2 like 0 dislike
17.5k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 17.5k views

67 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,j;

int main()
{
*** * ****** *** **** ** * ** ****** *
for(;;)
* **** *** ****** * **
for(i=1;i<(a+b);i++)
{
* ** * ** ****** * * ** ** * * **
** * ** ** *** ****
* ** * * * * * * ******* *
** ** **** * ** ** ** *
**** ** * ** * ** * ***** ***** *** **** * * **
*********** * ** **
}

i=1;
j++;
if(j==10){break;}
* ** ** ** **** ***

* ** *** * * * ** * * * ** *** * * *** * * ** **
** *** * *** *** * * *** ** ******** ***


}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
** ****** * * **** * *** * * * * * * * *
*** *** ***** *** **** * *
* * * * * * ** * ********** * ****** ** * *
** * ** * ** * ***** * * ** *** ** * * * *
    {
** * * * ** * * * *** ***** ** ** * ***** *** * ** ****
*** * * ******* ** * *** ** * * ** * * ** * * ** **
***** * ** * ** * * * **** ** *** * * ** * * *** **** * ** *** ******* * *
**** * ******** ** ** * ** * ** ** * ** ** ***** * * ** * *****
**** * * * ******* *** *** * * * * **
    }
* * * ** * * * * * * ****** ******** *** *
* ** **** * ** * **** * * *** *** * * **
    else
*** **** ** ** * * ** ** * * * * **** *** ** * * * ** * * *
** ** * *** ***** ** ** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * **** ** ** * * ** nom,denom,i,a;
** ***** ***** ** * * * * * * * %d", &nom, &denom);
*** * **** * ** ***** i<=denom; ++i)
    {
* ** * * * ** ** * * * * ******** *** ** * * ** * * ***
* ** ** ****** * ** * ** ** *** * * * * *** * ** ** && denom%i==0)
** **** * *** * ** **** ** * ** * *** * ******
* *** ** * * *** * * * ** *** **** * * ** * * ***** * * = nom/i;
** * * * * *** * ** * * ** * * * * ** ** **** * ** ******* ** ** = denom/i;
**** * * ** * ****** * * * *** ** * * * * * ************ *** *
*** * * ***** * * * * **** *** ** *** * *** * ** ** ******** ** *** **** * **
*** * * ** * ***** * ** *** * *** * ** * ****** * ** ** * ** * **
** **** * * * ****** * * ** ** ** * * *** *** ** * ** * ******* * ** * * **** **** *** *

* * **** * * * ***** * ** ** * ***** ** *** * **

    }
** * * *** * ** *** ***** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
*** ** * ** * ** ** * **** * nom,denom,i,a;
** * * * * * *** * * *** %d", &nom, &denom);
* * ** * * * ** *** ** **** * i<=denom; ++i)
    {
*** * * * * ***** * *** *** ** ****** **** * * * * *** * ** * ** **
* ******* * * * * ** ** * ** * * ******** *** && denom%i==0)
* * ** ** ** ***** ** *** *** *** * *****
**** ** * * * * * * ** * * ** *** * **** ****** ***** * * = nom/i;
* ** **** * * * ** * ** * * * **** ** * * **** * * * ** ** ** = denom/i;
* * * ** * * **** * * ** *** * ** **** *** * *****
* * * **** * * * * * * ** ** * * * * *** *** *** ** **** **** ***
* ** ** *** *** * ********* ** * ** * *** * ** * ***
** ** * * * * ** * * ** **** *** ** * * * * *** ** * ** * * * ** ** ** **** **

* * **** ****** **** ******** * * * *** * ****

    }
** ** ****** * ** * ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ******* ** * * * ** nom,denom,i,a;
** * * ***** ** * * * * * * ** **** %d", &nom, &denom);
** **** ** * * * * * ** i<=denom; ++i)
    {
** ** *** ** ***** ******* * * ** ***** ** ** * * *
* * ** ** * ** **** *** ** **************** && denom%i==0)
* * * * ** ** * ** ** *** *** * * * * *
* * **** * ** * * ** * ** ***** ** * ** * **** ** = nom/i;
** * * * * *** * * * * ** ***** *** * * ** * * * * = denom/i;
* ** * **** *** * ** ** ******* * * * * * ** * * * ******** *** * **
* ** ** * * *** ***** * * * * *** * * **** ***** * * ** * * * **** ***
* ** * * * * * **** *** ** **** *** * * ** *** * ** **
* *** *** ** ** **** ***** **** ** ** *** * * ****** * * * * * **** * ** ** * ** ** *

** ** * * * * * ** ** * * ***** * ** *** **

    }
* *** * *** *** * ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
* *** * * * ** * ** ** ** *** * * * * *
**** * * * ** * *** * ***
* * * ** *** * * *** * * ** * ** **** ***** ** * ** *** * * ***** **
** ** ** ** ** ** * * ** * * ** ** * * * **
    {
** ** **** * * ** * **** ** * ******** ** * * * * ** *** ** *
**** * * * *** ** * * *** **** * * * * *** **
* ** * * * *** * *** ** * **** * * **** ** * * *** ** * ** ******
* * * ** ** ** * * * ** *** *** *** *** * *** * **** * * * * * ******
* ** * * *** * * ** * * *** * * * *
    }
* ** ** * ** **** ******* * *** * * *** * ** **
* * * * * *** ** *** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * *** * * * * a, b, rem, n, d;

* ** ** * ** ** ***** * * * ** &a, &b);

* *** ******* = a;
* ********* * * *** * = b;

* * ***** *** * *** ** * * *** != 0)
* * * **** **** **
*** * ** ** *** ** ** * *** * *** = a % b;
* * * ** *** * * * ***** ** * * **** **** = b;
* * * ** ** * * * * * ** ************ * ****** = rem;
** ** *** ****** * ***** ***

*** ** *** ** ** **** * % d == 0)
* *** **** ***** ** ** ** ** * *** ***** * * ** ** * * n/d);
** ** *** *** * * * ***
* * * * ******* * **** **** * * **** * * * *** * ** ****** * ** ** * n/a, d/a);

* * * * *** * ** *** 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 17.5k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 17.3k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 22.7k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 17.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users