1 like 0 dislike
8.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 8.5k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * *
#include ** * **
**** *** * *** * *
** ** * * ***** ** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ****** * * *

* * * * * * * * ***** ** ** ** * *
* **** * * * * ** * ** * * * == b[i]){
* ** ***** **** * ***** ** ******* ** ** ** *
******* * ** * ****

** ** *** ** ** ** *
if (cnt == n){
* * ** ** ** * * *** ****** * * *** ** ** * ** * 1;
** ********* * * * * * * ** *
****** * * **** ***** *
* * * ** ** *** ** ** ******* * ** *** *** 0;

}

int main()
{
* * ** * * * *** s1[100], s2[100];
* ** ****** **** ** ** i,j;

** * ******** ** * * ** ** s1);
* * ** **** ****** * ** ** * ** **** s2);
* * ** ** **** (prefix(s1, s2)){

* **** **** * * ** * ****** * *** * ** * * ****** is a prefix of %s", s1,s2);
** * ****** ** *** ***** *** * ***
* * ** * ** *** * ** ** ** * ** * * * * *** * *
* *** * *** **** ** * ** * * ** ************ * ** ** ** **** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
** * * **** * ** *** ** c;
*** ** * * * * **** a[100],b[100];
* * ** ** ** ** * * * **** %s",a,b);
* * *** * ** * **** * * * * * ****
* * * ** * ***** ** ** ** *** * ****** **** 0;
* **** ** * * *** * ** * * ** * * ** %d",strlen(a),strlen(b));
*** ** * * *** ***** ***** ***** ** ***
* * * **** ** * * * *** * * * ** * * **** * ** * * * * ** ***** * * *
*********** * * *** ** * * * *** *** ** * * * ** * *** * ***** * * * ***** * *** ** * * **** * ** is not a prefix of %s",a,b);
* * * * * * * ** *** * *** ** *** * *** ** *** * * ** * * * ** * * ** ** * * * ***
* ** * ** ** * * ** **** ** * **** * ** *** ***** * * *****
* * **** * * *** * ***** * * * * * ** * **** * * ** *** * * ** ** * if(c==strlen(a)-1)
* * * *** * ** * **** * * * * ** * * **** ** * **** **** * *** * *** ** * ** ** ** * ******* *** * * is a prefix of %s",a,b);
    }
* * * * * ** ****** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** ** * ** * * ******* ** n,count;
* ** ** * *** ** * ** **** **** *** * * **
* * * * ** * **** * ** *** * * *** %s",a,b);
* * *** * ** ** * ** * * **

* * * *** ** ** * * ** * * *** ** ** ***
* * **** *** *** * *****
* * ** *** * * *** * *** * * *** *** * ** **
* ** * ** *

**** ***** * * * (strcmp(a,c)==0)
** *** ** * *** * *
***** ** *** * ** *** ** *** * * * * **** *** ** * * * is a prefix of %s",a,b);
* * **** * **** * * *
* ** ** * ** * * * *
* *** *** * *** * **
*** * * ** * * * * * ** * ** * * ****** * * *** ** is not a prefix of %s",a,b);
*** * * * *** * **** * *
* * **** * *** **** *** ** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** ** * * * * * a[100],b[100];
* *** ** ** *** * *** * * * **** * * *** **
    int l1,l2;
* * **** * *** ******* *
** * * * * * * * ** *** **
* *** * ** **** ***** * * **
*** ** *** *** ** **** **** ** *** ** ** ** **** ***** * is not a prefix of %s",a,b);

    }
** *** ******** * *** * ** if(l1<=l2){
* **** ** * * ** ** ** *** ** * * * * ** * * prefix=1;
* ** * ** ***** **** * ** * *** * * *** * *** i=0;
** *** * *** * ****** ***** ** **** * * ** * **** **** * * * *
*** * ** * *** * *** ** ******** * * ** ** ** ****** * * ** * * ** (a[i]!=b[i]){
* * *** * * * ** * * ** * * ** ** **** ** * ** * * ** * * * * * ** ** *** ** ** ***
* * * * *** * ** ** * * * * * *** *** *** *** * * * *** * **** ** * * * **** * * *** ** *** * * **
** * * * ** * ** * ****** * * * * * * ******** *** * *


**** ********* ** * * **** ** * * *** * * *
* * ** * * * * ******** * ** * ***** * * * * * ***** **
* **** * **** **** **** * * *** ******** ** * * * ****** * * ***** * * *** is not a prefix of %s",a,b);
* ** *** * * ** * ** * * * ** * * ** ** *** ***
* * *** ** * ***** * * *** ** * *
*** ***** * ** * *** ** **** *** * * ** * * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * ** **** * *
int main(void)
{

* * ** * ****** ** * pre[100];
** * ** ** ** * ***** *** word[100];
******* *** *** * **** * * *** * * %s",pre,word);
* **** ***** * *** * *** *** *** **
** * * ** * * * * ** * ***

** * * * ** **** * i;
* * * * **** * * *** ** * * ***** *** *
* ** * ** * * ***
* *** ** * *** * ** ** ** ** * * *** ** *** *** **** **
* * ** * * * * ***** ** * ** ** *
* * * **** ** * ** * *** * ** *** *** * * ** ** * * **** * * * * ** is not a prefix of %s",pre,word);
*** * **** ** * * * * * **** ** * ** ****** ** * * *** **** * 0;
* * **** ** * * ** * * * * * * * * ** *

* * * * * ** * ** ** **
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* ***** *** **** *** * *** * pre [100],a[100];
**** ** * * *** * *** * n ,i;
** *** ** * ** **** ** *
* *** * *** * * ** * ** * * **
* * * *** * ******* * * ** **** ** * ** * *
** * * * ** * * *
* ** ** ** ** * * ** * * * *** *** * (n=0;n<strlen(pre);n++)
**** * ***** ******* * * ** *** ** *****
* *** * * ** * ** * * *** * * ** ** ** **** **** **** * * *** (pre[n]==a[n])
* **** * *** * ** ** **** ** ** * * * ** ** *** * ** *** * ***** * * * * is a prefix of %s",pre,a);
** * * * * * * * ** *** ** **** * * * * ** * ** **** ** *
*** * * * ** **** **** *** * * ***** *** **** *** ** ** ** * ** * ** ** * **** * * * ** ****** * is not a prefix of %s",pre,a);return 0;
* * * * * *** * ** ***
* * ** ** ** *** * * ** ** * * * * ***** ** * ** * *** *** * *** *** ***

* *** *** ** * ** ** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * **
#include * **** * * *

int main()
{
* **** * * * ** * * a[100];

* * ** * **** * ** ***** b[100];

* * * ***** * * ** * *** * ** * %s", a, b);

*** * * ** * * *** len_a = strlen(a);

** * ** ** *** *** ** ** i = 0;

** * * * * * ** * *** ** flag = 1;

* ** * * ** *** * * = 0; i < len_a; i++)
* ** **** *** *** *
*** ** *** *** * ** **** ** ** * ** *** ** * *** != b[i])
** * ** * ***** * * ** * * * ** ****
*** * *** ** * *** * ** **** * **** * * * * *** * **** *** *** * = 0;
** * *** **** ** ** * ** * * *** **
** * ** ****** *** ****

**** * ** **** *** * ** * * == 0)
**** * ***** *** ***
** * * **** *** ** * * * **** * * * * ** *** * ** * * is not a prefix of %s", a, b);
*** * * ** * * **
***** * *** ***** *****
* ** * * ** * ******* * ******
**** * ** * **** ** ** **** ** ** ** * * ** * is a prefix of %s", a, b);
**** * *** * *
* *** ** * * *** ****** ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * *** *** *
int main()
{
** * * * *** * * i,n;
* * **** * ** ** ** p[100],s[100],a[100]={};
*** * * * **** * * * ** *** *** * %s",p,s);
* * ** * * * * * ** *
** * * ** * *** * * **
*** *** ** * * * * ** * **** *** ** * **
* * ** ** * * * ** ** * **** *****
*** **** * * ** ***** ** *** ** * *** * ****** * * ** is a prefix of %s",p,s);
* * * **** *** *** * *
** *** ** ** * ****** * *
***** ** * ** **** * * * **** * ** ** **** **** is not a prefix of %s",p,s);
** *** * * * ***
* *** *** * * ********* * ** * *
* ** * *** * * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
****** ** * ** ** ** ** * * * * ***
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * *** * * * ** * * * * ***** * ** * ** * **** *
** ** * * ****** * ** ** *** * * *** ** * * ** ** *** ** * * ** ** != b[i])
* *** *** * * *** ** ** ** ** ** ******** ** ***** ****** ****** ** ** *** ******* ** ****
** * *** *** **** **** ** ** * ** ** ** * *** ** * *** **** ***** ** *** * **** ** * ****** * * ** ** ** * *** ** * ****** is not a prefix of %s",a,b);
*** * ** ** *** *** * ** ** ** *** ******** * * *** ****** * * ****** ** * * * * ** *** ***
* * *** *** * * * * ** * * * ****** ******* ** * ***** ** *** ** ***** **** * *** ** **** * *
* ** *** **** ** * ** * * * * * * * **** *** *** * * * ** ** * * == b[strlen(a)-1])
* * * *** *** * * *** * *** ** ** ** * ** * *** ******* ** * *** * * ******* *
* ** ** * *** *** * ** * * *** *** ** * ******** * * * ** * ******* ***** ** ** ** * ******* * * ** * **** * * ** is a prefix of %s",a,b);
******** * ** ** ** * ** * * **** * ** * * * * *** * ** ** * * * * ** * **** ** * **** ** *
** * * * * * * * *** * * * * ** ** * ** ** **** * * *** ** * ** * **** ** ***** ** *
** * * * *** **** **** * * * * *** *** *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* * * * * * *** ******** ** i;
****** * ** ** ** ** *** (a[0]!=b[0]){
*** * * * ** * *** * * ** *** *** * ** 0;
**** * ******* ** ** *** * ***
*** * * * ** * ******** * * * *** *
** *** * *** *** ** * * * *** *** ** ** * * * * ** ** a[i]==b[i])
***** *** * *** **** ** * *** * ** * *
* * ** ** * * * * * * * ** ****** ** * * * *** * **** 1;
* ** * * * **** * * * * * * * * ******* ****** **** ** **** * * **
** * * * * * * ** **** **** ** ** * *
* * ** ** * ** ** ****** *
*** * * *** ** ** * * * * * * 0;

}

int main(){
*** ****** * ** * ***** ** c[n],d[n],e[n];
***** ** ***** * ** **** i;
* * ** * * * ** ** ** ** ******* * %s",c,d);

* * *** ** ** ** *** *** *
*** * *** * ** * * **** ***** * * * *** ******* * * * ** is a prefix of %s",c,d);

** * * *** * * * *
*** ** ** * ** * * * * * * * ** * ** * * * * *** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.199
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.8k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.7k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.9k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 6.9k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users