11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
11.8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 11.8k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

*** * * ***  *   ** * *   *  * *   i;
* * **** ** ***   * **   j;
*  ** *    *    **** * **  newNum1;
*   *  *******  ** * *** newNum2;
*    ** ** *  **   *  *   * gcd;
 * **  ***** ***  ** * ** * *  rem;
  ***     * *       * num1, num2;

 *** *** ** * ** ***    **  * **   ** ***** * *  *      ***** *  

 * **    *  * **  **** **   *  **
**   * **  ** * ** * * **  * * 

*  * *    *  **  **  * *   ***** != 0)
***  * ***   *****  ** ******* * *  
     ** *    ***** * *  **** * * **  *   * * * *  *   ****  = j%i;
   *******     ********** *  **   ****  * *  ** * *  = i;
* ** * *** * *   *  ****  * *  * ***  *   **  **  **    * = rem;
  *   *      * *****   **  *  ** 
        *  *  **  * *****  *** *** 

*  * ***     ****  *** ** *  * *     = num1/gcd;
***   *** *   ***** * * **   ** = num2/gcd;

** * **    * ***    *****  ****** **  == 1)
    {
        *   * * **** *   *****      ***    ***  ** * **** *******   ** *    * *  *    * 
    }

**   ** * ** * **    **  **
    {
* ** ******** *** *  ** *****   **    ***  *  ** *  ***  * *******  * *     **    ***     
* ***    ****  * **   *      

** *      ** * * ** * ***   **   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** **    *      * *     * **   **** * *** ****** * * **** *** *  *   *

* *      *   * **   *  ********   
* ** ***   **    *   ** *   **** ** **  *    ****** * * ****  *** * ***  ***** **   *   * 

    else{
* *  * *  *****  *    *   * *   *  ** *  
    {
 **  *   *   * * ****      * **** **  *** * 
***  ****   **** * *****     **  **  **   ** *     *   *** * *  * ******  *   *** *  * && deno%i==0)
 * ***   ** *   *     **** * **  *   ** * *    ***   **   ***    *  *    *    *   *
   * **** ******       **       *  **    *   **    * ** **   * ***  *** ** *    *      ** **** *      *** **  
* *  * ** * * **   ** * ** *** ***  **  ****  *     * *  * * * ******    * * * * *  *        *   *   ** 
*  * ** **  *  ** * ******* ** ***  *** **  * **  * ******    *  ** * ** ** *  ** * 
    }

* *  **       * ***  * **  * * * 
    {
* *    **   * * *** ***  ***** * ** * ** ***  *
    *   **** ******* * **   *  *   ****  *  *****  ****** ** *  ** **  ** *   * **** && deno%i==0)
      **   ***   ** **   *** ***      ***     *  **** *    *  ** *  **** ** ** ****  ** 
*** *  **  * ** * * * **** ** ****** * * ** **   *  *    ******* **    * *****      *** *   ****   * *     * *
**  *  *** **    * *  *** **      *   *  *  ** **** **  *  *     * ***** ***  ** *   ********   * * *  **     * ***** *
* ** ** * **** ** *  ****** *  *      *  *  ** *** *** * ** ***  *   **       **  *   
    }
   *  *  **  **   *   * * **  ****** * **    ** ****  *

    }




*     *****  *  *** * ** ****   0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *    *     **  **
#include *   *  **  

int gcd(int n, int m)
{
  *  **** *  * **  * * ***   * * gcd, remainder;

* * *  * * **   **  * * *   (n != 0)
******  ** ****  ***** * * 
* ****** * ***         ***  ***   ** * *** * ***** * ***    = m % n;
  ****   **  **  **   *  * *  *****   * **     ** * **      * = n;
* *  **     *   *  ***  * **  **** **** * *  ***  * ** *  = remainder;
 ***  * *   * * * *****  

** * * * * *** ***** **  *  **  *  = m;

* ****  ***  **** * *  ** *  ***  *  gcd;
}

int main (int argc, const char * argv[]) {

*  ***     * * *    **    number1, number2;
   * **  *****   * *  *  *  * newNumber1, newNumber2;

** * *  ***********    *   ***  ** * * *** * ** * *  ***        **  ** 

*  * * * * ***    ** ** ** * *** ** ** = number1 /  * * **** number2);
  *** * ** *** * *  ** ***   *** * ** ** *  = number2 / * **    number2);

     *  ** * *  **   *  * *** * * ** ***       * * *  
   *  **  ** *  ******    **    **  * *       **  **  * ** *  **  
  ***  **** ***  ***    *   
*** *   * *****  * *   ** **  **  ***    ***  ** **     
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*     *  ***** * * * * 
* ** * ***  *  ***    

int **** n, int m)
{
   * * *    * *   int gcd, *    *

**       * **  (n != 0)
   *  *    *     {
 *   *  *** **  ** ***    **    **   *    = m % n;
      * **     ***  *     * m = n;
  * *** *        *****  ****  n =  ***
 **    ** *****  }

       **  * *   gcd = m;

*****   *   **     ** gcd;
}

int main (int *  * *** char * **   {

   **   * *  * int  ***     *   
 *****    *     int   * **   ***  **  

*  ****  *   * **    ** *    * ****  *** *  ** *  * *  *** ** ***

**  *     * *  *   =  ** ** /  ***   *  *     *
***    *  * ** * *       *  =  *** /   *  *       * *

 ***     ** * * if    *  * ** * * * * *  
 * * ***  *** *  *  * ****  ****** * *  **     ****   *    *
***      ***    else
   ** ******* ***   * *   ****** ***********  * *      * * 
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
*  * **  **  * *****   ** ***   i;
  *  *     *  *** ** * * * ** * j;
 ** ** *  **********  ****  *  **   newNum1;
*  ** *** **   **   ****  newNum2;
* **  **   * **   **   **** gcd;
**    * *  *******       * * rem;
 ** ** * * ****    ** ***  *   ** num1, num2;
    
   *    * ******* * **   **   * *** *** * * ***  *  **    ****** * *    
    *   *  ** ** *    
**  *  ** **** **** ** *** ** * * *  
***  ** **  * * * ****    **
     **  *  **   *** **  * ** ***
  *     *   *** *  * ***** * *     != 0)
*** **  ***    ****  * *** 
*** ***********   **      **  **** ***   ** ** * ***   * **  * **   = j%i;
* *  *  *  *    *  *  *  **   * ******  *  *  ** * * *  *   = i;
* ** ****     **** ***** ** ***      **     *  **  = rem;
    **   **      ***  * *
 **  * *    * * *    **   *  **  * *
    
   ** * ***  ******* *    **  = num1/gcd;
   * *  * *  * ** *******     *  = num2/gcd;
    
 * * ***    ****** *****  *****  * == 1)
  *  *  **   ** **  **  *** 
* * * *  ** *****  **  ** * **** ******* *  ** **    * ***** **  ** *   *
*      **    *   *** *   **    
    
**  **  ***     **** * ***  * *
*       **** ** **** 
 * **** ** *  * *** * ***         ** *** **** ** * ** **** *   ******      * **
** *  * * * *  **  ** **     *
    
 ** *  * *** *   **  *   ** * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 ***      * *  *   *   ****** i;
  *   ** * * **   * ** **   * * j;
* ******* ** *  * ****  *    newNum1;
* ***** ** * ***   **** newNum2;
 ***** *  ****   *   ** *   *****  gcd;
 ***  * * ***   * ***  ** *****    rem;
  * * ***    *******     ** **    num1, num2;
    
* * *  **    ** *** *** *** ** *  *  *** * * ****  * **  *  ** *    
        ** *   * ** *** *  ** ***
*   * *  * **** ** *  *  *********
 ** * ***  * ******  *  ** ** 
** ** *    *** ******* ** *
 *   * ** *** *  * *  *     * != 0)
  * * ******** **  **   ** *  
**** ***  **** ** *** ** **   *    ** ****** * *  *    * *  * = j%i;
 *    *  * ****   *** * **  ** *   ***  *    ** *** *** * * = i;
*      * *****   *** *******      * ******* * *    *   ***  = rem;
 * ** *****   *   **   **  **
 **  *   *  *  ****      * 
    
* *  *        *    **  * ****  * ** *** = num1/gcd;
*  ** ******      * * *  **    * = num2/gcd;
    
 ** * * ** **   *  **  *  **  *   == 1)
 **  *** *  *  *    ***** *
 * **  *  *      **  ** ******  * *   * ***   ***    * *** ** ** * * *    **   *    **
****  ** **  *   *   * *   
    
* *   *  ***    **** ** * 
***  *** * **      ***  * *  *
 *  **    **** *** *** *******    ***    ** ** **  ***** ***  ***     * *  *  **  ** *  ** **
  ***     * **  *** ***  * 
    
* **  ***  * * *  * *     **** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
***** ** ** * ** *  *   ** ***   *   ***    **** **  *** * **
   * *   **  ***  ** *  *  *  **   ** *     *  ** ***    *** 
    {
* ***    * *   ** *   ** *  ***    * *  * ***  *    * *****  **** ** 
* * *   * *  *   *** *** ****   ** *  * *** **  * ***  *  **
** *  **      * * *  *  *** ***   **  * **   *
 * * ** *       ****  **  *** * ***  ***   
**** ***    **   * *   **    ** ** * * ****  

 **   * * *   **      * **   *  
**   *** **  **  *** *** *** * ***** **    * *** * *** ********      ****     *   * *       ***  *      * **  *
* *  **** **   * * ** ** * **  *  **** **  * *** ** **   * *     *    *** * **  *    


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
    * ** *  *  **  ***  *  a,b,GCD;
**   **   ****  *      *  * ****  *  *      ***  *  *  ********  
* **  **    * ***  ** *** ** *  *
**     *  *** * **** ** * *   *  
*  * * ** * ***** * ** ** **  ** ****** ** * *  ***     ** * ***
  * * ***  ******* ******** *  
**  ** *  *** * **  * ***   **     *   **    *   * ** * **  * ** *  * ** ***
* **** *  **    *  *   *  ***   0;
}
* *****  ***  **** **   * *** gcd(int a, int b){
 *      **         *     **   **** * **   *** * **   *   *   (!b) return (a);
*  * * *   * ** *   * ** ***  **     **    *    **  * *  *  gcd(b, a % b);
 ** *  *** *  * *****  *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *****  ***  *
#include    * ****   

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
   * * *   ******  *  ****   * gcd, remainder;
 *       * * ******  ********
 *  ** * ** ***   * **** ****     (n != 0)
*    ** **   * *  *** ** ***** 
*****  **** *   * ** **  *   ***     **  *  **  * ***** * **** = m % n;
**    *** *** ***  *  * *  ** ****     **  *** **** * ***** = n;
   *    *   **  ****  *** **  ** *  *    ***** *  *** = remainder;
 * *** * * ** * *      ***   *
**** **** * ***      *
        ***       *   **  = m;
***** * * ** *  * * *** **  *
**     **        * ***  ** ***     gcd;
}
int main (int argc, const char * argv[]) {
***   **  *  * *****  ***** number1, number2;
 * *  *  * *    * * **** * *  * * newNumber1, newNumber2;
    ** * *******   * * *  
  *  * ** *  ****      **  ** *
*****   ***** ** ***  * *  *** **     *** * *     **     ***** *  *  ** ** **** 
 ***** * *    ******    * ***   
  **  * *  *    * ****** *****   = number1 / gcd(number1, number2);
***  **  ****  * **  * ***    *  *  * = number2 / *       * number2);
        **** ****   ***** **
*    *******    *  *       * *
* *    * **  *** *  * **  *  (    ****  
   ****** * *   ** ***   ***       *   ****      *  **   **** *  **       *** newNumber1);
*   ** * * *** *  * * *  * 
*  ** **  *  ** *  * 
*** *  **   ***** ** ****  * *  ** * * * *  * **    *  *  newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*   ** **** ***** * *  **** * **   a,b,c,d,e,f;
* * ***  ** **  * ** * *  * ** **  *    * ** ***   *  * *  * * 
 *  *  *   *** *          * *
 ** *  ***    ***** *****   *  
 **  ***  * *** * *   ****  ***** *
    {
   **  * *  **  ***  *** ****  * *   * *  **  *****  *** **
   * ** ** * *  * ***   * **** *** * *  **    *    * **  **  
    *  ***  *****  *** ****** * **** **** ***   ** *** *
    }
*  * * ** * *    **   ** **  ****    *  
    {
 *    *   **      * *** *  *  * ** ** *  ** *** *   *  ** 
*** ** * *  *** * ***      *   *  ***  **   **  *    *****   *** * **** *
    *     *** * *  ******* **   ** * * ** ** * *** 
*** ** * *  **    **   ***  **  *   * *  *** ***    **   **  **  **     **     * 
    }
*  * ** * ****  * ** **  ** **
    {
 *    * **     * * *****     ******* **   ********* *****
   *  *   **** *  *** * *  * **    *   *********    *    * *   ****    *  * 
 ** * **** ***** *** * ** ***    *  ***  **    **  * *  *     
 ***** ** *  ** *        * ** *  *  **  *    *  * **  **  * * *     ***  ***     *
    }
*  *  **** ** * ***  ** * ****  0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.72
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 12.1k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 11.6k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 14.9k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 11.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users