11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
9.6k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 9.6k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

    *** *  *********** ** **  i;
    **   * **** * * * ****** j;
* * **  **  **      ***    *  newNum1;
* * ******* ****   * **   * *   newNum2;
**   **  *  * * *  ** ***   * gcd;
      * *     *  *   **      rem;
   **  **     *    **** * *  * *** num1, num2;

*  ****  *** *      * *****  * **** * *  **  **  * ***   **   ** *      **  

* *** * *  ***   * **    *  *** *
* * *  *   ** **       *   *

  ***** *     ** * ** **** ** *  *  *   != 0)
*  ** **  **   ***   * ** ** **
 *  * ** *  *    *     **  **   ****    *   ****   * = j%i;
  *   **** * *** * ***   *   *  *** * **** * ** *       * *  = i;
   ** *** * *  **  ** *     * * **** *    * *** ***** * ***  * = rem;
 * **    **  ** *  **** ** *
** *    *** * **** *        ** 

********  ****** *  * **** ***  = num1/gcd;
 *   ** ** *********** ** * = num2/gcd;

 * *   ** *  * * *   *** * *  **** ** == 1)
    {
* *  ***  ** ** ******    * *  *  *   **** **  ****     ***  ***   *   *  ***  ***
    }

 **      **** * * *  ** * * 
    {
  * **   ***  *   ***** *      *  ***   *  ****   * **** *  **       ***     ** * 
  ****  **  ****** * * ***   

 ****  **   *     **   *   ***   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
**  *   *** ***    ***  ***  ** ***    **  ***  ****** **       ***

*     **  ***** **     **  ** ****   
  *** * ******* * * * * ** ** * ** **   ** *** *  *  *   * * ** * **   * *** ** ***

    else{
** **      *  * * **  * ***   * **  *  *
    {
      *    ****  ***   * **   *    *****  
**** ***   *  *  ***  *  * *         **     * * ****  ****      **  *** **   * ***   *** && deno%i==0)
* ** * * ****  * * *  ** ****      ****  * * * *     *  **    * *** **  ***
** * * **   *  ** * * * ***  * *   *****  *   * *** ****  * *  ** *  *   **** * * **  **   **** *** *   **   
  * *  **   *    ***   ** ** * ** ***  *  *  *** *   ***** *  **  **   *    * * ****   * *  *    * **     *    *
 **    ****  *  * **   ** * *  *   ** **  *****    *     * ** **   * *    *      
    }

* * * **  *    *** ** **  *  *  ****** *
    {
* *     ** **** ***  *  **    *   **** 
*  *  * ** *  *   *** ** **  * ** *  * *   * *  ** *   **    *  * **  *     *   ***     *  *    ** && deno%i==0)
 * * ** ******       *  * *   ** *        **  **** ***  *** * * * *    ** *  * *** *   
 ********    *** *  * *** **** *    * **** * * *  **  *** *      ** ***  *  *   ** *****  * 
  *****  * *   * *  * ** *** ****  * *   ***  *  *  *****         *   * ** *** * ** ** ******* ** ** * **
  * **  ** *  * *  ***  ** ***  ** * ****  * *** * *  *  * * ****  * *   **  ** ** *
    }
* *   ****  *  * ****** ***  *** *  *    *  *  * * *** *

    }




      *    ** **  *** * *    0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *****  ***  
#include **   *  ***** 

int gcd(int n, int m)
{
*  * *  * ***    * ***    ** gcd, remainder;

  * * *  **  *** *  * ***** * (n != 0)
** **  * **   * *        * 
 *  *   *   *   ** *** *  **      *  ****** *      * ** *** **  *** *  = m % n;
  ***  *   **  * * *  * ** ***** **   ***  *     *  *** = n;
  * ** * ** * **  *** ******* * ***  * ** **  ** = remainder;
 *  * *** *****   * *** ** ****

* *   ** ****** ** * * *  **  = m;

* * * * *    * * * * * **** gcd;
}

int main (int argc, const char * argv[]) {

*****  *   ** * ** ***  * **     **  number1, number2;
*** **    *   * *******  * *****  newNumber1, newNumber2;

***  **** *  ** * ***** * * * ** **    *  * *  ** *** **  * **      *

*  *** *  ** **  ****    * *   = number1 /  *   ** number2);
* *  **   ***  * ** * * *  * ***  *  = number2 /  ** * **** number2);

* **** **  ** **  **      **    ** ***   *** * *
**  ** ***** *  *** * * *  **  *   *  * ***   *** *   **  * * ** ** ****
* ** **** ******    * *     *  
* **   * *   **  * **    **   * ***** * * * *       * ** 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
****** ******* **  *    *
* *   **    ***** * *

int  * *** n, int m)
{
*** **  **  ***     int gcd, **     * 

** * *  ****    *  (n != 0)
   ******   * *  {
******* * * *      ** ** ** *     ***  = m % n;
*  * *  ****   ****  ** ** m = n;
**     * *        * *  **  *** * n = * ** 
* **  *     *** }

  ** * * * * gcd = m;

   * **     *    ** *** gcd;
}

int main (int **** * *  char * * * * {

 * ** **     * int   * **  ** *
  * ****  ** **   int **    **   ***     

  *  *         **  * **** * * * ** *****    *     **    *** 

* **** *  ** **   ***  * =   * * /   *  * * **
** *  *** * * *** **** *  =  **** / ****  **  **** * 

  **** * ***  * if **  *** * *   *    
    **   ***    ***      ** ** *  **    **    **** *  
* **** * ***  * ** else
     ***** ***  **  *  *** *** ***   **    *       
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 **   ** *       *  ****  *   i;
   * ** * * *   ** *        *  ** j;
***   ****  *** * ** *   * newNum1;
* * *  ***    ***   ****  ***  * newNum2;
***    ** * ** *  *** **  * * gcd;
*   * * *   *** ** *         * * * rem;
****  *** * *  ***  ** ****  num1, num2;
    
**   **  *** **    *  ***  *  **  **** **        ** *  **** **  * *  *
* * *  * *   *  *** *  * ** *
* ***  *  * * *   *  * *** **  *
* **   ****** * **  *   * *  
* *  *  *   * * * * * ** *
** ****   **  *****     *   != 0)
     * * **   *  * * **     * * 
****    **     *** *** ******* ***** * * * ** ***** ****  * = j%i;
*   *   **** ** *  **** *  * *   * * **  *     * ** = i;
*  * **  *** *  ***      ***** *** *  * **** ** *  * *  * = rem;
     ******  *  ** * * *    
 * * *  **  ****  *  ** **   *** * 
    
 *   ** *  *** * ***       * ** = num1/gcd;
* ***  *    ***  *****  *****  *  = num2/gcd;
    
 *  *     ***** **  * **** *   *  **  == 1)
*    *  * *   *  *********  *  **
*    * ***     *  ** *** **** *   *  * *  *  * ** * ***    * ** *     ** **  
*  * * *****  ****  *  ** 
    
 ***       *     *   * * *  **     **
 *       **  * **  * **    *** 
* * *  * *  * * ** ** ********* *  *  *  * * ****  * *** **      * *  * **  *   *** ****    
 *  * ** * **  *** ** *  ***** ** 
    
** ****      **  ** ** **  ***  0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 ** ** *   *** * ****    i;
**  *  * ** *  * *   * *** j;
 *      ** ****   * * *    *  newNum1;
*   *** *   *   *  * * *** ** * newNum2;
* ** ** **  **  * *** *** * *** * gcd;
 *  *   * *  ***  **   * *  rem;
 ** **   * ** **** * *   ** * * num1, num2;
    
  *   ****    *****   **    **    *      **     ****      **    * ** *  ***  *
 ** * ** ***   *  ***  * * 
 ** ****** *  ***        *   ***   * 
  * * ** * *  *   **   * **
* ***  *      ** * ** * * **  *
**** *****  **  * * *   * * ****** * != 0)
*   ** ***   *  ** * *   ****  *
* *** *** ** * * * *      ***  *      * ** *       ** **  = j%i;
** ** * **   ***      ***   *    * * *  * *  *     *** *** ****** = i;
 ***   **    *  **   ** **** ***   *   *  * **** ***   = rem;
     *     **      **  ***
 *   * * ** ** * ***    *      *  
    
*** ** * **  *  ** *   * ***   * = num1/gcd;
  **  **  *  **  *    *  * ***     ** = num2/gcd;
    
*   **** *  *  *    * *  *  *   == 1)
 * *  * ** *     ** * *     * 
* *  **  *   * * **  *  *  **** ** ****  ***   ***    * * *** ***
*   ** *  *    *  ****  *  *
    
 ** *  * * **** * * ** *   *  *
*        *  *  *   ** *     
* *****      **      **  *** *  **    ***** *  ** * *  * *  ***    **** **    *** *  *
* ***    *  ******  * * * 
    
*** ***   *******  *    **    **   0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
 * *  * *  ** **         *  * **** *** *   * *****   **  *
  * ****** *   *    ** ***  * *** *  * *  *  ***  **  * * ** * 
    {
     **   ***    ***     ***  *****  ***  * *  * *** **** * * ******  ** *  **
    **  **  ***  * * * ***  ** *** * * ** *   *    * *  * * *  ***   *
* *** * ** *****      * *  ****   *  *  
 *  ** ** **   ***      ****    *  * * **    
     **** **  *   *  *    * *   *    * *** ** *

   *  ****  ***  ** ***  **  ** 
 ***** ** * **    *    ***   * * * *         *   ** *  ****** ** ** * *********  ***   * * *** * **
**   ******  **  *     ** *   *  *****   **  *** ***      ***** *    *** 


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
   * * ******* **   * ** ***  a,b,GCD;
** * * * *    *   ****  **** *  *** *  *     * * ***  *   *  
* ****   ***    ****  *    ***   *  
* *   ****   *** *  ** *   *       
 *** ** ** * *    *  ** * ** *   ** ******* *******    ****** *** *** *   
 *   *  **** **  *     
*   *  **  **  ** **   *  ** **** ** * *** **  ** *      *** *** **  **  * *********
 ** **  **      * *   **  * *  ** 0;
}
     * ****  *** ** * **** *   gcd(int a, int b){
* *   *   *     *     ***********   *     * **  * ***  ** ** (!b) return (a);
 * ****  **        ***  **  **     * *  *  **** ***  **  gcd(b, a % b);
* *  **  *   **    *  * *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include           ** 
#include  ********  ** 

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
   **  * *   * **   * ******** * gcd, remainder;
 * ** * ***   **** ****   ***
**   * ** *** ** *   ** * ** (n != 0)
*   **** * ***  * * *     *  *
    ** * ** **  * **          ***** *  ***** * ** ******    *    = m % n;
** *   *   * **  ******* *   *   ** *  *****  **  *  = n;
 * *** ** ** ** *  *** *  **** *   ** *  * *   ***  = remainder;
**** ** ***  ****   *  *    * 
*   * *  ** *  * ***   * *  *
* *  **** *  **    *    *** **  = m;
 ****   * *   **** * * 
***   *  * *    *  * *   ** gcd;
}
int main (int argc, const char * argv[]) {
*  **  * *       * *** * ***  number1, number2;
 *******  **  * *   *  * * ** newNumber1, newNumber2;
    ** * **** ** *****  *   ** *
****   *  *  * ** *  
     ***  *     *** * ***** ** * * ** *  **   * ** **  *    ***    ***  
     *  *        **  *  **
  ***   * **   ****    * **  *  ** = number1 / gcd(number1, number2);
 * **    *   *   *   * **   * = number2 / *  *  ** number2);
***     * ***       **
*** *   *  ***    *  
***  * ** *  *   *******   *** ( ** * *  *
  * ** *****        *** ***** **  *   * ****     ***    * *** ****  *  *** ** **  newNumber1);
** ***  *** *  *  ** **  ***** 
   **  ** ***** *** *******
* * ** *   **** ****** * * *       *   * *  * * *  ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
**  *   *      * ***   *****  a,b,c,d,e,f;
**   **   * **  * **   * * *** *  ** ** **  ** ** 
 ***  * ***  *    ****  *
**    **** * ** *** * ***  *  
  *  * *  ****  *** ****      *      
    {
 **     *** ***  **    *  **** ***  **  **  *** **** *  ***
 * * ***  **  ***  *** *     *  * * ******      *  *** *  * **  
 *** ***   *     *  ** ** ******* * * *  *   **      *   ***  *
    }
*   *  *** * **** *   ** *     * 
    {
   **   **    **   *** *  * *  *** *******    **** **** **
***** * * **   * **   **  ** ***** * ** * *   *   * *   *     ***  ***   *     ***
*  * * *** *****   ** ** * **** * *** **   *  **  *   
****      **   ***  ** *****  ********* **  *****      ***  *    **** *   * *    
    }
* ** *** * ************   * **
    {
******* **  * *   *  ***    ** * *  ** *   *  ***  *   
**  *  * **  *** **     * ** *** ** ***  * * **  **** ***** * *** * *****
  * * *        *  **  *   ****** *  *    ***  * **  ***
 ** **  **   *** * * * *** * *    * *  * ** **  *** * **  **  * * **** **  
    }
*  ** ** * *   * ** *   * ** *   ***  0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.90
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 9.6k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 9.4k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 11.8k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users