11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
11.8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 11.8k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

** ** * * *  *  *    ****    * * i;
 * *    *    *   *  *    j;
   *     * *** *** **  *** * newNum1;
 ** **  * *   *  ***  * * **  * newNum2;
 ** * *  * *** **    *   * *** gcd;
   * **    * *     *  * rem;
*  *  *     * *   *  * *   num1, num2;

*  *  **** **  ** ***** *  * * *    * * * *  * **  *  **

* ***       ***    ** ***  *  *
***   * * *   * * *  *****  **

 ** ** *  *     * *  * ****** * != 0)
  *   * **** **   * * *** ***  
* * ****  * ** *  * ****** ** **** ***  ** **   ***   *  ***** = j%i;
* **** ***   * **   *  *  * *   **  ** * *   *   *    *      = i;
 * ***** *  * *** *  **   *  * ** * ****  *** *   *  ****  = rem;
 * ****    * * *  *** * *  * *
**  *  **** ** ** ***  *    ** **

    **  ** * *****     **   ***  = num1/gcd;
*   * *       * *****   *    = num2/gcd;

*  **** *******      **  ****** * *   *  == 1)
    {
      ** * *** * *  ** ******  * * **  *   **** **   * **  * *   *  * * **  ** **
    }

 *** ***  ** ****  *   **  ** *
    {
    * * ** **      **  * *** * ** ** * ***  * * *  **** * ** ***    *****  ***     * *
*   ***  ** *  *  *  ***     

 * * *  ***   *** *  ****  *****   * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
 ** *   * ** * ** ***** ******* ***  *      * *   *  *  ***  ** 

   * *  * **  *    *  **    **  * *  **
******* * *******  * *      * ****  *         *** **  ** ** ****** * ****** * ** ***  *

    else{
  *    *   ** **  * ***  *** ** *
    {
*   * **  ****  **  ** * **  **  * *** ** * ** *
 *  * **** * * * ** **  *  ***   * ****   ****  *     **   *  *     * * ***   ** ** ***    && deno%i==0)
** *  *** ******  * **        * ** **** **   ** * * *   *  ******* **  **  ***   **  *
 *****  * *    * *  ****  **   **   *  **  *  * *   ** * *    *   * * * *   *** ** * ** ***   *  ** *   *
*  ** **** * *  * * **** ** *     **   **  *** * ***  ** * ** ****  *** ** ** *  *  ** **    * ***** * 
 *   ****   *  **** **  * *****  ** **  **  *  ** *  ** *  *** * ** *    * ***
    }

**  ** ***    *     *****   ***** **  ***
    {
 *  ** ** ** *  * **   *  * *  * *** * * *  *
****  ** **** ***  * *  *  ** *** * **** ** * *   * *    *** * *      ** ******* * * **** && deno%i==0)
**     ** **** *   **  * ***  *** * *   * ** ** **    * *   *  *    ******  
*  *   ** *  *   * *  * ** *     ** * *******    * ***** *** * **    *  *   ***      **  * * * ***   * ***   *
 *  * * *   *** *   * *   ** * * **     *** * **  * ** *** *  ** *  *  ******  *   * *  *  *  ********** *** ****
******  * * ***  * *  **     * *** * *   * ** **   *  *** *******  **** ***  **
    }
* ***** *   *** **     **  ** *  *******    ** * ** *** **    **  *  

    }




 * **  **** * *   * ** * **    0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *    *     * *  
#include  *  **    ** * *

int gcd(int n, int m)
{
**   ***  *   **** * *  ** *  gcd, remainder;

*****    *   *  *    *   ** ** *  (n != 0)
*  *  *  ** ***** *  **   ** *  
********  **  * ** *** ** *    * *  * * * ** *  * ***  *   * * = m % n;
       *  ** ****** * **     ** * ** *      *  ** **   = n;
**     **  * *** * *      * *   * **   * ******* * **   ** = remainder;
* *  ****** **   ******   

 *  ** ****  ****** * **   *  * = m;

 **  *  * ** **   ** *     *  ***  gcd;
}

int main (int argc, const char * argv[]) {

 **  *  **** *    *    ****  *  number1, number2;
    **  **** **      * ** * * ** newNumber1, newNumber2;

**    ****   **    * **   ******** ****   *** ***  *   * * *  ** *   * * ********

*    **    *** ** * *   *  ** *     = number1 / ** ****  number2);
* * *  ** *    **    ******** ** = number2 / ***  * ** number2);

**       *     *   ** * **   * **  *** * ** **    * 
 *  *  * **      ********  * *** ** * **    *      *** *  **  * 
**** **     * * * **  * 
 *** **      *       *** * * ***  **  **** ***** * * ****** * *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ** *  **      * * ***
  *    *** **  

int     n, int m)
{
 ** *    **   * int gcd,   *  *  

****     **  *  ***  (n != 0)
 *   *   *  ** * {
 ***** *  ***  **  **     * *   *  *       = m % n;
* **  *  ***   **      *  * m = n;
   *  * **      *     **   *** *  **** n = ** * *** 
*   ***    **   }

**** *   *  ** gcd = m;

***    *** * **  gcd;
}

int main (int      **   char *  *   {

 * * *    *  * int *    * *** *
 **      * ***   int    * *  *** 

* **    ** **      * ****   **  ** **   ***      *   * *   **

  *  * * **        **  =    **  / **   ** **      
** *   *  *        = *   * /  * ** *   ***

 ** *  * * if       *****   ** *  **
*  * ***  * *   *  * ***** *  * * ** ****  *   *  *  
* * * ** * else
    ***    ***    *** *   ** ** * * * * *  * ** ** **   
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 * * ** * *  * *   *** *     ** i;
 **  *  *   **  **** ***  j;
****** ** ***** **** **  *    * * newNum1;
* * *   * * * *  ****  * newNum2;
 *  * * ** * *** * ** *     * gcd;
  *    ***  *    *      *    rem;
*   * **  *  *  *    ***   *    num1, num2;
    
 ** * * **  * ***** ***      ** ****  * **  ** * *  * ****   **   *  
    ****     *  * *** *
*******  ***    **  * *** *  *** *
  ***  ** * * * *      **** **  *
  * *   *  *  ***  **** ** ** **
     ** **  **  *    ****    *  != 0)
** *   **  *  ***    * * * *
 **** * ***   ** ** *  *   **   ** **  *** ** ***  * = j%i;
* ***   ** ****** * ** **  *    *  *   * ** ** **** = i;
  * ** *** ** *  *   *****   **    *  * *      * *    ** = rem;
**    ****    * * * **   ** *
*  ***    * *   **   * * **    
    
 *   *  *   *  *** **   *****  = num1/gcd;
***    *   ***    **** * *  **** = num2/gcd;
    
*    *  *      *       * ******  * == 1)
 ** * ** *** * *   ** **
**    * **** *      **** * *   *     *    *   *  **  * **   * **  *     * ** **  
  *       ** ** ***  * *     *
    
**  ***  *  *   ** * * *  ******
 ***  * **  *** * * * **   
** **  *   ** **  ***  **** *   *  **   * **** **  ***      * *** ***   ***** ***  **    *
* * ***** *  *  * ****** 
    
*** ** * * **   *  *  *  ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 *  ****  **** *  *   ***** ** i;
***  * ***   *   ** ***  ** *  * j;
* ******* *  ***** * ******* newNum1;
*  *** ******** * *****   * newNum2;
  *  **  *    **   ** *         gcd;
 *  *    ** * **    * * **     **  rem;
 * **    *** * *   **   *** num1, num2;
    
 ***  *  * * ***  *  *  ** ***   *   ****   * * ** *** **  ****** ***   
  * *** ***  *** * *  ** 
  ** * ** *   * * * * **    ****  ** 
*  *    ** ***  ** ** * * * *  
*   ****  ** *  * *   ** ** ** *
   ***** * * ******   ** ** *** **  != 0)
*   ** *** ** * **    *  
* ** *     * * **  ** *** *  **  **    *  * *    *  * = j%i;
*  * * ** * *** *** ***     ** **   **** * * *** * *   = i;
*  * * * *  *******   **** *  *****  *  ** * **** * ** * = rem;
* ****** **   **  ** *** *
  *  * * *  * * *     **  **  *  **
    
*  * * *    * *   ******    **   = num1/gcd;
    * *   **  * *   *  *** ******  = num2/gcd;
    
 * * *** **** *  * * *   * ** **  == 1)
******  *   * * * ** *** ** *  *
*     *  *  *   * **  * *   ***   ** *  ****** ***  *** **  *** *** ** **  *  ***
* *** ***  **      *    * *
    
***  **    **   *  *    *   *
 **     * **** * ** ***   ***
  **  ** *******   **   ****    **** *** * ***     * *   * *    * ****  **  ***** *  *******  *** *
*  *  ***     * ****** * ****** *
    
* *****  *  * ** *   ** * *   ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
  *  ****** ** *     * *   *  *  **     *****  *  ***   ******  **
* * ***  * *  *** * ** * **   ****  ***  * **     * ***   
    {
** * **  *    *   *      * *  ******** **  *  *****   * * *** *   * *
   ** ***  * * *   * *   ** ***  * *  *   ** * ** **** * *   
* **  **  *  * ** **    *  ** ******   *
 *****  *    *     ***** * * ****** *****   *
 **  *  *   * * * *  * *   **  **   *   *  

** *  * *    *** *  * * * * *** 
***  **    * *   * ** **  **** * * **** * **    **   **  ***** * *     * * *    **   ** * **** *  * **** *   **
*  ** * * *  **  **  ** *   **    *  *** *   ** *  *     ** * * *  *  *  ***


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*  *   *  ** **  * * ** a,b,GCD;
 * ****  *   ****  **** *** **** *** *** *   *** * ** ** *** 
*****  * ** ***    *** *  *  *   *   
   * * *  *  ****        *    *
 * ** ** ** *** *   **    ***   *     ** * ***    ***  *****  *
 ***  ***    * * *  ** * * ** * 
       **** **      ****  ******  ***     ***   *  ****  *   *   ***  **  ** **
****  * * *   ** **    ****  *  0;
}
     *   *********  * *   gcd(int a, int b){
  **  * ** **** ****    * ****  *  * * * * ***  * *** *   (!b) return (a);
 *   ** ** *  ***  **  ** *** * ****** *  *   **   *     * **  gcd(b, a % b);
*  ******* * ** *        *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * *  * * *  **   
#include  * * **   * * **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
**        ****  ** *    gcd, remainder;
*  *   *  **** *** * ** 
***    *  **   *** * **  ** (n != 0)
*   ***** *  **  *  *    * *  *
   * ***  **   *** **** *** ** * *      ** * *   * *   **** ** = m % n;
   * **   * ***  ***    ***  *  *   * * * * *   ***  ** = n;
**  * *  ***  ****** * *** *  *      *  * * ***   **** ** = remainder;
 * ****   * ** **      * * *
* **** ****  *  * ***   *
**  ****    *   ****       *  = m;
* * * **     ******  
 *******  *   * **** * * ***    **  gcd;
}
int main (int argc, const char * argv[]) {
*  ***   * *  ** * **  * *  number1, number2;
* ******* * ***** ******   * **  newNumber1, newNumber2;
**** * ** ** * * ****     ** 
 **** * ***  ** ***  * ***
 * ****  * ** ** *  **   *   *    * * ***** *****     *  * **  ** **   **   ********
 * *   *** **  ***  **** 
**  ** * ****   * *    *   *  * *   * = number1 / gcd(number1, number2);
*   * *  *   **  *   *   * *** * *   = number2 / **   *** number2);
***   *  ***  *  **** ** 
  * * *   ****  *  *** *
* *  **  ** * *    ** * (    **  *  *
   ******  **  *** *** *   * **         *** **********      *  ***   newNumber1);
 *  ** *    *  *  * *   * ***
 *   *  **  *  *  ** * 
 **  ** * *    *  * * ** ** ***   * ***   ** ** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*   * **  * *     * ** **  * a,b,c,d,e,f;
        *  ****      ****  **  ** * ***   *** ****     * *
****  *    ***** ** **  *  *  *
* *   *   * ***** * *** ** ****  
***    * *  ** * * * * *  * *** **  *  *
    {
*    **  ** *     **** *   * * * *** * * ***    * *     *
 *     *  ** * ******** * ******  ***   **    **    * 
*  * * * * *   * *   *  **** *  *   **** * *      *  **    
    }
*  *  *   *      * ** *  *  ** * ******** 
    {
**    *** ** *     * ***** ***  **  *     * *  **** *****  *
*** ** *  *   *    * *  *****   ******** * **  ** * ***  *    ** ** 
 *  **    ****  ***  * *** *   *****   *  ** *** *  * ** * 
*** **** * **   **  **   ******* * * ****   ***  *****   **    ** *      * *  *** 
    }
*   *  * * *    **  *   *  **
    {
* * *  *   ***   **  **  *   ** *    ***** ****** ** ***
   ****** *  * ** **        *  **   * ** * **    *  **** * * *  *  *
 **  *  **  *    * ***** **** * ***** ** *  * ** ***
**   *** ***     *** * *       * *  *    * ****     ** * * **  **  ** * ****  *  **  *
    }
**** **  ***** **    *  ** ** *   0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.30
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 12.1k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 11.6k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 14.9k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 11.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users