11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
14.3k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 14.3k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

*   **  ** ***  *** **  ** i;
 **** ** * ****  ** *  * j;
* ***    * **   *   ***  *   * newNum1;
*    *  *     * *     ** *** newNum2;
* **  *  *******  ** * *** *** gcd;
  *  * *   ****     ****      rem;
  * *** ***  *  *    *   ** num1, num2;

*   *   **** *****    ***  *****  *  *** *** * * * ** **  * *  * ****

 ***  *  *  *    * * * ***** ** 
*   **   *  **  *    *  *   * 

  *       ***        ** **   * ***  != 0)
 * ***    ** ***    **    *
    * * *   ****** *   * *** **  * * ** * *   ***  **** = j%i;
* **  * *  * ** *    ****   *    *   ***** *    **  = i;
     * **      *    **********   ***    ** * **   ***  ****** = rem;
**** ******     ** **   *    
 ***  * **   * * *  *  *  * *   * 

   ** ** **    *** **    ***  = num1/gcd;
***  * *    ****  *  * **     ** = num2/gcd;

  *  *  * **   * *    * *** *  ** == 1)
    {
 *  ****    ** * *  * * **** ** * ****** *   ** *** *   ** *  ***   **** * ** *  
    }

*   *** * ***** *******  
    {
  **  ** **  *   * *  * ** *** ****  * *   *    * ****   * *************   * **  **    *  **   
**    * * ****    *  ***  ** *

***     **** *  * ***   *** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
    * *  ** ****     *   *    *  ** * *     **  *  **  * *** **    *

 ***  **  **** ***  ****** ****   * 
**    *    * ** * **    *   * ** *  ******     * ***      *  *****  * *   ** 

    else{
*** **** *  *  * *  *  ***** *  *     * 
    {
 **  **   ****  *** *     * *** **** * *    
* * ** **  * ***  ***** *     ** ** * ** *  *   * **** **    *  ****  *   **  ** *  **   && deno%i==0)
   * ***   * *** * *    *   *** *    *  *** *  *** * ***  *****   **  **    **** *
*** * * **      ****** * **  ** * ***   ***  *   ** * * * * **  *    * **  *******    *     **  ** 
*    *** **  *  *   ** * * **    ** * **  ** *       ** * **** **       **   **     *   ***  **  ** *
 *  ** * *** * * *** ***** ****** ****** *  *** *****  **  ** ***     ******* *
    }

 * *** * ****  * ***    * *   *** *
    {
******    ** **  *  *  * **   ** * ***   
 **       **    *     *****  ***   **     *** *        *     *      **    * ***   ********   && deno%i==0)
*    *** **  * ** *** ** *** *      * * **    **  * ***   * * **  * * * *
*  **  *** ****  *   ***  *    * ** **  **   *  ** *   *  ** *     * * *** ****    * ** ***  *   * * ** *
 **  ** ** **   **   ***    **** ** *  *  *  *  *  **** *   **  * * * ** *   *  ******* ** * * *   * *** * 
   ** *  **   ** *     ** ***  **        *** ** * **  **** * *** *    *  * 
    }
** *        *************  **   *    * *  *  * * *  **  * ** 

    }




* * ***     ****  **** ***** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *            *  *
#include  ** ***    

int gcd(int n, int m)
{
    **    * *** ** ***  *  *  **  gcd, remainder;

  ** * *  ***   *  * *   ***  *   (n != 0)
** **** *** ** *** ****  **  
  *  * *** ** **       *    *** ** **    * * ****  ****  = m % n;
* ***** *** **    ** ****** ** *    * **  **  ******* = n;
 ** ** ****** **  * **** **       *        *** ** * ***   ** = remainder;
*  *    ** **  *     *   * *

** * ** *** * ** ***  ******* *   = m;

 ** *** * * * ***  ***** ** ** * gcd;
}

int main (int argc, const char * argv[]) {

 ** * *  **** *  **** **        number1, number2;
 *    * **    * *    *   * newNumber1, newNumber2;

**   *   ** *  * **  *   **   **  **********  * **   **** *** *  ** * 

 ***  *  *  *  *  *  ** *    * = number1 / ** ** **  number2);
 **   *  ** *   *   ****   ** = number2 / ** *   *   number2);

* ****   *     ** ** ***  ** ***  * ***   *   ** 
*** *****   * * ***  * * *** **  **** * *  *   ** *  *  *****  * *    
       **  ***     **  *
* ***     **** *** *   ***        * *    *  *     ****
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** * ****   *   **  
 *** * ****       ** ** 

int     * n, int m)
{
* * * **   **** * int gcd, * ** *

*****  *   ****  ** * (n != 0)
*  * * ** * {
** **  *  ** *     *     * **       ***  = m % n;
  *  *   **      *  **   ***   m = n;
    ** *   ***  ** ***  *    *  n = ** * 
*    *** }

* *****  ** * *  gcd = m;

* **** *  *    *  **    gcd;
}

int main (int **    ** char * *     {

 *  *** * * int   **   * 
    *    *** * int *  * ***** *   **

** *** *   ** ** **  *  **  ***  * *    **  * *  *  *** 

**** ** ***  *  **  *  * = ** *  / **  ** * ***  *
*   *** * *  **   *** *  =     /  *   *    ***

**  ***      *   if *  *  **   *** * ***
  **** *  *  *  * ** **  ** *  ** ***  ***   **  *   *
 *    *    * ** else
**  * ** *** *  ***  **  ** * ***   ** *** *   * *  *  * 
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
* * **     * * ***  * ****  **  *    * i;
***  *  * *  ** *  ****** * *** j;
 *  *** * ** ***   * * *   newNum1;
***   ***********  ****  * ** **   *  newNum2;
** ** * * *  ****** *   gcd;
 ** *  ** **** * ** *** *   rem;
* * * *  *  * ** * ** * **** * num1, num2;
    
 * *   **     *********  *   **** ****   *    *   *    * * *   * *  * ***  *  *
     ***  *     **  * **  * 
* *      ***   * * **   **    
**  *  **  * ** **  ***** *******
   *   * ******  ****   * * 
 * *** ****      *  * * *   * != 0)
 **   ** **   * * * ***** *
*  *** * *  *****  * *** **     **  *  ****   ** *****  **    = j%i;
*    ******   ***       ****    ****  ****     ** ***   = i;
***  * *** ** *  * ** **  *  **** * *     ** *   ***   = rem;
***** **** * ***** *  * *   *
 ***** * * ******      ***   *    
    
******  *    **  *** **  * **** *** = num1/gcd;
*   *   * ******  *** ***   * ** = num2/gcd;
    
* *  *     *  *  *    ** * **  == 1)
    *****  *  **** ** **** *
   *** **      * ** *     ** * *** * ***  **  * **  ******   *     ** *   *   *** 
***  * ***** * *** * *** * **
    
  * *  *  *  * **  * *****   
*  ***** **  *  * * *  *     ***
****  ***  *   * **  **    * * * *   *     *  **   ** * *     * *  **  *  ***     **** 
 * * *   *    *  * * *   *  *  
    
 ****   ***** ** *  * * *  ***   *  * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
* **** ***  ****   **   * * i;
  *********** * ** * *  * *  * j;
  * **        **      *** * newNum1;
 ****    **** *  **  **  **   newNum2;
 ** *   ** **   **   **   *   *  gcd;
** * *****    *** * **  ***   rem;
 **    *     * *****  *     num1, num2;
    
* * **   *  **  **   *  * *  * ** *  *   ***   ****       * * *   ****
    *   *   ** ** ** *   *
* *  *          ** ********** ** 
*  **  ******* * **    *    *
     **   **    *  ** ** ** *  *
* *  ** *           *   ** ***   != 0)
 ***    * **  * * * *** * *   
***  * ** * * **   **        ***  ** ***** *  ** **    = j%i;
*  * **    ** * * ** ** **    *****    **** *   *  = i;
 * * *        ***** * * * ******* * **** * ****  * ** * **   = rem;
  **    ** *  **  * **   * * ** 
*   ** ** *      * *  * * *  *** *
    
  *** *    *  ******** * * * *   = num1/gcd;
****  *** *** ** ** ** ** * ** = num2/gcd;
    
*** ****     *  *  ***  ***  **   == 1)
   *  *  *****  *   * ***** *
    **** ** ***   * ** **  *  **  *** *****  *  * *     * *  *** *   ** * * 
    *    *  * * ** *   **  ** **
    
***** ***  *** *** *  ***   **   *
** *   * *** *   * **   *** *  
  *   *  ******  *      *  *     *  **  **   ** * * *****  *     **   *  ********
*   ** * * **** *    ** ** *
    
 **  * * *    *  *  * *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
  ****  *  * * ****  **  ***  *  **  * ** * * *  **   * * 
 *  ** *   *   ****   ** * **** *  *** ** *** *    * * *  **   **
    {
*  *  **  * *****   **   * *** **   ******  * * ******** *** * *    
    *  ***   * *  *  * ***  * *    ** **  **      *       **   
 ***   ** *  *    **** **** ****   ** *  
** * * *    ** **** *  ***   *  ***** * *   
***   *  * **** * *** * * *  *     * * *  * *

   *    *  * *****   * *  *   **
** **   ** * ****     *     * *  *   ** ** *  ** ** ** ****  *** ***   *   * ** ****  **  **   **  * *
*  * ** * * ** * ****  *     *   ** **  ***** ***  *  * **** **  * * * *  *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
*** *  *     *  *   *** **  ** a,b,GCD;
****** * *****  * * * * ** **     ** * * ***  * ***  ** **  *  
    *         **  *** *     * * **** **  *
 * **  *  * **   *** ***      *  
***** * *******  * ***  *  ** * * *   ** * * ****** *  * ***** *  *   *  
   *  **  ** *** ** * **** ** *
 ** *  * ** ** *    * **  *  *   *  ** * *** * *  **   *** *  *** * ***  * *
*** *  ****    ***  ***         * 0;
}
 **    * * *** * ** ***    *  gcd(int a, int b){
 *  * * *   **    **    *  **** ******   * *  ********* (!b) return (a);
  *** *   * * ***  ***  * **** *  *  ****    **  **    **    gcd(b, a % b);
 ******  ** *** *** *   **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *** **** * *
#include ** * *   ******   

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
   ** * ***   **  * **  *   * * gcd, remainder;
 ***  *  *** * **   **** 
  ***  *    **  **   ** * ***  (n != 0)
***  **  ****   ** *   ***** 
 * **      *   * * *  ** ***  *  ****** * **   * **  = m % n;
*  *** ****     *  ** *** *  *   * ****** **  ****    * = n;
*  *  ***   ***  ****** *  **** *  **   *   *** * ** * = remainder;
  * * ***  * * * ******  **** 
***   ** *** *  *  *** * *  *  ** 
**   * * **** *  * ** ** ** = m;
 ***   **  *   **** **** **  *
  ***** *  * **** * * *** *    *  gcd;
}
int main (int argc, const char * argv[]) {
*  * **** * *   *  *  ** ***    number1, number2;
  * **** *   **  *  ***** *  ** ** newNumber1, newNumber2;
*   **  ** ***  ****  ** 
**** *   * * **    *** ****  ***
   ***  *  ** ** ****  * * *  ****     *** ****    *    *  *  ** *  *  ****  * *
 * ** *   * * *   * ***  *** *
 *  ** ***    * ********* *** * **   * ** = number1 / gcd(number1, number2);
***** *    *  * *  ***  *      * ****  = number2 /     * ***  number2);
** * * *    * **  * ** *** **  
 ***   ** ****     ****** 
  *****  *     *   *  *****   ** (  **  ** *
* ****   ****     ***  **  **** * ****  **** * ***  ***  ** ***** ***     * newNumber1);
 ** **  ** *** * ****  *** ** *  * 
 * * * * ******* * ** ***
* ***  ** ***** ** ***     *** * ******** **  **  * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*** * ***  * ** *  ***       a,b,c,d,e,f;
 * *  * * *** **    *     ** *  **  *    *    **     * **   * *     
** **   ***** **   * *       *
***  **** *** *  *  * ** ** * *   
**  * * * *   * ***    **** * *     **
    {
* *  *****   *    ***** ** * *   **      *** * * * *  *  * * 
 *****  ***** * * *  ** * *   *** * ***   ****  **   *   * 
 * *   ***   * * **** * *  ***     ** *  * *   ** * 
    }
*** ***** **    ****  ****       *
    {
** * *** * *** **   ****  **    * *  * *  * *  *****    * ** **  * *
    **  ***  *** *  ***     *   **  *** * ** * * *    *   **  *          *  
  ** ** ****  * **   * ***  ******  *    ***  * *      * * *
   * ***  * *** * *** * * **  *   * **  * * ****  ** *** *  *  ** ***   ****  **
    }
 **** **   * * ****  ****   **  * **
    {
  **  ** *    *    **  ** ** *  ***   *   ****   *    **** *   
 ****  *   **  ***  * **   *     **     **   **   *    * ***     * *
**  *** * * **  *   *    **  * *    *       ** ****  *  *
 ******    *  * *  * * *   ***  ** ***    *   * * ** * ** ***** *  **** *
    }
** *   **  **  ** *** *** *  0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.120.164
©2016-2025

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 14.6k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 14.4k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 18.5k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 14.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users