2 like 0 dislike
12.8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 12.8k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

** ** * ** ***** ***** i;
**** ***** ** *** * *** * j;
* * ** ** * * * ** newNum1;
** ** *** ** * * ** newNum2;
** *** * * * ** * *** ** gcd;
*** * ** *** * * ** rem;
** * ** ** ** * * * * * num1, num2;

** ** * **** ** ***** * * ** **** * * ****** ** ** * * * * **

** * * **** * * ****
** ** ** ** * * * ** * * ***** *

** * * ************ * ** * != 0)
* ** ** ** ** * * * * *
* * * * * * * ***** *** *** * *** * * ** * * = j%i;
* ** * *** * * * * * * * ** * *** ** = i;
****** ** *** * * * ** * ** * ** ***** * * = rem;
* ** * *** ** **** ***
* * * ** * * * * ***

* * * * ** *** * ** = num1/gcd;
* * ***** * * ** ** * * = num2/gcd;

* ** * ** ** * * * * == 1)
    {
** *** * * * * ** *** *** * * * ***** **** * ** * * ** * ** * *
    }

* ***** * *
    {
*** *** * * *** * * * ***** * *** **** * ** ***** ** *** *** *******
* *** ***** *

* * * *** ** * * ******** * * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** * * **** ** * ** ** *** * ** * *** ** ** * * **

* * * * ** * ** ***** * ****
** * * * ** * *** *** ** ** * ** * * * ** ******* ****

    else{
** ** ** **** * *** ***
    {
* * **** **** *** ** *** ** * ** *
* ** *** * * *** ** * * *** * * ** ** ** *** ** ***** ** ** * **** * && deno%i==0)
* * * **** ** *** ** ** ** * * ** ** *** * **** * * *** ** *
* * *** * * *** *********** **** ** ** ** ****** *** ** * * ** * * **** ** ** * *
** * ** * * ** ** *** **** * **** * *** ** ** * ***** * * *** * * ** * * * * ** * **
* * ******* * * *** ** * **** *** * * *** *** ** ** ** *** *
    }

* ******* * * * * * * ** *
    {
* * **** ** * *** * * * * **** ** **
** **** * * * * * ** * ** ** ** ** * ** * * * ** ** * * ** * **** * * * && deno%i==0)
** ***** ***** * * * ***** ***** * ** * * *** ** * * * **** *
*** ** ** * * **** * * * * ** * * ** * **** * ** ** * *** * ** ** * * * * **
** * * * ** ** ** * * * ** * *** ****** * * * * * * * * *** ****** * ***** * ** *
*** ** *** * * * * ** ** *** ** ** * * * * * *
    }
* **** * * * *** ** * *** * * * * * * * *

    }




** ** * ** * ** * ** * * * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * * ***
#include ** *** **

int gcd(int n, int m)
{
* ** * * ** * * * gcd, remainder;

*** * * * * ** * * * ** * (n != 0)
* * ** *** * *
** * ** ****** * *** * ***** * * * * * ** ** ** = m % n;
* * ****** * * ** * *** ** * ** * * ** *** = n;
* * ** * * ** **** ** * *** *** ** * = remainder;
* * **** * **** * ** *

** ******** * = m;

* * ** * * * ** *** * ** gcd;
}

int main (int argc, const char * argv[]) {

*** ** **** * ***** * number1, number2;
* *** * **** * * ***** * newNumber1, newNumber2;

* * ** ** *** ** ** ** ** * *** ** ** * * *** ** * ** ** ***

* ** * * **** *** * *** * * **** = number1 / * number2);
* * ** ** * *** *** * = number2 / * number2);

* ** ** * **** ** * ** * ***** *
* * ** * *** * * * *** * * ** * *** * ** ***
* * * * * *** ** * * * *
* * ** ** **** *** ** *** *** * *** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * * * ** * ***
*** *** * **** *****

int * * n, int m)
{
* ** * ****** int gcd, *****

*** ** * (n != 0)
***** ** * * {
***** * *** ** * ***** * * ***** * ** = m % n;
** * ** ** ** * * *** m = n;
** * * * *** * n = **
* * *** }

** * gcd = m;

* *** ** * gcd;
}

int main (int ** * char * *** * {

** **** * * int * *** * *
* ** * * int *** * * ** *

* * *** *** * * * **** * * * * ** * ** **

* ** * ** = ** * / ** * * *
* * * *** * ** * * = ***** / * *** * ***

** * * * * if *** **** **** * *
* * * *** * * * * * ** **** * * *
* * * * **** * else
* ** **** ** ** * * ** *** ** * * * * * **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * ** ***** * * **** ** ** i;
*** **** *** * * * * * * j;
* * * * * ** * * ***** newNum1;
* *** ** ** ** * * newNum2;
*** * ** **** ** ** *** * gcd;
* * * ** ** * * * rem;
** * *** ** * * num1, num2;
    
* * **** ** *** *** * * ** * *** * ***** **** ** ***
* *** * ** **** *** ***
* * *** **** * * ** * * *** * **
** * ** **** *** * * *
** * * ** * * ***
* ** ***** * ** * *** != 0)
** ** ***** * **** ** *
* ** ** * * * **** ** * ** ****** * **** = j%i;
** * ***** ** ** * ** * * *** *** *** ** = i;
* ** ** * * * * * * * * ** ** ** *** * ** * = rem;
** *** * * * ** ****
* * ** * ** * ** * *****
    
* ****** * * * *** * **** = num1/gcd;
* ** * * * * *** ** * *** * = num2/gcd;
    
** ** * ** * ******* * **** == 1)
*** * *** ** * ** ***
*** *** * ** * * ** * * ***** ** ** ****** ***** ** * *
* ** * * *** * * * **
    
**** * * ** * ** ****
* * * ***** * **** ** *
** * * ** ***** * * * ****** * *** * * * ** ** * * ************ * ** ** ** **
* * * * * *
    
* ** ** * ******* * ** ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** * ********** *** ** ** i;
* * *** * ** ** * j;
* *** * * * *** ** ** * newNum1;
*** *** * *** ** ** ** newNum2;
** * *** *** * * ** gcd;
** **** ** *** * **** ** * rem;
** ** ** * * **** * * ** ** num1, num2;
    
*** * * *** * ******* * ** * * ** *** ***** **** *
*** *** ** ** *
** ** * ***** ** * ***
* ** ** * * ****** * * **
** * * * * * ** *** **
* * ** * ** ** * * != 0)
** ******* ***
***** * * ** * * ***** ** * * ** *** * * **** = j%i;
**** * * * ** * ** * ** * * * * **** * * * *** * = i;
**** * * * ***** * * * ** *** ** * *** = rem;
* * ** * * * ** *
* ******* * * ** *** *
    
***** ** * * * * * ** ** = num1/gcd;
*** ****** ** * *** * = num2/gcd;
    
*** *** * * **** *** == 1)
* ** * **** * *** * ***
****** ** * *** * * ***** ** ** ** * * ** * * ** ***** * ** * ** **
***** *** * * * * **** *
    
*** * * ** ** **
*** * ** * * ** * ***
* ** ***** *** * * * * **** *** * * * ** ** * **** **** ** * ***** ******** **
* ** ** *** * * ** ***
    
* ** ****** * * * * *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* ** * ** * *** ** ** *** ** *** ***** * *** *
**** * * * *** *** * * * * *** *** * ** * *** * * *
    {
* * * ** * *** * ***** * * * *** * *** *** **** *
* * ** ** * ** *** * * * ****** ** ******** ***
* **** * * ***** * * ** *
** ** * *** ** * ** * * *** * * *
* * * *** ** ** * ** ** * * * *

** * ** * * * * * * * ** **
* ** * ** **** * ** **** *** * * * ** * * * * **** * ** *** ** * *** * *
* ** ****** * * ** ** * * * ** * *** ** * * ** * * * *** * * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
** ** ** * * ** * * a,b,GCD;
** * ****** * * * * * *** * * ** ********** * * ** *
* *** *** * * * *******
********* * * * * ** * * * *
*** ** * ** * *** * * *** ** * * ******* * * ** ***
**** ** *** * *** * * ** *
** *** ***** ** ** * ** * * * * * ******* ** * * * * ***
* * ** * **** ***** 0;
}
** * * * *** * * * gcd(int a, int b){
* * * * * ** *** *** * * * * ** ** ** ** * * * (!b) return (a);
** * * ** ** * ** ********* * * ********* *** ****** gcd(b, a % b);
**** * * * * * * **** * *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ***** ***
#include ** ** ** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
***** * ** * * ****** * * gcd, remainder;
** * ** * ***
** * ** * * * * ** * (n != 0)
* *** * * * * * ***** *
*** * * * * ****** * ** ***** ** * = m % n;
*** ** * * * * ** ** * * ** * * * * = n;
** ** * * * ** **** **** * * * ** * ** *** = remainder;
** ** * * ** ***** **
* ** * ** ** * *** * *
* * ** * * * * ***** * = m;
* ****** * *** * ** **
** *** * * * ***** ** ** gcd;
}
int main (int argc, const char * argv[]) {
** * * * *** ** ** ** number1, number2;
**** * ** * ** * ** * newNumber1, newNumber2;
* * ** ** **
**** * * * * ***
* * * *** ***** * **** ** *** ******** * ** * *** ** ** * * * ***** *
* * * * * **
* ** * *** * * = number1 / gcd(number1, number2);
***** * * ***** ***** **** = number2 / * ** number2);
* * ** * *** *
* ** ***** ** * * **
* * ** * *** ******** * * * ( ****
** * * * * * ** * * ** ******** *** * ******* ** ** newNumber1);
**** * * * * *** ** ** *
* **** *** * * * ** *
** * ****** *** * * ** * * * ***** ** * ****** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* ** *** ****** ** * a,b,c,d,e,f;
*** * *** ** *** * *** * * * * * *** ** *** *
* * * * * * *
* * * **** *** ** ** ** *
* * * * ***** ** * **** *** *
    {
* * * * * * ******* *** * *** *** * *
* * *** ** * ** * * ** *** ***** ******
* * ** ** * *** ***** * * * ** * *** * *
    }
** * * ** * * * ** * *
    {
* * *** * ** * **** **** *** * * ** *** *
*** ****** ****** *** *** * **** *** * * * * * ** * ** ***** ****
** ** **** * ** * *** ** * * **** * ** * **
* * * * ** * * * **** ** * ** *** * * * * ****** * * ******** *
    }
* * * ** * **** **
    {
**** ** ** * *** * *** * * * ** * **** * **
* ** *** **** ** * * ** * *** * * ** * ** *** ** ** * **** ***
** ******* * ** *** ****** ** ** *** **** *
* * * * * ** * *** * ** **** **** ** * * * ***** * * * * **
    }
***** ** * ** *** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.26
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 13.2k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 13.1k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 16.5k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 12.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users