11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
14.7k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 14.7k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

  *** ** *** **  * *     *  i;
***   ***    *** ** * ** *  *  j;
* * **  * ****** ***  * * * **  newNum1;
**   **   * **** **       * * * newNum2;
 ***  ****  *  ****  *  ****    gcd;
**    *   *  **  **   **    rem;
*  * *    * * *** *  * * * * num1, num2;

**  * *  *     *  * ****   *  ** ***** **** ** * ** *   ****** *  *   * * *   *

 ****  **   * *  * *    ** ***** 
* **  ***   * **   * * ****** 

 *** ** * *******  *   *  **   != 0)
  ***   *  ** **  ****** * 
  *   ***    *    ** ** *  *  *   *   ** *** *** * *  ***  = j%i;
   *  * * **    **  * * *** * *** ****  ******  *    = i;
 ***** *  * ** *   **   ****     **    *  *** *** *  **  = rem;
*  ** *  ** *  * *    *    
 *** * *** **** **  *** * * *  

  * *   *   * **  **  ***    * = num1/gcd;
 *   **   ** ** *    ** **     = num2/gcd;

**         **  *     ** * *  * == 1)
    {
* ***** ** ***      * **   *   ***    *  * * ****   * * * **** *  *  *   **** * ** * 
    }

  ** *    *  ****   ** ****   
    {
 * ***        * *   *   *****      * * * *   **** ***** *** * *  ** *  *   **  *** *  
 *  * **  ** *** *** *    *

 ***  ** * ** **  ***  *** *   **  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
    **    * *    * **  * ***   **** ** *** ** ***  *  * *  ***  *  

****    *  *   *    *     ** *   * **
         *      * ****   *  ** *   *  *  *  * ** * * * ****      ** **  * *  ** ** * ** 

    else{
** * * * **  ** ****     **  *        **  
    {
 * **    ***  ***  *  ***  *     * *    ****  * *
 * * **   **   **** *      **** **** **** * ***    * *  * * **     ****        ** **  *   **  && deno%i==0)
*   * * ***** **  **   *** * *   **** ***** * *  ***   *** **    **   * *  *   *
 * * * *  *  **   * **   *  ***** *    * *  ***  *  *****  *  * *******      ***** * *  ** 
 *  ** ***  ***    *    * ** * * *** *    *  *   *   *    *     *   * **  *  *  ******* * * **      *  * * *
    *** * ** *    *      **   *** *    ** * *  * *** ** *** *   ** **  *   **  
    }

 *** *  **  *     *  * * ** **** * **
    {
     *     *  *       ** * ** *  ** ***  * * 
 **    **        *  *  *** *    * ****  ***  ** ** *  *     ***** **  ***** ** *        *  ** * * && deno%i==0)
  * *  **** ** * * * **   * **  **  ***  *** **   *   **  *  *   **********   **** ****  
** * * ** *   **  * ****  * *   **  * ***  *     *****    **    * *  *   **  * * * *     ** * **       *      ****
 ** *****  **  * *   ****   ***  *   ** *  *  **  * * *    ** *    *  ** *   *  ** *       ******** **  
 ****  * ***  *  *   *   * * *  *******  ***    *   ***** * * ***   **    * *     
    }
 * *  ** * ***** ****   *    **** **** ** *  * ***   

    }




 ** * ** * *** * **   *    *** *  * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  ** ******
#include  ****** ** **

int gcd(int n, int m)
{
*  * *  *    *    * *  *   *  gcd, remainder;

*    * * * **  * **   * **  (n != 0)
*  *  * * **   *  *** *    * 
** **   *** * **    * * *   **** *    * *    *****   ** *** * * *  = m % n;
**    * **** *** ***     *  * * *    **    ** ** *  *   = n;
*  **  * *   *  *  ***   * ***   *  *     ** **  = remainder;
* *     * * ** * **   **   * *

*  *  ****** *** **  **  **** = m;

    *  * ***** **      *       gcd;
}

int main (int argc, const char * argv[]) {

****        * *  ** ********* ** number1, number2;
  ** * *  * *  **  * *  *    newNumber1, newNumber2;

  *   **   ***  *  *  *  * **   *  ****    ** *   * ** *  * ** *  * 

*  ********** ** * * ** *  *** * * * = number1 /  *  *  * number2);
 ***  *   * *  * ****      *     = number2 /  *******   number2);

** * ** * * **** *   **** *   *    ***** ***  *  
 ** **** * *  * *  ***  *  **   ****  *** *  ***  *  * *   ** ***  * **
* **  **  ***** *  *     
  ****   **** ***  *  ** *  *   *  **    * * *******
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* ** *  ** * * *    ***     *
  * *  * **   ***** *   *

int   * n, int m)
{
**  * ***  *   * int gcd,  *   **

* * * *       ****  **  (n != 0)
* ****   *  * * *  {
** *** * ** *  ** * ** ****   * *   = m % n;
  **** * * * * * *  *** *   ***  *   m = n;
   *** * *     * ***** * ** ***** n =   *** * *
**** * *   **  }

**    **  ** ** * gcd = m;

* ** ***        ** * gcd;
}

int main (int   ** **  char * *    * {

  * *    **  *** int ** *   * ** 
*  *     * *  *  int    ** *    * 

    ******* ** ** ** **    ** **    *   *** *     ***    

 ***    **      *  *  =    *   / * **   ** *
*** **  ***  * *   = ***** /   *   ******

 ***     ** *** if * **  *  * ** * * ***
    * *** **   ****   * *  ***  * *  ***   **  * * ** **  * 
** * * *   *  else
* * **   ****            ** *   *  * **  **** *  ***   **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
   * * *  *  *     **    *** i;
     * * * * ***** *    j;
  * ** ***   *  ** **  * ** ** * newNum1;
***   ** **  **   ** ** ** ** *** newNum2;
*  * *****   *  *  *  *   *** gcd;
    *    * *   * *** *  ** *** rem;
  ** ** ****  *   *** **   *** num1, num2;
    
** **  ** **** **     *******   **  ** **  **   * **** **   ***** ** *
 *  * ******* ***** **** *  
* **      *      ****  * **   *
   * * ***  * * *** *** ** * *  
*** * **** *   * * *** **** * 
 *   *** ** * *  ***********  != 0)
 **  * *    *** * ** **  ** * **
*  * * * * * *    **   ** * ***  **  ** * ** ******** ** = j%i;
  *  **   *    ***** **    * *   *   **** *           = i;
  * *    * *   * ***  *    *    ***    *****  = rem;
** ** * *   *** ***  *   ****
       ** *    *   **   *
    
* *  ** ** * *** * * ********  ***  = num1/gcd;
* *    *   ** **  ** *   **   ****** = num2/gcd;
    
   *******   *** *   * ******   == 1)
   *** ** *  ** ** **** ***  **
* **     * * ***** * * **   *** ***   *  * * **  *** *  ******   * * *** ** *  *
*   *    ***  **  *** * *******
    
    * **** *** *  * *** *  *
***  * *  * ****  ****** 
 * *   **    **    * *** * **** ***  ** ***   ***   * *** *  **        *  *  * **** *  
    **** *** ***** ****   *
    
  ** ** * * **** **  *** ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
**   *******  *  **     *** *** ** i;
* ****** **  *** ****** *** *   j;
 * * ***     ** *  ********   newNum1;
*  ****** ***  ***  ** * * * *  newNum2;
**  * *  **   * **     *  *   *  gcd;
 **** *   *** *  *  * *** **      rem;
* ***   **** ** *  ******  num1, num2;
    
 *  ***    ** * **    **  *  * *  *   * ** ***  * *   * *   *****
* **   *     **       ** ******
     *    ***** * * *   ** **   * 
* * **  **** * **   *  *** 
   ****   ** *  *  * ** * 
** **  ****  *  *  *  ** **    * != 0)
    ** **  ** ***  **   **** *
* * **  *  *  **  *  *  * *  *  * ***    ****   *** ** * = j%i;
  * *  **   ** **  ** *** *  *    **** **  **  *  *** ** = i;
*   * *** *    *** ****** ***    *  * *  * *  *    * *  ****   = rem;
**  ****   *     *   ** *    
  * ** ** * * * **  * * ** *  ** 
    
  *  * *** * ****  *** *      *    = num1/gcd;
      ** *   *  * *   **** = num2/gcd;
    
  *  **   * *  * **** *  *  ** ** == 1)
****    *   *****   **  **  *
*** **** ***  ******** *    ****  **   ** *  * ****     **  ***  *  * ******* ** *   ** 
    ** ** *  ***  **    ***  **
    
     * *  ** ******  * *******  
*   *** *** **  *** * *  
* *  *  **** * ** * ***    *  *    * ** **    *  *   * *  ***  *  **  *  **** ** ****
* *   *  *    **  * **  *  
    
  ******* * ** * ***    *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
***   * *    * * ** ** * **** *  *  ****  *     * ** *     ** *  **** 
** * *   ***   *  **  ****    * ** * ** **  ****** * * *** 
    {
  * ***** * *** *    ** ** *    **    * **  * *  *  *  *   ** * ** **
 * ** * ***  **** * *    ***  *  *  ** *** * *  ***  *  *  *  
*   * ** ****  ** ** *    *    * **    
* **** *** * *     ** **    **** **       * *   
*     * *   *     *** *** *    * *   *  * **

*  ** *   *   ***         **  *
 *  *  *           * **  *     **   * ***** *** *   * *  *  ** * *****   **   * ** **   *** *    *  *
  *  * ***  * ** * ****   ** *        * *   * **** *    *  *  ****    * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
   *******  *  *  * ** ** ****  a,b,GCD;
*  * ***  *  ** *** *       * *  ** ***  ** * *  * **       
 * * ****** **  ***** ****     
* * **   **** **   **  **  
 *** **    *** **  * ** *       *  ** ** **   *   *        *  **** ** **
 ****  *** * *   * **  *  ** ** 
 * *  ****   * ***** ** ** ** **  *  * ** ** * *** * ***      **   **** *  ******
**** *  ***    *    ** ***** * 0;
}
*****  * *   * *    *    * *  * gcd(int a, int b){
  *****  *  ****  * * *   * ****** * ******  * *  *** ***** (!b) return (a);
  ***** **  **    ** *  *** ** ** ** *** * ** ***** ***  *** gcd(b, a % b);
 *   ** * ***   *** * **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***  *   * * 
#include  *** *   *** ** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
** ****   * * * **** *  gcd, remainder;
*     * * * ** ********  **  **
 *       ** **** **** * ** **** (n != 0)
   *** *  * * ** * **  *  
* **    *** *******  ** *  **   ***  ***  * ** * ***** = m % n;
*  * ***** *  * *   **  * *    * *    **** ** **** = n;
  ***  ****** *** ***   *****  ***  *  * **     ** ***   = remainder;
* *  *    *   **     ** *
 * * ** ** **  **  ***      
  **  *** **    ***  ** * **   * = m;
*   **** **  *     * ** **
       **    *  ** **   *****  * * gcd;
}
int main (int argc, const char * argv[]) {
*** *  *  *****  ** *** **   * ***  number1, number2;
*       ** **   **** *  * *   newNumber1, newNumber2;
* * *** * ** **** *  * *
    * *  **** * *  *  * *
*       ** * ** * * * *   **   *  **    * *  *  * * ** *   *     ** * *****   * 
   * *  *  *  **  *    * ***** *
**** ****  * ** ***** ** * ***** ** *** = number1 / gcd(number1, number2);
 **  ** **** *  *  ***  *   *  ** = number2 / * **  **  number2);
   * *** * *  ***  ** ****
   *  ********* ***   **  * *
  *  *  ** *******  * *   ( *  **  * 
 *  * ***  ** * *  **  *   *****      ** ***  *    **  * *   * **  *   * * newNumber1);
** * **** ** * *  ** **  *  *
  ****** ** *****   *** **
  **  * ****   * ****  ** * **** *  * *  * **** * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*  * ***  *  ******** **  *  ** ** a,b,c,d,e,f;
 * ****   * * ***  ****** *** ** *  *  *** * *  ** * **  ** **  
***   *  * *   * * * ** **** * * *  
 *  ** ** *   *   * **** ***  
*   *   ** *  * * * *      * * ** * *
    {
** * **  * **   *   *        **  ****  ** *** **  * * * *****    
* * * *  *  *   *** **  *   * * * *  *  *       **   * *** **
* **  ** **** * ***    ** ***     **   ******** * **
    }
** ** *     * ** **** ******
    {
*  **  * * ** ***  *  **** * *  **** * ****  *** ** * *  
 *    **  ***   ***  *   **   ***        *   **  **** ***  ***** * ** 
* * * **  *  **  ** ******** *  *   * **     **  ******
 ** * ** * *  **** *   *   *** * *  **** *   ****  * *** *    * *  * ***  * *   *
    }
** ** *****     *  * *  *** ** 
    {
 **   ** ****  *  **    * *   * *** **   * * * *   **    **
  ** ***  *  ** ****** * * ** * *  * *  *    ** **   ** **  *   * *  ***  
****  *  *    ** *    * *  * *  ** * ** ****** ** ***  * **  **  
*    *   *  ***** *  ** *  ** *  **********    * *  * **   *** ***  * *   * * 
    }
 ****** * * **   * **    *  *    0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.113
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 15k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 14.9k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 19.3k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 14.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users