11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
9.8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 9.8k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

 ***  *** *** *  *   **** * i;
*** * ****  *  * * **    * *   * j;
* **** ***    * **  **   *    newNum1;
  * *  *** **  *  * ** * *****  newNum2;
  **  **  ********     *  ** gcd;
  ** *  **  * **  ***  *** *    rem;
 *   **  ***  *****  ****** num1, num2;

  ** *    ***** * ***  ** ***     ***   *  * ***      *  *  **   ** 

 ***     *           *  *  *******  
 **    ***  *  ** * * * *** * * **

 *  * ** * **        **     *  != 0)
 * ****   * *** * **  *  
** *  ****      ****   *   **  * **    **  * *  *  ** = j%i;
  *   **   **  ****** ***   ** ***    *    **   **** **** = i;
 ****    * ***       **  *   *    * * ** ******  *** **  = rem;
*   **** *   **   * * *  *  
*      ** **** *  *   * *  **

***   **** *   ** * **  *    * * = num1/gcd;
***  * ** **   ********* **    = num2/gcd;

 * ** ***** *** *    **** ** ****  == 1)
    {
         ** ***   * **** * *  * *  ** * ******* * **   * ** **    *      ** *   
    }

 * ********* ** ***    ** 
    {
*******     ** *  *   *  *  **** * ** **  ** *    **  * ***  **  **** ** * * * **** *
 *   * *** * * ** ***** * **

    * *  *  * *     *   *****    0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
*****  ***     * * *     *   **   * ** * *   * * * **  * **   

 **** * ** * ********* ****** *     
 **  *****  *** ** ***  **  ** *  *     *   ** * * * * *   ***  *  *  ****  *   

    else{
*** *** * * **     *  **   * ** ** *    *
    {
  *** ****    * * * *   * * *  *** * *   ** ** *
**  *  **  ****  *    *** ** * *    ***** ** ** *  ** * ** * ****  *****    * ****   *  *    && deno%i==0)
  ***   ***  ** ******  ** * *  **   *    * * * *** ** * *  *      **  ****  *
  *   ** ********   * ** **   **   *** ******* ***  *   ** * ******* *** *   *  *** *    **    * * * * * 
* * ** ***       ** * *  ** *   *  ** *  ** ** ** **** **** ********  * **   **  **  *  * *******  ** * * **
**  **    *****  * **  * ***  **** * *  *   *    **   *** *    ***** ** **** 
    }

*  *     ***   **  *   **    **   **  *
    {
     *  ** *** * *   * *   ** ***  ******   * 
 * * *  *** * *** *******   * ** **** *    * ** * ** *    *** *  **  **     *   ** * **  *  && deno%i==0)
**** *  ****      ****  * *** **** ********  * **    * ***** **  ****  *  * **
  *  *  *   *** **  *** *     ** **  *  **  * ** ** * ** *  *****  **** * **  * * *** ****  *  *** ** **** * **
 *  *  **  ** **  ***  *    *    *   **  * **    **   * *    *      *  *** ***  * ** **  **   *** * * * *     ***
*****  *   ***    * *   ** **  ***   *  *  **       ** ** ***  ***   *    *** ** ****
    }
 **** *     * *  ***  **  *  * **   ** * **     * *** **** 

    }




*****    * * ***** **** *  *  **  0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***   *** * **  *
#include  ***** * *  **  *

int gcd(int n, int m)
{
***   * * *  ** **   ***  **   gcd, remainder;

  * ** *     *   **    ** *    (n != 0)
  * ***    * * *  *** * * **
 ** ** *  ******    *   *  **  *** **  ***   ****   = m % n;
 *  ****** *  * ** *** ** ***** *      ***  *     *** * *   = n;
* *** *   *****  * **   ** * *** ***   * ******* * *** ** = remainder;
*** *  *  ** * * **  *  ***

  *** *    ** ** ** *   ******** = m;

 * **     *   ***    *  * **   gcd;
}

int main (int argc, const char * argv[]) {

   ****** *    *   * ** ** number1, number2;
***   *      * ***   * *    *** newNumber1, newNumber2;

**** * *     * * ****   *** *       ****       **     ** *  **      * **

** ** ***  **     *     * * *    = number1 / *  * * * number2);
* * ****      *   *  ** ***  ** *  = number2 / **    * number2);

   **   * * *  ** *  ***  *    **     ***  *** *  
   * *** *** *** *  *  **  * ** *  *     *     **  *  *   *         ***  * 
*   ********* *    ** ***  ****
* *  **** ****   **  *  ***  ****  ***   *** ****  ****  * 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
****  *    * ** * ** 
 * ** *  * * ** *** 

int  *** n, int m)
{
   ****** ** * *  * int gcd, **   ** 

**   *    *     * *  (n != 0)
* *   **   *  * {
  ** * *** ***  *   **  *****     * ***  = m % n;
*   *   ***   *  **   * **    m = n;
     **  ** **   * ******   *    *  n =  ****** 
** **** ***  *** }

 *   **    *   * ** gcd = m;

  *   *     * * *   ** gcd;
}

int main (int *   ** char * **  {

  *   **  **  int  ***  ***  * 
**** * * ****** int ****  *** *  **

*      *** * **  ** *** ***    *  *   **     *** * ** **  * * ** 

** * **   **** *  ** *** = * **   / * * **     **
** **    *  **    * ** = ** * / * ** *  *  * **

  * * ** *  *   *  if  ** * *  *  * * *
  *** *  *   * *********   *  ***  * **   * ***  *****
 **** *   *  else
*** *   * * ****  **    ** * **  ***  *  * * ***  *
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 *       ***  *   **   ** * * i;
 *  *  *  **  *    ** ** *** j;
 * *  *     *    *     *  ***    * newNum1;
*** **  * ** *  ** * **      newNum2;
  * *     * ** *   * *     * gcd;
*   * *** *  **   **  ***  * *** rem;
*** **  ** *     *  * * ** num1, num2;
    
 ***  * *  *  **** *  *    *  *  * * **  * **  *  **      *    *  
      ** ** **** ******   
**  ***** *** ** ****   *       
* * **  *      *  *  *  **** ****
 ** **  ** *  ** ** *   *   *
**   **   * **     **    ****  * != 0)
    * *  *   * *** * ** **** * *
  * * **    * **  *    **  *****  *  ***          * *   = j%i;
**   *     *   * * ***  * *** **** ** **  *   ****  *** *  = i;
*** * **    *   ****  *** *** **** * ** ** *** *** *  * = rem;
  ** **** *    * *    ** ***** 
*   *         * ***    *  ** 
    
  *   * ** *********** ** ****  = num1/gcd;
 * *** **  ** *    *****       *   = num2/gcd;
    
 *   * *        ** **  **  * *** ** *** == 1)
*       * *       ****   **** * 
 *   * ***** ** *    *** *       *  ******   * * ******* **** **   *  **    *  **  
  ** * *  * *  *     ******
    
 **   **** *  * *   ****    *  
*** * **    ***** *    **  ***  
 * **  ***   **   ****** ****    *     **   *** * ** * * **        ***  *   ** ** * *  **** 
*  *       * **    ** **   
    
 *   ** *   * ******* *  ***** *   0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 * *****  ** * *    ***   i;
** ** *  ****** * ****** ** j;
 ****** *    *  ** ** * ** * newNum1;
  * ** *   ****  ***  **     * newNum2;
  ** *  *   ****** **** ****    gcd;
  *  **** ***  ***  * **  * rem;
  **** * *   * * ****** *****   ** num1, num2;
    
   *  **   *      ** ***  * * * * * ***** * *  *       *****     
***   ** ****     *   *  ** **
*** *** **    ** *   * ****
      * * **  *  **     *****  * * *
  * **    ***  * *** **    ** 
   **  *  **** ***  ****    ** *** != 0)
   **  **  * **   **  ***
* **  ** *   *  **   **   ** *  *  **   *****  ***  *    = j%i;
**      *    * *          *   ******  *** * *** **  *  = i;
 *   ** *  ** *  * *     ***************   * * **** * * **** = rem;
* *  * **  **   *   * *    
 * * *    * **  * *  *  **   **
    
 **  * **   * *    ** * *** = num1/gcd;
   * ** *  * * ****   *  *  *   *  = num2/gcd;
    
 * *** *    * *   *** ** ******** == 1)
  *   *  * ***** ** *** * ** * 
**** ** *   * ** * ****  **  * ** *  *  *    * ***  **       **** *****  **  * *
** *     ** ***   **
    
** *** ****  **  *  *  * *  *   ** *
**          * * *         * 
* **** ** * * *  ***  ***         * **    ** *** ***   **  **  *  *  ** * * ***  * 
** * ****    *  ****     **
    
 **  **** *  * ***   ** * *  *    * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
** *****  **    **  **     * *  *   **  **   ** **    *  * *
   ***     * **** ** **  **  *     * * *  ** * * ***  *     *
    {
********   *    ** *  ********  ** **    **   * *  ****    *** ** * ** *  ** *
* * * *  ** *** **    ** **    *   *   * *   * *  * *  *   *    ** 
*  *   **   ****  *   **** **  * *  ***
***     * **     ***  * * * ** ** ***         * 
*         *    * **** *   *  *   * ** * * * * *

  *** ** * **    ***    * * * * * *
*** *   ** *  *  *  * * ** * ** ** ** *    * ***  *    * * * ***  * * ******    * *   ** **   ******* *
    * **** *     * **  * ****    *  **** ****   * * *** ** * * *  *  * ** 


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
 ****    ***  *  ******   a,b,GCD;
* * * **   ** *  * *  ** *  *** **  *   ***    ******  *** **
 *  *** * *  ** *** * * *  * *  * *
  * ****   ********* ***  *
  *  ** * ** ****  * * * ***  **       * *  * ***  ****** *  *   
 * **  ***  *  * ***  * * ***   **  
 ******* ******  *****  * * * ** ** *  * **  *******  *** ***** *    ** *
        * **** *  * ****** * * *  0;
}
    * **  **    **  * *  * gcd(int a, int b){
     **** * **   ****** * *   *   * *   **   **  * (!b) return (a);
* * *  ***  * **** * *  *   * *   * ******** * ** ** gcd(b, a % b);
**     * **  **  *      ***
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *      ***** ***
#include ***   *   * ** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
**** * ***** **   * ** *** gcd, remainder;
**   ** **   *   **** 
* * *   ****   **    *  * (n != 0)
 ****    * * * ****** *   *
*   *   ** ** ****    *  **  *    *     **********   * ** *  = m % n;
    * *  ****   **   * ***   ***   * * ** **** *** = n;
 *  *  *   *** * *    *** * **  * **** *     ** * = remainder;
 ****     ******* ****
***    ** *    ***   ***  ***
** **   * * * * *** **   ***   = m;
*  *   *  ***  **   **** * *
* ** *  *   * * ** ** *** * gcd;
}
int main (int argc, const char * argv[]) {
* * * *  ***   * ** * **  number1, number2;
*   **   * ****    *  **  newNumber1, newNumber2;
***   * **** *   *  *     * 
*  ******  ***  ****  * * * ** * 
  **  * * *** *     * ***      **  * * * *  * *  ***  * * * * *  *    * * **  *
**  **  ** * * * * ***  *** *
 ***      ** **  *** ****     *   * = number1 / gcd(number1, number2);
*    * **    **  * **  * ** * *   ** = number2 /   *  *  *  number2);
 * *** ***  * ****  **** **
**   *   *  * * *****     *
**    ***  *    **   *****    (  *    ***
   * *  *    **   **    *  * *   * *    **  ** ** ** **  *  *   *  * ** *  newNumber1);
*    *****    *********** ****** *
 ***** *  *** * * **  * *
    ** **   ****  **   ********  *** *** *   *** newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
  ***** *  * **    **   a,b,c,d,e,f;
* ** * *   * *****  **** *  * **  ** ** ** *      **** * * **  **  
* *   ****** *     *    *   * 
  * *  * ** *** *****   **  
*  *    ** **  * *  ***    * ** *** 
    {
 **    **  * *   *  * ***** ***  *  *   * **** ***   *  *** 
 *****   **  *** ***   ** * *  * * *  ***** ***** **** ***
*  *****  * ****  * * * **** ** * * ** **  *     ** ** *
    }
 **   *   *  *  *** **  * **     ***     
    {
  *** * **  *  **** * ******** **  ** *** **    *    ****
 * *  * ** ****  **     ** *   *        *   ** **  * * *  ** **** *   *******  
  * **  **  * *    ** * ***  *  * * **  ** * *   *  * * *   ** 
**   ***  * *    * ******   * ** ** **  *    * * ***** * * *  ** *   * **  *
    }
  * ** **   **  * ** *******
    {
 **** ***  * * *  *  * **   *** * **  ***  ** **   ** * ****   
* **  ** ***   *****     *      ** * **  * ** ** *    *    ***  ***  **   **  *  
  ** **  ***  **  * * ** **   **** *  * **    *  *   **  * *
 **   *    ****** **  *****    *   ***    ** * *****  ********  ****     * ** ** * ** * *
    }
 *   *  * *   *****     **  ***  0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.185
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 9.8k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 9.5k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 12k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 9.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users