11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
16.7k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 16.7k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

* **** * *****   ****   ** * i;
  * *  ***  *  * *  *    **** j;
  *   * ** *    ********   *** * newNum1;
**  *** **** *****   **  * **   newNum2;
* *  **  ****   *** ***      gcd;
* *** *** * ******  *  *  *  rem;
 **** ** * ** ******   *** *  num1, num2;

   * ** *****   *** ** ** **  ** ***    ***** *   * **  * *    ***  **

******** **     * ****** **
 * * **    *  * ***    ****** *

**      * *** **  * ***       **  * != 0)
  ** *    *   * *  * * *   
 * ** ***  *   * ***  ** **  *** * *** *  **     *  ** * = j%i;
 * *   *** *  * *  * *    *  *    * * ***      **  ***  = i;
  * ** **     *    * * **    *  *  * * ** *  * * ** = rem;
 *  *   **** ***** ** ** ** *
*     **     **  *   *** * **

  ** * ** ** ***** ******  * * ***  = num1/gcd;
   ** * **   ***** *  *****   ** * = num2/gcd;

**  **  **** *  ** *  ******     * == 1)
    {
*** **** * ** **  *** *  *    * * * **    *   * * *  **   * * *  ******* *    **
    }

 ** * * **  **  * *  * *  
    {
********** * ****  * ** *   **    ** *  *   * **  * * *  ****    *  ** ***  ** * **   ** 
* *  * **  *** *  *** ****  *

 ***        * * **  **  *  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** **   **  * *  **** *     *   **   * *     ***  *** * *  * *  ****

*      *   ** **   *     **  *  *
     ** ** *   **   * *  * ***   * **   *    ***  ** *        **** *     **  *  *

    else{
  *** * ** ** ** ***  ** ** *  * *** **** 
    {
  ***   *  *** *   *** * * * * *  ** ** *    
* * *   *        *   *****     *    *   *   ** *  * * *** *  ** *     * ******    ** ***   && deno%i==0)
**  * ***  *** ** **  ***** **** ** * ****  ***** *** * ** ** * *** *  * ***
******   * * ***** ***    **  **  * *  ******* *   *    * * *  * * *** *  ** ***    **   **  ********
  *  * ** * ****  *  **  *  * ***  **    *  *     ** * ***  * ***** *  ** ** * * *  ***** ****  * **** 
  *   *  *** *   *** * **    ***  *  *** ***   *  *   ******* **  * ** **** * * *    *
    }

   ** *     **  ***** * *    *  * **  **
    {
*   *  *    **   ******    *** ******   **
     **        ** ***  **  * **   * *  * ***  * *  *  * * ** *   *  **  *  ** * *  **   * ** && deno%i==0)
** * ****  *** ** *** * *  *  *** * * *   *  *****  ** **  * *  *  *  * * ** 
 *   * *        * **** ** **  ** * *   * * * *  *** * *  **  * ***  * *******    **    *** * * * **** ** 
****  **  **    **** *** **  ***  ***   ****** ***    * ** **   **  * **  ** **  *  *  * **  * * *   
 *     * *   * * ** ** ****  ****  * *  **** *   *     * **     **** *** **     * 
    }
    *    *  **   *  ***  ***    * ***  * *   * * *

    }




  ***   *   *   **** ***  **  * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * **  **  *** *   
#include *  *** * * *

int gcd(int n, int m)
{
**   *   **** *** * ** *** ** gcd, remainder;

       **  ****   *** * *  ***** (n != 0)
  ** ** * * * **** * ** * * **
*   * *      *  *   * *  * ** * **  *****  *          *  *** = m % n;
******* ***  *    *  *  ***      * *   * ******   ** = n;
* *   ***** ** ** * ** **    **  * *  *  *   *** *   * = remainder;
**** * *    *** *    *   *

 *** **       * **    * * * **   = m;

  **** **   * * * ***    *******  * gcd;
}

int main (int argc, const char * argv[]) {

  ** ******    **** ** * ***** * number1, number2;
 * *    **  *  **  *  * *    * newNumber1, newNumber2;

     * *  ** *** * ** * *      **   ****   * ******  * *  * * *  ***  ****  * * *

**      * * ***     ***   ****  * = number1 / *** * * *  number2);
****** ***** **     **   **** = number2 /    **  * number2);

 * ** **** * *****    ** * ** **** ** * **   **  *  **
* ***   *   ** * * ****      *  ****  *  *   ** * **       ** ** **    
** *    * * *  *    **      *  
* ** **   *****     ***   *   * *   *  * *  *    * **  * *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  ****   * ** **  **    *
** *  *   *    **  *  

int ****  n, int m)
{
*** ** *  ***  * int gcd, **    

*** **   *  * ** *  ** (n != 0)
* *** ***  * {
* ** *  *     *     **  **      * = m % n;
*** * *    *  *  *    **   * m = n;
** ** ***       * *     **   *  n =  **   *  
*  *** ** ***  * }

    *  *  *** *      gcd = m;

 * * **   ** ** ** **** gcd;
}

int main (int  **    char *  *** {

*      *       int * *     *  * *
  ***** * ** * int ***** * * *** *

***  *       * *   * * ***      ****  *   ***  *  ***    * **** *

****  ** ***      * = *** * / * ***  ****      ** 
 ** * *    * **  ****  = * *** / *    * *  **

*****   * *  ** if ****  **   ** *  *     *
*   **      *       ** * * ****  *     * **    *       *
**  *  ***  **   else
 ***   **   * * **  **  *  **  *   * *  **  ****    ** *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 *** * *********** ***  **     * i;
 * *      ** * *    **** ** j;
** *** * *****  **     **    * *  newNum1;
 *      ** * ** *** * *       newNum2;
 ***  *** * *********       ** gcd;
* *** ** ***  ** *  **      * rem;
 *    * *******  *  *  *  *  *** num1, num2;
    
** ** ** *** *  *** ** *   ***    **    *   ****  *   **  * * *  
*  * * ***  ***** * *   **  **
 * *  *  ** **   *  * *   * **** *     
**  **  ** **   **        *
 **  ***    *****  * * * ** 
  * *  * ***  *   *   *   != 0)
 *   * *** ** *** *********
**     **  *** **      *  ** *     **  ** * **  **  **  * = j%i;
 * *  * ** **  ** ***  *   * *   *  *** **    *       = i;
*   * *  **  ** *     * **** *** *** *   **** ** *      * **  = rem;
*  * * **** *     ** **** **
 **** *  ***  *  *    
    
*    ** *    *  *   *** * *** **    = num1/gcd;
*  ******** **  *   * ** ** ** ** * = num2/gcd;
    
 * *** * *  * **   ****   *** ****** == 1)
**     * *    ** ****  
 **** * * ***      ** * *     * *   *** *  * **      **  **   ** **  *****   * **
 ***   **   ** *  ***  *    *
    
  **    **   ** * ***** *
****  ****    * * *  * *  *
  ****** **  *     * *** **    **   *** *  ***  **  ** * **   * *** ** **  **   ******  **
 **    ****       * * *      
    
    ** *       ***   ** ** *   0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
** ** ****   * *** ****  * * * i;
*  **     **** ** ** *      * *  j;
****  * *** *  *      **   **   newNum1;
 ** *  ** **  *****  ** **** *   newNum2;
 * ** * ** * * *  *   **     **  * gcd;
*  * * ***     ** * *     *  rem;
    ** ***** * * *       **** * num1, num2;
    
**  *   *   ** * *** ** **  ** *     *  *****   ** ***** ***    ****  *    
**  ****  *      *     *
* ****   ***   **** **    * ** 
 ***  *  ***  ** * **** **** 
 * * *    *  *  * *   * **
 *******  *  * *  * *****  *** != 0)
*       ** * *    ** *  * **
  ****   *** ** *  ****** **   *  ** *  **    *  *  ** **  = j%i;
 **** * **  * * * ***     *   * *  * ****** **** **    = i;
***  * *  **  ******** ****** ***  **  * *** **  ** = rem;
   * *******  *  ** ****  
* *  *** * * ***   * * *   *
    
**** ***     ***   *** **   **  * = num1/gcd;
**      *** * **    *    **      = num2/gcd;
    
  * **  * * * * *     ****  *  * *  *  * == 1)
***   *  *** **  *  ** * ***  
  * *  * ***   *  ** *** *      *  * *  *  *   ***  *    * *    *** *     * *  
  **  * * * **  **  *****  
    
 ** ****   ** * *  * ** *** ** * *
   *  ***   *  **  * 
   **  * ** *   *    * **  ****   *** * **  * *  *  **  *** *  * * ** **  **         ** ***
** ** *  ***  *  ***    *  
    
  ** * *  *  ****** ****     0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
*    ***  * ** ***     ***   * ** ** * ** ***    ****   * * **
 **  * * ** * *   * *   *  **** * *****  *  *   *** *** *   * *
    {
      *   ********   *      * *** **  *   ** *** ***   * *      *
* *    ** **** ** ****  *     *   *   ***    * ** ***    * 
* *   * * * * *** ****  ** **   *** **
 * ** ** **    *** *** **  ** *    * ** ***
  ** *    ***** **  ***     ***     ****    ***    **

  *   * * **      **** ***** 
*** *** ** ***   *  **     * *****  * ****  **  * **   ****** **  * *  * ****  *    ***        *****
*** * * * * ***   * * *   ***    ** ** *  *  **** ** * ** *   *  * ** ***


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
 **   *   * *         * **   a,b,GCD;
 * * * **   *  **   **** ******* * **    * *** ****** *** *****
 *  *** ** *    * ****    *    *** ** 
   **  * *  ***** **  * *  * 
** *  *     ** ** **   ***   * **  * *** ****    *** ** *** *   *   *** ***  *
  **** ** ** *** ***    * *
 *  *  * *  * *** *      **    *    * **  ** **   *** ****  *     **  * *      
 *  * ** *   *   ***       **** 0;
}
 *  *  **** *   **   * *  ***  gcd(int a, int b){
 *  ***  * * *   **** * ***  ***    *    * ** **   *   *  *   (!b) return (a);
 *** * **   ******** *  **** *  *   **** ** *  * *******  * gcd(b, a % b);
* * *** *   ** **  *     **   *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ***     *   
#include  * *      

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
  * *  *** * *      *  *  *** ** * gcd, remainder;
   *  * *****     *  * *****
   *  * * * * ** **  * ** ** (n != 0)
  * *********** * *  *   *  *
   **  ** *** * ** ***  **  ** * **** ** ** ***  * * * **** * *** *  * = m % n;
**  * *   *   ***   ** *****  **  *   ******  * * = n;
***** ** *** *** *    ***  *  **  ** *   * * *  * ***  *** = remainder;
 *   * **  * *  *****   *    *
  * * * **  *    *   ** *  
   *  **  * * *  * ** *  ****  **  = m;
***    ******   *       
** ***   *  **  *********  *  * gcd;
}
int main (int argc, const char * argv[]) {
*  *** *     * *     ** ** * ** number1, number2;
    *   **   *****    ** *** *** newNumber1, newNumber2;
*     *** *****    *  *** *
     *****  ** * * **** *
 **  *  *  *** ***  *  ** ** *** *********** *  **    *   ** *** **  **** * **  *
 **  ***** ********** *** ***** 
  ** *   **   * *  * * *   = number1 / gcd(number1, number2);
** ** **     ******  * ** ** *  *  = number2 /   **  * number2);
****   ****  *        ** **
**  **  **       *    **  **** 
***   * *  ** **  *  * *  **  (  **  ** 
 * * *  *** * **** *     *** *  *    ***  *  *   ***   *  *  *  * *  newNumber1);
*** ** * *    **  ** ** *
** *  *   ********** ** 
  *** *    ** **  * **  * *   * **** *   * *** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
**  * ** ****  ** *  **  * * a,b,c,d,e,f;
 ** *     ***          *  **  *  * *****   **     ****  * ** *  
***** * ** *  ***    ** **    *
***  *  ** ***  *** ** * *     ***
   ** ** *   * ***   ***  ** ******  
    {
 ***    *  *  **** * **   *  ** ** **  *     **  * ** * *  **
**  *      * * *      ** * *    *  *   *     ** * *  * ** ***
** * * **   *     **    * *   **** *   ******* *     
    }
*  *   *** * *** *** **** ******      *   **
    {
*** *     *  ***** *   * *** * ** *   *****  *    *
*  *   ********  *   **  *     ** * ****    ***   ****   ****   ***  *** *     *
* *****  *   *  * ***   *  *** ** ***  *  *    ** * * * ***  * 
  ***    ** **** * * * *   ***     ** **  **  *     *   *   ***  **** ***
    }
**  *  * ** *** * ***   * * 
    {
** ***** **** **  **     ***** *   * ** * ** *     **   **  
* * ** **       ***** ** **    * ****** *** *   *** *  * * ** * ******* *  * * *
****  *   *   *   **   ***      * ******    * * **   **** 
    * ****  ***  * ** **** ** **  * * ***     **  **    ** * * *  **** ** 
    }
*  **   ** **** *  ****  *  0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.10
©2016-2026

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 16.9k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 16.6k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 22k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 16.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users