11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 8k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

*   *  *  ** * ** * ****  ** i;
  ***  *  * * * *   *      *    j;
 **  * * *** ****   * * *  newNum1;
*  * **** *         *  ** *    newNum2;
 *   **** * * **** **  *  *    * gcd;
 **       **   *   * *** * rem;
*   **   ***   * ** * **** * *** num1, num2;

**   *  *   ** * * ***  **  *    *****  * ** * * ** * *** ***     * ***

 *   * ****     *  ** * ** *  
 ** **     * ******** *    * *  

*  ****   ***    * ** ** *** *  *  != 0)
*  *   **  *  * **   * ***  ** 
 ***** *    *** * *** * *       *****  * *  ****  *** ** *  = j%i;
** * * ** * * ***     * *  * **  *** ***   **   * **  ** ** = i;
  * * ** *    * * *    ***   * *  ***        *    *  **** = rem;
  * *   *  * *  **** * *  **   
   *** * * * ** * ** * **  ** * * ** *

* **** ****    ***    ***  * ***  = num1/gcd;
* *    ***** **** * ****   ** * = num2/gcd;

  ** * *   *     *  * *  *  ** * **  == 1)
    {
   **     ** **    ***  **  ****** *    ** ** *  *   ****   *  ***** *   *** **
    }

*** ** ** *   **   *  *   *  *
    {
 ** ****** *        ****    ** *  **  * *  * ****   ** **  *  **  *  *   ***    ** **
** ******* *  ** *** ** *  *  *

 ***   *  *****  *    ****   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
 ** ******  * **** ******    ***   *  * * * * * **  * **  * *   *

*****   *       **** *   * * *
 ** * * *   *  * *  *  ** * * * * ** *** *  ** **  *        *  * * **** * *  * 

    else{
* * * ** **  *    *  * ***  * * * ** * *  
    {
 *      *** * * *  ** * *  ** ** * **  **
*    * **** ****  ** *  **  *    *  ****   ** *  ** **   ** * * ** * *  * ****  ** ** && deno%i==0)
    * *  * **      * ***  *    *  * *****   *** * *    *    ******* ***   * *  
***   *  **  *   **** **        *   ** ** *  * *   ***  ********* *** **  * *    ** ** ** ** *  ** ** ** **  *
**  ** * * * ** ** *   ** * ** *    * *  ***  *    ****  ****  *   * *       * * * **  * *  * *** **
  *  * ** *** * *  ** ****** ** *    *** * *      * *   ***     ***  *  **   **
    }

** *     * ** ***  * *   * * *    *****  
    {
** **  * *  *** ****  * ********** ***   *
**  *** *    **   *    * * *** ****    *** ** ** * ** ** *** ***   * *    * * *   * *   && deno%i==0)
 **  *   *  **   **  *** ***** **  *** ***  ***     *  **   ***    *     ***** * 
* * **  **  *  *  *  **** *    *********  ** **  ** *  ******   * * ***       *  **  *      * *  ***   ***  
***   * ** *   ***  ***  *****  *  **         * *  *  *  **  **   * * *    **** *   *   *** **  *    * ***
**** * *** ****  ***  ***** *****  **  **    * ***** ** * ****   **     ******** *
    }
 **    *   **  *** **   * * ***   **  *** ** *  ** **  * *  

    }




 * *  *  **   **   *** **  *  * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * ***  *** 
#include *   * *  ***

int gcd(int n, int m)
{
 ** ** *     **   * * **** *  *  gcd, remainder;

 **  ** **  * ****  ***   ** (n != 0)
* ** ** * * ******  *   
*  *** ** * ***    ***  ****** ** ***  ***  *   *  **   ***  *  ** = m % n;
 *     **    *    ** ** *  *   * * *  * *  *  *        * = n;
* ** *   ***  *    * * *     *  *   *  *** ****  ******   = remainder;
*      *** ** **** * *  * ****

* * *   ** ***** **** ** *     *  = m;

*   *  * *      * **     *     gcd;
}

int main (int argc, const char * argv[]) {

   ** *  * *  * *       *   number1, number2;
    ***    *     * *** ***  * *** newNumber1, newNumber2;

 **** *     *  * ** ***   ** ***  ****  *   * *  *  **** ** ***  * *   *  **

 * * ****    *  * **  * *   * *****  = number1 /   *   ** number2);
   *  **   *  ** *    * ****     *  = number2 /  *  ** number2);

*   * * * ******* *** * * * **     *  ***  ** **  **
     *  *     *    ** ******* **  **  *  *          * * **  ** *   ***  *
**     *      *** ***  **** 
*  * *  ** *   *  *   **   ****** * ***  * *  *     *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   * ** * *  **    *
*** **  *** * **  * **

int  * *   n, int m)
{
* ** **     *  int gcd,  *   * 

*  **  *  *****   ** (n != 0)
*   * *  ** {
** * * **    ****** *  ******  ** * = m % n;
 *  * *   ***** *   *  *  ** **   m = n;
  *  *    *   * ** ** *** ** n = *******
    ***   * * }

***      * *     *   gcd = m;

*  *   *   * *  **  gcd;
}

int main (int       char *     {

* ** *  ** *** int     *    
  *  *      **   int ***     ** **  

   * ***  ** * *   ** * * **  * *** **  ***** **  * *** ***  **

     **  ***  *    * = * *** / *** *** ****
 *      *   **  ** ** ** =  *   / ** *  * *  *** *  

*  *  ***** *  if  * **  *  *** ****    
   *   **  *   ** *    **   *  **        **  *     * *****
  * *   ** else
**      *  ** *** ***  *    *  * **  ** ***   * ** 
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
*  * * ** * * *****  **  * *  ** i;
 * **   *   **  *** *   **   * j;
 * *   *  * *** * *    *** * **** newNum1;
*      ****  *  * ** *   *  *  * newNum2;
**    *****   *********    gcd;
 **  **** *   **  * **** rem;
 ***  *    *    * * * ***  * num1, num2;
    
*** ** * *   * * *****   *          ******  ** *   * * ** **   *  
 *** ** **  **  *  ****  **
*  **     *** ** **     ** *  *
* *** * * * ******   **   * ****** 
* ***  *  ** ** * *     ** * 
** ***  *     **** *  *  **   != 0)
*    **    * ******    *   *
** * * *** ** ** **  * * *  *** *******  ***  ** **   *  = j%i;
  *** **** *** ** *  ** ***  * *  ***   *    * ** ** = i;
*    **  ** *   *    *   *  *    **   ****  **    *   * ** = rem;
** * *  *** ** * ***  ** * **   
*** ***  * * ** **    *  **   ***
    
** *********   **  **    **  = num1/gcd;
 ** * *  *  ** *    **    *  *      = num2/gcd;
    
 ***  ** * * *  ** * *  * ********* == 1)
**  *** *   * * **   **** 
* * * *  *** *    ***      * * * *    ** *** ***  ******  ** * *  * ** ** *** * *** 
****  **  ***     ***  **  *    *
    
*   *    **   *      *  *** *    
*  ***   ** * * ** **  * *  * *
   * * **  *   ** * *   * **  *   * ** *      ***  **  * **  **      * ** * ** **   ** 
*   *** * **   * *   * *
    
   * ** ** *     ** ******   * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 **   ****** * ***  **   *  * * ** i;
 ** *   **     *  *    *  *  j;
**    * *      *** *** ***  *     newNum1;
 * *   *   ******** *** * * *  * newNum2;
 ******  * **  * **  * * ***      gcd;
** *     *   ***  ***  ***   * rem;
* *** *    **   * * *  *   * *  num1, num2;
    
   * * *   * *** *  *  ** ** **   ******    **  *  *** * **   ****
*  * ** * *       ***  
*** ****    * ***** *  **      *****
  *  ****** * *** * * * * * * *
*** * *      * * *  *  **   *
* * * **  ***  * ** *   * ***  **   != 0)
* *  * * * ******   *  * **  *  *
 * ** *  * *  * ***  * * *** ** * *  * ****   **  ** = j%i;
** **  **   ***  *** * ***    *   ** *** * * *** *****   = i;
*  *      * **  * ****     *  * * *  **** **** ** *   = rem;
 *      ** *   * *** * * 
* *  **  *   **     ** ***    * *
    
     *    ****  * * *  * ** = num1/gcd;
   ***** **  ******  *** ***  * * = num2/gcd;
    
  **  *     ******* *** *  * * * == 1)
*****   ***** ** ** *
**   **** **    ****** *    **  *** * * *  * *      *** ******* **   ***** ** **  
***   ** *** *  * * **  ***
    
** *** **  ** * *** ** **
   *  *  *** *  *  *******
*********** ******  ******   * **   **** **     *  * *   ** ***    ****   ****  *  *
   ***** **  **   ***** ****
    
*** ***    ** *  *  *  ****  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
**  * * * *   *  *  * ** * *  * *   *   **    *****    
*  **     ** ** **  ** ****   * * ** * * *   ***** *  **    * 
    {
 *    *  **** **** **** * ** **    * **   *        ** *  ***    
 * **  ** ** *   *  *** *     **  *  ** *  * *   ****** *   *  * **
*  **     * * **   *  * *******  *** ** *
* *  *    *    * ***   *        ****  *  ****  ** 
**  ** * *****  * * ** **  *** * *     *       

      * * ***** *   *    ** **  * **
*      * *  *   **** * * * * *  * * **   *  *  ** * *  *** ****    ****  *  **   **   * ** ***    *    *
 * **    *** *   *  ***  **  ** ** * *******   *    ***     *  **  ****** **  * 


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
  **  *  **  ***** * ****** a,b,GCD;
**   * * ****** * ***  * ** **  *  **   ** **** * *** *** *   *** *  
*  **    *    * **      * *     *  
 **      **** ***  ***   * *  **
     * * *  *     **      *     *  *** **     *  *  **     *    **
*** *** ***** *** ** ***  * ****
   * ****  *** **  *   ** *  **    *      ** ** * *  * *** *** ******* **    
   *   * *** ** *  **        *   0;
}
 * *  * * *  ***  ** **   ** ***   gcd(int a, int b){
*   * ** ** ** * *   *  * *** **   *   **     *  ** * *  (!b) return (a);
   *   *  ****   * *** *     ****** *  ** *  **    *    **  *** * * gcd(b, a % b);
    * ** * ** * **** ** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * **   *  **
#include  *** **** *   *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
   * *  ***   *  **  **  * gcd, remainder;
*  *     *    * ****   **  *  *
***  ** ** *  *      * * *   (n != 0)
 * ** * *       **   * *  *
 **  *****        ***** *   * *  *  * * ** *   *****    * ** ***    * = m % n;
* * *  * *   ** *  ** *****     * *  *  *  **     *  **  * * = n;
    ** ** *   * * **  * **   **   *  *  **  **  *      ***   = remainder;
******* *  **** ** **** **
 **    *  * * ****  *** **  
 *    * *   * * ** * *  **    = m;
**  * **   *    **  * * 
*    ***   * *****    ** *  *** ** gcd;
}
int main (int argc, const char * argv[]) {
***** *    *   *  * * **   * ** number1, number2;
*****     * *  ** * ** *** ** ** newNumber1, newNumber2;
*      * **** ** **  ****   *
  *    **  **     * ****   
*      ** * ****  **   * *      * *** *** **  *   *    *    * *** * * 
** *      *    ****** * ** *
 ***  * * *   ** *    ***  * *  ****** = number1 / gcd(number1, number2);
 *  *    ***  ** ****            * = number2 /  * *    number2);
*   **   * * * * *   * *** *
  **  * *   *  * * ********** **
* **        * *   *   *    * (  *****  * 
*  ***        *   ** ** **   ** ******    *** *  *****  * *** newNumber1);
 ****   ***  **    ** ** * ** ****
****  *** * *    * ******* 
***** * *      **    ***   *     *  * **   * **** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** *    * *** *      * ****   a,b,c,d,e,f;
      *** *** ** * * *      * * * *  *  ***  * ***   *  ** **  * 
***    ****   *** * *  * *
* *   **   ***    *** ****  * * 
**   ** *  ** ***   * * ** * * 
    {
 *  *  **   * **   * ** * *  **   ***  *** * ***  *  ** * 
****    ** ** *   *  * ** *    **** **  **** * * *** *
 *********      *  * * ***** *  ** **  *  ** ** ****** *  *   *
    }
 ** * **      *  **  ***  ** *   * * *   *
    {
 * **  * * *  **   * **   *   * ***  **  ** ** *   ****    *** * *  *
 * ***** *****   **  * **** *   ****** *  *  *  **   ** ** * *    ** * ** 
*  * * *  * **   *** **    * ***   *  *** * **  **  ***
 **  ** *  ** *  *  **  *** * * *  ** ***  ***** **      *   * ** ** * *  *  
    }
 * ** **** ***** *  ***  *    
    {
****** ***** * **** *** ** *  *** * * * ** *  ***  * ***  ***  *   
*     ** * * *  ****  ** **  **  ** ** *  *** ***** ** ***  **  ****  *  **    * 
 * ** ***** **       * * **************** * ***  * ** **
 **** *  * **   * ** * * *    * * * *** *   **   ***** ***** * ** **   **** * * **  **    * 
    }
 * **     *   ***  *  **** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.50
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 8.3k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 8k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 10k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 7.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users