2 like 0 dislike
15.2k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 15.2k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* * ****** ** *** * * * i;
**** * * ***** ** * * j;
* ** * ** *** * **** ** * * newNum1;
*** ** *** *** ** ** * newNum2;
**** * *** * *** ** * *** gcd;
* * * *** * * **** rem;
***** * ** ****** num1, num2;

** *** * ** ***** ** *** * ******** ** * * **** ** * * ***** *

** * *** * ** *
***** * * * * * ** *

** ** * * * * ** * * != 0)
* * ** * **** ********
* ** * * *** ** **** *** * ** ** * ***** ** * = j%i;
** * **** ** * *** * * ** = i;
* * ** ** ** * *** *** * ** ** * * ****** = rem;
**** ** *** ***** *****
*** ******** ** ** *** *

** *** * ** **** **** = num1/gcd;
** * *** ** **** ** * * = num2/gcd;

* * *** *** * * ** *** *** ** == 1)
    {
****** * ***** ** * *** *** ****** *** * ****** ** * ** ** *** *** **
    }

** * * * **** ** * **
    {
* * *** ** * ** * ** * * ** ** **** * * *** * * * ********* * * * ** ** * * *
* ** ** ** * *

** ** ** * * * ** ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * * **** * **** *** ** * * * * ** *******

* * *** ** * *** ** * * *
*** * * * ** *** * ** * **** * * * ** ** * * ****

    else{
* *** *** ***** **** * * ** ** * *
    {
** *** ** * * * * * * * *** ** * ** ****
* * **** * *** ** ****** ******* * * ****** * * * *** * * ** *** *** && deno%i==0)
** * * **** ******** * * ******* **** ******* ****** ** *** **** * ** *
** *** ** * ** *** ** ********* * **** ** **** * * * * ** ***** * * ** ** ** ** *
* * ** * * **** * * * ** ** ** * ***** *** * ** * * *** ** * * ****
* ** * * **** **** **** ** ** * ***** *** * * ** ** *** ** ** ** *
    }

* *** **** ** * ****** * * ** ** * * *
    {
*** * *** **** * *** *** * ** * ***
* *** ** ** ** * * * *** * ** * *** * * * * * * *** * **** * ** * * * && deno%i==0)
*** * * * ** ** ** ** *** * * * * * ** * ** * ** ***** *** * ***
*** ** ** * ** ****** ** ** ** * * ** * ** * * * * * * * ****** ***** ** * *
*** * * **** ** * * ** * * *** * *** * * * ** * * * ** **** * * ** ** ** * * ***** ** ***
****** * * *** * * * ** *** ***** **** *** * * ** ** ** * * * **** *** * ***** ** *
    }
* * *** ** * *** * * ***** ** ** * ** * * ** *

    }




* * *** * ** * * * * * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * *
#include * *** * **

int gcd(int n, int m)
{
* * * * ** * **** *** * gcd, remainder;

* ** * ** * ****** **** *** (n != 0)
** ** * *** * * ***
*** **** ** * ** * ** * *** ** * * * * * = m % n;
** ** ***** ** ** * * * ***** ** * ***** = n;
* **** * ** * * ** * * ** * ** **** ** * * ** = remainder;
* * **** * ** **

* ** * * * ** = m;

* * * ** * **** *** * ** *** gcd;
}

int main (int argc, const char * argv[]) {

** * *** *** * **** ** number1, number2;
** *** ** * * *** newNumber1, newNumber2;

* * * * *** ** ****** ** * * ** ** * ** *

** * * * * * * *** * * *** = number1 / ** number2);
*** *** * * * ******* = number2 / ** * number2);

** *** *** * * ** ** * ** ** * *
* ***** *** ** *** * ***** * ** * * * * * *
* * ** * * *
* *** * * * ****** * * *** * * *** * * * **** * ** *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * ** *** *
* * ****** * * **

int * * ** n, int m)
{
* *** * int gcd, ****

* * ** *** (n != 0)
** * * ** *** {
** * * * ** * * ** * * * *** = m % n;
* ** * ** *** * ** ** m = n;
*** * *** * * *** ** * n = * *
* **** * }

* * ** * gcd = m;

* ** * ** * gcd;
}

int main (int * char * * * {

* ** ** **** int * *
** ** * int ** ** **

* *** *** * * * *** * * *** *** * * * * * ***

**** * ** * = * * / ** * * *
** * ** ** * **** = * * / * ** ** **

** **** ** * if * ** *** ** * * **
* ** ** ** ** * * * * * * * * * * * *** *
** ** * * * * **** else
**** * ***** ** ** * ***** * ** ** **** * * ** **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * *** *** ** * * * i;
** * *** ** ** * j;
* *** * ** ** * ***** newNum1;
** * * ** ****** * newNum2;
* ***** ** * * *** ** * gcd;
* * * ** *** * * ** *** rem;
* ** * * ** * * * * * num1, num2;
    
* * * ***** *** ** ** * *** ** * * * * ** * *
*** * ** *** * * * **
* * **** *** * ** ***** *
****** * * **** ** ****
*** ** * * ** ** ** ***
* * ** * ** ** ** * ** != 0)
** * ** ** * * * * * * *
****** * * **** * * * * ** * * ****** = j%i;
* **** * *** * * ** * * * ** * **** *** ** = i;
****** * * * * * * * * *** * * ** * ** * * = rem;
* * ** * * ** * **
* * * * * ********
    
* * * ***** *** * * ** * * * = num1/gcd;
**** * * ***** * ** ** * ** = num2/gcd;
    
* * * **** * * ***** ***** == 1)
** * * * ** * *
** * * * ******* * *** ** * ** ** ** ** * * * * ** *
** * * ** * * * * **
    
** ** * ****** * *
** **** * ** **** **
*** * ** * ** ** * * * ***** * *** * * * * * *** **** ** * * * *
**** ** **** * *** *
    
****** ** **** ** * * * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * * * * * * * i;
* * * ****** * j;
*** ** * * **** *** newNum1;
* * * * * ** * **** ** ** newNum2;
** * *** * ** * * * gcd;
* * **** * * *** * * rem;
* * *** * * * ** num1, num2;
    
* *** * ** * * ** * *** * * ** * * *** * * *** **
***** *** *** * ** *
* * *********** ** * * *
*** *** * * * ** * **** *
*** ** * **** ** * ** **
***** *** ** ** * ** ** * * **** != 0)
*** ** ** * ** * ** ***
* ** ** ** ** * * * ** ****** ** ***** ** = j%i;
*** * * ** * ** * ** *** * ** **** ** * * ** *** = i;
** * ** * * *** ***** * *** * ** * ** * * ** = rem;
***** **** ** * * * **
*** * * * ** *** ** *
    
** ***** * * * ** *** = num1/gcd;
** *** * ** * * ** * ** = num2/gcd;
    
* * * ** * *** ** * == 1)
***** ****** * * * * * **
******** ** * * ***** * *** * * ** * *** * * * * * * * * *** * * *
** * ** ** ** * ***
    
** * * *** ** * * ** **
* * **** * * * * * **
** * *** *** ****** * * ** * ** ** * *** * ** *** **** *** **** *
*** * * * ****** *** **
    
*** ** * ** *** * **** * *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** * * * *** ** ** * *** ** **** *
* * * * * ****** * ***** *** * * *** * *** **
    {
**** * ***** ** ***** * *** ** **** * ** * * *** *** **
* * ****** ** * ** *** **** * ** * ***** *** * * ***
*** * * ** *** **** * **
* ** * * * ** *** **** * *
** * * * **** ************ *** ******** *

******* ** ******* *** **** ***
** * * * **** * ********** * * * *** *** * ** ** *** * * * * ** ****** * * **
* * ********* * **** * * * ** * * * ** * * **** **** *** * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
** ** * ******* *** **** a,b,GCD;
* * * * ******** *** ***** * * ** ** *** **** *** * *** *
**** * * ** ** ****** **
* * * *** * * * * *
* * * ** ** * ** ***** *** * *** *** **** *
*** * ** ** ** *
**** * ** **** * * * *** ** ** * * * * *** ** * ***
** *** ** *** * *** * * ** 0;
}
*** *** * ** * ** * gcd(int a, int b){
*** * ** * * * * * *** * ***** ** * ***** (!b) return (a);
* ** *** **** ** * *** ** ** ** * ** * gcd(b, a % b);
**** *** **** **** **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * **
#include ** * **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* * * * ***** * ** gcd, remainder;
** *** * * *** ** *
**** * * *** * * ** * * * ** (n != 0)
* *** ** ** ***** **
* * ** * *** ***** * ** ** * * * * * * * = m % n;
* * * * * ** *** * *** **** * = n;
********* * * *** * * * ***** * * ****** = remainder;
* * * *** *** * * *
****** ** * * **** * ** ***
* ** * * * * ** ** = m;
* * *** * ** * *** ** *
* ** ** ** * * ** * gcd;
}
int main (int argc, const char * argv[]) {
** * * * ** ** **** ** number1, number2;
**** **** ** ** * * * newNumber1, newNumber2;
** * ** * * ****** * **
* ** * * * **
* * ** * * * ****** *** **** * * ** * *** * * *** ** *** * * ***
* **** ** ** **** **** *
* **** ***** ** * *** ** * = number1 / gcd(number1, number2);
** * *** *** * * ****** ** *** = number2 / * ***** number2);
*** * ** * ****** * *
*** * * * * ** * *
* * * ********* **** ( * **
*** ** ********** * **** *** ***** ** * * **** *** * ** * newNumber1);
***** **** ** ***
* * **** ** * * * * * **
*** * * * *** ** ** *** * ** ** * * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*** **** ** * ** ***** a,b,c,d,e,f;
** ** * * *** * ** **** * * * ** * ** ** ** * ** * * ** * *
** * * * **** ** * ***
* * * * *** * * *
*** *** * ***** * **** ** * ** **
    {
* * ** ** * * ** * *** * *** * *** *** **
** * * ** ** ** ** *** * **** * * **** *
** ** ** *** * *** ** * ** *** **** ** ** **
    }
* ** *** ** *** * ***** ***** *
    {
* * **** * *** * ** ** * ** ***** ** *** * **
** * * * ** * * ** ** ****** * * * *** * ** * ****** *** * *
* ** ** * ** * * * *** * ** ****** ** ***
* * **** * **** ***** **** *** * * * * *** * ***** * ** **
    }
** *** * *** ** ** * ** ***
    {
*** * * * *** ** * ** * ***** * ** * * * * **
* * *** * * * * ** * * * * * * ** ** * ** ** * ** * ***** *
* ** ** *** *** * ** ** * ** ** **** * ***
*** * ** * * * * * ** * ** * * ** *** *** ** ** *** * **
    }
** ** * ** ***** **** * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.196
©2016-2026

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 15.4k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 15.1k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 19.5k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 14.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users