1 like 0 dislike
8.4k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 8.4k views

37 Answers

0 like 0 dislike
Hidden content!
#include ** * * *** *
#include *** * ***** ***
* ** * **********
* ** * * ***

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= *** ** **

* ** * * * * * ***** ** ***
** * ** *** * * ** ** * * * == b[i]){
* * * *** **** ***** * ** * ** * ****** * * ** * ***
** ** ** * ***** * * ** *

* * * * * * ***
if (cnt == n){
*** * * ** ** *** * * ***** * ** * * * 1;
* ** **** * * * ** * * ** * * * * * ** * * *** ****
**** ** * * * * * ** * *
**** * * ** * ** * ** *** ** * ** * *** *** * 0;

}

int main()
{
** **** ** * * * s1[100], s2[100];
**** *** * * ** ** i,j;

* * * * **** * * *** * ** * * s1);
**** * **** * * * ** * ******* ** *** * s2);
* *** * * ** (prefix(s1, s2)){

*** ** *** ** * ****** *** * * * *** is a prefix of %s", s1,s2);
***** * ** ** ** * * * ** * ** *** *
* ** ****** * * ****** **** * *** ** * *
* **** * ** * * ** ** * * ** ** * * * ******* ** **** ** ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* ** * * ** * ** * * * *** ** c;
* ***** **** *** ** * * * a[100],b[100];
***** * * * ***** ** *** ** * * * ** %s",a,b);
** ** * **** * * * ** * * * *** * **
* * * * * ***** * * * * * ** ****** *** 0;
***** * **** * *** ** *** ** ** * * * %d",strlen(a),strlen(b));
******* **** *** * * *** *** * **
* *** * *** * ******** * ** ** **** *** *** * * * * ** *** * **
* * **** * * *** *** ** ** ** * *** ** * * * * ** * ***** * *** * ** * * * * *** ** ** * ** is not a prefix of %s",a,b);
****** ** * * * ******** * * **** * ** * * ** ******* ** * ** * * * * ** **** *** *
** * *** * ** *** ***** ** * ** ** * **** * **** *
* ** * * * ** ** * * * * * * * *** ** ** ** ** ***** * * * if(c==strlen(a)-1)
* * ** * ** ** * ** * * ** * * * * *** * ** **** * * ** ***** *** * *** *** * ** * * * ** ** is a prefix of %s",a,b);
    }
***** *** ** * **** * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
******* ** * ** * * * * * n,count;
**** * * * ***** * ** ** * * *** ***
* ** * * *** ** * *** **** * %s",a,b);
***** * * * ** * ***** * **

* * ** ** * **** *** * ** * * * **** * ** * *
* * *** **** *** * *
* **** *** ** *** ** * * * ** * ** * **** * *
* ** * ******* **

** * ** * * * ** *** (strcmp(a,c)==0)
***** * * * ****** * *
* **** **** * * **** *** * *** *** * * *** * ** * * * is a prefix of %s",a,b);
**** * * ** ** * ** * *
* ** * ** * **
* * ** *** ***
* * ** * * * * * * * * * *** ** **** * ***** * ** is not a prefix of %s",a,b);
** * * * * ******* *****
* ** ** * **** ** * *** ** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** * *** ** * * ** * a[100],b[100];
** * ** * ** *** ** ** * **** * **
    int l1,l2;
* ** * * **** **** * *** *
** ** **** * * ** ** *
* ***** * *** ** ** *** *** *
* *** * ****** * **** * ** * *** * * * ******* * *** * * * is not a prefix of %s",a,b);

    }
* ***** ** ** ** ** **** if(l1<=l2){
* * ** * *** * * *** **** ** * **** ** ** prefix=1;
*** ***** ** * ***** * * * * ***** * * * i=0;
* ** * * * * ** ** * ** * ********** * * ** ****** * ** * **** ** * *
*** ** * ** *** * ** **** ** * ** * ** ** ** * *** ** ** * ** * ** * (a[i]!=b[i]){
*** ** * ** * ** **** * *** * * * * *** *** ** * ** *** * ** ** * * *** ********** * * * *
** *** ** * **** ** ** * * * * ** * ** *** ** *** ****** ** ****** * * * * * ** ** ***
*** ** * ******** * *** * * * * ****** ** ** ** ** ** * * * *


* * ** *** * * * * ***** * * ** ***** **** *
** *** ******* ** ** * * * * *** * * * ** ** ***
* *** ***** * **** *** ** * ** ** * * * * ** * ***** * ***** * **** is not a prefix of %s",a,b);
* * ** * ** * * ** * * ** ** ** * **
* **** * * ** * * * *** **** ** ** * ***** *
** * *** ** *** * ** * * ** * * ** ***** ** *** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * * ** *
int main(void)
{

** * ****** * * ** pre[100];
* * ******* ** ** ** ** * word[100];
**** **** *** * * * ** * * * * %s",pre,word);
** * **** ******* * * * ** *
** ** ** * **** * ** ** ****

** * * * **** ** ** * * ** i;
* *** ** * ** ** **** * * **** ** *****
*** * **** ** * *** * *
* ** * ** ** ****** * ** ** * * ** *** ******* * **
* * ** * * **** * * * * * * * * *** **
* ** ***** * *** *** ** * ** ** * * * * * *** ** ** *** *** *** ** * is not a prefix of %s",pre,word);
** ** * * * * *** **** * *** * *** * ** ** ** **** * * * ** * ** 0;
* ** ** * ****** ** ** ********* *** * ** ***

* ** ** *** ****** ** *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* ***** * * * * ** *** pre [100],a[100];
** * * * * * * * * ** n ,i;
* ****** ** ************
* * * ** ** ** * * * ** ** * **
**** *** * * * ** ** * ** ** ** * *
*** *** *** *** *** * **
** * * *** * * ** * * * * * * ** * * ** * (n=0;n<strlen(pre);n++)
*** * * ** * ** * ** ** ***** * *** * **
* * ** ** ** * * * * * * * ***** *** * **** * **** * * ** ** * (pre[n]==a[n])
**** * *** ** *** *** ** ** ** ** ** * ** *** ****** * * * * ** * ** **** ** * is a prefix of %s",pre,a);
* ** ** * ***** ***** * * * **** *** * * *** *** * * **** ** ****** *
* * ** ******* * * *** ** * * * *** ** ******* ****** ** *** * * ** **** * * ** **** **** is not a prefix of %s",pre,a);return 0;
* * *** ** * ** **
* * ** **** ***** * * * * * ** * *** * **** * ** **

* ** ** *** * ** ** * * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * * **
#include ** *** *

int main()
{
*** ***** ** * * **** * a[100];

*** * * **** * * ** b[100];

******** * * **** * * %s", a, b);

*** ***** * ** * * ** ** * len_a = strlen(a);

* ** *** * * i = 0;

* *** ****** * *** ** flag = 1;

** * * ** ****** ** ** = 0; i < len_a; i++)
** ** * * * * * ****
* * * **** **** *** * * ** ** * *** ** *** != b[i])
* * ** ******* ** * * * * * *** * * ** ** **
** ** *** ** * * * * ** ****** ** * * * * **** * * ** ****** * = 0;
*** ** ** ** * * * * * * ** * *** ** **
* ***** *** * * * ***

** **** * *** ** *** ** * == 0)
** * ** * ** * * *** *
** * * * * * ** *** ** * *** ***** * ** * * * ** is not a prefix of %s", a, b);
** * **** * ** * * ********
**** * ** ** **** * * * **
** ** ** * ** ***
* * **** * *** * * ** ** *** *** * * * * is a prefix of %s", a, b);
* * *** * *** *** * ** **
** **** ** * * * * * *** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* **** ** **** * *
int main()
{
** * * ** * * * * i,n;
** * * * ** * ** ** * p[100],s[100],a[100]={};
*** * * *** ** *** * * %s",p,s);
******* * ** ** ** * ** *
*** ** * ** *** **** * *
*** ** * * * *** ** ** ** *** * *******
**** *** *** * **** ** * ** ***
* **** * * * * *** *** * *** * ** *** *** * * * is a prefix of %s",p,s);
* ** ***** * * * ** ** * * *
* * ** * ** *****
** * * * * * * * *** * ** *** ***** * **** * * * * ** ** is not a prefix of %s",p,s);
* * * **** * ** * *
* * *** ** * ** * ******** **** *** ****** *
******** * * ***** * * * * ** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* * * * * ** * * * * * * *** ** **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
*** ****** * ** ** * ****** ***** ** ** **** *
** * ** ******* * ** **** * * * * ** * ** * *** **** * *** ** * != b[i])
** * *** * ** * ********* * ** **** * ** ** ** ** ******** **** *** ** * *****
********** * ** ** ** * ******* * ** * **** * * * * ** ** * * * ** * ******** ** * **** * * * *** * ***** *** * is not a prefix of %s",a,b);
** * ***** **** ** * ** *** *** * ** *** ** * * **** * * **** **** ********* *** * ** * ** ***** ** ** *
****** *** ** ** * ** *** ** * * ** * *** **** ** * ** *** * * * * *** ** ***** *
** ** * *** *** ***** * * * ** * **** * ** * *** **** ** *** * * ****** **** * == b[strlen(a)-1])
** * ***** * ** *** * ******* ** * ** * * *** * * * * * * ** ** * * **
* ***** ** * * ****** ** * ** *** * ** *** *** * * * ** * *** ** * * ***** **** * ** * * * ** * * ** *** is a prefix of %s",a,b);
** ** * ** * * * * * * * *** * * ** ** ** * *** * * * * * ** * * * * ** * *** * * *** ** ** ** ****
* * *** * * ** *** *** ** ** *** ** * **** * ***** *** ** * *** * ***** *** *** * ** *
* ***** *** ** * *** * *** **** * ** **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* *** ** * * ***** ** ** ***** i;
* *********** * ** * * ** (a[0]!=b[0]){
* *** * * ** * *** ****** ****** ****** * * 0;
* **** * * ** * ****
* * ** ** * *** * * * * ** * * * **** *
***** *** ** ** * ** ****** ****** ** * * * a[i]==b[i])
**** * * ** * *** * * *** ** * ****
* * ** * ** *** ***** ** * * ** ** ** * ** * * ** * ** * *** 1;
* ** * * * * * ** *** ******** ** *** ** * * ** * ** * **
* * * * *** * * ** * * ** ** ***
*** * * * ******* *** * *
*** * * * * ** * 0;

}

int main(){
****** * * * **** ** ** c[n],d[n],e[n];
** * * **** ** ** ** * i;
**** *** ** * *** * * * *** %s",c,d);

** * * * ** *** * * * *
* ***** ** * ** ** *** * * * ** ** * * ** ** * *** ** is a prefix of %s",c,d);

* * * ** * *** *
*** * * *** * **** **** ** *** * ****** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.199
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.6k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.5k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.7k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 6.8k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users