2 like 0 dislike
14.6k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 14.6k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

**** ** ***** * * * * i;
** * ** * * ** ** j;
* * * * * * * *** * * * * newNum1;
** * ** *** ** * * * * * newNum2;
** ** * ** ****** * * gcd;
** *** *** * ** *** * rem;
** * * ** **** * num1, num2;

** * * * ** * * ** * *** * * * * ** ***** * ** *** ** * ** *

*** ** * *** * *** *** * **
*** * ** ** *** ** **

** *** ** **** * ** * != 0)
*** ** ****** * * *
** ***** *** ** * * ** ** *** *** * = j%i;
***** * *** *** * * ** *** * ***** * ****** * = i;
*** ** ***** * ** *** ** * * * ** = rem;
* * * * ** ** ** ** * **
* * * * ** ** *** *** *

* ** *** * * * *** *** * * = num1/gcd;
****** * *** *** ** = num2/gcd;

** *** * * *** *** **** == 1)
    {
****** * * *** * * * * ** * * ** *** * ****** * * *** ** * *
    }

* * ** * * * * *
    {
**** *** **** * * ** * *** *** ****** * * *** *** ** *** *** ** * * ***
* *** * ** * * * ******* *

*** ** * *** *** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** *** **** * *** ** * * ** *** * *** *** * *** **

*** * * * * ***** * *** * *
** **** * ** * * ***** * **** * * * ***** * ** * * * * ****

    else{
* ** ** ** **** ** **** ** ****
    {
*** ** ** * * ** *** * * * * *
* * *** * * ** **** * *** *** * *** **** *** ** * ** ** * *** *** * * && deno%i==0)
** **** * **** * ** ** ** * * ** * **** * * ** * **
* ****** * * * ** ******* ** * ** * * *** * * *** * * ** * * * * * *
* * * * ** *** ** ** *** * ** * ** * *** * ** * ** * *** ** * ***
* * *** *** * * * * * * ** ** ** * * ********** * * *** * * ** * **
    }

* *** *** *** * **** **** * *
    {
* *** **** ** * ***** ** * * ****** ****
* ******** * * ** *** *** * * * * ** * ** * * * * ** **** * * * && deno%i==0)
** *** *** ** * ** **** *** ***** *** * * * * ** * ** * * **** *
* ** **** *** * ** ** * ** *** **** ** * * **** * * * **** * ** **** * * **** * ****
***** ** **** * * * * *** **** *** * * *** **** * **** ** **** *** * * * ** * *
* ** * * ** ** *** * ********* * *** * * ***** ******* * ** ** *
    }
** * **** * * * ** * * ******** ***** * * ** *

    }




* ** * ** ***** * * ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * ** * *** *
#include ** * ** * *

int gcd(int n, int m)
{
***** ** * * ***** * * * * gcd, remainder;

** **** * ** * (n != 0)
***** * *** * ****
* ** *** ** ** ** * ** ** ** * ******** * ** = m % n;
** **** ** * * * **** * * * *** ** * ****** *** = n;
* * **** ***** ** ******* ** * * *** ******* = remainder;
***** ** ** ** ** * **

** ** ******* ** * * * * * = m;

* * * ** * * * * ** * gcd;
}

int main (int argc, const char * argv[]) {

* ****** * * * * **** *** *** number1, number2;
* * * ****** **** *** newNumber1, newNumber2;

**** **** ** * * ** ****** * * * * ** * ******

* **** *** * * * * ** * = number1 / ** * number2);
* ** ** * *** ** * * * = number2 / * number2);

** ********* * ** **** * ** * * * * *
*** ** ** ** *** ****** * *** * ****** * *** *** * * ** *** *
* *** ** * *** ** **
** * ** * * ** **** **** * * * * * * **
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
** * ** *******
** * * * ** ** *

int * ** n, int m)
{
** * * * * int gcd, ** * *

** * *** * ** (n != 0)
** * * * ******** {
**** * ****** *** ** * * = m % n;
** * * * ***** * m = n;
** ** ** ** * ** * * * n = ***
* * **** * }

* ** * gcd = m;

* ** ** * * * gcd;
}

int main (int * * * char * ** * {

* * * ***** int *** * * *
**** ** int * ** * *

*** * * ** * *** ** * * * * * **** * *

* *** * * * ** * = ** / ****** ** * *
***** *** * * = ***** / * * ** *** *

** ** *** ****** * if *** **** ** * ****
*** * * ** * * *** ** * ** ** * * * * *
* ** * ** else
* *** * * **** * * ** **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
** * * * *** **** ** i;
* * * * ** *** *** ** ** j;
* * *** ** ** * ** * * newNum1;
** ** ** *** * ****** newNum2;
** *** * * **** * gcd;
**** ***** ******** rem;
* * * ** **** * ** num1, num2;
    
* * * * * * ** ** ***** * ** * * **** * * * *
* * * * *** * *** * *
* * * * ** *** ***** * * * *
** ****** *** * * * *
* ** **** ***** *** **
* ** ***** * * ** * * * != 0)
* ** ** ** * * ** ** * *
* * * * ** **** * **** * * * *** **** * *** * * = j%i;
** * **** * ** * * *** **** * * * * ** * ** = i;
* * ***** ** *** *** * * * * * * **** ** = rem;
** * * * * * * ** * *
*** ** ****** ** ***** *** **
    
** * ***** * *** ** ** ** ** = num1/gcd;
* * * *** ** *** **** ** * = num2/gcd;
    
** * * * *** ** ** * == 1)
**** * * *** *** *
*** ** * * * *** ** * * ** *** ***** *** * * *** * * *** ***
* * * * ** ** * **
    
**** *** * * *** **
** * * **** ** *
* * * ** ** ** * * ** ** * ** * * ** * * **** * **** ** * ** *** *
** *** ** *** * * *
    
* ** ** * * * *** *** * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* * *** * * * * ******** i;
** ** * *** ** * * j;
* * *** **** * * * * ** ** newNum1;
**** *** ** *** ** *** **** *** newNum2;
** * **** * * ****** **** gcd;
* * ** * * * ***** * ** rem;
** ** * * * **** * ** * * num1, num2;
    
*** **** * * ** **** * *** **** * * ** ** * ***** *** ** *
* * * ** * ** ** **
* * ** ** ** ****
* **** ** * * *
** *** *** * ** *** ******
* * ****** *** * * * *** != 0)
* * ******* ***** ** ** * *
* ** ** * * * * * * ** * ** ** * * * = j%i;
*** * * * * ** * **** ** * * * ** = i;
** * * ** *** ** ***** * ** ** * * = rem;
* * **** * **** * *
**** * *** *** * * * * * *
    
* * ***** *** *** ** ** * = num1/gcd;
***** ** * **** * * * * * * = num2/gcd;
    
** * * * ** ** * ** == 1)
** * *** *** * **
** * * ** * ****** * * * * *** ***** * * **** ********* * ** * * *
* ** * ****** **** ** * **
    
*** ** * * * *** ** ** **
* * * **** * ** * *** ***
** ** * ** ** * * ** *** * ** ** ** ** * * *** **** *
*** * * * * * * *
    
* * ***** * ***** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* * ********* * * *** *** *** ** * ** *** * * **
* **** * *** * ******* * * *** **** **** ** * * * *
    {
** *** ** * * * ** * * ***** * * ** * ** *** ** ***
** ** * * * * * **** **** * ****** * *** **** * *
* * * **** *** * ** * * ****
****** * ** *** *** * ** * ***** *
** *** ***** ***** * * ** * * * ** * *

* ** * ** * *** * * ** **
**** **** * ** *** * * * * * ** * * * ** * ** * ** * ** * *** ** ** * ** ** * **
***** ** * * ** * * * *** * * * *** ** * *** *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
** * * * * * * * a,b,GCD;
* * * *** *** ** * ***** * * * ***** * * * ****** * ***
* ** * * ** * ** * * *
***** ** * * ** * *
* **** * * * * *** * ***** * ******* * * * * * ** ** * * * * *
* ** ****** * **** * *
* ********* ** * ** ******** *** * *** * * ** ** *** ** * ****
* *** * *** * * * 0;
}
**** * *** * * ** * ** * * gcd(int a, int b){
* *** *** ** * ** * ** * *** *** * * * * * * (!b) return (a);
**** *** * * ********* * *** * * ** ** * * ** * * gcd(b, a % b);
* **** * *** ****** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * *** ** * *
#include * * * *** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* ** * *** * *** * * * gcd, remainder;
* * **** * * * * * **
* ** * * ***** ** * (n != 0)
** *** * ** * * *****
* ** *** ** * **** * * * *** ** ** **** ** * ** = m % n;
* **** *** * ** ** ** ** * * * * ****** ** = n;
** **** * *** * **** * * *** *** ** = remainder;
* * * * * * ** * * ***
* *** ** ** * ** * ** ** **
*** * **** ** *** * * ** * = m;
* * * ** * ****
*** * * * * ** * ** * * gcd;
}
int main (int argc, const char * argv[]) {
*** * **** * * * * **** ***** number1, number2;
* * * * * *** ** ** newNumber1, newNumber2;
** ** **** * * * * *
**** * *** ** *
* ***** * *** * ** * * * *** * * *** * ** * *** * **
** *** * ** * * * *** * *
*** *** * ********* *** * ** = number1 / gcd(number1, number2);
* ** * * ** * * * * ** = number2 / *** ****** number2);
* * ** * * *
* * ** * *** **** * **
* ** * ** ** ** ** * ( * ** ** *
*** *** *** ** * * * * ** * * * ********* ** ** *** *** newNumber1);
****** ****** * *
**** **** * ** * * * **
* ** ** * * * ** ** * * * *** * **** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* **** * ** ** * ** a,b,c,d,e,f;
* ****** * * *** *** * * ** ** * ***** * ****** * * *
* * *** **** * ** ***
* ** * * **
* *** * * * * * ** * * ****
    {
* **** ***** * * * ** * ***** *** ** **** ******
** * *** * ** * * * * ** * **** * ***
** *** **** ******* * * * * * *
    }
** * * *** ** ** *** * * ** *
    {
** * *** * * *** *** * * * ** ** * ** * *
*** *** * **** * * *** * *** *** ** * * ** *
** * * * **** * * ** *** * *
* ** * *** * * * * * ******** ** * * * * * *** * *
    }
** * * ** ** ** ** * * *
    {
** ** ** *** * * * ****** *** *** **** ***
* * * * * ** *** ***** ** ** *** * * * * * ** *****
* * *** ***** ***** * ** * *** ** *** * ***** *
** * ** * * ** * **** ** * *** * ** ** *** * * * *
    }
* * * * ** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.165
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 14.9k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 14.8k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 19.1k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 14.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users