11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
10.1k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 10.1k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

* **  *  ***  *  ** *    *** **   i;
     * * *  **  **  **   * **** *  j;
    * ****  ***  * * * *   * ** ** newNum1;
***  ***     *** *    *  *   newNum2;
***     *  *   ** * *  **** ***  gcd;
 * * * * **  ** ********* *** * rem;
 * ** ** ***** **  * *  *  **   num1, num2;

  ** ** *  *  *     **** *   ****  ***** *  * *  ** *      ** 

 *  ** *   ****   ***** **  *   *** 
  *  *   * * **  **  ******* ** *

    ***  ** *      * * *** != 0)
** *** ** * ** ******  * 
   * * *    ***  * ****  ** *     **** *  *   *  = j%i;
       *     *  * ** ** **  *   **  *       * ***** * * = i;
**** * *   * *      * ****  *  *  **   * ** *****   = rem;
  *  **  *  ** *** ****  
 ** * * *    * **    * *****

 * **  *   * * *  ***   *  *** **    * = num1/gcd;
** *****  *     * *** **  *   * *    = num2/gcd;

  *** *****  **    *   ***    ** * *** == 1)
    {
  **    ***  *  ** ***     ** **       **  **  *** **   * ** *  ** * * *********   *
    }

     ***  * *  *    *  **  
    {
 * ****  ** ** ***   * * **** * * *** *** **   ** * ***** * * *   *  * *  * *** *   * ***  
  *   ****** *  ** *   

*** *    ** ** *     *  * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
 * *    **   ** ** ***  ** **  *  ****    * **  ** * *****  *  *  *  

 **  ***** *    ** ***  **  **** ** **
* *** *** *  ****   *   ******        *  *  *  * ***  * **  ** **** *    ***    *

    else{
  * **    ** *   ** * * **   * **
    {
 * **  * *** ** * **** * * *   ** *     *** *
    *  ** ** *  *** **** * **  *   ** *    ****** *  * * * *   *  ** * * ** * ****   ** *  * ** * && deno%i==0)
*    ** *  ***  * * * *  * * *             ****   **   ***    *  *  **   ***  
**  *       *    *** **   *  ****  *   *   **  *** ** *  * * ** * ** * ******    *   **  * *** * *   * **   **   * 
   *  *** **  **  * ** * ***   * *   * *   * *******  *** **     *** *  *** * *   **  * *  **** 
* * **** **  *      * * * * ** *** ********* * *** ****  *   *** * ***  * *  ** *****  
    }

   **   ****** **** *  ** ******* **
    {
    *  * * * * * *  ** **    **        
*   * *  *  * * * ** * * ** *******   **  *  *** ****     *  *  **  *          **** *   ** && deno%i==0)
 ** **  *** ** ****** * *** **** * * * **  * *** *  **  **   * **** ** * **    **  *  ** ***
*   * * ****  **  ********* *** * * *      ****** * ** * ** * ***  * *  * * *  * *** *** ***      ** ** *** 
* * * **      *   **   *   ** **** **   *  ** *   ****       *** **  * * *** **  *  * ******** *     ****    **  * *  *  *  
 ** ** *   *  **  *** * *** *     *  ***** *     *   * **   * ****   *   *  ** * ***
    }
         **  * ** *     **   ***    * * ****** *    *  *

    }




  ***  **** *  *** **    **  * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *****    ***   ** 
#include       **  *

int gcd(int n, int m)
{
 *  *    ****     ** *  **  *   gcd, remainder;

  *      ** * *  * ***** **  * (n != 0)
** *  *** ** **   *  * **   
  *  *** ***** * **  *    ** ** ****  **  ** *  *  * ** * = m % n;
* * * *   *** *  * * **   *  **   *   **       ***  = n;
*  *****   **   *****   **    ** * *    ***    ****   = remainder;
  *     * *   * *  *****  *

**   **** **  **  * *** ** = m;

 *  ** ** **  *     **** ** gcd;
}

int main (int argc, const char * argv[]) {

 *** *** * * ** **** ****  *   number1, number2;
* * **  *    *  ** * *   *  newNumber1, newNumber2;

  * *** ** **   **  *****     ******     *** * * ***  *   * *  * *  *     *** *

*   * *   * *   *** * ** **   *   = number1 /        number2);
   *    **   *  ** **  *** * **   ** = number2 / *  *  *   number2);

*  ****** * ** ** *********** *  **   *       * 
  *    ** *      * ****     *  *  **     *   ** *      ******
**** * ****  * * **     **
*****     *****  * *** *  ** *** **** * **  * ** ****
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**      *  ***** * * 
**** * * *** ***** *** 

int * * n, int m)
{
**    *** ***** ** int gcd,    

***  **       * (n != 0)
****  *   * **  {
*      *** * ** * **** *  *   ** *    * = m % n;
 *  * * **  * * ** ****   * *   * m = n;
**  * * *        ** *** ** *     * n =  * ** 
 ***  * *   *  }

    *   **   gcd = m;

 *    * **** * gcd;
}

int main (int *      *  char *       {

**  **    ** **  int ****  ***
  *** *   ** *    int  *   * ** *  *

** *  *        * ** **********  ***      ** ** * *  ** * ** **  

*   *     **** * *  =   * *  /    **   * * *
*****   **  **  ** ****  = *  ** /  *   * * *   *

* *  *   *     if *  *  *  *** *    *  *
* **** ** *    *          ** *** *  *  * *  *        * ***** 
 **** * *   * else
*** *     *  * ** ** **  *  **    *   **** **  *   *     *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
* *  ** **** ****   **    i;
* **  * ****  *****    ** ** **  j;
  ** *  ****   **** * * ** *   newNum1;
  * * * ******    **** ** *  newNum2;
** ** ** ****  * *    ** * gcd;
 *   ** ** *   * *  * ****  *    rem;
*  *  * *       *  **** **  *** num1, num2;
    
 ****  **  **        ** ** *  ***  * * * *** *    * * * **   **  *   
   *** * *  *** *  **  *
  * ****         *  ****  * *** *
**** * **    *** ***  * ******* *  *
* *  * ** * **  * * *** ***   *
***  ****  *** **    * *   * *** != 0)
 * *** ***** * **** **** ** 
 ****   *****   * ** *   * * *** * ** ** ** *****  ***    = j%i;
*    ***   * ***   ** * * *    *  ****  *   **********  *  = i;
   ** ** **  ** *  *  ** **  **  ** **     **** * * *  = rem;
 * * * **      * ** **   * 
  **    * ****** *   *** ***  *
    
  *   ****** *  * **      *     = num1/gcd;
* * *  * *   *** * *  *  * *  = num2/gcd;
    
** *     * * * *  ***  *** * **  *** == 1)
  ** ***     * ** * *** *   * 
   ****** *** * *  * **  *******   *   **  *  **  *     *     * *  *** ** * ******  
* ***   * **  ***  * ******
    
 **   *     *  ******  *  **
**  *   * * *** *****   * 
  ****  * ** ****      **  * ***  **        ** ** * *** ***** * *  * ** ****** 
***** ** *   **  ** **** *** *  *  
    
*     * * ** *    *  *  ***  *   *** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
***  * *  * **  * * * * i;
 **  ** *** *** * ** * * j;
 **   ** ***   * ** *        *  ** newNum1;
**** *   ** **  *  *  ****  **  newNum2;
   *  *  **  * * **    *   gcd;
** ****   ***   * **** ***  rem;
** **   *    ***** **** ** num1, num2;
    
 ** *  ****** *** * *  ***   ****** *  *   * ** * ******** * *  *
  ***   * *    **  **  ***  * *
 ** *    * **   ***   **   ***   
* *  *****  **  ***  *  * *   * * 
** *  *      **   *  *** 
***  ***** * *  * *****  *   *  != 0)
****  * *  * ** *    *** 
 **  **    * *  *   *** ** * * * * * ** ** ****   ***   * = j%i;
 * **  *   *  *    * ** *  **   ** ** **** *  *   = i;
  ** ** * * * *   * *    *  * * *  **  ***  *       = rem;
  ****  * * ** * * ** * ****  * *
 * **  ***  *  *   *   **** * * 
    
**   *** **** **  **** *  **  *  * = num1/gcd;
 *   **    ** *** ** *** ** *   *  * = num2/gcd;
    
*** * ********   ** ** *  *** ***  == 1)
** **  *  **      ** * 
*   *  * **  * ** *  * * **  ** ** *   ******     *      *      *   ** **** *  *
 ** *  * ** ** *  * ***** * 
    
  * ***  * *** ****** ***    *   **
  * **   *  ***     * * *
    ***   * * ***   **  *  **  **** *    *  * *** * * **    *  *   ******* ** 
  *  **  ***  *  ** *   **
    
 ***      * * * ** *   * * *****  *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
**  ***** * * ***** ***  * **    ** *  ***     ****    *   *  *   
 ***   * **** * *  ****   * * * ** * *   *** **  **     *  *   ***
    {
   *  ** *   *  *   *   *** ***  * ****  *     *  ** *   **   ****  *** 
* * ***  ***  *** ** **  *  *  ****  * *** *  * ******* *** *
*** ****   *** **** *  ** *** * **  * *  
* * * ***  * * *** **  ***  *  *    *  *
*   **   *   * ***  *  ** * *  **       ****   

  ** * **** **  * ** *  ** *
 *  ***  ****   ***   * ****   *   *    ****** **  ****     ** * * *   *  * * **  ***    * *  *  ** * 
 **   **   * ** ****  **   ****  * ** * ** ***    *  *  * *  * ** *   *****  


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
  * ** *  *   **   *****    a,b,GCD;
 ***    *** ** ***  *** *     *      ** *  *   ****   *  *      *
  * *  * **  ** * *  **** ****   ** *
   *   *   * ** *  **** ****  ** ***
 * ***** *  *** *  *** *** *  * *  **** *    ***** ******* *    ******      *
 *** ***      *** **  ***
***  *   ***   *  * * ** **    ** * ****  * **  *   **    ****  * 
**    ** ** ** * ***  *   ** 0;
}
 *** ** *    **** *** *  * *   *   gcd(int a, int b){
     *****  *   ****  *   ****  * ** *** * **   **    (!b) return (a);
 *****  *              ******* *****  * * *** * ***  * ***  gcd(b, a % b);
* ***  ****    **   * *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ****      **   
#include  * **       *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
*  *****   ****   * *  * *** gcd, remainder;
   **  * **** ***   *  * ** * 
******** **** *  * * * **  *   ** (n != 0)
**  * *  **   ** ****  *** *
** **  ******* *** *** * ** *  ****** * ** *   *     * * = m % n;
***  *  ** ** *  **  *******  ** * ** *   ** ***    **  = n;
 **    **   *** *** **      *** * * * *** * * * *    = remainder;
** * ******* * *  **  **    **   
* *  ** ****** * *  *** * * 
**** ** **** *  *  * * * *   = m;
*****  **    *** ***  * * ***
   ** ** * ** ***** **** ** *    *** gcd;
}
int main (int argc, const char * argv[]) {
   * ***   *   ****   **   number1, number2;
    * *** **  *   *******     ** *** newNumber1, newNumber2;
 ***  **    * **        * *  
***     * *  * *    **
   *****   ** * **  **  ***    *****  *** *  *** ***** *    **  **     *  
******** ** ** ** *   *  *   *
    *   *  * * ** * *   * *** ** = number1 / gcd(number1, number2);
*** * *  * *** **  * * * * * *  *  = number2 /   *  * number2);
 * ******** * *** **  ** 
 ** ** ** **** * *  *****   
 * *    **** * *   ** *** (  * ****   
 *   **  * * ***    *      **** **   **    ** *** * *  * * **** *      *      * ** newNumber1);
 *****  *  **  ** ** * * *   * * *
** * **   * ** *  * *  *  *
** **     ***  *****  **   ****   *  *  *  * * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
 * ** ** * *  *    ** *** **     a,b,c,d,e,f;
     *  * * * * *  * ***** ******        ** **** *  ***   *  *****   * 
  **  ** ** *** *       **** 
* **       **  **  *     *    
   **   ** **     *   * **   * *** *  *** 
    {
   *   ** *  *    * *****  * * *       **  ***  **** *   **  *
  ** * ******** *  * **   ** * *  *     **    *** *      * 
    * *  ** * *** *  *  *  ***  *  ***      ** ** *  ** 
    }
  *      *  **   **    * *   * **** * * *
    {
**  *     * * ** * *  **    **  **  * *****   ****  *  *  
***   * * *  * ******  *  **** *    *********  **   * *****    *  * * * *       * **
   **  *  ****     ** * ** *   *** * ** *******  * *  *  **  *
*    **** ***     *   * * * * * ***  **** * *  ****   * * **   ** * *  *** *  ** 
    }
*  ** ***   *   **  *   * ** 
    {
*   * **  * * * *  * * * ** *  *    ****   *** ***   **   * * *  *
 * **  *** *  ** *** ****** *** *  *** *** *** ** ** *  * ***        ***** * * 
  ** * *  * *  **** ***      **  * *****  * ****   **** * 
 * * *  *   *** ***** *** *      *   *  *   ***    *     ** ***    * ** *  * ** 
    }
   *  **   **  * *  **      ** ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.155
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 10k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 9.8k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 12.4k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 9.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users