   ****  *  *    **** ** * **   **  * **     *     ********  ** **    * 
***** ** * **** * *** * *  *   *  *  * *** **** **  ****  *  ***   * *  **  * **** ** ****  **      *  *** ** **      is a prefix of %s",pre,str);
 **  *   * ***   *      ** **  **** * *  * * *    ** *** *  *     *   *  
 ***   ** *  *  *     *       * * *** ***  **  ** * *
  *   * ***********  * * *   * * ** ** **    *  *** ***    **  ** ***        
* *    **** ****   **** *  ****  **  * *     ***     *******  * ****  * * *   ** ***   *  **  ***  ** * ** *    *  ** *** *   is not a prefix of %s",pre,str);
    *  ** ***   *  ****  * ** ****   *****  ** *  ***    ****** *  *    ***   * *****

**  * *      **  * **  * ***** * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
** *     ** *     ** ****  * ******* a[100];

*  **  *  * * *** *** * *  b[100];

 **  ***  **     * **  *    i = 0;

* * ** *** ** ** * *  * ** * prefix = 1;

   * * * ** *** *   ** ****  * *** * * ***  *  ** a, b);

  ******* ****     * *** * * len = strlen(a);

**  * **** * ** *  * **** *  *  = 0; i < len; i++)
****** *** ** *   * ***** *
 * **** **  *   *    **   * * *** * * *   *  *   *****  * != b[i])
   *  **   **  ** ***  ****** **** * *** *****  * * **
** * *  **  **  ***  **** ***   **   **    **       ** * *** * * *  **  ** * = 0;

* *   * * * **** *** *  ***********      * ** *** *  **   **  * *****   * **  * *****  *     is not a prefix of %s", a, b);

 ** ** ******  * *  ***   ** *   ***** *      * *** *  ** ****  ****   * * **   * **
* * *   *     *  *   * **  **  * * * *  * *** **    * *
 *  *    *  * ** *   *** * 
*  **  **   ** * **  *  *** ** * *  == 1)
*      *** * *  ***    ****
  ***  * ** *  *   ** *   ***  *  * **  *** * * * ** *  ** *  *** is a prefix of %s", a, b);

 *  *     *******  **     *  
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** ** * * **  
#include  * *** * *  *** 

int main() 
{ 
 *    * * *** *** *** *      * a[100],b[100]; 
** ******  ****      *       i,j,prefix = 1; 
* ***  * *** * *    ** **    **  ** %s",a,b); 
    * *   **  ** *****  ** ***  len = strlen(a); 
* **  * *  * ***** ** *    ** = 0 ; i < len ; i++) 
 *  * **  ***   *** ****  ** 
  * *   *   ** * **   *    ***  ***** **** * ***** *  *  *    != b[i]) 
**** ***   ** * *** * **   * **   * *  *    **  * *   ***  
  *** *  ***  **** **  *    ***  **** ** *  * * *   * *   ** *   ** *   **     *   *** = 0; 
 ***** ** *** * *       ***** * *   *     ****  ** **   *  ****  *   **  *** *    * ** *  ****   is not a prefix of %s",a,b); 
 ***  *  **** **  * *          ** * * ****  **** * **  ******** * **   * ***** *     ** * ** 
*  **  ** * * *  * * ** *  ****    * ** *** * * ***** 

     *    ********  **   * * 
 * *     **       ***  *** * * == 1) 
 *****    * * *  ** *    *      *   **  * *    *   **  *** * *  **   is a prefix of %s",a,b); 

 
** ***  *   ** ***  **   *  ***  *   0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **   *  *  * ** *
#include *   ***   ****  

int main()
{
  ** *****  ****  **** ** **    a[100],b[100];
* **  **    *** **  * * * *  i,j,prefix = 1;
  **  ** ******** * *   * * *  *     %s",a,b);
    ***    *   *  *  ****  * len = strlen(a);
 * **** **    ** * *   *****  ***  = 0 ; i < len ; i++)
* *   ***** *   *  
 *** *    * *     *******   **       *  **  ** *  ** **  != b[i])
 * ** *  ****  *  ** **** *** ****** *  *** **  **
   * **  *  ** ** ** **** *   **      *** *    ******  *  ****** ******  * *** = 0;
*  * * *  *** **  * ** **    ********   *    ******  *** * ** ** ** ***       *** *  ** *   ** is not a prefix of %s",a,b);
***** * * **  *  * *** ****** **** ***     *  *  *  **    **  *   **  *    *** *  ***
**  ** ******  *  * * ***  ** ** ***  ** * **  **

**  **   **    * **  ** *  *
   * * *******     *   *  *** * ** == 1)
*   * *  **    ****   ****  ***   ***     *** * *    *** * * ** ** is a prefix of %s",a,b);


* ***       ****  ***    ***** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * **  *  *     *
#include **** *        ***

int prefix(const char *pre, const char *str)
{

* *** **   *  * ** ***  ** *** ** *  * * *    **
 ***   ***  * ***** *** *     **  ** ******    ***   *   * 0;
**    **  **     **   *  **** ******   * *   *  * ** 
    *  * * ** *    *   *  * ***  **  ** *****     ** **   ** 1;
    *   ***   *  *    *    * return 0;


}

int main()
{
*****       ** *   ****  *  *   pre[100],str[100];
***  *     ** *  **  *
  *       ** *   *   ** ** * * *    *  *  *  *   
 *  *  * ** **      ** **  *****   * * *
*** * **    *****   *** * *** *   ** *    *   * ** * **     * * is a prefix of %s",pre,str);
 ***  **   *  *** *  *  ** 
**     **       * ** *   ******* * *******   **     ** ******   * is not a prefix of %s",pre,str);
  ****  **   ***  *  * *         0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
*******  ****  ***  *  **     c;
 **** ***** ** ** ****   *  * *** **    *****  * *    
***   **** *       *   ** ** *   * ****  ** *   *** **  ** 0;
  **   *       *  **  *   * 
      ** ** *** ***** *    *  * ***
   *     * ** ** * *  *   ** * *      ** * **** ***   *  * *  * ****   * * ***     of a string
 * *  ** *  * ** *  *   * *** * * ** *  **   * ** ** * **** *   * * ** *    ** ** *  * ** ***
***   ****   ****  *   **  *  ** ***  * **  **** *  **  ****  * *     * ***  **   *  * *** *   ** *     *  * *** 0;
** * * * ** *  *  * *   *  **     *    * *  ***   *     *
***      ***** * * *  *  *  ****   ** *   ** ** *** * **** * 1;
    }
}

int main(){
*   * ***  ***   *  *  **** a[100],b[100];
 *** ** *****  * * * ** *** *      ** * %s",a,b);
  ** **  *  * ***  ***  *   **  **
* **      * * *    *  ** ** ***    *  * *** ** ****  *  *** *****   *  is a prefix of %s",a,b);
  *   *   ** * * *** ****  
*   ****** *** *** *** * *  **  * ** ***  *  *    *** *** ** ** * is not a prefix of %s",a,b);
*  ** ***        *    ***  * *  0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 ** *******   **  ***       *  p[100],s[100],a[100]={};
* ****  *   * ***    **  * t;
*  ******  *    ** *  ****  ***  **     ** **
** **** *****   **** ** *   **  *   * * *
*** *  ** * *  *****  *   *   * *    **** %s",p,s);
* *   ** **   * ** * ***    *** * * *  ***
 * * *    **** *****  **     ** * 
  * * * * * *   ** **    ** *   **
 *** ** *    *** *  *** *  *  **  *    ***   *
   ** * ****  *        **** **    ***  *  * ** *  
*** *   *   ***** *** ** **** * * *** *** *** ** * ***      * ***  ***  is a prefix of %s",p,s);
 *    *    * *  *  * * ****
 *   * *  *   *  *    * * * 
       *    **   * **  ***  **  *    ***** *** *** ** ** *****  is not a prefix of %s",p,s);
 *  * **   **** *** ***** ****
     *  * *   *  * *     *  * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.15
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 12.2k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 8.1k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 11.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users