2 like 0 dislike
13.5k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 13.5k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* * * * **** * * * i;
* * * * * ** *** * ** *** j;
* **** * ** * ** newNum1;
*** *** ****** ** * * newNum2;
** *** * ** *** gcd;
* **** * * * * rem;
**** *** * *** **** * * num1, num2;

**** * **** ** ** ** ** ** * * * * * ** * * * *

***** * * ** * * * ** * **
* ** * * ** * ***** *

* **** ***** * * *** ** * * != 0)
* * * * * **** *** * ** *
** ** ** * * *** * ***** ****** * * ** = j%i;
*** ** * **** * *** * *** *** * * *** * *** = i;
***** ** ** ** * ** ** * * *** * ** * ** = rem;
** ** * * * * * ** *
* ** *** * **** ** *********

* * *** * ***** * *** ** * = num1/gcd;
** *** ** *** *** * * ** ** = num2/gcd;

*** * ******** * * ** * * * * **** == 1)
    {
** * *** ** * *** * ****** * *** * * * * * ** *** * * ** * *** * *
    }

**** ** ** *** * **** * *
    {
** ***** * * ** ***** * ** * * *** ** ********** * * ****** * *** ** *
* * * * *** *** **

** * * ** *** **** * *** ** ** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** * ** *** *** * * * *** *** * ** * * * ** * * ***

** ****** * ** ***
* * ** ** * * * *** * * * * ** * ** * * * ***** *

    else{
**** * * * * * ** ** ** ** **
    {
*** * * * ** * * * ** *** *** ** * *
** *** * * *** * * *** * * ** * * ***** **** ** * **** ** ** && deno%i==0)
** * * ** * ** *** * ** * ** *** * * **** * * * *** **** * * * ****
* * * **** ** ** ** ** * *** *** ** * ** * ** * * ** *** * ** ** * * * ** *
** ** * * * * * * ******* **** * ************ * ** **** * ** ** ** * * *** *** *
* ** **** **** * **** * * * * ***** ** ** ****** * * * * ** ****** ** **
    }

*** **** ** ** * * ** **** ** *
    {
* **** * * * ** *** ** ** * ***
* ** * ** ** ** **** ** * * *** ** * * ** * ***** * * * * *** * * && deno%i==0)
* *** * * * ***** ** * * * ******** ***** ** ** **** ** ** * *
* ** * * * ** * * * * ** ** * * ******* * * * ** *** * * * ** * * ***
* * *** * * * ** ** ** * * * * ** ** *** * * * **** * * * * ** ** **** ****** *
* *** * * ** * * ** **** * ** ** *** * **** * * * * *** * ** **
    }
* * *** * ** ** **** ** * **** *** *** * * ** **

    }




** * * **** * * * **** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** * * ****** **
#include ****** **

int gcd(int n, int m)
{
* ****** *** * * * **** gcd, remainder;

** * * *** * ** * (n != 0)
** * ** *** * ** *
* * * * *** * **** * * ** * ** * * * * ****** = m % n;
** ** ** * *** * **** *** ***** * * = n;
* * * ** * * **** ** ** * *** ** ** * * = remainder;
** ** ** ** **** * * * **

** ** * * ** **** = m;

*** * *** * **** **** gcd;
}

int main (int argc, const char * argv[]) {

* * ********* **** * * number1, number2;
**** *** *** * * newNumber1, newNumber2;

* *** ** * * ** * * * * * ** ** ** ** *** ** * * **

* * *** ** ***** * **** ** = number1 / * ** * number2);
*** * *** * ** * *** * * * = number2 / *** ** * number2);

* ** * * * ** *** * * ** ** * * * * * * **
** * *** *** ** **** * * * * * * * * ** * * **** ***
* ** ** * * * ** ** *
* ***** ** ** ***** ** ** * * * * * *** ** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
**** ** ** * ***
* * * * * ** * ****

int * * n, int m)
{
* * * int gcd, ** *

** * * ** (n != 0)
**** * * ** * * {
* * ** ***** * *** * *** * = m % n;
* * * ** * ** m = n;
** * * *** **** * * * n = * *
** * * }

** * *** ** * gcd = m;

** * * *** **** gcd;
}

int main (int * char * {

* * *** ** int * * **
* ***** ** * * int ** * * ** *

** * * * *** * ***** ** * ** ** * ** * *

** * * * ** *** = ** / ** ** *
*** * *** ** = * * / * ***** *****

******* * * if *** ** * * **
*** * ** ** * * * * * * * **** * * ** *
*** * * else
**** * ** * ** * **** ***** **** ** * * * *******
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ** ** * * * *** ** i;
*** * ** * *** **** ** * j;
**** *** ** * ** ** ********* newNum1;
* *** ** ** newNum2;
******** * * ** * * * * * ** gcd;
* ****** *** ** rem;
* *** ** * * ** * num1, num2;
    
** ** ** ** ** * * *** * * ***** ** *
** ** ** * *** ******* *
* *** ** * * *** * * ***** **
* *** * * * ****** *** *
* * *** ** ** * * * *
* * * ** ** ** ** ** ** != 0)
**** ** * * * *
** ** * ** *** * * * * * * ** * * = j%i;
** * * ***** ** * * *** ** ** * * * ** **** = i;
** ** * * ** ** ** *** ** ** * * * *** * = rem;
** * * * * ** *** ** ****
*** *** *** * ** * * ** **
    
***** ** ** * ****** ** = num1/gcd;
* * ** * ** * ** * * ** = num2/gcd;
    
** * **** * ** *** *** * * * == 1)
* * * * * * * *
*** * ***** * *** *** * * * * * * * **** * * *** * *** ** *
** ** **** * ** ***
    
* ** * * ** ** ** ** *
* **** ***** * * * **
* * **** ** ** * **** * * *** **** * * ** ** * ** * ** * * **** ***
* * * *** * ** **
    
** ***** ** ****** ***** * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ** ** * * * ***** ** i;
* * *** * * *** ** *** j;
*** * *** ** ** ** newNum1;
** ** * *** ** * * ** ** newNum2;
* ** ** * ** ** *** * * ** ** gcd;
** * * * ** * * * * rem;
*** ***** *** num1, num2;
    
* * * **** * *** ** ***** * ** * ** * ** ** * * *
* ** ** * ** *** *
** ***** * * **
*** *** ** ***** * *** **** *
*** * **** **** *** *** * **
* ** **** * * *** * * ** * != 0)
* *** **** * * * **
* ** ***** **** ** ** *** * ** * * ** * * * = j%i;
* **** ****** * * * **** **** * ****** * * * = i;
** * *** ****** * * * * * ** * ** ** ** = rem;
** ** * * *** ** * * * *
* * * * ** ** * ** * * *
    
*** * ** **** *** * = num1/gcd;
**** * * ** * * * = num2/gcd;
    
*** * * *** *** * * *** * == 1)
** * ** * * ** ** *
* * *** *** **** * * * * * ** *** * * * ** * ** * * **** * *****
** ** ** * ** *** **
    
*** *** *** *** ** ** * **
* ** *** ** ** ***
* *** * ** **** * * ***** * *** ** * * * ** *** * ** ** * * * **** **
**** * ** **** * *
    
**** ** * * * * * * ** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* * **** ** ** *** * ** * * * **** ** * * ******
* * ****** * * * **** * **** * ** **
    {
****** ** * * * ** *** ** * * **** ** *** **** * ** *
** ***** **** * ** * * * * * *** * ** ***** * *
** * ******* *** **** * *** **** *
* **** *** * *** * * *** * * * *
* ** * ** ** ** * ** ** * * ** *** **

* ***** ** * ** * ** *****
** * **** ** ** * * * * * ** * * **** *** * ** * *** ** *** * ** * * ** **** ***** *
*** ** * *** ** ** ** ** * * * * * * ****** ** ** ** * *** ***


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* ******** *** ***** * * a,b,GCD;
***** ***** * * * **** *** *** * * ** * * *** * ** **
* ***** ** * * *** * *** ****
*** *** ** **** * ***** * ***
** *** ** ***** * *** * ** *** ** ** * * * * * * ** * * * **
** ** *** * *** * ****
* ** ** ***** ** * ***** ** ** **** * ** * * * * * * * * * **
** ***** * ** * ** * * * ** 0;
}
* * *** ****** * * ** gcd(int a, int b){
* * **** * *** **** ** * * * * ** *** *** (!b) return (a);
* * * * **** *** * *** * * * ** * gcd(b, a % b);
** * *** * ** * * **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** **** *** * *
#include * *** * *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* ** ** * * *** * ***** * gcd, remainder;
* * *** * * * * *
** ***** ** *** ** * * * * (n != 0)
* ** ** * ** * ** * * ****
* * ** **** *** *** * ** * *** * ** * * ** = m % n;
** ** ** * * * ** ** * ** * * * ** *** ***** = n;
********** * **** * ** ** * **** * * * * * * ** * = remainder;
** * ** ** * *** *
* *** ** * * *** **** *
*** * * ** * ** * ** = m;
***** ** * **** ******
* * * *** * ** * * * gcd;
}
int main (int argc, const char * argv[]) {
*** * * * * * * ***** * number1, number2;
** ** * ** ******* newNumber1, newNumber2;
* ** * **** ** *
* ** ** *** **
* **** * ** **** * * *** * *** ** ** * *** * ** *** ****
** * * * *** * *****
** * *** * * ** ** *** ** = number1 / gcd(number1, number2);
* * * * * ** ** *** * ** = number2 / * * ** number2);
*********** * * ** * *
** * * ** **** *** * **** *
** ** **** * * *** * * * ( * *
* * * *** * * * * * ** * *** ** ** * * *** ** * *** newNumber1);
* *** ** *** ** * ****** *
** * * ** * *** *** ** **
* ******* ** **** * ***** * * ** * *** * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** ***** ******* ** * a,b,c,d,e,f;
** *** * **** * ****** ******** *** * * ***
** *** **** ** * * ** **
*** *** ********** **** * *** *
*** *** ** * * ** ** * * *** * ***
    {
* ** ** *** * ** * ** ** *** * ** * ******* ***
** ***** ***** * *** ** ** * * * * ***
*** *** * * ****** *** ** * **** * * ** *
    }
* * *** * * ** ** * **
    {
* * **** * * ** * ***** * * *
** * * * * ** * * *** * * ** * * ***** ** **** * * * ** * ** ** *** ***
*** * * ** **** ** ** ** ** * * * * * ** ** **
** * * ** ******* *** * * * *** * ** ** ** * *** ***
    }
********** ** **** * **
    {
** ** * ** ** * * ** *** * * *** * ** *** *
* **** * ** * **** * * * *** *** **** **** **** * * * * ** * *
** * ***** * *** * * ** **** **** **
*** ** * *** **** * ** * *** ** * * * * * * * * * * * **
    }
** *** * ** ** * * ** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.203
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 13.9k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 13.7k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 17.4k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 13.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users