1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include      **         
#include     *** *  ** 

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
 * *   * *****  *** ** *
 
  **  ** ** *   * ***  *** *** *  * *  ** ****   ***     *  
  ******   **  **   *   *   *     
  **     * * **   *  * ****** *  **  * *** ** **   ** * **   == s2[i])
 ** *  *** ******  * ***  *   **** * *  * *   *** **  *   
*       **  *  * *    * *** **   *  *    *******  ***** ****     ***    *    **       
* ***  ** *   *    * **  *  ** ****  *****    ** * *** * *
 
 *  *  *****  ***** *  *** *** 
 
*   *    *  * *    ****    * *** *** * *  * ***** == length)
** *** ** **  *  **** *  *   ***     *  
* ***   *   **   * *** ** ** **   ***       ** *** *  ** *   **     ** * is a prefix of %s",s1,s2);
 *  ** *  *   * *** ***** ***  *
 
*** **  *** * * **   *  * * *   * ****
  * **** ** *  * ******  **   
*  *          *****      *** *     *   *   ** ** **  * *   * *   ***** **** is not a prefix of %s",s1,s2);
*    ***** ****    *    *  ***  ***
 return 0;
 *** * *  * ***  ********   
 }

int main(void)
{
  ******* ****** * **  *   *  * s1[100];
** **  *** *  * **  ** *  * **  s2[100];
 *  ** ****** * **   * * i,j;
  *****    * ** * *******
 *  ** ***  **** *** ** **    *  * *   * *****  s1);
* * *  *  *  **     ****** * *      ***    * s2);
* * *  ****** * * ** ** * 
*   ***  *** **  * *  ***    *   *  
  *    * ** *** * ***** 
  **  *  **     ** * *****  * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ****** * * ***  
#include     * * *** *  *** * 

int prefix (char st1[],char st2[]){
* **  ***     ***  * *    * *  * * len=0, i, cnt=0;
 ***  *   * * *   * *   *  
* * * * ** **  **  *  **   *  = (unsigned)strlen(st1);
 * *  * *** *** *****      *
  *   **** *  ******* ** ** ** *  (i=0;i<len;i++)
 *** *    ** * * ***  ** * *
******      (st1[i]==st2[i]){
* * *** *  * *  * *    **  * * *** **   *    * ****** * *  **  ***   * ** *
***    * *  **  **  *****  ** * ***  * **  ******  *** 
*** * *    * ** ***  *  * ** * 
 **      **** **  ** ** *   ** ** (cnt == len){
* * **  *   *   ******  * *** *  **** ****  *   ** *   *   1;
*   * ***  * **  *** ****** ***
****     *    ** **     ** * *
  ** *    **   * *    **** *   0;
 ***    *  *** *  **   ** *
}

int main(void) {
** ***** **  ** * * **   *** st1[256];
 *  *   *    *  *******  * * * st2[256];
    * **** *** ** **  *** *  * * **  ****  ** **   ***  st1);
  *****  ******* *  ***  **   * * * **    st2);

** ****  * *  ****   **** * *****  (prefix(st1,st2)){
  * *  ***   *   ** ***  * ** *  **** *****   ** *  ***  * *  ** * *  * * is a prefix of %s", st1, st2);
**  **  **  ***    *
* * ** *** ***  ***** * ** **
*  *   * ***   **   * * *     *** * * *    *  *     *  ** * *  * ** *   is not a prefix of %s", st1, st2);

 ** ** **  ** ** **  *** *    0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
   ** * ** * *** ** ****** *    *  ** * ***  ** **** ** 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
***   *   * **   ***** * ****  *** * *  **     **  ** ** *** 
*  *** * *** * ** ***** *   ***  ***** * *** * **   ****** ******* *    * *     * **** ** **** *
*     ** **  ** *  **  *  *  **  **    *****  **    **  **  * ***  * *   *** ********    * ** ****   *  *   
*   ****  *** *   **** * * * ***  * *  *  ** * *   * * ***   * ***  *  **    ***  *  ****  *     ****   *** * *  ****** ** ** ***** *** * *** * *   is not a prefix of %s",a,b);
* *   ***   *  * *  * ***    ***  *** *  *      ** *** ****      ** *   * **** * * * ***   **  * ***    **      *  *    ***** *  ** * 
*  * **    * ***  *** * *  * **  ***   *  * * **  * **    **** *    *  * *    * *** *  **     *  ***
* *   **** ** ** *     *  * *** ***   * ** ** * *   **  * ****  ***  *    ** **** ** 
**** *  *  ** *  *   * *  *  *  ****** * * ****   *** **  **** *  ** * ** * ** * * ***   **   *  * *  ****
     *** *** *  ***   **    * **  * ******     * * * **  *** ** * ***** * **  ** ** **     **     ** ** *        ** **  **  ***** * * *  *  **    ** ** is a prefix of %s",a,b);
 ****** *****  * *  **  *  *  * **** *  **  **  ** *       *   * * *    *  *  * ** **   * ******** ** * **  * * *** *** *  *  *** ** 
   * *  *** *    *** *  **  **    ** * **  **    **    * *  *   *  * *        ** * *  *         *  * ** *** 
   * * ******   *** ** ****   *  *   ****    *    * *




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
 *  **     *       * *    * *** ***    **   **  *      ***  
  ** ** ** *      *  * **    *  ** *** * * *  *  *****   

*  *      ***** **  ** **  *****  *     *    ***** ** *    **  *   ***        * 0)
 * *  ** **  *  **  **  *  ** * ***  *  * *  ** ***       *   ***   *** * ***  *
*  **  ** * *  *****    ** ********** *  *   *   *  ** * *  * * ** * **   *  ***  ** ** *    **  ** *****    *  **  * *** is a prefix of %s",pre,str);
************ ***  ** * * * ** * ** *  * **       **     ***** * *** * * ****
 * ***   *  **  * * * ** **  ****     * * *   * *
  *  * ***   ** *  *  **  *  ** ** **    *  **  * *** * *** * ** **  *     *  ***
*  **** *  ** *    *  ** *  ** * ** *   **** *   ** ** *   ***  **    *    *  ***  ** * ** * **  *  *** * * ** *** *    is not a prefix of %s",pre,str);
  *    *** * *  *********     * *   **   ** ** *****   **  **  *  **** * **   *

* * *****    *** * * * *  * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
* *  ** **** **  ***** *     * a[100];

**  *  *    *******  *** **  **  b[100];

**  *    * * * ***  * *   * i = 0;

* *   *      ***  *  *******   * * prefix = 1;

     * ** *****      * *****   **** ***   a, b);

**  ***  **   *  ****  **  *  *   len = strlen(a);

 *  *** * ****  * * *   **** ** ** = 0; i < len; i++)
*** **  * **** * * * *  
***      ** **  * ** ***  ** ** ** **    **       *  *     != b[i])
 ** ***    *********  **  **  **   * *  * *****  * *  
********* *** ** *** * **   *  *   *  *  **  * *  *   ***   ******  ** ****       *   *   = 0;

 * **   *** **  ** **  * ***  * **   ***   **   ** ***  ***  *  **  *  ****  * *** ** *   *   is not a prefix of %s", a, b);

   * * * * *** * *           *** **** ***  **** ***      *   **  * ** *   * *    
    ** *   *   **** ***** ****   ****   *****
    *  *  ** **  * * *  *  
 *** **   **  **    *  *  *  *   == 1)
** * * ** ****  * * *   * *
* *** * * **   *****   * ***** *  *   ****  * **** * ** *   *   * is a prefix of %s", a, b);

  *   * ** * ***    *** *** *
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     * ** *  *   ** 
#include *     **  *   *    

int main() 
{ 
***  *  * **  ** **        * ** *  a[100],b[100]; 
    *   * * * *      *   **** i,j,prefix = 1; 
   * ***  *    **  *** * ** * **  *   %s",a,b); 
* *  *     *******   * **  *  len = strlen(a); 
  *  *****  * **   * * **  **  = 0 ; i < len ; i++) 
  *** *  *  *   * *** **  
*  *  * **   *  ****  **     * *  *   *  * *** *      **** != b[i]) 
*    ** * **  ***  ***  * ** *** **** ** **   *** **      
 * *  ** ***       * * **   ** * * **  *** **** ** * *  * ** *       **  **  *** * = 0; 
**  ** *   **   *  ***   *** *       **   ***  **   *** * *  *** * **** *   **    *  ***  *   is not a prefix of %s",a,b); 
   *** *  *** * *   **** *  **  *  *   *  ****** * ***  *  ** *** *** *****  * **  ***    
*****      *  *  *** *  *   * **** **** * *  *** *     

  *   * ** ** ** *  * **     
 *   * ** **** ** *  *** ***  *  == 1) 
  *  ***** ***  ****   **   ** ** * ** **  **  *   *  ***  * * **  **** * is a prefix of %s",a,b); 

 
**  *   **   **   ** ***  **** 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include ** ** **    * 
#include *** *** * ****

int main()
{
  *  ** ** ***   *    *   * * a[100],b[100];
   ***   ** * * **** * i,j,prefix = 1;
***  ** ***  ** **  ** ***** **   *  * %s",a,b);
 **        **** ****  ***  len = strlen(a);
   ***   *   **    * *     ****  = 0 ; i < len ; i++)
*   **** ** * *** ***** **     
*   **   * *** *    **** **  *   *  **   *  *** ****    **  != b[i])
* *  *** **   **  *   **    * **    *  *   *  * 
 *****  ** *   *  ** * *  * * ** **   *** ****** *  **     *    ***   *** ** *   **   = 0;
*   * ***  * *  ***** *  *  **   ****  * * * **   **  *  **** *** ** ***   * * *  **** ** *  is not a prefix of %s",a,b);
***   ***  * **** ***    *  *   * *****    * ** *  **** ** * * *** * *  **   *** * **
   *  * ***** * ** * ** ** **** ** **** *  *****   *       * *

*  *  ****   **  * ***    **
**** *   *      *   **   *** * ***  == 1)
*** * ** * ** *  * *   * * *  *** * *****    * * * ****** *    ** * *** is a prefix of %s",a,b);


****  * **   ** ** * **    * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** ** ******
#include    ** * * ** * * 

int prefix(const char *pre, const char *str)
{

    ** ** *     *  * **      *  **    * ** **   
*   ***  **** * *   ***** ***** ***  *   *   ** * **   * **  * 0;
  * ** **  * * * ** *********  *     *   *  *   * * *
 *   **  *  *** * *  ** *   * **   ****** *** * ***  **   *   1;
* * *  * **  * **  ****   * ** return 0;


}

int main()
{
* *** ***  ***   ** ***  ** * pre[100],str[100];
 **         ** *  * ** *
  *  *   * **    **  *** *  * **** *    ***** *  * 
*    * ** *** ** *  * * *  ** *   *  *** 
  *  **  * ****  * ** **   *  * ****** * ****** *** *  * *  **  ***  **   is a prefix of %s",pre,str);
 ***   ** *  **   ******* *  * *
***   * * * *    *** ******  **** *  * ****   * **** **  * * **  *       **   is not a prefix of %s",pre,str);
   *   *  *   **  **    * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
 ** * * ****   * *** **    c;
**** ***  *   ** ** ***** *  *  ****   *** *  ** 
*  **  * *  *  ***  **      ***   *** **  * **         *  0;
 ***   ****   * *  *  **
*** ** * * ** ** ***        * ** **
     **  ** **   ** **** *   ** ***  *  * ** **    *** ** *   * *** ***** *    *  of a string
     *****  *   *   *  ** ** ****   * *** * * *  * * *  * **** ** ***  *** * ***  
 * * ** * *** *****  **    ****   * ** *** * **   ***  * ***** *     ****** ****   *   *  * *  ********  **  *  *   0;
* **    ** *   *  *** * ** *  *   *** * **   *  *  ** ***
** **   **   ***    ***    * *      **   ** ******  1;
    }
}

int main(){
 * * ** ** **    ***** *   *  a[100],b[100];
*****     * *** * ****   ****** *  * %s",a,b);
  ***          *    ***    **     *
***    *  **** ***  *  *  **      *    *  * ***  **   *  * is a prefix of %s",a,b);
      *** *****  * ****   * ***  
* *** ** ** * ****   * * *    *** * *****  *** ******** *  * ******   is not a prefix of %s",a,b);
 *    ** ****   * *     0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
   * *  ****   ****** **  **    p[100],s[100],a[100]={};
* *   ** ** ******* **  **** t;
 *** *   *    ****** **** * * *    ***** 
***  ***** **   * *  *   ** * ******  *****
*** * *** ** ***    **   * *   * *  ***   * %s",p,s);
* * *   *  ** **  *  *  * **** *
** * ******* *****   ** *     **** **
**  *** ** ****   * *        *  ** *  **
** *     *  **    *   * *** ***   *** **   **
  *  * *     * *** ****   *         *  ** *
  *   ***  ** *  ** * ** ***  * * **   ** *** * * *  **  *  *  * * is a prefix of %s",p,s);
**   *** * **** *     ***  
  * * * **  *  **  * * * * *  ****
 *****  **** *          ** **  *******  * *   *   *        **** *** is not a prefix of %s",p,s);
  *   * * * ** *     * 
****   **** *  * *   **  **  *  * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.95
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 10.1k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 6.6k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 9.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users