11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
9.2k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 9.2k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

*  * *   *** *     **  ** * ** i;
*  ****  * *  *      * j;
 * *** * * ** *****   **   *** newNum1;
 ***** *     **** ***  * *  **  newNum2;
 **      * ******* * * *     *  gcd;
 **   *    **   *  ****** ***    * rem;
 *  ** *** ***   *  ***  * * num1, num2;

  **  *  ***** *  *** *  * **    * **  ** **   * *    **  * * ****    *  * * 

 *  * *  *** ** *      *  *
*  ****** **  ***  *****      * * *

* ** *   *** **    *    *** *  != 0)
   ** ** * *** * * **   **   
* **  **  *  **   **********   *** ******** *    ** ** ** = j%i;
 * ***   **  *****    ********** ** **   ***** ** = i;
 * *** ** ***** * **  *****    * ***  **    **  * ****** = rem;
* **** * * * * *     **  * **   
* *****  **   *   ** *  ** 

**   *** *** ** ** *  *    ** = num1/gcd;
*    **    ** * * **    * ** ***  ** = num2/gcd;

* * *  **   **  ** * ** * ** * == 1)
    {
* *** * * ***  ***     *  *   **   **  * * *    **    *   * * ***  **** ** * * ***
    }

* **     *       * *** ***** ***  
    {
*****   *** *    ****   *** * * **   **  *** **  *    ** *****    * **  * * ***  *
**  * * *  *   * **** *  

*   * ****** **  *  *   * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
 * ***  *        * ***  ***   **** * * *** ** * **  ** **** ** *  *

 *****  * * **  * * *         ****  
* *    * *  ** *  * * ** *  **    *  ** *** **  ** * *** * * *   * **   * *

    else{
 *    **  ** ** * *****         *  *****    
    {
**** ** *  ** **  *   * * *** ** * ** 
    *** ** **  ***  * ***** * ** **  * *     * *** ***  ****  *** ** *  **   * **** *   ** ** * && deno%i==0)
****    *** * * ****** *   **  **   ***** ** ********* ** *  *   * ** * *** *
 **  ** * *      *     *** *  *  **********   **** * ** **      **** ****  *   * ** **   * ** *
* *   ****  *** ** **  **  *  **    *  *** *   *** ***** * ** **** *** ** *** *   ** ***      * **  *  *
 *** * * *** ** ** *  *   * *  *****    ** ***   **  *  *   *   * **  *       *   *
    }

* * **** *   ****** *   ***  ***     * 
    {
  *  *** *  *   **       * * *  * ***      
 ** **    ****    *     ***  ****   *  *** **   **  ****  * **  ***  *    * * **    * *  ** && deno%i==0)
** **  ** ****** *   * * *    *** *  *******    ***   *  * ** **  * ***** *   *  *    **
 **** ** *** ** ** ** *   ** *  ***** *     *       *  *  *******   ** **** * * *  ** * **  ** ** ** *  
  ******* *** *   *    **   ***   *  *   ** *  *  *  **   **********   *    * **** **  *      **  * *      
**  ** *  **   **  * **   *   *****  * **  *   *  ***  ****  *   **  *** *  ** ***** *** 
    }
 **    ***** ******* * * *** * *   ******* *       *  * * *  * 

    }




 *  * *   *** *  **  * **  ** ** ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *  *   **   *
#include  **    *     **

int gcd(int n, int m)
{
 *******  * **   * ** * *  *  * gcd, remainder;

**** ***** **** **   *  * *   ** *  (n != 0)
 ** * ***    **   ******  * * *
 *** * **  * **  ** *** * ****  ***      *  ** **** * ** = m % n;
******** *  * * * *  * ** *** *   *   * * * * ** ****  = n;
*     *  *** * ******    **      *  ** * ****    *  *  **  *   = remainder;
  * *    ** ***   * *   

   *  *****  *  ** *     ***  * = m;

* ** *   **  * ** ***  *    * ** * gcd;
}

int main (int argc, const char * argv[]) {

** ***    *   *  ****  *  *****  number1, number2;
   *** *****  ** * *  * *   newNumber1, newNumber2;

  *   *** ** * ** * * *   **  *** **** * **** **   * *  * * * ** *    ***

  * *  *   *   * *   * *****  ****** = number1 / *  * ** number2);
   ****   *  **** ***** * ** * **   = number2 /  *   **  number2);

*  **** *** ** * *   *** *  *   * **   *** *   
*  ***     * ***   * * *  **  *****  *     * * *   **  *  * * **  * *
  *  * *  *  ***    * * * 
* *  **   * ******** *    *      *   * * ***  ****
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*     * *    *   *  *
   * * **     **    

int    * n, int m)
{
*** *    **  int gcd,  ** ***

 *  *   * *     * ** (n != 0)
*** * * **  *** * {
**  * * ****  ***  *   * * *** = m % n;
  * *   ** * *   * **   * * ** m = n;
* ** *** * * * ***** * * ***  n = * ***
       ***** }

*   *  * * *    gcd = m;

* ****     **     * gcd;
}

int main (int  **  * char *  *****  {

*  **    ** *** int   * *   *** *
 * ** ** * * **** int *  *  **    **  

 * *  * *  *      ** **  *    * **  * ***  **  ****   ** * **   

   ***  * *  * *  *  ** ** = *  ** * /   **  ***   * * ****
 ******      *  *** *  =  ****  / *   * *    * *

    **   *  *    if **  * *  * * **   *  
***        *  * ** *  **  ** **   *        *  *   ***
  *** **        else
* ***   ****   ********** **  *         * *  ** *  ****  **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
****** *****  **   *  *   i;
 *    *    **  *** * **   ** *  j;
* * *  **** **   ** **** *         newNum1;
   **  **  ***   *   *   *  newNum2;
******** ** * ** ***  ** ** **   gcd;
* * * * *    * * **  ****** rem;
**  * *  *  ****   *   *** num1, num2;
    
  *** *     *   **** *  *   * * * * * *    ** * **  **     *  *  *  ** *  
** *  ***      * *** *    **  
 *  *   ***  *  * *** * *    *  *  
   ** ** ******  ** * *** **   *  
*** * ****  **    **  * * 
***      ***** ** *  *  * **    != 0)
    *   **   * ***  **  **  
 * ** ** *   *   *  * *  **     *    *   * *       ***  * = j%i;
 * *** *   * * * * ***  *   *     * *  *   * *****    *  * = i;
 *** **  ** *  * * * *** * ** ** *** * ** *  ***  * ***  *  = rem;
*   ******* * * ** *   *
 ** *** *  * *** ***   **  *
    
  *** *  ** *** *  *  * *    * * = num1/gcd;
**    **  * *** * ****    **  *** = num2/gcd;
    
       ** *    ***** **  *    *  *** == 1)
   ****  ** ** * *     *
  ** **** * ** * *   **   *       **     ***** ***     ** ***   **    *  * ***    * 
 * *  * *****  *** *  *** * 
    
 **  * *  **  * * ******  **
** *    ****   ***  * *** ******
* *  * ** *   ******   ** **  * * *****   ***  ** **** *    *** ** *** ***     
 ** *    **   * *** * * 
    
* ***  **  ** *** *****  0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
*    ***  *   ** **    * *   i;
    * ** **** *  * *  **     * j;
*  * *** * *  ****  *** * *    newNum1;
 *   **   *** *  **  ** *** newNum2;
*****  ****          *   ** *  gcd;
 **** *** * ** * * ** * * rem;
* ******   **    * ****   num1, num2;
    
 **     ***  ***  ***   **   * ** *   *** ***  **   **   ** ** * * * *
****  *  **  ** *    *   *
 *  *** ****      ****  * **  
****     * * **      ***** *
 ***** ** * ***  ***** *  *** *
   *  *** *** ***   *  * ****  * != 0)
* *  * * ****     ******* *  
** ***   * ****  **   * ** *    ** *    **  ** **  * **** *     * = j%i;
* **  ** ****   *     *  *   **    ** *   *** * ** **  **  = i;
 ** * ** **  * *** **  ***     *  **  **  *  * ** *** ** * = rem;
 *   *** * ***    ** ***  
*** * *  ** **  *  *******
    
** *        *****       *       * * = num1/gcd;
*   * **   *  *  * *  **  *   = num2/gcd;
    
 * **** *  * ** ***     *  *  ** == 1)
* * ***** **  **  * * *   *  
* **  **  *    * ***  *** **    * *** * *** *   * ***     *  *    * ****   ** **  *** 
**  * * * **    *     *****   
    
     * *** *        ******  **** 
* * * *****    *  *   *    ****  * 
 ***********  **** ****   *   *** **  ****** ** *    **    *   *   ***  *    *  *****
 *      *        *    * 
    
* ****  * **** *** * * ****   0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
 *****  ** ***  *   *   *       *  ** **  *   **  **  * **** *  *
  * ** *   ***  *    * **  **    ** *** *          * **    * *
    {
  ** * ** **  **     **   **  *   **  **  ** *   *** ***** ** ***   *
 * ** * *   * *      * ***  *** *  *   **  **    * *  * * * *
****       *   * ***  **  ****  * * * 
*  ****  **** *   ***   ****** ***** ** * *   *
***** *  **** * *******        ****** *** **  * * *

**  * **  ** ** ***** ** *    ** 
 * **   * **  **** **  * *** *   **    ** ** ****  *  ** ****      ** ** **  * ****  *****
** ***  *     *****   *    ** *    *    **   *     **  ** * *** *   ***      *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
** * *  ***  ** * *****    *  *  **  a,b,GCD;
** * *  * *   ** * ***   ** ** * ** * * * ***    * *  *   *  
** * *  * *  *** **  *    * **
****    *  **  *** * * *  ** *  
  * * *  ** ***     ** * ******  **    ****  **   ** ** *   * * * **** 
 *** ** **  **  **  ** ***** 
**   * *       **    **    *  *** ***   *** *** **  ** *****  * * *    * 
*** ** *    ** * **  *****  0;
}
*  ***     ****     ***  *   * gcd(int a, int b){
*  **   * **** *****   *   * * *  ** *       ** ****** (!b) return (a);
 * *      *     * *   *      * **   *** * * **  ***     *   ***     * gcd(b, a % b);
 * * * *   ****** * *  ***
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     *** ** * * **
#include ** * *       *  

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
 * *  * * * *    *** *** ***  gcd, remainder;
** * ** * **** * * ***** ** 
 *  *    *** * *** ******    (n != 0)
*****   *    *** *  *    *****  ** *
 ***      **** **** * **** *  **   **  *     * ** * *  ** ****  = m % n;
 **   *   ***  * **  *  * * ** * *** ** *        ****  *  = n;
  ***** **  ** ****  *  *    *   * *    *   *** ***  *** = remainder;
** *** *   ** * ***  * *******
  *   **  *  *** ****     *  
* * *   ** *****    **     * = m;
  ** ** *  *   ***   ** **** 
  *****   *****  * ** **  **  gcd;
}
int main (int argc, const char * argv[]) {
* *  * * ** *********  ***  ** *   * number1, number2;
 ** **   * ***  *   **** * *    newNumber1, newNumber2;
*    *** **  *    **** * * ***
 *******  *  ******  *  ***
 *** **     * * *  **** ***  *  ********   **** ** ** * *     * ***   * * *****  *
  *** ** **  *  *********** * 
   ****   *     **** *    *** **** * = number1 / gcd(number1, number2);
 ***    ** *  * * *    *  *  *  *  = number2 / *  * number2);
 **    * * ** * ********   
 *** *   **  * *** **  **
   *** **    *             (  ***    
* *  *** ** **  **  *  *   ***  *  ***   *   **** **  * **   **  * **     *  newNumber1);
**** *****   ******  *****  
** *   ***  * *** *** *
  **** *  *** ** ****   *  ******** ** *** *   ****   newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
 *  ***   **   *  ** *  *  *   a,b,c,d,e,f;
*    *  ****  *** *  ** ** ****    **  * **  * ****  ****  *** ***  *****
 *   * * *** * **  * ****  **** 
*    *  **** ***  ***  *  
*     *** **** * ** *     * ***  *
    {
* *  *  * * * *  * ***  * **** ** *****  * *  *
  **    *** * **  * *    *  ** **    ***  **  ********    * *
* * **  ** *  *    *    *****  *     ***  ** *** * *  
    }
 **  *** *  * ** **   **    **  ******  
    {
 **  * ****  ***  ***      *****  ****  ***** *  *  ** *
 **   ***   * * * * * **      ** *    *  * **** ** * ***** ** *  * ***  * **
       *    * ** **  ** ** * ** * **        *     **
 ** **   * **  *  ** **  **  ** *   **    **  *    * ** * **   *   *  *  ** * ** * *
    }
 ***  ** ***  ***   *  *    * * * *
    {
*   ** *** ***  ****** *** ***   ***  **** ** ****** *  *
***       *   * * *** **** * **  * **  *    ** ******  * *  *    ***  **   
* **  *  **** * * **** * *** ** *  * * * ** * * 
  ********  * **  *  * *** * **  **  * * *    *     * * *  *** *   * ***** **
    }
 * * **** *** * * **  **  0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.103
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 9.4k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 9k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 11.4k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 8.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users