2 like 0 dislike
13.6k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 13.6k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* **** * *** * * * *** * i;
* * * ** * * ** *** * * j;
**** ** ** * *** * * newNum1;
*** * * * * ******* *** newNum2;
* * * * * ** * * * *** *** gcd;
**** * *** ****** * * rem;
** *** * * *** *** ** num1, num2;

** ** ** *** ** ** * *** * * * * * ** ***

* * **** *** ** * *
*** * * * * ********** **

* * * * *** ** ** *** != 0)
* ** ** * * *** ** *
** * **** * ** * * ** * ** * *** * *** ** ** * = j%i;
** ** ** ** * ** ** ** ***** ******** * ** * = i;
**** * * *** * ** ** * ** ** **** * * ** * = rem;
* ******* * ** **
* * ** ** * ** ***** *

*** * * * ** * * ** * = num1/gcd;
**** * ** * *** * * *** * ** = num2/gcd;

******** * * ** **** * ** == 1)
    {
*** *** ** ** ** * * * *** ********** ** ** ** * ** *
    }

* * * * ** ***** * ***
    {
* * * ** * * ** * * * * ** *** ******** **** ** ** * * * * *** * * *******
* * ** * * * ***** *

* * **** *** **** * * * * * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* **** ** * ** * * ** *** *** * ** * ** * *** * * *

** ** * * * * * * ** ** *
**** **** * *** **** ** ** * **** * ** ***** *** * ** * * ***** *

    else{
**** *** * * ** ** * ** *** * ****
    {
* * * ***** * * **** ** * *** *** * * **
* ** * ** * * ***** * * * * * * **** * *** ** * * * ******* * * * * * && deno%i==0)
********* ***** * **** * ******* * ** * ** **** * * * **** **** *
** *** ** ********* ****** * * ** ** *** *** ** **** * * * *** * * * * * * ******
**** ** * ** * *** *** **** * * * ** ** * * ** ** ** ** * *** *** * * *******
** ** * * * * ** * * *** * * * * * * * ** * ** * * ** **
    }

** * * *** ** * * ***
    {
* * * * *** ** ** ** * ** ** * ***
* ** *** *** ** * * * ** ** ****** * * ***** ** ** ** *** * ** * * * && deno%i==0)
* * ** * * ** *** * * * ** * ** * *** ** * ** **** *
* ** * ***** ***** ** * * **** *** * * * * * * * ** * * *** * * ***** ** *
* ** * * ** **** **** * * * * * * *** *** * ** * * ** ** * * * * ** * ** * ***
* *** ** ** * ** * * ** ** ** * * *** *** * * * * * *
    }
* ** ********** ** * *** ** * * *** ** * * ***

    }




* **** ** * * * ** ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * ** ***
#include *** * *** *****

int gcd(int n, int m)
{
** ** **** ** gcd, remainder;

* ****** * *** *** (n != 0)
* ** *** *** * *********
** ** * *** * * *** * ** ** *** * ** * * * **** = m % n;
** *** * * * *** * ** *** * * * * *** = n;
** ** * ***** * ** ********* ** * * ** * * * = remainder;
* ** * ******* ** **

* ** *** * * * * ** * = m;

* ** ** ***** ** ** * gcd;
}

int main (int argc, const char * argv[]) {

* * * * * **** ** * * * number1, number2;
* * * * *** * ***** ** newNumber1, newNumber2;

** ** ** ** *** * ** *** ** * **** *** ** * ** * * * *

** *** ** * * *** **** *** * * ** = number1 / ** ** number2);
*** * * * *** **** ** * * * *** = number2 / * ***** number2);

***** ***** * * * * * ** * * * **** * **
** * * * * **** * ***** ***** ** * * * * ** * *** *
**** ****** * **** **** *
* *** *** *** * * * * ***** ***** ** **
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * * ** ** *** *
*** * * * ** * *

int ** * n, int m)
{
** ** **** * int gcd, * * *

* * * * * ** (n != 0)
* *** ** *** * {
* * * *** * * *** *** ** ** = m % n;
* ** *** * ** * ** ** ** * m = n;
* ** *** * ** * * *** * **** n = * * *
* * * *** }

***** * ** gcd = m;

* * * ** *** gcd;
}

int main (int * * ** * char * * * {

* * * * * * int ** *****
**** * *** ** int * * *

**** * * * **** * *** * **** * * ** **** ** *

** * * *** * * = * / * * * ***
** ** * * * * * * = ** / **** * ** * *

* ** * if ** **** ** *** ***
**** ****** * * *** * * * *** * * * * *
** * * * * * * * else
*** * ** * ** * ** * * * * * ***
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ** ** ** ** ** *** **** i;
* * *** ***** * *** * j;
** * * ** ** ** **** * newNum1;
*** * ** * * * * ** newNum2;
* * *** **** ** * *** ** gcd;
* * *** *** * * * ** ** rem;
* * * ** * * * ******** * num1, num2;
    
* ** * ** *** * **** ** * ** * * * **** * *
* ** * * ** ** **
* *** * **** ***** ** **
** * ** *** * * * * *
* * ** ** ** **
** ** * **** ** * * * ** != 0)
*** **** *** ** **
** *** ** ***** ***** * ***** ** ** * ** = j%i;
** ** * *** * ** ** * **** * ** * * = i;
* *** * *** ** * **** ** ** ** * ******** ** * **** = rem;
******* ** **** * * **** *
** * * * ** * *****
    
* ***** ** ** *** * ** **** ***** = num1/gcd;
***** ***** * * * *** *** = num2/gcd;
    
*** ** *** **** ** ** * * == 1)
** * * * **** ** * ***
** * * * * ** ** * *** * * * * * ****** ** ** ******* *
* * *** ** * ** * **
    
** ** *** * ** ** * *
* *** * ***** * *** * *
*** ** *** * *** * * * ******* * **** *** ** * ******* ** ** ** *** ** *
* * *** ** ** * ** **
    
* ****** ** * * ** * * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * * * * * *** * * *** i;
* ** * * ** * ** *** * j;
**** ** ** * *** **** * * newNum1;
* * ****** ** ** * newNum2;
* * ******* * *** *** * gcd;
** * * **** * * rem;
* * * * * * * * * ** ** num1, num2;
    
****** *** * * * *** ** ** * ** *** * ** ** ****** ***** *
* ****** **** * ** * *
* *** *** * * ***** * ***
*** ** *** * ***** * ** *
**** * ***** *
* ** * * * != 0)
* * ** ** ** ****** * ***
* * ** * ** *** * **** * ** ****** * *** * * = j%i;
* ** ** *** * * * ** * * * * * ** **** = i;
* * * ** ****** * **** *** * * * = rem;
* ** ** * * ** * * ** * * *
**** * *** * ** ** * * *
    
*** * * * ** * * * *** ** * = num1/gcd;
*** * ** * * * ******* *** * = num2/gcd;
    
** *** *** * *** *** *** == 1)
* *** * ** ** *******
* *** ***** ***** ** * * * * * ** * * *** ** ***
** * * *** * **** *
    
** * * ** * *** ** * **
** ** ** * * **** *** **
** ** * ** ***** * ***** * ** * *** * * * * * * * * * ** ** ** ***
* ** * * * * *****
    
*** ** * **** ***** * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** ** * *** ***** * * * * *** *** * * *** * **
* *** * * **** ** * ** * ** * ** * **** ** *
    {
* *** * * *** *** * * * * ** ** * ** * ** * * *** * * ** **
* ** ** **** * ** ** *** *** * * * * * *** * * ***
* * ****** ** * ***** * ** * * *
* * * ******** ** ** ***** * **** ***
* ** * **** * ** * ** * *** * ** **** **** *

* * **** * *** * * * * * *
********** **** ***** *** ** ** * * * * * ***** ** *** ** * *** ** * * ***
* * ** * * ** * * * * * * **** * * ***** * * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* * ** ** ***** ** * ** * a,b,GCD;
*** **** ** ** **** * * **** ** **** ** ** * * ***
** ** * * * * *** * ***** * *
** * * * * * *** * ***** *
* * ** * * * ** ** * * ** ****** * *** **
* * * * ** * *** *
* * * * ** *** * *** ** * * * ** ** *** * ** *** ** * *
* *** * ** ****** **** 0;
}
* * *** **** ******** ** * gcd(int a, int b){
* ******** ** ** * * ***** * ***** ***** * ** (!b) return (a);
** ** * * * *** *** * * * ** ** ** * * * ** **** * gcd(b, a % b);
* ** * * ** * * * *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *** * *** *
#include *** ******* **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* * * * ** * *** * gcd, remainder;
** * ** * *** * ** * *
* * * ** * *** ** (n != 0)
****** ** * ** * ***
**** * **** * *** *** ** *** * * * ** ** ** ** ** ** = m % n;
* ** ** * * * ******** * * ******* * * = n;
** * *** ** * ** *** * ** * ** ***** ** * = remainder;
* * **** * * * * *
* ** ** ** * *****
* ** ****** ** * * * ** * * = m;
*** ** *** ** **** ** *
* * * * ** * * ** gcd;
}
int main (int argc, const char * argv[]) {
**** ** * * * * number1, number2;
**** * ****** ** ** ** newNumber1, newNumber2;
** * ******* ** * * * *
**** * ** *** ** *
* * * * ** ***** * **** * ** ** * * *
* ***** * * ** * * ** *
**** * * ** * **** * ** * ** = number1 / gcd(number1, number2);
* * * * ** * ** *** ** * = number2 / *** ** number2);
* ** * * * *** * ****** *
**** ** *** ** * * *** *
* ** *** ****** ***** * ( ** ***
* ***** *** ** * * *** ** **** * * ** *** **** * *** *** ** newNumber1);
*** *** * ** * ***** *
* * **
* * ** * * * ***** *** *** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * ** * * *** * * a,b,c,d,e,f;
*** ** ** ** *** ** * **** * ** *****
* * * **** **** *** * * ** ***
* * *** * * * ** **** ***
*** **** * * ** * *
    {
** ** * * * * * **** * ***** * * *** *
** * * * *** **** *** * *** * * *** * * *** * *
* * * * ** **** * *** * ****** ** **** *** ** **
    }
** ** * * * * ** * * *** **
    {
* * *** * * * ** * **** * * ** ** * ***
** ** ****** ***** ****** * * * * * * * ** ** * * * ** * * * *
** * * **** * * * * ** * * ***** ** ** **
* * *** *** ** * *** **** * * * ** * * ** ***** **** * * * ** * * **
    }
*** ** * ** * * ****
    {
* * * * * ** ** * ***** * * **** * * *
*** *** ** * ** * * ******** * * ** * * ******* **** ****
***** * ** ** ** ** * ** * ** ** ***
* * * *** ** * ** ** * * ** ** * ** ** ** *** ** * * ** **
    }
* * ** * * * * * *** * *** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.27
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 13.9k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 13.7k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 17.4k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 13.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users