11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
14.4k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 14.4k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

    *   * *** * **    *  *** i;
**** ** * * * ***     **  *  j;
 *  *** **  **  *    *   ** *   newNum1;
*****  * *   *** ** ***** newNum2;
      *** ** * *  ** *****   *  gcd;
  *  *** **  *  *     ** *      * rem;
*** *** *  **   **     * * num1, num2;

    *** *  *** ** ** ** *      ****** ***    *** **   *****  * *  **

*** ** * **  *  **  *  * **  ****
 * *  **** * ***  **  **   *

* **  *   ** ***     ****   **  ** != 0)
* * * **   *  **   *  * *
 *****     * *  *            * ** *  * ** **  *  ****   ** * = j%i;
 ***  ** *  *  *  ***  *   ***   ******* ****  *  *    = i;
**** * *  ** ***  **  * *     *  * * * *  * ** * * *   = rem;
 ****  ** *   * **     ****    
***** **   *    **   * * *  *** 

   ***   ** * * * *  ***** ***     * = num1/gcd;
*    *  *** ***** *  * *   * **  = num2/gcd;

 **    * **     **  ***   *  == 1)
    {
 ***   *  *  * ***       **  *** *****  **    ****  ***   *     *  *  **  
    }

  *   *** ** * ** ** * *     **
    {
** **  * *  ** *  * *  **** *   * **  ** **** *   *  * **  *    * * ** ** ***   * *   * ** ** 
 * **  *** * * ** *   * *** 

** *** **  **** *  **** *** **  * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** **  * ** * *  *   **      *  * *  *** ** **  *  *   **  ** *  

 *  * *   **  *  *   * * *   ***** *
  *** *    **  **  *  * **  **  *   *  *** *  *  **   * ****** * ***** ***

    else{
*** * * **********     * **    *  **
    {
*** * * ****   ** *  *     ** *  * * ****  *    
   *******   *  ** ** ** *** **  * * * * *** *       * * *  ** ** **** ****  *   && deno%i==0)
 *   * *** * *****   *  * *   **    * * * **      * **** * * *     *  *  
   * *  * *  *  ***   **  * * ****   **  ***** * ** *****  * **  ** ***  **  ***** *   * * *** **  *****  * 
**    *  **  * * * * * *  *** *    **    ****   **   ***   ** ***  **** **  ***  * ***   * *** *    ***         * *
 ** * * ** *** **   *     * *******  * * ****   *   *  * **  * ** * * ***   *** **
    }

*  * ** ********   **** *   ** **** **** *   
    {
 * ** *   **** ***  *   * * * *    *  *   * * * *
     * **** ***** *   *  * * ***   *      *** * * * * **** ** * * **  *   **** ** ** * && deno%i==0)
 *     *** *  * * **** * *  **  * *** **    ** *****     * *   ****  *   ** *  **
 *     * *   ********* *   **   *        *   * * ******** *   **** ** ***  * ********** * ** *** * ****
     *** ****   *** **  ** *** * *** * ***  *********   *   ** * **********    * *  **** ***  ***   **  ***
  **   *** ***  *    *   ** * * ** ** * ** ***  * * ** *  * *      * **  * * ** *    **** 
    }
   *     ** ** * **** ****   *  **   ** **  ***   * *   

    }




 * * **  *  **  **** * * *  ** * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **** ** ****  *
#include  *  **    *   *

int gcd(int n, int m)
{
*  * *  *  * ** *  ***     gcd, remainder;

  **  * *  * ****  * ***   ** (n != 0)
**      ***  **  *** * ***** * * 
*  * *   ** * *       * *   *  *  * *   * *** *  *   *    **** = m % n;
    ** **      *** *   ***** ** *  *      ***  * **  * ** **  = n;
  * ****   * *   *  *  ****** *   ****  *   ****    = remainder;
* *   * * *    ***** **** *** 

*   ** *  *  * *     ***   **  = m;

* **   *   *    * ** **   *** *** * gcd;
}

int main (int argc, const char * argv[]) {

*  * * *   *   ** * *    *  *  * number1, number2;
* **  *    * ** * **** * *  newNumber1, newNumber2;

  *    * *     *  **   ****** * ***     ** *    ****** ** * * *** *

* *   ** * *  *****  ** ** * ***  **  = number1 /   *  ** number2);
*  ** * **  *  **** **  ** ***  = number2 /  * * **** number2);

** *** ** *  **** * *** *  ** **  *  *    * *     *
* *   *****   *  ** * *   *** ***    **** * * * *     *    *   
** *    * *   *  ******  ********
 * ** *  *   *     ***   *  *****    **  ** **   * * *     *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** *      * * * ******
*  **   * ***  *  *  *

int   * ** n, int m)
{
*   **  * *  *    int gcd,  *   *

 **    * ******** ** (n != 0)
* * * *   *  *    {
 ** ***       *    *  * * *       *** * = m % n;
  *  ** * **     *    ** **  m = n;
*     ***  **   *******     n =    * * 
 * ** *   *** *  }

*     *  * * ** gcd = m;

  *  *   ** * * *   gcd;
}

int main (int * *   *  char * * ** {

  *     *   ***  int  ** * *  *  
*   *** **  * * * int *      ***  * 

         *******  *****   **  * *****     *       **  ** * ** 

** *  **   **  * * **** ** =    *** / * ** ***   * *
* ** ***** ***   * * *   =     /  * *   **   ***    

*****  **   *  if **  *      *  *****
**  * * *         *     * **  ** ** ***  *        *  * 
 **      **  * else
*** *    ***    * *  *********  *   *** **  * *    *** ***  
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
  **  ** ** * * **     ** **  i;
*       *  ** * * **  *  **   *    ** j;
 ***** **   *  * * **** *  ** newNum1;
** *** * * ***  **** ****       newNum2;
   * *****        *** * ** *  * gcd;
*** ** ***** * *  ****   *  rem;
 *  * * * *   * **  * * **   num1, num2;
    
  ******   * * *   *   *  **   ** ** * * ** * ** *  *   **       * **   ** * ** 
*****  *  **** ***** *
 * * * **  * **  ** * ** * *   
*  * * **  *  * * * * *     
*** **  * **  * **  **** *
***  * * **   **    * **  **** * **  != 0)
**  *   * *   *   **  *    
****   *  ***  **** * *      * **    **     *   * ***   *    = j%i;
*   * *** *  *   *   ******  *** ** *   ** * *  ** ** = i;
*** ***** ****** **    *   *   *** * *     **  *  *   * = rem;
* * *** * ***   *** **  * ** ** 
** *  * *  ********* ** ** **
    
 * *  ***  **** ** * * *** *  * ** = num1/gcd;
**  * *** *    *  ***    **** = num2/gcd;
    
 ** *** * **    ***    ****   ***  == 1)
   * *   **       * *    
 *  ***********  * * **     ** *****    * ** * *  ****  * * * *  *  * *** ** * * *    * 
 * *  * ****  *   *   * *
    
 *** *  * * * *  *  **  ** 
*  * ** * * *** ****** * 
  **** * * **    *  * * *  * * * **  ** *** *   *    ** * *** *   **  * *        ** **  *
 ** *  ** * *   *  * ****  ** 
    
* *   ** ***   ***  **** *   * **  0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
*****   **  *  * *   ** i;
 *  ***  * * **  *** ****** *  j;
*****  *   *  *** * *   *** newNum1;
* **   ** ** ** ** **  *** **  newNum2;
* *      **   *  *   *     * gcd;
**    * * *     *** *     rem;
 *   **    ** * ***  * * *   ** num1, num2;
    
      * *******  * * * *   ** ***  *   **   *  *    * *** * * *  ** *  ** 
 **  **  ****    ** *  *  *  **
  ** * ***  *    **   ***** *
******* *   *  **   * * *    ** *****
   ***  *   *        * *** 
  ***    * * *   * *      * **  != 0)
***     **** *** ***    *
   *  ******    **** *  *  *   *       **   ** * *** = j%i;
  * * *  ********* **    * ******   *** *** ** **  **    **  = i;
* * *** **   * *  **  *   *    *  **    *  * *   ** *  = rem;
   ****  **   *   **   ****  *  
 ***     *** ** ***  * *  **  
    
 * * * **    *  **** * **    ***  = num1/gcd;
* ****     *** ***  **   **    * = num2/gcd;
    
*  *   * *     * ** ****   ** ** * == 1)
 *     **    **   ****** ** ****  *
 ***  * ** * ******* * *    * ****** ** *   *  *   *  ** * *  *  *** *   * 
 ***  *  * **** * **   *** 
    
  **  * **  *** *  *** **  *  *
 *   * **   * *  * * *   ***   
     ** ***   * * **      **  *** **** **   * *** *   ****    ***  * **       ****   *   
** ** *  *** *  ** **     * 
    
 ** ** * **     **  * **  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
    **   * ** *** *    *     *******  * **** ** * *    * ** ** **  
***   *  *  *  ****   * *     * *    *  ***    **** *****
    {
  *   **   * *  * **  * ***    ***** ****  * * *****    *  *   *    ** 
****** *  * *     * * * **  *  * **   *** *  ****    * *   *        * 
 ** ** ** **** ***   **   *****  * ** *  *  
    * ***  *  * **** ** *  *** *  * *   ** ***
 **     ***  **** ** ***** *  *** * ***      * 

 **** *    *  ***  *   **** ***
 ** ** ***** ** ** *     *   ** ** ** *  *   *   * * *    *    * ****  *** *  * **   * ** *** ****   **  ***
  * **  * * **  **  ** * * ***  ** * ** * *  * *  *  * ***   ***   *  * **


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
 *   *  **   ** * *   *   a,b,GCD;
 *  ** *** ** ** *  * *    *  * *** *  * **  *     **** **        **
   * **   * **    * ** * *  *    * * 
 **  *   *** * * * * ****   ** * ** ***
 ****     *    * ***  **** * ** * *   *   **   *   *** *   *  * ** ***  ** 
* ***       **   * *** *** **  *
 *** ***  * *   ** * *****  ** *** ** * ***** **   * ****  * ****   ***   *
  *   * *   **        **** 0;
}
 * *     ***   ** * * ** *  * gcd(int a, int b){
 *  ** **  * * ** *    * ****  *     **** * ***  *** (!b) return (a);
 ** ***** * **  ** *** ****      *  **  **   * *  **     *  * gcd(b, a % b);
*   **** ** *  ******
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * **    *  **  **
#include  ****      * ***

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
 **** * *  *****  * ***   * * *  gcd, remainder;
****  **  **  *  * ** ***  *
 * ****      **** * *  ***     * (n != 0)
** **  * *     **** **  *  ** 
  ********* * * ****    *  *  *** * ** *** **  ** ******  ** = m % n;
* * *** ** **** * ***** * ** **  **    ** ** *   *   ***  = n;
    **  ****  *****   **  *** ****  *  ****  ****  *  * = remainder;
***** *  ***   **   * *  * *   
    ** ***   ********  * *   * 
* *    **    ***  ** * *   = m;
* * ** *   ** **  * ***
***  * * *  * ** *** ** ****  *  *  gcd;
}
int main (int argc, const char * argv[]) {
  *  *    *    *  *  * **  * number1, number2;
* * ** *      *  ** ***  * ** * ***  newNumber1, newNumber2;
  *    * * ** ***  *    **** * 
      * *   * ** ** ****** **
 **   * *   * **       *    *    * * **  *  *  ****   **     *     * 
 ** *     * *          * 
  *  ** ******   *   *  ** *****    = number1 / gcd(number1, number2);
 **   *   * ****** * *    * * ** ** = number2 / *   *     number2);
 *****     *  *   *       * *
* * * ** **   *          ****
    ** *  * * ***  ****   ***** (  ** ** *
  * * * *  * *  ** ***   *    *  * * * ** **    **  ***** *   **   * *     *  newNumber1);
  ***   *   * *** *  * ** 
  *   * *     * *   *   ***  
 ***** * ** * **     *  * *  **  *  *  *** **** * * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*  *    ***** * * ****  *  *** a,b,c,d,e,f;
  **  *** **  * ** * **  **  * *** * ***** *** *  *  * ***    **
  *     * *   *   ***** ** * *
 **    **    * ** **   ** ** 
   ** * ** **  * * *         * ****
    {
 ** *    *     **  * * *    * **** * * ****   *    
    **  **   *  * *  * **    ** **  **  **  * ** * **   * ****
*  *** * **   ** *      * * ** *  * *  *    *** ***** *  
    }
* ***  ** ***  *** ****  *  ***     
    {
 ** ****  ** * * ** * *** *** ** * **         **  *  *  **     *
* ******* * *    ****  ***** **   * ** * **** **   ******  **      *** * 
* * * *  ***  **   *******  *   * **  *** *  ** ** ** **
* **     * ****  ** *  ***   **  ****   ***  * *** ***  * ***   * *** *   
    }
 ***  *  ******   *  ***   **
    {
  * *   *   ** * *    * **         *  * *    *** **   *
 *  ** ****  ** **      *     ** ***  *  ** *  ***  *  ***  **  *    ** ** * **    **
 *** * * ***  * *  * ***  *   *    **** * **   *    
 * *    * * *  *** *** ****  *    * * * **** *   ** *   *** **** **   *** * ** * * *** * 
    }
*  *  **   *** * ** * ** **   * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.196
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 14.6k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 14.4k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 18.5k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 14.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users