1 like 0 dislike
13k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 13k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** * **
#include * ** * **
* ***** * * * *
* ** * * * * ** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= **** *

**** * * * * * * * ** ** *
* ***** ** * ** * == b[i]){
** ** ** ** * ** * ** * * * * ** * * * * ** *
* ** ***** ** * * * *

* * ** ***** ** * **
if (cnt == n){
* * * ** *** * * * **** * * * *** *** *** 1;
* **** * * ** *** *** * ** ** ** * *
* * * ***** *** * ******* *
* ** ** * * * ** ** * ** ** *** * * * 0;

}

int main()
{
* ** * ** * * ** s1[100], s2[100];
* * * * ** * * * i,j;

******* * ** * * * * ** * * s1);
** * *** * ****** ** * * ** s2);
* * * * * * (prefix(s1, s2)){

* * ** ** * * **** ** * * * ** ****** * **** is a prefix of %s", s1,s2);
** * * ** * ** * ** * * *** * * ** *
* * * ** *** ** * ** * *** * * **
* ** * **** * * ** * ******* * ********* * ** ** * * ** * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* ***** ** ** * ** * ** c;
** * * ** ***** *** * *** * a[100],b[100];
***** ** ** *** * * *** * * * %s",a,b);
** ** *** ** ************ ** *** * * ** *
** * ** ** ** * * * * *** * *** ** *** 0;
* * * * **** * * *** * * ** * %d",strlen(a),strlen(b));
* ** * * * ** **** * * * * * **** *
* * * * * *** * * * *** **** ****** * * * * ***** ** * * ** **** **
* ***** ***** ** * * * **** * * ** * * * * * ** ** ** * * *** * **** *** * ***** **** * ** is not a prefix of %s",a,b);
*** * ** ***** * * ** ** ***** * * ** *** * ** * ** * ******* * * ***** * **** **
* * * ********** * ** * ***** **** ** * ** ************* * * * * **
** **** * ******** * *** ** * * * * *** * ** * ** ** * ** * * if(c==strlen(a)-1)
* ** ** ** ** * * * ** *** ** ** * ** ** **** *** *** * * * * * * ** * ***** * * * is a prefix of %s",a,b);
    }
** * ******* * ** * * ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* ** ***** *** * **** ** n,count;
* * * * *** ** *** * * * * ** * **
******* * ** * * ** * * * %s",a,b);
* *** * * * * * * * * ***

* *** ** ******* * * * * * *** * ** * *** ***
*** * * * ** ***
* * ******** *** **** * * *** * * * ******* **** ****** *
* * ** * ***** ** **** *

**** **** ** * ** *** ***** (strcmp(a,c)==0)
******** * * *****
** ** * * *** * ** * **** * * *** ** * ***** * *** *** * is a prefix of %s",a,b);
* ** **** ****** * *
* * * * ****** *** * *** *
***** * ** * * * **
* * **** ** ********* * * * ** * * **** * * ** * ** * is not a prefix of %s",a,b);
**** **** *** ** **
**** ** * ** * *** * * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* ****** * * * * **** a[100],b[100];
* ** * *** ** * * ** * * * * * * * *** *
    int l1,l2;
* * ** **** * ** ** ** *
*** * * * ** * **** * ** **
*** * * * * ** ******* * * * *** * ****
* * ** ** ** * ** * ** * ** * ****** * ** * * * *** * is not a prefix of %s",a,b);

    }
* * *** * * ** ** ** if(l1<=l2){
*** * ** ** * ***** **** * ** * ** *** *** *** * prefix=1;
*** ** **** * * ** * * ******* *** i=0;
* * ** * * * * * *** ** ******* ** * * ** ** **** *** *
** **** ** ** ** * *** * * ******* * * * ***** ***** * * * (a[i]!=b[i]){
** * * * ** ** * ****** ** *** **** * **** **** * * ** * *** *** * * * * ****** * * **
* * ** ** * ** *** * *** ** * * *** * * ** ** ** * ** * *** * * *** ** ** ** **
* ** * ** ** * ** * * **** ** *** * ******* *** * *** * ***


** ** * * **** * *** ***** ** ** * ** * * *******
** ** * ** * * ** ** * *** *
* *** ** ** * *** * * ** * * * **** ** * * * * is not a prefix of %s",a,b);
*** ** * * *** ** * ** ** * ** * * ***** ****
* * * ***** *** **** * ******* ** *** **
** ** ** *** ***** * * ** * * ** *** * * ** ** * * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * **** ** * *
int main(void)
{

****** * *** * ** * *** pre[100];
** * *** * * * * * * word[100];
* * * ***** ** * ** ** * *** ** * %s",pre,word);
* ****** ****** ** ** **** **
* * * ** * ** *** * * * * * *

* ** * * * *** * ** i;
* * * ** * * * * * ** ***** **** * * **
* * ** *** * * ** ****
** * ** *** ******** ** * ** * *** ** ** ** * * *
** *** ** *** *** ** * * **** ** ** *** ** * * *
** * * * * * * * * **** * * * ** * * * * * * * * *** is not a prefix of %s",pre,word);
* * ** * *** * **** * * *** ******* * * ** * * ** * ** * ** *** 0;
** * ***** *** * *** ** * * * * * ** *

* *** * *** * * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** * * ** * * ** pre [100],a[100];
* **** * ******* ** n ,i;
* *** ** ** ** * ** ** * ****
* ** **** *** * * ** ** ** ****** *
*** * * **** * ** * ** * ** ******* *
* ******** * *** * **
* * * ** * *** * * * * * **** * ** ** (n=0;n<strlen(pre);n++)
* * ** * * * ***** **** * *** ** * * *
* * ** * * ** * ** * ** * * * ** ** *** ** ** * *** * (pre[n]==a[n])
***** ** * * * *** * * * **** ** ** * * *** * * ** * * * ****** ** * is a prefix of %s",pre,a);
**** * ***** ** **** ***** ** * ** ** ** ** * *** * * ** * *** **** *** *
* * ** ** ** * ** * * *** **** * * ** * * * * * **** *** ******** * * * ** ** ** * * *** **** is not a prefix of %s",pre,a);return 0;
* **** *** ** ** ** *****
* * ** ** ** *** * * * *** ** * ************ ** * *** ** * * ***

*** *** **** * * * * **** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * ** * *
#include * ***** *

int main()
{
* *** * *** * * *** *** a[100];

*** * * * * * *** b[100];

** * *** * * * * * * *** * * ** * %s", a, b);

* * * * * * *** len_a = strlen(a);

** * **** * ** ** *** i = 0;

*** ** * * * * ** * * flag = 1;

* * * ** * * ** = 0; i < len_a; i++)
* *** * * * ** * * * * * *
* ** ** ** ** * * ** * * * * * ** *** * * != b[i])
* **** ** *** *** **** ** **** ** * ****** ** ** *
*** * * **** * * *** ***** ** * ** *** * * ** ** * * ** ** * = 0;
**** ** * *** * ** ** * * * ***
* * ** * *** * ** *

* ** ** ** * * * * == 0)
*** * **** ** * ***
**** * ** * ******* *** ******* * * * * ** * is not a prefix of %s", a, b);
** * * * ** * ** ** *
** ** ** *** ** ** *** ***
*** ** * * ** *** * * *
** *** * * * ***** * ** ** * ** * * * ** ** ** **** * is a prefix of %s", a, b);
* * *** * *** ** ** * **
****** * **** * * * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* **** * ** * * **
int main()
{
* * * * *** * * * ** * i,n;
*** ***** *** ****** ** ** ** p[100],s[100],a[100]={};
* * * * **** ** * * ** ****** * %s",p,s);
** ********* * **** * ** *** *
** *** ***** *** * ** *** ***
***** ** * * * * * ** * *** * *** **
** * ** **** ****** **** *** *** **
* * * * * * * *** * * **** ** ** * * * ********* * ** is a prefix of %s",p,s);
****** ** * * * ** *
**** ** ** * * * * ***
** * ***** * ****** ** ** * *** * *** ***** * * ** ** ** is not a prefix of %s",p,s);
****** * ** ** ***** *
* ** ** * * * * * ** ** *** *
* * ** * ** * *** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
**** * ** * ** ** **** ** * * * * * **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* ** * * * * ** ** ** * *** ** * ****
***** * * ***** * * * * * * ** **** *** * * *** ** *** ** ** *** != b[i])
* * * *** ** **** * ** **** * *** ** ****** ** ***** ** * *** ** * * **** * **
***** * *** * **** ** *** ** *** *** * * * * * * *** * * * * * * * * ** * * ****** * * * ** ** **** ** * ***** is not a prefix of %s",a,b);
* * * *** * ** * * * ** ** ** * *** *** *** ****** *** ** * ** * ** **** * ** **** ** * * *** **
******** * *** **** * * * **** *** * * ** * * ** ** ** * ** * ** *** *** ** * * *
** ** *** * * ** **** * * * ***** ** * * ** * ** ** ***** ** * *** * ** * == b[strlen(a)-1])
* ** ** ****** * * **** **** *** * **** * * ** *** * * ** * * * **** * * * **
** ** * *** ** **** ** * *** **** * * *** * *** ****** * * *** **** *** * ** * * * * * ** * ** **** *** * ***** * is a prefix of %s",a,b);
** * * * * * * ** ***** ** * * ** ** * * * * **** * ** ** * ** ** ** ** ** * * ** **** *** * *****
** *** * * *** * * * ** * ** ** * *** * * ** **** * * * ** ***** *** **
*** ** * * **** * * * ** * * * * ** **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* *** * * ** * *** ** * i;
** * * ** *** * * * (a[0]!=b[0]){
* * * ***** ********** *** ** * * * *** ** **** 0;
*** * * * * ***** *** * **** *
*** ** ** * ** ** ** * * ** * ****
* * ** ** * * ****** * * ** * * * ** *** * *** **** a[i]==b[i])
* ** * * * ************* *** ** * **** * * *** *
****** *** **** ** * * * * * * * * * ** * * ***** * * *** ** * * **** 1;
*** ** ** ** * * *** * * ******* * * * * **** *** *** ** * **** ***
* * * *** *** * ** * * * *** ** ** * *
*** * * *** * * * ** **
*** ** * * ** **** ** * * * 0;

}

int main(){
* * ** *** ***** **** c[n],d[n],e[n];
* ** *** ** *** ** * * i;
* * * ** *** * ** ** %s",c,d);

* * * ** **** * *** ** ***
** * ** ** **** * * * ** * *** *** **** * * is a prefix of %s",c,d);

***** * *** ******* * ***
** * * * * * *** * **** * * *** * *** *** * **** * * * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.120.163
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.6k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.5k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.4k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.3k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users