11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
15.2k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 15.2k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

**  * *  * **   *****  * * * i;
*  *  *** ** *  **  ** *  ** j;
***** ** *  * * *  ***  **  ****   newNum1;
**    *  ** ** * *    ****  *   newNum2;
** *    ***   **  **  * * * * gcd;
 * *** **  * **** *   * * *** rem;
   *    *  * ****              num1, num2;

 * *   * * *  **  **** *** *  ***** *      **** ***  **** *   *** **

 *      * *** ****** *** *  
* **        *  * **  * * *  *

*   *** *    *  ***  * ** * != 0)
****** **      ** **  *
 ****** * * ****  * ** ** *** *  * * * ** *  *****  * = j%i;
**    ***  ** *****   *** **  * **   **  *** * ***** *  * * *  * * = i;
 **        **  **   *  *  *  * ***   ***    * ** **   = rem;
 *  * *    ** **  * **      
 *  *** * *  ***   **   ** 

 ****  *  ***   *   * ***** *  ** = num1/gcd;
***  *   *  **   *  ****      * *  *  = num2/gcd;

*** *** * ** **  ****   * **   == 1)
    {
 *** * ***** **** **   * ***** * ***** * ***   *  **** * ** *** * *  ** * *
    }

***   ****    ** *  *  *****
    {
 ******* ***  * * *  *** ***     **    ***** ** * ****    *    ** *    *  * *   ***
  ** ** ** *    ***  *    

*  *  **   * * * * *  * ** *** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
 ***  *   **** * * *** * ****** * *  ********  *  **  **    *   *   

**  * *  *** ***    ***   *   *  * *** 
 ** ***  * * *      **********   * ** * *  *   ****  * * ***  * *   * *******  ***

    else{
  ****   *  *  *** *   **  ***  *** * **  
    {
 *** * ****   * ******* **  **   ** * * *  * * *   
* *        ** **     * ***   *  * ** * *   **  ***     *  **   ********    *   * && deno%i==0)
*  * * * * *  ***  * ** ***** * ****** * **   **  *** ** * *    *** * *     
***   ****  **** ** * ** ** ***  ***  *   *****     * **  ** * *  ****   *     ***   ***   ** ** *   * 
****    ** *  * ** * *  * * *  * ** *  **** **  * ***   *    ** ******  * ** * ** ** *  * ***      **********
 * * *  ** ********  *** ** * *   **     *  ** ******* *      ** **** **     * *  
    }

     **** ***** *  ******  * **  ***   * 
    {
** *     *** * **   *  ****  **  ****     
  *      *   *   ** *  *   * * * ***  *   *  * ***  ** *  *   * ** ***     ** **  **** * * *  && deno%i==0)
* ****     *** ***   **    *  *  *  ***    ***        * *  * *   *   ****  *
*  * **    ***  *** ** **  *     *   * *** * ***  *   ***** ** **  *  ******** * *** *   *****    * *      * ****
   **  * **      * *  *   *****   * **** *   ** **  *  *****     ** ****  *    * ** **    * *  **** * 
  *     *   **  *    * *  * *    ***** **         ****  *  ** **    *  *   *       
    }
 **  * **    *** **    *  **** *** ** **  ****   *     * ** * 

    }




********* **  **  *  ***   **  **  0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *  ****** ** *
#include ** **  *  **

int gcd(int n, int m)
{
 * **   *  ***  *    ** ***  gcd, remainder;

*   ****  *  *    *****  (n != 0)
  * ***** **** **    * *** * 
 *  ** *  * **     *** * *  *  *  ** *** *  **     ** * * *** = m % n;
       * *      ***  **** * * *    **  *  *** **    * *  *  *  = n;
*  ***  **   * ** *  *  **  ****  * * *      ** ** ** = remainder;
**  * ** *    **  * ** *   *  

*  *  **** * * ** * **** *   = m;

*   *   **  ******* **     *****  *** gcd;
}

int main (int argc, const char * argv[]) {

  ***  *   *** * **  *  * ** ** number1, number2;
*  ****  ** *  ** ****  **  **** newNumber1, newNumber2;

     **  * *  ** **  ***  **  *    * ******   ** * *  **  **  *  ** *   

*  *  ***   ***** *  *** ******   * = number1 /  *** *   number2);
***           *  *   *    **        ** ** = number2 / * *** number2);

 *** *   *****   *     * * **  * **   *      * **
* *** *** ****    *   *  *  *  *  *** ****** *  ** *    * *   **  
** **  *    **  ****  *  
* **  * * *   * * ***   **  * * *     * * **   *  *** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
    * *  **   *   
*         ** *       *

int * ** n, int m)
{
*  *       *   int gcd,   ** ** 

 * ****  * *** *  **  (n != 0)
*    **    *    {
* ***  **   * * ****   * *  *     **  *    = m % n;
**** *     **   *****   *    * m = n;
      * * *****  * *      *** n =   * * 
* *  * *     }

 ****** *  **** *** gcd = m;

*      **   * ** gcd;
}

int main (int ***       char * *   * {

 ** *    *     int   *   *  *
*       * ** ** int ***      *  *   

    * * *   **** ** ** * * ***  * ** **     * *** * **** 

** * ** * **   ** *    * = * ***   / *****  *    **** 
* *** *   * * **   * * **  =    ** / *    *   *

 *   * * * ** * if    *****   ** *****   
***  **   ** *      ***    ** * ** **** **   ***     ** *  *
 *     ** *****   else
*  * *   ** *      *   **********  *      *   *     * * ** 
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
****    ** ***** *   ****  ***  i;
   *      *    **** * ** j;
***    * ** *** *  * *     *  newNum1;
**  *     * *  ** * *** ** newNum2;
**   *****  ***  * * * ** *   *  gcd;
      * *** **   ** *  ** rem;
     *  ***  **   ** *******  num1, num2;
    
* **** *  * * ** *** *  *   **  ****      **     * *** ***  *    
   **** ** *  ** *  *   **
     *   * *  **  *  *    *
   ****   *  ** *****   *** **
*   ****    * ** * ***
 ***    * ******  *** ****** * * * != 0)
*** * **  *  **         *  
 *** *  *      *  **  **   ** **   *   **    *   *   = j%i;
*    **  *    * * * * *  ***** ** ***** * *******  *****    ** = i;
*******   * * **    * *      *   *    ** * * *** **  **  = rem;
* * **    ***   * ** ***  *
*  *  *** **  * ** *   * **** * 
    
 **  *  ****    ** *    ***  ** = num1/gcd;
  * ****  ***    **    **   * = num2/gcd;
    
*** **** ***  ****    **  *   *   == 1)
*  *** * ** *  *   *** * *  
   ****     ***   **** ** ****  *  * *  **** * **   *  * *  * ****   **
 * ******* **** ** *  * * 
    
** ** *  *******  *  * **  ***    
*  ***  * *** *  * *******
*   ** *     * ** ***** *   **   * * *  ** * *** * *** *  * * **  * ** *   *********  *  *
 *   ** * *****  *** * *  * **  
    
* *  *  * * ** * *** * *  *    0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 ** *    * *   *   *** * * * i;
***  ***** ************  **** * *   * j;
    **        ***   *   *  * newNum1;
 *** ***    *     ***   **** newNum2;
***  ** * ***   ** *  ***  **  gcd;
*** * *   **       * *  rem;
      **     *  **  * ** ** num1, num2;
    
 ****    **  *  *  ** ** **   ***     *   * *  * *  *  * *  **  ** ***
* *** **   ** **  * 
*** *  ***   * **  *** *  ** *   
*  * *  * *    **  **  ** *   * **
 * * *  *  *    *       ** * ****
      *  * ** * *** *** *   != 0)
*  * *     * **** *   *  ***  
****     ** **      * **    ** ** *  * *    ***    *  * = j%i;
 ** **  ******* *  *** *  **  * * **    ****** ** = i;
 **   *  *   **** * *    *** * ** * ****  ***   = rem;
**  * * *  *   *  **   **** **  * 
* *    ***    *  ***** **** * *
    
** **  ****  *** *  **       = num1/gcd;
 *******  * * * *      * *       ** = num2/gcd;
    
* ** **  ** * *** *     * *  == 1)
   **********  ***** *  **
  **** ****** * * *** *  ** *** ***  * * **  * *   *  *      * *** * ******* * **
 *   * *********** * * 
    
**         *    ***       *    
* * *  ** * *   *  **********  
 **** **    * * ** ***   ******  * ** * *  *    * ****  ** ******  ** ** *    ** **     
      ** *** * *** ** *   
    
 **   **  ****  *   *   **   * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
 *** ***  ***    *** **  * * ** * **   **  *  * * **  ****  **   **
*  *   * *** **   ***     **      **** ****** **   **  ******   
    {
**** ********* *  * *    * **  *******  ***  * ** *  * **** *   *   
  **** *** * **     *    ** **   *  *****     * *   *** * *  ***  
* * ** * ** *  **  * * ******    * 
      *   *  ****** * ** *   * **** * ** **   ** 
  *** *** ****  *       ***  *** **** ***     ** **

 * * *   ****** * * **   * **   *
*  **        *  * **  *  *****  * * *      **  **   * *  *** * **    ***  *  * *   *  ** *       *  ** * 
***  *  **  * **** ** *** *  ***  *** ** ******** * *  *** * * ******  * 


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
**  *  **** ****** * * * ***    a,b,GCD;
 * *  **  *   *    *** * *  *** * * **  ***** *     ** * ****
*  ***** *    *  **   **      *  ** * **
  ***    * *  * ** * * * **** * *
* ***     *    *****       * *   ** ** ** * **** ** ***** * * *     * 
 ** * **** *** * *   **** * ***
  * *   * ** *  **  *   * ** * * *** *** **    * **   *  ***   *****   
** **     **  **   * **  ***** 0;
}
 ***    *  **  *** *        ** ***** gcd(int a, int b){
   ** ***   *   *  * *  * *  *    *****    *****  ***  * *** (!b) return (a);
*     *   *  **  * ** **    * *  *** **  ***  *  * * *     * gcd(b, a % b);
****   *   *  * * **  **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *    *** *  *  **
#include ***         *  *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* *     * *  **** ** * **   gcd, remainder;
  ** *  *  *  **   ** * 
*  **    *   * * * ** ******   **  (n != 0)
****** **  **   ** *     
**  ** *    *   ** ***     * ** *    *    * **** * *     * = m % n;
 *      * *      * **   * * **  **  *  *  **  ******  * * = n;
** *** *   * ** *  * * **             ***  *   * ****  *** = remainder;
  * * *   ** **   *** * *    * 
****  * *** **   ** *  *  * *
*    * ***  *  **  * *  * *  = m;
  *       ** * * *   ***** 
    *** *** *  * ******* *  ****  gcd;
}
int main (int argc, const char * argv[]) {
* *  ** *  ** ** **  *** ** *    number1, number2;
 * * * ** *** *  * ***    newNumber1, newNumber2;
*  *   **      ** ****** *
 **  *** *     * * *****
 **** ** ****  *** * *   **     *   **      ** *   *  *   *  * * * *** 
* * *    ** **    *   ** 
* * **** **   *     **      * * **** = number1 / gcd(number1, number2);
***   **** ******   * * * **  *    ** = number2 /    **    * number2);
* *****  ****    **   ****** 
**  * ** * ***** **** *  **** **
***        * * **     ** *** (  * *  **
  *** *  *   * ******* **  ** *  ******  * *   ** **** * * ***  * *  **** newNumber1);
  *   *    *      *   * *     ***
   *  * ** * *         ** ** 
* * * **** * ** ***   *   **  * **  **     * **     newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
  *  *    *** *   *        * *   *  a,b,c,d,e,f;
 **  * ******  * *  ** *** ** *   ***        *   ***  *  * *
 * ** **    **  * **      *** **   
     **  * **  *        *  *  * *
  ***   * *   *       * *    *  **      *
    {
   *  ******  ***  * ***  ** *  * * * *    ****   * ****
*  * ** *** *** ** **  * * *   * * * **** **********  ***  
**   * **  *   **     *****  **   * **  ***   **** *    * * *** 
    }
     * ***** * ***** *  ****** * ***  
    {
*   *** *  ****     * * *** ** *  **  ** ****   *   ***
*      ** * * * *******  * **  * *   ** **     ***  ** *    ***** * **  **   ****
 ***   ***     *   * **********  ** ****  *  *    ***  *** *
  * * * **    *    **    *   ***** *      *      * *   *  * ***   *  * ** 
    }
*** ** ** **** *   **    **  ***
    {
*** *   ***   ****    *  ** *  ****   * *** *** ****     * 
* * *** ***    * * * * **  ***** *** ***  *  **  ***** * *   **** * * **   *** 
* * **  * **    * *** ** **** *    *   ***** *  ***
*  **** ** **  *    ****** *  ***  * **       * ** ** * *      *** *  * * ** ***
    }
**  * **  **   *   ****  ****   0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.66
©2016-2026

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 15.4k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 15.2k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 19.7k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 15k views
12,783 questions
183,442 answers
172,219 comments
4,824 users