11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
10.1k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 10.1k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

  ** **** *  * ***** * ***   *  i;
* * **     * ***  **     *   j;
*  ***   ***       * ***   *  * newNum1;
* ** *  *   * *  ** ****   **  newNum2;
**   * **  * * **  * *  ****  gcd;
   *    ******** * ** *   ****  rem;
 *  **     * *  * ***  *    * num1, num2;

  *     ***  *  * *   **** **  ******  *  *** ** ******  * *   **  * *

  **  * *** * **** *****  *****
** * ** **   ** * *      * * ****** *

       ** * ** *   ** * ****     != 0)
   ** *    * ** *  ***
  * ****  *** * ***     ***  *   * ** ** **   * ** * *** *  = j%i;
*  * **** *** * **   ****   **   **** *  ** *  * * *** *    = i;
   *   *** ** ** * ***** ****  * * * ** * * ***  **   ** *  = rem;
**  *   *      *** ** 
 * *******     **  **  *   * ****

*** *   * * ****   *      *   ** = num1/gcd;
******  * * ** *** ** **          = num2/gcd;

 **  **** *** *  *   *  **  **   * *** == 1)
    {
*   *    **   ***    *  **  ** *  * **   * ***  **  *** ** ** ** * ***  **    
    }

 ***  * **   *  * *  **   * * * 
    {
 ********  **   * *   *      *   *** *** * ***  ** *  *****  * ****  * *  ****  *   *** 
   **      ** * *      * ***  *

*  *  *     ***     ******* **** *** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
**    **** * **   * **** *   ** * *  *  * ** **  * *   ****  * ***  

     ** ****  *  ***   * *     *** ** *
    * *** * * *****  *    **    **     *    * ** **      *      ** **    * *

    else{
     *     * *  * * * ***  * * * * **
    {
** ***    **   *   * *    *    *  *  ** 
*   ***** *     *           * * *    **  ***** *         ** *** ***** *     ** *  ****  * && deno%i==0)
  * * ** * **   * ** ***   ***** ********     *  *** **     **   *   *********  *
    *****  ** *  *****  ***        **** * *  **             ****    *     *  *   ** ***     * *  * ***   *  ** 
* *  ***   ********   ** * * **  *  *** *      * **** ****** ** ******* *   * ******* ****  **  * *    
  *    **    *   * **  *  * *  * **   ** * * **  *  ***** * **     * ** *      
    }

   *   **** *** ** *  ***  *    **** *
    {
 *   ****   * * * ***  **   * * * **     ***    *
  *    *  * **       ** **   **** *  *** *** ** *  *  ***  **** ***      *   **   && deno%i==0)
 * *  ***    ****  ****   *    *      * ** * *  *   *    *     **   * * **** * **   * *  **
**   * **  **    * ***        *  ******  *  * **    * **   ** **  ** ****  **  ** *     ****    * ****   * 
 **   ** *****   ***  *   * *** * **** **  *  **  * ** **     *  ***  *   *   **      ** *          *
  **  ******     * *  ***   **   ***   *   *    ***   **** ** * * * *  *
    }
**   *** **  * *  *** * * * *  *  * * *     **  ***  

    }




*      *    *  *     *  ** *  *  0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **   * *  * *** 
#include **    ***   **** 

int gcd(int n, int m)
{
 ***** * * * *  *** ******** gcd, remainder;

* ***** * *      ***     ****  (n != 0)
* ***  * *  * ******** ******
  *******   *  **     *  *    * ** *   ** **  * *  **  **** = m % n;
    ***     *  ** *****  **   *** * * ***       * * * * = n;
*** **  **** *  * *  ** **   * **  ** **  ***** **  **** = remainder;
  ****** ** *    * * *  *

  ** *     *   **  *** **  ** ** = m;

*  **  ****   ** *  **   * gcd;
}

int main (int argc, const char * argv[]) {

***   ***** ***  ** * * *   **   number1, number2;
* ** ****  ** * ***     *  * newNumber1, newNumber2;

* **** *  *  * *     ***   *    * ***   * *   * * * * ***     *    *** 

      **  * ** **  ** * *  ** * ***   = number1 / *   * * * number2);
* * *   ** *** * *** * * *    * * = number2 /  *  *  * number2);

 * *  *   * * **   * ** **   *   **  **  *** ** 
 * *  * *** * ** * ****  ***  ***   * * ********** *  * *      ** ** 
**** ** *** **     * ***    ** 
 **** ****  ****   *  **** **  ** **  **** * *   ***  
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  *  ** * **   ****   
   **  ***  * *  * *

int    ** n, int m)
{
 **  **  *    *** int gcd,    * 

**    *  **       (n != 0)
   * * *    * ** {
     ***  *  ** * *      ***     * * **  = m % n;
  * **  *    ***     * * *      * m = n;
   *   * *** *** *   ** * * n =   *   
***   * **   }

*  *     *   * gcd = m;

 **  ** ** ** *   ** * gcd;
}

int main (int     *     char *  ** {

** ** *    * * * int * *   * * 
***  *** * * * * int    * ***   * *  

     *** *** *   *   * * * ** ** *  *    * *** *   ****   *  *  *

*  *****   *   *   *  **  = **    /  * * * * * *   
*   *******  *  *  ** * **** =  **  * /   *** * * ** 

 * *           *  if   ***     ***** *
* ****  *   ****  **** * *  *     * **  ** *  *  ** * * * *
   * *     * * else
   *        **   *   **    **** *    ** **  *  * * *  ***
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
***  **  * **** * * * ** *** *** i;
 ** *** ***  * ** ****** **  ** j;
* ** *  **  ***  *     **     newNum1;
  * ****** *   *    ******     * newNum2;
     * **  * *  **** * ** *  *** gcd;
*       ****      **    * * ** rem;
* **  ** *  *  **** * * *  * num1, num2;
    
 *  *  *** * **  *** * *** *  **** *    ** * ***  ** *     ** ** *
  *    ***   * *** **   **  **  
  *******   **  * * *  ** 
**  **  *   ***  **    *   ** ***     *
 *** *  * ** *** *   **  
 *****    *     ** *   *   **    != 0)
*  ** *        **    *  * 
** ** * *  **  *    ***   ** *   * ***   ** *    ****  * = j%i;
* *****    * ** *  * *     **** * ***   *  * * **  *     = i;
**    *     ***  * * *       * ******     ** * *  = rem;
** ** * * ****** ***** ** *   *
* *  *  *  *  ** ** *   *** * *
    
 *  ** ******  * ** *    * *    = num1/gcd;
 * *  *** *  * ** **  *   **   = num2/gcd;
    
  ** *  ****** * *** *  ***** ***  == 1)
**  **  **** ***** ***  *
* *  * *  *** ******** * * **  *  ** *    *** * * ** ***** *   * ***** *   *** * *
 * **      *    **   *  *
    
** * *   *     ** * * *****  *  
  *  *  * ** ** *   *   
   *** * *** ** **** *** ***   ***  ***    ***  * *   *    *  *  ****       ***** ***      
    * ******  ****  * *****
    
**   *   ** *** ** *      *  0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
***  *  * **      *  ***   * i;
     * **   *   **   *  *** **  j;
*  *   *     *** ** * *  **  ** newNum1;
     * **      **  * *  ** ****  newNum2;
** ****   * * *  *  ** *   gcd;
********* *   *  **** *****  * **  * rem;
*** *  *   **   *  * *  * *    num1, num2;
    
 *** *   **   *** **  ***** **  * ****** ***   ******   *  *  *   **
*  *     *  * *  ***  **** 
 *   ** *    * ***** ** * **       **
 ****** *  **  **  * *  *   *  * 
 *    * ** ** **    *** *
**  ***** ** * *****     ** != 0)
 ***** *  **  ** *  * * * *
*** **   ** * ****  *     * * **** * * * ** ******  ***  *  = j%i;
 *   ******  ** *   * ***** *****  ********    * * = i;
 *  **  * *   ** ** *  *****   **  * **  **    * ** *  = rem;
 *   ***  *  *  * **   *  
 *    **  * *    **  ** *  
    
***  *****    * *    **  *  *  **  *   = num1/gcd;
* *   *  **  *   ****         = num2/gcd;
    
* * * *  *    ***  * ** *** **    == 1)
***  *  **** * **  * * *** * * 
    *   **    * **    *  *  * ******* *   **   **** *      ****** *  * **
   *  ****  * **   *   * ** * *
    
  * ****  * * ***** ** * ***  
 ** *    ** *   *  *** ****
*  * * *  ***    ** *      *  *    *     *  * ** * ****     *   ***  *  *  ****      *
****  ****  **** * *  **    
    
 ** **** ***  *  * * **   *  *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
 *   * * *** * **       **    * **  **  **      *  **  ** *      **
 **  *   * ** * * *   ** *  * *  * * *** **   *** *** *  
    {
***  *     ** **  ** * *****   ***  ** ** *   ** ***  * **    *** 
**  **  ****     ** ***   **     *** * ** ** ****  * **   *   ***
** * *  * *  *    * * *  *    * *** *  *
**  * ***  **    **  *  * *    * * *    *  
**  * *** ***  * *   ***   * *  ********* *****

 * ***     *  *     *      * 
 *     ** **** ** *  **** *    **     *  * * *  *** *  *  ****** ***   * **** * *  * ** ** *    *  ** 
 *   *    *****  ***  *   *** * * *** * ***   ** ** *  *** **   * ** *  ** ***


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
**** *** *    * ** * * ****  * a,b,GCD;
***  * *  * * *********** ***   ****** **   * *** *  *   *  ****
* ** * **   **      **    ** ******
** ** **        * **  ** ** *   *  *  *  
 * ****  ***** * **   *  * **** * * *  **  * ***  ****** * *   ****
**  *   * **    ** ** * ** ** *
*    ***  ****    ****   * *** ** **  **** *  **** ***** ** **  * * **   *** **
   **  *  *  *  *  * * ****  * 0;
}
****   ** * **    * ****  **   gcd(int a, int b){
** * *  *  **  * **   * *     * *   *   *  * ******    *  * (!b) return (a);
* ***  ***   *  * *   **   **  ***    **   *   ***  ***  gcd(b, a % b);
*** ***** ** **  * * ***   *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * **  * **** *
#include   *       ** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
  * ** *  *  * *  ** * * **** gcd, remainder;
**  ** ***  *    ******  
  **   *  **** *  ** * *** ***    * (n != 0)
******  * *   * * **   **  *  *
 ** ** *  * *     ** *  * ** *  * * **   **********  *** *  * = m % n;
**** * ****   * ** **  * * ** *  **    * ***    ***  **   = n;
  *    ***  *** ** **  **        ******* **  *  = remainder;
****  *      *  * *  *     
**** * *   *  * *  ** * *
 *   ** *  * *   **** ***  * *  = m;
  * **  *   **** **  ****   ** 
 * ** ** *  **** * * *  * ****  * gcd;
}
int main (int argc, const char * argv[]) {
 * ***   *   ***   * **  *      number1, number2;
   ***     ***** *   * *   *****  newNumber1, newNumber2;
 ****** * * * *** **    **  
* *   * ** *  * ** * ***
 **  ** * ** * *  ** **        * *  *** * *  **   * *  ** * *   * * * **
 * *** *    * *  * **   * 
*** *    **  * *   **  * * ***   * *  = number1 / gcd(number1, number2);
* **   **  **** **   * **  *  * *  *  = number2 / * **   ** number2);
 *** * *  **** **    *  ** 
* ***  *  *  *  * *  *   **
 * * **** *****  *    ** * ( *******  
 *******    ********  * ** *   **     * ***** ** * *** * * ** *   *****  * * newNumber1);
 ** *   *      ****    ****  ***
*   * * ***  * * * * *   ** ****
  *   **  *   *  * ***** *  * *   * * *******   *  * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*  *** **   **  ** ***  *   ** a,b,c,d,e,f;
* ** *** ****  * * ******   * * ** *  **   ** *****  *    *** * ** * *
 **   *** ** ***  * * *** * *
 ** **   * ** *  ***  * *
  ***  ** *  * *    *****  ***  * * *** 
    {
 * **  ***  * ** * ** **  * ** ** * *    * ** *  * ***** 
  * *    *   *     *   *** *       ** *  ** *** * * **   *
* *   ** **  *   ****** * *   *    **  *   ** ****     **  * * 
    }
***  * ** *  *    ** **  *  *  ***  * *
    {
        * *******  *** * *** *  * *  ** **  * ** *      *
 * *    *  **** ** *  **   *** * *  *  *** ** *  **** ** * * *   *   *  *  
    **  **** **   *  *  ** *     *  *****  *****  * *  
 * *   *  ** * *     ** *    *     * ********** **  * *  *  ***       *  * * ** *
    }
* **** * * *****  * * * ***  ** 
    {
 * **   * *  ***  **    ***  **** ** * ****  *     * *  
** ***  ** ** ***  *  *** *  ** ** ** **    *****  * *   ***    **   **     
 ** * *   * * *** *   * *** ** **      **   *** *    * *  *
    *  **  *   * * * *  * *   *  **** *    * *   ***** *  *  *****   **  ***  *
    }
 **  * *       * *    *  **   * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.117
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 10k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 10k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 12.5k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 9.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users