2 like 0 dislike
13.5k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 13.5k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* * **** ** *** ** ** * i;
* * * ** * * * *** * ** *** j;
* * *** * * * ******* * newNum1;
*** *** ** ** newNum2;
* ** ** * **** *** ***** gcd;
*** *** * ** * ** ** rem;
* * * * * ** ** ** ** * num1, num2;

* * * *** **** ** * *** * *** *** * * * ** * * ** ******** *

* * * ** * * ** **
** ** **** * * * * *** * *

** ** ****** * *** * ** * != 0)
** ***** *** *** * ******
* ****** ** *** **** * * * ***** ** * ** * * * * = j%i;
* * ****** * ****** ***** ** * ** ** * * ***** = i;
***** *** ** ** * * *** * ** ** ** = rem;
* * * ** *** * ** ** **
* * *** * * * * * *

**** *** *** *** ** * = num1/gcd;
* * *** * * ** * * * * * = num2/gcd;

** * **** ** ** ** == 1)
    {
*** ** * ** * ****** * *** * * * ***** * * ******** ** ** * * * **
    }

** * ** * *** *****
    {
**** *** * ** * * **** ** ** ** ** ** * * *** * ****** *** * * **** **
*** ** ** ** * ** * **

* *** **** * * ** *** * * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * * *** * * ** *** * ** **** * * * ** *** *

* ** * * * ** ** ** * * ***
* ** **** ** *** ** * * * * * * * ****** *** * **** * ***** * *

    else{
* ** *** ** * * ***** * *
    {
****** **** * *** * ** **** **** * **
** ****** ** *** *** * *** ** * ** * ** * * *** * *** * ** * * * && deno%i==0)
* * **** * * ** * * ** * *** * ****** * * * * *** * * * * * *
* ** *** ** * * *** * *** * *** ** * * ****** * * * * ** *** ** ** * *** **** **** * ** **** *
** * * *** ******* * * * ***** * ***** ** * * * * ** * *** ** * ***** ***** * * *
**** * * * ** * * * ** *** **** **** * * * *** ** *** *
    }

* *** *** * * ** ****** * * * * *
    {
* ** * ** * ** * ** * * **** *** **
** ** * ** ** * * * * * *** * * * * * * * ****** * * *** **** *** **** * && deno%i==0)
* ** * ** * ** ** ******** * ** ******* * * *** * **** ** *
* * ** * ** *** * ** ** ** ** * * * ** *** * * * * *** * ** * ** ******* *
* ** * * * ** ** ** * **** ** ** ***** ** ** ** * * *** * * * ** * ****** ** * ***
**** ** * ***** * *** * ** * **** * * ** *** * ** ** ** *** * ** *
    }
* * * * ** * ** * * ** * ** ** **** * *

    }




* * ** ****** * *** * *** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *
#include * * ** *

int gcd(int n, int m)
{
** * * * **** * * gcd, remainder;

**** **** ***** * **** * * * (n != 0)
*** * ** * * *** **** *
** ** ** *** ** * *** ** * * * * * * * * ** = m % n;
* ** * ** * ***** ****** * ** * ** *** * = n;
** ** ** * *** ** **** ** ** * * * * * * = remainder;
***** *** * * * * **

* * * * *** ****** * ** = m;

*** * * * * * * gcd;
}

int main (int argc, const char * argv[]) {

* ** *** * * * * ***** * number1, number2;
***** * * ***** * ** newNumber1, newNumber2;

* * * **** *** ***** *** ***** * ***** * ** * *** * * ** *** *

* * *** * ****** ** * ** * = number1 / * *** number2);
***** ** *** * * = number2 / **** *** number2);

* **** *** *** * * * * ** ** *
*** ***** *** ** * ***** * * * * * ** * * * * ** * *
* ****** * * * * * *
* * ***** * * * ** **** ********** * * * * * * ******
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
*** ** * *** **
* * ** * ** *

int * * n, int m)
{
** * ***** int gcd, ****

* ** ** * * (n != 0)
* * *** * {
* *** *** * ** * ** * * = m % n;
** ** *** ** * ** m = n;
***** * ** * * * *** * **** n = * ***
* ** * * **** }

** ** * ** gcd = m;

** * **** * gcd;
}

int main (int ** ** char * ***** {

* * * * int * ****
* *** * int ** *** ** * *

*** ** * * * * * * ***** * ** ** * * *** ** *** *** * *

* ** *** * ** * = * / * *
*** * ** * ** ******** = * ** / * ** * *** *

****** * ** * if * ** ** * *** ** * *
******* * * * *** * ** *** **** *** * ** *
**** *** ***** * else
* * ***** * * *** * * ** * * ****** * * *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* *** *** ** ** i;
* ** ** * * * * ** * ** * j;
********** ** ***** ** *** ** newNum1;
** * *** * *** * ** * * newNum2;
* * ***** *** ** * * gcd;
* * * ** *** ***** * rem;
***** **** * * * num1, num2;
    
* * *** * * * ** ** ** * * * ** * *** *** ** ** ** * **
**** * ** * * ******
* ** * * **** *
* ***** * ****** ** ** *
***** * * ***** ** **
* ** ** * * * **** ** *** != 0)
**** * * *** ** *
** * * * ***** *** * * * **** **** ** ** = j%i;
* ** ** ** * * * * * *** * ** * * ** * = i;
* * ** * * * * * * ** * *** *** * *** * = rem;
* ***** ** * * * *** *
* * ** * *** ****** *** *
    
** * * * ** ** * * * * = num1/gcd;
****** * ** * * *** * * * *** = num2/gcd;
    
** ** * * * ** * * == 1)
* * *** * *** * ** * *
*** ******* * ** * ** ** * ** *** * * * *** *
** * **** * ** ** *** * *
    
****** * * ** * * * * ****
* ** **** *** ******** *
* ** * * * ** * ** *** ** * * * * * *** * **** * **** * * ** * *** *
* * * ****** ***** ** ***
    
* *** ***** ***** ***** *** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** ** * * ** ** i;
** * ***** ** * * * * ** j;
** * *** * * * * * * ** newNum1;
* * *** ** * * ** * newNum2;
* * *** *** * * * * **** gcd;
* * ** * * rem;
** *** * * *** * * * * * num1, num2;
    
* ***** * * ** * * * * ** * ** * * *** *** *** * * * *
*** * * * * * * *
***** ** * * ** *** * ***
** *** ***** ** * *** * * *
***** *** ** * * **
*** * * * * ** ***** != 0)
** ** *** **** ** *
* **** * ** ** ** **** * *** * * ** * = j%i;
* * ***** * * * ** * * **** * *** ** **** ** *** **** = i;
*** * * * ** ***** * ** * * ** **** * *** = rem;
* * * ** **** * ****
*** * * * * **** ** *****
    
* ** ** * * *** *** = num1/gcd;
*** * * **** *** ** ** * * * = num2/gcd;
    
**** *** ** **** * * == 1)
***** *** ** ** * **** *
** *** ** ** *** ** ** *** * ****** ** ***** *** * * * * ** **
**** * ** * *** * *****
    
**** ** ** ** ****
*** * *** ****
* * * * **** ***** * * * * * ** ***** * ** ********* **** **** * * * *
*** * * ** * * **** *
    
* **** ******* * ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** ***** **** * **** **** *** ** * ** * * * * **
** ** * ******* * *** ** * **** ***** ** ** * **
    {
* ** ** * *** * **** ** * * * **** * * * ** ** **
*** ***** ** ** * * * ** ** * * ***** * ** ** * * * * * **
*** * * * *** * **** * ** ** ****
* * * *** ****** * * ** * * **** *
* ** * * **** ** **** *** ********** * ***** *

**** ** ** * * * * *
* * * * * * ** * * * *** ** *** ** ** * * * * ** * ** ** * * * *** ***** *
*** * * *** * * ** ** ** * * *** *** ** * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* ** ** * * ******* **** **** a,b,GCD;
* * * * * * * * * ** * * * ** ** ****** ****** **** ***
**** *** ** ** *** * * * *
** ** ** * ** * ** * * * * *
** * * * ** * * ** ** ** ** *** *** ********* * ***** * ** *
***** *** ** * * **
*** **** ***** * ** * *** *** ***** *** * * ** ** * **** ** *
** ****** ** ***** 0;
}
**** ** * * *** * * *** gcd(int a, int b){
* ** ** *** * ** * ** ** * * *** * (!b) return (a);
****** ** ** * * ** **** * * *** ******* *** gcd(b, a % b);
** *** *** * *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** **** ** * *
#include * ****** **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
**** * *** ** * * * * gcd, remainder;
* ***** * *** *** * ** ** *
** *** ** *** * * * ** * * (n != 0)
* *** * * **** * *** *
*** *** ** ** * * ** * *** ***** ** * ** ** * ** = m % n;
* **** *** ** ** *** ** * * ** *** * ****** = n;
* * * **** ** **** *** *** * = remainder;
* * * * **** * * * * **
* ** * *** ** **
** * * * ** * **** * ** = m;
* * ** *** **** ** ** *
****** ** * * ** * * * ** gcd;
}
int main (int argc, const char * argv[]) {
* * ** *** * * ** * number1, number2;
* * **** * ** ** * newNumber1, newNumber2;
********* *** * *** ***
** *** * ***********
** * ** ** * ** ***** ** ** ****** ** ** * * * *****
* ** * ** ** ** * **
* ****** * ****** * *** = number1 / gcd(number1, number2);
* ** *** ***** ** * ** * = number2 / ** * ** number2);
** * ***** * *** ***
*** **** * *
******* * **** ** * ( ** ** * *
** **** * ** * * ** **** * * * ** * * * * ** * ** **** ** newNumber1);
** * * ** * ** * * *
*** * * *** *** * * *
**** * * * * * ** ** *** * ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * * * * * * ** * a,b,c,d,e,f;
*** ** ****** *** ***** * ** ** ** * **** *** * *
*** ** * * * ***** * *** *
*** *** * * ** ****** *
* * * * *** ** ** * *
    {
*** ** * **** ** ** * * ** **** * * ******** **
* ** * * * * ** *** ***** * * * * ** * *
* **** ** * * * ** * * **** **** ** **** *** **
    }
* * **** ** ** * * * * **
    {
* * ** * * * * * * * ** ********* * **
* ****** ** ***** * ** **** ** * *** * *** ****** * * * *
* * *** *** * ** **** * **** ** *** *
* **** * ***** * * *** **** * * **** * ** ****** * ***
    }
* * ** ** * * **
    {
* ** * ** * ** **** * * * * * * ** ** ** *
* * ** **** * *** ***** * * * ****** * **** ** ** * ***** * ** ** *
**** ** * * * * *** * * * * * * ** *
*** ** * ** * * * * * * * * ** ** * ** * * *
    }
** * * ** * * ***** * * *** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.26
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 13.9k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 13.6k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 17.3k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 13.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users