2 like 0 dislike
16.3k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 16.3k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* * ** * ** *** i;
** ** ** ** ** ** ****** j;
*** * **** ** * ** * *** newNum1;
** * **** ** *** * ** ** newNum2;
* *** ** * * *** * * gcd;
*** ***** ** * *** rem;
**** * *** * * * *** ** * num1, num2;

** ** * * ******* * * *** **** * *** * ** ** ** * ** **

* *** * ** * * ** * *
** * ** * * ** ** *

* *** ** * ****** * != 0)
*** * * ** * ** ****
* ** *** ** ** ** ** ** * * ** * * * * * * * * = j%i;
**** * * * ** * **** ****** = i;
*** ****** * * * ***** *** ** * * * ***** = rem;
*** * *** *** * ** * *
** * *** * *** ** * *** * **

* * ** ******* * *** * ** *** = num1/gcd;
* * **** * * *** * = num2/gcd;

* ** * ** * * * * * ** * == 1)
    {
*** ****** **** * * ** * * * * **** * ** * ****** * * * * *
    }

* *** **** *** * * *** * * **
    {
** ** * ** ** ** ** * **** ***** * * ** *** ***** **** ** * **** ** * **
* *** *** ** * ******

** * ** ****** * ***** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* *** * * ** * * * ** *** ** *** * **** ** *

** ***** **** * *** ***** * *
**** **** * * *** ** * * ** ** * * *** *** * ** ** **

    else{
*** * * ****** *** * *** * *** *
    {
** ** ** ** ** *** * * *** ***
*** * * ** *** * ** **** ***** * * * * * ** ** * ***** ***** && deno%i==0)
** **** * *** ****** ******** * * ** * * *** **** ***** * *
* *** * ** *** ** ****** * ** * * * * **** * ** *** * *** *** **** ** * * * *
* ** ** * ** ** * * **** * *** * * * ** * * * * * *** ** ** * * ** **** ** ****** * *
* * ** ** * ** *** * * *** * * ** * * * ** *** *** *** * *** * ** ** ** * * *
    }

**** *** * * * ** *** * *** *** * **
    {
*** ** ** * * ***** ** *
*** * * * * ** ** ***** * ** ** * ******** * *** *** && deno%i==0)
**** ***** *** *** ** * ** * ** ** **** *** * *** ***** ** * ** *
** * * *** ** ** * **** *** ** * * * ** **** * *** ****** * *** * * * ** ****** ****
* ** * * ****** * ** **** * *** * * ** **** *** ** *** * * ** ** * **** **** * ** * *
** * ** ** *** * * * * *** *** *** ** * **** *** * * * * ** * * * **
    }
*** * ** * ** * ** * ** ** *** * * *** ***

    }




* *** * ** * * ** * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ***** **
#include * ***** * * **** *

int gcd(int n, int m)
{
* * ** **** ** *** * * gcd, remainder;

* * * * **** * * *** ***** (n != 0)
* * ** ** ** * ** ***** * *
* **** *** * ***** ** *** ** * * * ******* * * ** = m % n;
**** * * ** ** *** * *** ***** * * * * ** ** ** * = n;
* **** * * * * *** * * *** * * * * * * = remainder;
* ** * **** *** ** ** *** *

* * * * * * * ** * * = m;

* * ** * * *** * * ** * gcd;
}

int main (int argc, const char * argv[]) {

************ *** ** * ** **** number1, number2;
* ****** * **** ** * ** newNumber1, newNumber2;

* * ** ** ** * * *** * * * * * ** * * ** * * * * **

********* *** * * * * * * *** ** = number1 / ** number2);
*** ** * ** ******* ** *** = number2 / *** * number2);

* ** * ** *** * **** *** * * **
* ** **** ** * ** * ** * * * * **** * *** * ****
* ** * * ** ***
*** ****** * * ** *** *** ****** ** * * * * * **
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * ** * ****
* * ** ** *

int * * n, int m)
{
*** * * ** * int gcd, * *

** * ** * ** *** (n != 0)
******** ** {
* * *** ** * *** **** ** * ** * = m % n;
* * * * *** * *** ** * m = n;
* * * ** * **** n = *
*** ** * }

** * * ** * * gcd = m;

*** * * * gcd;
}

int main (int * * char * * ** {

** *** ** ** int * * ** *
* * * *** * int * ** * * **

***** ** * * * * ** * ** *** * * * ** **** * * *

* ***** ***** * * = *** / * * **** * ***
* ** * **** ** *** = * / * * ** **

* * *** * * if * * *** **
* * ** * * ** ****** ** ** * ****
** ** **** else
**** * ** * * ** ****** * ** * ** *** **** * ** * ** *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
**** * ** ** * **** * ** i;
* * * ***** * * * ******** j;
* * * ** ** ** *** **** ** newNum1;
* ** ** ** * * ** * newNum2;
* * ** * * ** * *** * * gcd;
** * ** ** * *** * ***** * rem;
**** ** *** * * * * num1, num2;
    
** * **** ** ** * * * * ******* * ***** ** ***
* *** * * * ** * **
* * * * ********* * *** *
* ******* ** ** * *
* * * ** ** * *
*** * *** ** *** * *** != 0)
* ** * ** * ** **
* * ** * **** * ** * ***** ** *** * *** ** ** = j%i;
* * * * ** ** * *** ** * ** * * *** ** *** = i;
**** * * * ****** * *** ** * * *** ** * ** * = rem;
* * ** ** * * * ** * **
*** *** * * * **** * * ******
    
** ** * ** * * *** * = num1/gcd;
** *** * * ****** **** * ** = num2/gcd;
    
* ** * ** ** * * *** * * == 1)
* *** * * * * **
** ** * ** * * * ** ** *** * *** * ** ** *** ****** **** ** * *** * ******
** ***** * ******
    
* * ** * * **** * ** *
* ** *** * **
* ****** *** * ** * **** **** * ** ***** * * * *** * * *** **
***** ** ** *** * **
    
* *** * *** * * * ** * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
*** ** ******* * * * * i;
** * * * *** * * * * j;
*** ** ******* ** * ** newNum1;
* *** ** ****** * newNum2;
* * ** ** *** ** *** * gcd;
******* * * ** *** **** rem;
* ** * ** ***** ***** * num1, num2;
    
* ** *** ** * * * * *** ** * * * * ** *** *
* * ** ** ** ** **
* ***** * ** ** ** * **
** * ** *** * * **** * ** * **
** * ** * * * ***
**** * **** * * * * ** **** != 0)
*** * * * * ** * ** ***
**** * * * * * ** ** ** * ** ***** * ** *** = j%i;
* *** ** * * * * ** * * ** ** * * *** * * * * = i;
* * *** ** ***** * **** * **** ** ***** = rem;
* * ** **** **
* * ******* ** ** ***
    
* *** ** *** ** ** * * **** = num1/gcd;
** ** ** * *** ** * ** * = num2/gcd;
    
* * * *** * **** * ** * ** == 1)
** ** * *** *** ******
* ** * * * * ** * ** ** * *** ** * ** ** **** * *** * ***
***** *** * * * ** * *
    
*** **** * **** **
** ** ** **** ** **** *
* * ** * *** * * * ** * ** * ** * ** ******* ** ** ** * ** * * ** ***
** * * * * * * * **
    
** * ** * ** ** * ** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** * *** ** * * ** * ** ** * ** * *** ** * * *
*** * ** * ** ** ****** * *** ** * * * ** **
    {
* **** ** ** * ** * **** * * * ** ** * * * * *
* *** * ** *** * * ** * ** ** ** * ** *** * * ***
* *** ** * **** * ***** ** ***
*** *** *** ** * * * * * *** * *
* * *** * ** ** * * * * * ******* **

* * *** ** ** ****** ** ***** *
** * ** ** *** *** *** * * * ** * ** * ** ** * * ** ** ** * * ******* *** ******
** * * * *** ** *** * * * **** * * ***** * * ** *** **


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*** ** * * * *** a,b,GCD;
* ** ** * * **** * ** ** * *** **** * **** **** *** * *
** ** * * * ** * ** **
** **** *** **** * ** * * *
* * * * * * * * **** *** * * * ** * * * * *** ** * ** *** *
** **** ** * * * ****
** * **** ** ** * *** ** * *** ***** * ***** * *** * **** * * ** ** * *
****** * * ***** * *** * * 0;
}
* * * * * * ** * gcd(int a, int b){
****** ** * * ** ** * ** * * * * ** * (!b) return (a);
* * ** ***** ** * * * * * * * ***** * ***** * * gcd(b, a % b);
* * * * *** * ** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** * **** *
#include * * * ** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
*** ** * * ** * gcd, remainder;
* ***** * * * *** ** * *
* **** * * * * **** (n != 0)
** *** * ** *
****** * *** ******* * * * ** * * * *** ***** = m % n;
**** *** ** **** ** ** * * * * * = n;
* * **** ** *** * **** * ** * * ** *** = remainder;
* * * *** * * ** **
** ** * ** ** *** *** **
**** * **** *** * * = m;
***** ** * * ** *
** ******** * * * * ** * gcd;
}
int main (int argc, const char * argv[]) {
* * * *** *** * number1, number2;
* * *** * * ** * *** newNumber1, newNumber2;
* * ** * * ***
** * * * * **** * *
* * * * *** *** **** ** * * ***** * ***** ** * * * *** **** *
***** *** * * * ***
* * ** * ** **** ** * * * = number1 / gcd(number1, number2);
**** *** *** * * ** = number2 / * ** number2);
*** ** ******** ** * *
* ***** * ** * * * **
* * ** ** * *** * ( * * **
*** *** ***** * ** ** ** ** ** *** * ** ****** * *** * ***** ** *** newNumber1);
*** ** **** * *** **** *
* ** * ******* ** *
* * * * *** * *** * *** * ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
***** ** ** * *** * ** a,b,c,d,e,f;
***** ** ** *** *** *** * * ** * ** * *** **
*** * * ** * * **
* * ******* * * * ** ** **
**** ** *** * **** * *** **
    {
** * ***** *** * ***** ** ** ** * * ** **
* *** * * * * ** *** * * * * * ** *
* * **** *** * * * ***** ******
    }
* *** ***** *** * ********
    {
* * * * *** ***** **** ****** * * * * * ** *
*** ** * ** * * *** *** ** * ** ** * * ** * **** * * *
* * * * ** *** * * * **** *** **
**** * * **** ** * * * ** ******* ** ** * * ** *** * ** * * * * *
    }
*** *** * ** ****** *
    {
******* ** ** ***** *** ** * **** * ** ** **
*** * ** * * ***** * ** * *** * ** **** * ** ** ** * ****
*** * ***** * ***** * **** * * ** ** *
** * * * * * ** ***** * * ** *** ** *** **** *****
    }
* *** * ** * *** *** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.31
©2016-2026

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 16.2k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 16k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 20.9k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 15.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users