0 like 0 dislike
6.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited

edited by | 6.2k views
0 0
12345

27 Answers

0 like 0 dislike
Hidden content!
#include ** * *
#include * *** *

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
** * * * * * ** * **
 
****** * * ** * * * *** * ** *
*** * *** ** * * *
* *** * * ** ** **** * ** * * *** ** ** * * == s2[i])
* * ** ** ***** ** * * *** * * * * * ** * * * *
** *** * *** ** * * * * ** **** * * *** ** * ** * * *** * * * *****
* * ***** ** * *** * ** ** ** ** *
 
** * **** ** * ** * * ** *
 
* ** * * * ** ** ***** == length)
**** *** ***** * * * * ****** * *
** * * * * * ***** ** **** * ****** ***** * * ****** * * * * *** is a prefix of %s",s1,s2);
*** ** ** ***** * * *
 
* * ** *** *** * * * * * **** *
* * ** * * ** * ** *
***** ** **** * * * * **** * *** ** * *** ** ** *** * ** is not a prefix of %s",s1,s2);
** ** * ** ** * ** ** *
 return 0;
* * * ** ********* * ** **
 }

int main(void)
{
** *** ** * * ** ** s1[100];
* ** *** *** * ** * ** s2[100];
**** ** *** ** ** * * ** i,j;
*** ****** * ** * * ** *
* ** *** * * * * ** ** * ** * *** * s1);
* * * **** * *** * * ** *** * * * * s2);
*********** * * ** ** *** ***
*** **** * * * ** * * * * ** ***
** **** * ** * **** *
* ** *** * ** * * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include * *** * *
#include * * ** * *

int prefix (char st1[],char st2[]){
******* ** ** * * * * ** *** len=0, i, cnt=0;
*** * * * * *** ** ****
** * *** * = (unsigned)strlen(st1);
* *** * ** * ** * * *
** * *** * * *** ** (i=0;i<len;i++)
*** *** * ** * *
** * * * (st1[i]==st2[i]){
* ** * ** * ***** * * ** ****** * *** * * * * * ** ** ***** *** *
* * *** **** **** ***** ** * ****** ** **
** *** * *** * * ** *
*** ****** * **** **** (cnt == len){
* *** ** * ********** * ** ** ** * *** 1;
* * ** *** * **** *****
* * * ** ** * * *** * *
** ********* **** * * * ** * ** * 0;
* * * * * *** * * * **
}

int main(void) {
* ***** * **** ****** * * st1[256];
* ****** * ** * st2[256];
* ** * ***** * * *** ****** * * * * st1);
********* * ** * ** **** * * * ** *** st2);

** * ** **** * (prefix(st1,st2)){
* *** *** ** * * ****** ** ** ** * *** * * ** * is a prefix of %s", st1, st2);
** * ***** * * * * *
* * ***** ** * * ** *
****** * ** ** *** * * ** * ** * * ** ** * ***** *** ************ is not a prefix of %s", st1, st2);

* * * * *** * *** * * * * ** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
* *** * * *** * ** * * * * * *
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
**** * ** ***** *** * ** ** ***** * * ** * *
**** ** ** ** *** * * *** * ** * * * ** * * * * ** * * * ** **** ** ***
****** *** * * * ** *** ** * ** *** ****** ****** * * * ****** ** ** * ** * *** * *
* *** * ****** ** **** ******** ** *** ** ** * ******* * ** * ** ***** *** **** ***** * ** **** ** * ***** ** **** * * ***** * * ** is not a prefix of %s",a,b);
** ** *** * * * **** ** **** * * *** * ** *** * ** **** ** * * **** * *** *** * * *** **
** * * ** **** * * ** ** ** * * * ***** **** * * *** * * * * * ** * ** * **
* ***** ** *** ** ** ** * * * ** ** * * * * * * ***** ** * **
*** * ** *** **** * * * ** *** *** ** **** * * * * * * ** * * **** * ** * *** * *** ** ****
* * *** * ** *** * *** **** *** ** ** *** * *** ** * * * ** ** **** * * *** ** * * ** * * *** * * * *** ** * is a prefix of %s",a,b);
* * * * **** * * * * **** ** * ** ** * * ******* * * ** *** * * ** * ** ** * **** * * ** * * * * * **
* * ** * * * *** ** * * * ** *** * * * * ** * ** * *** * * * *** * * ***
* * * * * ** ** **** * * * *** * ** * ** * * ** * *




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
************ *** ** * *** *** ** *** ****
** * *** ** * * ** **** *** *** *

*** *** ** **** * * * * *** ****** * *** * *** * **** **** * * * 0)
*** * ** * ** ***** * *** **** ** * * * * ** **** ****
** * **** * * ***** **** ** * * *** ** * *** * *** * * * ***** ** * ** **** * *** ** * is a prefix of %s",pre,str);
*** ***** * * ** ** ********* *** **** * * * * * ** ****
** * * ** * * *** ** ** * * * * ** *** * * *
*** * ** ******** ****** * * * ** ** * ** *** **** ** ** ****** * *** ****
** * * * ** * * *** * * ** ***** * * ** * ** * * * ** * * * * ****** * * * is not a prefix of %s",pre,str);
* ** *** * * **** * ***** *** ** * ** ***** * * * ** * ** ** * * **

** **** **** **** * * * * * ** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
* * * ** * ****** * **** ** * * a[100];

**** *** *** * * * b[100];

** * ** * *** * ** * * * i = 0;

* * * *** ** * * * prefix = 1;

** *** ** * ** * * ** **** ** * ** **** ** * a, b);

*** ** * *** ** len = strlen(a);

** * ** ** ** ** ****** = 0; i < len; i++)
* ** * ** **** ** *
* * ** ** * *** * ** ** * * ** * *** ***** ** != b[i])
** * * ** ** * ** * ** * **** * * * **
*** *** * * * ** * **** * * * * * ***** *** * ** * *** **** ** * * ** = 0;

* ****** * *** ** ** **** * * * * * * * * ** * * * * * ** ** * * is not a prefix of %s", a, b);

* *** * * * * *** ** ** * * **** **** * * ** ** * ** *** * * ** *
* * *** * * * * * ** ** ** * ** * * ****
** *** * ** ** * ** * *
* ** ** * ***** *** *** ** == 1)
* ***** * * * *** * * * *
** * * ** * * * ** *** *** *** ** ****** * * * * * **** is a prefix of %s", a, b);

* * * * * ** *****
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include ** *** * * *
#include ** * * *

int main()
{
* * *** ** ** * ** a[100],b[100];
** * * * * * * **** i,j,prefix = 1;
***** ****** *** *** **** *** ** %s",a,b);
* * ******* ** ** ** * len = strlen(a);
** *** ** **** * * * ** ** = 0 ; i < len ; i++)
* * ** * *** ******
** *** * * ** ** ** * * * * ** * ** ** ***** * != b[i])
**** *** * * ** ** ** ** * ** *** *
****** ** * * * ** ****** * * * * * * ** ** ** * *** * **** *** = 0;
* * ** * * * * ** * * * * * * *** ** ** ** *** * ** *** * * ** ** is not a prefix of %s",a,b);
* ** ** * * *** *** ** ** * * ** ******* * **** * * * * *** ** **** *
* * ** ** *** ** ** **** * * * * *** *

*** ** ** ****
*** *** * ** * * * * ** * *** * == 1)
* ** * *** ** * * * **** * ***** * ** * * * ** ***** * ** is a prefix of %s",a,b);

 
** * ** * ** * *** **** * 0;
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * *
#include * *** ***

int main()
{
* * * * ** * * a[100],b[100];
** ** * ** *** ** i,j,prefix = 1;
* ** * ** *** * * ******* %s",a,b);
* **** * ******* *** * len = strlen(a);
*** * ** ** * ************* = 0 ; i < len ; i++)
**** * ** ** ** ** *
** * ******* * * ***** * ** * *** * * * * ** * * != b[i])
** * **** ** ** ** * * * * * ** * ** *
** *** * *** * ** ** **** ** *** ** * *** ** ** ** = 0;
*** ** * ***** ** * * ** **** * ** * *** * * **** * * * * * ** *** is not a prefix of %s",a,b);
*** * ** * *** *** ** * * **** * ** ** ** **** ****** ***** ** *
* * * **** ** * * * ** * * *** *** * ** **

* * * * ** *
* * ** *** *** *** * * * == 1)
** * *** * ** ** * * *** ******* * ** ** **** * * is a prefix of %s",a,b);


** **** * * **** * * * * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include ** * ******* * *
#include * ** * **** **

int prefix(const char *pre, const char *str)
{

*** * * ** * * ** * * * * *******
** ** ** **** *** ** ** * * * ** ** ** * 0;
* * ** * * * *** * * ******** **
* * * ** * * * * * ** *** ** ** * * ** 1;
****** *** * ** * * ** * * return 0;


}

int main()
{
** ****** *** ****** **** ** pre[100],str[100];
* *** * **** *
* ** ** **** * * * * ****** * * **
** ** * * * * * **** * ** * ** **
** * ** ***** ** * * ** * * ** * ***** *** ** * is a prefix of %s",pre,str);
* ** * * ***
* * * * *** * * * ** ** * * * *** * * ****** is not a prefix of %s",pre,str);
** * ***** *** * *** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
** ** * * * ** * * c;
* * * ** *** *** **** * * ***** * ** * ** **
* ******** * * **** * ***** *** ** * *** **** 0;
** * *** *** ** ***
* ** ** ** **** * ***
**** ** * ** **** * * * * * * ** ** ** * * ** * * * *** * of a string
** * ** ** * ***** **** ** * * ** * *** ** * * **** * * ** * * **** **** * ** *
*** * ** * * ** * *** * ** **** *** * * *** * * * **** * * *** * * **** * **** 0;
* * * *** * * * ** * * * * * * ********* * **
* * * *** * **** ***** ** *** *** ** * *** **** * 1;
    }
}

int main(){
* * *** ** * ** a[100],b[100];
*** ** * * ** * * * ****** **** %s",a,b);
** * * ** *** * * * *** * *** **
** * ** * ** * ** * * * **** *** * * * ******** ** * ** is a prefix of %s",a,b);
****** * ** * *** ** **
* ** **** **** **** ** * ** * **** *** * * * is not a prefix of %s",a,b);
** ** * ** **** * *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* ** * ** ** ** * p[100],s[100],a[100]={};
* **** *** * * * * t;
*** * **** * * * ** * **** **** *
* ** ***** * * * * * *** ** * *
* ** * * ** * * ** ** ** %s",p,s);
* * * * ** * * * *
* ** *** * **** **** * * *** **
**** * * * * * * *** * ***
* * ** * ***** *** * ** * ** * * * *
* ** * * * * *** * *** * *** * *
* ** ** * * * *** * * ** **** ** * ** ****** * ** is a prefix of %s",p,s);
** ** * ** * *
* * * *** * ***
*** **** *** * * *** * * ** * ** * ** is not a prefix of %s",p,s);
* **** ******** * **
* * * *** *** *** * *** * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.195
©2016-2025

Related questions

0 like 0 dislike
57 answers
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited
| 8.8k views
0 like 0 dislike
29 answers
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited
| 5.9k views
0 like 0 dislike
53 answers
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited
| 8.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users