Final Exam 2 (20%)

1 like 0 dislike
11.7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 11.7k views

37 Answers

0 like 0 dislike 
Hidden content!
#include  *  *  * **** * * *
#include * *  *** *  * 
 **   ****    **** *   *
** **     * *  ***  *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n=   *  * ***  *

**    *   **     *** * **   ** *      * ***
 **** * **  **  *** *** *  *  *   == b[i]){
**** * *   * **  **   **  *  *   **  * **  **      *    **  
  *** ******   * ** **     

*      ***   ****** * ***
if (cnt == n){
* * ***** * **    * ***  *****  *   *** **  ** *      *******  1;
 * *  ***** * ***     ***   **  *    ** ******   **
**    *  *  * *** ***   *
   * ** **      **  *   ***    **  ** *** *  ***  * 0;

}

int main()
{
          ** ***** ***** s1[100], s2[100];
 **** ****  *  ****  **  i,j;

** *   *      *  * **  ** **  ** *****  s1);
* *    *  * ** *    * ** *** * * *  ******* * * * s2);
 ** ****  ****  *   *  (prefix(s1, s2)){

 ***  ** * * *  *  ** * * **  ***   ** **  ** *  *    * * * is a prefix of %s", s1,s2);
 **  **** *  * * * ** ** **** ***  *** *** ***
    ** ***        *  ** * *    **   *  * **  
 *** *** * * *  *  **  *** * **  **  ** ****  *  * *   **    *  * *** *** *    * ***** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
     *  *** ** * * *  **  *   c;
*** ** ****  *  ***   * *** *  a[100],b[100];
 **  ** *  **  **  **  ** * *    * * ** ***    %s",a,b);
** ** *  ****** ***       * * * *  ***  * * ** ***  
    ** * * *   ** **  * * ** ** * *  **** *** ***   0;
 *   **** *   *   *  **   **   *** %d",strlen(a),strlen(b));
* *  * *  ** ***  * ** ** ** *    *   ** * **
* * * *  *   * *     *  * ** ***   *   * **** *  ** ***     *  ***    * ***  * ** 
   *  ****  *** ** *     **** ** **     **     **** *    ********   *** * *** *****   *  * *  * **  *   ******  *   **  is not a prefix of %s",a,b);
*   *** ***  *   *  *** *   * * **   *     * *** * *   *  * * *   * * ****  *    *   ***  * *** ** * **  *    ** ** *
 ** ***  **      ****** *  **  * * **   *** * ********  **  *    * **      *  **    ****
 **    ******  ** **  ******  * **** **  * *        *****    * *****      ** * if(c==strlen(a)-1)
*   *** *    * *****  * * *   * *** *****  ** * **   * ** *    *** *  **  ******   *  *     **  *  ** * **** **  * is a prefix of %s",a,b);
    }
 ** *  ** *  *** **  ** *  * * *   * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
  ***** ** **   * *** *    n,count;
 *** *   **   *  *   **  ***  ** *   * *   *** *   *
 * **  * **    *     **  **  * * **     *  %s",a,b);
**    *** ** *   ** **  ****    ***

*    *******  **** ** *** ****  ******  ** **   
 *   * *  * *     *  *  ** 
 ***  * *   * * ***  *  * * * **  *   * *     ***  *  *    *** *     *  *
* *     ***   ***   *** * **  *

     *** * *   * ***   ***     (strcmp(a,c)==0)
     **  * **    ** * * 
*****   ** * ** * **  ***  * **  *   * ******     * * ****    *      is a prefix of %s",a,b);
 **   * ****   *  **        
 ***  ******* **  ** *   * * *
 *******  *  **   *    *    *
*  ****     ***  * *  **    **  ****    * **  * **   * * *** *  * is not a prefix of %s",a,b);
*** **  ****** ****  *     * 
**  * *****  *  **** ** * *   *  0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
     * ** ** ** ***** ** ** **  *   a[100],b[100];
   *  *** ****** ****    ** *** *  ** ***   **  *
    int l1,l2;
 ** ****  ***    *   **    *
* *  *    **    * ** * * ******* * 
***  ** *   **      *   ** *   *   ***
 *  ** **   **   * ***  **    ** * **  *    * * * **  * **** *   *  *  * *  is not a prefix of %s",a,b);

    }
   *** * * *  *   * * *** if(l1<=l2){
* *  * **   * **     *  ** * *** **  * *  **  * * *     prefix=1;
** *      ** *  * *** ****  **    *  * * *    ** **  * i=0;
*** **** * **  *** *  * **   *  *  ***   *   **     **   ** *   ** * ***  *  
 * *   ** *** * *   **  *  ** *** *  * * *  ****  *      * *  ***   ** *  * (a[i]!=b[i]){
****  ****   *  **   ***** ** ****** *** * ****  *** ** *  ***  *   *** * ** ***** * * ** **  ****** **  ** * * **  * 
** * **  ****  * *     ****  ** **  ****** * * **  * **  *** *** ** ** ** *  * ** **   *  **** * *** * *
   ***    ***  ** **    *    * * * ** ** *   * *   * ** ******  * **  * *** * 


 *           *  *   ** **  ** ***  *  ** ** *** * ***   ** *
 ***  ***  ***  *   *  ** * * ** *    ****  *  * *** *   ***    *
* **  *    *** *   **  * ** * ***   * **  *** **  *  ***  ***    **  **** *   ***   *  **      * **  *** is not a prefix of %s",a,b);
** *  * **  *  *  **** *  ** *    *** **** *     * *    **
 *  * ****  *   * *** **   *  * **   **  *** ****       *
 **    **   *  **** **   *** *  * * *     ***  **  ** *  ***   *** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
 *** *   **   *  ** 
int main(void)
{

****  * *  *******   ***   *      pre[100];
    **** ***   ***      *     *     word[100];
  * * ** ***   *  ***  **  * *    *     %s",pre,word);
   ** *****  ***  * ** *** *  ****** *
 *   *  *    ***** * ** ** ** * ** *** 

**  **  ***  **   *  *  *****  *  i;
  * * * *      * * **** ** **  *** *  ***  *    *
 ** *   **    *    * *** * * *
*    **   **  * *  ***  **    **        * *  *****  * *
*  * ***  * * * *     ****  **  * *   **  * * **   ***
 ***    *     **    * ** *** *** * ** *    **  ******  *** *  ** *   * * **      * ** * * ** is not a prefix of %s",pre,word);
* **** **   **** *   ***** * ** **  **   *  ** * * *   ****** **** **** ****     *** ** * 0;
***  **    **   *  *     ** **  * * **  * *  *** *  * * * *    * 

  **  * * ** ***  *  **   
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
 ***    *   * *  ***** ***   pre [100],a[100];
*******  *** **   *  *  ** **** *** ** n ,i;
* *       * * * *    *** *   ***    *
   ** *** * ***** *   *  * *** *  *  **** **
***  **     **** ** ****** * * ** ** ** **   ** * *****  *
*  **** * * * **  * ***** ***  
*  *****  * * *** *    * *   *  *** **** *** **     **  (n=0;n<strlen(pre);n++)
 * ****   *** * *  *  * * * **  ***  * **  ***    * ** 
*  *** *  ** *** * *     * ***** * ***  **  *** ***   **    ** * *  * **** **  *   * (pre[n]==a[n])
 *  **  *  * * * *  ***  *** * **     * *    *   **** ****** * *    *** ** * ***  *   **  is a prefix of %s",pre,a);
**  *   *****     * *****  *    * *   * * ** *** **  **  *  * ** ** *  * *    **
**        *   ** *  *  *  ** * ***  * *  *** ***   * *******     *   *   * **     ** *  *  *  * *    ***  ****  * *   *   is not a prefix of %s",pre,a);return 0;
**** **  *    **      ** * *** * 
** * *   *  **  **   * *  * *   *   ** ***    **** * *  * **   * * ***** *

*  *   * ****   **  *   **    **  0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * ****  *  *   *
#include  *   **** ** *

int main()
{
  * * *  *** ** *   * ***** * * * * a[100];

   **    *  **  ** ** **** * b[100];

 *     ***   * *    *  *   **  *  %s", a, b);

 *  * * * ** ****  ***** * **** len_a = strlen(a);

 * **  ***     *****  *  * **  i = 0;

   * ***  *    *  *   *     * flag = 1;

 *    * *** * *** *   *** *    = 0; i < len_a; i++)
  * * ** *  ****  **** *    
* ** ** * *     * **  *  *  * * *  **  *  *** *     ** ** * != b[i])
 *  *  ***  * *** ** ****   * ** *  **    * ***  ** * *
 *   *   *  *  *  **  * * ***** ***  ** *****  ** * *  *****  * ***** * * * * * = 0;
**     **** * ** ** *  ***   *** ***   *** *  ***  * *  * *
***    **  *  ** ** * ***** *  

  *    * *   *** ** *     * ***    == 0)
*   *     * ******    **
** * *  **  *    *   *   *** ***   * ***** **   ** * is not a prefix of %s", a, b);
* **   *** ****      **  * *
**    ** *   **    ***  *
  ** * ** **** **   * * *** *
*    ****  **** *   *** * *  *   **   ** **  * ***** **    **** *   * **** is a prefix of %s", a, b);
 ***** ***  ** **     * *
*** *    *    ***   ** ** ****    0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
** **** *****  ****  **
int main()
{
*** ****** ** ** ***** **  i,n;
*          **  * ** ** **   p[100],s[100],a[100]={};
  ***  **   *****   *   *   *  **** %s",p,s);
**    **  **********  **   ** *  *  *  
***  **  ** * *  *   *  *** *  *  ** 
  *  ***** ** **  **      ** *      *   **  * ** *  * 
 **  **  * * **  ***     * ** * ****  *****
** * ** **  * *      * ** ***  *    **  *** * *   ** * *  * * is a prefix of %s",p,s);
 ***  *****    ** **** *
* **   *******   *****  *  *  
 ***  **  * *    ** *** *  * ** **       *   * ** * ******   * * *  is not a prefix of %s",p,s);
 ****    ** *** *****    * *
 **  *   * ** **          *   *****   *  * * * *  *  * *
* ** *     *  * **** ** ******     0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
**    ***     * ** * * *  ***   ***  ***   
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
  **   *     *  * *   *** ***    *  * ****  ** ** * **
 *** * ** *   *****  *     * ***   *    *****         *** **  ****   ***  *  **  *   ***   *   != b[i])
*** ** *   ****  *  ** **       *** *****  * *  ***** **  **   *  *    *   **  *****  **
* ** * *  *   * **  **   **  ** * *** *** ** *   * * *      *  * ** **  * * *****   **  **   **  **   * *  ** *** *   *** * **  *   *    ** ** *   *  *  is not a prefix of %s",a,b);
 ***  ***  ***   **  ** ********   **   **  *** **  ****  *** ** *** *  *  *** *  ********* *  * **  * * ***   **    *****  ***  * *** *     * *
   * * *  ** **  *** *  * * ** **   **  ** *   * *  * ** ** *    ***  * ****    ***   **  **
 **   ** * *   * *  *       *   **** * *** *    ** **        * **   *    **    *   * *   *     ** == b[strlen(a)-1])
******  * *****    ******* ** **  *  **** **  * * **** ***    * *  ** * * *  * ****  ** **** ***  ** ** *
** *   *  *** ********** * ****  * *  * **   * ***** **  ****    *** ** ** *     *  ***  * ******** *       * *  ** * *   ***** ***    is a prefix of %s",a,b);
****  ***  **  ***** ***  *****  * *    *  ** ** *  *  ** *  ** ** *  ***  * ** * * *    **  ***    **  *** *** *      * ** *  * * ** * ****** ****
 *  * **     *   ** * *      ** ***   ***  ** * ** *      *   *******  ** * *   ** ***  ***  *  **
   ***   * *     *  *   *** **  *  ******    * *  *   *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
 * * *** *  ** * *  *   ***  *  * i;
***   *     ****     *   ******** * ** (a[0]!=b[0]){
* *         **  ***  * **     **** **        * *   **  0;
 ** *    **  * ** ** ** **    
    * *******    * *** ** * **  **    **** * * *
****  ** **** ** *  *  *  *  *  ** **  * *** **** **  ** *** ****    a[i]==b[i])
  ***** **** *  ** * **   * **     **  * ** * *** ** 
  * ** ***  **  **  * * ****     **    * ******   *****   ***    **     *   *  * 1;
   ** ***  ****  ****  ** **  ** ** ** * ***     * ** * **    *     ***  ***** ** ** *
* ***      ***  * **** * * *****  * **** ** *** *     
** ***  **      *  ** ** * **  *  **  
***   *** *    *** * *   * * * *  *** 0;

}

int main(){
**    **  ****     **  ** * **  c[n],d[n],e[n];
 *   *     *****     *  *  *** i;
*    ** * ***** * *  * **    * *   ***** %s",c,d);

     **  *  * * *    *** ****   *
   *  *  **  * *** *  *   *** * *  * **** **   ** *      ****** *  * is a prefix of %s",c,d);

  *   ****  **  *  ****       *
*  ** * ****   *    ****** * ***** **  *    * * ** *  *** ** * *   ** **  is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.204
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.7k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 10.6k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.8k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 9.5k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 2.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users