1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7.5k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include  **  ** * ***  **   
#include  **  * ******  

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
* **** * **   *** **  *  * **
 
***    *** * * **    *** *  *** * ** **  ** ***   * 
 ** *  *** *** ** ****  *  * ** 
**  **    * ** * ***   ** ***** * *** *  **  *   * * ****   == s2[i])
 * ** *********** * *** * **  *   *     ** * ** ***  
 **        **   *   **  * ** *** * ***  *  * *   ****  ***** **  ** * * **  * * * **
   ****   **  ** **    ** **   ****   **** *  *  * ***** 
 
* * *  *     * ****   ***  **  ** * * ** *
 
 * *** *     ****  * *  ******  ** * *** *  == length)
* * *       ** **    ** * **   *
  * * * **  * *  *  *   * **  *    * ** * * **  ***** *  *   * *  ** *   ** is a prefix of %s",s1,s2);
*** ***   **      *   * **** ** **** 
 
 **  *  *    *****   ** *  ***      *  
***** * *** ***   ***  *  ** ***   
 **     *** **   * *  ***   * **  * *   *** *  * * * *   ***    *     is not a prefix of %s",s1,s2);
***** *    ****  *   *** *********  *
 return 0;
  *  **    *    *  ** ** ***
 }

int main(void)
{
  ****  ***  * ** **     * ***  s1[100];
    * * *  *  *  * ** * *** *  *    s2[100];
 ** ***** *      * ***   *   i,j;
* *** * ****** * ** ***  *
 **** *  * *******    *** **  ** **       *    *  * s1);
* *   *** *   *     *    * *  *****   ** ***  ** s2);
*** * ***   ***     *   * ***  *
***** ***   ** **   *  ***  ****   * *
     ***** * * **   *  *  
   **    *****  ****     **** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ***  ** **  *
#include   * *    * ***

int prefix (char st1[],char st2[]){
   *  **  *  ** * * ****     * * * len=0, i, cnt=0;
 * **********  ***** **    * 
 *     *  * *  ***   *     **  = (unsigned)strlen(st1);
   * * ***   **** *   *
**** *    *** ***   *******  ***  * (i=0;i<len;i++)
 *   *    *    * * * **** **  *
 ** *  * **     (st1[i]==st2[i]){
***    ** * ** * * *   *  **      * * *  **   **   *      * *     ********* *  ** *  *
  * ** *** * ** * * *  ***** ***       *  ** *     *  **
 **     **  *       *  *  * *
 **  * *  * ** * *** * ***** *  (cnt == len){
 * * **    * * ** *    * *      **  *   ***  **    **   *  * 1;
** **  * ***     *  * ****
* *  *  ******* * *****
** * ** * ****  *** * ***  ****  * 0;
 **** *  * ***  ** * *  *** ** 
}

int main(void) {
**   ***  **   * *   ****    ** st1[256];
   * * ** **** ** *  *   **** st2[256];
 * * *    ** *   * *  *  *  *** *   ****  ****   * st1);
**** *  ***      *  ** * *   *    ****** *   st2);

**** **** * *   ***   *   ***** (prefix(st1,st2)){
*  *   *   ***  *  ****   *** * *       ****    * *     **** * *  **** is a prefix of %s", st1, st2);
**  **** ** **** ****    
 **  * ****  * *   ** **   
 **** ** * * **  ** * ** *****     *  ******   *  * *  ** ** * * is not a prefix of %s", st1, st2);

* *** **   *   *****  *   **  * 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
**   * ** *   **     **   *  *  *   * 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
 * *  ** *  *   **       ****** *  ***    * ** **  ** ** * *  **
**** ** *** ***     **  ****** *    * *      *        **   * *   * * *** *  * 
* *    * * ***   ****  * * *   *    * ***  ***  *   ***  ** *  **           * * ** *********** ****  ** 
  *** **** ***  ******     **  *      *  * *   ** *  *     **** **  * *****         ***  ** *  **  *  ************ **  * ** *   ** ** ** **  ***    is not a prefix of %s",a,b);
   *     *  *  * **  **** * ** *  * ****   **  ** ** ****  * ********* * ***** ** *  *  ** **   *   * *   *  **  *** ***   * * 
** *    * *       *   **  *  * *   ***   **   ** * **    ***** *** * *     **   **   ***  ** ** *** ** 
* * ** *  * *** *  * *** * *  *   **  ****  *  * *   **  * ** *** * **  *** *   * **     *
  *  ****** ** *   *  * ***  ** ***  ** *   **   ****  *  **  ** ****  ** *  *** *** *  * *** * *  ** *     ** 
*  *  **** *** **  * *** **    **  *   *  **** * *   ***   ** ** *** *   **     * ** *     ***  **  * *******  * ****  **** ****    *  ** is a prefix of %s",a,b);
 *** *** * * * **** *  *      ** * ** **  * * * ** *** **** ** *  *   * *   *  *** *  *** * *** *    *  **** *  * *    **  ** *** * *    *******
** **** ** *     **   ****** ** *   ** *    **** **  *** ** ***  ** *     **** *  ** * * **   **  * ***
** *** ***  * * * * * *   *******    ** **  * *      *  ***




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
* *  **  *   *  *   * ***  *     ** *** ** *  *** 
*  * *    *  **  *  ***     *   **** *   * *     * 

*** ***** *** *** * *  ***   **   *  **  *  *   ** ****   ***** ** *  0)
** **    **** * *****   ** *  ** ** **** ** *  ** ** * **  **** * * * **** **
 ** * *** * *** ****   **   * *  *  *** ***    ** * *** *    *   * **** *** * ***  **** *  **  ** ****  * * * * ****  *** * is a prefix of %s",pre,str);
 ** *  ** ***  ** *   *  ** *  **** *   ***   *   **  *  ** *   ***
 * * * *** ***    * ****     **  *** *** *    * ***   
*  **** * **   *  *  *   *  *     * ** ***** ** * *  ***  ** *** * *  * *  *  *   **
  *  ***    *    *  *  ****  *  **** **    * *  * *     **     * **       ** *   *** *    ** * * ** **   **  **** is not a prefix of %s",pre,str);
    ***   *  ***** * *  **    ****  *  * * ** *  * *   **  **  *  *** **  *** * *

** * ** ****** * *      ***  0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
****** * ****  *   *  *  * * ** a[100];

  * *  **  * *  * *   * *** *** b[100];

   *** ***** **** ** **    *  i = 0;

 ****  **** *  **** * * *    ** prefix = 1;

  ***  ** * *   * **  ***** * ***  **  **   **** * a, b);

  * **   * *   **  * *   * len = strlen(a);

*       **** **   ** ** *  *   * ** = 0; i < len; i++)
   * **    **  * ** * *   * **
         * * ** **  ** *  ** * * ***  ** *  *  *  * != b[i])
  ** **  ** * ***** ** * *  *** * ***  *      *   *    
 * ** ** *  ***** *****  * * **  *   * *****     * *  * **  * *   * **  *   *** *  *  = 0;

*  *    * *** **   *  ** * *******  *** *      *****  * * *** *     * ** *   **   * ** *  is not a prefix of %s", a, b);

 * *  *  **   **  ** *** ***  **  * * **** *** *** ** * **  * ******   * **** *    **  
* ** ** **  * * * *    *  ** **   ***  *   ** *  * 
    **  *** * *  * ** ****      
*******  ** ***   **   *     == 1)
***      * * ** *****   *** 
*     *****    **** **  * ** ** *  * **   ******** * * ****  *  is a prefix of %s", a, b);

* ****  *  * * *   *     
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * **** **  * * 
#include  **    * ***  * *  

int main() 
{ 
 * * * ****** ****       **  a[100],b[100]; 
    *   *   **  *  **** *  * * i,j,prefix = 1; 
*** *  * **   * *  ****    ***   %s",a,b); 
*  *  ** *** *** * **     *  *   len = strlen(a); 
*** * ** **  ** *   **** = 0 ; i < len ; i++) 
* * **  ** *    * **  ******  **  
 * ** ***** ***     **** ***     ** * * **  ** *   ** != b[i]) 
** *   * ** * **     ** ****  *  *   ***  ** * 
* **   ***  *     * **   *** **    ***  *** * *  *    * ****  * ** *   * * *     * = 0; 
*** *  * **  **  *   *    * *  *** ** ** **  *   * ** ****  ***   *    *     ***** *   *  ***** * is not a prefix of %s",a,b); 
** *     *   ** ***** ***  ** **   ** **     * * * ** **** *     * ***** ***** * **    
      *    **   **  * * **  **** *  *  * * * **  

    ** ***** *****  ** *    
   * ** ** ****  *  *  * *** == 1) 
*** **** **** *** **     *   * * *   ***  *** ** * * *  *** *  is a prefix of %s",a,b); 

 
  * **** ** * **  ***   *  0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include    *  **    ** *
#include  ** *     * *  *

int main()
{
** *  *  *   * * *** ** * *   a[100],b[100];
  ***** ** *   **** * *** *** i,j,prefix = 1;
  ***   ** ********  * **   *  ***       * %s",a,b);
* *****   * ***   ** ** ** *   len = strlen(a);
 * *  *******  ***    ** ****** **  = 0 ; i < len ; i++)
 **   * *** *  * *  ***   ** * *
***** *  *    *  ** * *   **  **  **  ****  *******      **** != b[i])
   * *  **  ******    * *  * **   * * *  * ** ** *
* **    * * *    ** * ***   ****** *****  *   **** ******* ********  *** ***    = 0;
*** ***  ***   *    *   * *******   **  ** * ** ** ****** * ** ** *  **  * ** ******   ***  ***  is not a prefix of %s",a,b);
  *  * ***  ** *  *    * **  * *  *    *** * **    *** *** *   ****  *** ** **  **
*    *   **** ** *  **  *** ** *      *** ** ** * * ****   

 *  *     * ** ****   * *** *
 * **    * *****  * ****      **    == 1)
 *  **   *  **  *  *** *    ** **  * *  **     *  **** * **** is a prefix of %s",a,b);


 ** *     *   *  ** **** *     ** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** ***   **  
#include **    ** **  **** 

int prefix(const char *pre, const char *str)
{

 *     *  * **  ** ****   ** *  *   ***   **  *
 ** ** ** *    *  *  *** ** *     *  *   ***   ***** ***  * 0;
***  *  * * * *    * *  *  * *  *     ** ******* *  *
 * **     *   ***     *  * **  * *  ** **  *    ** ****  * 1;
**** **  *   *  ** ** **   *  ***  return 0;


}

int main()
{
*** * *   ** *** **    * **    pre[100],str[100];
   * *  *****   *   **  
  **    ***   **  **   *  **  ** **    * * ** ** ****
 **  ****        ** * * **     ***    ****  
** *** **  **** ***  *   *  **** *****  ** * ***     **** *   ** ** *  * is a prefix of %s",pre,str);
*    **  * *  ****  *        * *
   **** *** ** * ****** *** **   ** *  **  *   ** * **  * *   ****  * is not a prefix of %s",pre,str);
 * ** *   ** *  ****  * **   * *** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
 * * *  *****  **  **   **  **** c;
***** ****** * *  ***   * ** *        * *** * **
**  * ***** *  ****   ** * * ****  *** ** **** *  ** *  0;
 **  *    **  ****   *    
 ** ** *     ** * ***  * **** ** *
*     ***********   *     ** * * ** ***  ***  * **  *  ****** * ***   *  **  * of a string
* *  *** ** *  *  *  * * *  *    **        ***** ** *  * * **    * *        *     *  ****  *
        ** *   **    ***   ***  *  **   ******* ** ***** *  * **  * *   *  *    *  * * *  * * * *     **   *  * 0;
*      ** **  * *   * *  **  ****  * *   * * *** * *** ***
*** * *   * **  ****  *   ***  *   *   *  * *     * ***  **  1;
    }
}

int main(){
*  * *   *** *    **  * *  * a[100],b[100];
** **    * * *** *   ****  * * * **  *   %s",a,b);
   ***  * *******  **** * * * **  *
 ***         *  **  **    *  * ** *** ** *** **   **** *  ***  is a prefix of %s",a,b);
 * * *   *    *****  *******
** ** ** * **  ***  ** * ***  *    ** ***** *  ** **     *   is not a prefix of %s",a,b);
*    *** *** **** ****  *     0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 ** * **  **   ***   ** *  p[100],s[100],a[100]={};
**  *  * *   ***   ******  * t;
*  *******    ** * ****  ****** *  ** 
*  * *    * ****  * **** **  * * ***   ** * *
   *   * **     *  ** ** * * *    ** **   %s",p,s);
 **  * ** * * * ** **  **  * ***  *   *
* * *     ** **   **     * *    * 
* ******* *** * **  **  ** *   **   *  *  ** 
   ** ***   **** *      *    **  **   ** **
** *     **** *  * * *  * ***   *      * 
*  * ** ****    **** ****   *  **    * * *******   *  * *** *****  * is a prefix of %s",p,s);
** ***  *  ***  * *** ****
****     ** * **** *    ** **   * *
** * *   * *    **********   *   **   ****  * * * **  ***    *     is not a prefix of %s",p,s);
    ** **  * * *   * **** *  *
  ** ** * * ******* **** ***   0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.25
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 11k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 7.2k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 10k views
12,783 questions
183,442 answers
172,219 comments
4,824 users