11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
9.2k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 9.2k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

*   *   *    *  * **** * *  i;
*** *  *   * **    ***** **  *     j;
* *    * *** * ****    **  ***   newNum1;
 *  * *****  **   * **    ** * newNum2;
**  ***   **** ** ** **  * * ** gcd;
   * ***   *****  **     *  ****   rem;
***  * *** *  * *****  num1, num2;

*  **  * ** * * **  ****   *    * *     ** **   **** *  ** * ****     

   *** **  *    *  *  *     
* **  *****  *** * *   *  * *   *    

  ** ****   ** * *****  *  *  **   != 0)
**  *  ***  *  **    * *   *
* * *   **    * ****  * * ** *  ***    *  ***   *  **  = j%i;
*  **  ***    *****  **      *     ******* * *** ** * = i;
  ** *****  ****** ***** ***   *    ***  * *  * ** *  * *** * *  = rem;
*** ** *      * ** *** * * 
 *  *   ** ** **  *** ****  *  

****  ** * ****      *    **  * *** * = num1/gcd;
**   *        ********** *  ** = num2/gcd;

***** **  *** *   ** **      *   **  == 1)
    {
*  * ** *** ** ** ***   *   *** * ********      * * * *  * **    *       
    }

     * * * *    * * *  **  
    {
** *  *    *** *  * *** *   *   * **   *   *** ** *  *  * **  * *** **** **  **** **** ***
*  * *    **** * * *           

* ** **   * *** ****   * **   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* *  * ***   *   * **** *  *** **** *** ***** ** ***  ***** ***  **   ** *** 

   *** **** **  *  ** *  * *  ** *  *       
    * * * *** * **     ** *  *  ** *  * * *    ** * ** ** * * *  *   * * **  *  **  *****

    else{
   **   * *** * * *     ****** ***  **   
    {
* * *    ** **** *  *  **        *  *  *
  **** * * **   * * * ** ** ** **  * ** *    ** *** ***** ***    *  * * ** *** **  && deno%i==0)
*** **    ** ** **** ** * * *        *   ***** *** * *** * **** *** *** * * 
    ** *** *   *   *  **   ***     ** *  *    *  ***  *** * ** ** *  *  * *** * * ******   * *
     **    ***  **  **** **  * **  *  * *   **  *    **** *   * * *  *** ******* *** *****  ***  * *       **
 * ***** ****  **** ***      * ****   ** ** * * ** ** **    *           ***    ****
    }

*    *   * *** **  * ** *    * **   *** *
    {
    ***** * **** * *** **  *    *** **  *  
**  * *  *    *****   *   *   *  ***    *   ****   *     *     *  *  *    **   *****  *** * && deno%i==0)
 **    *     *   * *** ****** **  * *  ****   *   **** **  **  * **** *   *  *  ** 
*  * *  *  *  * **  ** ** **    *****  * ***  * * *   *   ** ***    * ** ***  *  ** ****** **** *  **** * *** *  *
  **    * **         ***** * **** *    * ***    ** ** ****  **  **  * *    *** ** **    *     *  ****  
**   *  **  *   **    ****   **    * * *  ** ***   *   *  **  * * **   *  * ** * *
    }
* *  ******    **  ***   *   ** **    ****** **  **       *

    }




 * **  **    **  *   ** **  ***  ** * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *** ** *   **  ** 
#include   *** **  *** 

int gcd(int n, int m)
{
 ***  ********* *  ***  ** * * gcd, remainder;

* *  *** ***  *   **  *  ** *** *** *  (n != 0)
  *  *****  * **  * * *  *
* ***    * * * **   ****  *  *   *   *** ** *   ***   * *  = m % n;
*    *** * ** ******  **   **  *  *  * *** ** *** **    = n;
 *     * * ** **  * *  * * **   *  *   * *  * **** = remainder;
*  * ***    **  **     **  *

*  * ****  ** *** ** ** ****   = m;

     *   * * **** *        *  **   gcd;
}

int main (int argc, const char * argv[]) {

*  * *    ******     **** *  *  number1, number2;
***   * ***       *  **  * *  *  *   newNumber1, newNumber2;

* *** * ***   * *** ** ****   *  * * **** ** *   **    ***   **** **  

*    *** ** *  *** **  ***  *  = number1 /  *  *  * number2);
* ** **   ** ***    *****   ***   = number2 /   *  *  number2);

 *     ** ** *    ****   ** * *    ** **    * ** *
* * ** *   * *  * ****   *  * *   **  *   *  *   ** **   * * ******* 
** * *** ***  ** *  **  *   
*  **** **  ** * *** *  ***** *  *  *      **  **   *  **  * 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** ***   *  ** * *  * **
      *       **  *  

int    * n, int m)
{
 *** *   *    int gcd,      

* * ****    ** * *  **  (n != 0)
* ** **         {
 **    ** *  * *  ** *  *    ** **      * = m % n;
 *****  *  **** * *    *  *  * * m = n;
****  ****  *** **   ** *    ** *  ** n =  *   *
    ****   * ** }

 ** *  * ** * *  gcd = m;

*  *****  *    *** **** gcd;
}

int main (int ** *   *  char *  * * * {

** *** **     int * **  ** 
**  * * * **  ** int     *      *  **

**   ** *   **   * *   *    * *  **   *  * *** * * ** ****  *  *

 ** * * *  **    ** = *    /  ***  *  * *   
   *    *  *  ***   *   ** = * *  /   ****** **    

* *** * * ***  if  * *****  **  **  * *
   ***    *    * ** * * ** * *    *      *  *  ** * *
*** * **    else
* *     * * *** **   *** *  **     **  **        **      
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
   **   * * ****** * * i;
*****        ******    ** * j;
  *   * * *  ** ***   *  ** * * * newNum1;
* * **** ** ** ******   *** ***  * newNum2;
      ** * ** ** *** * ***  * *   gcd;
** **  **  ****   *   *******   *  * rem;
   * **   **** * *  *** **  num1, num2;
    
* * **        **** *** *   **  **  ****   *    ** ***  **  *
  *  *  **  *  *  **** 
*  * **     *   *   ** * **      
***  **      *   *   ****   ***     *
 ** ** * *** ** *** **** **** 
*  ** * ***      **** *  ***** * * != 0)
***  * ** * *** ** * *   *  
   ***** **** * *  *  *   *** ******* *  **  **  *   **  = j%i;
 * **    **  ** * *** ***   * **  ** *   * ** ***  **   = i;
**  ** *   ******* * ***  *** ****  * *    ***  *****    = rem;
** ** **** *******  *** * **  ** 
*  *   **** * *  * ***** *  *  * ** 
    
      *        ***    **    * * = num1/gcd;
**   * * *** ***** **    *   *  *  = num2/gcd;
    
**   *  ***  **  * ** * **    * *  *   == 1)
 * * *  **** ***   **** * ** 
*  **  ****    *  *     ****   **** *******    *    ** *  *** *  ** *   **  * **  * 
* ***  * * * ** ** ** * *  ***
    
 *    *    *  ****  * ** ** 
    **  * ** * * *****  *
* ** *  **** * *** ***   *** *    **  ***      *   *     *   *****  ******      **  *****
  ** *  *** * * * * * *    
    
  *   **   ** **     *    0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
** *   ****      **** **  ** * *   *  i;
      *  *  *** *  **** * ** * j;
**  **  ******* *   ******* newNum1;
* *  ** * * * ***   ** ***** newNum2;
 ** * *** **  ***  *    * **  * gcd;
**  ***** *     ****** ** rem;
***** ** *   *    * ** ** * num1, num2;
    
       *******  **  ** *  * *  **  * *  ** ***     *  ** * *  * **  
   ***  ** * **   **  **  * **** 
  * *   ** *   * *  * ***    **** **
  ** *** * *  * ** ***  *******  
* *  *** *   ***** *  ** 
 *      *  *******  **  **** ***  **** * != 0)
  *** * *  **  *  * *** * * **
*** * ** *  * *** * * ** **  * **  *     * *  ***** *  * ****    = j%i;
 **    ***   *  *  ***** ***** ****** ***  *     ** *      = i;
    *  **   *        * ** ***   ***  *   ****    * * **  *   = rem;
**** ** **  * *** * *** *
 *     *****   * *******  ****  *  
    
 *** *  *** **   **  * ********** = num1/gcd;
**  **  ***  *******   ****    * = num2/gcd;
    
** ***  ***      **  *** * **  *   == 1)
*  **** * *** ** **  **  * *
 * * *   * *  * * **   * **** ***  *   *    *** ** *  * ** *   * **     * **     *
**    * * **  *  * * * *  ***
    
* ****  *  **** ** *  
*  * *  ********** * * * *    
**   **  **  ****  * *      *   ** *  * ****  ***  *  ******   *  ** *   *  *  * * 
 ** ****   **  *** * * **
    
* *   *    * * ****** * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* *  ****  ***  * * *  * **   *  * *  * ** ****** **** * ** *    
   **  ***** *      *  * *** ***   * *   **** *** * * *   ** 
    {
  *   *  * *  *** **  * **** ***   *   *  *** *** ****   ** ** ** ***
  * * *** * *   * ** *  *******  **   *  ** *      ****** *       *  *
* * *** *** * *** *   * **** * *  * **     * *  
** *   *** ** **  ****** **  *** ******
   *** **** *    *  *  ***   **** * *  *** *  * 

 *** * ****   *   ***        
*  * ** * * * *  *  *  *  * ***   ** **   ******* **  * * *     *** * *  ***  * * * ** * *    ***  ****
***** **     *  * ***  ***   **  *****   * * ** ****  **** **  * * * * * * 


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
 ** ****** * *  * * *   *  **** a,b,GCD;
    **** *   *  *  *  **** **   ** *   *** ** ********* ***  *
** ** * **    *  ** *  *** *   * *   * *
   *      * **   * * ** * * ***  
  *** *   ***** * ** * *  * ** ** * **     ***     * ***     **   * *
 *  **  * ***** **** * **  **
*   **** * **** **  * *   ***  * *     *  *** * ** * *  ** *** *     * **  ** 
      *** ***** **   *  * *       0;
}
**   *   ** * **  *  ** * **  gcd(int a, int b){
*    **       ******  **   ** *  ** *  **** **  *  ******* (!b) return (a);
  *****    ***   *  *** ** ** * ***   * *** *   ** *   gcd(b, a % b);
  *** ***   * ** **     *    **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    *    *** * * * **
#include        *     ** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
**  **  ** **   ********   * gcd, remainder;
 ***   *  ***  * **  **     *  ** 
   *** *** * *    **   *  * (n != 0)
 * *  ****** **  * * *   
 **** **** ***       *    ** ******* *** ** ** **      ** ** = m % n;
 *    * *****  * **    *** **  **  ***   * *  ****  = n;
 *   ***  ** ****** ** ****** * ** * *** ** * ********  * = remainder;
 *  * ** *** ** * * * *  * 
 ** ***   * ****   **** 
* **    *   *    ** ** *  * = m;
  ** *    * * *     *** *  * 
* *  * * * * *        **** ***** * gcd;
}
int main (int argc, const char * argv[]) {
 **  * *****  **** *** *  **  number1, number2;
       ****   * * * **   * newNumber1, newNumber2;
 * ***      **     *** *
  **  ***        *     *
   *   ****    * ** **   *** * *   ****       *  * *  **      
**   * *****  ***  *  ** 
* *** ** *    *** ****  ** *** **** = number1 / gcd(number1, number2);
* ***** *  *  *  **** ** **   ***  **  = number2 /    *  ***  number2);
 **    **   *****  ***  * *
   * *    *  **  * *** *  * 
*    **** ***   **    *****   ( * * **** 
*    ** *** ** ***   * ****** **** *   **** * ** **  ** * ** * *** *  newNumber1);
  *  *** *     *** **    ***  
   * *    **** *         
*  *** *   * * * *******  ***   *** ***      * ** ** *  *  newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* *   *   *** *  ***** **  **  a,b,c,d,e,f;
** *   * *   **   *   ** * * *   * *  **  *** * *      *  * * * *
  ** ** ******** ** **  *  *
 ****   * * *** *  ** * * *   * 
 *      *  ** ** *  * * **  *    * *
    {
    ******  * ***  *   *   ****  **  ***  ***   ***      
* **   **  *  *** *** * *   **  * *   * *   ** **   **  *   
** ***   **    *    * **  * ****   *  *** * *  ** ***    ***
    }
  * *    * * * ***   ** *   ** *  ***
    {
   *** * * ****   *   *     *** **** **** *    **  * *** * 
* ** *  ** * * **  **   * * * *    ***  *  ** * * *** *** *    * ** ***  
*  *  *   ****   *  ****  * *   *   * * ***  *** * **    
*** ** ** * **  **    * * *  *****   ****  * * * **  * *  **  * * * ***  * *    * ** 
    }
     * *  *      *   ***  ***   *
    {
 * * * **       *   ***    ** * * **  * **  * ******     * 
        ***  ** *** * **  * * ***    *   **   * ** **  ***  *  ***  ****   
*  *  *    ****  *** * *  ** *  * *  ***   ** 
  ****   *   ***      **  * *     *  **      **  *******  *  *  * *** ****** * **** **  * 
    }
       *     * ** **    ** **  * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.197
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 9.4k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 9k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 11.4k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 8.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users