2 like 0 dislike
8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 8k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

*** ** ***** * * **** * i;
* ** ***** * * * j;
* ** ** * * * * *** * newNum1;
** * * * * ** * * ***** * * newNum2;
** ** ** * * *** ** ** gcd;
* **** ** * * * **** * rem;
* * * * *** * ** ** * num1, num2;

*** * * * ** ** ** *** * * * * **

* ******** * * * *** *
*** **** ** * **** *

**** ** * ** ** ***** ** != 0)
**** ** * **** * * **
**** * * *** ** **** * ** * * * ** * * **** * *** = j%i;
* ** * ** ** * **** * * ** ** * ** * * * * ** ** * = i;
* ** * **** ****** * **** ** ***** * * ** = rem;
** ****** ** * * ** *
* * * * ** ***** *

* * * *** ***** ** * = num1/gcd;
* ** * ***** ** * ** * = num2/gcd;

*** ** ** ** * * **** * == 1)
    {
* * **** ** * ** **** * * * *** ** ** * **** ** ** * * * * * **
    }

*** * *** **** * * * *
    {
* * * **** ** *** ** **** *** * *** **** *** * **** ***** ** *
* * ** * ** ** ***** ****

** * ** * ***** **** * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
**** * *** ** * * *** * ** * * * ** * * * ** *

**** *** **** * **** * * ***
****** * * *** * * ** * * ** *** **** *** **** * ** * **** * ***

    else{
* * *** * ** * * * ** **** **
    {
****** **** * * **** **** ** **** * ** *
** ***** ** *** ** * * ** * **** * ** ** * ** * * * * ** * * ***** && deno%i==0)
* * **** ** * * ***** **** ** *** * * * * *** * ** *** ***
* * * * * ** * * **** * * **** ** ** * **** ***** ** * * ** ****** * ** ** *
** ** * * * ***** **** * * ***** * *** *** *** ** * * *** * * * ********* * ** ** * * *** **
** * *** * ****** * **** *** * * *** ** * *********** *** ** *
    }

** * ** ****** ** * ** ** *
    {
* **** * * * * * * *** * * * * * **
** ** * ** * * ****** *** *** ****** * * * * ***** *** * *** * && deno%i==0)
* *** * ** *** ** **** * ***** * ** * * * ** ** *
* * * ** * * **** ** ** ** * * * ***** ** * * ** * * ****** * ****** * * *** *
* * **** * ** * * * *** ***** * * ** * * ** ** * ** * * *** * ** ** * * **
** ** * * ** ** * ** ** ** * ***** * * *** * ** ** * ** ***
    }
* * ** * *** * * *** * **** ** ** **** * ** ***

    }




**** **** *** * **** * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ****** **** *
#include *** * *******

int gcd(int n, int m)
{
* ****** **** * * ** * * gcd, remainder;

* ******* * * ** **** *** (n != 0)
*** * * *** *
***** ** *** * * * ** *** * *** **** * ***** = m % n;
***** * *** * ** ** ** * * ** * * ** * * *** = n;
*** ****** * * ***** *** * * * ** *** * = remainder;
*** ** ** **** **

**** * * * ******** * * * * = m;

* * ** * *** * ** ** * ** * * gcd;
}

int main (int argc, const char * argv[]) {

* ** *********** *** ** number1, number2;
* * ** * * *** * * * * ** * newNumber1, newNumber2;

******* ** * *** ** *** **** **** * * * * ** ** * *** *

** ** * * * * * ** ** * = number1 / ** ***** number2);
* * * ** ** ** *** ** = number2 / *** *** number2);

* * **** ** * ** ***** *
* ** ** * * ***** * *** * *** ** * **** * *
** * ** ** ***
** **** * *** * *** ** * * *** * ****** ** * * *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
** * * ** *** *** **
** **** * * * ** *

int * * n, int m)
{
* *** ** * int gcd, *******

* ** * ** ** (n != 0)
* ** ** * {
*** ** ** * **** ** ** *** ** = m % n;
** * *** * ** ** * * * * m = n;
*** * * * * * ** * * *** n = ****
* *** * *** * }

**** * *** gcd = m;

*** * * * * gcd;
}

int main (int *** * * char * * {

* **** * ** int ** ** **
* * * * int * ** ** ** *

* ** * *** ****** * * ** * * ****** *** * *

* * ******* ** * * = ***** / ** * * *
* ***** * * ** ** = ***** / ** * * ***

* * *** * if * **** * * * * *
* ** * * * *** * * * * * * * * ** ***
* *** ** * ** else
***** * ******* ** ** *** **** * * ** *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** ** ** **** * * ** i;
* ** ***** * ** ** ***** j;
* ** ** ** * ** ** * * ** * newNum1;
* * * ** ** ***** newNum2;
* ** ** ** * ** * gcd;
** * ** * ** * ** rem;
* ** ******* * * ** num1, num2;
    
** ** * ** * * ***** * **** * ** **** **** *
** *** * ** * *
* * * * ** * ** *** ** *
****** *** ** * * ** ** * * ***
**** *** ** * ******
*** * ** * ** *** * * **** != 0)
*** * * ** * ** **
* * * ** * * *** ** ******* * *** *** ** *** ** = j%i;
***** * ** ***** ** * *** * *** * * * * = i;
**** * * ****** *** ** * *** ***** * = rem;
** * * *** *** *** *
* ** * ** * ** ** ****
    
** * **** ** ******** * * ** = num1/gcd;
** * *** *** * ** * ** = num2/gcd;
    
* * * * ***** * * ** == 1)
* * ** * * * * ** * ***
* ** *** * ** * *** * *** ** * * * * * *** ** * * * ***
** *** ** * *** *** *
    
* ** * * ** * **** *
* ** * * ** ** *
** * * * * *** * *** * ** * * ** * ** * * * * * * **** ***
** * * * **** **
    
****** * **** *** * *** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* *** * *** *** * * * i;
* * **** **** * ** * j;
** * ******* *** * ** newNum1;
**** * * * *** ** ** newNum2;
* ** **** **** ***** ** * gcd;
*** ** * ** ** *** * * **** rem;
**** * ** * * ** * *** * * num1, num2;
    
** * ** **** * ** * * * *** *** *** * ** ***** ** * *
** ** * * * ***** *
**** *** * * ** ** *** **
* * *** * * ******** * *
****** **** * * * ** * ***
* * ** ******* * ********* * * != 0)
* * *** * *** ** * ** * **
** ** **** ** ** ** ** * *** **** ** **** * = j%i;
* * ** ** *** * * ** * ** *** *** * * ** ** = i;
* *** * ** *** * *** *** * **** *** ** ** * *** = rem;
* *** * * * * ** * *
* * *** * ********** * *
    
** * **** * * * = num1/gcd;
* * ** * * * ***** = num2/gcd;
    
** * * *** ** ***** ** == 1)
** * ** * ** * **** * ***
* * * ** **** * * ** ** *** * ** * ** ** ** ** * *
* * ** **** * * * ** *
    
* *** * ** * *
* ** * ** *** ** ***
* ****** * ** * *** * *** ** * * **** ** * *** * * **** ** *
**** * * * * *
    
* * *** * **** * **** * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* **** ******** ** *** ** **** * ***** * *
* * ** ** ** ** ** ** * * * ** * ** *** * * ** *
    {
*** * * *** **** ***** ** * ** *** * * * * *
* *** * ** ** ** ** * *** * ** * * ** ** * **** **
** * ** *** ** * ***** **
* ** **** **** * * * *** *
* ** * * * * * * ** * ** * ** **

* * * * ** ** ** * * ** **** *
* *** * ** **** * * * * * ** * *** * *** * ** * *** ** * **
** ** ** * ** * ** ** ** * * * * ** * ** * * * ** * ****


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
** ** *** * ******** ** * a,b,GCD;
*** * * * * * ** * ****** * * * ** ** ** * * *
**** ** *** * * * **
* * **** * ****** * ** *
* **** ** ** * ** * *** ******** ***** * ** ***** *
* ** **** ** ** **** *
**** *** * * ***** * ** ** * *** * * * * * * ***** * **
* * *** * * * ** ****** 0;
}
*** * ** *** ** * * * gcd(int a, int b){
* * ** * ** * * ** * * ** * * * ** *** ** * *** (!b) return (a);
******* *** ** * ** **** * * *** *** ** * ** ** ** gcd(b, a % b);
* ***** ** * ** **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** ** * ***
#include * **** **** **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* **** * * ** * gcd, remainder;
* ********* ** ** ** * * **
** * ** * **** ** *** * * (n != 0)
* * * ** ** ** **
* ** * ** * ** * * * **** ** *** * * *** * * *** = m % n;
* * ** ** *** * ** * * * = n;
******* ** ** ***** * * * * ****** ** ** ** ** = remainder;
* * * ** * * ** * *
* ** ******** * * *
* ** ** * * ** * = m;
*** * *** * *** ** * *
*** * *** * * * ** ** ** ** gcd;
}
int main (int argc, const char * argv[]) {
* ** * * *** * ** number1, number2;
** ** * ******* ** ** newNumber1, newNumber2;
*** * * * ***** *
* * * ** * ** * * ** * * *
* **** **** ***** *** ** *** * * ** ** * **** * ** **
* * * * * ** * *** *
*** * * ****** ***** ******* ** = number1 / gcd(number1, number2);
* * ***** * * **** ** * * = number2 / * number2);
* * *** ** ** * * *** *
* * * * * ** *
*** **** * * * *** * * **** ( *** *
* *** * ****** ** *** ***** * * * *** ** * * ** *** ** * newNumber1);
****** * **** * * * *** *
**** * ** * **** *
*** ** ** * *** ** ** *** * ****** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** *** ** ***** * a,b,c,d,e,f;
* * * *** * *** ** * * ** * * ** * * *** ***** ******
** ** *** * *** ***
****** *** **** * *
* ** *** * ** *** * **** *
    {
* ** * * ** **** ** ** * * * * * * * ******
**** * * ** ** **** * * ** * ** * *** * *
** ** * * *** *** ** * * * * *** * * * * **
    }
***** * ** * ***** * *
    {
* * * * * * * *** * * ** * * * ** * * ******** *** *
***** *** * *** * *** ** ** * ** ****** ** ** * ** * ** ***
*** **** **** * *** ** ***** * * ** * **
** **** * ** *** * * * * *** * *** *** ** * * * * *
    }
** ***** ** * ** **
    {
*** ** * ** *** ** ** * * * ****** * ***** *
** * **** * * * **** *** *** *** **** *** * ** * ** ***** * ** *** *
* * * * * * * * * * * * * * ***
****** *** * * ** ** ***** *** ** *** ** * ** * *** * * *** * **
    }
* ** * * ** ***** * **** ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.144
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 8.3k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 8k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 10k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 7.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users