1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7.3k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
* *  **** ** **  ***** * ** **  
 *** * **** **  *  ***   * * * * **  *   *       **  *
    {
 ***       **** * *  ***    *   * **   **    ** *  *  *    (i=0; i<=strlen(string2)-1;i++)
 **  *   ** *  *     *** * *** *  ***   * **   *    **  * *** *
* *   *** *     *** *** * *  ****** ****** ** * *  * * ** **  *** ***   *  ** *  *  *  * (string2[i]==string1[i])
 ***     * *  *****  *** **** * *    ***   *   ** * *    ******   *   ** * **** 
 *  ****    ***  **   *   ***  *  * *  * ** ***** ***    *  ** ** *      * *  *  *** **     * * * ** * *** ** * * ** *  **   ***
*  * ** *   * *  **     ** **  * ** **** ** *   **   *  * ** ****** * ****** *
 *   *  *** *  ***  *  *** ****** ****** ** * * * *  *  *   
****** *    ** * * *   * *** ****** ***  **   **   * ** **
****    * *** ***   *** **** * *  *  ***** ** * *
 **  ** ** *     ******** *** ** ***** **  *   *** ** ** **  ** ***  *****    **   *    * * is a prefix of %s", string2, string1);
* ** *   *    **      *   * * **  **   ** * * **
* * * * *  *****      **  * * ********* ** * *    ***
   * ***  ** ** * *  ** *** *** *   ***  *** * * **   *   
*   **  * * *** *  * * * **     **    * *** * *  * * **** * *  ***  * *  **** * *  *******     is not a prefix of %s", string2, string1);
*      * * ******  *    ******  * ** * ** ** **** *  ***
    }
  * *  *   *  *   *** *****    *  * * *****  **  * ****** *
    {
 ****  * **  **** *  ***** **** *      *      *  ***      (i=0; i<=strlen(string1)-1;i++)
*         * ** *      ****   ** ***  *    *    **   *
* *  ** *   ***  *  *       *  * ***** *     * * *    * * * **       ******** *** (string2[i]==string1[i])
     *  *** *   * ** **** * * * * **  *** ****  ** **  * ****  **** *    * *
****     ** **      * * * * * *     ** ***  **  *   * * ***  *   *** ** ** ** *   **** **** * ** **** *  
**   **   ***  ***  *   ****  **  ***   **   **  *  * **    **  ** *****  **   * * * **  
*  *   **** *** ****** *  * ***   ***   ****    * **
 ***        * * ****** *** *    * *   **    *** ***** * 
  **** * *  *** *** **     * *    * * ***  *******  *   *
 *  ** ** **  *   *******   * * * ****    **   **  *    * *   * *  *    **** *  * **  *  is a prefix of %s", string1, string2);
 *  ** * **    ** *    ****** * *  * ****** *  * *** 
  * *** * *   *    *** *  **   **     *     ** **   ***
  * *   ** *** ****** * * **   * *  * *  *    ****  * * *
   *  *** * ********* * *  *  **   **** * *  * * *   * **  ** ** ****  *  ** *    *  ***** is not a prefix of %s", string1, string2);
* ****  * * *** * * ***** *** ***  ** **  ****
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 *  * * * **  * *   *   *  **  **  * *   *  %s", chaine1,chaine2);
   * * * *    **  **  * *** *    *   *    *** 
* ***  *   *   * ****    *  **  0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
****  ***     * * *  * **** lenght1,lenght2,c;
 ********  *** *** ***   *  *** b[100];
*   *   ***   ***    * *   a[100];
* * ** *  * * *** **  ****** d[100];
 **        ***** * *  ********** **  **** * * 
   ****  **      * *  *  *** * * ** * *   **  **  ***
 ***     * **  *   **  ** **** **     *  *** *
*    **  * ***  *** *  **  **** ***** ** **   
*  ** * *** *  *  * *** * ******** * *  * *  ** 
*  **  * *   ** * * ** ***
****  ** **  * * *** *  ** * **   ****         * **** ***** is a prefix of %s",a,b);
***** * *  ****  ***   ***
* **  **** * *** *  *  * ***   
   *  *  ** **    **  * **
 *  **       **    *    ** *** *  * *  *** *** ** *   ** *  *  * is not a prefix of %s",a,b);
**  ***** * ****  * *     **
  **  ***** * ** *****  ***  ** ***** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include ** ******* **  ****
#include  ***   ***  
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
****   * *  ***    i;
**** ** *  **** ***  ** * *   
  {
*** **   ** **    **    **** *  ***  *** **  A[i]!='\0' && A[i]!=B[i]   )
**  **   *  * **** *    * *** ****** * **** ** * * **  ** ***   *** * **    0;
 *  * * ****    * *  * *   * **  ** *  *   *    ** *
*** *    * *****    ** * *  *  *** *  * ***** * *****  ***  *** * *   
  }
    ** * *** *   ** 1;
}


int main()
{
    ** ****     * *    ** **   * a[n],b[n],c[n];
*** * ****    ************ i;
 *  **  * ****   *   ** ****   ** * *   *****   
 **  * * ** ***       *   *  **    ****   
**  * ** * * * *      * * *  * (aa(a,b)){
********  *    **  *  **  **** *****    *  * * * ** * * *  ***    *   * *  
 *** * * *   *  *   **  ****   *  * * **  *  * ****  ** ****  ** * ** * ** ******** ** *  *  *
     **** ******** ***  *   ***** **  * *   *******    **** * *  *  *   **** *  *    **   * * * *  ******
* *****  * *** * *   *         ***  *    *   *****    **   ***** * **   * ** ** 

       **  *    *** * *  **    ** ***  *    * **   *
* *  * *** **  *   * **  *       * * * ****  *    *   ******* ** ** *   * is a prefix of %s",c,b);
 *  ** **  ** * ** *  *   * 
*  *  * *** *** **  * **   *** *
**** **  *   *   *   ** **  ***    * * *  *   *   ** **** * **  **   is not a prefix of %s",a,b);
   ** **  * **   ******* * **  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** *  **      *
 * *  ***    *  * *
int main (){
char   * **  **
char  **  ***
**  * **  ** *  * string1: *    **
*  **    *    ************ 
* *  *** *     *** string2:   ** * 
 * * *** ** *  *  **  ***  ** 
** *  *   *  **   *   *
 **   ** *   **  **  **  *  * **    **  is * **   *** of *  ***    ** ****
else
******  ***** *  * ** ***  * *   * *** is not prefix of ** *   *** *** *  * *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    ******* **  ** * 
#include ** ***  *    * **
#include ****   *   *    
#include * ** ** *    
int prefix(char p[],char s[])
{
*  **  *  **  **   **  *    *   **** **
* ** *     **         * * * *   0;
* * *  *   * *    * * if  ****    ** *  ** **
   *  ** ****   **        * *** 1;
  ***  *** *****  ***  **
  *  ***** *  *  *    **   **    **** 0;
}

int main()
{
   *   *** ***  * **  *  p[999],s[999];
** ** *    *  **   * * *     *** ** ** *****    
 **** ***   ** ** **    * *   ****** * *  

  *  ***  *  **  **           
  ***  ****   *  *** ** ***  *   *  *  is a prefix of %s",p,s);
* **  *   ***   * *  **  *
*   ** **   **  * * *  *****   *  **   is not a prefix of   **    **

***** * **  *  **** *  0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * *     **  *  
int main()
{
** *  *** * *** * *** * *  *** *** length1,length2,c;
**** *    ******  * *      *   a[100];
   *** **  *  ** * * **   *   * b[100];
*       * *  *  **  ** **** d[100];
 *   *    ** ****** *  ** ** ***** **   **   
  * ** *  *   * *  **       *  *  ** ****  *** 
  *   **   ***  *  * * * ***   *** * *
*    **    ** ** * * *** * ** ** * *** 
if (strcmp(a,d)==0)
    ***  ** ***  **  ** *
   *  ** ****   * ***       ******** **** *****  *** *  ****   **  is a prefix of %s",a,b);
* * * *** * * **  *  ** *    * *
   **    *   **** ** *  * * * **  *   
*  *    *** *****  **** **
** ** **** **  *  *********   * *   * ** * **    *  *  *  **    * is not a prefix of %s",a,b);
*   **   *   *  **  * * ***  * *
** * ** **** * * * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * *****
#include *    *  ***   

int prefix (char     *  ** str2[])
{
   *** ** * ****  ** ***  length=0,  * ***
*  ***  *** * *  *  **
** ****** ** * **   *   **   ***  * =      ****  ** ** 
    * ** *  *    * **** *    *
* ** *** ***  ** *  *  **   * ** ** * *  ****  
* ** *    ** *  **  *  *    *   * *** * ****
*** **   **    ** *    ** if ****  * ** 
      **    *** *  *  *        **   **    **** * *  ** ***   
*   * ** * **  * *   *  ***     }
 ******          **** * *   * *******
          *  *   *   **  (count == length)
* ** * *  * * *     *  ***   *    ****   1;
   * *      * ** ***  *  ** * else   *  *  0;   *****  **  * **   **  
 *** **  *   * *         ** *   
}
int main(void)
{
 * *    *** ****     *  *    *  * **  ** ****   **
   ** **  **    * ** *  *
* ** ** ** *   *  * *  * ***  * ***   *     *** str1, str2);

******   *  * *    ** *****  **   * * ***  
   **    *     *  {
*  * ****  *    *  *   *   ** * **  *   **  **    * **  *** *  * is a prefix of **  * *** str1, str2);
* ****  * ** *  *   *  *
**  ** * ******        ** * ** 
**  *** ** * ***** * ***  **  ***    ** * **  *    *  **  *  is not a prefix of ***       str1, str2);

* * * ** * *  **  *** ** ***        0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *** ***** * *
#include * *   *   * *
#include * * * *  * ** 

int main()
{
** *** *  ***        * * prefix[100];
*   * *  **      **   **  word[100];
 *        * *     * *   *   ** ****  * **   %s", prefix, word);
** *     *  *   * ***  * * * ** * i;
* *** * ***     * ** *   *    *** = 0; i< strlen(prefix); ++i)
  ** *  * **  * *   * ** **   **
* *   * *  * *** *** *   ***  *  *   ***    * * *  **  **  *       
* * *    **   *****  *    *  * * * * ** ****   ****    
 **  *   *** * * * * * ** *  *** * ** *    * **   **   *  * **  *** ***    * * ** * *  **     * *** is not a prefix of %s", prefix, word);
   *** * * *  *****  *   *  *** **   ** * ***         *  **     **  * *   *    ** ***   0;
* *  ** *   * * * * *  ** *    ** ** *  * **   * *    **** *
***   ******* * ** **    * 
*** * *  * *   *   *  **** ****   *** * ******  ** is a prefix of %s", prefix, word);
*       * *  ***  **  *   * 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  *  ***
#include *** *  **** *** * *
#include ****  ** **  

int main()
{
 ** * **  * **  **  *   *  * prefix[100];
* *  *  ** **  * ** ** *  word[100];
 * *  *  *   *** * **   *** *  **  * %s", prefix, word);
* *****  *  *   ** * **** **  i;
 * * ** ** * * * * *** * *** ** = 0; i< strlen(prefix); ++i)
* * ****  ***  *   **** **
 **   *    *** * * ***   *  ******* ** *   *****  *** ** * * **  ** 
   * ** ***  *        * **   *  *  ****** * ***     *** **
*  * *  **  ** * ** * * ***** **  * * ***    * **  ** * **  * *  *       * *    ** ***      ** * is not a prefix of %s", prefix, word);
   **   ** * *** **  ***   * ******** ** ***  **** *** ** **   * **** *  * ***  ** **   0;
   *  * *  * * **    *  ** * * ***  *   *  *  **   ** *
 * *     * * * *  ** *   
 *      ** *  **** *    ** ***   *** ***** is a prefix of %s", prefix, word);
* ** *  *      *  * **  ** **** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * *     ** *** ** *** * 
***** * **         **
      *   ***  * * ** *    * *

int main()
{
** **  **  ***  char   * ** 
  *  ** * * **  * char *** 
 *  * ** * *   *    * * ** * * *  **   ***  word);
  ** **  * **** int i;
  * ** **  **  for(i = 0;  * *    *   *   ++i)
*    *   **** ** {
  **** **    * * *    ** ***   ***** *   ** *
* **   ** *  ** *    * {
   ****  * *     *** ** * *   *  *      **** **** * ***** is not a  * of * ** **** * * ** word);
  ** *  * ** * *   * ****   ** ***   * * * * * *       0;
 *** ** * * * * ** * *  *     *  }
*** *    *******   }
***   *  * *    ***   ***  * is a prefix of    * *  * ** word);
 **  **  ** *   *   **  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.200
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 10.6k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 7.1k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 9.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users