1-11 Exercise 3: Prefix of a string

0 like 0 dislike
9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include **       ***   
#include  **** ******* 

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
     *  ** *  **  *  ****
 
**  ****  *  ** * *** **   *** * *     * *****
  ****       *    *   **    *** ** *** 
**   *  * **     * *   * ***   ** ** ***  * *    *  ***   **  == s2[i])
******** **  ***** * ** **       *    ** *  *** ***** 
   *  *  ***** ** ** ***  ** ****   ** ***  ***  * **   * ** ***     * *** **  *
**** * ****** * ** * ** *** * *   * * ** **    **  *
 
   ** **    * **  **** **   **  **
 
   ***  * **** *****   * * **   *  * == length)
**  ** *** ** **  ** **  ****
* *    *    *  **  *  *  **   *** ** ** ***** ** *  * **** * ** * ***   is a prefix of %s",s1,s2);
  * * ***  *  *** ******* ** * ** **
 
  ** *   *  ** * ******   *   *** *  
*  * ******      * **  *  *    **  
     * ** * *     ** * ***  ***  * * **  **  * * **** * *******  * *   is not a prefix of %s",s1,s2);
  ***     *   *  *** **** *   * * * **
 return 0;
 * ****   ** *** **  ***       
 }

int main(void)
{
   * *  * *** **  *****  **    *  s1[100];
*** **     * *    *          ** s2[100];
* *   * * ***  *** * **  *  *  i,j;
 * **  **** * *       *   ** *
* * *****  *  * **  *  * *  *** ***  * s1);
       *   ** *    *  * *   *   * ***** **  * * s2);
*  * * *  ********* *  * *  
 *  **   *   ** * * ***     *  ** *
*  * *** *** **  *  * * *****
  * ***     ***   ***   * ** * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * **   ** **
#include **   * * *   

int prefix (char st1[],char st2[]){
   ***  ***  *** * *    *** len=0, i, cnt=0;
** *** * * *   ***** *   
 * **** *  **   *    ** *   = (unsigned)strlen(st1);
 * **         **  * * ******
**** **** ** ***   **** ****  (i=0;i<len;i++)
* *  *** *** ** * ****   * **
  * ***  *** **   (st1[i]==st2[i]){
*  ** * * * * **  *  ***  ** * * * ***   ***  *   ***  ** **  *  *  * *    ** * *
**  * * * *    *  *     *  *  *  *     *   ***   ****  
   * **** **** *  ** *  * *
 *  * *** *  ****  ***  **  (cnt == len){
*  *   * ***  *    * ** ***        *   ** ******* *****  1;
 * ** **    * ** ** ** * 
* **** * *** **** *  * ***
 *** ** * *    ******  ** * 0;
 *** * *** ** ** ** *   
}

int main(void) {
 **   * * * **  **   ** * *** * st1[256];
  *****  * **  *   *    * * *  st2[256];
*  *** **  ***   **  ** * * *  * * ** *     *** * *** * * st1);
  ***  ***  ** * *** *  **    *    ****   *  st2);

* * ** **  ******  *   *     (prefix(st1,st2)){
*  *   ** ** *  ***        ******** *  * *  ***** **       *  *  * *** *  is a prefix of %s", st1, st2);
 ****   ******   ***  ** **
 * * ***  ******   **  *  * **
*  **** **  * **  ***     * * **** *** *   *     * * *    * *   is not a prefix of %s", st1, st2);

 *   * ********    **  **  *   0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
*** * *    **  * ** ** *** *** **  **  * **     ** **
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
  *   *** **** * ** *  ***    *  **** *   *********
 * * **  **  *** **** ***    *  *  * * *   **** ****  *      *    ***  * *   *  *  
 ****  * *  ** * *****    **  * *  **  **  *  *   *****  *    **  ** **      * **  ****  ** * *** ** **  *    ** *
   ***** * *   * * *   * *  **  *  **  * ****** *   ** *  *  * * * ** *  * *    *** **  *** **  ** * * * *  ***  *   ** **  * ***   *** *** **   is not a prefix of %s",a,b);
****    **  ****   * ** * *** * ****** ** *  *** **  *    *   ** * * *******  ***** * ** *   *** ****   * *  ** *  ** * *      ***       **  
 **** *   ** ***  ***   * ******    ***  * *** ** ***** *   * *   ****   *** ** *   *  ** *   * **** * * *       **  
** * *  ***** *     ** *  ** * **   * *      *  **  * **  ** * *** ***    *  ***         *
 * *  * ** * * **    ***   *   * ** *   *   ** **  **      ** *  * * * * * ****** * **  *   * **** * * *  *** **  
   * *  **  ** * *  *   ***  ***** ***    * ***  *   *    ****   *      * * **  ** * *  *    *   *  **** *******    ** **     * * *   *    *  * *****  *   * * is a prefix of %s",a,b);
***  ***  **   *  *  *   *  *   *  ** ** ** **   **** * * **  * * **  ***    **** * * *** * * ** * *** * **** * * ***      ** ***********
** **  ****  *     *    *****  **  * *     ***  *  *  ** * *  *  * *  *  *   ***   * *   * ****** *  * **   ***  
  **    *** * * ****   *      *** ***    ****  **   * **  *




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
****  *   * ** ****   **  ** *  **   **  ***** **
  ** ****  *  *  * * *  ****   ***** ** * 

 **********   ***** * * *** **   * **** **     * *    *     *  **  * ***** * ** 0)
*      ** * ** *   *      *  *  * *****   *   * * *  * *   * **    **    ** 
** *    *  * ** ********* *    * ***  ** ** * **   * ** * ****  ** ***  * * ** ** ** **  **** **  *    * **  *** is a prefix of %s",pre,str);
    ** *    *   * * ***   * *** **  *** ****  * * **  *   * **   *** **** **
*** * ***** *  * **  * **  * ** * *   *   ***      * *   *  *
** ** ** *      *  *  **  *  * **** ******  * * ****   *  *  * **  *   **  *  *   
*  * *  **** ** **** * *   **** **  **  * **     ** ***  * ***   **  *  * * *  ** * ** ** *** *    * **   *   is not a prefix of %s",pre,str);
** * **    *  **** * *  **  **** **  *  ** *    *****   * ** ** ***  * *

****  * *     *   * *  *   *** ** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
  ** * * * * ** ***  *** ****** * a[100];

 **** **** *    ** **   *  ** b[100];

* * *  *** *   *  *  *  *  * i = 0;

  *    * **  *   *     *    *****  prefix = 1;

*  *** *  *  * *   *  *   * *    ** ***  *   * *  a, b);

*  **** **  *  *  ** *** * * len = strlen(a);

   *****  **  *   ***** ** **   = 0; i < len; i++)
* *** **  ** *   **  * **
 * **    *   ***  *****   **  *    * *****   * ****** *  *  ** != b[i])
   * ** * * * * ** * **  * ******  *  ***  * ** *  * *** *
 * **** ***  ***** * *  * *** ******   **    * * * * *     **      ** *       ***  *** = 0;

**  ** ** *****  ****   *** * *** ** *    ** ** **  ***     *** * ** * *  * ** ** ********* is not a prefix of %s", a, b);

 ********* ** *   *** ***  *   *******  * *** **     * *****  **** ** *  * * **  *
   ** **** ***** *  * * *      *   * ** ***  *  *** *  **
*** *  *  ** *** ***   *
 ***  *      *** ****      **    **   == 1)
 *   ** ** * **  ** *****
  *  *****   *****      * *****     ***** *** ** * ***    * *    is a prefix of %s", a, b);

  ****** *  *** * *   * ***  * 
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * **  *  **** *      
#include  *  *  *     ** 

int main() 
{ 
* *  **  * * * *     **  ** a[100],b[100]; 
 ****** ****    **** * i,j,prefix = 1; 
** * ***   *  * *   *  * ** ** ***** * ** * %s",a,b); 
*  ** *     *  *  * * *      len = strlen(a); 
*   **  * **            * *** *  = 0 ; i < len ; i++) 
  ** *   **  ** **  *  **   * 
 **         * **  *  * * * *   ** ***** *  **   *****  != b[i]) 
  ** **** *** ** *  * ***    *   ** ****      **  ** **** 
*  * *  ******   **     * * *  *    *   **** *   * *   * * *    *** *     **       * *** = 0; 
 ** **** **  * **  *  *  *** ** **  *  *    * * * * **** ** *  * *     *  *      ** is not a prefix of %s",a,b); 
* **    ****** * **** * * ** *    **** ** ****  ***    **  * * *** *   **** *   **    *   
 ****  ** **  * *  *   **  *** ***  **  * * *    

* ***   ** *****  ** *     
****  *   **  * *    **  *    ** == 1) 
 *****    * *   *** **** * **** *** *  * * *  **    *    ** ** ** *** is a prefix of %s",a,b); 

 
    *  * ***** **   ****** 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *** **      ****
#include *** * * *    **  

int main()
{
** ** ***        ****  *   ** * a[100],b[100];
 *  *** ** ** **    * * *   *   i,j,prefix = 1;
 * **  *******   * **  ****** *** * *   %s",a,b);
   *   * * ***  *  *  **  len = strlen(a);
   **  ***   *** * * **   **** *** = 0 ; i < len ; i++)
**    * **********  **
 ***** **      ** * **** **        * ***** **   * * * *   != b[i])
            *** ** *  ***      **   *    *     * ****   
 * * *   ** *** ****     * ** *    *  * ** ** ***** ****  ** * * **       ***    * ** = 0;
 *** * ** ****** * *    **  *   **  ** *  ****** **   *    **  ** **     *   **  ** * **** *** **  is not a prefix of %s",a,b);
 * ** * *  * * *   *    *   *  * *  ** ***  ** ** *** **** **  * *****  **    * 
* *   * *   **** *   *****    *  *** *  *    * * **  *    ***

  *     * **   * *   * 
 ** *  ** ****   *****    ******* == 1)
 **  * ** * **  *****  *    **   ** **  * ** ***  *  * **   is a prefix of %s",a,b);


  ***  ** ***** ***   **   * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *    ** * * **  * 
#include  ***     *** * *

int prefix(const char *pre, const char *str)
{

*  * *   *****     **  * ** * ***  *   * **   ***  **
  *       * * *    **  * ***  * * *  *  **** *   *   * *  0;
  * ** *  * **   *** ****   * ** *  *   * **
 * *** * *******   * *  *    **  * ***   **      *  1;
* *  ** *    *  *   ******      return 0;


}

int main()
{
**  *   *** * *  ***     * ** * pre[100],str[100];
  * **  **  * *** ***   **
  ***  ****    ** *      ** ***  **  ** * * *   ****
*    ***** **   **   **      *  ***
 ** ** **** *     * ** **  ***   *      *  * *  *    ***  is a prefix of %s",pre,str);
   * ***** * *  * *  *  * * ***** 
  ** ** **  **     * ** * **** ** * * *  ** ***  ****     is not a prefix of %s",pre,str);
***    *   **   *   * *   ***  0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
** ***  *** ****** *  ***  *  ***  c;
  ***  *      ***  *** *    * ** *   * ** **  * 
 * **   *  *   *  * * **  ** ***  * *  *  * * *** *** *   *** * *** 0;
 * ** * *  *  *  * **  ***
** *** *    ***   *     * 
* **** ** * **** * *   *** ** * *      ***  **  *   *  *****  *   *  *  ** *** of a string
 *  *   ** **** *  ****  *  *** ** **  *  **  * * *** **   * *** *  *  * **  **  **  ** *
* ****  * *   ***   * *   *  ****       ** ***  ****** **   **** ** ***  *  ** ** * * * * * **    * ** **   ** ** *  ** * 0;
     *****  **** ** ******* *** **    *   * * *     
**  **  *  *  *** * **** ****** *     ***    **** **    1;
    }
}

int main(){
  * **  * *****    * * ****** *  a[100],b[100];
*   ** ***  * * * **** *****   ** *  ** * %s",a,b);
** * ***  **  *  ***  *   * *  *  **** 
  ***** **   **  **  ** ** ** **   * * ****   *   ***  ****** *  * is a prefix of %s",a,b);
*  ***  **  * ***  * * * ** * * 
*  *** * *  ** *   *  *  *** * *     * * *   ***   * *    is not a prefix of %s",a,b);
*  *  *       *** *  ***** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
    ** ***** ** *  **   *** *  p[100],s[100],a[100]={};
 *** *  *   **  * ****** *   * t;
  * * ** **  *   ***  ***  *  *  
  ** **  *  *  *** **** *    *** **     ** 
  **    *  *      * **** *  * * ** * %s",p,s);
 * **** *  *** ** *  * * *  *  *   * 
*  **     *** ***   * *  * ***** ** ****
* * ** * *    **  ****** *      *  * 
 *  *   * *    * * * * * * *    *    ******    *
    * * **** *   ** *  ** *  *  *******  
*  ***   ** *** * * *  *****   *  ****    *    **  * ****** *  * * ** *** is a prefix of %s",p,s);
** * *  *    ***       *  * 
*   * *  *  * * *  *   **   * *
   ** * ***  ***   ** *   * **    *** ****         *  *  * * *  *** is not a prefix of %s",p,s);
**  *  **** *  ** * *  *   * * 
 *  **  **  *****  **** ***    0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.250
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 13.1k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 8.8k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 12k views
12,783 questions
183,442 answers
172,219 comments
4,824 users