Final Exam 2 (20%)

1 like 0 dislike
15.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 15.5k views

37 Answers

0 like 0 dislike 
Hidden content!
#include ** *   ******  *
#include * ** * * ** *  **   * 
**     ** ** ***    * * **
**  ** ** *  *  *  ***   *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= **  **  * *   *  

  **  * * *   *** *      *  **   * *
 ** **  *** * **  **** ** *   == b[i]){
***  *** ***  *** * **  ** *  ***     *   * *** ** *   *
* *   ** *   *     * *****  *

* *    ****  *   *    *
if (cnt == n){
*  * ** *** ** *       **** **  *  **  *** ***  *** 1;
 *** *   * **  *     **   ** * *  * *      *  *  **** 
*   *   *  *    ***       
  *** * * ** **      * **  * * *** *  * **          *  *  0;

}

int main()
{
 *   **     * **    s1[100], s2[100];
 ** **** * * *  *  * ** i,j;

*** ***** **           *  * **  *** *   s1);
  ** **  *  * * * ** **   *****  *  ** **   **  ** s2);
** *   **  *** * **** *  (prefix(s1, s2)){

* ******  * *** **  *** *  * *     *   **   *****  **  * is a prefix of %s", s1,s2);
 * ****** *******    ** *   ** *********  **** * * 
 *** * * * * ** *   *   * ** ***      *** ** 
*   *****  *     * * ** ***** *   ***** **  *  *   *    ******    *  * ***** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
  ** * *   **  *    **  **    * c;
* * * *  ** **** *   *   a[100],b[100];
     ** * * ** ** **  * *  *  *  ***   *  %s",a,b);
  * ***   ** * * ** ***** * *  *** **** *****    *
*  * **** *  * *   *   *** *** * *   ****  *  * *****  **  * 0;
**   * **     *    ** ** *** * ***   *  * * %d",strlen(a),strlen(b));
 **  * *  * * ** * *    * *******  ** ***   * ** * * 
***      ** *  ***   *  * *  * * *** *** * * **   *  ****    *   **  **  *   *     ** 
   ** * **   ***  * *     ******* * ** *** ** *   ** **    * ** *   * ** *   *** * * *     **  *  * **  * is not a prefix of %s",a,b);
**  * *    * *** *  **  * *** * * *******  **** ** *     *    **  ** **    * **       * ** *       ***** * ****
 * * ** *  * ** **   **   *** **** *  *  **** * *      *** * *** *** *****  *    * * *  
  *  *   * *** * * *        *** *  ***    ***     *** *****    *  * * *   ***  if(c==strlen(a)-1)
*        ***** *   * *******     ***    * *   *** * **** * *   ** *  *****   *  ** **   * *** *** ** * * * *     is a prefix of %s",a,b);
    }
  * **  *** * **  * *  **** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*  *        *  *  *    *   * * * n,count;
 *     **     *** *   ******* **** **** **   ** *  
*        ***  *  ** *****  ** *    *** * *  %s",a,b);
 ** * ** ***   **    ******  *  *

*  **     *  * *** *    * **  * *  * *** ***** *   **** *
*  **   *** * ****    * *
* **  *  * * ** **    * *   ***    ****  * ** *      *  **   
 *   * *** *   * ***   ** **

*   ****  * ** *       **  (strcmp(a,c)==0)
*  ****   **** * *  **  * 
    *** * *   *  ** **  * *****  **      * *     * *** * * ***  * *    is a prefix of %s",a,b);
** **** **   *****   **
   * ***   *  * ***  * ** * *   ** ** 
 ** ******   * * **  ** * *
***   ** *  *    * * **  *  *  *  ***  *****    ** ****  *** *   * ****  is not a prefix of %s",a,b);
** ******* *** ** * **
 *  * **  *** *    *    *  *   * * *  0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
 **      *** * * **  *  ** * ** * a[100],b[100];
 *** * *****     * **   * ***  **  ****    
    int l1,l2;
 **  *** **    *       **  **   *  *
  * * ***** *   ** ** * * *** * **  * ***
      *      ***   * *    * ****  * **  
  **   *   *  *******   *  **** * *  * * *  ***      ** ** **  * is not a prefix of %s",a,b);

    }
* ** *    *** ***  ***  * *  * if(l1<=l2){
   *      * ** * *  * **  *      *      **********   ***  *  ** prefix=1;
*** ***   **   **     ****   *    ***** **  * * *****  * * * i=0;
**       ** * * * *** * * **     * ** *  ** **   **  ** * ** ****  *
** * *       ****  * ** ***   ****    *** *  * **    *** *  * * *    ***** (a[i]!=b[i]){
  *  **** *** *  **  ********    **  *****   **   **** ** *        ** ** *   *  *  * **  * ************  **      * *
  * * **  *********** * **   *****  **  **** * *** * *  * ***   * *    *    ***  * *    **** *    * ** **** * *   **    
 * ***  **   * *  ***  * **** **  * ** *    *  **********          * *  ** ** * 


 *  ** *  * * *     **** * *******  * *   *     *  ***
*** ** * * ****  ** ****** * *   **  **  ** *****  * * ** ** * 
* * * *  *    **  **  *   ** *** *  *     *   * *** ** *  *** * ** *  ********      ****    * * * is not a prefix of %s",a,b);
  *   *     *     *        ***   *  * ***  * **   * 
***  **     *   ***   * **  *  ** * * *** ** *** *
** **  ** **   *  * *  **   *  *** *****  *       *  *** *** *   * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
 ** * * * * **  * * *  
int main(void)
{

 ** * *** **   ** **** * *    **  * pre[100];
*** *  *  *      ** **   word[100];
* * ***      *  *  *   **   *** ** *   *  %s",pre,word);
  * * ***** * * * *****  **** * **  * ** * 
* * *   * * ***  ** ** * ** **  *  *      *  

   *     **** * * ******  *   i;
* *  ** **    * ** * * **  ** * *  *    **** 
******* **     * *   ** ******* 
 *   *  *  *    ****    ** * * * * *     * *   * * **     * *    *** *
****      *  *  * ** ** * **** *    ******    ***  *  **
** * *    *  *** *   *   *   ***** **** *******  **** ** *    ****** ** ** *   *** **  **    *  is not a prefix of %s",pre,word);
* * ********* **    ***** * ** ***    * ** *********** ****** *** *   *** * * **** 0;
    ** *   * *** *    * *     **** * *  **  ** * ** *

 *   *  *  * *   *  ** ** * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
***   *  *** **  ***  ** * pre [100],a[100];
  *** ****  *** ** ** *  * ***  n ,i;
 * ********** * * * *** ***  *      *  
  *  *    **      **  * * *  ** * * **  * 
*    * *  ** * **  * ***      * ** * ******* *  
 *  * *** *** *   *** 
** *  *   * **    **** *  *  *   **  * * * * *** * ** (n=0;n<strlen(pre);n++)
* **** * *** * **** * * ********* ***  ** ***   * ****  * 
 *   *** ** *  ** ** * ** *  **** ** *** ** * *   **    * * *  ** **     ***** *  (pre[n]==a[n])
    *  ****  *  ****   **   **** *** *    ** *  *    ** *  *  ** * * **   **    * *  **** ** is a prefix of %s",pre,a);
****   * *  *  * * ** **   **     ** **** * * ** * **  ****  * *********** * * ****
** *** **  *      *    * ***  ****  *   ** *****  *  * * *********  *     **** * *  ** * ***  ***  * *** * *   **** is not a prefix of %s",pre,a);return 0;
* * *  ** **  ***  * *  * * 
* **  * ** *  * * ******  **   * **  * ** * *  ** * ***  *   *  ** ****  ** ****** 

 ** * * ***  ****  *** *  *** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **     * ** *  
#include  ***  * **** ** 

int main()
{
 * ***  * ** ** ***     ***  ***  a[100];

 **********  * * ***** *  b[100];

** ** *   ***   ***** *  ***   **    %s", a, b);

***  ** *  *     * *** * * len_a = strlen(a);

  *   * ** *    *  *  *** *  *  i = 0;

  * ***   **** * ***   *** * flag = 1;

  **  * *   *** **  **  **  *   * = 0; i < len_a; i++)
** * **   **   * *****  * *
  *  * ***         * * ***   ** * * **** ** *    *** *** *  * * != b[i])
 ** ******** **  * * *** ** * *  ****  *  ** **    ***   
***   * * **    ***    *  ********   *     ***  *     * * **** *********  *   * * *    * = 0;
* * *  *******  *   * ***  *** * *** *     ***  *  * **** *
  * *     * ******   *  *  

    ** ******* *** * ** ** * * == 0)
**  ******   * *  *   *    
* ****** * ** *   **   * * **      *** *** ** ** ** ***  **** is not a prefix of %s", a, b);
******   * **  ***  *    *
 *** *** *  *   ** **** * * 
*   *****  * ** *   *        **
 * *   *    * **  ** *********** * **  * ***** **    *      is a prefix of %s", a, b);
    *   * * *  **  **    *  **** * 
*    ***   *  ** ***   * * * * ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
      *   ** *   ** *
int main()
{
* **    **** ** * * ** *  * *  i,n;
** ** * **    * *  ***** p[100],s[100],a[100]={};
* ***** ** * ** *** *   * ** * **   %s",p,s);
**   *   ***  **    ***  *** *    * * *
 *    *** ** ****   ****** * *    *
 * * **  **     *** * ** *  * *  ** * ***  ** *
 *  ***  *  *  **** * *****    *    * *
*  **  * * * *****  *  **** **   ** * * *  * * **  ****** * * *** is a prefix of %s",p,s);
*  *    * *  **     *  *
*         *** *  *  **    ** ***
***  *********  *   *** * ** *    *** *      ****   *  ***   * * is not a prefix of %s",p,s);
****** **  ** ***      * **   
  ***   * * *    **   ***    * **** ****   *** ****  **   ** *  
 ***  * *  ***** *    ** *  *     0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
     * ***** * * *  *  *  *   *     * **     
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
 *** *  **** **  * *******  *  *  ** * *  *   ****   **  * **
**** *   ***  ** ***  ** *  *** * ****   *** *  ****  **  ** **     ** *  *** *   * *   *    != b[i])
 * *  * **   * *  * **  * ** *  ***** **  *  **    ****  ******* *  * **    *  *    *  *   *** ******  * 
    **** *  * **    **   **  *   * *** ** ** * ***** **  * *     *    **  **   ** *****    *** * ** *** *  *        *   *  * *   * ** * *   *  *   is not a prefix of %s",a,b);
  *****    * * *** *  * ***     ** *  * * ***  * * * * **   *  ****  *   *****  *  * **    *  ********  ***    ** ***  **  ********** ** ****
 **** *   * *****   * *** **   ** *  *    *        ****     * * * *  **    ** ****** **  **  *  
** * *** ** *** *** ** * ** ** **** * *  ** *  **      *    *  *** ** **  **  **  *   ** *** == b[strlen(a)-1])
  **  **  * *    * *** **  **   ** *   *     ***  ** ** * * *  ***  **     ** ** * * * * *** *  *** *  
*   * * *   ***  **  **  * *   *******  ** *  * ** *** ***  *      *    **      *** ***** ****  ** ***  *    * *  * ***   *** *  *  *   *** * is a prefix of %s",a,b);
     * **   ***  **  * ** *** **  *    ** *   * *  * **      * * * ***** **    * **   *    * * *   **  *****  * ** *** **** * ****
***** ***** * ** **  ** ****  * * ****    * ** *       **    *   ***  **    *      *  ** ****   *** * * *****  * * * 
  ******         ****** *   * * **** **** * *     **   *  * 
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
   * * ***  * *  **      * *** * *** * i;
* * ***        *  * ****  *  *     (a[0]!=b[0]){
* ** * ***   ** *    * *** ** **  *** *    ** *  **  * ** 0;
   **   *** *  **   ******      *
*   **  *   * * *    ** **  *  *   ** **** * * * **  **
***   ***  ** ** *** ***  * *** * *    ** * **  **  *    * * * ** *** **  a[i]==b[i])
    ****** *     * *         ** * ***** ** **      
   * **  *** **** *   *   *   **  ****  ****      *  * *  ***  *  **** * *   1;
 ** * *   ****   * ***** **   *  * *    **  ***  *   * **   **** *  *      ** **   *    
 * *** ***** ***       *  *  ***  ** ** **** **  *****  *
*  *  **   **  *      **      ** **
** ***   ** * * ******  **     * 0;

}

int main(){
*** * ****  ***    * *  *  *  ** c[n],d[n],e[n];
** *  * * **        * ****   **    i;
   **   ***** *****     ****  *   %s",c,d);

********** ****** *  * * *  *   
 * **      *  * * *** * **    ****** ** ***  ** *   ***** *  ** **   * *  is a prefix of %s",c,d);

  ***   *  ** * ****  *** ***     *
** *  ** *   ** ***  *  **  *       * * *** *   **  *   **  *  *    is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 14.1k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 13.4k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 16.6k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.5k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users