1 like 0 dislike
7.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 7.2k views

37 Answers

0 like 0 dislike
Hidden content!
#include ** **** *
#include * **** ** *
** * ** * * *
* * ** * *** * *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** * **

***** * * *** * * **** * **** **
******* **** ** * ** ** == b[i]){
* * ** * * * ** * ** * * * ** *** *
** * * * ** * * * *

* ** * * *
if (cnt == n){
* ** * ** * * * * ***** * * * ** * * * 1;
* * ** * ** * *** * * * **** *** * ** *
* *** ** **** * * ** **
* ** *** * ** ** **** ** ******* * ******** *** ** 0;

}

int main()
{
*** * * * **** * s1[100], s2[100];
* **** * **** ** ** i,j;

**** ** ** ** * * * ** ** *** * s1);
** *** ** * * * ** * * * **** **** s2);
* **** * * * * *** (prefix(s1, s2)){

** * * ** *** * **** ** **** * * ** * * * is a prefix of %s", s1,s2);
*** ***** * * * * *** ** * **** *****
** * ******* * *** * * * * ** ****** * *
******* ** * * * * ** ** ** * ** * **** **** * * * * * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * * * **** * * * * * c;
** * *** ** * * * a[100],b[100];
* * * ** * ** * *** ** * * %s",a,b);
* * * * ** ******* * ***** * *** * * ***
** ** * *** * *** ** ** * * ** ** * ** * 0;
** ** ** ** * * ****** * ** * %d",strlen(a),strlen(b));
* * * * * * * * * ***** * * * * **
**** * *** *** * * *** * * ** ** * * * **** * **** * * * * *****
*** * *** * **** ** * * ** ** * ** *** *** * **** *** ** * * * * ** ** * * * ** * *** ** ***** is not a prefix of %s",a,b);
* * ** * **** ** * * * * * **** ** * * * * * ** ** * ** ** ***** ***** ** * ** * **
* *** * * * * *** *** *** *** ** * ******* * ** ***** * ***
** * *** * * * ** ** **** ** * ** **** * ** **** * ** ** ** * * if(c==strlen(a)-1)
* **** * ********* * * * *** * ** * *** **** *** * * ** * * *** * * * *** * ** is a prefix of %s",a,b);
    }
** ** * ****** ** * * * ** * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* ********** * ***** n,count;
**** **** * ******** *** * * *** * *
* **** ** * * * * * ** ** * %s",a,b);
*** *** ** ** *** * ***

* ** ** * * ** * * ** *** * * * **
* **** * **** ** *
* ** **** * **** * ** ** * ** **** **** * * * *
** **** * * * * * *

* * * * * (strcmp(a,c)==0)
* ** *** ** ** **
** * * ** * * * * * * * * * *** ** * is a prefix of %s",a,b);
* * * *** * * *** *** *
*** * * * * * * *
*** *** * * * * ** *
* * * ***** ** ***** ** * * * * * * ******* * * is not a prefix of %s",a,b);
* * * ** * ***** *
* * * * * *** * * * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * * * * * ** ** ** a[100],b[100];
*** * * **** ** * * * *** * ******* * **** ****
    int l1,l2;
** * *** * ****** * ** *
** * ** * * ** * *
* * * * * ****** ** **** **
* * * * * * * ****** * * * * ***** ******* ** * ** * ***** is not a prefix of %s",a,b);

    }
*** *** ** * ** * ** * if(l1<=l2){
** * ** * ** ** * * * ** ** *** **** * * prefix=1;
** * *** ** * * **** *** * ** ** * * i=0;
* *** * *** * ** ** * ** * *** * * ***** ** ***** *
******** * ** **** ** * * * *** * ** ** * ** * *** *** * (a[i]!=b[i]){
* ** * *** * ****** * * *** * * ** ** * ** * *** * ** *** * ********** ** * *
***** **** * * *** * * ***** ** **** ****** * * * ** * * ** * * * * ** ******* ** *
* * ****** * ** ** ** * *** **** * * ** * * ** * * *


** *** ** **** *** * ** * ** ** *** ** * ** * **
** *** ** * *** * *** * * *** * * ** * ** *
**** * * *** * *** * * *** * * * *** ** **** * ***** * * * ****** * ** * is not a prefix of %s",a,b);
**** ** ** * *** ** ** *******
* **** * **** * * * * ****** * *** ** *
*** * ****** ** * * * **** **** * * *** * * ** * *** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
********** ** ** ** * *
int main(void)
{

** *** * ***** **** * pre[100];
** **** * *** * ** * word[100];
**** ** **** ***** *** * **** * %s",pre,word);
* * * ** **** **** **** ****** **
** * * ** * * ** ** ** **** * ** **

** * * *** * * ** * * ** i;
** * *** **** * *** * * ** * * ** **
* * * * * * ** ** * *
**** * * * * * * ****** ** ** ** * * * *
**** * ** * *** ** * * * * ********* ** * *
* **** * *** * **** * ** ** ** * * ** * ** ** * *** ** * ** ** *** *** is not a prefix of %s",pre,word);
******** * *** *** * * *** * ******** ******* * * * ******* * ********* * 0;
* * ** * * * * ** * * * *** *** * *** * **

* * ***** * * * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * ** ** ** ** * * pre [100],a[100];
* * ** *** * *** *** ** * * n ,i;
* * ***** *** ********** ** *
* * * * ** * **** ** *****
* **** * ** *** * ** * * *** **** * ** *
* ** * *** ** ** ** * ** *
* * * * *** ** ** * ******** ** * **** * (n=0;n<strlen(pre);n++)
*** *** * ** ******* ** * **** ** * *
** ** ** *** * * ** * * * * ***** * **** * **** * ** ** * * ** * * ** (pre[n]==a[n])
* * * * * * * ** * *** *** ** *** ****** ** ** ** *** * ** ** is a prefix of %s",pre,a);
* *** * ** * ** * * ** ***** * **** * * * ** **** * *** *** ****** **** *
* * * ***** ** ** * * * * * ***** * ****** * * ** * * ******* * ** * * * * * ** *** * ** * * ** * * * * is not a prefix of %s",pre,a);return 0;
*** ** * * **** * *
* * * ***** * ** * ** * * **** *** ** **** * ***** *** * * * * ******

* *** *** * *** ** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * ** *** *
#include **** * *

int main()
{
* **** * ** **** **** * a[100];

* * * * * b[100];

** ** * **** ** * ** * ***** * * * %s", a, b);

* * **** *** * *** * * len_a = strlen(a);

*** * ** * * * * * i = 0;

** **** * * ****** * * flag = 1;

** *** * * * * * * ** *** = 0; i < len_a; i++)
* * * * *****
** *** ** **** * * * ** ** ***** != b[i])
** * **** * * ** * ********** * * * *
* * * * ** ** ***** ** ****** * ** *** **** *** = 0;
* * **** * * * ******** ** *** * ** * ** * * *
**** * **** ** * ****

******** ** ** * ** * == 0)
* * * * * *
* * ** ***** * * *** * * * * ** * * *** *** *** * is not a prefix of %s", a, b);
* * * * **
****** * *** ** ** * * * *
* ** ******** * * *
* * * * * *** * * ** **** ** * ** ** * *** * ** * * is a prefix of %s", a, b);
***** *** **** *** * ******
* * ** * **** * *** ** * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * *
int main()
{
** *** * * * * i,n;
** * ***** * *** *** * ** * * p[100],s[100],a[100]={};
* * ** ** * ** * * **** * *** **** ** %s",p,s);
** ** *** * *** * * **
* * *** *** * ****** * *** * *
*** ** ***** * *** * * ** ** *** * * ***
* *** * ** *** * * ** ***
* * *** ***** * **** * * ** * ** ** * ******* *** ***** *** is a prefix of %s",p,s);
* * *** *** * * * ** ** *
* **** * * ** * * *
***** *** ** * **** *** ** * ** * * ** ** ** is not a prefix of %s",p,s);
* ** **** ** * * * ** *
* * *** ** ** * ** *** * *** **** * *
* ** *** ** * ** *** * * ** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* * * ** * * * * ***** ** * * ** ********* * * *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
*********** * ******* * * * * ********* * **
* **** * * ** *** * * * ****** ** * *** * ** ** **** ** * ** * ** != b[i])
* * ***** *** * * * ****** ** *** * * * * * ** ****** * ** ***** * *
** * *** * ***** * * * ** *** * **** * **** * * *** * *** * ***** * * *** ***** * * **** * * * ** * ***** **** *** * *** is not a prefix of %s",a,b);
* * ***** ** * ** * * * *** ** ** * * * ** * * * ** ****** * *** ** * * * * * * * *** **** * * ** ****** * *
* ** *** * *** ** * *** ***** * *** * ** ***** *** * * **** ** ** ** * *
* * * ** * ***** * *** ** * ** * ** * **** * *** * ****** * * * == b[strlen(a)-1])
** * *** *** * *** * * ** * ** ** * * *** * ** * *** ** * * * * ** **
***** * ** ** * * * ** * ** * **** ** * * * *** * ** **** ** * * ***** ** **** * * *** *** *** * * ** ******* is a prefix of %s",a,b);
** ** **** * * * ** ** * ** ** **** *** ** ** * * * ** * * * **** ******* *** * * **** ** * *** ***
* ** * * * *** * * * * *** *** ** * *** * * * * *** *** *
** * **** *** ** **** ** ** *** *** * * **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* ** **** ** ** *** * * * i;
* ** *** * * ** * * (a[0]!=b[0]){
*** * * * ** * * * * * *** * **** *** 0;
* **** * * * * * ** * *
*** * * ** ** * * ***** ****** ** * ** * *
* ** * * * ** ** ** * *** ** ** * ** * * ** a[i]==b[i])
* * * * * * **** * * ******* ** * ** *
* ** * *** **** * ** * * * * * ** * *** ** * ** * ** * 1;
** * ** * ***** * * * *** ** ** * * ** ******* **** ** ******** **
*** ** * * ** * ** * * * * * ** ** * **
* *** ** *******
* * * * ** *** ** *** * * 0;

}

int main(){
** *** ** ** * ** * * ** ** c[n],d[n],e[n];
* **** ** **** ** i;
*** * * * * ** * * *** * *** * %s",c,d);

* * * * * *** * * ***** *** ** *
**** *** *** * ** * ** * * * **** * * * * * * * * ** ** is a prefix of %s",c,d);

* **** **** * * **
* ** * *** *** **** *** ** **** * ****** * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.57
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.5k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 6.5k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.5k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 5.8k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users