1 like 0 dislike
18.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 18.1k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * ** * * *
#include * ** **** ***
***** * * * **
* **** ** ** **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** ** ** **

*** **** * * **
*** * ** * *** * * ** * * == b[i]){
* * *** * * ** * ** *** * ** **** **** * * **
* ** * * * ** * ** **

* **** * *** *
if (cnt == n){
****** *** * * *** * * * *** ** ** ** * * * 1;
** * ** *** *** ** *** * *** * * * *** ** * *
** ** ** ** ** *** *** ****
** * ***** * **** *** ** * * * ** * *** 0;

}

int main()
{
* * * * * * * * * ** s1[100], s2[100];
* *** ** * * ***** i,j;

* ** ** * * ** ******** s1);
* * **** **** ** * * s2);
* * ** * * * ** * (prefix(s1, s2)){

***** * *** * *** * * **** * * *** ** *** **** ** * is a prefix of %s", s1,s2);
* *** * * ** ** ** ***** * * * * * * ** **
* * * * ******** **** **** * * * ** ***
** * ** * ** * ** * * * *** * ** ** * ** *** * * * * ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
*** * *** ** ** **** * *** * c;
** * ** *** * * * * ** a[100],b[100];
*** ******* * ** * * *** * ****** %s",a,b);
* ** ***** * **** * ***** * *****
* * * ** ** * * *** * * * * ** *** * *** * ** 0;
* * * * * ** **** * * * ** * %d",strlen(a),strlen(b));
*** * ** * ******* * * * * ** **
*** *** * ** **** *** *********** * ** ** * * *** * *** * ** * *** *
*** ** * * ** ** * ** ** * * **** * * * ** * *** * * * * * * ** * * * * ** ** * * * is not a prefix of %s",a,b);
* * ****** * * * ** *** * * * ****** * ***** *** ** *** * * ** * **** * * * * * * * * * **
** ** * * *** * * ** ** * * * * * * * * * ** ** * * ** *
* * ** * * * *** * * * * ** **** *** ** * * * * ** * if(c==strlen(a)-1)
* ** ** * ** ** *** * * *** ** * * * **** *** * * **** * * * *** * * ** * * ** * * * * is a prefix of %s",a,b);
    }
* * *** * ** ** * ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * * ** ** * n,count;
*** ******** * ** ** *** * *** * * *
** ** ** * * * * * ****** * %s",a,b);
*** * **** * *** * ** * *

* * * *** * ** * ** * ** *** ** ** * *
*** ******* * ** * * **
* * * * * * * ** *** * * *** ***
* * ** *** ** ** *

*** ** * * *** *** (strcmp(a,c)==0)
* * * * * *** ***
* * * * ** ********* * * * * ** ** ***** ***** is a prefix of %s",a,b);
** * ***** ** **
* *** ** * ** **** *
* * **** * * * * *
* *** * * ***** ** * ***** * * ** ** * ** * *** * is not a prefix of %s",a,b);
*** ** ** ** * * ***
** ** * * ** * *** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
*** * * **** * ** * ** * * a[100],b[100];
** * * **** * * ** * ******** * * * **
    int l1,l2;
** **** ** * ** ***** ** ****
* ** * * **** ** * **** ** *
** ******** *** *** ***** * **
****** ** *** ****** ******** ** * ** * * * * ** ** * * is not a prefix of %s",a,b);

    }
** **** * * ** * ** if(l1<=l2){
***** **** * * * * ****** * ****** ** ** * prefix=1;
***** * * ****** ******* ** * ***** * **** i=0;
** ** ** ** ** * ** **** ***** * * *** * * ****
*** * * *** ****** * *** ** ********** * * * * * * * * * * * ** * * ** (a[i]!=b[i]){
* * ** *** ** **** *** * *** * * ***** ** * ** * * * * *** * * * * **** * * * * ** *
****** * * * * ** ** ** * *** ** ** * * ** * * ***** **** * * **** * ** * * **
** * * *** ***** ** ** * **** ** * * ** *** * * *** * * ********


** * * * * * * ******* **** ** **** ** ** **
* ** **** * * *** *** * * *** * * * *
** ** ** * ** *** *** ** ** *** * * * * * * ** * * * **** * * is not a prefix of %s",a,b);
* * ** *** * * ** ** *** * * *
* ** **** * ** * * * *** * * * * *** *********
* ** ** ** * ** *** **** *** ** * **** ******* ***** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * ** **
int main(void)
{

** * * ** * * * * * pre[100];
* ** * * * ** ***** word[100];
* *** **** ** *** * * * *** %s",pre,word);
*** * ***** ** *** *** * * ** * * *
* ***** * * * ****** ***** *

* * ** ** * * *** ** ** i;
* *** * *** **** * * ** * *** *** * ***
* * * ** * * ** * *
** ***** * * ***** * *** * ** ** *** **** * * *
* *** *** * * * * *** **** * *** ***** * *
** *** * *** ** ** * * ** *** **** * ** ** * * ** * * * * ** * * * ** * ** * is not a prefix of %s",pre,word);
* * * **** ** * ** *** * **** ** ** ***** ***** ** * * *** * *** 0;
**** *** * * *** * ** * ***** * * * *** ** **

** *** *** *** * * *** *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * * *** * * *** pre [100],a[100];
* * * * *** * * *** * n ,i;
* ***** * * ** * **** **** *** * * *
* ** ** * ** * ****** * *** * ** ****
** ** *** * * ***** **** * * ** ** ** ** **** *
*** * *** ** *** *
*** *** * * ** ** ***** ** * ** * * ** * **** (n=0;n<strlen(pre);n++)
*** ** ** ****** ** * *** * *** * * * * * * *
** *** ** *** ** *** *** * ** ** ** * * * ** *** ** * * *** * * * (pre[n]==a[n])
* * **** ** * ** * ** ** * * **** ** * * *** *** ** *** *** * ** *** * ** is a prefix of %s",pre,a);
*** ** ** ** * *** * *** * *** *** **** **** ** ***** * ** **
** * ** * ** * **** * * * ** * ******* ****** ** * * ******** * * * * * *** ** * * ***** is not a prefix of %s",pre,a);return 0;
*** * ** * ***
* * ** * ***** * *** * ** * *** *** * * * ** * *

* * * *** * * *** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include *** * * * **
#include *** * *** ****

int main()
{
** * * ** * * *** * * ** * *** a[100];

* *** **** **** * *** * * b[100];

** ** * **** * ***** * * ** *** %s", a, b);

** * * * *** * len_a = strlen(a);

* *** ** * ** ** ** * *** i = 0;

* * * * *** **** ** ** * flag = 1;

* ** **** * ***** * ** *** = 0; i < len_a; i++)
** * ***** * * *
* ****** ***** * * * * ** * ** * ** *** * ***** ** != b[i])
* * ** * *** ** * ** ** * ***** ** * * * * ** **
** * * * ** * *** * ** *** * * * * ***** * * ** ** ** * = 0;
* * ****** * *** ** * ** * ** *** *** **** *** ** *
** * * * *** * *****

**** *** * ** * * *** ** == 0)
** * * * *** * ** * *
* ******* *** ** * ** * * * * ** * * * ** *** is not a prefix of %s", a, b);
** * * * * * * *
**** **** ** **** ** * *
*** * *** ** *** * **** **
* ** ** ** * * ** ** * *** * * * * * ** ****** is a prefix of %s", a, b);
* ** ** * * * * *** * ** *
** * *** ** **** ** ** * *** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * * ** ****
int main()
{
** ***** *** ** * ** * * i,n;
***** * ** * * ***** p[100],s[100],a[100]={};
***** **** * * ** **** ******* %s",p,s);
* * *** *** * * ***** ****
***** * ** *** *** *** * *
*** * * * ** **** * *** * * * ******** ** * *
** * ** ** *** * ***** * * * ** **
* **** ** *** ** * * * * ** *** * * ** * *** is a prefix of %s",p,s);
** **** ** * **
* * * * * * *** * *** **** *
* ** **** ** *** * * * * * *** * **** ***** * ***** is not a prefix of %s",p,s);
* ***** ** ** * *
* **** * *** ******** * *** ** ** * * * * *** **
* * * *** **** ** ***** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** * *** ** *** *** ** * * *** ** * **** ***
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
***** * * **** ** * * * ** * * * ** * * **
* *** * * * * ** *** * ** ** ** ** * **** * *** * * * **** * *** != b[i])
* *** ******* *** ** **** * * * * * * * ** *** ** *** * * * ** ** *** * * * ** *** * *
** * * * ** * ** **** * * * ** * *** * * ** ******* *** * ** ** * * * ** * * ***** ***** ** * * * *** * * is not a prefix of %s",a,b);
* ** * * * * * * * ** * **** * *** ** ** * * * * ** * *** * *** **** ********** * * ** ** *** * ** ** **
* ** * * *** * ** * * * * ** ** * ** ** * * * * *** **** * * * ** * * *** ******
** * * ** *** ** ** * * * *** ** * * * ***** * ***** ***** * ** * ** * == b[strlen(a)-1])
*** ** ** ***** * * ** * * * * *** *** * * *** *** *** * ** * ** * *** ** *
** * * * * ** ** *** ** ** * * ** * * * ******* * ** ** * * * * ** * ** * **** ****** * ** * * * is a prefix of %s",a,b);
* * * ** * ** * * * * * * ** * * * * ** * * ** * ** ** ** * * * *** ** **
* * *** ***** * ** *** ** *** * * * * * * * ******* * ** ** * ** * ** ** * ** **
* ******* ** * ** ** *** * ** ***** *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* * ** ** ***** * * * * ** i;
* **** ****** * ** * (a[0]!=b[0]){
* ** * * **** * **** * * **** *** * ** *** **** 0;
* **** * * * ** ***** *
* **** * *** * * ******* **** ** *
* ** * * ** * ** ** ***** * **** * ** ** * * a[i]==b[i])
* **** *** ***** * ******* **** * ** * *
* ** ** * * ** ** * * ****** **** *** ***** ** *** * * * * ** ** * *** ** ** * * 1;
*** * * * * * * * * * * **** ** *** * ***** *** * * ** * ** * * ** * *
**** ** * * * ** * **** ** ** ** *** *
* ***** * ** * ******* **
*** ** * ** * * *** ***** *** * 0;

}

int main(){
******* * **** **** ** c[n],d[n],e[n];
****** ** * ** * *** * i;
* * *** ******* ***** * ** **** %s",c,d);

* * * ********* ******
* * ** ** **** * * ** * * * *** **** ** ** * is a prefix of %s",c,d);

* *** ***** * ** **
** * **** * * * * * * ** *** * ** * * * * *** *** ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 16.7k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 15.6k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 19.4k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.5k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users