2 like 0 dislike
17.4k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 17.4k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

** ** ***** * **** * * ** i;
* * * * ******* *** *** j;
* * * ** ** ******** newNum1;
*** * * ** ******* ** newNum2;
***** *** *** ** * * ** * * gcd;
******* * ** ** **** * * rem;
* * ****** * ***** num1, num2;

* * * *** **** **** ** * ** ** * * ** * * *

* *** ** * ** *
******* *** * * ** **

*** ** ** * * *** *** ** != 0)
* * * ** * * * * *** **
* * * *** ** * * ** ** * ** ** *** * * = j%i;
* * * * * *** * * ****** * *** * * * * = i;
**** ** * * * ** * * * * * ** ** **** * * ** ** * = rem;
* *** *** *** ** * * ** **
** **** * ** * ** ** ***

**** ** ** ***** *** = num1/gcd;
** ** ** ******** * * * * = num2/gcd;

** * *** * **** ******* *** == 1)
    {
* ** ** ** ** * **** **** * * * * ** *** * ***
    }

** ******** *** * ** *
    {
* ******** ****** ** **** * **** ***** *** ** ** *** ** ** * **** ** * **
* **** * ** *** ** **

* ** ** * * *** ** ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** ** * * * ** * * * *** * * * ** *

** * * ** ** * ** **** * *** *
**** *** ******* * ** * ** *** *** ** * *** *** *** * * ***

    else{
* * * * * * * * **
    {
*** ** ** * ******* ** * * *** *
* **** * * ** * ***** ******* ** * * ** * ** ********* * * ** && deno%i==0)
* ***** *** ** * * * *** *** * * ** *** * * *** ** ** *** * * * * * *
** * *** ** **** * **** * ** ** ** * * * * * *** * * * * * * ** * *** **** ** *
* ** * *** *** ***** *** * ** ** * ****** ** * * ** * * *** * ***** * * * *
***** ** ** ** ** * * * * * * * *** ** * * **** * ** * * * * * * * *
    }

* ** ** * *** ** * * ** ** * ** *
    {
** **** ******* * * ** * *** ** * *
** ** * * * * ** *** * ** ****** * **** * *** * ** ** * *** **** **** && deno%i==0)
** * *** *** * * * ** ******** * ** * * * * ****** **** * ** *** * ***** * *
** * ***** * ** * *** ** * * * **** ******* ** ****** * * * * * * * * * * *
* * ** * * * *** * * ** * ** * * * **** *** *** * * *** * * ** *** * ** * * **** * **
** * * * * ****** * * *** ** * ******** ****** *** *** *
    }
** * ** * * * *** * ** ** ** * *** * **

    }




**** ***** * * ** *** * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * ** *
#include * *** **

int gcd(int n, int m)
{
** ***** * **** *** * ** gcd, remainder;

** * ** * * ** * * (n != 0)
* ***** *** * * ** * *
* ** * ** *** * * *** * * * ** ** ***** * = m % n;
** *** * * ******* * *** ** *** * * ***** * * = n;
*** **** * *** ** * * **** * * ** = remainder;
* **** ** ** * * * *

* * * *** * ********* *** = m;

**** * * * *** ****** gcd;
}

int main (int argc, const char * argv[]) {

** * *** * ** * *** number1, number2;
** * ** * **** * newNumber1, newNumber2;

** * ****** * *** * * *** ***** * * * ** ** * * ** ** * *

* * ** * ** ** ******* * * = number1 / **** * number2);
** *** ** **** * * *** * ****** ** = number2 / * * * number2);

* * **** ****** **** * * ** *
*** * ** ** * *** * *** * ** *** *** * ** * * * *
* * * * * ** * *
** * * * ***** * * * ** * * *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
** ** ** *** *
* * * *** * * * ******

int * n, int m)
{
* * ** ** * int gcd, **** *

* * *** *** (n != 0)
* * * ** {
*** ** ***** * * * * ** = m % n;
* * * *** * * m = n;
* *** * ***** * * ***** n = ** **
* * ** ** }

* * * ** ** gcd = m;

* ** ***** ** * gcd;
}

int main (int * * * char * * ** {

* * * * * ** int *** * *
** **** * * int ** * * ***

* * * * *** *** * ** ***** * * *** * *****

* * * **** * * * = * / ****** *
*** ** ** ** = * * / **** * ** **

* * **** *** if * ** ** * **
** ** * * ** * * ** **
** ***** ** *** else
* * * * * ** * ** *** ** * * * * * **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ** *** ** ** * *** * * i;
*** ** * * ** *** *** * j;
* *** * * ** ** * **** newNum1;
** ****** * * *** * newNum2;
** ** ****** **** ** * gcd;
** *** ** ** ** * ** rem;
** * **** ** * *** num1, num2;
    
***** * * * ** * * * ** * **** * ** ** ** * * * *** ** **
** * * * * * * *
* ***** ** * * * * ****
*** ** * * * * ***
** * ** ** * * *
* ** ** * * **** * * * * **** != 0)
*** ** ** * ** *
* ** ** * *** * * ** ** * ** * * = j%i;
* ** * *** * * ** * * * *** * * **** * * * ** = i;
***** ** * * *** * * *** *** * **** * = rem;
** * ***** * * *
* ** ** ** ** *** * **
    
* * * * **** *** ** * = num1/gcd;
* ** ***** *** ** * * * * = num2/gcd;
    
* * * * * * * *** ** * * ** ** == 1)
* *** ** * ***
* * ** *** ** * **** * * ** * **** ** ** ***** *** ** *
*** * **** ** * **
    
* * * * * ***** *
* * *** *** * ** *
** * * ** **** * * *** * ** *** * ** * * * *** ******** ** * * **
** * * * ** * ** * *
    
* * ** * ** * *** **** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * * * * * ***** i;
*** *** * ** ** j;
* **** * ** * ** newNum1;
* *** *** * ** * newNum2;
*** ** *** * * ** * gcd;
* * * * **** ** ** * * * rem;
* * * ** *** num1, num2;
    
*** **** ***** ** * * ** *** * ** ** *** * ** * **
* ** *** * *
* * * * ** * * ** * * ******
* **** ** ****** *** *
** *** * *** *** **** *
******* ** * *** * * ** != 0)
* ***** * * ******* * **
** * **** * ** **** *** * ** * **** * * ***** ** *** * ** = j%i;
* * **** * ** * * * * * ** ** * * * * = i;
*** *** *** ** * **** ** * ** *** * *** = rem;
** * * ** ** ** **
* ** * ****** * * *** **
    
******* ** * * * **** * *** = num1/gcd;
* ** ** * *** *** ** = num2/gcd;
    
* *** * ***** * * * * ** ** * == 1)
* ** *** ** ** * *
* * * *** * * *** *** * * ** ** * ** * * * ** * ****** * *** *
* * * *** ** ** *** * *
    
* ** * **** ** * * ****
*** * * * * *** ***
*** * *** * ** ** ** * * *** * * ** * *** *** * ** ** *** * * *
* **** * * * * * * ** *
    
** * * * ** * * * ** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** * *** ** ** * ** ** *** * * * ** ** *** * * **
** * * ** ** *** *** *** * ******** ** ** ** * *
    {
*** ***** * * * ***** ** **** * **** * ***** * ** * ***
*** * ** * * * ***** *** * ** * * * **** ** ** ****** **
** ** ** * ********** * ***
* *** ******* * ** * ****** * ******
* ** *** *** *** * ** ***** *** ******* **

* * * * * * * ** * **
** ******* **** *** * ** ** ***** ****** *** * ** * * ** ********** *** * *** ** * * * ** *
* * * ** * *** * *** * * * * *** ** *** * ** * *** * ****


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* **** * *** ** * a,b,GCD;
*** ** * * ** ** * *** * ** * ** ** * * * *** ***** * **
* * *** * *** ** ** * * * **
* *** * ** ** ** **** ***** ** * **** *
** ** *** * * ** *** * ** ** * * ** ** ***** * * *
* *** ***** ** * * *
******** * *** ** * * *** *** ** * * * * ** *** * **** * * * *
* **** * * ** **** * 0;
}
*** ** * * ** * * * * gcd(int a, int b){
* * ** *** * ** * * * * *** * ** ** **** * * (!b) return (a);
** * ** * * ** ****** *** ** ****** * * ** * gcd(b, a % b);
** * * * **** ** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * ** *
#include * **** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
** * ** *** ** * * ***** gcd, remainder;
* **** * * *** *
*** ** *** ** ** * ** * (n != 0)
***** ** * * ** * * *
* * **** * * * * *** * *** ****** * * = m % n;
* * * ** * * *** ****** * * * ** = n;
** ** * * * * * * ***** * ***** *** * ***** ** * = remainder;
** ** * * ***** * *
** ** ** ** * * ** *
*** * * ** ***** ***** * = m;
**** ** * * **** ***
**** * * ** * * ** *** gcd;
}
int main (int argc, const char * argv[]) {
** * * * * * * * * *** number1, number2;
** * * * * *** * * * * * newNumber1, newNumber2;
* * ** *** ** ****
*** ** *** * ** * *
* * * * *** * ** **** ** * ** * *** * ** * *** * * ***
* * *** ***** * **
*** ** ** * ** * ** = number1 / gcd(number1, number2);
* ** * * ****** *** ** = number2 / * *** ** number2);
* * ** * ** *** *** ***
* * * *** * *
* * * **** * ** *** **** ( *** * *
* ** *** * *** * * * * *** ** ** * * *** * *** * * newNumber1);
** **** *** ********
* * * ** * * ** * *
*** *** ** ** ** *** **** * * * * * ** * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * *** * **** * * *** ** a,b,c,d,e,f;
* * ** * ** ** * ** * * ** * * * ** * * ** ** ** *
* ** * * *** ** ****
**** * **** * **** * *
****** * ** *** * ** * * * **
    {
* * ** * * ****** ** ** * * ***** * *
** * ***** * *** * *** ***** * * * * **** **
*** * * * * * * * *** ** * * * * ** * *
    }
* * * ** * * ** * ** ***** *
    {
** * * * ** * * ** * * * * ** * * * ** *
* * * * **** * * *** *** ******** ** * ****
* * *** ***** ** * ***** ****** * * ** * **
*** * ***** * * * * ** * ** * * ** ** ** *** * ** *******
    }
* * * ** * ** *** *
    {
** * **** * * * * * * * ** *** * * **
** **** * * * * *** * * * ***** * * * * ******* * **** *
*** * * *** ** * **** **** * * ***** * ***** *
** ** * ** * * *** *** ** ****** ** ** * **** * * * *
    }
** * **** ** * * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 17.3k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 17k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 22.5k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 17k views
12,783 questions
183,442 answers
172,219 comments
4,824 users