2 like 0 dislike
12.7k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 12.7k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

**** * * ******** * *** i;
* ** * ** * ** * ** * **** j;
* * * * * ***** ** **** newNum1;
** * * * ******** * ** * * newNum2;
* * * ** * *** ** * * * gcd;
** **** ** * * ** ** rem;
** ** ** ** * * * ** * * num1, num2;

*** * *** *** *** **** * * * **** *** ** **

* * * * **** ** ** * *
*** * * ** **** ** * ***

* * * *** **** ** * != 0)
* ***** * * *
** * * ** * * * *** * * * * * ** = j%i;
* * ******* ***** * *** ** ** ** * * ***** * = i;
* * ** ** ** * ****** ** * *** ** ***** = rem;
* * ** * * * **
**** *** * * ******* **

* ** * * * * **** **** = num1/gcd;
* * ** **** * ** * ***** ** ** = num2/gcd;

* ****** *** *** * * **** == 1)
    {
* ** *** ** *** ** ***** * **** * ** ******* *** ** *** * ** ** ** *
    }

* * * * * * *** *** * ***
    {
* * *** ** * * ** ** * ** * *** *** * * * * ** * **** * ** *
* ** ** * ** * *

** ** * * * * * * ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * * * * * ***** * * * * * * * * ** * ******* ** * * *

*** ** ***** * * * * * * **
*** ** *** ** **** * **** ** ** * ***** * ** * ** ** *** *** ** *

    else{
* * *** * * ** ** * ** ***
    {
**** ** **** ** ******* * **
* ** *** * * * *** ***** * * ** ** ***** * ** ** * * *** * * * && deno%i==0)
* ** *** * * * * ** * * *** * * **** * *** ** * * *** * *
*** ** ** *** * ** **** **** ** * * * **** * * ** *** * * *** * ****** * * **** *****
* * ** * * ** *** * ** * *** * * ** ** **** ***** ** * * ** **** * * * ***** *
***** *** * * * * * ****** ***** *** ** ** ** * ******* * * ** ** ***
    }

* * ** ** *** * ** ** * ******
    {
** ** * ** *** ** ** ** **** *
* ** * * * ****** *** ** * **** ** * * ** *** * * * * * * * * * * && deno%i==0)
* ** * * ** *** ***** ***** * ** **** *** ** * * * ** ** * * *** *** ** * ** ***
** ** *** ** *** * ** * ** *** *** *** **** *** ** *** ***** * *** * * ** * *
* *** * * * * *** * **** ** ** * * * *** *** ** * * ***** * ** * * * ***** *** * * * *** *** ** *
***** * * ** *** *** ** ******* ** * *** * * *** ** * ** * *
    }
* *** * * *** * * * * ** * ******* * * *** * **** * **

    }




* ********* * *** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** * ***
#include * * * ** ** *

int gcd(int n, int m)
{
* * ************** ** * gcd, remainder;

*** * * * * ** **** **** (n != 0)
* **** ****** ** ** ****
* * **** * * ** ***** ***** ** * ***** * * * = m % n;
** * ** ** **** ** * *** * * ** ** * ** ** * * * = n;
** ***** * * *** * * ** * *** * ** = remainder;
** * * * * * *

**** * ** * *** ****** ** = m;

** * ** * *** * * ** gcd;
}

int main (int argc, const char * argv[]) {

***** * ** ** * * * * number1, number2;
* * **** * * * * * newNumber1, newNumber2;

* * * ** * *** * * * ** ** * *** * * ** * * * ** * *** * * **

*** ** *** ** * * = number1 / ***** ** number2);
** ** * * * **** ** * ** = number2 / **** * number2);

***** * ** *** ** *** * * *** * * **** *
* * * **** ** ** * * * * * ** ** * ***** ** **
*** ** *** * ***** * *
****** ** ** ** * ** * ***** * * * **
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * * ** *** * * *
* *** * ** ** *

int ** n, int m)
{
** * ** * int gcd, ***

**** * ** ** (n != 0)
* * * ** {
* ** ** * * * * * * = m % n;
* **** * * * ** * m = n;
******* * * * * * n = * ***
** * ** ** }

*** * * ***** * gcd = m;

* * ** * gcd;
}

int main (int * * * char * * **** {

** * int *** * **
*** * * * int * ** ** *

**** *** * **** * * * ** * * * * **** * **** ***

* ** * * * ** * * = *** * / ** * *
* ** * * ******* **** * = * ** / ** * * ****

* * * * ** * if ***** * *** * *
* * ** * ** * * ** *** *** * * * * ** * * *
** ** * * * else
*** ** ** ** ** ******* ** * * * *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * ** **** * * *** **** i;
*** * * * *** * ** * * * * j;
* * **** * ** * newNum1;
** * *** * * newNum2;
* ** * * ** ** ** * gcd;
* ** ********* * * ** * rem;
****** ** *** ** *** num1, num2;
    
* *** **** ** * ** **** * * **** **** * ** * ** **
* ******** ** * **
* * ** * ** ** ******
**** * *** * * *******
**** * **** * ** **
* ***** * ****** * * != 0)
** ** * * * *
* ** * * *** * * ** *** * * ****** * ** ***** *** = j%i;
***** *** * * ** *** ** ** * * ***** * * ** = i;
*** *** * * ** * ** ** * ** ** * * ***** *** = rem;
****** * * * *** ***
* * * ** * *** *
    
**** * ******* ** ** **** = num1/gcd;
* *** * ** * *** ****** = num2/gcd;
    
** ** **** * ***** * * * * == 1)
* * **** ** ** * ** ** * * *
* *** * * * * *** ** ** ** * ** **** * *** *
* ** * ** *** ** * * ** **
    
******** * ** * ***
***** ***** * * ***** *
****** **** ***** ** * * * * ****** * * **** * ** * **** * *
* ***** *** * * *
    
* * * * ******** * * **** * ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** **** * * ** * * **** ** i;
** ** ** *** * ** j;
* ***** *** * ** * newNum1;
** * ** ***** ** ******* newNum2;
** * ** ** * * ****** * gcd;
** **** ** * ** * ****** * rem;
** ** *** *** * * num1, num2;
    
** * ** *** **** * **** * * ** * ******* * * ** ****
* * * *** *** * ** *
* ** ** * * ********* *** *
*** **** * * * * ** *
* * * *** * * ** ****
* * ** ** ** ** * *** ** != 0)
* * *** ** * * *
*** * * **** * ** * * ** *** * * ** ** = j%i;
** ** *** *** ** * *** * * * * ***** = i;
* *** ** * ** **** ******* * * * ** ** * ** = rem;
* * * *** * * * ** * * *
* **** * ** **** * **** **
    
** * * *** ** * * = num1/gcd;
* ** * * ** ** **** * * * = num2/gcd;
    
** ** * * ** *** * *** == 1)
** ** * *** * *** * *
* ** ** * *** * * * **** ** ** ******* ** * * * ***
** * * ** ***
    
** * * ** * *** *
* * * ** * *
* ** * ** ***** ** * **** * ******* **** * ** *** ** * ** *** * **** * *
* ***** ** * * * *** **
    
*** ** * ** * * ****** * ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* ** * *** ** * * ********** * * * ** ** * ****
*** * ** ** ** ** ******* ** ** ******* *** ** *
    {
** ** * * ** *** ***** ** * * *** **** ** * ** ** *
******* * * ******* * * * ** ** * *** * ***** *
** ** * ** * *
** * ** * * * * * * * *** * * *
** * ** *** ****** ****** ** ** * * *

* * * * ** * ** ** ******
** *** * * * * * * * ** * * ** * *** * * ***** ** **** ** * *** * * *
** **** *** * * * * ** ** ** * **** * ** *** ** * ** * * * **


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* *** * ** *** * * * * * a,b,GCD;
* ** * ** * ***** * **** ** * *** * * * ** * * *
* * *** ** * **** ** * ***
* *** * * ***** ** **** *
* * * **** ** * * * **** * **** * * * * * **** *
* * * *** * * * *** *** * *
** *** *** * * ** *** *** ** * *** * ** * * * * * * *
* *** ** ******* * * ** ** 0;
}
** * ** * *** * gcd(int a, int b){
* ******* * ** * * * * *** ** *** ***** ** * ** * (!b) return (a);
***** **** * * * ** ** * * * * * * *** ** ******* gcd(b, a % b);
* *** * * * ** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** **** * *
#include *** ** * ***

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* ******* * ** ****** gcd, remainder;
* * ** *** * ** * ****
* *** * ** *** *** ** ** ** (n != 0)
**** ********* * ** *** ***
* * * * ** ***** ** * * *** **** * ** * *** ** ** ***** * = m % n;
* ** * * * ** * * *** * *** ** * ** * **** * = n;
** * ** ** ******* * ** * ** * * * *** = remainder;
* *** ** ** ** ** *
* ** * **** * ***** **
* ******** ***** * * ** = m;
** ** * **** * ** *** * ***
* * ***** **** * ***** * * gcd;
}
int main (int argc, const char * argv[]) {
** * **** *** * * * *** number1, number2;
* * ** * * * * ** ** * * newNumber1, newNumber2;
* *** * ** ***** * *** *
* **** * *** * * **** ****
* * ** * ** * * * ** **** * * * * * ** **** *
* ** * * **** ** *
* * * * **** *** ** * * * = number1 / gcd(number1, number2);
* ** * **** * * * * = number2 / * * * number2);
** * ** * ** ** ** *
* * ** * ** **** *
* ** * * * *** ** **** ( ****** ***
* * *** ** * **** * * * ** * * ** ****** **** * **** * *** ***** newNumber1);
* ******* ******** ** * **
* ** **** ****** * * ****
** ** * * * **** ** * **** * * ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* *** ** **** ** * **** * * a,b,c,d,e,f;
**** ***** ** * * * * ***** ** *** *** *** ** *** * **
* * ** ** ******* * *
** * * * * * ***
* * * * * ** * ** * * ** ****** ***
    {
* * ** * * *** ** * ***** ** ***** **
**** ** *** *** * * *** *** * * ******* *** *
* ******* * * * **** ** * ** *** * ** *
    }
* ** * * * ** ***** *** ** ***
    {
****** ** ** ** * * ** **** **** * * ***** **
* * ****** ** * * *** * * * ** * *** * * * * **** * *
***** ** ** ***** * ** * ****** * * ** * ***
** * ** * * * **** *** ** ** * ** ** * * * ** ** *** ****
    }
* ** * ** *** * * * * ** *
    {
* * *** ****** ** *** ***** * * **** * ****** ***
* * ** ** * ******* * * * *** * ** *** * *** ** * ** ** *
** ***** * *** * *** * ***** *
* * * ** ** * ** ******** * * * * ** ** *** * * *** **** * * ** *
    }
* ***** * ** **** * * **** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.53
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 13.2k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 12.9k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 16.3k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 12.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users