Final Exam 2 (20%)

1 like 0 dislike
14.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 14.9k views

37 Answers

0 like 0 dislike 
Hidden content!
#include   ** ***** *** *  *
#include *    *  * * *   
  **  * **** * *    *  * 
***     ** * *** *****  

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= *  ** * * *   

** *** * *** ** **   *   * * *   **  * ** *
*  *     * **  *  *****         ** == b[i]){
*  *  *** *** * *** * **     * *    * ***     ** **  * *   *
*       **** ***** * * *** *

** *********  *   
if (cnt == n){
* ****    *** ** *  * *  * *  **  **   *  *  ***** ***   1;
* *  * ** *** ** ** ** *  *   * *  * *****  * *** ***  
**   * ** **  ** ******  * *  **
    * **** *****      *   * ****  * * **  ** * * *** *  0;

}

int main()
{
  **  * * ** * ** **  s1[100], s2[100];
   *****   ** ***  ** i,j;

**  * * * ** * *** **  *   * ** **   **  s1);
*  *  **** *** ** **     * * **   *  *  ***   ** s2);
     ********  *   ***** (prefix(s1, s2)){

**  **  * **** **  * **  *  *  *    * **** *** ***** is a prefix of %s", s1,s2);
**   ** ** ******* ** **  *   **   *   *  * *
   *     *** ** ** *****   ** **  **  *  ** * * *   *
 ****** *** ***  ***   *    **  ***     * *  *** * ****   ****    *      *  is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
  * **** ** *** ** *    *   c;
**  * **   ** *  **** ** *  * a[100],b[100];
*** ** *  ** * * ** *      **  *     ** * %s",a,b);
**    *  ** *  **** *   * * *  * ****** ***
  *  * *** * *  ** *   *  *  ***   ***** **        ** 0;
* * * *   * ** *    * **   **   *   %d",strlen(a),strlen(b));
* ** **   ***   **  * * * *  ***   ***    **** *
***** ****  * ***** **  *  ***** *    **  *  *   ******       *    * *** **** *** *  * *  
   **** ** ***** *  **** ** **    * * * * *********** *    *  **** ***  *  ****** **    ** * *  ** ****   **    *** is not a prefix of %s",a,b);
* *          *****  * * * ***   ** ** *  * ***  * ** *     ** **       ****    *       * **  *   * ****  *   **  
      **      ***   ** ** **  *** * *   * *   *****  ******* * * * *  *  *  * ** * 
***  * ** *    ** ****** ***  * *    * * ** ** * * * *     ******  ** * ***** *  * * **    if(c==strlen(a)-1)
 *** *  *  * *    **** **   * *******   *   ** ********  ***** *   * ** * * * *    ** * * *    *   **** * ********       **  is a prefix of %s",a,b);
    }
  * *  *  *   *   *    * *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 **  **    **    *** ** * n,count;
***    *       ***    ** ***    ** *   * **    
  * *  * *  **    *  *** ***  ******* * %s",a,b);
***    * *** * *    *  * ** **** *

 ******   *** * *****  *  *******   **   * *
** ****      ** *     
*   *** * **** * *      * ***  **** *   *** * ***  **** ** ** * 
* *** *  * ** *  ** *   *  ***

   *  **  ** *** **    *  (strcmp(a,c)==0)
  * *** ** * * ***** *** 
* ** **    **   **   ****** * *** *** *** *   **   ** *  * *    *  is a prefix of %s",a,b);
    **** **   * *** * *  ** 
  **** ****** *   ** *     ***
    **  **  *  *      *** * * *
* * ****** ****  *   * **  **    *** *  * *  *  ****  *     ** **   is not a prefix of %s",a,b);
   **  * **  * * ****  *  * 
   * ** * *     **  **   ***   0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
  *    * ****             *** *  a[100],b[100];
   ** * * ***     *    ** ***    *** *    ** * *   *   
    int l1,l2;
* *  *  *  *   *   * * * ** *  * **   *
* *   ** ** **   **  ** *  ** *  **  *
 **  *****      *    ** ** *** ***  
***    * * * * **  **  **  * **   * *** * * ** *   *    *      *  is not a prefix of %s",a,b);

    }
*  *   *     ** ***  *  * * ** if(l1<=l2){
 *  *****   *    *  ****     ** **     ** ** *** *** prefix=1;
    ** *  ***** *   *    ** *** * *  ** *** **  ** **   i=0;
* ***   ***     * ****   ***  ** *  *   **     *** * ** ***   *     ***  
*   *** * **    *** *   * * *** *    *** ** *  *** **** ** **   ***** **     * *  (a[i]!=b[i]){
  **  *     *  *  *   *  ** **    * *  *  *** ** ******** ** * * ***** *** * ***  ** * *       **** **  *  *** ****
   * ****  * *  * *  * *  *     *** ** *   ** **** * ***** ***** **  *  * ** **  *** * *****  ** * * * *  **   *
*  * ****   **  *      *** * *  * * **** *  *   * *   *     *******     * *   


    ** *  ***    * **** *  ***    ***  *  * **  * *** 
*   *  * ***  * * **   **   **  *   * * **** ** ** ** ** * *** 
 ***       *****    **** ** * *  *** * * **       *** * * * *** * * *    **  * **  ***** **        is not a prefix of %s",a,b);
  ** ** ****   * *** * ** * **   **** * * **** **  
*  **    *  ** ** * ***   *  * * *  **   **** ***   * * **
**** *  ***    ** ********  *    * ***  * *      * **    * *********  * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
* *  *** * * *       
int main(void)
{

   * ***  * * **  *   ** * ***** ** pre[100];
***    ****     ****   ** *  word[100];
**    ** **   *** ** ****     **  *  * *   %s",pre,word);
* * *    * **     *      * *  **  **  *    
**** **** ** **  *** **   **** *   ** *  ** 

 *  * **  *****      * ***  i;
   ** ***    *      *  *   * ***** *  *   * * **   
*** * *** *   **  * **** **  ***  
 ** *    ****       **  * * ****   *      *** *       ** **   ** *****
*      *  * ***   *  *    ** **  ** * **  ** *  * * 
* *** ****  **   ***    * ***  * ****  *   * ***   **  ***    **         ****   ** is not a prefix of %s",pre,word);
** * **  *  ***  *** ***       ** *   * * *   * **** *     ****** *     ***    **  * * 0;
  **    * ** * *    **  *      *  *** * **  **** *** 

 *  **   ** * ***  **     
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
   ***  **  ** * *    * *** *  pre [100],a[100];
 ** ***   *   ***  ** *** ** n ,i;
*  ** * ** *   **  * ** **  * *** *  * * * 
**   * *   * ** **** * * ***  ***  * *  
       ** ***  ** ** **   **   * *   ***   **  * ***  
 *  * *  **   * ** *  * **  **
****  *****  ***  ***    ** ***  **  *** *** * *** ***  * (n=0;n<strlen(pre);n++)
  * ***** ***   * * ** ************  *  * *****
    **    **   * *** ***** **  *   **  ****  * *  *  ** * *    * ***** *  * **** **  (pre[n]==a[n])
**  ** *** **** *  * *   * * ****  *** *** *  * *  ** ***  * ** ** **  *   * **   * **  * *****   is a prefix of %s",pre,a);
 ***  * ****  * **   ***   *  *  * **    **** ***   *** ***   *   ***   *        * * *  *
 *** ******** * * * *****      *****    * * *  *   * * *    ****  **  *   ** *   ***    **  ** * *****   **  * * * *  is not a prefix of %s",pre,a);return 0;
** *  *  *   *    **  ***  * *
  * **** *   *  ** **  *** **** * **     * *  * ***   *  * *   * * *   **

  ***   *  **  **** **** *  0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *  **   **   ****
#include  ****    **** *     *

int main()
{
   **** *   ** **  *** ** * * ** a[100];

 *  ***   *    ** *******  b[100];

    ** * **   ***    ***** * * *  %s", a, b);

*  ***  *** ** **   ***  **** len_a = strlen(a);

** * *** *    *** *   *    * i = 0;

* *   **   *  ** ***  ***** ** flag = 1;

*  ** * **  ****** ****  = 0; i < len_a; i++)
*** * *  ** ***     **** *
*  * *     *** **  *  *   * **   * *    *** *** ******  * != b[i])
*   *** *     *   ******   ***********  ***    **   
** ******* ** ** * *** *      * * *  *  * **  ***  *   * * *  *  * **  *   ****** * ***    = 0;
*** ***     ** ********* **  ** ***  * ***  ***** *****  * ** 
 **   **  ** ** * * ** * *

 ** *  *  * **  ** ***     ***   == 0)
     ***  *  *** *  ****** *  *
**    ** *   ******  ** * ****** ****  * * ** *  * *  *    ******* is not a prefix of %s", a, b);
 **  ***  *  *  * ****  * * 
** **  *** * * ** *** * **** **   
**  *   *  ** *  **** ***** *
* *   ** ** * **  **    * *  *****      **   *** *   **** * *     *  is a prefix of %s", a, b);
**   * *   *  * *  ********  
  ***  * **   **  *  *** * *** * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
**  * ** **  **   *
int main()
{
   ** ***** *    *   *  **  * i,n;
*** * ** * *  ** * *     *   * p[100],s[100],a[100]={};
 * *  **  * * *   *  *** *    *      %s",p,s);
 *  * * ****   * ***    ****** *  *  
 ***** *  * **  *   *   *   **   *  
*    * ***  * * **    ******  ** *****   *   * 
** **** *   * * **       ***   *** *  
* **  ***** *  *  ** ***  ** *  * **   ***     ** * * ***   *  *  is a prefix of %s",p,s);
  * * *    *** **   ******
    *** **   * * *** *  * 
*  **  * **** *  **  * **   *** * **** ** ** ****   * * *******      is not a prefix of %s",p,s);
*** **     *  *  ** ** *** *** *
 * *  *  **      *** * *****     *    ** *** * * * *     ***
  * *  *      *  ****  * *   0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
*  ***  **    * ** **** *   *  **  ** ** ******        
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
*     * ** **  *  *   ** ***   * * ** * **   * *  *  
 **  * ***** *** *   *** *  *    ******   *  ** *    *****   ***   * ****  *  ** * * * * != b[i])
  ******* *** *  *  **** * *  **  *      * ** * **  ****  *   **   **     *         **  *  * *
* *** ***  *   *******    * ***     * *  ** ********    * *  * ** ** * *** *** **  ***  ** *** *  ****** ** *  * *   *  *   *  *   * *** *** *  is not a prefix of %s",a,b);
 * *** *****     ***  * *** * * * *  * **     *    **** *  * ** ** **  * *****  * * ***   **  **  ******** *  * * **  *  **** *  ** *    **  *
**    **  ******** * *  ********  ** *  * ** ***  *** *** **  *   * ******   **  ** * * *   * ** *   * *    ** *****  * ** *
  ** ***** ***** **** *       *  **   ***** *****  ***** **** * * ***    *     ***   *     ***   * == b[strlen(a)-1])
    * *   ******** ***  * * ** *             * ** ****** * ***  ** * *    *  ***    ****   ****** ***  *        
 ****  **   **   ***  ** ***    *  **  ** **   **** * ***** ** *  ****    **   * * *  * * *   * *****  **  *   * * **  ****  * **   *  ****  *  *  is a prefix of %s",a,b);
 **   **** **  ****** ****** *****  ******  *   *  ***** **   ****   ** **     * **     * *   ** ****    *     * *  **  * ** *   *       *  * * 
** *  ** *** *  *    *  ******* **    *   *   ** ** ** * ***  ***  ** ** * *        *  *  * * **       *  ** **
 * * *  ** ** ***   ** **     *  * ***   *  **     *   **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
   ***** ***   * ** **    *   * ****  i;
  *  *   *   ******  ****    * ** (a[0]!=b[0]){
*  * ** *  * *** *  **  **    **   **  *  *   *  *  * **  * * 0;
  * ** ***  * **   *  ** * *        
* **   ******  *  *  *   ****   **  ***   *   *  *
* *  **     * ** *   *   ** *****   *    **   *     ********   **  a[i]==b[i])
  * *  *  *  **  **  * **  ***   ***  ***** **  ** * **
** **   * * *** * **** * * *   ***    **  * * ** *  * ** * *** * **    *   ** *** 1;
   ** *      **     * ** **    * ** ** *** ** ***** ** ** *****  *  **** * ***
*  *** *     **  *****     *  *** * ** **        **** **
    *** ****  * **  ** ** **   ***      *
   **** *** * * *  ** * *  ** * **  **  * 0;

}

int main(){
  **       * * ** * ***  * c[n],d[n],e[n];
 * ***  *  **    *  ** ** *** i;
 *** ** * ***    ***** ******     %s",c,d);

****** ****  *  * ** *  **  ** * ** 
 **    **  ** **    ** ****** *     **** **  *   * ****  ** ** *** * is a prefix of %s",c,d);

**** *** **** *  ** ** 
 ** ***  *   *  *   * ** *    *  **   ** ** * **  *   *** *  is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 13.7k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 12.9k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 16.2k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.2k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 2.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users