2 like 0 dislike
11.8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 11.8k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* ** ** *** *** ** ** * i;
* * ** *** *** * * * * ** j;
* *** ***** **** *** * * * ** newNum1;
* *** *** * * *** newNum2;
* ** * ** ** * * * * gcd;
***** ***** *** rem;
* ** ** * * * * * * * * num1, num2;

*** * * ** * *** ** * ** * * *** **** ** * * ***

** ** * ** ** ** * * **
** ***** *** * ********* *

*** ** ** ** *** * ** * * != 0)
** ** ** ** **** ** **
***** * * ** ***** ** * * ** *** * ** * ***** ** = j%i;
** *** ** ** ** ** ** ** * * * ** * = i;
** * * * *** ** * * ** ** ** * * ** ** ***** = rem;
* ** *** * ** * *
*** * ** ** **** * * * ****

* *** * * * * *** ** * ** = num1/gcd;
** ******* * ****** ** * * = num2/gcd;

** ***** ****** * * * == 1)
    {
* ** ** ***** ** *** * ****** **** * *** * ** *** *
    }

* * * ** ** ** * * * **
    {
* * ** *** ** * * *** * ** ** * * ** * ** * *** * ** * * * ** *
********* ** * * * * *

**** **** ******* **** * * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
*** * * *** * ***** * * ** ** * * * ** * ** ** * *** ** *

**** *** ** ***** ** ** *** *
* * * * * * ** * * ** *** * * ***** *** **** *** * ***** ** *

    else{
* **** ** * * * ** * *** *
    {
*** **** ** * *** * ** * * * *
** * ** *** * *** **** ** ****** * * * * * * ******* **** * ** * * * && deno%i==0)
** * * * * ** * * ******* ** ** * *** * * * * * ** ***
** *** * * *** * * ** * * ****** * *** * * ** ** * * * * **** ** * ** ** * ** ** * ***** * ***
** *** * * * * ** ** * * * *** **** * **** * **** ******** * * * ** * ** *
**** ** * ** *** ** **** * ** **** * ** *** ** ** * ***
    }

**** ** *** * * ** **** **** * *** *
    {
* * **** * * * * * ** ** *
** * * * * * ** *********** *** * *** * * ** ** * * *** * ** * ** ** *** ** && deno%i==0)
***** ** * ***** * * ****** *** ****** ** ***** ** * * ** *
* *** * * ** * * *** *** * * *** ** ************* * *** ** *** * * ** * * ** ** **
* ** *** ** ****** * *** * * * * * **** *** * ** * * * * * *** * * ** ****
** *** * ** *** * * * ** * *** * ** **** * * * *** ** *
    }
** * *** **** * * * ***** ** * **** * * ** * *

    }




* * * * * ** * *** * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** ** *** **
#include * * * ** *

int gcd(int n, int m)
{
* ** * *** * * * gcd, remainder;

* ** * ** * ** * * * * (n != 0)
* **** *** *** *** ** *
* ** * * ****** * * *** ** ** *** ** ** ** = m % n;
** * ** ** * * * ** ** * ***** **** = n;
* * * *** * * * ****** ******* ** * *** ** ** = remainder;
* * ******* ** * * ** ** * * * *

****** ** ** *** *** = m;

* ** * ** ** * ***** gcd;
}

int main (int argc, const char * argv[]) {

* * * * * ****** ** * number1, number2;
* * * ** * * * newNumber1, newNumber2;

** ** ** * ** **** * ** ** * * *** * * * ** * **

** * * * * * * **** * = number1 / * * * number2);
* * ** * ** * ******** * = number2 / ****** number2);

* *** * *** * ** ** * * * ** * *** **
*** * * *** *** ** ** **** ** * ** ** *** **
** * ** ** ** * * * ***
* * * *** * * * * * * * ** ** * * ** ***
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * * * * * * ***
* * ** * * **

int * n, int m)
{
** ** * * int gcd,

** ** ** * ** * ** (n != 0)
*** * * * ** {
***** ** *** ** ** ** *** *** * = m % n;
******* * * * * ** ** * m = n;
* *** * *** ** * * * * **** n = * ***
* ** * * ** }

*** * * ** gcd = m;

* * * * ** * * ** gcd;
}

int main (int *** * char * * {

**** ** * ** int * * *
* ** * ** int * *** * **

* *** * * *** ** **** *** * * * *** * *

* ** * *** * ** = * / * * * *
* * * *** * ** *** = * / *** ** **** **

**** * *** if ** ** **** * * **
*** * ** * * ** **** * * * * * **** *** **
** ***** * else
* * **** * ** ** * ****** * * * ** *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * ** ** ** * **** * i;
** ***** ***** * **** j;
* * * * * ** ** **** newNum1;
* * ** *** * ***** * newNum2;
* ** * * * * * * gcd;
* * * * * * ** * * * * rem;
**** ** *** * **** ** num1, num2;
    
* * *** ** * *** *** * * *** *** * * * * * ** * * * ** *
* * *** ** ** *
*** * * * * * * *
*** *** ** *** ***** *** **
** ** * *** ****
******* **** *** * ** * * **** * != 0)
****** **** * ** * * * * **
* * * * ** * ** ** * * * * * ** = j%i;
** * ** ** * ** ** * * ** *** *** * * * ** = i;
**** * ** * * ** * * * * * **** * = rem;
*** * ** ** ** * *** *
** ** * ** * * * * *
    
** *** ** **** *** ** = num1/gcd;
* ** * ** ** ** ****** = num2/gcd;
    
** * * ***** * ******* *** == 1)
** ******* * * *** *** *
**** * * ** ** * * * * ** *** * *** * ** * * ** * * * * *
***** * ** *** ***
    
* * * ** *
* * *** ** ** ** ****
* ** *** * ** * * ** * ** ** * *** * * *** ** * * * ** **
***** ** * **** * * *
    
* * ** * * *** *** * ****** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** ** *** * ** * ****** i;
** ** *** *** * * ** * * * * *** j;
* * * **** ** * * ** * * newNum1;
** * * ** **** * * ** * ** * newNum2;
* * * * **** * ***** gcd;
** ********* *** * * ** *** rem;
******* * * * ** * ** **** num1, num2;
    
*** ** *** ** * **** ** **** * ** * ** * ** ** * ** *** * *
* * * ** * ****** * *** *
** * **** * ** ** * *
* * **** * *** ** *
** ** * ** * **** * **
** * * **** ** **** * * * * * * * != 0)
** ** * * **** ** * ** **
* * ** *** * ** ** ** * * ** *** ** ** = j%i;
** * * ** ***** *** * **** * * **** * *** = i;
* * ** * ** * ** * ****** * * * *** = rem;
***** * ** * * **
*** ** * ** * **** * * *
    
**** ** * ** = num1/gcd;
* *** *** * * * *** ********* ** = num2/gcd;
    
* *** * ****** * == 1)
* ** ******** * *****
*** *** * ** ** *** ** * ** * ****** **** ** * **** * * * ** *
** ***** * * * *
    
** * *** * * ****** *** * *
* ** * * **** * **** **
** * * * ** *** * ** * * ****** ** **** * * ** ***** * ****** *
* * *** ** * *** * *
    
* * * * * * * ** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** *** * * * *** ****** * ** ** ** **** *** * * * *
** * * ** ** ** * **** * * * ** *** * ****** **
    {
*** **** ** *** * ** ** * * * * ** * *** ** * * **
*** ******* ** * * * ** **** * **** * * * **** * * * **
* * * **** * ****** * *
* ******** ** * * ** ** ***** * * *
** * **** * ** ** ** * * **

** **** *** * **** * * * * **
* ** ** * ** * ** * ** * * * ** **** * * * * *** * ****** * *** ** * ** ****** *** * *
* *** ** * * * * * ** * * ** *** ***** * * *** * * * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* * ** * ** * * ** **** a,b,GCD;
*** * *** * * ** ** * ****** *** * **** *** *
*** * * ***** * ** ** **
* * * * * * ** ***** ******
**** * ******* * ** *** * * * ** *********** * ** * * ** ***
* ** **** ** ** ** *
** *** ** **** **** ** * ** *** * * ******* ** * * **** *
* * * * ** **** * * 0;
}
* ** *** * ** ***** * ** gcd(int a, int b){
** ** * * **** ** * ** *** ***** ** * **** * ** (!b) return (a);
* * *** **** ** * *** *** ** * * *** **** gcd(b, a % b);
*** *** * * * ** * * * * ***
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * *
#include * ***** * **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* * ****** *** ** * gcd, remainder;
* ** *** * * *
***** ** *** * * ** * (n != 0)
* ******* * * ***
* * * ** * * * * * * ** * * * *** ***** ** *** *** ** = m % n;
* ** ** * *** * * ** *** **** ** * ** ** = n;
** ********** * ** ** * ** * * * * * ** * = remainder;
* * ***** * *** ** * ***
** * * * * * ** *
* * * * **** * * * = m;
*** * * ** **** * **
* * *** * * **** ** * * gcd;
}
int main (int argc, const char * argv[]) {
* * ** ***** * * number1, number2;
* * * ** * * * ** *** *** * newNumber1, newNumber2;
* ** *** *** * *
*** * * *** *** * ** ** *
***** ** * * * * *** * * ** * ** * * *** * * * * ***
* * * * * ** *** ** *
* * ****** * * * * * = number1 / gcd(number1, number2);
** * *** * * * ** *** * * * * = number2 / ******* * number2);
** *** *** * ***
*** * * * ** * * * *
* * ** * * * ( ** *
* * *** * * *** * ** * ** ***** * * * * * **** * * *** newNumber1);
* ***** *******
* ** ***** * ** * **** * *
** *** ***** * * **** ** *** ** * ** *** ** * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** *** * ** ** ** a,b,c,d,e,f;
**** *** * ** * *** * ** ** ** * * * **** * *
* *** ** ** * ** ** ***
** ** * ** **** ** **
* ** * *** ** ** * ** * * *
    {
***** * *** * * * * * *** ** ** * * * *****
** * * **** * * *** **** * * * ** **
** **** * * **** * ** * ****** * ** * * **
    }
** * * ** ****** ** * ** * ** **
    {
** ** *** ** * * * ***** *** **** * ***********
* * ** ** * * * *** * ** * ** * ** * * * ** ** * *** ** **** * ** ****
** * * ***** * * ** * * ***** * * *** ****
* ** ** ** * ** * * ** *** * * * * ** *** * * * ** ** ********
    }
** ** * *** * ** * *****
    {
* * * ******** * **** * * * * ** *** *
*** ** *** * * ** * * **** * ** * ** * ***** ******* * * *** ** *
** * *** **** * * ** * ***** ** ** * *
* ** * ** ** *** ** * * ** *** * * * * ***** * ** **
    }
** * * * * ** * ** ** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.73
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 12.1k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 11.6k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 14.9k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 11.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users