Final Exam 2 (20%)

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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Hidden content!
#include ** * **   **
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int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

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}
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Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
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}
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Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
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}
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
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Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
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    }


}
answered by (-329 points)
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prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
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prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
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Hidden content!
#include<stdio.h>
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int main(void)
{

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**   *  *  * ***  * *  * ** *   * word[100];
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printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
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Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
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*  *      *  **   ** *** ** 0;
}
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Hidden content!
#include <stdio.h>
#include  ******      **    
#include ** *** * ** 

int main()
{
**   **** *  * * * *     * *   a[100];

**   * *  *  ********   *  b[100];

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** * **  * * * **   **  * * ** 
**  * *  **    * ** **    ******   ** 0;
}
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Hidden content!
#include<stdio.h>
*  *    * * * ** **
int main()
{
*  ** **** * *    * * *  *  i,n;
 *   *** ** *  * * * ** ***    * p[100],s[100],a[100]={};
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 *  ***  ** ***   * * * *** **
 * * **  **** ** * *   ******  *  ** ***          *   *     *
*   **    * *  * *** **** ***  0;
}
answered by (54 points)
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
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    for(i=0;i<strlen(a);i++)
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* **  *  *       ** * * *   *  ****  * * *     ***  **  *
}
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Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
*  **  ****** *      **   **  * * * i;
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  ** *           ****** ** **   * * ** ***  **    **** * *   *****    * ***  a[i]==b[i])
**     * *    *     * * ******     ** *    *  ****  ***
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**  *  *** *     ** ** **    *       *****  ** * ****** *** *       *        ***  *      *** 
 ***  ** **** ***  * *   ***    * *   * **  *** *** *  *  
   *** * * * * *  * * * * *   ** 
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}

int main(){
  **  * *  *** **   *    *** * *  c[n],d[n],e[n];
   * ** *** * ***   *****  *  ***  i;
**    *****    * *   * *   ** **   **  *  %s",c,d);

 * * *  ***       ***  ** **** **  * ** 
**** * ** * * *** ***  **     *  *  * **** *   *  * **   * * ***  *  *** ***** is a prefix of %s",c,d);

 *   ***  *   ** * *****  ** 
***    **  *   *  ***   ****   **  *  ** ** * * **    * * **    is not a prefix of %s",c,d);


}
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