11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
12.8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 12.8k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

** ** ** **  **  *  **  * ***   *  i;
     *  * **   * * ***    * *  ** j;
*  * ***      ***  *   * * ***   newNum1;
 ***  *****  **  ****  ** **   newNum2;
  ** ** *** ** *** **   * *** * *   gcd;
 ** *  ** ** ***       ** *  rem;
 * *   *    **** ***** * * ***  ** num1, num2;

* * ***  *  * * * *     *  * ** **    * * ***  *** * * **   * * ***

 **  **** ***  * * *  * **    *** *  *
** ** * *   *  ***** * ** * * **

 ** ******  *  ** *** * ***  *     != 0)
   * * *** **     *  *  
  ***** * * * ** *** * *  **** * ** *   ******** *  *  * *  = j%i;
  ** * ****    **   ** **  **  * * *****  *  * *  ** * * * = i;
***  *     *** *    * * **   *   **  *   ***   *  * = rem;
*   ** **     **       *
* **** *     ***             *   *

* **  * ** ****** **  *   * ***  = num1/gcd;
  **  * **   **   ********  ** = num2/gcd;

** * * * *  *   * ** *    ****   == 1)
    {
*   **** *******    *  ****  ** * * *  **  *  *     ** *****   ***  *   * *** *
    }

 ** **** * ***   *       ***   
    {
* ** *** ***  ** * ** * ** *  ** ***  * *  *    *   * **  ****  **  * ****  * **
 *  *** **   ***   ***    

    ** *  *    *    * ***** * * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** ** **        *** * * ** *****    * * **     *  * * *  * *   **  

** ** **  ****** * ***      *****    * 
  *  ***  *  *   *  *    * ***  ***  *   **  * ********* **** ****      * * **  ***  

    else{
  ** *  *     * *   *  **  * *  **** 
    {
  *    ****  **  *   ** * ***  ** *  *** *
  ** *    ****** * * ** ***     **       ***  **   ***** ** * *    *** * **** ** && deno%i==0)
 * *    *** ********* **      *  ** *   * * *   * * * ***** *  *  *** *  ** *
*  * *     * ** * *** **** * *   *   ***        **  * *         * * *  ** ***** * **  ** ** *     * **
  *    **     *    * ** *    * * * *** **   **  *   *   **       * * ***   *  *  * **   *  **** **  *   ** *
 ***  * * **    **  * * * ** ** *   * ** *  ***   ** * ** *     *   * ** ** *
    }

  ****  *   ** *******  ****     
    {
* *  *   ** * **   *****  *   *** *   * *** 
 ** **   * *       **     *  * *       *  *    *  *  ****  *     *  ** * ** * ***   * && deno%i==0)
  ****  * * *  *    * **** *   *   *  * * *   **  **   ** ******  ******  **    
    * *  * ***** *  *   *  ** * *  * * *** ** **     *  * *** *    **** ***  *   *   ** *** *      * ** ***    ** *  
 *       *   * * ** *  **  ** *** ***** *** *      **   *   * ***** ****** ** *********** * ** * * *  *  * 
****** ****  **    *  ** *  *  *****  ** * * ** *  **     * ***  ***** **  **
    }
 * *** * **    *   *** ******** * ****  * *** ***        

    }




 ** ***** *     *** ** *        * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  ***    *     ** 
#include ***** ****   *  

int gcd(int n, int m)
{
 ** ****    *** **  *** ** *   *  gcd, remainder;

 *    **  *  ****   * **  *     (n != 0)
*  * ** *   ** *   **   **
* *** ****  **** ***** **       * *  * *  *  * **   *    *  = m % n;
**  *   **   **      ** **  * ** * *** *  * * **   *    = n;
***  *  **** ************   **  **    *** * *    ** **  = remainder;
 * *  ********** ***  **   ***

*  ** *  *   *****   *      **  = m;

 * *  ** * *            **** *   gcd;
}

int main (int argc, const char * argv[]) {

* * ****** ** *** **   number1, number2;
**  * * * **** ****  *   **  *** newNumber1, newNumber2;

 *** ** * * *    *  * * *  ** *** *  *  *** *** *    ******** ** *   ** ***  

**  * *  *  *  *  **   * **  *  = number1 / **      *  number2);
 *  ** *  * ***    *** * *****  ** = number2 /  * ** ** number2);

** **  ** *   *** ** * ** * * *    *     ** *  
 *  **   * ** *   * ** *** *   * * **  * ******  ****** *          ***
 ***    * *** ** ** *     * ** 
* ****   **  *  *****  *   **  ** *  *  * **   ** * **  
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *   *     ****  **  
****  * * ***** * ***   *  *

int    * n, int m)
{
 ** **  **  int gcd, *  *** **

   **   * *  **   ** (n != 0)
 **    ***    {
*    * *       * *  * * *  ** *        = m % n;
*  *   **** *   * *** * **    m = n;
  * *   * * *   * *****   *      n =  **   *
 *** * * * ** *  }

*  * *  ** ***  gcd = m;

 * ** *  **  * * *** gcd;
}

int main (int ** *   char * **    {

 * *   ***  * int **  * *****
*       *   *  int  *****  *** *** 

 * ***  *  ** *  *   *  **     *  * *  **    ***** ** ** * * 

*  *****  *    *   *  *   = **    / * ** *    *** 
***   *  ***** ***  *   = *** /  ** *    *****

  *****      *   if ** * *  * *   *  *
* * *  *    *****   ****    *****     ** * *  * **         *****
**    *   **   else
** *   * ***   ** ** *      ** * * * ****** **  ****
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
*    * *  *  ****  * ***   ** *  i;
** * * * ***  **   *   ***** * j;
** * **** *** **  * **    ***    ** newNum1;
  *** **    *  **** *  * **     newNum2;
***   *  **  ** ** *    *    gcd;
 *  * ** ***** ***  **    *      rem;
** ** ** ** *  *  *   * ** *  * *** num1, num2;
    
* *  * *****  * * ***  * * *  * *  *****   *** * * ** *  *  *  ****
**  *** *  * * * ** *     * 
 ** *** *   **    ** **   ** *  * 
 ****  ** *    *****   **** *   
* **** **  ***  **** * *  *
***  * ** *  ** *** * **** ** != 0)
 **  ***  *******    *  **  **
 *   *  ** **  **** **    *  ** **    * * ****   * ***  *  ** = j%i;
**       * ** **  *  ** * ** * ****  ****  ** *** *  **  = i;
 * ***** *     ** ** **    *   * *** ***      **** ** *  *  * = rem;
***   ***  **   * *   ***  
**  * *** * *  *  *  ******* * * 
    
**    *** ** **  * *  *  *****     = num1/gcd;
 ***   *  *** *     *     ***   = num2/gcd;
    
***  * **** * ***  * * * *****    * * == 1)
   *     **  **** **  *****
    **** *   *    **  ** * * ***** **       ** ** * *     *** ***  * *****  * *  *  *  * 
*    ***      *  ******  *
    
  * ***** ***      **     *
*  * *   ***   * ** **  *****
* *******  * **   * *     **** * ** *   ** *** *  ** **** *     **  **  ****  * **** *** * 
 **** ** * * *  ** * *      *
    
 ***    ***         * * *  *  *** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 *** *  *** ** *  *** *   i;
    ***** ** * * ******* **  ** j;
 *** * *  *  *** **  ** ***  *** newNum1;
  ** **   * *  **   ***  * ** ** newNum2;
  ** ***  **    ***       gcd;
 *******   *    * * *** * *   rem;
*   * **  * **  *   **  **  num1, num2;
    
**** *** **  * ** *  *  *  ** **   * *** *****  * ** * ***    *** * * **
 **  ***  * *****      **** *   
       *** *** * *  ***    
*   **  *   *   *  *** * **  * *
** **  **** * *  ****     ** *
  **** * **  * * ** *  ** * * *   * != 0)
 * * *   ***  *******  * *** 
* **  * *****  ***  ** *  * **         *  *   *  ** *  * = j%i;
* **  **  * ** * * *   * *   *   *  **  ****** ** * *      *   = i;
***       * **** ******** * *  * ***    ** **   **   ** * = rem;
   * *  *  * *      *    * 
** *     ** ** *** **    * * * *  
    
    ** ***   ** **** ****  * * = num1/gcd;
 **  ** ** *** * ******** * ** *** * * = num2/gcd;
    
   * * ** * * * *    ** * * **** ** == 1)
 * **  *   **   * * *** *
* *** *  ****   ***  *******  ***  * * ** *  *      *    * **  **** *** *  *  
**  * ****  * ** **** ** * *
    
 ** * **  * **   * ***** *** *  
**** *****   * * *  * *
** * ** *  * *  ***     ***      *  *  * *** * *  * ** **** * ***  **** * * ** ****    **
 * *   *****   * ***  ***** * **
    
** * * ***   *  ** ******   ** *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
 *** **    ***      *   * ** **** ** ***** ** ***  *  *   ***** 
* ** * *** *     **  ***  ***  * *  ******* * ***  **   ***
    {
 *     * ** ******  *   *   **   ***** ** *****  * **  **  * *      * *****  
***   * **  *   * ** ******* * *   *  * * **  *  *  ** ***    * *  *    
    ** ***   *** ****  ** ******  *  *  ***
**** *** *** *    **  ** * ** ***  **  *  ***  
 ** * ** **  * *  ***  *    * * ***  * * * * ** 

  ** **** ** ** * ***** *** *
 ***   *** *        *    *       *   ** ***   *   ** *   * *  ** * * **** **** * *  *  *   * *** *   * * *
  ****  *  *    *  * **  **      *   **  ***   **  ****     *   * *****   *  


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
**  **  *  **** ***  ****  a,b,GCD;
** **  ****      * ******   *    ** * **  **       **  **** *** *
**    *** *   *  *** ***   ** *  
* *** **   * *  **    **  *  ** ***
   *   * *  ** ** **  ** ****** ** * * **   * * * *   *** ** *    * * **
*   ****    **** * ***  * *
*** *  ****   *  **  **    * *  * * *    *  *** ***** *   **   *** * * *      ***
 ** ****   ** **   *  ****** *** 0;
}
* *   *  *  *  *****  ***   gcd(int a, int b){
  **  *      ** * * ****  ***    * **    * *   * ****   ** * * (!b) return (a);
*  * **  *  * * ***  *** ** *** ** *  * **   **** *** **  *  gcd(b, a % b);
* ***  **  * **  *** ***  ** **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** * * **    **
#include * * *   ***  * * *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
   * ** **     * *****   * gcd, remainder;
** *****  *  * *   * **   **
*   *  **  * * **   *    ** *  *  (n != 0)
        *  ** ** ***** *  *
 *** **** * *  **   ***  ****  ** *  * ***  *** *   ***** = m % n;
** *** *  * *  ******  *  ***  **    * **  * ** **    = n;
 ** ***   ** *     * *  ***    * ******  * *   *** * * = remainder;
* ***  ***  *  ** * * *  * *
***   *      ****  *     ***  *
     *      ****  *** *** = m;
*  *    *   **  **  ** *  * *
*****   ** ******* ****  * *  * gcd;
}
int main (int argc, const char * argv[]) {
*** *  * ***          **   * ***    number1, number2;
*  ** ** *  *** ********  ** newNumber1, newNumber2;
  ****** *   * *** *   *
** *  *          ****    * 
**** ***     ** ***   ** ** * * **  **    **  * * *  **      ***   ** ** *   *
     *******  ** *   *      **
 *** *** *  **********  * * ** * ** = number1 / gcd(number1, number2);
**  *   ****    **** * **  * * *   * = number2 / ****** *  number2);
******     ***   * ****  *  
 **  **    * *    * ***  **   *
*   ***  * *** *      *   ( **** *  ** 
***  * **** ***       * *  * * *** ****  * ******* *  *  **  * * *   * newNumber1);
   **  * *  **     *******  
***   * *  * *     ** *******
 ** *** * *     *** ***   **** *** **  *  * *   **    newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*     * **  ** **  ** * *** a,b,c,d,e,f;
* *****   * *  **  **  * ***  ****   *  ** *  *    ***  *  * * * 
*      *   *  ** * ** ** **  
  **       ** ****** * ****** 
    *  * ** **** * * *    *   * * *
    {
 * *   * * ** **  *  * * **   *   * * **  **  ** * *****  **  *
     *   * *  *      *   * **** *** **  *  *  ****     **
** *       *   **** *  * * * ***  * * *    *   * **
    }
**  **   **    ***   **  ** *** *   
    {
 **** ** ** *** *** * *   **   * *  ****    ***  *** 
        *  **  * ** * **  * * ********* * *  ** **  *    ***   *  *   ** *** 
   * ******** * ** ** **       *  * **** *  * *    **  *     **
  ***  ** ******* *  * * ****** ***   *    ***  ***  *** *  ******  *****  ****** 
    }
******* * *   *  * *   ** *****  
    {
  **  *  ***    *    * ***  *** *  ****  ** * ** *  *   *  ** *
*    * ***   *   **   **  *   *    ** **     **** * * *  ** **** *** * **** *  *
 **      * * * *   *  ***  * ******* *  ****  * ***  ** **   
*** * * * *  ****    * *****      *  ***   ** * * *** **   * *** ***  ** *  **  * * *  *** 
    }
*    ***         * **  ****** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.134.207
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 13.3k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 13.1k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 16.7k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 12.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users