0 like 0 dislike
11k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited

edited by | 11k views
0 0
12345

27 Answers

0 like 0 dislike
Hidden content!
#include * * ** * ** ***
#include * * ** * ** *

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
* **** **** * * * ** **
 
***** ** ** * * ** * ** * *** * **** * ** ** *
** * * * * * ** **** * * * *
* ** * ** ** * * * ** *** * ***** ** **** * ***** * == s2[i])
* ***** **** * *** ** *** * * ****** * * ** *** *
** *** ** ** * * ** ** **** ** *** * ** ** * * ****** ******
**** * **** ***** * * * * * * * * ***
 
**** * *** * * *** * *
 
******** * * ** ** * *** == length)
******* ** **** * * * *******
**** * * ** * *** * * * *** * * ****** ** ** * ** * is a prefix of %s",s1,s2);
** ** ** * * * ** * * ** *
 
* * *** * * * **** * * *
*** * * * * * * ** ***** **
* ******** * ***** ** * * ** * * * * * *** ** ** * *** *** is not a prefix of %s",s1,s2);
* ***** ****** * **** * *** * *
 return 0;
** ***** * * *** ** * * ** **
 }

int main(void)
{
** * ** *** * * * ** *** s1[100];
* ** ** ******** * * ** **** s2[100];
* ** ****** ** * ** i,j;
* * * ********** *
***** * ** * * ***** ** *** * * s1);
*** ** * ** * ** * ** * ***** ** * s2);
*** * * ** * * * * *
*** *** *** ** * * **
* * ** * ** *
* ** ****** ** ***** * * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include * * *** *
#include ** * ** ** *

int prefix (char st1[],char st2[]){
* * * * * * * * **** ** * ** len=0, i, cnt=0;
* *** * ** * * *** *
*** * *** ** ***** ** = (unsigned)strlen(st1);
**** ** * ** *** * *
** * * ***** * ** * ** (i=0;i<len;i++)
* * * ** *** ** * * *
** * * *** (st1[i]==st2[i]){
*** * * * *** * ** * * **** * * * * * * ** ***** ** * * ** * * * *
* * *** * ** * ** **** ** ** * * * * * ****
* *** * * ** * ** ** *** **
* **** * *** * ** ** (cnt == len){
* ** *** ******* * * * * **** ** 1;
*** * **** *
*** ** ** * * * * *
** ** * * * * **** *** * 0;
**** ** ** ******* ** *
}

int main(void) {
* ** * *** * * ** st1[256];
* * * * * **** * *** ** st2[256];
* ** * * * ** ***** * ***** * * * * ** * * ** st1);
**** **** ***** * *** ** *** ** **** * * st2);

**** ** * * ** ** ** (prefix(st1,st2)){
** * * * ****** ** * * ** *** ** * ********* * ***** is a prefix of %s", st1, st2);
* * ************ *
* ** ** * **** * **** *
* *** *** * * *** * * * * ** * * ** *** * * ** * * is not a prefix of %s", st1, st2);

* ** * * ** ** * * * * 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
** * * * * *** **** * *** * * *** * * ** *
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
*** * * ** ******** ** * **** *** * *** * ****
***** **** *** * ** * ** * * ** * * * ** * * *** ** ** * * **
*** ** * * *** ** ** * * * * ** * * ** ** ** * * * * * ** * **** * * **** * *
* * * **** * **** * * **** *** ** * ** * *** ****** **** ** * * ** ** ** * *** * *** * ** ** * * ****** is not a prefix of %s",a,b);
* ***** * * *** * **** ** * *** * ** ** **** * ** * * ** ** * * * ** ** *** ** ** * ** * * *** ***
* ** ** ** *** **** ** * **** **** *** **** *** *** ** * * ** * * * ** ***** * ** ***
** * * *** * **** * * * *** * * ***** * * * ** * * ** * * *** * **
*** * * * * ***** ** * ** ***** ** *** ** ***** * * ** * *** * * ********* ** * * ** * *
** **** * * ** * * * * **** ** * ** * * ** ** ***** ** **** ** *** * * * * * * ** * * * **** ******** *** is a prefix of %s",a,b);
* * * * * * ** * * * ** ** ******* *** ** ** ***** * * **** * ********* * * **** **** * *** ****** * ** * * * ** *
* *** ** * ** ** * * * **** ** * *** ** * * ** * * * ** * * * * * * * * *** ** ****
* * ********** *** *** **** * *** * * * * * *** ***




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
*** * **** * **** ******* * *** * * ***
* ** * * * ****** **** ***** * * * *

**** ** * ** ** ** ** ** * * ** *** **** * *** *** * ** 0)
** ** **** ***** ****** * *** * **** ******** * * * *** * * *
* *** * **** * **** ** * * ** * * ** ** * ** * * *** * ****** * * * * * * * * is a prefix of %s",pre,str);
* ** ** ** * * *** * * **** ** * * ** * * * * *** ** ***
***** ** * ** * * ** ** * * ** ***
** ** **** ** * * * ** * * * * *** ** * *** *** * * **** * *** *
*** *** **** ** ** **** ** * ** ** * *** ****** **** * ** * * * *** * * * * *** * ** *** is not a prefix of %s",pre,str);
** * ** **** * ** * * * **** ** * ** **** ** * ** ** *** *** *** **

* ** ** * ** * ** * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
***** * * * * **** * ** a[100];

* ** ****** ** * *** * * b[100];

** *** *** ** ** *** * i = 0;

* * ** *** ***** ** prefix = 1;

* * * ***** ** ** * * ****** * ** ***** ** *** a, b);

**** * ** * *** * * ** * * len = strlen(a);

** ** * ***** ** ** ** ** = 0; i < len; i++)
* * ** * **** ***
** ** * *** *** ***** * *** * * **** ** * * != b[i])
*** * * ***** * * * * ** * ** *** *******
* ** **** * * * * ** ** ** ** ***** * *** **** ** * * ** ** **** = 0;

* **** * * ** * ** *** **** * * * * * * *** * ** ** *** ** * **** is not a prefix of %s", a, b);

* * *** * * *** * ***** ** *** * * * * * * **** * ** * ** ****
* ** * * ** ** ** ** * * * * * *** * **
* * * * * * * ** *
** * ** * ** * * * * *** * ******* == 1)
* * ******** ** ******** *
* ** *** *** *** * ** * * ****** ******** * ** * * is a prefix of %s", a, b);

* ** * *** ** **** *
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** ****
#include *** * * ***

int main()
{
* * * *** ** *** ** a[100],b[100];
***** **** * * ** * ** *** * i,j,prefix = 1;
** * * * * * * * * *** ****** *** * * %s",a,b);
* * * * ******** ** * len = strlen(a);
** * * * * * ** * * ** = 0 ; i < len ; i++)
* *** ** * *** * ** **
*** ** * * ** ** ** *** * * ********* * != b[i])
*** ** * ******* ** * *** * ** * ** **** * ***
** * ** *** * ** *** * **** * ** ** *** * *** ** * * * **** ** = 0;
** * ***** ** * * * *** * * **** ** * ** * * * ** ** * **** * ** ** is not a prefix of %s",a,b);
** *** **** ** * ** **** **** * * **** * ** ***** *** * *** **** ***
* ** * * **** * * *** ** *** ***** ** ** *

* **** ****** * * *
**** ******** ** * ** ** * * * == 1)
* * * * ***** ******* ** ******** ** **** ** ** *** is a prefix of %s",a,b);

 
* * ** * ***** * *** * * * 0;
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * *
#include * * * * *

int main()
{
* * *** **** ******* * ** a[100],b[100];
* ** ** ** ****** i,j,prefix = 1;
* ** * **** * * ** *** * * %s",a,b);
***** **** ** * * **** len = strlen(a);
** ** ** * * *** * * *** = 0 ; i < len ; i++)
* * **** ** * ****** **
** *** ** ***** *** * ***** ******* * ** != b[i])
** ****** * * ******* * ** * **** * * *** *
* **** * * * ** * * * * ** **** ** * ******* ********* ** * ** = 0;
** * ** * * *** **** ** *** ** * **** * * ** *** ** *** * *** * ** *** ** * * *** is not a prefix of %s",a,b);
* * **** ** ****** * ** * * ** * * **** * **** * * *** ** * * ***
** ** *** * * ** * * ** * ***** * *

** *** * ***** * ** **** *
* * *** * **** ********* * * == 1)
****** ** * * ** * * * * * * * **** ***** ** ** ** *** *** is a prefix of %s",a,b);


* *** **** ** *** * * * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * * *
#include * ** ** *

int prefix(const char *pre, const char *str)
{

***** * ** *** ** * ** * * *** * ******
*** * ** * * ** ** * * * ** * * * * ** 0;
******* * * * ***** ***** * ** *
* * * ** * ** *** * * * **** * * * * * * **** * 1;
* ** * * * * * * *** return 0;


}

int main()
{
** * ***** * * * ** pre[100],str[100];
* * * *** ** *
** ** **** *** ** * ** * ** * ** ** *
** * * ** ** * * ** *** ** ** *
***** ** *** * * ***** ** *** **** * *** * is a prefix of %s",pre,str);
* * * *** * * * * * **** * *
* * ** **** * * ** ***** * * * * * *** * * * is not a prefix of %s",pre,str);
* *** * ** ** * ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
* ** *** ***** ******** * * * * c;
* ** ** *** *** * * * ** ** * * ** * ***** * *
* ** ** * ** ** * **** * * * ** * ** * ** * * 0;
**** * ***** *** ** ** *
** * * * *** * * *
* ** * *** ** **** ****** ** * * ** ** * * *** ****** of a string
** *** ****** * * * * *** * *** * * ** ** *** * * * * *** ******** * * *** *
** * * * * *** * * ** ***** * * *** * ** ** ** * * *** * * **** ** ***** 0;
*** ** ***** * **** ** * * * * *** **** * ***
* * ***** * * * *** ** **** * **** ** * * ** ** 1;
    }
}

int main(){
** * * * * * ** **** a[100],b[100];
**** * *** **** * * ** %s",a,b);
** **** ***** ** ** ****
* ****** * * *** * *** * * ** * *** ** ** *** **** **** * * is a prefix of %s",a,b);
* ** * ** * * * *** ** *
** ** ****** *** * ******* ** *** *** * * * * * * * * *** is not a prefix of %s",a,b);
***** * * *** ** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
**** * **** **** ** * p[100],s[100],a[100]={};
* * * * ** **** * t;
** * **** ***** * ** * *** * **
**** ** *** ** ** **** * * ** ** * **
* * ** *** *** * ** * ** *** %s",p,s);
** ** **** * * * * * **
** ** * **** * **** ****
** *** * ** *** * **** ***
** * ** ** * * *** *** *** ** * *
* *** ****** ** * ** * ** ***
****** * ** * *** ** * ** **** * * * **** ** *** **** ** is a prefix of %s",p,s);
* ** ** * * * * * * *
* * ****** *** *** *******
* * * ** * **** *** * ** ** * *** ***** ** ** ** is not a prefix of %s",p,s);
* **** * * * ***
* *** * ** * * *** *** * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.197
©2016-2025

Related questions

0 like 0 dislike
57 answers
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited
| 15.9k views
0 like 0 dislike
29 answers
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited
| 10.8k views
0 like 0 dislike
53 answers
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited
| 14.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users