1 like 0 dislike
17.4k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 17.4k views

37 Answers

0 like 0 dislike
Hidden content!
#include ** **** ***** *
#include *** ** * * *
**** * **** ***
** * **** * ** * **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * ******* * **

* * * * ****** * * *** * ** *
* ** ****** ****** * ** == b[i]){
* * ** * ** **** *** * * ***** ** * *
* * * ** * ** ** * * *

** * *** * * *****
if (cnt == n){
*** * **** * ** **** * * **** * ***** * * * 1;
* * *** *** ***** ** * ** ** ** ** * *** *
****** * ** * *** ** *
* * * * *** * *** * ** * ********* * 0;

}

int main()
{
* *** *** ** ***** ** s1[100], s2[100];
*** ** **** ***** i,j;

* **** ** * * * * * *** *** * s1);
* * * *** * * **** ***** * * ** *** s2);
** * **** ** ** ** (prefix(s1, s2)){

* *** * * *** ** * ** * ** ****** * **** is a prefix of %s", s1,s2);
*** * * * * * * ** *** * * * * *
*** ** ** * *** ** * * * **
*** ** *** *** * * *** ** * ***** * *** ** **** * ** * *** *** * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
** * * * * * *** * c;
*** **** * * ** ** a[100],b[100];
**** **** * * * * ** ***** ** * %s",a,b);
* ** * * ***** * ** ** * ** * **** * * * *
* * * * *** * * * *** * *** ** * * ** 0;
* * * * ********** *** * *** * * %d",strlen(a),strlen(b));
*** *** ***** * ** * * * ** * * * *
**** * *** *** * * ** ** *** ** * *** * * ** * ** * * * * *** ******* * * * * *
** * *** * * ** * ** ** *** ** ** * *** ** * * ** ** * **** * * ** * ** ***** * * ** *** *** ** is not a prefix of %s",a,b);
** *** ** ** * * ******* ** **** ** **** * * * *** ** * *** * *** * *** * ***
** *** ** **** ** * * * ** * * * * *** ** * ** * *** *** ** * * *
* * * * ** ** * ** ** * ********* * ** **** **** * * * ** *** * if(c==strlen(a)-1)
*** ** * * * **** *** ***** * * *** ** ** ** ** * ** ** ** ***** *** ** * * ** **** * is a prefix of %s",a,b);
    }
* * * * * *** * *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** ** ** ** ****** *** * * n,count;
**** * ***** * ** *** * * * * * ** ********
* ***** * * * ** * * *** ** %s",a,b);
* * **** ** * * *** * ** ** *

** * * *** * *** * ** * ** * * * * *
* ** ** * ****** *
* **** *** * **** * *** * ** * * * *** *
** * * * * * *** ** **

******** * * ** * * (strcmp(a,c)==0)
* ** * ****** * *
* * *** **** *** *** **** * * ** *** * * * ****** * ** is a prefix of %s",a,b);
** *** *** **** ***
** * * ** *** * ** * ******
* ****** * * *** *
* * ** ** ** * *** * * * * * ** * * * * * * * *** * * * is not a prefix of %s",a,b);
*** ** * *** * * *
** ** * ****** *** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * *** * *** *** ** ***** ** a[100],b[100];
* * ** * * ** * ** **** * ** * ** ** ** *****
    int l1,l2;
* ** * * * *** ** * * ** *
** * * * ** *** * * * * * * *** *
* * * ** *** ** * * * ** ** **
**** * * ** * ****** * * * * * * ******** * * is not a prefix of %s",a,b);

    }
* * * * ** * * * *** if(l1<=l2){
** ** ** ** * * * ****** * * * ** ****** prefix=1;
* * ** * ******* * ** * * ***** i=0;
* * * * ** * ** * ** *** ** *** * * * *** ***
*** *** * *** **** * * ** *** * *** * ** * ** * **** * *** (a[i]!=b[i]){
* * *** ** * * * * * * * ***** **** ** *** *** * *** * * ** * ***** *** ** * *
* ** * *** * * ** * ** * ****** ** ** * ****** * **** * ** ** ** * * * * *** *** ****
** ** ** ** ** * ***** * ** **** * ** *** ** * *** * ** * *** *** **


**** * *** * * * * * ***** ***** * ** ****
* * * * * * **** ** ** * ** * * * *** * **
** * ** **** ** * * ** * * *** ** ** * * * ** *** * * *** **** ** is not a prefix of %s",a,b);
** * * * ** * * * ** ** ** ****** ** **
** * ** ***** ** ** * * * ****** * ** *
*** * ** * * *** *** ** * ** *** * * ***** ** **** * * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** *****
int main(void)
{

* * ** ** *** * * * pre[100];
* * * * * * ** * ***** ** word[100];
* * ** * * * ******* * * * %s",pre,word);
*** * ** * * * ** * * ** ** ***
** *** * * ** **** ** ****** ** *

* * ** * * **** ****** i;
** ** * * **** ***** * **** ****** **** *
* * * * * ******* ** * ***
* * * * ** ****** ** ** *** ** ** ** * ** *
** * * ** ** *** **** *** * * ** * ** ********
** *** *** * * ** ** ** * * ****** * * * * * ***** ** * ** **** * ** is not a prefix of %s",pre,word);
* ** * * *** * *** * * * * * * * ** * ** **** * * * ***** **** **** * 0;
** * * * * ** ** * ***** ** ** * * *

** ** * *** * * ****
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * * ** * ** * ** ***** pre [100],a[100];
** * ** ** * ** * * n ,i;
* * * ****** ***** * * ** ** * *** *
** *** * ** * * * **** ** ** * * * **
*** * *** ** *** * * * ** ***** *
** * * * * ** ** * **
* *** * * ** * **** ** *** * **** (n=0;n<strlen(pre);n++)
* ** * ** * * * * * *** * *** **** ** **
***** * * * ** *** *** * **** *** *** ** * * **** ** (pre[n]==a[n])
* *** * * * *** * * * * * **** * * * * * ** **** *** **** * * * ** * * ** * is a prefix of %s",pre,a);
* ** * ** * **** ** * *** *** ** * * * ** ** * **** *
** * * * * *** *** * * * * * * * *** * * * * * *** * ******* * is not a prefix of %s",pre,a);return 0;
* * * * * *** ** *** ***
* * * * * * * ** ** * *** * * ***** * * ***** * ** ** * * * * *********

**** * * ***** * **** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * * ** *
#include * * ** * *

int main()
{
*** ** ******** * * a[100];

**** ** * * * * ** * b[100];

*** * ** ** * **** * ** * * %s", a, b);

** *** * * ** **** ** len_a = strlen(a);

* * * * ** *** ** i = 0;

* * * * **** ***** flag = 1;

** * *** ***** ** * * ** = 0; i < len_a; i++)
* ** * ** * ** * * * *
** * ** * ** ** *** * * ** * * * * ** != b[i])
* * * ** * *** * ** * * * * ** * *** ** * *
* ** **** * * **** * * * * ** ***** *** ** * ** * * ****** ** * * = 0;
*** * * *** * * ** * ***** * ** * **** ****
* * * * * ** ***

** * ******** * *** * * == 0)
** ** * *** * * **** *
* * ***** ** * * * * * * * * ** * ****** **** ** *** * is not a prefix of %s", a, b);
* *** * *** ** * ** * ***
** * **** *** * **** *** * * *
* ** ** ** ** ** * * ***
** * **** **** * ********* *** *** * * * ** ** * * **** is a prefix of %s", a, b);
* * ***** * * *** ***
* * * ** * *** * ** * * * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** ***** * * ** *
int main()
{
* ** * ** * ** i,n;
** ** *** **** *** * p[100],s[100],a[100]={};
* * * ***** * ** ** ** *** ** *** %s",p,s);
** ** * * ** * **** * * ** *
*** * * * * * * * * * ** *
* * * *** **** *** *** **** ** * * *
** ** * * * * * ** * *** ** *
* * ** **** * *** * ****** ** * * * ** * * *** *** is a prefix of %s",p,s);
** ** * **** *
********** ** ****** *** * ** *
*** * * ** *** ** * * * * ** *** * ** * * is not a prefix of %s",p,s);
** ** * * * *** * * **
* *** ****** **** ** * ** *** ****** ***** * **
*** * * * ** ** ***** ** * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
*** * ** * * * ** * * * * * * * * * * *****
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
*** ** * * * * ** ***** * * ** *** *****
** * * * ** * ** ** * * * ** * ***** *** **** ** ***** * * * * != b[i])
* ** * * * *** * * * ** * * * ** * * * * ** * * ******* * ** * **** **** ** ** * * * **
** ** ** * *** * * * ** ** *** *** *** * ** ** ** * *** * * * * *** * ** *** * * ***** ** ** ******* * ** * * * ** * is not a prefix of %s",a,b);
* * * **** ** ** ** ** ** * * **** ** *** * ** * * *** *** ** **** * * *** * * ** ***** * * *** *** ****** *
* * ** * * ** * ** ********* * * ******* *** **** *** * *** * * * * * **** * ***
** **** ***** ******* ** ** ** ** * * * *** *** * ***** ** * ** *** ** * ** == b[strlen(a)-1])
* ** *** * ** **** * * * ** **** *** ** * ** *** * **** * * * * * * ** * ** * ***
*** ** * * * *** **** **** ** **** * ** * ** * * ** ** ****** * ************ *** * * ** **** ** **** * is a prefix of %s",a,b);
* * ** ** ** * *** * ********* **** * ****** ** ******* ** ***** * *** * *** * ** ** ** ** ** ** ** ** *** *
** ****** ** * * * ** ** * *** * * * ** * * * **** * ** **** ** * * ** *** ***** * *** ** **
**** * * *** ** **** * ** *** **** ** *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* ******* ** *** *** * * * i;
*** * * * * **** * * * * * * (a[0]!=b[0]){
* ** * ** * **** ** ***** * ** * * * ***** * 0;
*** ***** ** **** ***** * *
* * * * *** * ** **** ** * ** ** * ** *
*** * *** * *** * * * ** * * * ** * * ** a[i]==b[i])
* * ****** * * * * * ** ** ** ***** * ** * *
* * * ** * * * ** * * * * ** * *** **** * ** * ** * 1;
* * * * ***** ***** **** *** *** *** *** ** * ***** * *** * *
** ** * * ****** * * ** * ***** **** *** ** *****
** ** ** * ** * ** * *
*** ******* *** * ** ** * 0;

}

int main(){
* *** ** * ***** * ** c[n],d[n],e[n];
** ** * * **** * * ** i;
**** * *** *** ** *** * ** %s",c,d);

****** * * * ** * *******
* *** * * * *** **** * *** **** ** ****** **** **** * ** is a prefix of %s",c,d);

** *** **** * * ** **
* * * ********* * ** ***** ** *** ** **** * * ** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.9
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 16k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 15k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 18.7k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users