11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 8k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

* **  **********  * **********   i;
**   *  *  **** * *  *    j;
   *  * *****  * * *  ***** newNum1;
 ** ****   ***   * *    **** *  newNum2;
* *  **    * *  *   ****  * * gcd;
* * * ** *    *  **  *  ** * * rem;
**** ****** *  *  *** *  ** * *      num1, num2;

*    **  *   ***  *  ** * ** *  * * * **  *   ** *    * *  * *  * * *

  **** **     * **  *   * **
* * **  * *  * ***    **  ******** * 

* * **  ** *  *  ****  *  ** *  != 0)
    *  **      *   * *** ***     
*** *** *  *** *  ** * **  **  ****  * ***   ****   *  * = j%i;
* ***  ** *   ** **  * ***** *   *     *  *   * *  * * = i;
** * *** * ***   ** *  **   * * *  ****  * **        = rem;
 ***     **  * * *** ** **** 
* **   *  **   *** * *  *  

* *****   * *   *       *  *****  *  = num1/gcd;
  *   * **      ** * *  * * = num2/gcd;

*     **  ***  * *      ****  ** * == 1)
    {
********     *   **  * ** **  **   *  *  *     ** **   * *  * * * **   **  ** 
    }

**  *** * ****** ** ***   * **
    {
 ** * *** * *    *   *** ***** * *    ***** * ****    * ***  ** ****   **  *  ****  * 
  *******    * *   *  ** *

   **** * *****  *** *      * * **** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
*  ***  * *  **   ** *  *   * * * **** *       * * ***  ** *    ***

  * *** **   * ** * ****  * *  ** *** 
* *  *  * ****  *  ** *  ****  * * * **      *** *     ***  ** * ** *     

    else{
****  ****  * ** ** * *   ****     **  ****   *** 
    {
  *       ** *  * *     ***    *  * *** **  * *
*  ****  ** **  *    ******** * *****    ******   *** *****  ***  * *** *  **    *   && deno%i==0)
*******   ** ****** *  * * *    * **   *    ** **  *  *  * **   ***** **   *  ** *     
 **** **    *  ***    ******* *  * * **  *   *** * * *** * **  *      **  *** *  *****   ** **  ***  **
   ******   ***   *  * ** ***  ** *    *  **    ** *****   ***************  ** ** *     ***      * ***
* **** *** ** * * *  *** **   ** ** ***   **** * ***   *   * * *  *  * ***   * *   *** *    
    }

   *** ** *    ** * ** * *     * *** 
    {
**    *** **  * ** * **  ** ** *     ***
*** **  * ** *******   *** ** *  * * * *  ** ** *** ** ****  *  *   * * *        *  && deno%i==0)
***  ****  ***  **    ****  *   * ** * *  * *   ** * ***** ** **** ** *     *  * *
* **     *  **  *  * **  *  ****  * * *  *****   **** * * * **  * ******* ****      *   *  * **  ***  ** *** 
  * **   * **   * **   ****  **  **  **  * **  **   * **** * **  * ******  *  **        *    ***  * ******  
* **** ** * ** *    * * **  * ** ****  ***   ****     **  *  *         **  *       *  * *
    }
**** * **** **    ***   * *** ****** ** *  ** ** *  * **  *

    }




**     *    *  * *    * **  *    0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** *   ***  * * **
#include *  *** * **  ** *

int gcd(int n, int m)
{
**      *       **          * gcd, remainder;

 * ** ******* *  * *    * *** (n != 0)
*  **** **   *  ***    *  
* ***  ** * * *  ***  **  *  *** *  *     **    ****** * = m % n;
** *** **  * * ** ** *   *****    * *    *  ** *  *    *  *  *   = n;
 * *  * *  *      *  * * *  ** ***  *   * *  *  **** *  = remainder;
 *  * *    * *   **    *  

*     *** ** *  *  *  *     **   = m;

    ** *  ** *  ** * *** **  gcd;
}

int main (int argc, const char * argv[]) {

* * *  **     * *  **  * * *** number1, number2;
*  * *** * ** ** ** *   *  ** *  newNumber1, newNumber2;

**** * ** *    * ****  *** *  *  * *  *  * *    *  * ** ** *   *   *   *     

*  **  ** **** * * ** * * ** *  = number1 / **** *** number2);
***    * *  **** ***** **  *** * * = number2 / * ** *  number2);

 * **  * ****  *  * *      *  * **** * * * **  
*****    ** * *******  ** *  ** *  **   *** ***    * **  ***   
*  * ** ****** ***   *** **  ** **
*** ***** *  ***  * *     *** ******  ****  * *   *****  
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* **   * *** * ***** * 
*****   ***   ***   *** 

int  * * n, int m)
{
*******    ***  ** int gcd,  *    

     ** ** ** ****  *   (n != 0)
* ****  * ***    {
 *           * *  * **  *  *** *  *** ** = m % n;
**  * * *      * * * * **  m = n;
*** *** *     **** * *   ** * n = *  *  *
***** ** **     }

*      *  *  * gcd = m;

*  ***** ** *     gcd;
}

int main (int    *    char *   ** {

* * ***   **   *  int ***   * ***
  *  *** *       int **  * ** * **    

  * **   * *     *   ** **  ***  * * *  * *   **  * *   ** **

    * * *   * * * ***  = *     * /     *   *      *
****  * ***    ***   =  ****  /  **  ** *  *  

****  **   ** if  ** *     * *******
** **    **   *     *  *  *  ** *   *  * **    *    *
   * *   ** *  else
 * ****   **      *  * * * **  ** * ***  *  ** *     *    
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
***    ***    *   * ** ***  *  i;
* *  *** **   * *** *  *** *  * j;
     **   * * **** ** **  *   ** newNum1;
******  * *  ***  ** **      ***  newNum2;
****  **  *  *  ***** *  ** gcd;
**     *  * *  **  * *  ** ** rem;
   * * *         *  *     *   num1, num2;
    
 ****  * ****** * *******  * *** * * ** **   *     * * ** *   *  ** * 
***  *  **  ** *****  * 
*  ** *       *** * *  ***    
   **** ****   **** **  ** ***
** **** ** *** * * ** *    *
     *****   *  *** * *** ** *  != 0)
 *  **** *  * *** *  *   
** * * *** * * *** *   **** ** *  * * **  *  ***  ***   * *     * = j%i;
********   ** * **  * ***      ** * **  ** ** **** ** *  **  = i;
**   * ***  *** **    *******  * **   *    * *** **  * = rem;
      * **  ***     * ** 
 ***    * ** ** * *** ** * ** 
    
 ** * **** ** ** ** **** **** = num1/gcd;
*  *   * *** *** * **  ******  **  = num2/gcd;
    
  ***** * *  *  * **  *   * * **  ** == 1)
  ******    *** *  *  *   * 
* *** **  **  *  *      ** *   *  * *    *   * *     **   * **  *** ***  ****   
* *   ***  *   * *      *    *
    
   * **  * **  **    **  ***** *
**  * * *  ***********  *** 
    **  * *  ** * *     **** **    ** * *    * ****** * *   * **   * *  * ** * ** 
 *** *    * * *   ***  *** 
    
 * * *  *   *** *    **     * * *   0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
  * ****** *****   ***** ****   i;
** *  * ******* *** *** *    * j;
 *  *** **   ***  **   *** newNum1;
  **     * *      * **  newNum2;
 *   *  **  * *** ** * **  *     gcd;
  *  **  ******  *  ***   *  **  ** rem;
** ** ***  *********  * *    num1, num2;
    
** *****  * *  * **   *  ****    * **  ******     *   
**  ** * ****** * ** 
  * ** *** **** ** *  * *** ***
 * *** ******     ***** ****
  * * *** *  *      * *  *
   *** * *  *  * *  * * **   ** != 0)
* ***** ** *  *** * *  ** ** 
 *** *    **  ***** ** * *  * **** ***  * * *  ***** * = j%i;
 * **  * *  * * ***** **********    **** *   **  * *    = i;
  **    ** ******** *** * *   *   ****     * ***  * * * = rem;
   ** * *** * *    ** **   ** 
 *** *    ** *    **** ** *    * ** 
    
***    *  *  * ** *    *      * *   = num1/gcd;
****  ********** **  ****  ** = num2/gcd;
    
 *****  * *   *   ** * ** *  **** *  == 1)
 *  ** * *** *  *****  *
*     ******  **  *      * * **             *  ***  ***  * *****  ** ** *
** ** *** * *****   *
    
*    * ** * **   **** ** ******
* *  *  *   *   ** *  *   **  
* *  * *  * *    * ** *     ****** *     **  ****  *           **  ** **  ***** * **** 
    ***    *  ***   *  
    
      * * *** ** ** * *   0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
***   ** **   ** *   ** * * **  ***  ** *      *  *      * *****   
     **   **   *  ** ***     * *****  *   **  * ***   * *
    {
*** ***** **  ******** *  ***   ** **  **  * ** ** *   *   *** ******** * * 
**** * * *** * **  **  ** *  ** **  * *      *   *  *  * *******     
   **    ****   ** **** *   * * * * ** **
*   * * ** *  *   ****** * * *  **  *  **  * **  ** 
***** *    * * *  *** *   **** *     ** *****

*  * *  * *    * *  * * ** *  *
 *  **  * *   *  *      * *  *  * *    * *       ***  ** * ***  ** *     **  * **  * *   ******  **
 * ** *  *****  *****   *** *  ***  * **  ** **** *  *** **      ** * * *     * * *  * 


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*  **** * * **     ** ***   ***  * a,b,GCD;
   *   ****  **  **  ****       * *    *****  *   *  **      **
*** *** ** *   *** *  * **  ** * * *  *
   ** * * *   ** **    * **     * *
** * ******  **   *  * * *** ** *** *  * *  * * * ** **   *** ** ** * 
**** ** * * **     **       **  
**   * ****  ******    ***  * * *    ***  *** *  *     **** ** ** * ***    * 
 *      **    *  * * *   *** * *    0;
}
* * * *    *   *    ***  * *  gcd(int a, int b){
 * *  * ******* **  * * * *  * *   * *   *     *** *** (!b) return (a);
** ****   ** *    ****** * ****  * ***  **   *** * *    *    gcd(b, a % b);
 ** * *   *** * *    *    *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * **      *  *
#include   *   *  *    ** * 

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
********** **   *  ** *    **   gcd, remainder;
*     *  *  *  * ***  **  *  *  *
 * *  ***   *  *             ***  (n != 0)
 ** * *    ***  ***  * ***  
****  ****  **    **     ****       ****  *** **      ***** ** = m % n;
   *** *****   * *** ****** * *  **  ** *    *   * **** * = n;
 *  * ***  * ***  *** **  ** *   *    *   *   **** * * **  = remainder;
  **  **  **** ****   * * ** **** 
     * * ** * *  ****    
** * * * ***  * *   * *****  ** = m;
  *   **** **        ** ** 
**   * ****     *   *  * * ** gcd;
}
int main (int argc, const char * argv[]) {
* *      * ** *  *  *  ** *  number1, number2;
* **  ***   * * *   ***** newNumber1, newNumber2;
**        *  **   * ***  *** *
**** * *** ** **   *  *   ***
*  * *  **** * ****  *   **      **   ***  **** **          *  * ** * *    ***
   * * * *  *   ******   **** 
* *    *****   *  * *    *  * * * * * = number1 / gcd(number1, number2);
*  * ***  *   ** * *    * ** *** *** = number2 /  * *   number2);
   ***  *  *   * * *****   ****
*     * **   * *    **    * 
***  *   * ****  **   * ( **     
*** * ***** *   *    ***** * ** ***** * *   * **** *  **  * * *  newNumber1);
*  * **** *  *  ******  * ****  **
** *   **   ** **  * **  *
* * ***   ** **  * ***   * **** * ** **** ***  ***  newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* **      *   * *  * ******** a,b,c,d,e,f;
*  ** *   *  *  * * **  *  *  **** * ** *********  *  ***  * ****
* **  * * *** *   ***  **  
  * *   *  ***  * ** *      ***
 *****    ** * ***  **  **** * * 
    {
*** **** * *  * * **** * * **      **  **** *  *  *** * ***
 *  *  * *  *** *   * *       **  *  **** ** * *  ***   *
*    **** * * *   * ****  ** ***  **   ***  ** ***   
    }
  * * ******  *  **** * *    ** *
    {
*   *   * * * * ***  *  *  *  ** ** * ****** *  *    **   **  *   *
 * **  ***** *  * *****  *  *** * ****      *** ***   * *** ** **  ** 
  **    ***  * *     ** **  ***  * **** ** *  **     *   *  **
  *  *** * **  *   ****  **** * *   **  ** *    ****   *  ** **  ** * **** 
    }
*  **** ***   *   ***  *  * 
    {
***   ** * * * * *  *** *** *      ** **** *** **   * ** **      
 ** **   *  *  *  *  *    * **** ****** * **    *    ****   ***  ** *****   **
 * *  * * * *** * *** *  * *** * *  **** ** *****    **   *
* * * *    **  * ** ***** ** * **  *   **  *  *  ** *** *** * *** *** ** ***
    }
*  * ****   **** * ***** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.34
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 8.3k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 8k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 10k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 7.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users