2 like 0 dislike
11.8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 11.8k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

***** ** * *** ** *** * i;
* * * ***** **** ***** j;
***** * * ** * ***** *** newNum1;
** * * * ** *** * newNum2;
***** * * ** ** ** * * gcd;
* ** * ** * ** ** *** rem;
*** ** ** * * *** * * * * * * num1, num2;

***** * * ** ** ** * * *** * ** * **** * * * *****

* * ** * ** **** ** **
* * * *** * * * * ***

* **** ** **** *** * * *** != 0)
* * *** ** ** * **** ***
* * ** ***** *** * ** *** * ** * * * * ** * = j%i;
**** * ** ** * ** * ** * * * * * ** * = i;
**** ** ** * ** *** * * ******* ** * * = rem;
*** ** ** * * * **
* * ***** **** ** * * *****

* * **** * * * ** * * ** = num1/gcd;
* * * ** **** *** * * * * = num2/gcd;

** ** ** ** ** ******** * == 1)
    {
* * *** *** * * ** * * * * *** * ** ** ** *** ** * ** *
    }

* * ** ** ******* *** ** **
    {
**** ***** * *** * *** * * * * * * ** * ******* ** * * ** * * * * **
****** * * ** ******* ** *

***** ** ** ** **** ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* ** ** ** *** **** * * * * * * * ** * ** **** * ***** ** *

* *** *** *** **** ** * *
* **** ** ****** ** **** **** * ** * ** ** * * ** * *** * * * ***

    else{
** ** ** * * ** * * ** *
    {
***** * **** *** ** ** * ** * ** * ****
* ** *** *** *** * *** * ** *** ***** * * *** ** * **** *** * ** * ** * && deno%i==0)
* * * ** * *** * * * * ** * ** ** ** * ** * * * *
** *** * * ** * **** **** * * ** *** * ** * * * *** * ** * *** ** *** * * **** *
*** ** * ** * * **** * **** ** ******* * ** * * ** ** * ** * * * * * ** * ** * *
**** * * * **** ** * * *** * * ******** * **** ** * ** * * * * ** * * ** *
    }

* ** * * ** ** ** ** * *
    {
* **** *** ***** ******** ** * *
** * * * ** ** * ** ****** * * * ** ** * *** * * *** * *** *** ** ** * ** && deno%i==0)
** **** * ** **** ** * *** * * ** * * * * **** * *
* ** ** * * ** ** * * ** * * ** * * ** * * ** * * * ** * * ** * ** * * **
* * ** ** ****** * ** *** *** **** * **** **** * **** ** * * ** * * **** ** * * * * **
*** * * *** *** **** ** * * * * * *** ** ** * * * ** *** * **
    }
* ** * **** * ** ** * * **** **** *** ** * *

    }




** * ** ** * * ** ** *** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * *
#include ** * * * * **

int gcd(int n, int m)
{
** *** **** * * **** * * gcd, remainder;

** * * ** ****** ** * ** (n != 0)
* **** * * * * ** **
* * *** ** * * * * *** * * *** * * **** * = m % n;
****** **** * ** ** * * * *** ** ** * * ** = n;
*** ** * ** * * * * ******* *** * * **** * = remainder;
* * ** * * * *****

** *** ** * * * *** * ***** = m;

* ******* **** ********* ** * gcd;
}

int main (int argc, const char * argv[]) {

** *** * *** * ***** * number1, number2;
* *** ** ****** ** * * newNumber1, newNumber2;

* * *** *** * ** * * ** ** ****** * * *** ** **** * * * * * *

* **** ** *** *** ** = number1 / * * ** number2);
* * **** ** ***** * * = number2 / ** ** * number2);

*** **** * * * **** ** ***** ** ** * * **
** ** * * * *** * ** * * ** ** ** ***** *
*** ***** * ** ** * ***
*** ** ** *** *** * ***** * *** * * *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
*** * * * * ** *
** ** * * * **** *

int * n, int m)
{
**** ** int gcd, *

******* * *** ** (n != 0)
* ** * ** * {
** * * ** ** ** **** ** * = m % n;
** * ** *** **** * m = n;
* * ** ** **** * ** * * n = * * *
*** *** * }

* * ** * ** gcd = m;

* * *** gcd;
}

int main (int ** char * * {

** * ** ** int * ** * ***
** ***** int * ** * ** * *

** * * ** * ***** ** *** ** * * **** ** *** **

* ** * * **** * *** = ** / ** * *** * *
** ***** * *** * * * *** = ** ** / * * * ***

* ** *** if * **** **** * **
* ** ***** ** * *** * * * * *** * * ** * ** * *
**** **** * ** else
** * ***** * *** * * * ** ** * *** * ******
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * * * *** ** * *** i;
*** * *** * * ************ * ** j;
* * ***** ** ** **** * newNum1;
******* *** ** * *** newNum2;
**** ** * * **** ** gcd;
* ***** * ** * ** * * ** rem;
* * ** ** *** * * ** *** num1, num2;
    
* * ** * *** * * * *** *** * * ** * ******* * * * * *
* * ** * ** ** * ** *
** *** ** ** * *
* * *** * * * **** * *
** ** * * *** * * **
** * *** * ** ** ***** != 0)
* ******* *** * **
* ** ***** **** ** *** * ** ** ** ******* = j%i;
* ***** * ** *** ** * * * ** * * ** *** = i;
* ** * ** * * ** ** ** *** ** ** * * * *** * = rem;
* **** *** * * *** *****
* * * * ** * *
    
* * * * * ** ** * * = num1/gcd;
* * ** ** * * *** * ***** = num2/gcd;
    
*** ******** ** ** * * *** * **** == 1)
* **** * ** ***
** ****** * * ** * *** ** * *** * ** * * * ** **** * * ***
* * * * * * * ***
    
* * *** * ** * ** **
*** * * ** * * *
* ** ** * *** *** ***** ***** ** **** * * * * ***** * *** ** **
* **** * *** * **** ***
    
*** ***** * * ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
**** * * ** ** ** * ** ** i;
** *** * ** * * j;
* * * *** **** * * ***** newNum1;
** **** ****** ** * ** ** newNum2;
** **** * * * **** ** * gcd;
*** * *** ** * * * * ** rem;
** ** ******** * ** * num1, num2;
    
* *** **** * * * * * * ***** * **** ** * * ** *** ****
* **** * * **** * **
* * ****** ** ****** **
* ** * * *** * * **** *
* * * * * * * ** **
* * *** *** * != 0)
* * * * * * ** ** *** *
*** * ** ** * * *** * * *** **** * * **** ****** = j%i;
*** **** ****** **** * * ** ** * ** * * * ** = i;
** *** * * * ** * ** * *** ** * * ** * = rem;
* * *** *** * * ** ** * *
* * * * * ** *
    
** *** ** * * * ** * = num1/gcd;
**** * * * ** * * **** * * ** = num2/gcd;
    
** **** * ** * **** * * == 1)
* * * *** ** * ****
* * ** ** *** * ** * * ** * *** ******* * * *** ** ** * ****
* **** * ** * **
    
* **** * *** ** **
* * * *** ** *
* **** ** * ****** * * *** ** ** ** * * * ** ** * ** ** ******
*** *** * * *** *
    
** * * * ****** *** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* **** * **** ******* ** * **** ** * *** * * *
** ** * * * *** ***** * ** * * ** ****
    {
** * * *** * * * ** *** * ****** ***** **** ******* **
* ** * ***** * * ** * * * **** ** * ** *
* *** * * * *** ****** **** **** *
* ** *** ** ** ** * *** *** * * *
*** **** **** *** ** * ****** *

* * * * * ** *** ** **
* **** * * * * ** **** * * * * ** ** * ** ** ** * * * * * * * ** ** *** * * *
* * * *** ****** ** * ** **** ** ** ** * * * * ****


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* * * * * * * a,b,GCD;
** * * * ** ** ** * ***** ** * **** * * * * ***
* * * ** ** ** *** * * ** *
*** **** ** ** ** * **** *** **
* * ** * * * ** * * * * ** ** * * **** * * *** *
* * * * * * ***** *** *
* * **** * * ** ** **** * * **** ** * ** * * * * ***** * *** *
** ** ****** * * * 0;
}
* ** ** * **** *** gcd(int a, int b){
* ** *** *** * * *** **** * **** ****** ** (!b) return (a);
** * ** * * * ***** * * * ** * ** * *** *** * gcd(b, a % b);
** **** *** * * *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** ** * *
#include *** * **** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* * * **** ****** * gcd, remainder;
** **** ***** *** **
* * * * **** * *** (n != 0)
* * * ***** * * *
* * ** **** *** **** ****** * ***** * ** * ** * *** = m % n;
* * * *** *** * ** **** ** ** ***** * ** * * ** * = n;
** ** * ** * * * * ** * ****** ** * = remainder;
** * * ****** * ** *
** ** ** * * ** * * * *
** * *** * * ** * *** **** = m;
** ***** *** * * * **
***** * * * * ** **** * ** * gcd;
}
int main (int argc, const char * argv[]) {
** * **** * * *** * ** number1, number2;
** ** ** * * * ** newNumber1, newNumber2;
****** ** *** ** * * * *
**** * ** *** ** **
* *** ** ** *** * ** *** ***** ** * * * * * * ** ***
* ** * ***** **** **** *
* *** ** * ***** ** *** = number1 / gcd(number1, number2);
** ** * * * * * * ** * *** * *** = number2 / * * number2);
** ** * ****** *****
* * *** * * * ** ********
* ** * ** *** * ** ( * **
* * * * ***** * ** * *** * * * *** *** **** *** ** *** * newNumber1);
* ** * * * ***** * * * *
* * *** * * * * ***
**** ** * **** ** *** *** *** * * *** * * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
***** ** *** * * a,b,c,d,e,f;
** * * ** * *** * * ** ****** * *** *
* * ****** ** *
* **** ** * ******* **
* ***** * * ** * ** * * **
    {
* *** * *** ** * ** ** * * * ** **** *
* * * * *** *** *** ** ** * * * *** * **
*** ** **** ** ** * ** * * * ** **** ***
    }
* *** * ** * * ** * *
    {
** ***** * * ***** ** * **** ** *** ** * *
* ** ** *** **** **** ** *** *** *** ** * * ** * *** ** **
* ** * * * * * * * * * ** * * *** * * **
** * *** ** * * **** * * **** *** *** * * ** * ** ** * **
    }
* * * ** *** * * *
    {
*** **** * * * * ** * ** * *** **** *
** ** * * * * ** ** * **** * **** * * * *
** * *** *** * * ** * * **** * * ** * *** *
* * * *** * * * ***** *** ** ***** ** * ***** ** ** ** ** * * ** *** *
    }
* * ** * **** **** * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.73
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 12.1k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 11.6k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 14.9k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 11.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users