2 like 0 dislike
15.6k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 15.6k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

** ** * **** ********** * * i;
* ** * ** ** ** ** ** j;
*** * * ** * * ** * * * newNum1;
* ** **** * * ** newNum2;
** ******** * ** * gcd;
* * * * * *** * ** ** ** * rem;
* ** * ** * * num1, num2;

** * * ***** *** * *** *** ** *** **** **** *** * * ** *** * * *

** ***** *** ** * * * ***
*** * ** *** ** * * ** *

* * ** * ** ** * ** * != 0)
* * **** *** *** ***** ***
* * ** ** * * * * * * **** * **** ** = j%i;
** * * ** *** ** *** **** ** * ** * * *** = i;
******** ** ** * * ** ** **** ** * *** * *** = rem;
** ***** * ** * **** *********
* * * * ** ** * * ****

** * * * ** * = num1/gcd;
** ********* **** * ** * = num2/gcd;

**** ** ** * * * *** * == 1)
    {
*** ** ** **** * * * *** * ***** ** ** **** ** ** * ** ** * * * *
    }

* ** * * ***** * * * *
    {
*** * * * **** *** ** *** * **** * **** ** **** ****** *** * * ** ** * ****
* **** ** * * **

* ** **** * ** ****** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** * * **** * ** ****** * ** ** * * * ** ***

** * * * ** **** * * *
** **** ** *** * * * * **** *** *** **** *** * ** ** * *** * *

    else{
** ** **** ** * * * * * **
    {
** * ** * * *** * * ** ******* ****
* * *** **** * * ** ***** ******* ***** * * * * ** ** **** * ** && deno%i==0)
*** ** * ** * * * * ** * ** * * ** * ** * * * ***** ***** ***** ** *** *
* ****** *** * *** * * * * *** *********** *** * * * *** ** ** ** **** ** * * **** *
* * *** * ****** * * * * * * * * * * ** * **** ** ** ** ** ** * * * * * ** * ** * ** *
* *** * * ** * **** * ** *** **** ** ** * ** *** ** **** *
    }

* * ***** ** * *** * * * *
    {
* * *** ** * * **** * * * * * ****
* * *** ** * *** *** ***** ** * * *** * **** ******** * *** * && deno%i==0)
** * *** *** * ***** ***** **** * ** * * * * *** * * * * * ***
** *** * ** * * **** * * * ** **** * * **** *** ** ** * * ** * *** *
* **** * **** ***** * * ******** *** * ***** * * *** * * * ** ** ** *** * *** * * **
* ** * ** * ** * * * *** * *** ** *** * *** **** *** * * ***
    }
* ** * ** ** * * ** *** * * *

    }




** ** * ** * * * * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** ** **
#include **** * * ** *

int gcd(int n, int m)
{
*** * * ** *** * ** gcd, remainder;

* *** * * **** * ** ***** (n != 0)
* *** * * * * * * * *
*** ** * * ** *** * * *** **** * * *** = m % n;
* ** * * * *** ****** * ** * * * * * *** * * = n;
* *** ** * * ** ****** * * * ***** *** *** ** = remainder;
* * **** * *

* *** * ****** *** * = m;

*** * ** ***** * * ** gcd;
}

int main (int argc, const char * argv[]) {

* ** ******* * ***** number1, number2;
* *** *** ** * ** *** newNumber1, newNumber2;

* * * * * **** ** * * * ****** *** *** * * ** * ** **

** ** * ****** ** ** = number1 / * number2);
** ** *** ****** *** **** * * = number2 / ** * ** * number2);

***** * * * **** * * ***** *** * *
* * **** ** ***** ** ** * ****** ** **** * ****** *
* *** * * **** ** * * *
** ********* *** ****** ** ** ** * **
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* ** * * * ** **
* * *** *** ***

int **** n, int m)
{
*** ** * int gcd, *

* ***** * (n != 0)
* *** * * * {
** * ** ** *** * **** * = m % n;
* * * * * ** * * * * m = n;
** *** * * ** ** * *** n = *
** * * * }

* *** * * gcd = m;

** ** ** *** * gcd;
}

int main (int ** ** char * {

** * ** int * * **
* * * * **** int * ** * * *

** * ** * ** * * * ** **** *** *** *** * **

** * * *** * ** * = * / * ** * **
* * ** ** *** * * * = * ** / * ** ** *

*** * * * * if ** ** * * * *
** *** * * * * ** * ** * ** * ** * ** * **
***** *** else
****** ** * * *** * * *** ** ** ***** *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* **** * ** *** *** *** i;
* **** *** * * *** * ** j;
* ** * ** *** *** ***** * newNum1;
* * * * ** ** *** * * newNum2;
***** **** * ** * ** * gcd;
*** ** * **** * rem;
* ** ** ** * ** * ** * num1, num2;
    
* **** *** ***** * * * *** * * ** * ** * * * * **
** ** ** ****** * ****
* * ** * ***** **** * * * *
* * * * **** ***** * **** * **
* ** ** * * * * * **
* ** * * * ** ** * != 0)
* **** ** * ** * ****
* * ** ** * *** *** ** ** **** ** * *** *** * = j%i;
* ** *** * ** *** ** *** * * ** * **** ** ** *** = i;
* *** ** ** * * ** ** * * * * * * = rem;
** * *** * * * ** * ***
* * **** * * * * ** * **
    
**** ** * * * * * *** = num1/gcd;
* * **** *** * * * * *** = num2/gcd;
    
** * * **** * **** * *** == 1)
* * * ** * * ** ****** ** *
* * *** * * * * * *** ***** * *** * * ***** *** ** * * *
** * * ** *
    
* **** * * **** * * **
* * ** * * * * ** *
** * * * * * * **** ******* ** * * * * ** ** ** * ** ******
** *** ****** *****
    
** ** ** * * * ** * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * ** * ** i;
* * * ** * ** **** ** **** j;
** * ** * ** *** *** *** newNum1;
*** * ****** * * ** * * newNum2;
*** ** * * * ** gcd;
* *** * ** * **** ****** rem;
** * ** * *** * * * num1, num2;
    
** * ** *** ** *** *********** * * * ** * * * * *** ** *
* ****** * *** * * * * *
* * ***** * * * * ***** **
** ** * * * * * ***
* *** * ** * ** ** **
* * ***** ** * ** != 0)
*** ** ** * * ** **
* * * * ** * * * * * * * *** * ***** * * ** = j%i;
* * * **** * * * ** * **** * * = i;
** ** **** * *** * * *** * *** ** * * = rem;
* **** ** ** * * * *
* **** ** *** * * *
    
** ** * * * * * * ** ** = num1/gcd;
* * ** ** ** *** ***** * = num2/gcd;
    
* ** ***** *** **** * *** * == 1)
* ** * * ** ** ** *
* * ***** * * * ** * *** *** ** *** ****** * ** *****
* * **** ** *** ** ***
    
*** * * *** * ** ****
* **** * * * **** ** **
* ** * * *** *** *** **** * *** * ** ***** **** ** ** * * * * ******* *** **
** * *** *** ******
    
* * * ** * * **** * * * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* ***** * * * ** ** ** * * ****** * * *** * *
* * * *** * * ** * * ** ** ** ** ******* * *****
    {
* ** * * * * * ******* **** * * * ** * **** *
* * ** ******* ** * ** ** * * ** *** * * * ** *
* * * * * * * ** * ** *
***** * * ** * ** * * * * ****** **
*** ******** *** * *** * ***** **** ***

* ** * * * * **** ** **
* ******** ** ** * * * * * * * ** **** ** ****** * *** *** * ** * * **** *
** * ******* * * *** ** * * ** * ** * * *** * * * * * * * * * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*** * * * * * * ********* * a,b,GCD;
********* * * * ** * ** * * ***** ** * *** * * *** * * * * **
* * *** ** * * ** * * **** * *
**** ** * **** ***** **** * *
** * ** * * * * * * * * ***** ****** * ** ** *** *
* *** ** * ******* ** * *
* ** ****** * **** **** * * * * * *** * * * *** *
* * * ** * * * ***** 0;
}
** ** ** ** * * * * gcd(int a, int b){
* * *** * * ** ** *** * * * * * *** (!b) return (a);
****** ********** ** ** * ********** * gcd(b, a % b);
** * ****** *** ** ***
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** *
#include * ** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* ** * * **** ** gcd, remainder;
* ** * * ***
* *** ***** ** * ** * (n != 0)
**** * ** * * * ** *****
* * * **** * * * ** ***** * * ** * * ** ** *** * * * * = m % n;
**** ** * **** ** * *** ** * * * * ** = n;
* * *** * * * * ** * *** ** *** * **** ** *** = remainder;
*** * ** * **** * **** ** *
** * * *** ********* **
*** **** * *** ** *** * * * = m;
* * ** * ** * * *
** * ** * *** ***** * * gcd;
}
int main (int argc, const char * argv[]) {
* ** ** * * ** ** *** * number1, number2;
* ** *** ** *** ** newNumber1, newNumber2;
* * * ** **** * *
* * * *** ** * ** ** **
** ****** * **** *** **** * * *** ** * * ** * ** * ** * ** *
** * * **** * * *
** * ***** ***** ** **** * = number1 / gcd(number1, number2);
** ** * * * *** *** * * ** = number2 / * ** number2);
** ***** * ** ***** *
* * ***** * *** * ***
*** *** * * * *** * * ( * ** **
** ** ** **** * * ** * ** ** * ** * * newNumber1);
******** **** ** ** ** ***
** * *** * *
* ***** *** *** **** * ** * * ** ***** * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*** *** **** * * a,b,c,d,e,f;
* ** * ** ** *** * * * * * ** ** * * ** ** *** *
* * **** * ** ** * ***
** *** * ** * ** ** * **
* * * * * *** * *****
    {
* ** ** ** **** *** * * * ** * * * ** *
* ** ** * * ** **** * *** *** ******* * * * *
*** ** * **** *** * ** * *** ****** ** ***
    }
** ***** ** * ****** * *
    {
* * * * * * * **** * *** * *** * * ***
* * ** ** ** * ** * * *** **** * ** ** * ** ** *** **** * ***
* * * ** * ** **** ** * ***** * * * *** *
* ** * * * *** * ** ****** * ** *** * *** **** *** * * *
    }
*** **** ***** * *****
    {
** *** ** * * * * * ** **** * * * * *
** * * * * *** * ** ** * * * ** * ***** ** * ** *** * *
* * * * *** * ** * ** * * * * * * *
* ****** ** ******** * *** *** ** * ** **** ******** ** * * * ** ** *
    }
** *** * *** ** * * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.65
©2016-2026

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 15.7k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 15.6k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 20.5k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 15.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users