11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
16.6k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 16.6k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

***  *** ** ***  *  *    * * * i;
   * * *     ***  *  **   *    * j;
   ** *     ***     ***    * newNum1;
  *       ***  *  * **  *** newNum2;
** *  * * * ***      **   *   gcd;
* ****  ** *** *  * **      rem;
 *** *    *    *   ** ***   num1, num2;

  ** *   ** ** *** *   ***  ** ** * *  * * ***   * * * ** ** ***  * 

**  ***  **** *    ***  ****     *
***  *  *     *    * ****  * ** ** *    

* ** ***  *   ** **  ** ****   *** != 0)
    *** ** **   ***    ** * *
*   *  ***  ****  ** * ***    **       ***    *** *   * = j%i;
** ***    ** ***     *   * *    ** * *  * *  *  * *   ** = i;
         *  ***       ** *  *  ***    *   **  **   **  = rem;
* ** * **        *** *  *      
  *    **   **** ***    ****  *

***  *** **** ** **   ****   ** ** * = num1/gcd;
   * * *    **   * **    * * *** * = num2/gcd;

* *  *** *** **          **  **  * == 1)
    {
 *  *****   **    ** ***  * ** *** *** * * *  *  ***    *****  ** **  ********  
    }

 *** *** ****  ** ****  ** **
    {
 * *  *  * *  ** ** ** * *  *  *** * ****** * *******  ***  * *   **     *   * ** ** 
 *  *    * ****  * ** **   

   *  * ******  ***  ***  ** *  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* *  * ***    * ** *** **  * ****  *  ***** *    **  ** ** *  *   *  * 

*****    * *      *     *******   
 ***     * ***  ***  *     ** **  * *        **** * *** **   * * ** *   ** **  *

    else{
 * *** *   **   *  *** *     **  **    * 
    {
**  ***  ********    *** ******  ** *  *** **   
 ** *      *****  **  *  ** * **** *  *  *  **   * * *  *** ****    * *** **** && deno%i==0)
  ***  * * *  ** ** **     *  * ** * **  ****  * *    **** * **    *  * *  * ***   * *
  *  ***     *  * *** ******* ***      *  ********* **  * * *  ** *  **  *   **  **** * *  * ** * 
  **   ****  * ******* * *** *  * * **  **   ***   ****  *** **** * **   *      **  **** * * *    ***   * *    *
   ***  **********  *  * * *   * **   * * * * *         ****  * *** * ***** * 
    }

* ***       ** *     **  ***   **     * 
    {
   *** *** **   *****     *** **
*  * ** *** *   *   *  *     * ** * ******  * * *  ** *  **  ** *     *  * * * * *  * *  && deno%i==0)
* * * *****  *** **** *   *** * *  *** * *    *** ** ** **** * ** * **** *   
   * **  **   **   * *** ** * * **** * *    **    ** **  ***** *** * ** * *   * *  *** *** *  **  *  
*  ** ****  *  *   **   *   *   ***    ** ** * ***   *****   ** ** * * *  **  * ******  * *  *  *   ** ****
**  *** ***** ***      * ****  * * *  **  ** *   ** * **  * ** *  *  * **   
    }
  ** *     *        ** *  * *   *  ** ***   * *    

    }




  *  * * ***  **** **   **  * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***  ** * ** ****
#include **   **  *** *    

int gcd(int n, int m)
{
  ** **** *****   **  *** **  gcd, remainder;

*  * *    * ** * * **    * (n != 0)
 * ** ***** * ***  ****    **  
* ***    ** ** ***  *    ***** **  *   *** *** *****  *     = m % n;
*  *** ****  ***   * ** * *    *****  * **        * = n;
* * ** **  *   ** **   * *** ******** ***  ***** * = remainder;
*** **   *** ******   * ***** *  

****  *  *     *   ** *** ** ***  = m;

  * *  * ** *   **   *  *    ** * gcd;
}

int main (int argc, const char * argv[]) {

 *  **   *  * *    *  * number1, number2;
       * *** *** * * * * ** * newNumber1, newNumber2;

*     *  **** *****    * ** * **  ** ** **  ***  *     *** ** * * *     * *  * *

**  * **  **** * ***  ****       = number1 / * * ****** number2);
***  *  ** * **    *  *  **** *    = number2 / *  *   * number2);

* **   *   * *   * ** *  **  *   ** *  ***     
*  **  ***** **  * **    *   **    ***   ******  *   * *   ***   *
   *   * *  *   *  ** ** *  ** 
  **  *  * * *   *  *    * *   * *  ***  * ** *    *  **    
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  ** ********* ***** *
**** * *   **   

int *  ** n, int m)
{
 * * *      * * int gcd, **** * *

 ** * **   *   *   (n != 0)
****      ** ***** {
***** **     *  *      **    **   * * = m % n;
  * **    *****     ***** * * * m = n;
*  ***   * **      **    ***   n = ** *   * 
  *      * **   }

***** **   *  * **  gcd = m;

 ** ***    * *  * *   gcd;
}

int main (int   * * *   char * ** * {

 * **  ** *    ** int *    * **
* *** **  **    int   * *   *  * 

***    **  *  ******   **   ** **         ** * *      *** * *   

*** *  ** **      *  *  =    /  *   ***  *    * 
   ***  * *  *   *     =    * /  **     * ****

** *** ***  ** if * * *** *  * ** 
**   *** ** *  * ** ***     ***    **  * *     ***
***  *    **  *  else
**   ****** ***   * *  * ** * *****  * ****   * *  ** 
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
***  *** * ** * ***** **       i;
**    *   *  * ***  ** * *  j;
 **    *** * ** * *      * **** ** newNum1;
**    *** **** **  * **    ** newNum2;
** * **  * * * **  ** *** *    * gcd;
**    *** ** *  ** * *  *** *  rem;
* *** *  *  **    **** *  **   num1, num2;
    
*** ** * **** ***** ***       *   **   * *   *   *       **** ****
***  *** *   * ** *  * *** 
 ** *  ****** ***  ** *   *
  ***  **** *  * * * *  **   * ** 
       *** **** *      **** **
** * **  ***      ****  *    *    != 0)
  *      * ** **  ******** *
*  ***  ** ** * ** ****  **** *  ** * *   ***    *    = j%i;
** * * * ** * ** * ** *  * ***** ***    *   ** ** *   = i;
**** ***    * *  *  ***  ***  * * ****** *      ***   ** *  * ** = rem;
 *** * **  *  * ** **  *   **
 **  *    * ** * **  ***   **   ****
    
 * **  ** *  **  **  * ******* = num1/gcd;
    **  * *** * **   **   ***   **  = num2/gcd;
    
   ** ***    * *  **  **  ****  == 1)
   *  ****** *   **  **   * ** ***
**** **  *   **  * *** * **  *  *** *    * *  *** **** * **  * ***   *     **
        *** *******   *** *
    
** *    ***  *  *****      
 * * * * *** * *  *    ****
 * **** **   *  * *    *  *    **   * *     ** *     **** ****   *  * * * *   *  *  
  * ****    ***** *  * *
    
    ** *** * ** **  *** * ** *  0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 * **   *    * ****  ****   i;
 * * *     *   **  ****    j;
*   ** ******  *  ***  * ****  newNum1;
*   **   ***** **  **     * *    * newNum2;
 * * * **    *******  ***  * gcd;
**  *  **   **   ****       **  rem;
***  ********  * *  *      num1, num2;
    
  * *****  * **** * * * * *  * * ** *** * *  *  *   ******** **** 
* ***** *  ***     **  ***
  *  **    ***      **  *****  
**** *  * * *   *  *********   
**   ** ** ****  *    ** ***
 ** * *  *  ** *******    **  * != 0)
**  *  * ** *   ** *  *  
***    *  * ****  ** *  *  *** **  * ***   ***   ** *  *   = j%i;
  ******  * * * *  * * **** ****** * ****     = i;
   *    *** *  *  * * ** **  * **  * ** ***** * * = rem;
   * * ****  *       **  ** * *
     *  *** * **  ** * * *
    
* * ***** * ** ***** * ****   = num1/gcd;
*  *   ** *   *****   *  **** * = num2/gcd;
    
** ******    *   ** **    == 1)
   *  *      *    *   * ***  *   
 * * * ***** * *  ****   * * ****      * *    * ****  ****** ** * * **   *  *
**     *  ** ** *  *    *   
    
  * *     *       ** **   * *
 ****  **  * * * ****  *  
 * ** *** * ********   ** * **    *   **   ** * *  *   * ** *** * ** **      **
* ** ***    *   *** ** * *   
    
   *    *   *   *   * *******    0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
 * *  * **** ***  *  * * *   * ** ** ******   ** * *   * **   
****   ** **** ***  * **  *  ** * **  *** *  *   ** **  * *  * 
    {
*   *   **   *    *   ***     ** **  **  **  *   * * *    * ** * **  **   * * 
* **** *   **** **   * *    *** * *  *   *****  *     *  *****   *
 ***** *   ***  ****  **  ****  **  * ** 
 ** *  *   *   * *****  *    *   **  **
   *  ** *  **   *  *  ****    *  **     * *  **

   ** *   ***   **  *  *  
** *** ***   ***  * **     **  * **  ***   *****    ** **   *****      * * *  * *  * ** ***  *** *        * 
   * **   * **  *    **  *******      ***   *** ** *  ** ** **  * * **  *   **** * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*   **    *  ** *** * * * **  a,b,GCD;
      **** *       * *  **** ****  ** *** **  **  ** * ***** *  * *  
 * ***  **    *   **    * * ** *** **** *
    * *  ** *  *  * **** * *     ***   *
*** *  **   *  *    * * ** *  **   ** **   *** *** *  * *    * ** *  *  * 
**  *  *   * *    *  **  *   
* *  *  *   ** * **     * *     ***   * ** * *      ** * * * ***    **  * * 
  *** *  **   *****  ****    * ** * 0;
}
   ** * *** ***  * * *** * gcd(int a, int b){
** *  * * **    * ***       * *** ***   *  ** ** *   ***  (!b) return (a);
**** *   *   ***     **  *   *  * *  * **  **  *     *   * gcd(b, a % b);
* ****  * * * *** *    **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   * ** *** 
#include    **    *    

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
*** ** * ** *  * *    * * * * *  gcd, remainder;
  *  *   *     * ** * ** * *  * 
* **  *** *** *** * ** **  * *   (n != 0)
  ***  *      * *     ***   **
****  ** *  *** * * *** *** ***** *   * * ** ***   * * ****     * = m % n;
   ** * ** * *  *   * *   * *  *   *  *  **** * **  = n;
****  * *  ***   *  * *    *   ***   * * *  * * **  * = remainder;
 * ** *        * *** **   * *
  ***    *** * * **  *  * **
 * **   *   ** *    * *   = m;
 *     *   *  * *      *  **
 * *  **  ** * ****   **  ***  gcd;
}
int main (int argc, const char * argv[]) {
  **   ** * **  *  * * *   number1, number2;
* ** * * ** ** *  ** ***  **  newNumber1, newNumber2;
*** ******  *** **  ***   ** 
  * *******  **    ***  ****** *
  **** *  * ***   **  ** ******* * * *  * *    ** ****    **  *** ***
 ** * * ****  ***  **   **   
  ***     ****  **    * *** *     * = number1 / gcd(number1, number2);
** ***    * ***  ** *   ****   **   = number2 / *  *** ** number2);
  * *   * *    **  ******  
***  ****** ** *    *      
 * * * *****   ***** **  **** (  ***  
*  ** ***  *  *   * * ***** *  *  *   *  *    * * ** *  ** * * *******  ***** newNumber1);
** *** * **   **  ******  **
* * *   * *   ******** *    
    ***  **   ** *  * ***** *    ** **     *  * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
 ** * * ****   *  ***** * a,b,c,d,e,f;
 *    **** *  **   ** *****  *   * * **  * ***  ***  ***     
   *   ********* *   ***  *****
 *    *  * * *   ** **       ** *
** **  * ** *  *** *         *  **  ****
    {
     *  *  **   *****  *      *    ***  ***  **  * ** * ** **
**   **  *  ****    **  *   * **   ** *  *  *      * *  ** *
*  * ** *** **** *   *  ***  **  **  * *  ***   * **  ** * 
    }
* **** *** ***   ** ******  * *  * 
    {
***  * * ***   ** **** *  *   *** *   **   *    *   * * **** ** *
***  *  **  * ** *    *  ****  **** * *  ** *  **  *  * **  ** ***   **   *
 ***  ******   ** ****  ***  * *    * *  * ***** **  *
 ** *   *   *    **** * **  *    * ***     *  * * *    **     *    *****
    }
* **   **  * ****    * * *
    {
* *        ***  *** ***  ** **   *****     * ** * ** *  ***  * * *
*  *** *  * ***** * ** *   * * *   *** *  *   * *  **** *  *   *     * *  * ****
  **** *   **    *   ***** *  *****  ******      *   *
**  *     ****       * *   ***  *  *  ***  *    * * *  *** ** ** * **   ** 
    }
* *** **  *  ** * ***    *   0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 16.9k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 16.6k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 22k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 16.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users