1 like 0 dislike
16.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 16.1k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * ** **
#include * * *** ** *
* * *** * * * ** * *
* ** ** ** ** *** ** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= **** * * * *

* * *** * ** * * ** **
* * ** *** *** ** ** ********* * == b[i]){
** ** *** * * * * * * * * ** ** * * *** * *** *
********** * * *** * ** *

**** * *** * * ***
if (cnt == n){
* **** * * *** * *** * ********* * ****** 1;
* *** * **** ****** ** ** ** * ** ** ** * * * ******
* ** ** **** *** ** * * * *** **
** *** *** **** * *** * * ** **** * **** 0;

}

int main()
{
* * **** ***** * s1[100], s2[100];
*** *** ****** i,j;

* ** * * * ** ** ** * * * **** s1);
***** ***** * ** * ** **** * * **** * * s2);
** ** ****** *** ** (prefix(s1, s2)){

* ** * * ** * * *** ***** * * ** * * * * ** * *** is a prefix of %s", s1,s2);
** *** * *** ***** * ** * ****** * *
** ** * * ****** * * * * * ** ** *
* ** * *** * *** ** * *** **** ** ** **** * * *** ***** * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* ** *** ** *** ******* * c;
* ** ** ** ** * * * * a[100],b[100];
*** *** *** * ** * * * *** ** ** * %s",a,b);
* * ** *** * * *** * * ** * *** ** *
* * ** * * ****** ** * * * * * * ** * * ** **** *** * 0;
* * * ** * **** ** ** *** ** * * %d",strlen(a),strlen(b));
** * ** * ** * * ********** * * ****** ***
** * * * * **** ** * * *** ***** ** * ******** *** * *
**** ***** **** ****** * * *** * * ** *** *** * *** ** *** ** *** * ***** **** **** * **** ** *** * ****** is not a prefix of %s",a,b);
** * * * ** **** * * * * **** ** *** * ** ** * * * ** * * *** ** ************* * * ** ******** *
* ** * * ** ** *** *** *** * * ** *** * * * *** **** * *** ***
* * **** * * ** ****** * * * * * * *** **** * * * * * ** if(c==strlen(a)-1)
* * ****** * **** ** **** * ** ***** * * **** * *** * * ** ** * ****** ** * ***** ** * * ** is a prefix of %s",a,b);
    }
** * * ** *** * ** * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** **** *** * **** ** * n,count;
****** * *** ** * * * * * ** * * ** *
******** * **** ** ***** ** ** * ** * %s",a,b);
* * * * * ** * * **** *** *

* * ** * ** ******* * ** * ********** *
****** * ** ** **
* * * *** *** * ***** * *** *** * *** ***** *
* ** * ****** ** ** ***

* ** **** * **** ***** (strcmp(a,c)==0)
* ** ** *** ********* * **
* * * ** ** ** ***** * * ** * **** * * * * * is a prefix of %s",a,b);
** ** * *** ****** *
** ** *** ** * **** *
* * *** * * * **
* * ****** *** * * *** ** * **** ****** ** ** * * * * * * is not a prefix of %s",a,b);
* * * * ** * **** *
* ** * * ** * ** * ** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* ******* * ** ** * * * a[100],b[100];
* * ** * * *** ****** * * ** ** * * *
    int l1,l2;
**** *** ****** ** * ** *
******* ** * * * * * * ** * ***
********** * * *** ***** * *
** ***** ** ** * ** * * * *** * * ** ***** *** *** is not a prefix of %s",a,b);

    }
** **** **** * * *** if(l1<=l2){
** * * * *** *** *** * * * * *** * * * prefix=1;
*** ** ** **** * * ** * * * ** * *** *** * *** * * i=0;
* ** * * * ** * *** *** * ** * * ***** * * ** ** **
* ** ***** * * ** * ** * * * * * *** ** * ** * * * ** *** * * * * *** * * (a[i]!=b[i]){
*** *** * ****** * ** * *** ** ******* ** ** * ** * * * ** *** * ** *** ** * ****** ***** ****
** ** *** * * ****** *** ** *** * *** ** * **** * ** *** ** * * * ** ** * * **** ** ** *** **
* * *** *** * * *** * ** * ** * *** * * ** * * *


* ** ** *** *** * ** **** * * *
** * *** * * *** * * * * * ** * * * * *
** * * *** ** **** * **** ** ** ** ** * * *** *** ** * ** ** ** **** is not a prefix of %s",a,b);
* *** *** * * * ** * *** ** * ** ** *
* * * ** ********** ******** **** ** * ***
** * ** * * * ** ***** ** ** * * * ** ***** * * ** ** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ****** * * ***
int main(void)
{

* **** * ** * *** *** pre[100];
* ** ** ** ** *** ** word[100];
* * ** **** * *** * ** %s",pre,word);
* **** * * * ** ** * * *** *****
*** ** ** * ** ******* *** ** *** * *

* ** ** * *** ** * i;
* * * * * * **** * *** * ** **
** *** * **** *** ** ** **
****** * * * *** ** * * ***** ** * * ***** ** ** *** * *
* ***** *** ** ***** * ****** ** ** * ** * *** *
****** * * ** * ******* ** ** ** * * * * ** ** * * * * * ** * ** * * is not a prefix of %s",pre,word);
** **** ***** ** * * ** * *** * *** * * * ** * * * **** ** * *** 0;
* * ** * ** *** ** * * *** **

** *** * * * * ** * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* ** ** * * ** * pre [100],a[100];
* * ****** ** * ** * *** n ,i;
***** ** * ** *** * ***** * **
* * * * * * ** ** * *
* ** ** * * ** ** * * * **
** * *** ** *** * **** ****
* *** * * ***** *** *** *** * * ****** * * (n=0;n<strlen(pre);n++)
* **** ** **** * * ** * * ****** * * * * ** * **
** ** * *** *** * * * ********* *** * * ** *** * *** *** * (pre[n]==a[n])
* *** * *** ** ** **** * * *** * * *** ** ** ** ** ** **** ***** *** * * is a prefix of %s",pre,a);
*** ** * * * * * * ** ** * * * * * * * *** ** * **** *** ***
** ** * * *** ** *** ** *** **** ** ******* * ** * * ** ** * *** ****** * ** * * * ** * is not a prefix of %s",pre,a);return 0;
* * *** ** **** *
* ** * * ** **** * * * ** ** * *** *** * * * ** ** * * * ***

*** ** *** ** * * * ** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * *** * * *
#include * ** *

int main()
{
* *** **** * ********* * * a[100];

* ** * * *** * **** * * ** b[100];

* ** ** * * * ** * * ** %s", a, b);

** * ****** *** * *** * len_a = strlen(a);

* * * * **** * * i = 0;

**** * * *** **** * *** * flag = 1;

* *** * * * * **** * * *** = 0; i < len_a; i++)
* * * * *** *** ** **
** * * ** * * * **** *** *** **** * **** *** != b[i])
* *** * * *** **** ** *** * * * * * **
* * ** * ** **** * ** * ** * * * * * *** ******** * ********* ********* ** = 0;
*** * ** * * * * *** * ** ** ** ** ** ***
** ** ** ** * * * *

***** ** * ** *** * * * * == 0)
* * * * ****** *
***** ** ** ***** *** ** * * * ** *** *** * ** **** is not a prefix of %s", a, b);
** * **** * ** * * * **
** * * *** * * ** ** ****
*** * * * * * * ** *
*** ***** ** * ** * **** * ** * * * ** * * * is a prefix of %s", a, b);
* ****** * **** ** *** ** *
** * * **** *** * ** * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * **** *
int main()
{
** * *** * * ******** * ** ** i,n;
* * * * * *** ** ** * * p[100],s[100],a[100]={};
****** * * * ****** *** * **** ** %s",p,s);
*** * * **** ** ** * * ***
******* * ** * * * ** * *** * *
** *** * ******** * ***** *** ***** *
* * * * *** ** * * **** * ***
* *** * *** * * ** * ** * *** * * ***** *** ** **** * ** * * * is a prefix of %s",p,s);
* * * **** * ***
** * * ** ** * *
* **** ****** ** * **** * ***** ** * * * ** is not a prefix of %s",p,s);
* * * **** *** ***** *
* ****** ******* * ** ***** ** * ** * ** **
** * * *** * * * * * ** * ** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
**** **** ** ** *** * **** * ****
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * *** * ** ******* *** * * * * **** **
* * ** * * *** * **** * * *** *** * * * * *** *** ** * *** * * * ** ** ** * != b[i])
** * ** * * **** * ** ** * *** * * ** * * * **** *** ** ** *** **** * *
* * * ** ** * * ** ******** ******** *** **** * ** * * * * ** * ** * * *** * **** * * ** * * ** *** **** ** * *** is not a prefix of %s",a,b);
****** * ** * *** ** ** ** * * ** * * *** * ****** * * *** ** ** * * * *** * ** * * * * * *** * * ** **
* * * * ** * * * * ** * * **** ** **** * *** *** * * * ** * * * **
* **** * * * * ******* ** * * ** * **** ** ** ** * * *** *** ** * ** ** * * * * == b[strlen(a)-1])
** * *** **** ** **** * * * ** * * ** **** ** ** ** ** * * * * * *** * * ** ***** ***
* * ** * *********** ** * * *** *** * ** *** **** * * ** * ****** * *** ** *** * * ** ** *** *** ** ** * * ** ** * is a prefix of %s",a,b);
** * *** * ** * * *** ** * * * **** * * *** ** * * ** ** * * * * * ***** * ****** ** ** *** ** * ** ***
* * **** * * * * * *** * * *** *** * ** **** **** *** * * *** **** * * ** ** ** * *
* * * *** ** ** ** *** *** * ** * *** *** ****
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* ** ****** * * ****** ** i;
* * ***** * *** **** * (a[0]!=b[0]){
** * ** ** ** **** * ****** * ** * ** ** ** * * * * 0;
** * * * * * * * * ** ** *
** **** * * ****** ** * ** * * * * *
* * * *** * * *** * * * ** *** ** ** *** * **** * a[i]==b[i])
* * ** ** ** ** * * ** * * * * * * **
* * **** ** ** * * **** ***** **** ** ** * ******* * *** * * 1;
**** * * * * ** ***** ** ****** * * ***** * *** * * * ** ** *
** *** ** **** ** ** * * ** **** *
*** **** * ** * * **** ** * * ** ***
*** ** * *** * * * 0;

}

int main(){
** *** * ** ** ** c[n],d[n],e[n];
*** ** *** **** * *** i;
* ** * ****** *** **** ** *** * * * %s",c,d);

* ** ** *** * *** ** ****
***** *** * **** ** * * ** * **** ** * * ** ** is a prefix of %s",c,d);

** * * * **** **
* *** * * *** *** ** * * * **** ** ***** ** * **** * ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.65
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 14.7k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 14.1k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 17.1k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users