1 like 0 dislike
13.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 13.2k views

37 Answers

0 like 0 dislike
Hidden content!
#include ** ** *
#include *** * *
***** *** * ** **
** **** * * ****

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** ******** *

** * * * *** ** * * *
**** *** ** * * * ** ** * == b[i]){
* * * ****** *** ****** ** * ** * *** ** ** ** * ** **
* ** ** ** * *** ***

**** *** * * *
if (cnt == n){
* ** *** * ** ***** ** ** * * *** * * * ** ** *** * 1;
* ** * * ** **** * **** ** * ****** * * **
*** ***** ** * ** * * *
** **** ******* ** * ** * **** *** ** * 0;

}

int main()
{
**** *** ** **** * s1[100], s2[100];
* ** ** *** ** * * i,j;

**** * * *** * * ***** * ** s1);
**** *** * ***** *** * * * * * * s2);
** * * * ** * (prefix(s1, s2)){

** ** ** * ** * * * ** ** ** * *** is a prefix of %s", s1,s2);
* * * ******* * ***** * * *** * *
* * *** * * * * * * * ***** *** *** * * **
* *** *** ** * ** ** * ** * ** ** * * * **** ** * * * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
*** ** **** **** * * ***** c;
*** * * * * * * * * * a[100],b[100];
* * * * ** * * *** * ** * * * * ** * %s",a,b);
* * * * * *** * ** *** * * ** *** *
***** **** * **** **** * ** ** * * ** * *** * * 0;
*** ** *** ** * ** * ** * * %d",strlen(a),strlen(b));
* * * * * ** * *** ** *** * ** * *** *
* * * * ** * * ** ****** ****** **** * * * ** **** * * *** ** ** ** ** *
* * * ** ** **** * ** *** * * ***** ***** ** ***** * ** ***** * * * ** ** * * *** * is not a prefix of %s",a,b);
* ** * * * * ** * *** * * * * * * * *** * ** *** **** ** * ** * ** * ***** *
* ** * * * **** ** * ***** ** * * * *** ** * * * * ** * ** *
* ** *** * ** * ** * * *** * ** *** ***** * ** ** * * * if(c==strlen(a)-1)
* *** * * * *** ** * * * ** * ** * * * *** * * ** * ** *** ** * * ******** * ** **** * is a prefix of %s",a,b);
    }
***** ****** * ** * * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*** *** ** * **** n,count;
**** ** * ** ** *** * ** * ** * * * * *
* ** * ** * * ** ******* * %s",a,b);
* * * ** * **** * *** ***

* ********** * * ** ** * ** **** * *
* ** ** * *
* ** * ** * * * * * ***** ** ** * ** * * * ** * *
* * ** ***** *** *** * *

* *** * ** ** * (strcmp(a,c)==0)
* * ** * * ** * * * **
** * * * * * * **** * * ** ** * **** * ** * * ***** * is a prefix of %s",a,b);
** *** * * * * *** **
** * * * ****** * * ** **
** ** * * ** **** **
** ** *** * * *** *** ** * ** ** ** *** * *** ** * is not a prefix of %s",a,b);
********* ** **** ** ** *
** * * *** ** ** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
*** * ****** **** * *** ** a[100],b[100];
* ** *** ** * * *** **** *** ** ****** *
    int l1,l2;
** ** * ** *** * * * * ***
**** * ** **** ** *** * * ** *
* ** *** * ** * * * *** *
** ** ** ** * * *** * * * * *** ** * ** * ***** * * is not a prefix of %s",a,b);

    }
* *** * * * * * ** if(l1<=l2){
* ** ** * ** **** * ***** * ** *** * **** * ** prefix=1;
*** * *** * * *** * * * **** * * **** **** ******* i=0;
* * *** ** * * * **** * *** ** ** * *** **** * * *******
* ** * * * * * * * * ** *** * * *** ** ** ** **** *** ** *** * * ** (a[i]!=b[i]){
** *** * ** * ** * * **** * ** * ** **** * ** ** * * ** * * ******* ** * * **** **** ** ** *
** * **** ** ** * ******** ** ** * ** ** ** * * ******** * * * * * * ** * *** *** * ****
* *** * *** * * * * * * * * ** * ******** *** * *** *****


*** * ** * * *** **** **** *** ** ****
* ** * ** *** * * * *** ** * **** ***** ***
* *** * ** ** * *** * * *** * * **** **** * ***** * ** * ** * ** ** * * * is not a prefix of %s",a,b);
* *** *** *** * ** *** * * ** * * ** * *
* ** ** * * * * ** ***** * ** * * * ** **
* ** * *** ** ****** * ** * * * ** ** ** * ** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * **** * **
int main(void)
{

* * * **** **** * * pre[100];
** * ** ** ** ** * word[100];
** **** * * * * ** ** ***** * **** %s",pre,word);
** * *** * ** ****** **** * ** * * *
** * **** *** ** ** *** * ** * **** *

* * ** ** ** * ** * i;
*** ** * ****** * * * ** ** * ****
*** ** ***** * ** *
*** * * * * *** **** * ** ** ** * ** * *** * * * **
**** * ** ** ** ** * * ** * * * **
** * **** ** * ** * *** * * ** * * * *** ** *** * * * * * ****** * * is not a prefix of %s",pre,word);
* * * * *** **** ** * * * * * ***** *** * ***** ******** ** 0;
* * * * *** *** * * *** * *** ** ******* *

** * * *** * * * *** *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * **** * * * * * pre [100],a[100];
*** * *** *** ** n ,i;
*** ***** * ** * * * ** ** *** * *
* ** * ** * * * ** * **** **
** **** *** * * * *** * ** ** * * ** * * *
* *** **** * *** *
* ** * ** * ** ** * ** * ** *** *** * (n=0;n<strlen(pre);n++)
* *** * *** ** * ** ** * **** * * * ****
* *********** ** * * * * * * * * * * ** *** *** *** ** ** * (pre[n]==a[n])
*** * * * * * * ** **** * * * * * * * * ** * ** * * * * is a prefix of %s",pre,a);
***** ** * ****** * ** ****** * **** * * ** ** * * * ** *** * ** *** ***
** * ** * ****** * * **** * * ** * ****** * * ** ** **** * * ** * * * ** * ** * *** * * **** * ** is not a prefix of %s",pre,a);return 0;
* ** ****** ** ** * ** * * **
* ** * ** ****** *** * *** * *** ***** ** * ***** * * *** ****

* * **** ** * ** **** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * * * * ***
#include *** ** ** * **

int main()
{
* * ** ** ***** * * ** a[100];

** * ** * ** ** * * b[100];

** * * ** * * ** **** ** * * %s", a, b);

* * * ** * ** len_a = strlen(a);

* * * ** * ** * * ***** i = 0;

* * *** **** ** ** ****** flag = 1;

** * * * * *** ** *** **** = 0; i < len_a; i++)
* **** *** *** * * * *
* **** * * ** *** * * ** * * ***** * * ** * != b[i])
* * **** * ***** *** * * * * * *** * ***
***** * * *** ** ** * * * * **** **** ** * * * * = 0;
* * ** * ** * * ** * * * * * * *
* * * *** **

* **** ** * * ** * ** == 0)
* * * * ** * *
*** ** *** * *** * ** * * ***** ** *** ** * is not a prefix of %s", a, b);
*** ** *** ** ***
** * * * * ** ** ***
* * * * * **
*********** ** * ******* * *** * * ** *** * * is a prefix of %s", a, b);
* * * * * **** * *
* ** *** **** * * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** * *** * **
int main()
{
*** * *** ** ** ** ** * * i,n;
** **** * * * * * * * * ** p[100],s[100],a[100]={};
* *** **** ** * * * ** * ****** %s",p,s);
***** *** * * * * ** * * *** **
** *** * ** * * ** * * * * ** **
*** ** *** * * * ** *** *** ** **
** * *** **** * * * *** * **
******* * *** * *** ** ** * ** * * *** **** ** * * * ** is a prefix of %s",p,s);
* *********** * **
*** * * *** *** ** * ***
* ** * ** *** * * * * *** * * ***** ** * * *** ** * ** ** ** is not a prefix of %s",p,s);
** * ** * ***** * ****
** *** *** ** * * **** * * ** * * ** * ***
* * *** ** *** **** * * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* ** * * *** ****** * ** ** * **** ** **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
** * ** ** * * * * * * *** **** * * **
* * * * ** *** * *** **** * * ** * * * **** * ** * * **** != b[i])
* ****** * *** *** * **** ** ** * * *** * ** **** ** * ** ** * ** ** * *** * *** * *
* * **** *** ****** * * * ** * * **** * * * * * * * ** *** ** * *** * * ** * ** *** ****** * *** ** ** * * ** * is not a prefix of %s",a,b);
** * ** * ** **** * *** * * **** ** * * * ***** * ** *** * * ** * ******* ** * * * ** * * ** * * **** * * ***
* * **** * * * * * ** * ** * * * **** * ** * **** * * *** * *** ** ** *** ** ******* *
* *** * ****** ** * ** ***** ** * * * ******* ** ** * *** * * *** * * * == b[strlen(a)-1])
** * * * * * ** ***** * ** * * ** * ** *** ** * ** * * * * * * * ** * ** ****
* * ** ** * ** *** * **** ** * *** * *** * * * *** * *** ** *** * ** ** * *** ** * * * **** ** *** ** *** * is a prefix of %s",a,b);
* ***** * ** ** * * * * ** * * ** * * ** *** ***** *** **** ** ** * ** ** ** * * * * * * * * *** ** **** ** *
* * ***** ** *** ** ** * ***** * ** *** * ***** * ***** *** *** * *** * * *** *** * **
* * ** ** * *** **** ** **** * * *** ** **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
**** *** ****** * ** * * * * i;
* * *** ** * * * * * *** ** (a[0]!=b[0]){
****** * * ***** * * ** * ** * * ** ** * *** 0;
********** ** *** ** ** ***** **
* * * * * ** ** * * ** * *** ***** ** ***
**** *** * ** * *** * ***** * ** ** **** * * ***** ** a[i]==b[i])
*** * * ** * * * **** ** ** * **** * **
** **** ** * ** * ** *** * ** *** ** *** ** * * *** **** * *** **** ** 1;
****** *** **** * **** *** **** * * *** ** * * * * ** * ** *
** *** *** ** **** **** * *** * * * * * * * **
*** *** **** ** * *** * ***
* ** * * ** *** *** *** ** * * 0;

}

int main(){
** ** * * * * * * c[n],d[n],e[n];
**** **** * * * * ** * i;
**** * **** * * * ** * ** *** %s",c,d);

* * * * * * ** ** * ***
*** ** * *** * ** * * * *** ***** ***** ** ** * * * is a prefix of %s",c,d);

** **** * * ** * * *
* ** *** *** ** **** * * **** ** ** * * ** **** * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.240
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.7k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.7k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.7k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.4k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users