2 like 0 dislike
14.3k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 14.3k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* ** ** * * * * ** i;
* * **** * ** * ** j;
*** *** *** ********** newNum1;
***** * **** ** * ** * ** newNum2;
** **** * ** * * * * *** ** gcd;
******* *** *** ***** **** rem;
*** * * *** * ***** * ** * num1, num2;

* ** ** * ** * *** * ***** ** *** * ** * **** * *** *

*** * ****** ***** *
* ***** * * **** ** *** * * ** *

**** * ** * * * * * != 0)
** ** * ***** ** *** ** * *
* * ** ** * ** * * * ** **** = j%i;
*** *********** * ****** * *** *** * * * ** = i;
***** ***** * ** * * *** *** * * ***** * **** * ** = rem;
******* * ** * *** **
* * * ** *** ** ** *

* * * ** * ** **** * *** **** = num1/gcd;
* * **** *** * * *** = num2/gcd;

* * * *** *** * **** *** * * * == 1)
    {
**** * *** ** * * ***** * *** ** * ** * *** * * * *** ** * ** **
    }

* * * * ** ** ** *
    {
* ** * * **** * ******** ** * ** ** * * ** * * **
* * **** ** ***

* * * ** *** ** * ** * * *** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
**** * ** ** * * * * ** * * *** *** * *** ** * *

* * * * *** ** ** *
*** ** * ** * **** ** * * * * * **** * ** * ** ** ** * * **** **

    else{
* * * *** * * * *** ***
    {
** * ***** * ***** * * * * *** ******
** ** * *** * ** *** *** ***** ** * * **** *** * * *** * * ** ** * * * ** && deno%i==0)
* ** ******* *** ******** *** * ** * * ** **** ***** * * * * * * * *
* ** *** ** * *** ** ** * * * * * *** ** ** ** * ** ****** ** ****** ** ** *** * **
** ***** * * * *** **** * **** ** * **** * **** ** * * * ***** ** * *** *
** ** * *** ** * **** *** ***** ** * * ** ** * * **** * * *** **** *
    }

* *** **** ** * *** * * **
    {
*** ***** * * * * ** **** * *****
**** *** * * ** ** ****** ** * ** * ****** * * * * * *** ***** * ** && deno%i==0)
** ** ****** ** * ** * **** **** * ** ** * ***** *** *
* ***** ********** * **** * **** ** *** ***** ** *** *** ** ***** * *** *** * **
* * * * * * * *** * ** *** * * * * * ** * ** ** *** ** *** * ** * *********** * * ** ** * *
* * ** * ** ** * * * *** *** *** * * * * * * * ** *** ** *
    }
* * ** * * * ** *** ** * ** * * * *** *** * *

    }




* * * ** * ****** ***** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *** * ** **
#include ***** **

int gcd(int n, int m)
{
* ****** *** ** * * * ** gcd, remainder;

*** ** * * * * * * ** (n != 0)
* ****** ***** * * *
** ** ** * ** * * ** ** *** * ** **** * *** ** = m % n;
**** ** * * *** * ** * * ** * * ** ** = n;
* * *** *** **** **** ** *** * * * * * * = remainder;
* * * *** ** ** *

* **** * *** * ** **** **** = m;

******* * *** *** ****** gcd;
}

int main (int argc, const char * argv[]) {

* * *** * * ** * **** number1, number2;
* ***** * * *** * * newNumber1, newNumber2;

* * ***** **** **** ** ** * *** ** * ** *** *

***** * *** *** *** * ** = number1 / ** * * number2);
* ** * * *** ** **** **** * = number2 / * * * number2);

* * * ** *** * *** * *** ** **
* * **** * ******** * *** * * ** * * * * ** * **** *
* * ** *** ** ** ****
* ** * * * ****** ** *** * ** *** ** ***
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
** * ** * *
****** * ** ***** *

int ** n, int m)
{
*** * * * int gcd, **** * *

** * * ****** * * (n != 0)
* * ** ** {
***** * * * ****** * * ** ***** * = m % n;
* * * * * * * * * ** * ** * m = n;
** * * * * ** ** * ***** n = ***
** *** *** }

** * * gcd = m;

* ** ** ** * *** gcd;
}

int main (int * * char * ** * {

* * * * ** int *** * * **
* ** ** * int ** ** * **** *

* **** * * * * *** *** * *** * * ** ** * * ***

** ** * * * * * * ** * = *** / * ** ***
* ** * ** * = * * / ******* *

* ** **** * if ** * **
** * *** ** ** * * ** ** * *** * *** *
**** * ** ** * else
* ** * *** * * * ** ** *** **** * **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** * ** ****** * * * i;
** ** ** * ** * ** *** * j;
**** ** ** * ** ** * * newNum1;
* * * * * ** ** ******* newNum2;
** * * * *** * * * ********* gcd;
*** * *** * * ****** rem;
* *** ** * * ** num1, num2;
    
** *** * * * ** * * * * *** ******** * ** ** ** ** *
*** ** * * * * **
** *** *** ** * * *****
* * * *** ** ****** *** *
* * * **** * * **** ** ***
* ** ** * * ***** **** ** * != 0)
** * * * **** ****
****** * * * ** ** * * ** * * * * **** *** * * = j%i;
* ** *** * ******** * * * * * * * ** = i;
* * ******** * ** ** * ** **** ** **** = rem;
** ***** ** ** * * *
* * * *** ** ***** * *
    
* * * ** ****** * * = num1/gcd;
* ***** ***** * ** * * * ** = num2/gcd;
    
* *** ** * *** * *** * * ** == 1)
** **** * * * ** * ** *
* * * ***** ** * ** *** *** * * * ** **** * * ** * ** **** **
* * * * * ** ** * *
    
** * ** * ** ****** * * * *
* *** * * ******* * *
**** ** *** * ** * * *** * *** *** ** * * * * ** *** ** * * * **** *
*** * * * ** * ** ****
    
** * ** *** * ** *** * ** * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * * ** * * ** ** i;
*** ** *** * ***** j;
* *** * ***** **** * * newNum1;
* *** * ** ** ** ** newNum2;
* ** *** * * *** * gcd;
** ** ** * * * * rem;
** * * ** ******** ** * ** num1, num2;
    
*** * * ** * * ** ** ** * *** * * * ** * * ** *
* * * * *** * **
*** * * * ** * ** ** * ******
****** ** * ** ** *
** ** * *** ** *
** ** ** *** * ***** ** *** != 0)
* * ***** * ***** * **
* * ** ** **** * * ***** *** * *** *** ** * * = j%i;
**** **** ** ** **** ** * * *** *** ** ** * * * * * * = i;
* * * * ******** *** *** * * * * * * **** ** * = rem;
* * ** *** ** **** **
*** * ** * ** ** * * *
    
* ** * * *** * *** * * = num1/gcd;
*** * **** **** ** ** ** = num2/gcd;
    
* * ** ** * * *** ***** * ******* == 1)
* * * ** ** * **
* * * ***** * * *** * * * ** * * * * ***** * *** * **** * * * * * *
*** * ***** *** **
    
*** ***** * * * ** ** *
* ** * *** ** ** *
* ***** * * *** ** * * * ********* * ** ** ** * *** *** * ** * * *
* ** ** ** ** * ****
    
*** * * *** * * * * **** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** ** * * * **** ** * **** *** * * * * ****
* * * ******** *** ** *** * ** ** * * *
    {
**** * * **** *** *** ** ** ** ** * *** *** * ** ** *** *
** * ****** * ** *** **** * *** *** *** ***** * * * *
* * **** ** ** *** ** * * *
* *** * * * * * * * * *
** * **** * ******* * * * ** *** **

*** ** ** ** ** *** **
* *** * ** *** * *** ** * **** *** *** ** * ** *** * ***** ** * * *
** * *** ** ** * * *** ** *** * ** * ** * ** * * ****


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
***** * ** ** ***** * * * a,b,GCD;
** * ** * * ****** ** *** * ** ** ***** * **** *
**** * * * ** * ** * **** **
* ** ** ** **** **** *** * * * **
* ** ***** *** * * * * ***** ** **** * * * ***
* ****** * ** * ** * *
* * ** *** * * **** *** * ** * * *** * ** * **** ** * **** *
* ** * ** ** ** * * * 0;
}
**** * * ** * * * * *** * gcd(int a, int b){
** * * * * **** * *** **** * * ** **** * * * * *** (!b) return (a);
* * *** ** ****** * ** * ** ** * ** * * * ** ** *** ** gcd(b, a % b);
* **** ** ** *** **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * ****
#include **** ** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* ** ** * ***** ** * * ** gcd, remainder;
** *** ***** *****
* * ** **** * * * ** (n != 0)
* ** * * *** **** *** *
** **** * * * * ** ** *** * * * ** ** * ** ** * ** = m % n;
**** * * ** * ** *** **** * * * * *** ** * = n;
* *** ** * **** ***** ** * * * * * ****** * *** = remainder;
*** * *** * * ** * * *
******* ** ** ** * *** * *
* ** * ** * * ** * *** ** = m;
** ** ** * *** ** * *
* * ****** * * ***** gcd;
}
int main (int argc, const char * argv[]) {
* * * * *** ****** number1, number2;
* ** *** * ****** *** newNumber1, newNumber2;
* * ** * * ** * * * *
* ******* * * ** * ** *
** **** *** ** *** ** ** *** ** **** * ** * ** ** ** *
*** * * ** ** **** ** *
* * * * * * ** * ** = number1 / gcd(number1, number2);
** ** * * **** * * ***** **** * * = number2 / * * * number2);
*** ** **** * * *
*** * * *** *** ** * *
* **** * * * * * *** * ( *** **
* **** * * * ***** ****** ** * ** * * ** ** * ** * * ** ** *** ** newNumber1);
***** * ** **** * * *
* * *** ** * * ******
****** ** * ** *** ** ** ** * * ** * * * ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * *** * *** * * * ******* a,b,c,d,e,f;
* **** *** ** ** *** * **** *** * ** *** * * **
* * * **** * ** *
* * * * *** * * ** * ***
* * ** **** * * *** ** * * * ***
    {
** * * * * * ** ** ** * ****** *
** * * ** ** ** ** *** * ** **
**** * * * * ** ******* * * ** *** * ** * **
    }
** * *** * * * ***** ***** ** *
    {
** * *** **** * *** * * * * * *** *** ** * *
*** * ** * ** *** * * ** * * * * * ***** * ** **** * * *
***** **** *** ** *** *** * ****** * ** * ** *
**** ** *** ***** ** **** **** **** ** **** * *** ** ** *** * * *
    }
* * * * ***** * * * ** *
    {
** *** *** * ** ** ***** ** * *** ** ********
* * * ** * *** ** **** ** ** ***** ***** *** * * * ***** **** **** *
* * **** ** **** ** * ** *** ** * **
** * * * * ******** ** ** *** **** ** *** * *** * * * *** * *****
    }
** * * ** ** * * ** * * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.120.163
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 14.6k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 14.4k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 18.5k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 14.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users