2 like 0 dislike
12.8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 12.8k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* **** **** * * * ** i;
* * * ** * ** * j;
*** ** * * * * * newNum1;
* *** ** ***** *** * * newNum2;
* *** ** **** * *** * * gcd;
* ***** * **** * rem;
** * *** ** ** *** * *** num1, num2;

* *** * ** **** * ** *** * * ***** *** * * * ** *

* * * *** ** **** *****
** * * ***** ** *** * * *

** * ** *** **** ******** ** != 0)
*** **** * * * **
**** * * * ** * ** * * **** * *** *** * * * = j%i;
********** *** **** ** * * **** ******* * * * *** = i;
* * ** ** * * ****** * * *** ** *** *** = rem;
** * * * * ****
* ** ** ****** *** ** * *

*** * * * * ** * * * ** * = num1/gcd;
* *** ***** *** * ** * *** * * = num2/gcd;

** ***** * **** * ** * * == 1)
    {
* * * *** * **** *** ** **** * ** ****** * ***** *** ** ****** ** **
    }

** * ** ** * * *
    {
* * *** * ** ** ** * * * **** * * * * * * * * ***
** *** *** ****** ** * ***** *

*** * * *** * * * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** ** *** *** *** * * * * *** *** ** ** * * *

* * * * **** ***** * * *
****** * ** *** * ** ** * ***** ** ********** *

    else{
*** ****** * ******** * **** * ***
    {
*** ** **** ** *** * **** * * *
** ** * ** **** * * * *** * * ***** ** *** * * * * * * ** *** *** * && deno%i==0)
*** ** **** * * * * * * * * ** * * ** ** ** ** **
** * * ** * ** * *** * * ** ** ** ** ** * * *** * *** * *** ****** *** ******
***** * * * ** ** **** ****** *** * * * * ** * ** * * *** * ** ** *** * ******** ****
* ** ** * * * * ** * ***** * ** * **** * * ** * * * ******* *
    }

** ** ** *** **** ** * * ***
    {
****** *** ****** **** ** * * **** ** *
* ** * ** *** * *** ** ** * ** ** *** *** ** * **** * ** *** ** ****** && deno%i==0)
* * ***** * * * * * * * ** ** *** * **** ***** * * ** ** ***
* * * ***** * ***** * * ** * * * * * * * ***** * * * ** * * ** * * *** *** ** **** *
* ** * *** * *** ** **** * * *** ** **** * ***** ** * *** **** ****** * * * * ***** * **** * *
** ** ** * *** ** ** * * * **** * * * ** ** ****** ** *** ****** *** * *
    }
* * * * * *** * * * * * ** ** ** * *** *** **

    }




*** * ** ** * *** * * **** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** ** *
#include * ** *** ** **

int gcd(int n, int m)
{
** ** ****** *** ** * ****** gcd, remainder;

** ** * **** * * * * * (n != 0)
* ** * * *** ****** **
** *** ** * ** **** * * *** * ****** ** * * * *** * * = m % n;
****** * * * *** *** * * ******** * * * * *** = n;
** *** ** ** * * *** * * * * ** ** *** *** * = remainder;
* ** * ***** * *** ** *

** * * * * ** = m;

* * **** ** *** * * gcd;
}

int main (int argc, const char * argv[]) {

** ** ** *** ** ** number1, number2;
* *** **** * * * * *** newNumber1, newNumber2;

**** * * * ** **** * * * ****** ** * * ** *** ** ** ** *****

*** ** * * * ** * * * **** = number1 / *** number2);
** **** ** * *** * * *** = number2 / ** number2);

* * * ** * **** * ** *** * * * ** **
***** ** * ** ********* ** * **** *** * * **** * * * * * ****
* * * * *** ** * *** * *
**** * * * * * * **** ** * *** * * * ** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * * **
* * * ** ** *

int * n, int m)
{
* *** ** * int gcd, *

* * ** * * ** ** (n != 0)
** * * ** {
* * * ** * *** * * * * *** = m % n;
* * * * ** ** * ** m = n;
** * ** * *** * ** * * ** * n = ***
** **** }

** * *** ** gcd = m;

* * ** gcd;
}

int main (int ** char * **** {

** * * * * * int * **
* *** ** ** int * * * ***

* ** *** ** *** * * *** ** * **** * ** * * ** *

* * ****** * ** * = * / ** * ** **
*** * * * * * = * / * ***

*** *** *** if * * * * * * **** *
* ** ** ** * **** * ** * ** * * * ** *
*** * * ** ***** else
****** ** * * * ** * **** *** **** **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
*** **** * * * * ** i;
* **** * ** **** ** j;
* * ** ** * * newNum1;
* * ** ***** * *** * newNum2;
* * * *** * * *** ** * ** ** gcd;
* * *** ** ** ** * ** rem;
* * * ** ** ** num1, num2;
    
* *** ***** ** * * * ** **** **** * * * * * *** *
* *** ** ** **** *
**** * ** ********** ** * **
* ** * **** * ** *** **** *
* * ** * *** ** * **
**** * *** ** ***** * * != 0)
* * ** * * * ** * **** * *
**** ******** ** *** ** ** ** * ** * *** ** ** = j%i;
* * * ** *** * * * **** * * * *** * * * ** = i;
********* * * **** * **** * ** * * *** *** * * = rem;
* ** *** * ** * * *
* * *** *** * * *****
    
** **** *** ** ** ** ** ** * * = num1/gcd;
** **** ***** * ** ** ** ** = num2/gcd;
    
** *** ** * * * * ** ** *** == 1)
* * * * *** *** *****
* * * * * **** *** *** ****************** * * * * * ** *** ****
********** * * ** * * *
    
**** *** ** * * * *
* ** **** *** * *
** * * * * ** * * * * *** * ****** ** *** * ** * * * * * **
** ** ***** ** * ***
    
* ***** *** * * ****** * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** * * * * * ** * * * *** i;
* *** * * * ** ***** j;
** * * * ** * * * * * ** newNum1;
*** * ** ** *** * * * * * newNum2;
** **** ** * ******** ** * gcd;
** * ** ** *** * * ***** rem;
* *** *** ****** **** num1, num2;
    
* *** * * * * *** ****** * ** ** * * * ** ** * *
** ** * *** * * *
* * *** * * ***** *** ***
* **** *** * * * * * *
* ** ** * *** * *
** * ** ** ** * **** * * * != 0)
**** ** * * ** *
* ** *** ** * *** * ** ***** *** *** * * **** *** ** *** = j%i;
** *** ** * * * **** * * *** *** * * = i;
* ** *** * *** * ******* ******* **** ******** * * *** = rem;
** * ** **** ***
** * ** * * * ** *
    
***** **** * * *** ** * ** * = num1/gcd;
****** * *** * *** ** * ** = num2/gcd;
    
**** ** ***** * * ** ** * ** * == 1)
* * **** *** *** * * * **
* * *** * * * *** * * * * ** ** ** *** * ** *** ** * * **
* **** * * *
    
* * ** ***** * ** * *****
***** ** * * *** ** *
*** * *** * *** * ** * ****** **** ***** * * *** * * * ** **
* * ** * * ****
    
* * ****** * ** * *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** * * * * * * *** * * ***** * * * ***** * * * ** ****
* ** **** ****** * ** * * * * * * *
    {
*** * ** ***** * * ****** * * *** * * *** *** **** * **** ** *
** * ** *** ** * * **** ****** **** * ***** ** * **
* ** ********* ** **** * * ** ***
* * * * * * * * *** * * * ** * * *
* ******** ** * * * ** *** * *

** * ** ** * * * **
* ** ** ** *** ** ** * * * *** * ** * * * * ** * *** ** * * *** * * * ** *
*** ** ** ****** * * * * ** * * * * ** * * ** ** * **** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* * *** * *** * * ** a,b,GCD;
*** * ** ** ** ** ** ** ** * * * ** * * ** * * **
** ** * * ***** * ** ** *
***** * * * * * **** *
* * ***** ****** ***** ******* **** ** ***** * * * ** * * *
* * **** * ** *** ***
* ** ** ****** ** * * * * * **** * ** * ** * * ** * ** **
* * *** ** **** 0;
}
* * * ***** ** ** ** ** gcd(int a, int b){
* * *** ** * * * ***** * * ** **** ** * *** * (!b) return (a);
** * * * ** ** * * * * ** ** **** gcd(b, a % b);
* * * * * * * *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** ***** * *
#include * ** **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
*** * * ** ** ** **** ** * gcd, remainder;
** * ** ** * * **
** * *** * * (n != 0)
* ******** *** * **** **
* ** **** * * **** * * * ** * * * **** ******** * = m % n;
**** * ** * * ******* * *** ** ** ********* = n;
** * ** ***** ** * * ******** * ** *** ** * = remainder;
* **** **** * ** * * *
* **** * *** * ***
**** * *** * ** ** * * = m;
** ** * **** *** ** * *
** * * * ** ***** ** gcd;
}
int main (int argc, const char * argv[]) {
* * * *** * ** ** ** ***** number1, number2;
****** * * * *** ** ** newNumber1, newNumber2;
* ** * ** ** ** * *
** ** * *** ***
** * * * * ** * ** ** * * * * * * * ** ** * * ** **** ** *
*** ***** * ** *
* * *** * * **** * = number1 / gcd(number1, number2);
***** * * ** *** * * ** * = number2 / * *** ** number2);
* ** ** ** *
* ** *** *** * ***
*** * ** ** ** ** * * ** ( *** *** *
** * *** **** * ** **** ** *** ** **** ** * * * * * * * ** newNumber1);
*** ** *** ***** * *** * *** *
* * *** *** * *
*** * ***** * * * * * * * * ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** ** * * * * * * a,b,c,d,e,f;
* * ** * * *** * * *** * * * * ***** * ** * * *** *
**** * **** * ** * ** ** *
** *** *** * * *** *
** ** ** * *** * * ** ***
    {
* ** * * * * ** * * * ** * *** *
*** * * ** ***** ** ** * * * * *** * * ** ** **
* * * *** * * * * ** *** ** * * ** ***** * *
    }
* *** * **** * * * **** *
    {
* ** * ** * * ** ** ** ** ************* * ** ** *
** * * * ** **** * * * * ** * * * * * ** * * * * *** **
* * * * * * * * * * ** * * *** *** * **
** * * * **** ** **** * * * * * * *** * * * ** * ** *
    }
*** * ****** ** ** **
    {
* * * *********** * * ** * *** * * * * * *
* * ** *** ****** **** ************* *** * ** ** * *** ** ** * * ******* *
** ****** *** * ** **** * *** * ** **
* ** * * ** * * * * * *** ***** * ** * * * * **
    }
*** * ******** ** * ** * ** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.223.174
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 13.3k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 13.2k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 16.7k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 12.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users