2 thích 0 k thích
18.4k đã xem

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - đã hỏi trong Chapter 6: Loops bởi (5.2k điểm)
ID: 31048 - Xem được từ: 2017-11-09 18:00 - Hiệu lực đến: Không giới hạn

đã sửa bởi | 18.4k đã xem

67 Trả lời

0 thích 0 k thích
Hidden content!
#include <stdio.h>

int main()
{

* * * ****** *** **** i;
*** * * ** ********** *** ** *** j;
** * *** **** ****** * newNum1;
*** ** ** ***** *** * newNum2;
***** ** **** * gcd;
** **** ** * * ** * rem;
* * * * ****** **** * num1, num2;

* * *** ** **** ** *** * * ** * * ** * * * * * * *

** *** ******* ** * *
** * * ** * ** * * **

* * ** **** ** * * ** * * != 0)
*** **** * **** * * **
** ** *** * * ** ** ***** *** ****** ** ** * * = j%i;
* * ** ** * ** * *** ** ** **** * ** = i;
* *** * * *** *** * ** ** * * ** * = rem;
* **** ** * * ** ** ** **** *
**** * ** * * * *** * ** * * *

* ** * ** * * * ** * * * = num1/gcd;
** * *** * ***** **** ** ** * = num2/gcd;

* ***** * * * ** *** **** * * * == 1)
    {
*** * * * *** * ** ** ***** ** * * * ** ** **** ** * * * *
    }

****** * *** * * * ** ** **
    {
** * * * * * *** * * ** ** * * * **** * * ***** *** *****
** ** * * ** *** *****

* ** * * ** ** * ** *** 0;
}
trả lời bởi (-140 điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 thích 0 k thích
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
*** ****** *** ** ** *** * ** ********

** * ** *** * **** * * *
** * * * * * ** * **** * * * * * * ** ** * *** ** * *** ********* ***

    else{
*** * ******* * ** *** * * * * *
    {
** * ** * * *** * *** ** ** * ****
* * ******** * *** *** **** *** * ** * *** * * * * *** * *** ** * ** && deno%i==0)
* ** ** * * * * * ** *** ** ** * * ********* * ** * *** * ***** * * ** *
* * **** *** **** *** **** *** * **** * ** * ** *** ** *** ******** *** ***** *** **** *
*** ***** ***** * ** * * * * ** * * ** ******* ** ** ** ** * * ** **** *
** * ********* ** ** ** * ** ** * *** ** * **** * *** * * *** ** ***
    }

** * **** **** * ** ** * ** * * *
    {
* ** * * ** ** ** ***** * ** *
** ** ** * ***** * * ** *** ** ****** ****** ** * **** * * * ****** && deno%i==0)
* * * **** * *** *** * ** *** * * ****** * *** * ** * ** ** * **
** ***** ***** * *** * *** * ** * ** ** * * ** * ** * * *** ** ** ** * ****** * * ** ***
** ** ****** ** ** * * ***** ***** *** * * * * * * ** * ****** ***** * *** ** ** * ** *** *** *** * *
*** * * * ** **** * * ** *** ** * * * ** * * **
    }
* ** ** ** * ** ** * * * ** * ** ******** **

    }




** * * * ** * * ** * 0;

}
trả lời bởi (-16 điểm)
đã sửa bởi
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 thích 0 k thích
Hidden content!
#include ** * * *** *
#include * ** *

int gcd(int n, int m)
{
***** * * *** ** * *** gcd, remainder;

** * ******* * * * * (n != 0)
* ** *** * ** ** ****
* * * * ** * **** **** * ** ** * **** * *** *** * * * = m % n;
* ** * ** ** * * * ******** ** * ** ***** * = n;
* * * **** *** * ** *** * ***** * * * = remainder;
* ** * * ****** * * * **

**** *** * * * * * * = m;

* ****** * ** * * ** gcd;
}

int main (int argc, const char * argv[]) {

** *** ** * * * * *** * number1, number2;
* * **** *** * ** newNumber1, newNumber2;

* ** * * *** **** * *** * ** * ** *** ** ** ** ****

* * * **** **** * * ** = number1 / ** * ** number2);
** ** * *** *** * * ** ** = number2 / * number2);

*** ***** * ** * * * *** ** * * *
*** * * ** * * ** *** * * ******** ** * * *** * *
* * * **** ** ** * **
* ** * * * **** * ***** * * *** * ** * * * ** **
}
trả lời bởi (-108 điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 thích 0 k thích
Hidden content!
* ** *******
* * * * **** *

int * n, int m)
{
** ** ** ** * int gcd, *** **

* ** **** * * * (n != 0)
** * * {
* ** **** * * ** *** * *** = m % n;
* **** * * ** * * * *** m = n;
** * *** * *** ** ** n = ** *** *
** ** ***** }

******** * * gcd = m;

*** * *** gcd;
}

int main (int * * ** char * * {

* * * * ** int ** ***
* *** ** int * *** * * * *

***** ** * * ** * * * ** * * * * * * * ***

** * * ** * * = / ** * * *
* * * *** * = * * ** / * *****

* * ** * *** if *** ** **** ** **
** * * ** * * **** **** * * *** * ****
** ** *** else
* * ** ** * **** * ** * * ** * * * * ***
}
trả lời bởi (-168 điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 thích 0 k thích
Hidden content!
#include <stdio.h>

int main()
{
 
** * ** * ** * *** * ** i;
******** * * **** * * * * j;
* *** * * * *** *** **** newNum1;
***** ** ** * * * * * newNum2;
* *** * * ** ** *** * * *** gcd;
* *** * ** *** ** rem;
* * *** **** * *** * num1, num2;
    
* ** * ** ** ** * * **** * *** * * ** ** *********
*** * * * * *** *
** ** * ** * * ** ** **
* * ******* ** ******
** * * * * * ** ** * **
* ** * * ** * * ***** != 0)
*** * ** * ** * * ** * * * **
** * * * **** * * * * * * * * * * ** * = j%i;
*** * ** ***** ** ** * ** *** ******* * * * ** ** = i;
***** * ** *** ** *** ** **** * * * *** = rem;
*** * ** *** *** * * ** *
** * *** * ** * **** ** ***
    
*** * *** *** * * = num1/gcd;
*** *** *** * ** * * = num2/gcd;
    
****** ** * * ***** **** ** * == 1)
** **** * * * **** * ***
******** ** * * ** *** * * * * * * *** * * ** ***** ** * * * *
* **** * ** ** ** *
    
** ** * **** * * * ***
* *** * * ** ***
**** * ** **** ** * * * * * *** * *** *** * * * * ** *
* *** *** ****
    
* ** * *** * * * ** 0;
}
trả lời bởi (-284 điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 thích 0 k thích
Hidden content!
#include <stdio.h>

int main()
{
 
* **** * * ** **** * * * i;
**** * ***** ** * * ** * ** j;
* * *** ** **** newNum1;
** * *** ** ****** *** * ** newNum2;
** ** * * *** ***** * ** ** * gcd;
***** * *** * *** ** rem;
* * ***** * * * ** ** * * num1, num2;
    
** ** *** * * ** * * ***** ** * **** * *** *** *
******** ** **
** *** * * **** * ** * **
* * ** ****** **** * * * *** *
** * * ** ** * *
* * *** *** * ** ** != 0)
* *** * ** ** ** *** *
* * ** **** * ***** * *** *** *** ** ** * * * * = j%i;
** * *** ***** *** * * **** **** ** *** = i;
* * ** * * ** * * **** ** * ** ** ****** *** = rem;
*** * * ** * * ** *
* ** **** * * * ** ***
    
*** ***** * * *** **** *** * * = num1/gcd;
* * * * * *** ** *** * = num2/gcd;
    
* ** ** *** ***** ** ***** == 1)
* ** * * * **
* ** * **** * * * *** *** * **** ** ** ** ** ** ** ******
* ** *** ** ** ** ***** ** * **
    
* ** ** *** ***** *
* * * ** *** ** *
* * * ***** * *** ** * * *** * * ***** * * * * * * ** * * * *
** * ******** * *** **
    
******** * ** * ** ** * * * * 0;
}
trả lời bởi (-193 điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 thích 0 k thích
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
*** * ** ** * * * **** ** *** *** **** ***
* ** * * *** ** * * * * ** ** * **
    {
** * * * * * ** * * ***** **** ** *** **** ** * ** ***
** ** ** ** *** ******* * * * ** ** ** ** * ** * * ***
** *** *** *** ** *** * * * *
* * * **** * * ** *** * * * * *
* * * * ** * * *** * * **

* ** * * * * * ***
** ** * * **** * * ***** * * ** * ** ** * ** * * ** * ** ** ****** *** *
* * * * * * * **** * * *** * *** **** * * * *************** ****


return 0;
}
trả lời bởi (-32 điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 thích 0 k thích
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*** ** **** ** *** ** a,b,GCD;
* ********* * *** ** ** * *** ******** * **
* *** * * ** **** ** ** * ***** *
*** * * ** * **** * * *
* **** *** ** **** * * * * ** ** * ** * ** ** ** **** *
* * * ***** * * *
*** * * **** *** * **** ** ***** ** * *** ** *** * *
** * * * * *** ** * * ** 0;
}
* * *** ** * ****** ** gcd(int a, int b){
* * * * * **** ***** ** * * * **** *** * ***** * * * (!b) return (a);
* * ** * ** *** *** ** * ** ** * * *** * * gcd(b, a % b);
* * * *** * * * * *
trả lời bởi (-32 điểm)
đã sửa bởi
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 thích 0 k thích
Hidden content!
#include * *** ***
#include **** * ** ***

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
** ** * * * *** * ** gcd, remainder;
* * * * *** * * *** *
** * *** ***** *** * * ** **** (n != 0)
*** * ** **** *** ****
* ** ** ***** * *** * * ** * ****** * ***** ** = m % n;
** ******* ****** ** ** ** * ** * ** * **** = n;
* *** ***** ****** * * ***** ** * **** * * * = remainder;
** * ***** * * ** ****
* * * ******* *
*** * ** ** * * * ****** * *** = m;
* **** ** * ** * ***** *
** ** ** ** **** ** gcd;
}
int main (int argc, const char * argv[]) {
** * ** *** ** * ** * * number1, number2;
* * *** *** * * **** ** * * newNumber1, newNumber2;
**** * ** ** * * * **
* * ****** * * *
******* * * * * * * * ***** * *** * **** ** *** * **
* * *** ** * * **** * *
* * * *** ** * *** *** * = number1 / gcd(number1, number2);
* * *** ** ** * ** * * * = number2 / *** ** number2);
* ** * *** *** ** ** **
* * ** ** * ** ******* **
* * * * ** * * * ( * * *
**** * ** * * * ********* ** **** *** * * **** * ** * ** newNumber1);
* **** * **** ** * ** *** * *
* *** ** * ** * ***
*** * ***** ***** * ** *** * ** *** ** newNumber1, newNumber2);
}
trả lời bởi (323 điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 thích 0 k thích
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** *** * ** * * * **** * a,b,c,d,e,f;
** ** *** ******* ****** ***** **** ** * * ***** **
** *** * * * ** * * *
**** * ** * *** ** **
** * ****** * * **** * *** **
    {
* *** * ** *** * ** * * * **** * ** ** ***
* * ** * * * * * * *** ***** **** *** ***** * * **
** ** * ** ******** * * * ** ****** * ** * * * *
    }
** * *** **** * **** * ** *
    {
* * * *** * *** ** ** ** * ** * ** * **
* * ** ** *** * *** ** ** *** * * *** * * ** * *** *** *****
* * * ** ** * **** ** * ****** ** * ** * ** **
** ** * * * * * * * * * *** ***** * * ** * * ** ** ***
    }
***** * * *
    {
* * * **** ****** ** * * * *** * * * *** *** *
**** ** * ** * * ***** *** * * * * * * ** * ** *** * * *** *** *
* ****** * ** *** * *** * *** ** * ** * **** ** *****
** * *** * * ** * ***** * **** ** * ** * * ****** * **** **
    }
** *** ****** ** ***** ** 0;
}
trả lời bởi (-498 điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.10
©2016-2026

Những câu hỏi liên quan

0 thích 0 k thích
71 trả lời
[Exercise] Coding (C) - đã hỏi ngày 9 tháng 11 năm 2017 trong Chapter 6: Loops bởi semicolon (5.2k điểm)
ID: 31047 - Xem được từ: 2017-11-09 18:00 - Hiệu lực đến: Không giới hạn
| 18.3k đã xem
0 thích 0 k thích
72 trả lời
[Exercise] Coding (C) - đã hỏi ngày 2 tháng 11 năm 2017 trong Chapter 6: Loops bởi semicolon (5.2k điểm)
ID: 29831 - Xem được từ: 2017-11-02 18:00 - Hiệu lực đến: Không giới hạn
| 18.1k đã xem
1 thích 1 không thích
85 trả lời
[Exercise] Coding (C) - đã hỏi ngày 26 tháng 10 năm 2017 trong Chapter 6: Loops bởi semicolon (5.2k điểm)
ID: 28914 - Xem được từ: 2017-10-26 18:00 - Hiệu lực đến: Không giới hạn
| 24.1k đã xem
0 thích 0 k thích
69 trả lời
[Exercise] Coding (C) - đã hỏi ngày 26 tháng 10 năm 2017 trong Chapter 6: Loops bởi semicolon (5.2k điểm)
ID: 28913 - Xem được từ: 2017-10-26 18:00 - Hiệu lực đến: Không giới hạn
| 18.3k đã xem
12,783 câu hỏi
183,442 trả lời
172,219 bình luận
4,824 thành viên