1-11 Exercise 3: Prefix of a string

Question

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited Jan 11, 2018 by semicolon | 13k views

27 Answers

Page:

Diyiel · Answer 1 · 2018-01-13 00:58:32

Hidden content!
#include  *   **  * * 
#include ***** ** * *

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
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**** * ** * * * *  *** ** ** **
 
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 return 0;
** *  * ** **  ** **     * *** * *
 }

int main(void)
{
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 * * *  *** *** ** **  *** ***** s2[100];
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*  *  * *    *  *    * *   * *
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* * ** **** **  *  **  ******** * 
*   *    * **  **      *
 *  **  *** * *   ***  **    ** 0;
}

answered Jan 13, 2018 by Diyiel (-193 points)

Stephen Richards · Answer 2 · 2018-01-13 00:46:20

Hidden content!
#include * *    **  ****  
#include ****    ** ** *

int prefix (char st1[],char st2[]){
**  *    ** ** *  *  * **** * len=0, i, cnt=0;
*    *  *  ***  **  * **
 ****  * *** ** * **** ***   = (unsigned)strlen(st1);
   *   * * * *   ***    *
 *  **** *   *** **     * **   (i=0;i<len;i++)
  ** *** ** * * *   *  *     *
 **    **    * **  (st1[i]==st2[i]){
* *  * *** * * *  **   **  * * **  ***** * *  ** * **    ** * ** ** **   ***** 
*   *  * ** *****  ** *  ** **** * **  *  ***   * **  ***
**  *****   *   **   * * **
* *  * *****  *  **    ****  (cnt == len){
** * ***    *    *    *  *  * ***  *  **    **  * *  **  * 1;
 * **** * * * * * *  ** *   
* * ******* ** *  *  **    
****  ** *    ***  **     * *     0;
* *****   *    * ****    *
}

int main(void) {
 *  *   ***  ** **   ********* st1[256];
*   ***  *   **   ******* *** st2[256];
   ** * *    ******* * **   *   **   ***  ***** st1);
     **  **    * *  * *** *** ** ** *** ** ** *     st2);

* *  **  ** * *    ** ***  * (prefix(st1,st2)){
* ** ***  ***   **  * * ****    **     *** ** *   * *  ***  **   *  **** *  is a prefix of %s", st1, st2);
* *  *** *  **    * *  * **  
 ** ****  *  *       *  * * **
***  *   * * * ****   *** **  * * ***** ** ***  * * *** *** * *    * is not a prefix of %s", st1, st2);

*   *  ***  ** ** *   *  * ** 0;
}

answered Jan 13, 2018 by Stephen Richards (323 points)

ryan · Answer 3 · 2018-01-11 22:07:28

Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
*** *  *** **   *****   * *  ***  ** *  **   * *****
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
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*** *   ** ***   **   *    *** *   **   * **  * *




}

answered Jan 11, 2018 by ryan (-301 points)

Headshake · Answer 4 · 2018-01-11 21:22:34

Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
** *  ** * ***  * **** * ** ** ***  ** ** ** ****  ****
* *  * *  ******  * *   **    * ***** ***  *****  

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***  ** ** * *    * **  *** *  * ***  *  **  *  *****   **  * ***** *   ** **  **

*     ***** *   ***  *  **  *  * 0;
}

answered Jan 11, 2018 by Headshake (-281 points)
edited Jan 13, 2018 by Headshake

Sabrina Lin · Answer 5 · 2018-01-11 21:03:22

Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
***   ** *** *  **   *  ***** a[100];

  ***** * *****  **     ** **** b[100];

*  * *    ******* *  * *   * i = 0;

  **  * ** ** *  * * * ****   prefix = 1;

* *     *  **    * * ** ***** *** ***  * ***   a, b);

***** ****  * * * ***  **  * *  len = strlen(a);

 **   ** ***  *  *******   *  * = 0; i < len; i++)
 ***** ******* *  *    **  *     
  ****   * *** * *   * **** **    **    *   *   *    * ** **** != b[i])
 ** *   * * *   *  *   ** * ** * **   ** **   **   *** ***
**** *   * ** *  * *** * *  **  *  * ** **** *** *  *** **  **** *  ** ***** **** * *  = 0;

*  **  *  *       *  *  *** *** *    **  ***  **  * ** *  ***   **         ** * ***** * is not a prefix of %s", a, b);

****   ** **** * *  *  ****   ** ** ** *   ** ** ****  *  ** *  ** ****  **  *
**     ** *   * * ****  * ** *****   ** **     *  *
     **     **      * **
 **  ******  *    *    * ***** == 1)
*** * *   **  * *   **  * ** * 
 * ** **** ** * *  ***  *  * * *  **  *   ** *  * ***    ** **    ** * **   * is a prefix of %s", a, b);

** * * ** ** ** ** * 
}

answered Jan 11, 2018 by Sabrina Lin (-285 points)
edited Jan 11, 2018 by Sabrina Lin

watty1998871108 · Answer 6 · 2018-01-11 21:00:46

Hidden content!
#include   ** * *** * ***** 
#include         ****    *  

int main() 
{ 
***** * **** *   ******* ** a[100],b[100]; 
 * * * * **      *** *   *   ** i,j,prefix = 1; 
  ***  ****  **       **   ***   %s",a,b); 
  * * *  *  ** *   ***    ** len = strlen(a); 
 **    * **  ** * *    **  = 0 ; i < len ; i++) 
        * *    **  *   ***   * 
* **   **           *  **  *   *  * ** *  *  * * ** **  != b[i]) 
   ***  **  **   * *** **** **  ** *  *          **** 
      ** **  *     * *    *** *** * *** *  *** *   ****  **** ****  * **** *  * ** = 0; 
**  ** * ***** **  *  *   ***** * *      *  *     *    ****  **   *  *  * * ***   ** ****    is not a prefix of %s",a,b); 
  *  ** *** ** * *** *    * *   *  ********* *** **  ****       ** ***   ** ** * **  
 *    *  * ****     **     *  **** * * **     ** * 

  *  **  ***  *   *   *** ** * 
***  *  *     ** *  **   *   == 1) 
* * **       *   ***    **  **  ******    *        *    **  * *  ** ** is a prefix of %s",a,b); 

 
*   **   *   * ** * * *  *    *  ** 0; 
}

answered Jan 11, 2018 by watty1998871108 (-127 points)
edited Jan 17, 2018 by watty1998871108

prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'

commented Jan 17, 2018 by The Judge (4.3k points)

prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'

commented Jan 17, 2018 by The Judge (4.3k points)

Sammi0208 · Answer 7 · 2018-01-11 21:00:08

Hidden content!
#include <stdio.h>
#include *** *  **  *  *   
#include  *  *   *   *  *

int main()
{
*   ** *** ***** * * ** **   *  a[100],b[100];
**      *  ***    ******  *    *     i,j,prefix = 1;
***  **       * * * ***   ** *    ****   * ** %s",a,b);
* * **** *  **  * ** *   ***  len = strlen(a);
 ***   *   ** ** * * *  **** *  *  = 0 ; i < len ; i++)
* **  *** ***  *  **   *****  *
 ****** **       * ***     ** ** ***  *** *      *  *     ** * != b[i])
*   ***** *  **   *  *  *** * *       **   
**     * **  ***  * ** *  **  ** *    * ** *  * * *  ** ** * ***** *    **** **** **  * **  = 0;
** * *  *   **   * *   * * * ***     * *   *** *  * **          ************     **  * ** **   *** is not a prefix of %s",a,b);
*** * * **   ** * ** *    ******** * **         *   * **  *** * **    ***** *** * ** *
 ****   ****   **** ** **   ** * *    ** *   * *

 ** ******* ***     **  **  * ****
** * * **   *  * * ** *  * *  ** == 1)
*  * **  ***      **** **  * ***** ** *** **  *** *  *   ** * *** ** is a prefix of %s",a,b);


* * *** ** ***  ** ** ****** 0;
}

answered Jan 11, 2018 by Sammi0208 (-255 points)
edited Jan 11, 2018 by Sammi0208

410530022 · Answer 8 · 2018-01-11 20:46:02

Hidden content!
#include **   ** * * * 
#include    *   ***   

int prefix(const char *pre, const char *str)
{

* **  *  ****      *     * * *   *** *  * ***
  *  * ** ** ****    **** **   * ***  * *   ** *    * * 0;
**  ****  * *   ** **    **   ** *  * ******   
  ** ******* * * *****  ** * * *   ** ****   **  * 1;
 ** *  * *    * *    ** **        * return 0;


}

int main()
{
 **** **** * * **** * * * * *     pre[100],str[100];
 **  **  **  * ****  **
** ** *     ** ***  * *   ** *  * * *  ** ***  
* **  *  *  *** **** * **  *   * *  * ******  
*  * * * ******    ***** ******  * ***** ****    * * **  * * **    is a prefix of %s",pre,str);
*     **  ** *  *  *  ** *     ***
*        **   ***** ***     ****  *  ***** * ** * ** *****  *  is not a prefix of %s",pre,str);
** *** ** *    * *   *  ****  *  0;
}

answered Jan 11, 2018 by 410530022 (-196 points)
edited Jan 11, 2018 by 410530022

LinJingYao · Answer 9 · 2018-01-11 20:28:50

Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
 *  * **  **** * * ** * * * c;
 * *   *        *   * ** * **  * ******  **  **
 * ***  *  *  **  *    **  **  *  *** *    **  * * * 0;
  **   *  *   * * **
** *  ***      * * * * **   *  
* ** *    ******  *  *      **   **  **** *   *   * * * ***  *** *  *      *      of a string
** ******    *    **  *    *      *   **   *      *  **   **    *** **** **   **** *  *  * *** *** 
*  **  ****     * *** *   **** ***** * *      * *       *** ** * *  *   **  * *****  *  ** *  **  *  ********  ** *  0;
***** * ****** * **  *  ***   *** **  **  ***  * *  *** 
**** **   * **   *  ***** *****       **  * *  * * *  * 1;
    }
}

int main(){
* *   * **  *** ***   * **    a[100],b[100];
* *  * **      ****** *  ****     *  *  %s",a,b);
**     **  **   *     * ** *** ** ***
  * ***    *   * *    ** **      ****  ***    **      ***  **   *   is a prefix of %s",a,b);
 **    * *  **   ***      ** 
 *   *    **     *      ****     ** ** *   **  ***  **   ***** is not a prefix of %s",a,b);
  ****** ****   *** ***** **  ** 0;
}

answered Jan 11, 2018 by LinJingYao (-498 points)
edited Jan 17, 2018 by LinJingYao

VincentXV · Answer 10 · 2018-01-11 20:05:37

Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* ******   *   ***** ** * *  p[100],s[100],a[100]={};
* ** ** ***   * * **    *  t;
* ** * ***  ***   **   * **** *** ***** ** *** 
*   ***   * **** ***** *** ** *  *  *
*  *    *******     * * **   *** ***  %s",p,s);
*  * *  *  ** **    * * * * *  * 
 * **  * * **     **  * ** * * *
  **  *** **     **   **  * * **    *
    *    * **    *  *   * ** **   *   * **
**  *       * *    * *   ** *   *     * *** 
        **  *** ** **** *****  * ** * * ** ***  * * ** *  **     *  ** * is a prefix of %s",p,s);
* * **  * * * ***   **  ** *  
  ** * * *  * *  *   *  **  *** *  *
    *       ***** ****  *  *    ****** **   *  * **  * * *  * ***   ** is not a prefix of %s",p,s);
* *    **   *   ***       * 
*   *** *   *     ** **   *  * ** * * 0;
}

answered Jan 11, 2018 by VincentXV (54 points)

1-11 Exercise 3: Prefix of a string

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