2 like 0 dislike
14.6k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 14.6k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

** **** * * * * * ** i;
* ** ** ** * ** * **** * j;
** * * * ****** ** * newNum1;
* * * * * * * ** newNum2;
** *** ** * *** ** ** * ** gcd;
** * * * *** ** ** *** rem;
* * * ***** * ** * num1, num2;

******** * ** * * *** ** *** * * **** *** * *** *

* **** **** * * * ** ** * ** *
** * * * *** * * * *

* * ** **** ***** **** * != 0)
* * * **** ** *
* ** *** * *** * * ** ** * * ** * * * ** = j%i;
** * *** ***** * *** * ** *** *** * ** = i;
* * ******* * ***** * * ** **** **** * ** = rem;
** ** * ** *******
** ** ** *** ** ** ***

** ** ** * * ** = num1/gcd;
* ** *** **** ** * * = num2/gcd;

***** * * **** ** * * * ** * == 1)
    {
** *** * * * ** * * ** **** ** * ** * ** ** * * * **
    }

**** * * * *** * ***
    {
** * *** ** ** * *** * ** * *** ** ** ** * * * ** * * * ***** *
** *** * * ** ** *

* ***** ** ** * ***** ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* ** *** * * * *** * * ****** ** * *** * *

** **** **** ** * * * **
** * * ** **** ** ** *** **** * *** * * *** *** * *** ** *** **** ** *

    else{
*** * *** * ***** * * *
    {
** * **** * * ** * * * * ***
**** ** *** * * ** ** * **** * ** ******* * ** *** * **** ** * * * && deno%i==0)
* * ** ** *** *** * **** * ** * ** * ** ** * ** * * * **
******* * **** ** ***** * ** **** ***** ** * * ****** ** ** * * * * * ** ** *
******* ** * **** * *** * * * ** * *** * * ** * * * ** ** **** ** * * ** * ** ** *
** * * ** ** ***** * * ** *** * ** **** * **** * * **
    }

** * **** ********* ******** *****
    {
** ** * ***** * * ** **** ***** * **
*** **** ** **** **** * ** ** *** *** * * * * * * ** ** * * ** ** * && deno%i==0)
* ***** * *** *** ********* * **** * *** ****** * * * *** **
* ***** * *** *** * * * * * ** * * * ** * *** * * **** **** *****
**** ***** * ***** *** * ** ** ** ** ** ** ** **** * **** ** * * *** * ****** ** * * ** *
**** * ** ** * **** *** **** **** * *** *** * * * * * ** * ** *
    }
**** ** * ***** *** **** *** * ** * * ***

    }




*** **** **** ** * **** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** **
#include ** * * ** * **

int gcd(int n, int m)
{
*** *** * * * * ********* * ** gcd, remainder;

* *** *** * ** * * * (n != 0)
** ** ** *** * * *
*** ****** ** *** ** * ** ** * ** **** * * = m % n;
* **** *** * * * ** ** * * ** * ** = n;
* * * ** * * ** *** * ** ** * ****** *** * = remainder;
** ***** ** ***

* * * * *** ** *** * ** = m;

*** * * ** * ** ** * *** gcd;
}

int main (int argc, const char * argv[]) {

* ** * ** * * * * * * number1, number2;
** * * * * * ** newNumber1, newNumber2;

** *** ** * * * * *** * ** ** * * * *** * * * * * ****

* *** ** * ** **** * ** **** = number1 / ** number2);
* * * * *** * ***** ** * ** * = number2 / * ** number2);

*** * * ** ***** ** *** * ** * ** * ***
** * * * * * * * * ** ****** ** ** * *** **
* * *** * * * * * **
** ** * *** * * * ** * ** * **** * * * ** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* *** ** * * *
****** * ** * *

int * * n, int m)
{
* * * **** *** int gcd, ** *

* ** * *** (n != 0)
* * *** * {
* ** * * * * * * * ** * * = m % n;
** * * * *** * * *** * m = n;
* ****** * * * ***** * * * n = *******
** ** * ** }

**** * * gcd = m;

** ** * * * * * ** gcd;
}

int main (int * * char * *** {

* * ** * * int * * * *
*** * int * * * * **

*** *** * ** ** ** ** *** * ** ** * *** * * * * **

* * *** * ** * * * ** = *** / * * ** **
*** * * *** * * * ** * = * * / **

** * ***** if *** ** * *** ***
* ***** * **** *** ** *** **** * *
* * ** else
* * ** ** **** * * ** ** * ** * * *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** *** * ** ******* ** * i;
* * ** *** ** * ** * j;
* ** * ** *** * *** * * ** newNum1;
* * ** ** *** * * **** newNum2;
* * * * ** ****** ** * gcd;
** *** * * ** * ** ******* * rem;
*** ** *** ****** ** * num1, num2;
    
** ****** *** ****** * ** ** * * * *** ** * **
* * **** ** *** * ***
**** ** * * * ** ***
** * ** ** * * **
* * * *** * * * * *
*** * *** ******* ** * *** ***** != 0)
** * **** * * *
*** * ** ** **** **** * * * **** ** = j%i;
* ***** *** * ** * * * * * * * ** * * = i;
* * * *** ****** *** ** * * * *** *** ** * * * * = rem;
** * *** * * *** *
* * *** **** * *
    
* ** ** * *** *** * * = num1/gcd;
*** ** * * * * * * * * * = num2/gcd;
    
*** ***** ******** * * ** ** == 1)
* * * ** * ** * * ** *
** * * ** ** ** * ** *** ** ** * * * **** *** * * *
** ******* * ** **** *
    
* ** * * * * ** *** * **
**** ***** * * ***
* * ** ** *** * ***** * ** * * * * * * * *** * * ** ** ** * * * **
*** ** *** **** * * *
    
** ** * * * * *** *** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** *** * * * * ** ** i;
****** * ** *** * * * j;
* ** ******** *** *** ** newNum1;
* * * ** **** ** newNum2;
* * * ** *** * * * * gcd;
* * * * ** ********** * rem;
** ** * * *** ** * * num1, num2;
    
* ** * * ** * ** * ** *** *** * *** ***
** * ***** * ** * **
** * ** ** * * ** * ****
* * ** ** *** ** **
* ***** * **** ** *
* * * * * * ** * * != 0)
* * * * * ** * **
* *** * ** ** *** * ****** * ** * = j%i;
* ** ** * * **** ** * * * * ** = i;
* * ** *** ** ********* **** * * * ** * * = rem;
* * ** ** * ** * *
******** ** ** * * * * ***
    
** ** * ** * *** * = num1/gcd;
* * * * * **** *** * ** * * * = num2/gcd;
    
* * * ** ** *** ** * ** *** == 1)
* *** * ***** * *
** ** ** ******** * ******* * * ** * ****** * * * ** * * ** ** * **
* ** * * *** **** ****
    
*** ** *** ** ** * ***
** ** * ** * **
* ** * *** * * * * * ******* * * * * *** * *** * * * ** ** * * ** *
** ** * * * * *** * ***
    
**** *** * ** ** *** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** * ***** * * *** * ** ** * * * * **
* * * *** * * * *** ** * **** * *** *** *
    {
* * *** ** * ** * **** ******** * * * * * ***** *** * ** **
** ***** ** * * * * * * *** ** * * ** ** ** ***** * *
** * * * * ****** * **** * * *
**** ** **** ** *** * * *********
* *** *** ******* * *** ** * * ****** *

******** **** ** * * * *
* *** *** *** ****** * * *** ** **** * * **** ***** ** *** * * ** * ***** ** ** * * *
* ***** * ****** * *** * * ***** ***** ********** ** * ** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
** * * * * *** **** * a,b,GCD;
** * *** * *** * ** * ** ** * * ** * * ** ** * * *** **
*** ** * ** * * ****** ** **
* ** * ** * * * ** * ***** * * *
*** *** * * * ** * *** ** * * *** * *** ** ** * ** * ** ** ** *
*** ** * ** *****
* * * **** * * ** *** *** ** *** * ** ** * * * ** *** ***** ****
* ***** * ** * * ** ** 0;
}
* * ** * ** * ** *** gcd(int a, int b){
* * * * * * * *** ** * ** * (!b) return (a);
* **** **** ** * * * ** * * * * * * ** ** * * gcd(b, a % b);
* * * * * ** * * ***
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** * * *
#include * * *** * * **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
****** * ** **** gcd, remainder;
* **** **** ** * *
* *** * ** ***** * ** * ** (n != 0)
* ** *** * * * *
* * ** ** ***** * ** ** ** * ** * * * **** = m % n;
******* ** ** *** *** ** ** * * **** *** * = n;
***** * ***** * ** * * * ** *** * *** ** ****** = remainder;
* * ** * ** * * * * *
* * * **** * *** *
***** * * ** ****** * *** = m;
* ** **** ** * ** **
* *** ** * * *** * * **** *** gcd;
}
int main (int argc, const char * argv[]) {
** *** *** **** number1, number2;
**** *** ** * *** * * newNumber1, newNumber2;
* * *** * * *** *
* **** ******* ** ** *
* * *** **** * ** * ** ** ** * * *** ** **** * ** * **** * * *** * * ** *
** ** * * * * ***
* * * ******* ***** **** = number1 / gcd(number1, number2);
* ** * *** ****** *** * * = number2 / * ** * number2);
* *** ***** ** * ***
*** * ** ** * **** **
* *** *** *** * * ( ** **
* **** ******** ** * * ** * * **** * ** ** * ** *** *** * ** ** newNumber1);
* ** ** ** ** *** **
* ** ******** * **
** ** ** ** ** ** * **** ** * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
**** **** **** * *** * ** * a,b,c,d,e,f;
****** *** * *** *** * * * *** ** **** *
* **** ** ***** ** * ***
* * ** * * * * ** * * **
* * * * * **** ** * *
    {
* * ** ****** **** * * * ** **** **
* ** *** ** ** *** ***** * ** * * * ** * * ** *
** * * * ** * * * ** *** * * * ** * * ***
    }
* *** * **** * *** *** ** *
    {
***** *** *** *** * * *** ** * * * ** *
* * * *** **** **** * ** * * ***** * * * ** ** ** **** * * ** *
* * ** * ** ** ***** * * * *** * * * ***
** ** * * *** * * * * * * ** * * ** **** ** *** * * ****** ** ** *
    }
* * ********* **** ***
    {
* * **** ***** ** * * * **** ** * * * * *
** * *** * * **** **** ****** * **** * * * *** ** * ** * ** *
** * * ***** ** **** * * * * ** ***** * * *** *
* * * ** * *** ****** ****** **** ***** ** ** * *** ** * ** **
    }
*** * ***** * * ** * ****** * **** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.67
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 14.9k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 14.8k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 19.1k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 14.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users