2 like 0 dislike
9.7k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 9.7k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* * **** ** * ** * ** i;
* * * * * ** *** *** j;
** * ***** *** *** newNum1;
**** * ***** *** ** * * newNum2;
** *** **** *** * *** * * ** gcd;
* ** ** ** ** ** rem;
*** ** ** ** ** ** num1, num2;

* * * ***** * * * * * * ** * ** * * **** * * ** ** * ***

* ** ** ** * ** *** * ** * *
* * *** *** *** **** *

***** ** * ********** * * != 0)
* ** * * *** * ****** *
* ***** ** *** ** * *** *** *** *** * * * * * = j%i;
* *** * * * ** *** * **** **** * * ** **** * ** = i;
* *** * * * * ***** **** *** ****** ** ** = rem;
** * * ** **** * ** *
** * * * * ** ** * *

**** ** * * * ** * * ** = num1/gcd;
* * ***** * *** * * *** = num2/gcd;

** * ** ** * **** *** == 1)
    {
* * **** ** * * * ***** ** * * ** * * * * ** * * * * * * ** * * *
    }

** ** * * ** * *** * * ** **
    {
* ***** * *** * * **** ****** * * * *** ** **** * ** * * ** ***
*** * * * *

* * ***** ***** ** * ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * ** ** * ** * * * * * * * *** ** * **

* *** * ** ***** * *** *
** *** * * ** **** * * *** * * * **** * * * **** * * * * * * * *

    else{
** * * ** * * * ****** *** **
    {
* ** *** *** * * * ** *** * * *** **
** ** ** ** * *** ***** ** * * * ** * * *** * ***** * ** * *** * * ** * && deno%i==0)
* ** * *** ***** * ** ** * ** ****** * * ** * * ** * ** ** **
* * * * * *** * ***** * ** * * ** * * * * ** **** ** ** * ***** ******* ** * * * ** *
* ** * * * * * **** **** ** * * * ** * * * **** ** ** ** * * * ** * *******
* * * * * ** * * * * * * * * ** * * ***** * ** ***** * ** * * * *
    }

** ** ******* ** *
    {
** ** * ***** ** * * ** * *** *
** ** ** * * * ** ** ** **** ** *** ***** * * * ** * * * && deno%i==0)
*** *** * * *** ** * ** ** * ** * *** ** **** ** * * *** *
* ** * * ** *********** ** * ** ** * * ** * * * * ** *** *** **** ** * * * * ** * *
** **** ** * * * ** ** **** ** * ** *** *** * ****** ** ** * *** *** * **** *
*** * *** * * *** * **** *** ** ** *** *** * ** * ** ** *
    }
*** * ** * * ******* ** * ** * * ** ** * * *

    }




* * * ** * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * **** *
#include * *** * *** ****

int gcd(int n, int m)
{
* * *** ** * *** ** * gcd, remainder;

* * **** ** * * *** *** ***** * (n != 0)
* ***** ****** * * * *
* * * * ** * * * ** ** *** * **** ***** = m % n;
* * * ** ** ** ** ** * * ******* * ** * = n;
** *** **** * *** * **** ** * ** ** *** **** = remainder;
*** * * *** * * *

** *** ***** * * * = m;

**** * * * *** * ** ** * * * gcd;
}

int main (int argc, const char * argv[]) {

** ** ****** **** number1, number2;
* * ** * ***** * * ** newNumber1, newNumber2;

* ** ***** ** ****** *** * *** * ** * **** ** * * ***

* ******* * * * *** * = number1 / *** * number2);
**** * *** * **** * **** * *** = number2 / * * * * number2);

* ***** ********* * * * * ** * **** *
** ** ** * ** * ** ** **** ** * * * ** * **** * **
*** *** * ***** **** * *
*** * * *** * * * *** ** * *** **** ** ** * *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * ** ** **** *
* ** * ** * ** *

int ** * n, int m)
{
* * * * int gcd, * * *

* ** **** ** * (n != 0)
*** * * * * * {
******* ** * * * * ** * * *** = m % n;
**** * * * * *** *** m = n;
* * ** * * * n = * ** **
*** * * * *** }

** * * * gcd = m;

* ** * ** gcd;
}

int main (int * **** char * *** {

* * * * int * * *
* * * * int * * *** *

** ** * * ** ** * **** * * * * ** * **** * *

**** * * ** * * = *** / *
* **** **** * * * * = * / * * ** * ***

** * ** *** if ** ** * * *
** * * ** * ** ** *** ** * ***
* ** ** else
** * * ** ** * ** * * * * * * ***** * * **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** * * ** * ** ****** * * i;
** ** *** ** ** * ** j;
* * * ***** **** * newNum1;
**** ** * * ** **** * * newNum2;
**** *** * * ** ***** gcd;
**** ** *** *** ** * * rem;
***** *** *** * * ** num1, num2;
    
* ** * * *** *** * * **** * * * * * ***
** * * ** **** *
* * ** *** * ** *** *** **
**** **** ** * * * *
* ** * ** ** * ****
** * * ***** ** ** * * * != 0)
**** * * *** * *** *
** * ** ** * * * * * * * *** **** * * = j%i;
* * ****** * * *** ** *** * * * ** = i;
** ** ** * ******* * *** ** * ** * ** = rem;
* * * * * *** *** **
** * *** * * * * * ** *
    
* *** **** * ** * * * * = num1/gcd;
* * * * * **** * * *** = num2/gcd;
    
* * * * *** ** ** *** * * **** == 1)
* *** ** ** *******
** * * ** ** **** *** * ** **** ** * ** * ***** * ***** ***
* * * ** * * ** * *
    
* * *** *** * ** ** *
** ** * * *** * * ***** ***
*** ** *** * *** * ** * * * *** * ** * ** * ** **** *
**** ** * **
    
** * ** * ** * ** * * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
*** ** * ** ***** ** i;
*** * * * **** * ** *** ** * j;
* ** **** * * *** newNum1;
****** *** **** * * newNum2;
** * * * ** * ****** gcd;
*** *** **** **** * rem;
** ******** *** *** ** num1, num2;
    
** * ** ** * * ** ** ** * *** * * **** ***** ** *
** **** * * ** *
* **** ** ** * *
* * *** * * * * **** **
* **** * ** * **
* ** * ****** * * * * *** != 0)
* ** ** ** * * **
* *** ***** * * ** ** ** * *** *** * ** = j%i;
* * ***** ** * **** **** **** ** * **** ***** = i;
** * ** * * ** *** * ** * * *** * * = rem;
******* * * *** * * *
* **** * ****** * ** * *** *
    
*** * *** ****** ** ****** * * = num1/gcd;
* * * * * ** * **** ** **** = num2/gcd;
    
**** * * **** ***** *** == 1)
** * * * **** ** *** * **
* * ** * * * * ** * * ***** ** ** * * ** * * * *****
******** *** * * * **
    
*** * ** *** ** ** *
** * *** ** ** **** * * * **
* * * * **** * ** * * ** ** ** * * * * * * *** * * * * * ** * ****** *** *
******* * * ** * ***
    
*** ** ** * * * * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** * * * * ***** **** * ** * * ** * ** * ** ** * * * ***
* * ** ** **** * * * * ** * * * * *** ** * * * * **
    {
* *** * * ** * * * ** ** * * * * *** ** * **** ** ** * *
**** **** ******* ** * *** * * * ** * * ** * ******
* ** * ******* * *** ** ** ** ** ****
** ** * ** ** * * ******* * ***
*** * ** ***** *** ** * * * * ** ***

***** * * * * ** * ** *
** ** *** *** ** *** * ******* ** * ** *** ** * ** * * ** ** *** ** * ***
*** *** *** *** * * * *** * * **** * ** * ** ** * * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* * * ***** ** ** **** a,b,GCD;
* * ** ***** ** ** ******* ** **** *** ** * * *
*** *** ** * *** ***** * * *
* ** ** * ** ********* * * *
* * * *** * * ** ** * **** * ** * * * ** * ** * * *
* ****** *** * ** ******* *
** ** * * * *** * * * * * ******* *** *** ** * *** *
* ** * ** ***** ***** * 0;
}
* * * * ****** * gcd(int a, int b){
* * ** *** ** * ***** ** * *** * * * * ***** *** (!b) return (a);
* ******* ** **** * * ** * ***** ** * * *** * * gcd(b, a % b);
**** * * * * *****
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * **** * *
#include ** * *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
*** ** *** *** * gcd, remainder;
** * * ** ** *** * **
*** ** * * ** * * ** * (n != 0)
* ********** * ** * *
* * ** * ** * * *** *** *** * *** ** = m % n;
** ** ** * ***** * *** ** * * * * * * ** *** ** = n;
** * * ** ** ** * ** *** * * **** *** * * * = remainder;
** ** **** * **** ** *
* **** * ** ** * **
* ** * **** * ** * * * = m;
** * **** ** **** **
******* * * * **** * * gcd;
}
int main (int argc, const char * argv[]) {
** *** * *** *** ** * ** number1, number2;
**** * *** ** * * ** ** * newNumber1, newNumber2;
** ** *** * **** ******
* * * *** ** * **
* * *** ** * * * * * * ** * ** * * * * * *** * ******
* * ** * * * * ** ** **
*** * ** * * *** * ** = number1 / gcd(number1, number2);
**** ** ***** *** * **** ** * = number2 / *** * number2);
** * * *****
** ** * ***** **** ** * *
* ** * * * * ** * *** ( * **** ***
***** ** *** * * * * * ** **** * ** ** ** * *** ** ****** newNumber1);
* * * ** * ** ***
* * * * ** * **
*** ***** * ** ** * * ***** *** * **** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** * ***** ** * * * ** ** * a,b,c,d,e,f;
* *** **** * * * ****** * *** **** * * ** *** * * *
* * ** ** * ** *** * *
* ** * * * * ** *** *
* *** *** * *** *** ***** *
    {
** * *** * * ******* ** * ** * * * * *** * ** ** * *
* ** * * ** * ** ** ** * * ***** *** * **** *
* ** ** * * * * ** * * ***** **** * * * ***** * **
    }
* ** ** * * * * * * ** **
    {
* *** **** ** * * * * ** * ** ***
*** **** *** *** * ****** *** ** ** * ****** ** * * **
* * * * * * **** * * ** * ** * ***
** ** * * * * ** * * * ***** * * * ** * * **** *** *
    }
**** ** ** *** ** *** *** * *
    {
* * * * *** ** * ******** ** ** * * *** *** *
*** *** * * * *** ***** **** ** ** ** **** * ** * * * *** ** ***** *
* * **** ** *** ** * ***** *
* * ** * * ** ** * ** ***** ** * ***** ** * **** * * * * ** * ** * * *
    }
** *** ** * ***** ***** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.200
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 9.7k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 9.5k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 12k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 9.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users