11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
12.3k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 12.3k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

*  **      **   * *  * * *  *   i;
   *   *** **   **   *** j;
  * ****** ** *  ** **** **** newNum1;
  ***   *** *  * *    * newNum2;
 **  *** ** * ** *****  **  ** gcd;
 * *  *******  **** *  * * rem;
* ** ** *  *    *   * * *     *  num1, num2;

**** * **** * **** *  ** **  *** *  *    * * *   * **    * ****       

*  ** * ***** *  ***  ***  * 
**** * **   *    *   * *** *    

*     ***  *  * * * ** *  *   **** * != 0)
 ****  *  *  ** * **  ** * 
 *  **  * *    *     * *  *** *   * *   * **  *  **  ** = j%i;
****  *    ** *** * * *   **  **  ******      *****    * = i;
 *** ***  **   ** ** *** ** *** *** * ***********   = rem;
****  *** **    **   **   * 
 * *    *  *    *** * **** *** *

  *  *  * *** *****     * *****    = num1/gcd;
* * ** ***  * * **        = num2/gcd;

 ** ***** * ** *  **********   ** ***  == 1)
    {
 *** *  **   **  *     *    ****    ***  * * **** *** ***  ***   ***  * 
    }

* ***** *    ****   * *   *** *  ***
    {
* *  ** ***    ** *** ** *    *   **  ***  *** **    *  * ***   ******   *  * * *  
   ***    ** **  *  **   

 * ******* ****** * * *  ** *  * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * **     ****     * *  ** ** **  ****    ** ** ** * **  *** ***** *

*****   *     ***  *  *      **  ** 
** * *** **    **   **    * ** ***  ** * *** *  * * *  **  ** * * *  ***  ***

    else{
   *   ** ****  *   * *    ** * ** * ***
    {
**** * * *       ** *  *  *        ** *   
      * *  * *  ****   **  ***  * * ****   ****   * ** ****       **   ** * ******* *** ** ** ** && deno%i==0)
** ***** ***  ** * * *  ** ** * *** * *   ** *  * *  *        ***   **        **
    * *    * *     * *******    ** * *  * *  *******  **   **    ** ****  ***  * * ** ******* *   * *
    **   * *** **   *** * * * ** **     ***      *   ** *     **  ***     * *** ******  *****  **  * *  ** *     **
***** * ** ** ****  * *    *       ** *     ******  *  * *   ** ** *** **  * * **     
    }

*   *  ** *   * ***    *  * ** * * 
    {
 **** ***  * ** ***  **  *** ***  ** *   ***  *
*  *   * * * ***   *   ** *  * ** *   *** *** **    ** * ** ** * * * *   **       ***  && deno%i==0)
*** * * *   * ** *   *   ** * * ** ***  ***  ***  * *    * ** *   ***   *** ** 
* ****     *   ***** ******  * *** **     **  **   *    *  *   **** * *** **    *   *  * *  *  ** *  *** ****
*   * ***  * * *** *        **   *  *** *  *   *    **** *   ****  **  *  *   * * **  *****  *  *     *
*     ** ****  * *******  *  ** *  *  * ***  ** ** ***   * ***   **  * *****
    }
 ****   ** **** *** **  ** *   * *   ******  * ******   

    }




** ** * * ****  * *** ***  ** * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** **** *****  
#include  *  * ***  *** * 

int gcd(int n, int m)
{
** ** * *  *** *** * *  ** **** gcd, remainder;

 ***  * *    *** *     ** *** **   (n != 0)
      **    ***** * **   * *  **   *
 ** ** ** * * * ** ***   ****    * ****   * ** ** ****   *  * * = m % n;
*  ***  ***  ******  ** *  *  *  * ** *  * ***     * * * = n;
* ** ** ***   *  * *  *      * *** ***  ** ** ** ** *    * = remainder;
        *  * * * **      

   * **** * *** * **    *  = m;

 *** ** *****   ****   **   *  gcd;
}

int main (int argc, const char * argv[]) {

***   **** * *  * ***  *    *  **    number1, number2;
**  ******   *   ** *      newNumber1, newNumber2;

* *** ** *        *   * * * *       ** *  ** *  **   **  ** * * * * *

 ********* **    ********* * = number1 /  * **  number2);
*** ** ** ** * **** * *** * = number2 / *  *** ** number2);

*  **  *****    ***  * * ******  * ** ****
  ** * *  *** ***  *  **** **   * * * * **    **  ***  ** *  * ** **
    ****   * ** *** ** ** *******
** *  ***  *** * * *   *** ** **  *      * ****         *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
     **  *    ** ** 
*    ** *****   **    **

int *** * n, int m)
{
* *     *    * int gcd, ****  

  * **  *    ** *** (n != 0)
 **  ** * **  *  {
 *  * *   *   *  **    ****** *  * = m % n;
      ***  * *   *  **  * * * m = n;
******   **  *   **  ** * **   n = *  **   
**  ****  *  *  }

     *  * *** gcd = m;

**  * *** **      gcd;
}

int main (int *  **  char *  *   {

*** ** **    **** int  *  * *** ** 
 *** **       * int   * *  *  ***

 ** *   * **  * * *   **** *  *    *  **   ** * *** *** *** *

  *  *    *  **  *** *   = ** * / *  **  *  * * 
**    * ***  ** **  *  =    ** /  *    * * **

*  *** * * * *    * if * *** ** **  **   ***
* *     *  * **     **** *    ***   ***  *  ** *  *
* ** *   * *   * else
 ***** **   ** *    ***  *  *  ** *****  *  * *  **  *****  
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
*** * ** ** ****    *** *   **  i;
*  * * ** **** *     * *    * j;
 ******** *** * **** *  *   newNum1;
  * * *******  * *****  **   newNum2;
* *****  *  ** **   *    * * * * gcd;
*     *   *    *****  rem;
*  ******   ** *  **     num1, num2;
    
  ** **   ***   * * *  *****  *  ****    *** ***    ** ***    *** * * ** *
** *  * ** *  * ** *     *** *
 *   *** ** **** * ******* 
 ** * *** *     *  * ** **  * **
* *  *      *   *   *******
**  ****  *       ** *** **   * != 0)
***** **  *  **   *** *** **
  *     ** * **   * *****  ***** *  *  *    ** = j%i;
 ****    ***   **   *** **    **  *  * *** **** ** = i;
 *******    ***   *   *    *    **   * * *  *    * * *  = rem;
**   ** *    ***    * * 
  ********* **        **  *  * 
    
***   ***  ******  *  *  **  = num1/gcd;
   ** ** * **   * ** ** ***  ******     = num2/gcd;
    
* **      *** ***   * *   **    *  == 1)
    **  * **  ***     *  *  * *
  ** *  ** ***    *   *** **  * * ***  * ** *    **        * **** *   *** *    
** ** ***  ** * * *    **  
    
*  **** ***  ** * * *   ** *
    **** **  *        ** ** *
 *  **    * **  ***  ** ****    ****      * *  **        *   *   *  * **        **   ** 
 * *** * ***   * **  *   *  *
    
**   ** ** ** *   * * *   * ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
  * *   ***  *****     *  ** *   i;
*  * ** **** **  * ***  *  ****  j;
** *    ***  *   *** **   ***** newNum1;
***  **  *   * *  ****        * *  newNum2;
 *   ***** ** *      * * gcd;
 ** **           *      * *   *     rem;
  *** ***  ***** **  * ***      *  num1, num2;
    
     * *    ****** *******      * ** ****  *   * ** ** * *
  * *   ******  ** *   * 
 **** *     ***** *   
***   ** * ** ******    * * *   *   
   * **  *   *  * ****** **    
  *** **  *** *** **   ***  ***  ** != 0)
 ** **  * ***    *    *   * 
      * *** *** * *    *   ***** * **  ** *    *  *  ** ** = j%i;
****** **   ** ** * **    *  ** *   ****   ***** ** = i;
*** * ***    *    * * * **** ***   ** **  * **  ** ** = rem;
 *  * *** **  *  ** ***** *  * 
 ** *    * **** *  **** * *  ***
    
* **  * * * **    * ** **   **     = num1/gcd;
    *  ***        ***     **  *** = num2/gcd;
    
** *  * ***  ** * *     *   **  == 1)
***     *   ***     * * ******
     ********  * ***  ***** *     **  *  * *** ** * * *     **  *  * **  * ** *  **
 ***   *     * * * * *** * *
    
****    * * *** *****   ***** *
** * * *   **  ****   ***    *
* * **   ** ***  **   *  *  *  ** * **   * *  ** ** *      *  ****  ** **** **   * ** 
  *** * * **  * *  ***** 
    
 * ** *** **   **  *** * * * ***  * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
  *   * ** *** ****       ** **   ****** ***    * ** ***  **  *  * * *
** **  *  *** * ****  ***   **     **    *     **** ** ****       ***
    {
*** **  * * *          ** ***   * *  *****   ** *** ****  **    ***** *
 ***  * **   *  **  ***  **** *    * *  * ****** * *
*   **  *  *  *  ***  **  * *** * * **   
 **  ** * *  * **   * ** ****** *  *  * ****  
** ******  ***** * **   *  * ********

*     ** ** * *   *   ** * * **  *
*    * *   *** ***  * * *  ** *  *  *  **  ** * *   *  * *** * * * **   **  ***   *  * * ********   * 
* *  ** *    **  *   **   *****  * * **   *         * *  * ** ***  **** **  **   


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
    * ** *  ***    ****** a,b,GCD;
    *** *   * *  *  * *  **  ** ** *   ** **   *** **  ***     * 
   ***** ***    * ****  *  * **  ** *
***    * *** **  * ****    *  *
 *** *** * * ***** ***   * ********   * *  **  ** *** **   ** * ** **
  **  ** *** ** * *   
***** ***   ** **** * *  *   *  ***     * **   **   ** ** **   ** *   * ** ***
*  **  *   *  **   **  ** * **** ** 0;
}
*   ** *  * * ** ** **** gcd(int a, int b){
* ***** **    * ** * *    *  * *     * * **  *           *   (!b) return (a);
 *  *    *   * ****** * *  * * * * *** *     *  * **  ***  gcd(b, a % b);
  ** * *    *    **** ***** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * *  *    ** ** 
#include * ******   ***

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
**** ** *********   ***  ** gcd, remainder;
* * ** * *  *** **  * 
*  ** ******** * *        (n != 0)
 * **  * **  **** *   * * ***
  **** * ** * * **   *  ** * ***  ** * *      *  *      **  * = m % n;
*    * ** * ** ****** **    *  ***    **   * **  * = n;
** *  **** *  * ***  *   *   *** *         * * **  = remainder;
* * *     *** ** *      **** * 
  *  ** ** * **  * ***   ***
*   ***  * *  *** ** *  * * * = m;
* ** *      * ** *  *  **   
* ****  * ** ** * * **   *  gcd;
}
int main (int argc, const char * argv[]) {
*  *   *  **     *    ***  number1, number2;
* *    *  * * * *   ***        newNumber1, newNumber2;
 * * *   ** * *  *   * * * * 
  *   * * *  * *  ****   ***
*** **    **  *  ****  * * ** * ** * * **  * *  ***** **** ** *  ** ***  
*** ** *** ** * **** * ****** *
     * * **     ****** **** **    ** *  = number1 / gcd(number1, number2);
    *         *******  ** *** **  ** = number2 / * ** *    number2);
  *** ***  **  **   ***  * *
* ** * *   ******** **
   *  ****  **     *         * (  ***** **
**  **  *** * * * ** *   * *** *** ******  **** ** *  *  ***  ****  newNumber1);
 ****   *   * *  *     **
 ****  * * *** ** ***** ** 
* * *  *   * ******  * ***  ***  *  ** *    *  *  * ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
 ***    * **  **    **  ** a,b,c,d,e,f;
*   *** * **  *** ********* *        ** * ** **  ***** * **  **  
  ** ******     *  *      *  ****
  * **  * ***   ***  * **  *
 *   ** * *         * * *** ***     * 
    {
**    * ** * *  *   *  ** ** *   *** **  ** * *  
**    * **** ** * ***  * * *****      * * ***  *  * **      
  * * ***** *  ***  *  ** *** ***      **  * ** **  * 
    }
 ******* *  ***        ** * **     
    {
 ***  **** ***  **        ****  **  *      ***  **** *  *  * 
   **** **  *    *  **  ****  ***   *   *  *  **  * **** **  * * **  ** ***    * *
 *   ***     *   ** * *  **     ****     **** *    
** **  *     ** *  * *  * ** *  **  * ******  *  * * *   *  ** ***** * * *** 
    }
  *    ***  *  **   ** *   * * 
    {
 * *** ***** ** * *******   * **  *** *** ***** *  *
 *  ** * ** * *   ** *  *    *** *********   **** *  *** *    *    ** ***  * *     
  ** *      ****  *    * * ** **  * **   *   * ** * *
* ** * * *** **   *    ****     * ** * * * * ** * **** ** *  * ** *  **   
    }
* * *    *   **    * ** **** *  ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.52
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 12.4k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 12.3k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 15.5k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 11.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users