1-11 Exercise 3: Prefix of a string

0 like 0 dislike
9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include  * * **    *
#include      *  * * **  *

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
*** *** * *    * ** * *  
 
*** * *    *  *   ****     *  ******  ***** *  ** ***    **  
   *  **       ***** ****** **   **
 **    *    ** **  *    * ******   *      **          * ****** == s2[i])
**  ***   ****  * * ****  *  *  ** ***  ** * * **   **    *
*   * * ***  ** **   ** **** ** *    **       * ****  * **    *    ** **      * * ** ** *
  *    *      *    *  **  **** *   *  *   *  *  **
 
 *  *** * ***       * ** **  ** * 
 
 **** * *    ***  * *    **** * **    *****   == length)
******** *     *** *  *  *** *   
*     *  *  **   * *** ** * * *****        **     * *    ***  *  ****  * ****    is a prefix of %s",s1,s2);
* * * *** * *  *    *  **  ** ****** 
 
 * *     ** * *      *  ** * ***** **    
 *  **  ****   *   *  ********
* ** *  * * * * * ** *    *  *** **    ***   * *  *** **     ***** * ** *    is not a prefix of %s",s1,s2);
*  *   *      ********   **  *  **   
 return 0;
  *****  **   *   * **  ** **   
 }

int main(void)
{
 * ****** *    *****     ***   * s1[100];
* * ** ***  **   *** * *   *** s2[100];
**  *  **   * ** **** *** i,j;
 * **  **      ** ** ******
  * * *** * *** *  **** ****   ***   ** *  *** s1);
* *  *  * *    * * * ** *** * ***** *  *  ** * s2);
** * * ***** *  * *   *
*   **   * **   *****  *  ** * ****  
**    ****  ** **   **  * **
* ** **  *   *  *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** * * *  
#include  **  * ***   *** **

int prefix (char st1[],char st2[]){
    **  *  **** ***    *   *   len=0, i, cnt=0;
   * *** ****   **  * *  * 
**   *      *** * ***   = (unsigned)strlen(st1);
**  * *       ** *  *  * ** 
** *  *** *  ** * *****  ** *  (i=0;i<len;i++)
*  **  * ***  *  **   * * *  * 
  *   **  **   (st1[i]==st2[i]){
* **  * ***  *     ******  *** *   ***** *** * ** * *** *  ***  * *** ** *  **  * ** * *
*    **  * * * ****  ** *  ***     * ***    * **** *
 ** **  *  ** ******** *
 *  * ***      * *      * ** *    (cnt == len){
*  * *  *   **    **** **** **** *  ****   *  * **   * *  *     1;
*   ***** *  ******* * ** 
* * *   ** *** *  * *** *** ****
   * ** ***  *    **   ** **  ***** 0;
  ** **** *  ** ******  *   
}

int main(void) {
  *  ******  **     * *    * *     st1[256];
*** ********  *  * * *** *** st2[256];
  * * * *** *    *   **  **  **  *   *** *****   ** ********  st1);
  **** ***** ** ** * **   * ** ***       **  * **   st2);

***** * ***    **   ****   *** (prefix(st1,st2)){
* **  ** ***  * **** *  ** **** **    ********  * * *  is a prefix of %s", st1, st2);
    * *******  * ** ** 
  *  ****** *  **  * *  **  *****
* *** **  * *  *******  * * * ****   *  ******  *******   *  **** ** *  is not a prefix of %s", st1, st2);

  *   ** ** *** * *   * *** *  0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
    **** **    ** * *    ***  *  * **  *     *
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
 *** *      **** * ***   * *** **  **  *   * ****
* *    * ****  *    * * ** ** **  *  ***   ** *   * * ******  ********     **  *  **  
 * * * **********  *** ** **  **  *  ***   * * **  ****  **   *** * *  **     *     ***** ** *  ***   
  *** * **   *   *  ******    *   *  * * *   * ******** ** ****  *****  * *  ** **     ***  * **   *    **** *  **  ******* ***** *        *** **      ** *   is not a prefix of %s",a,b);
**  * * ************ * **     * *** * *  **   * *     * * * *   ****   *     **  *          ****  ** * ********* ****   **  
* *   *** *    ** * *  **   *  *   *   *  *  *   ** **  *********   * *  *  ***** *  ********* *****  * *   *
       * *  *   **   * * **     ** * ***  ** *    *   **** ***** * **  *  *** **  ** *  *
*** ****  ** *    ** ***** **  *   * * *  ****  *** *** ** *   ***   *  *  ** **  ***   * ******** * *** ***  ** **
  * * *     ** **  ***** **    *    *         *    *  ******** * **** * *** *    * **  *** ** *  **  * **   ** ***     * *    *  * *** **  ***  is a prefix of %s",a,b);
*    *  * *    * * *   * *******  *  ** *   * ** ***      *  ********* ***   **  **** *  *  ** *  *** ** ***   *  ** *  ****  *  * **** 
** *  *    * * ***** **  *   ** * *  ** *    ***    *       * *    **  **  ******* *  * **   * ** **   * *   
 * * *   * ***    * *** * * ** **** * *  ***  *  **




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
** * *** **** **  *** * * *****  **   *   *    ** 
** ** ** **   *  ****  *  ** * ****  *  ** * *** ** *****

* **   *** ***   *  *  * * **   * **   **** * * ***    ****  * * *  ***** *  0)
** *      * **** * * *   * ***** * * **** ***   *  ** * ***** ***  *   * * 
 ****** ***       **** * **   *  * * *  * ** *  **** *  **  * *  *** *  **  *    **     *  * ***** *** *  is a prefix of %s",pre,str);
 **   * *** ** *    *** ****     ** ** * *** * **   ****    **    ****
**  *   **  **    * *** *****  ** *  *  *   ***   ******  *
  **** * *   * ***  * * ***   * *  *****  * *  * * *  ******     * **  *   *  * **
** *   *  ** *       ***** ** **       *   *     * *** * * ****   * ** ***** *   ** *   * * * **   *   *  ** * ** **** *  is not a prefix of %s",pre,str);
*** * **   * * **   ** *    **   ***  ****   *   * ***  ********  *  **** *

 *****  *** *   * * *  *    ** * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
*  ***     *     **   ***** *** a[100];

   ***  * **** ** ********** **  ** b[100];

 *   *  ****  * *** *  * ** ** i = 0;

**  *   *  * * *** * *   *  prefix = 1;

* ** *  *  ** *  *      * * ***** ***    a, b);

 *  * ** **  * ***     ***   len = strlen(a);

**  *        * ******  **  ***  = 0; i < len; i++)
* ** **  **   ** ****  *  *** **
  *  *    * * *    **  * ** **  *  ** * *  ** *** *   *****    != b[i])
**  *   ** **  ***        * *** **** **   **  *    
  *  *  * *  ***    * ****** ** * **** *** *** ** *   ** * ***  ** **   ******** *** *  = 0;

 **** *  *   **  ****  ***  **  ** *         *  *   ** * **    * *   *          is not a prefix of %s", a, b);

*** *  *   *    ****  *****    *  ** ***** * **** ***   * *     *  * * * ****  * * 
******    ** *  **  *  * *  *****   ** *  *** *   ***
*   **  ** * *  * **      * *
  ** ** ****** **      *** **  * == 1)
*  ***  * **       ***    ***
        **     ****   * ****    ***** *** *   *   **  * ***     is a prefix of %s", a, b);

 ** * **  *    ** ** * 
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * **    ** ***    
#include  ***** *   * *  ** 

int main() 
{ 
*  **  ** *** ******** *  a[100],b[100]; 
  ***  **  *****   * *  *   i,j,prefix = 1; 
 **  *  **     ** * *  *  *** * * **     %s",a,b); 
  ** *  ** *  *  *        len = strlen(a); 
****   * *   ****** * ** * ** *  * = 0 ; i < len ; i++) 
* **  *** *     * ****  ****  
  ** * ***  * *  *    * * ********* * * **   ** * ** != b[i]) 
*   *** ***** *** *   *     **** ** ** **     * * *   ** *    
* **    * *** ***** ***    *  ** *  *  *  ** * **  * *  * ** *  *   * * * *** ** = 0; 
* *** ****  *****    *    *  * **  **** *        *   * * ** * *  *  ******* * *** **** * **   *  * is not a prefix of %s",a,b); 
** *    *** * *     * * * ***  *  * *   **   *  **** * * * ***   *  *    ** *** *** 
** *** * * * **   * *** ** * *   ***** *   ***** ** ** 

 *  **    ****    **    ***   *** 
 **  ****  *** ** *** **    * == 1) 
 ** **** *  ** *     *   *    *    ****** ******* **** * *   is a prefix of %s",a,b); 

 
*  ***  *   ** ** **** **  ****  0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   **  **** **** 
#include   ***       *

int main()
{
 *   **  *** * ***    *    *    a[100],b[100];
****    * *   *   ***** i,j,prefix = 1;
 * ***** *   ***   * * * *  *  **   %s",a,b);
 **  *** *        *   *    ** len = strlen(a);
   ** **    ** **  ** * *  * *** ** = 0 ; i < len ; i++)
    **** **  ** ** **   **  
**  ** ***     *  *** * *   ***   ** ****  ***   ** * != b[i])
  *** *** * * *    ** *  ***   * * *  **  **  ** *
*  * * ** **  * ** *  **   ***** *** ******  *  *** ****  ** * ** * ***** *  *** ** = 0;
 *         *     *  **  *  *   *** ***** ***  ** *** * *    **        * ***        * **  ****  *   ** is not a prefix of %s",a,b);
***** **   **  ** ** * * **   ** * *  **  ** ** **   **  ** * * * *  *  **   * ** * **
* * *      * ***  *** *** ** ***  ** * * ** * * *    **

  ****  ** ** ****       *  
***  * *** * * *  *  ** * * == 1)
 *  *  ** *  * * * ***  **** * * *  *   *** *   * *     ** * * *     * * is a prefix of %s",a,b);


*     *     ** ** * *  * * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   * ***  *  * 
#include   **  **   * * * * 

int prefix(const char *pre, const char *str)
{

  ******* **  ** * * **** * *** ** **  *** ** * *
* *  **   * ****   **     ***** * *** ** **      ** **  * 0;
 * *  ** * *   * *  *** * * **   *** * * * ***
** *   *  * * *** *  *** * ****    ***** ****  *  **** * 1;
   *  * **** **   ***** *** *** return 0;


}

int main()
{
***  ****  * ***  * ****   ** pre[100],str[100];
*     * ** *  * *** * **
 **  ** * *            ***    * *  * ******  ** *
* ***    * * **  ********   * * *  *  *
****     *   **  ** **   *    ** *** * ****       ** *  *   *   * **   ****  * is a prefix of %s",pre,str);
*  * **  *** *    ** **** *** **
**** ** *  * *  **   * * ** * **   ***      ***  **** *       * is not a prefix of %s",pre,str);
    **   *     ****** ** * ** *   0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
*** * ** ***  ****     * **   c;
 * *  *  *  *  **  *  *    *  ** *  **   *   *  
  **     * *** **     *** * * **** *  **  *** * **  * ** ***  0;
  *   ** * * **  ** * *** *  ** ****
 * *** * **   **     ** **  * * 
  *** *****    ** * *   **        *  * *    *   ***  **  * ***    *    ** of a string
**** * ***  ******  **** * ****  **  ***   ****  *** * **  *   * ** **     ***   * *** * **  **    *
**     *** ****** *  *** *****     * ***     ****  **      * * * * * *   ***       **  **    * ** *    ***  *   ** 0;
 * *   ***   * ** *** * *  * **    *  ***  ** * * **  
*** *   ****   ****      * *** ** *   * * * * *  *** ** *  1;
    }
}

int main(){
**   ***   **  *  ** * * **  a[100],b[100];
  *  *  ***** *** ***    *  ***    ** %s",a,b);
 *  * * * *  *  *   **     *** ** ** 
***  ** * *** ***  * ** ***  *  *  *****     * *  *** **     *    * * is a prefix of %s",a,b);
* *       * *** * * *    *  *   **
***       ***** ** * **  ****  ***    * * **    * ***  *   ***  *****   is not a prefix of %s",a,b);
   ** * **  * * **** *  **** *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 *  *   ****    *   *    * *    p[100],s[100],a[100]={};
*  *  **  *****  * **  *****  ** * t;
      ** *    *** ***  * ***   ** *** ** *
*  *** *   **  *****  *** **  ** *  * **
*   * *   *** * **  * **** * * * %s",p,s);
** *  * **   *     *  ** ***   
**   **** *  *    *   *****   ******** 
*  **** **  * *** *   ** ****  **  
 *  ** ****  * *** **   **** *** * * * **    
** *  * ** ***  *  *  * * **  ** *    
**   **   * *  * *  * *       * *  *  *    * **   **** * *** ****   *  ******   is a prefix of %s",p,s);
***  ***         ** ** ***   
 ***       *     *   * ** *** *
 ***   *  *  *  * *  *  * *     ***  ***  *   ** is not a prefix of %s",p,s);
   *  ** ** ***  *** ** * ** **
**  **   * * * **  **** *       * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.205
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 13.1k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 8.8k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 12.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users