Final Exam 2 (20%)

1 like 0 dislike
11.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 11.2k views

37 Answers

0 like 0 dislike 
Hidden content!
#include *  ** **   *
#include  * *  *** ***  
*  ****** ** **     ***    
 ***    * ** ** *  * *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ***  **  ** **

 * **** **  *  *  *    *   ****** ***  
 ** * * * ** * *   * *    *  *  == b[i]){
*** ****   **  *   * **      **  * **** * ** * ***   ** * **
  *   *    *  ** *  **

**  *   ****  *** *  *
if (cnt == n){
 * * * *  **    *******      *  ** *  ** *  ** **** 1;
* ** * ****     * *** **   *  ** ** *  ***  ***    
*****         ** *    ***   
** *********   ** *** * **  *   * ** * * ** ** *   * * 0;

}

int main()
{
**    ** *  ** * **   s1[100], s2[100];
**  * **  * *  * ** i,j;

**  * **** *** *** * * **  *     ** **   s1);
*  * **** ***  *** *****   *  ** * * *  ** ** *   *  s2);
*** *  ****  **** * *   (prefix(s1, s2)){

  * *   * ***   **      *    *  ** *  *      *  **   *  ** * * is a prefix of %s", s1,s2);
*  *  *  ****** * **   *** * * *** *  *  **   
****** *    * ****   ****      ***** ***    ***** 
*  ***       **    * **      * *****  * *  *  * * * **     * *  *    * **   ***** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
  * **  * *  *****  **  *  c;
   *     *****  *   *****  *  a[100],b[100];
 *** * *   *  **  * * **** **   * ***** %s",a,b);
     **** **** *   *** ** ***   *  **    * *   **
    ***** * * **    * **** * * **** * * *** * *     *  * *** 0;
     *  *** ** * ***** *   ***   * *      %d",strlen(a),strlen(b));
 *   *******   ** **     **         * * *** *  
  *** ***   * ** * ** ** **    * *** * * * ** ***    * *   *  *** *******  ***  *   
 ***** **   * *  * *** *   *  **   *   ** ****  *  *** ****  *  *    *  * * *           * * ** ** *  *   ***  ****   **   is not a prefix of %s",a,b);
**     *  *  **  ** ** *   *** * **    *    *   *    ** *  * * * ** * **    ***   *** ***   **    ** * ****  **   
*** ***  *** * *  ** ** **   * * * * *** *  * ****   * *  *   *  * *  **  *  * *  
    ******  **    * * ** *      **      * **  ***   *** **  ***** * *  * * *     if(c==strlen(a)-1)
 ** * * * ******** ** ******** ***  *****   *     **** *  *   ***** *    * * *   **   *  ** * * * **** * * ****   ****** is a prefix of %s",a,b);
    }
** * ****    ***   ** **   **   *    0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
  *** *   *** *      * * * ****  *   n,count;
* *   ** *   ***  ***  * * * *** * *      * ** *   
* ** *** *  * **  ** *****  *      %s",a,b);
  *  * *  *****  **    *  **** **

      * **   ****** **  ** ** ** **** **    * ***  **** ** * ***   
 **   ** **      **** * * ** *
*  ***  **** * ****    **     **   ** * *** **    * *****     *
  **   **** **  ** *        * *

********  ****        *   ***** (strcmp(a,c)==0)
*   ***    ** *  *     *    *
  ** *  *   *  ***   ***** * ***** *** * * *  ** *** *  ***  is a prefix of %s",a,b);
   **   * * **** ** * * *   *
* *  ** *  **   *  *   * * **   
    ** ** *      **** 
* * ****  ** **  ***   *  *** **  ***      **  *     * * *    * is not a prefix of %s",a,b);
  * *** * **  **** **    * *  *
  *   **** ** *    * * ****** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
******  **  *   *   *    **  a[100],b[100];
 *  *** **  *** *** ***  ** * * ******  *  *    
    int l1,l2;
 ** *    *  **  * ** ** *    * **  *
*       ******  **    * *  * ******
**  *     *  * ***** **  *  *  ***  *****
* ***  ** *   *******     * **  *  **** *  *  ***  * *   is not a prefix of %s",a,b);

    }
 ** * * *****  *     *   * ** if(l1<=l2){
* ***** *  ****** *   ** **    *   *** *  *** ** * *   prefix=1;
*   ******* **  * **   ** * * * *  * *   **   **   i=0;
 *     *    **  **** * *** *** *****     * **  **  **  * *   **** 
 **      ** *  **  *     ***    **** * *  *** *   ************* ****  *** ** ** *** (a[i]!=b[i]){
  ** *   * *******  *   * * **  ** * **  ******  ***** *   *******   **  *** **   *  *   *  * **    * *
*****   * *     ***   ***   *    ***  *   * ** ** *  *** **       **  * * *** * * * ** *  * **  **  ** * *    
 *  **  ***  * **  * *  *****  ***  **    *    ** * **  **     **  ** * * * * *** * 


 * *  ***  **    **   * *     *  **   ** ****** *  **
 * **     ** *   *  ***   ******** **** ****** **  ** **     * *
   * **   * ****  *      **** * *  ** * ***  *** ***     *  *  **  ** *** * ******  * * is not a prefix of %s",a,b);
* *   ******  *  *   * *   ***** * ****** *  * * **   * 
*   ***   * ** * ****       *    *        *  ***   *** ** * **  
*   **** * ** *  * *  *** *   * *  **   *   **  * ***  * *  * *   is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
** **  **** * **  *   
int main(void)
{

* *  *   ** **  * *   * **  ** pre[100];
  **  * * ***  *  *****  * * * word[100];
 * ********  ** *   * * *  *  * *      * %s",pre,word);
 *** *    * **    **    ***** *  *** **   **   *
 * **  **  *  **    * ****    *     **   * *    * 

 *   **  * **  * *     ***   * i;
     ***        * ** *         ** * ***   *   ** 
 ** *****   *  ****  *  
 * * *   **   *  *  *** *   ** **** * * *   **   *    *  * *   * *
*  **  *     ****** *** *   ****  *   * *  **  **  ** * *  
  ** *  * * *   *** * *** * **** *      *  *  * * ***** * *    * **        ******* * **  * is not a prefix of %s",pre,word);
   * * ** ***   * ** * *** *   *******    * ***       *   *******   *  ****** 0;
  *     *    ***   * * * ** * ***       *****  *  **  **

  ****  ****   ****  * **    
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
 **** ** ** *  ***     **  * * * pre [100],a[100];
 *        *** *  *** *   * * n ,i;
 * **  *  * * ** *  *  * *   * ** ***
    *  *   ***  ** * **** ***   **  
* *  * * * * *** ** **    **  *   *** *  * * **
* * * **    ***  *** **  * *
* **  ** * ** **  ********** ** *       * ** *** * ** * (n=0;n<strlen(pre);n++)
* * ** **   *  ***   *** *  * **  *  * **  **** *  * 
*        *****  * **  **   *******     ** *   * * ** ** *** * * * *  **  ** * **  (pre[n]==a[n])
** ***  ** *  ***  **    ***   *   ***   *    ** *** ** **     **    **   *  * ** *   * ** is a prefix of %s",pre,a);
 **  *  ****  * * *** *  * *******    *  ** *  * *   * *  **** ** **   *  ***
* *  *  * * *  * * **   ******  **   *   ***** ***  ** **  * ** *  *** **  *       **  *  ** * ** **   *  ****  *      *  *  *   is not a prefix of %s",pre,a);return 0;
 *** *  * *** *  * * *** **
     ********** ***** *** ** ** ** **  ***** *   *  * **  ***   *  *** *** * *  *   * *****    

 *  * ***** ** ** *** *** *  * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include    **        *
#include * *  * **   * **

int main()
{
 ***** ******  * *   ** ** a[100];

***  ****   * **    * ** ***     b[100];

****** *  *  **** * **   ****** ***** ** *** %s", a, b);

 ****** **   ** **   * **     len_a = strlen(a);

*  * * ******   * * * **  i = 0;

*   ****** *** *  *  *  *   * flag = 1;

*** **   ***   * * ** *   *  *  = 0; i < len_a; i++)
 *** ***     *      *** * **
*****  ** **    * * *** ** * **      * ***** **** **   **   ******* != b[i])
* *   ** *  *****     *    *    * ** *    **  * *  **
 ***   ***   *     ** * ** **  **    **  ** * *  *** * *  **   *    * ***      ******    * = 0;
* ** **   **** * ***   *     **   * **** ****   **    
* *****    **    * *  **   * 

**  * *  * * ** ** **** ***  == 0)
  ** **** *        ***   
*  * ***     ** *  *** *** ****  ** * * *** * *   *   **    *** is not a prefix of %s", a, b);
**   * ***  * **  *  *  
 * *  ** *****  * *   ***   
*  **  * * * ***** ** *      *
   * * *  * ** ** * * *   *   ** * ****  *  **  ***  ***   *  * * is a prefix of %s", a, b);
 *   *   * *   * ******** * 
    *         *   *  * ** * *   ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
* * ****  * ****  *
int main()
{
* *       ** **    ****** i,n;
*******  *  ** ** ** **  *  p[100],s[100],a[100]={};
  ******** **    ** * *****  *    * %s",p,s);
   * * *     *  ** ***** **   **
* ** *** *   *   **    *****          *
*** * * *  ** *** **** **  *    **     ***     *
*****  *  *   *      * **    **    * * *  
  **  **  *  **    *      * *** * ** * * * ** *    ** **    ***   is a prefix of %s",p,s);
**  *   * * *   *****    *
 **   * *   *  ** ****** *  ***
  ****  ** *   *  *  * **** ** * ** * **   *    **** *****    * ***   is not a prefix of %s",p,s);
* *  **   *** *  **  ***** * 
    * ** * ***** *   ** *  * **** ** ***  * **** ** **********
** ***   ** ***** **  * *    0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
 *  ***  ** * *      **  *** *    ** *** *** *  *   
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
**   *   *   * ** *   * *     *  *     * ***  * ** *
   * **   *            * ** *** * ** *  ** ** *** * *    *  ****** *  *** * ****   != b[i])
  * **  *  ****   * *** **  ***  ***** * ***  **   *   ** * ***  ** * *  **  * ***** ***    * *      **   
* ***  * *  *    ** *  *   * * *  *   ****  *  *****     *  ** *  *** ***   ***   *  * *  * * ***** * ***   *   *  *  *     ***   **    *** is not a prefix of %s",a,b);
    ****   * *  *   ** *  *   ***  * * * ** *    *    ***  * * * * **   ** **   * * *  * *** * *           *  * ** ****** ** ** * *  **   ** * **   *  
******   ****** *****  ** *  **   **  * **  *   *   *** *     ****    ***** ****    **  ****** **  *   * ** *** 
* * **** *    **       *  ***   ***  **    ** * * *    **** ** *  ** **    *** ***  *   ***     == b[strlen(a)-1])
**  *  *   *  ** * *** ** **** * * * *   **   ** *** * *      **  *   *** *   ** **** ** * * * *  *
*    *    * ***   ****      * *     ****  * ***  ** **         * ****  ** **    *   *   **  ** *****         *  * ** **  ** **  * *** ****  ***  *   *    is a prefix of %s",a,b);
 ** *   ***   *   *** *** **  ***   * *    * ***  *  *** * *****    *    *** * ** * **  * * **    ** **  ****   * * *  * ***  **** *   
 ***    ** *   **  * * ***** *** * *  * ** * *  *    ******     * *   ** ******** **** **     **  ***    *****   ** * * ** *
     *  *   * ******** ** * * ****  *   ** **  * *   
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
  ****     *  * * **  *  **       ** i;
** **   ****  **  ****   * * ** (a[0]!=b[0]){
 ****  * *    *     ** *       * *  * *   *  ** ***  **    * * * 0;
***  ** ****  *  * *   ****  ** 
  *  *** * * * * *   ***    *   * *** *  **  ** *  ** 
*  * * **  * * ** **   ***    **   *  *    * **   *****  **  a[i]==b[i])
 ******        * ** **  *  * * *      *    ***    * **** 
*   *  ** **   ***  **     * ** ** ** **  **** *  ****   ** *    * * * ***** 1;
 ***  * *   ** ** ***** *    ** **    * * * *  *  **   * *   ***  ****** *  **       
 ****  * **     * * *  *  * * * *      * **      **
   * ***** **    **  *   * *****
**      *  *  *    * **** ** *****   *   0;

}

int main(){
** *        ** * *****   *  c[n],d[n],e[n];
 * * ***  *  * ****     ***  * i;
   **  * ***  * * *  **  ******  * %s",c,d);

*** * **        *  **   **    *
*   *******  * ** * **   * * ** *  *  ** ****** ****  ***  * ***   is a prefix of %s",c,d);

 *   ***  *  *  ****  **  ** *   
  *****  * *  *    *** **** * *   *** **   ** *  * * **     ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.59
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.2k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 10.2k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.7k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 9.2k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users