2 like 0 dislike
17.4k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 17.4k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

*** * ** ** * * ****** i;
** * * * *** **** j;
* ** ** **** * * newNum1;
* ** * ** **** ** * newNum2;
** ** ** ** *** * ** * **** * * gcd;
** * ** * *** * **** * ** rem;
* ********* * *** num1, num2;

* ** * * * ** ** * ** * * ** * ** ****

* * ** * ** **** *** * * *
*** *** **** * * ** ** ** *

* *** * * * * * * ** * * != 0)
* * * * * ****
** * * * ** * * ** ** ** * ****** * ** * * = j%i;
**** ** ** ***** * *** * * * * * * = i;
* * *** * * ** *** * * * *** *** *** * = rem;
* ** * * ** ** **
* * ** ***** * ** * ****

* * * * ***** ** * * *** = num1/gcd;
* * * **** * * ** * * = num2/gcd;

* *** **** ** * ** ** * * ** == 1)
    {
* *** **** **** * * *** * ** * * **** ***** ******** ** * *** **
    }

* * ***** ***** *** ***
    {
**** * ** ** * *** * * *** **** * *** *** * ** *** * * ****** * * ** ** ** * ****
* ** ** ** ** ** * **

* **** * ** *** * ***** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** * ** *** ******* ** *** * * * * ** * * * * ****** **

** *** ***** * ** **** ***
* ***** * **** * ****** ** ** * ********** *** * *** * * * *

    else{
* * *** * * * * ** * * *** * *
    {
* ** ****** *** ** **** * ** * * * * * * ****
* * * ** * * * ** * ***** * ** * * * ** * ** ******* * * ** * *** && deno%i==0)
* ** ** * ** *** * * **** ***** ***** *** **** ** ** * * ** * ***** * * ***
* * * ** * * ** * * *** * * ** * * * ** ** * *** *** ** * * * ** * * * * ***
* ** ** **** * ** ** * ** ** * *** **** * * * **** * * * * ******** * ****** ***** *
*** * * * * * ** * ****** * ***** ** ** * ***** * * * * *
    }

*** * * ** **** ** ** *** ******
    {
*** * * * * *** ** ** **
** ***** ** ** * * * * * ** * *** ****** ** **** * ** ** * * * && deno%i==0)
** * *** * **** * ** ** *** ** ** *** * * ** * ****** **** * **
* * * ** * ** ** ***** * * * * ** ** * ** ** *** * * * ** * * * *
* ** *** * **** * ** *** ** * * * ******* * *** ** * * * *** * ** ** ****** *
** * ** **** **** * * ** **** ** * **** * * * ***** *** * *
    }
*** * **** ** * * * * ** ***** ** *** * ********

    }




**** *** * *** *** * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * ** ******
#include ** ***** * *** *

int gcd(int n, int m)
{
** * *** ** * ***** * ** * gcd, remainder;

* * *** * *** *** *** ***** (n != 0)
** * * * * * ** *
***** ** * * ** *** ** * * * * * **** ** * ** * * = m % n;
* * * ** ** * *** *** * ** *** ** * * * ** = n;
** * **** * * ** * *** * *** * * ** * ** *** = remainder;
* * * * * * *

* ** * * * *** * ** ** ** = m;

** *** ** * *** ***** *** *** gcd;
}

int main (int argc, const char * argv[]) {

** * *** * **** * * * ***** number1, number2;
** * *** ** * * * * ** newNumber1, newNumber2;

* ** *** ** ** * * * *** * *** * * * ** * *** ** * * ** ** **

** * ****** * *** * = number1 / **** * number2);
* * * **** **** ** *** = number2 / ** number2);

* * * *** * * ** * * *
*** * * * ** ** *** ** * * ******** * * * * * *
** *** ** ** ** * * **
*** ** * * *** * ***** *** * * * * * * * ** * * ** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
** ** * * ** * *
*** ** * * * *

int ** n, int m)
{
* * * **** * int gcd, * ** *

** * * ** * *** * (n != 0)
* ** * * **** {
** * * * *** ** * * *** * * = m % n;
* **** * ** ** * ** m = n;
*** ** **** * * * * * n = * **
** ** * ** * * }

*** ** * * gcd = m;

**** * **** **** gcd;
}

int main (int ** ** char * ** * {

** *** * * * int ** * *
* ** ** * ** ** int * ** * * * **

* ** * * ** **** * * * *** ** **

** ** * * *** * ** ** = ** / * **** ****
** * ** * ** = **** / **** ** *

*** * ** if ** * *** * * *
* *** * * *** *** ****** * ** * *****
****** * ***** else
*** * **** ** * ** * ***** * * * * ****
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* **** **** * *** ** * **** i;
*** *** * * ** * ** j;
** * *** * ** * ** *** newNum1;
** * ****** *** *** * * * * newNum2;
* ******* ** ** * ** gcd;
* * * ** * ** * rem;
**** * ** **** ** *** * num1, num2;
    
* *** * ** ** ** ** * ** ** *** ** **** * **
* ** ** * ** * * * *
** ***** ** * **** * * *
* * *** *** **** ** * *** *
* * * * ** * * ***** * *
* ****** * * ** ** ** ** != 0)
**** * * * ** * ***** *
*** *** ** * **** * *** * * * ** ** = j%i;
**** * * ** * ** * ** ******* ** * ***** * * * = i;
*** *** * ** * ** **** *** * ** * * * * = rem;
****** * ** * * ***
***** ** ** ** * * * * * **
    
****** *** * * * ** ** ** = num1/gcd;
* **** * ***** * ** * * = num2/gcd;
    
*** * * ***** *** * ** * * ** * * == 1)
** * * *** * * * ** ****
** ** * * * **** *** *** *** * *** * ** * ** **** ** * ** * *** *
** ** * ** * ** **
    
* * *** * * * *** ** **
* ***** * * * *
*** * * ** **** * ** *** ****** * * * ** * ** ** * ** ** *** * * **** ** ****
* ** ** ** ** ** ** * *
    
* * ** * ** *** ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
******* ** * * * ** *** i;
* **** ** **** ** ** ** ** j;
**** * * **** ** newNum1;
*** ** * *** * * *** * * newNum2;
** * ** ** * *** * ** gcd;
*** * *** ****** *** **** rem;
* ***** * **** **** ** * **** num1, num2;
    
***** ** * * *** * ** * ***** * ** *** ** *** *
*** **** * ** * * * **
* *** ***** ** * * *
* *** **** * * * *** *
* * ** * ****** ***
***** * * * * * ** != 0)
*** * *** *** **** * * *
** * ** * * ** ** ** ** *** * ***** * * *** ** = j%i;
** ** * * * * ** * * * ** * * * * *** = i;
** * ** ****** * ** ****** * * **** * * ** = rem;
* * ** ** * ** **** *** *
* * ** * * ** ***** * *
    
*** ** ******* * * * ** = num1/gcd;
** * **** ** * **** = num2/gcd;
    
***** * ** * * ** * ** ** *** == 1)
** * ** * *** * ***** * * *
*** *** *** * * ** * **** * * ** * ** * *** ** * ** ** * *** *
* *** *** * *
    
* ** * * * * * * ** ** ** * *
* ** * *** * ** * *
*** ***** ** * *** * *** * **** * * ** * ** * * *** * * *** ** *
* ***** ***** ***** * ***
    
* ** * ** ** * **** *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
**** ** ***** * * ** *** * ** * **** ***** *
** *** * ***** ** * *** ** ** * * ** * ** **** **
    {
* * * ** ** ** * ** * * * * * * * * ** * * ** * *
** **** * *** ** ***** * * * * ** * ** ** ** *** ** **
** * *** ** *** * * **** * * * * *
** *** * *** *** * ***** ** *
* ** ** * * * * * ** ** *** ****

* * *** * ** * * ** **
* ******* * *** * **** * * **** * * ** * * **** * ** * * * ** * ******
* * *** * * * * ** * ** ** * ** ** ** * ****


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* ** ****** ** *** * * ** a,b,GCD;
** ** * * ***** ***** * ** * * *** * * * *** * * ** *
** * * * * ** **** ** *******
** * ******** * * ****** * * **
* ** * * * *** ** * * *** *** * ** ** ** * ** *
* ** * ** **** * **
* * * * * * ** * * *** * * * **** * * ** * ** ** **** ** * ** * ** *
** ** ** * *** * * *** * 0;
}
*** ** * *** ***** * ** ** gcd(int a, int b){
* * ** * *** ** * * * **** * ** **** * *** (!b) return (a);
** * ** ******** *** * *** * * * * *** * ** * ** ***** gcd(b, a % b);
* * * ** * * * * * **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * **
#include * * * * *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* ** * * ** * * * gcd, remainder;
* *** * * *** ***
** * * * * * *** ** (n != 0)
* **** ** * **
** * * * * * ** * * * * ** * * * * = m % n;
** * ** ** * * ** * * * * ** * ** ***** * ** = n;
** ** * ***** **** * * ***** *** * * ** * * * = remainder;
* ** * * ** ****
* * ****** * ** ***
* **** *** **** * ** = m;
* ** ** *** * ***** ** *
** * **** * * * * ***** ** gcd;
}
int main (int argc, const char * argv[]) {
*** ** * * ** * ** number1, number2;
*** ** **** ** * ** * newNumber1, newNumber2;
** * * ** * ** ** ** *
* ** *** *** * ** *
** ***** * * ********* * ** *** * * ***** * * *
* ***** * *** * ** *** *
* * *** * ** * * * * = number1 / gcd(number1, number2);
* * ** * * ** * * *** * ** * = number2 / * ** * * number2);
**** * ** * *
* * *** **** * ** ** * *
* ******* ** * *** * ****** ( * *
* ** ***** * ** * * *** ** ** *** ** ****** ** * ***** * newNumber1);
* ** * * ***** * ** * *
* *** **** *** * *
* * * * * * * * * *** ****** * ** ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * * * * * * * *** * * a,b,c,d,e,f;
* * * ** * * *** ** ***** ***** ** ** * ** *** **
** * ** ****** * ** **
* * ** ** * ** ** *
** * * * ***** *** * * * * ****
    {
* * ****** * * ****** ** * * ** *
** *** *** * ** ** * **** ** ***** ** * * ***
* **** ***** *** * * ** *** * ** **** *
    }
* * ***** * *** * *** * * * **
    {
* ** * **** * * *** * ** * *** * ** *** ***
**** ** * * * ** ** ** **** * * * ** * *** ***** * ** * * * *
**** ** * *** * ** *** * * * * * *** *
* * *** ** ** * ** ** ** * ** ** ** *** **** ** * ** ** ** * *
    }
* * ** * ***** * * * *
    {
* ** * ** ***** * ** ** * * * ** * * ** **
** * * * ** **** **** ** * ** ** **** *** * * ***** *** ******* ****
*********** * * * * ** ** **** ** * ** * ** ** * **
** ** * ** * *** * ** *** * * * ** ** * * ** * *** ***** ** **
    }
* * ** ** ** ** * * * *** * *** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.10
©2016-2026

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 17.4k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 17.1k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 22.5k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 17k views
12,783 questions
183,442 answers
172,219 comments
4,824 users