1 like 0 dislike
8.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 8.1k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * * ** **
#include * * ******
*** * ** * ***
* * **** **** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= **********

* *** * * *** ** ** * **
* ** * * * * *** ***** ** *** * == b[i]){
** * ** ****** ****** * ** *** ** * ****** *
** **** ** ****** ** *

* *** *** **** * *
if (cnt == n){
*** *** ** ***** ** ** ** *** * * ** * * 1;
** * * * * ** * *** *** * * **** **
** ***** * * *** * * * *
** * * *** ** ** * * * * ** * * *** ** * *** * 0;

}

int main()
{
** * ** *** ** s1[100], s2[100];
* *** * ** ** *** * ** i,j;

* * * **** ** * * * ** * * s1);
* *** * *** * ** ** * *** **** * s2);
** * * ** *** * ** (prefix(s1, s2)){

* * ** ***** * * * * * **** ** * ** is a prefix of %s", s1,s2);
* ** ******* * **** * * * * ** ** * * *
** * ****** * * * *** ** * * * ** *
* * * * **** ** * * ** * * * * * * ***** ***** ** ****** * ** * * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
*** * **** * * * * ** * c;
* * *** * *** * *** ** a[100],b[100];
**** ** *** ***** ** *** * %s",a,b);
* * ** * ***** * * ****** * ** ** * *
***** * ** * ***** * ** *** * * **** ** 0;
**** ***** *** * ** * * * * * ** ** %d",strlen(a),strlen(b));
* ** * ** * * * * * * * * *
* * * * * * * * ** ** * * *** * ** ** ** * ** ** ** ** * ** * ** ***
*** * * ** ***** **** * ** ** * ****** *** ** * ** *** ** * * *** **** *** * ***** * * ****** * * ** is not a prefix of %s",a,b);
* *** * *** * * ** * * * * * ** ** * *** * * * * *** *** ** * * * ** * * *** ** ** ** ** **
* *** * * * * * ** * * * * *** * * ** **** * ** ****** *** *
* * * ****** * * *** * ** **** * *** * ** * * * * * ** * if(c==strlen(a)-1)
* * *** ** * * ** ***** * * * **** * ** * * * *** ** * ******** *** * **** * ** * * is a prefix of %s",a,b);
    }
** * ** *** ** *** * * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * ** **** ** * *** n,count;
* ** * **** * ***** * ** ** **** *** * **
*** **** * *** **** * * * * %s",a,b);
** * * * ** *** * *** * ***

**** ** * ** * ** ** * * ** * * ** ** *
*** *** * * *
* ** ** *** ** *** * * *** * **** **** ** * *
* ** * * * ******

* * * * * * * *** (strcmp(a,c)==0)
* ** * * *** * ** *
* *** ** ** ****** * ** * * ** * ** **** ** is a prefix of %s",a,b);
** ** **** * * * * **
** * ** **** ** * ** * ** *
* *** * ** * * ** * **
**** *************** * ** * ** **** * **** * * * * * *** * is not a prefix of %s",a,b);
**** **** * ** *** * * **
* ** **** *** * ** *** ** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** ** **** * * ** * * ** a[100],b[100];
**** * * *** ** *** * ** * * ** * * ** ** **
    int l1,l2;
*** * * ** ** ** ** * *** * *
** * ***** ** * * * ** * * * *
*** **** ** *** ****** * *** * * *** *
* *** * * ** ** * * ** * ***** ** * *** * ***** * * * **** is not a prefix of %s",a,b);

    }
** * * ** * ****** if(l1<=l2){
* * **** * *** * *** * **** **** ***** * *** prefix=1;
*** * * ** * ** ** ** ** ****** * * * ***** * i=0;
* * ** * * ** ****** ** *** * ** * * *** *** **
** * * ** * ** **** * * * ** *** ** ******* **** *** * * * ** (a[i]!=b[i]){
* * ** * *** ** * * * * ** * ********* ** ***** * * ** * ** *** * *** * * **
** * **** * * **** * ** ** * *** *** ** **** * ** * ** * * ** * *** ** * ** ** ****
* *** ** * * ***** ***** * *** ** *** ** *** * * *** *** *


** **** ** * * * * * ****** *** ** ** ******
* * * * ** ** * * *** * * * * ** ** * *
* * * ***** * ** ** * * *** **** * * * * ** * * * ** *** **** is not a prefix of %s",a,b);
* * * * * * * *** ** ** * * ** *** * *
* ***** * * * **** ** *** ** * ** * * * **
***** ** ** ** **** * * * ** * * *** * **** * * ** ** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
****** * ** * ******** *
int main(void)
{

**** *** * * * ***** *** ** pre[100];
** *** **** **** ** * word[100];
* **** **** ** ** * * ** * %s",pre,word);
** *** * * * * ** * * * **** **** ** ****
*** * *** * ** *** * * *** ***** *

*** *** ** * * ** * ** * i;
* *** * * * * * ** * * **** **
** **** *** ** **
* **** *** ** *** * * * *** * ** * * *** ** * * **** * ** **
* ** * * *** ****** * * ** * ** ** *
** * ******* *** **** *** * *** ***** * * **** * * * * * * * is not a prefix of %s",pre,word);
***** * *** ***** ** **** ***** *********** *** *** * ** ** **** *** ** * ** * 0;
* ** * * *** * *** ** ** ** *** *** *** *** * *

*** **** * **** ** * * **
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** ** * * * *** ** ** ** pre [100],a[100];
** * * ** *** * ** *** * n ,i;
* * *********** **** ** * *
*** * * * * ** * * * * ** *
* * * * * **** * * * ** * * * *
* * *** ** ** **
* ***** * * * ** * ** ** ** ** * (n=0;n<strlen(pre);n++)
* * ** **** ** * * ** ** * * * ** ** * * *
* * * * ** * *** * ** * * * * *** * * ** * **** ** (pre[n]==a[n])
***** ** ** *** * **** * * ** ** **** ** *** * ** * * * * ***** * * ** * is a prefix of %s",pre,a);
**** *** ** *** * ** ** ** * * ** * ** **** * * *** * *** * ** ** *
** * ** * * * ** *** **** * ** ** *** * * ** * ***** ** *** * * ** * **** ***** ** ** * **** ** is not a prefix of %s",pre,a);return 0;
* ***** *** * * *
*** * * ** ** ** ** *** * ** ***** * ** * ***** * ** **** * ******

** * *** * ** *** * * * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** ******* **
#include * * * * **

int main()
{
** ** ** **** ** * * * a[100];

* * * *** ** * * ** ** b[100];

* **** * ** * * ******** * **** * %s", a, b);

* **** * *** *** *** * len_a = strlen(a);

*** ** * * * * * i = 0;

** * ***** * * *** * * flag = 1;

** ** * * * * *** * *** * = 0; i < len_a; i++)
* ****** * * *
* ** *** **** **** **** *** *** * ** ** * **** *** != b[i])
* ****** * * *** *** * ** * * * ** ** **
**** * ****** ** * * **** * *** * * * ** ** *** * *** = 0;
*** * ***** * ** ** * ** * * * ** * ***
* **** *** **** ** *** ***

* * * * * * * * **** * ** == 0)
** **** ** ** ** *
* ** ***** * * * * *** * * * **** * ****** * * ** * * * ***** is not a prefix of %s", a, b);
* ** ** * ** ** ** * *** **
* * ******** ** ** ***
** * * * ** * *** *
*** *** ** * * *** * ** * *** *** ** * ** ***** ***** ** is a prefix of %s", a, b);
** * * ****** *
* * ** ** * * **** ** ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** *** * ** * *
int main()
{
* * ** * ** i,n;
* * * * * ** * **** *** * ** p[100],s[100],a[100]={};
* ** * * * ** *** ** * * ** * * %s",p,s);
***** * * * * ** * * *
* *** *** * * ***** * * *****
*** **** ** * *** *** *** **** ** * ** * ** * ** *
* *** *** ** * * *** **** * *
* **** * **** * * ** * * ** * * * ** ** **** * * *** * is a prefix of %s",p,s);
** * * ** *** * **
* * * ** * ***** * ** * *****
* * ** ** * * * * * * * * * **** * * * *** * * * * ***** is not a prefix of %s",p,s);
* * * *** * ** *
** * *** *** ******* * * ***** *** ** ****** *
* ** * * * ** * *** ****** * * ** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* ** * ** ***** ** ****** **** ** * ** *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* ** ** ****** * * * * ** ** * **** * * **
** ** * ** * ***** * ** ***** * ** * *** ** * * * ** ** ** ** * != b[i])
* ** * * ** * * ** * ** * ** ** * **** * * * * ** * ** ***** * *** * ****** **** * ** **
**** ** ***** ** **** * *** *** * * * ****** *** ** * * * * **** ** * *** ** * *** ** * * ** ** ****** ** * * is not a prefix of %s",a,b);
* **** * * *** ***** ** * * ** ** * ** * * ** *** * ** ****** *** ***** *** * ******** * ** * * * **** **** *
** ***** **** * *** *** ** * * ** ** * * ** * ***** ***** **** * * * * ** * *****
* ** *** * * ** * * ** *** * *** *** ** ** *** * ** ** *** * ** * * == b[strlen(a)-1])
* *** ******* * ** * ** ** * *** ** ** ** ** * ** * * ** * * *** * ***** * * **
* ***** *** ** * *** ***** * * ** **** * * * * * * ** * **** * * *** * * * * *** * * ** * *** ** * ** * * ***** * ** **** ** is a prefix of %s",a,b);
** * * * * ** *** * * ******* ***** * * * * * * * * * **** ******* * ** * **** * * ********* * ** * * *
**** *** ** * * * * ** * ** ** ** ** * ** * * ** ** *** *** * *** **** * * * ***
* * * *** * ***** * ** * ** * *** * *** * *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* * ** *** ** * i;
* * *** * * ***** *** *** (a[0]!=b[0]){
** * * ** ***** ** ***** * * * * **** * ** 0;
* * ** * *** ** **** * * ** * *
** *** ***** ** * *** *** * * * ** ***
* ** *** * * * * * * * * **** ** ****** ** * ** * *** ** a[i]==b[i])
* *** ** ** * * ** ** ** * ******* * * * ******
** * ** **** * *** * * * ** * * ** ** * * ** *** * ** * *** * * 1;
*** * ** * * * ** ** ** *** ** * * *** * ***** * ** * ** ***** **
** * * *** * ** * **** **** * **** ** * *
* ** * * ***** * * * **
* * * * ** * * * * * * * 0;

}

int main(){
* ** * * *** ***** *** * c[n],d[n],e[n];
** * * ********* * i;
* ** * * *** *** ** ******* ** %s",c,d);

* ***** * * * * * *
**** ** * * * * ** ********* *** ***** ** ** * ** * is a prefix of %s",c,d);

***** * ** ** * * *******
**** * ** * * ** ** * ** ***** *** * * * ** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.135
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.4k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.3k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.4k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 6.5k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users