11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
9.8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 9.8k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

   **  **    *  ****  * * * i;
*  *        **     **    *  * **  * j;
*   * * ** ****** **** *  newNum1;
**   * *** ** ***** ** newNum2;
* **  * ** ** *   **     ** *  gcd;
 *  **** ****      ** * *  *  rem;
**  * *      ***   **  * num1, num2;

*  *** ** *  * **** *    *  *   ****  ** ***  **  *** ***   *  

*** *     * ** *  ** *  *  
*******   **** ** *** * * * **  

  * ** ** ******* * *      *** != 0)
 **  * *    *  * ****    
 *    ***     *   *   ****   ** *** ****  * *** = j%i;
*  ***   * ** **  * ** **    *   *** *  ******  ** *  = i;
*  *  * ** * *  **    ****** **  ****  ***** *  *   = rem;
* *    **** * * *    * * * * ** 
* * ***   *** *****  

*  * * **** * * ***    *** **  = num1/gcd;
 * ***  * * ** *** * * *  **   *  *  = num2/gcd;

* *  *   **  ** ***** * ****  == 1)
    {
* ** * *** * * ****  *        *** *   * *  ** *  ** * * ***  *  **  ******  *   
    }

  *** * *     *  **  * *  
    {
 * ***** *    **** ** *** *  ***      ***  * *   *****   *   * ***    ******* * *  *  
* ** *  ***  ** *    * **     *

  * ***   **  ** ** * **    * *    0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
*   ** *********    *** ** *   * *  *  **** **  * ****** *    *     ***  

     * *    **  *** ** *  * * **  *   **  
***** * ***  *   ********    ***  *  **** *    ***   * **  *   * *** ** **  **   *  *  * **   *

    else{
  **  * **   **     **  * *  * *  
    {
  ** *  ***      **** * **  **** ** **  *** 
  **  **  ** ** ****** *********** *** ** ** **  **   * * *   * ** * ****  **  **  *** * && deno%i==0)
*  ***  ***        ** * *  *   * *   *** ** * *  *  **    **  *   ** **** ** ** ****  **
*  * **    * ** ****** *   *    ** *  * **** *  *** * *****    ** ** *** *  ****  * *****   **** ** *   *  
 ***** *  *  ** *     *  *       *  ***   ** * **  **  ** ** **** * * * *  ****  ** * * **** *    *  ** 
 * *       ***** *  * * ** ** ***   ****  **  * **  ** * **  * * * * * * *** *******   *  *
    }

** ***   ****  **  *  ** ** * *  *  *  * 
    {
***** *   ****  *  *  * **      *  * **   * *
* * ******  ** **   ** ** **  * * ***    ***  **** ** *   *  * ** * * **    * && deno%i==0)
 ****** ** * ***  ***  **  ***** **   *    ***** * * *** ***  *** ****     *  ***
 * * **  **  ******  **   **  * **   **    *  *    ** ***    * **      *    *  *** *  * *  *    ***  **
 ****   **  ** *    *** ** *** *  * *  ** *   **      * *  **  *  * ** ****  **     *     *****  * *    *****
 *    * * ** * *  * ****    ** *    *     ** *  **  **   ***** * ***  * *    * * ***  * ****  
    }
***  **  *** ***  * *  *  * *  *    *    **  ** * * **

    }




 ****  * **    *** *    *    **  0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ****     * ***  ***
#include  ** * ** ***** * 

int gcd(int n, int m)
{
 *** * **  *  *  * ***  *** * * gcd, remainder;

*  * ****  * *  * **  **   ** *   (n != 0)
 *  *  *** ** ************
*  *** * *  *   *  *  * ** ****  *  **    * *** ** *****    ** * = m % n;
  ***  *   **  *  *  *  *      *  **  ****** **    * = n;
 ***   *  ******  *   ** *  *******     *    *   ** *     = remainder;
****  *  * *  *  **  * **  

**   * **  ** * **** **** * = m;

* *  *** ** *  *   *** ***  * gcd;
}

int main (int argc, const char * argv[]) {

** *  *  ** ** **  *** *  * **** number1, number2;
 ***  *  ****  *** **** ****** * *  newNumber1, newNumber2;

 *      *** ***   *  ** ***   ** **    **     *   *    *** * * * ** *******  *

  **** * * * ***** ***   * ***** * = number1 /   *    number2);
       *       *    *      *    **   = number2 /    ***** number2);

** ***     ** **   *   * * *** ***  * * **  * * * 
 ** **** *    * *     * *            ***   *    **   * ** ***      
   ***     **   ** *   * *   * ** 
***   * ** * ******  **   *  * **** **  *  * **     * * 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*****   ** **      *** * 
 * * *    *  ***   *

int  ***  n, int m)
{
**     * *** int gcd, *  * * 

*****  ** ***  ** (n != 0)
* **** *   *  *  {
** * ** **   *  * *  **  ***  * * *  * * *    *  = m % n;
* *     *  ***  * *  **  * **  *   m = n;
   ***  ***   *   **  ** * **  n =   *  ** 
**     * ***** }

  ***    * *  gcd = m;

   ***     * * * *   gcd;
}

int main (int *  * char * **    {

* * ** ****  *   int *  * **** 
**  * **    *  int ***  ****       **  

  ***  *   * * *  *    ****  ***  * **** ** ** **       ***  *  *  

*  ***** *** * * *  *  =     /  *   **       ***
**** ** **** *   ** =   *   /    ***  *   

*  * * * *** ** if *  *  ****   **** 
** **   *  ** *** * * ***** * * *   * **     **   ** *** 
 ***  * * * ** else
**  *   * *** *  *    * *    * **** *   *   *   * ***  *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 ***** * *   *    ** **** *** i;
 **  *  *** **   ** *   * *****   * j;
**** * *   *    * * ******   *   newNum1;
**    * * ** ** ** ****  *  *   * newNum2;
 *  ***  *  ***** ** *** *** gcd;
   ***      *   ***  *     **  **   rem;
* ********   * *  **  **     * num1, num2;
    
* ****   * ***   * *    * **  * ** **   * * *   *  *** ** ** * **
   * **  *   ** **  * ****
 ***   **   * * * *** * **  *     **
 *   *** *    *  *      ** *    *  
 *** *   ****   *    **   *
   *** * * ** ********* *   * * != 0)
** *** * *  *  *   ** * ***    
    *  ** * * *** ***** ***** *** * ***  ****   **    ***   = j%i;
*** * *  ** *    * **      *     *  *** *  ***  * **  * ** ****  = i;
 *   * **       ***  * * * * ***  *   ** **  * *   **  = rem;
 **  * ******* ** *  * ** *    *
  ***** * *     *** ***** ** * 
    
** *** * * * * **** *   ** * = num1/gcd;
    * *   * **  **      **  **    = num2/gcd;
    
****** * *  *  *   *** ******* ** ***   == 1)
*  ** *    *     ***      *   *  
 *  * **** * ** *  * *** ** ****    ** *     * *  **    *     *  ** * **   *
  *       *  *   **   *****  ***  
    
** ***   ** * ** ** ** *****
      **    *   * ****   ***  * *
 **** *  *     * * ** **  * * ** * *   *   ***** ** * **   * ****** **     * *** ***** *  **
   ***** *** * * * **     * 
    
*   *   * * * * * * * *   ** * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 ** **  *  * ** **  * *   * ** i;
    ** *     **  * ***  *  ** * * j;
 * *  *  *   * ***  *  * ** newNum1;
* *    ** *  * **  * *        newNum2;
**** ** **** ***    ****  **   gcd;
*  *  *      *   *  * * rem;
  *  ** *    *  ***    **   ***  num1, num2;
    
*    * * ** ***** * *  **   * ****   *** * * * ***  ** * **  ** * **
   ** *   ***     *
 * *   ***** **    * ******    *
  *      ** *   *  **  **   ***  * 
 * **  * * **   ***** *** ** *
* *  **   * ** *  ** *    **  * *  != 0)
   * *  *** *  *   * **  ** 
 **   **** ***  * ***     ***  ** **   *   *** * *   = j%i;
 * ** *    ** **  * *  *   * ***    ****  * **  * *  * **** ** ** = i;
 **   ***** **  *    *** ***  **  *   ** ** *  *    *  = rem;
   *** ** *  ** * **     *
*  **   * *  ** *  ***   ** *  
    
*****  **   **** **  *** ***    = num1/gcd;
   * * *** * *  *  *****  *   *** = num2/gcd;
    
  **   ***  *  *  *    * *   *  == 1)
  **     * **  *    ** * * ** **
 ** *    **  ***  *** *  ***  ** * ***   * ************ *** **   * *   * **** **  ** 
 ** ***    *  ** ** *** 
    
*  ** **  **  * *  *  * ****    * * 
  *** * *  * ****  **  *    *  
*     *** *  *  *   ** **  *   ** *  * *  ** * **** **    ****     * ** ****   **  ****    
 ** *   *     **    *    *      * **
    
* *    ***  * *** **  ** * *** *   0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
 * * *  ** *    ***  ***     *  *  ** *   * ** **   ****  ****  **  
*** * ****  * ***    **** * *  **   *   * * ****   *  ***  * *
    {
   **  ****   *  * * *** *****        * **   * *  ****  ****  *  * ***  *
 *   ***      ** *   **  * *  ***  * **    * ** *  ******* * * **
****** *** *  * ** ** * * *****  **  
**   *   *** ** **  ** ****  *    *  ** * * ** * *
     **    *  ***** ***** ** **    ******  *

****      ** *   ** * ** *** **   ** 
 **  * *   ***** * **    * ** ***   ** **  *   *  ***  * ** ** **    *  * **   *  * **  * *  * *   
** ********    ***  ** ***   ** **** * **** ***  *   *   ******* **    *** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
   ** **     *      ***  *    a,b,GCD;
* **** *  *  **       *   **  * *** *    * * ********** **      
 *   *      *  * **   *** ** * 
 * *  *     **  ***** ** ** * ***** * **
 **  ******  * * **** **  *** **    * *      ** **    ***   * * * **  
  *  * * ** ** *  ***   *  *    *
*   * *  *  *****   **  *    *    ** ***   *        ***    * *  *  * ****  ****  *
**  * *   * *** * * * * ** * *  0;
}
*  *  * * * *****   *    * ** * *  gcd(int a, int b){
* * **   *   * **** *  * ** ** ***   * * *        * ***  *   ** (!b) return (a);
*   *  * ** *  **** * * *  *    *   **    ***  *  *  * * ****** gcd(b, a % b);
****     * * * ******  **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * ****  *   
#include * ** **** *    

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
**** * **  *** *  ** *   * *   gcd, remainder;
 *     *  **** *  **
  * * ** **   **  * *   *** * *  *** (n != 0)
 *****   *******     ****  
**   * *    * * **  **  *    * *** *    **     **    * **** * * = m % n;
 * *    ** ****  **   * *****    **** * *   *   **   * = n;
* * **   *            *  ***** **  * * **  ** *  *   *    *    = remainder;
  **    *    ** *        
 *  ** *  **  **   ***      
**        *    *  * * * = m;
 **   ** *****     ***
*  * * ***     **   ****** *  *  gcd;
}
int main (int argc, const char * argv[]) {
* * * * ***   *   * number1, number2;
*** *  *   *  ***   ***  **    **   newNumber1, newNumber2;
******* ** **** ***** **** * 
*** **     **          *  *
  **  *  *      ** **   ** *** * **** *          *    *   **    * * *  ***  * 
**  **  ****** ***  * *   *
  *  **   ** *****  ****** *  = number1 / gcd(number1, number2);
   ** ******    ** ***  *   ** *  *   = number2 / ****  * number2);
*  ** ** *  * **     *  * *
*** * **       * * **  **  
 ** *    * ****   *** * *** (  *  ** 
*   **  **     ****   *  *  **  * ****  *  **  ******** **  * *  **    ***  newNumber1);
 ***  * ** **   * * ******
 * **   *  *   ******  *   **
*     * *   * *      ***  *  *   * *  ** *  **  ****  newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
**    *     * * *  *     ** a,b,c,d,e,f;
          * *  **   * **  * **    *** *   *        *   *  ******  *  
 **   ***** **  ** *  **    
* *  **   ** ** *      *  *  *  **
  * ** *** * *  ***     *****   
    {
 *  ** **** **   * *** *  *     **     *   **  *   **  *
*     * *   **  ******  *  *** * *    * * * ****** *** ** *   
      * **  * *** * *  ** *** *  *** * * * * ** * **  * 
    }
 *** * *  *  *    *******    ** * *
    {
       **  *****   ** **  ***   **     *** **  *   * * **   * ** ** *
    *  * *  **** *******     *    * *  * ****** *** * **** *** **   * ***** ** 
  **** ** **  * *  * **** * ** *   **  *     ** *  * **   
 * * ** *   * * * * * * **     ** ****    * *  *  *   ** * ***  * *   * * *  *   * *** 
    }
 **   * * ***  ***    * * *
    {
    *** ***   ***** * *  **  * **** ****** ****   *    
 * *** * ***  *****  **** *    ** *  * **** *** ** **     * ***   ****  ** *
* ** * **  *   *** *  *   * ****   * *  *  *  ** *  **
 **  ** ****** **  **  *  * **   *****     **  ***  *** * *    *   * ** ******** *
    }
 ** ********* **  *   **   ***   0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.119
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 9.8k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 9.5k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 12k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 9.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users