1 like 0 dislike
8.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 8.1k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * * * *
#include ****** * ***** *
* ** ** ** *****
*** ** * *** ***

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * **

*** **** ** ** ** ***** * ** *
** ** **** * * == b[i]){
**** ** * * ***** * ***** * *** * * * * ***** **
* ** ****** * ***** *

***** * * *** *
if (cnt == n){
* * * * ** *** **** * * ** **** * ** * * 1;
* ** ** * ** ** *** * ** ** ** * * * * * * *
* * * ** * **** ** *** *** **
* *** ** * * * * ***** *** * * * * * * * * 0;

}

int main()
{
* * * **** s1[100], s2[100];
* * *** * * * *** i,j;

** ** * * * ** * **** * * **** ** s1);
** ** ** * *** ***** ** ***** *** *** s2);
* * *** *** * ** * (prefix(s1, s2)){

* ** ** * * * * * **** ***** *** ** ** * * * is a prefix of %s", s1,s2);
* * ** * * * ** * * * ** * * * * *
* *** * *** **** * * ** ** **
* ** **** **** ** * * ** * ** ** * ** ******* ** *** **** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
***** * * * ****** c;
****** ** **** * * * * a[100],b[100];
** * * * * * ** *** *** ** * * * %s",a,b);
* ** * ***** *** *** * ** *** ** * *
**** ********** ****** **** * ** * * * * * 0;
* ** ******* * * * ** **** **** * %d",strlen(a),strlen(b));
* ***** * * * ** * **** * * * ** * ** ***
**** *** * **** **** * ** *** * ******* * ** * ** * **** * * * ** * **
** ** * ** * * *** **** **** * * ** * * ***** * * ** ** *** * * * ** * **** ******** is not a prefix of %s",a,b);
** ** **** * * **** * * * *** *** * *** * *** ** ** * **** * ** ** * * ***** *
*** * ** **** ** ****** **** *** ** ** ** * ***** *** *** ***
** ** *** * ** *** * ********* ** * ** ** * ** * ** *** * ** ***** if(c==strlen(a)-1)
* ** * * * ** *** ** *** ** ** ** ** * *** * * ** *** ** * * ** ** ** ** * * * ** is a prefix of %s",a,b);
    }
** * ** * ** ** ****** *** *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*** **** * ** * * * n,count;
* **** *** * * * ******* * ******* * ***
* * * ******* * * * *** ** * * %s",a,b);
* ** *** * ** * ** **** *

* **** * *** ** ** * ** * * ** *** * * *
** ** ** * ** *** *
*** * * * * * **** * * * * * * ** ***** * *
** ** * * ** *** * ** *

* *** * *** ** *** ** *** (strcmp(a,c)==0)
* * * * ** * *** ***
* *** **** * ** * ** *** * ** ** * * ** ** *** ** is a prefix of %s",a,b);
* ** * ** ** * * *
* ** **** * * * * * *
**** * ** * ** *** * **
****** ** * * * * * * * * * * **** *** * * *** * is not a prefix of %s",a,b);
* *** * * ** ** * * * *
** * * ****** ** *** * ** * ** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * * ** ****** ******** a[100],b[100];
** *** ** * * ** * * ** * * ** * * *** *** * *
    int l1,l2;
* * **** ***** * * ** ***** **
* * * * * * *** * ** * * * *
* ** * ** ** *** ** * **
* * * ** * * * * * * ** * * * ** ** ** * **** * * * is not a prefix of %s",a,b);

    }
* * **** * ** ** * ***** if(l1<=l2){
**** * * ** * * * ***** * * *** **** ***** ** ***** prefix=1;
* * *** ** * * ******* ** * * * * *** ** i=0;
* * * * ** * ** * * ** **** **** **** *** * ** ** * * *
* ** * * *** * * ** ******* * * * * ** ** **** ** ** * (a[i]!=b[i]){
* *** * *** ** * ****** * * * *** * * ** **** * *** *** ** * ** * **** * ** * ****** **** *
* *** *** **** ***** * ** * **** * * * ** ** * **** ** **** *** * ****** * * * * * ** * **** ** **
***** *** ** * * ** ** ** * ** * * * * ** * * * * ** ** *** * **


* ** **** * ** ** * * ** * ****** * *
**** *** **** * * * * ** * ** * *** * * *** *** * *
*** ** * * * * * *** ** ** * ** ** * * *** * ** ** * * * * ** * ** *** is not a prefix of %s",a,b);
* *** * * **** *** * * * * ***** *** * ***** *
* *** *** **** ***** ** ** * * * *** ** *** *
* ** * * *** * * ** * * * * *** *** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* **** * ** * *
int main(void)
{

* * ** ** ** * pre[100];
***** * ** * * ** * * * * ***** * word[100];
** * * ****** ** ** ** ** %s",pre,word);
* ** ** *** ** ** ***** * *
* * ** * * * **** ** ** *** *

** ** * ** ** * ** * * * i;
**** ** ** * **** *** * *** * * *** ** *
*** * * ** ** *** **
** ** * ** **** * * * ** *** *** ** * * * ** ** *
** * * *** ** **** ** ***** * * ** * * *
****** * ** * ******* * * *** *** * ** *** ** **** * * * *** * is not a prefix of %s",pre,word);
** ** * ** * * ** *** **** ** ** **** * ** ****** * ********* * *** * * 0;
* * ******* * * * * ** *** ** * ** * * * *

*** * * ***** ***** *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * * **** ** *** pre [100],a[100];
* ** * * * ****** ** n ,i;
* ***** *** ** ** **** * * * * **
*** ***** * ***** ** *** ** ** **
**** ** * * * *** * * ** * * ** ***
* ** * * ***** *
*** ** * * * * ** * *** * ** *** ** * * (n=0;n<strlen(pre);n++)
* * *** * *** * * * *** ** *** **** *** * *
* *** * * * * ** *** ** ** * * *** * ** * * * * ** * ** (pre[n]==a[n])
* * *** ** * ** ** * **** * * * * * **** ** * ** *** *** *** ** ** is a prefix of %s",pre,a);
* * *** *** * * * * * * ** * ** ** * * * ** * **** * * * *
***** ** * *** ******** * ** *** ** ** **** * * *** * * *** *** * * *** ** ** ** * *** ** is not a prefix of %s",pre,a);return 0;
** ***** ***** * * * *** ***
*** * ** ****** ** ** * * ** **** * * * * * **** ** * * * **** ** ****

******* * * * ** *** ** *** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * **** * ******* *
#include ******* *** *

int main()
{
*** * ** * * * ******** * a[100];

* * * **** *** ** b[100];

******* * ** **** * * * ****** * *** %s", a, b);

**** * * * ** *** *** * * ** len_a = strlen(a);

** ** *** ** * * * i = 0;

* ** *** ** ** * * ** *** flag = 1;

* ** * * * ** ** * ****** = 0; i < len_a; i++)
* * * *** * ***** ***
*** *** ** * * ** ***** * * ** * * ** ***** * != b[i])
* **** ** * ** * *** ****** ** * * ** ***
*** * *** **** * ** ***** * * * * * * * **** * * = 0;
* ** *** ** *** * * * **** * *** ** *****
** ** * * * * * * * **

* * ****** **** ** * * * == 0)
**** * ** * * ******
*** * ** ***** *** ** *** ** * * *** * * **** *** * ** * is not a prefix of %s", a, b);
** * ** ** * **** ***** *
** **** ** *** ** * *
*** *** *** ** * *
**** * * ** ** * ** * ** *** * * *** * **** ** * ** is a prefix of %s", a, b);
* * ** ** * *
** * * ** * * * ** ** ***** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ***** * ** * **
int main()
{
* * ** ** ** *** *** i,n;
* ** * * *** *** * p[100],s[100],a[100]={};
* ** * * ** * ** * * %s",p,s);
* ** ** * * * * * * ** * *
* * * **** ** **** *** * * ** *
* * * *** * * * *** * **** * * **
* * *** * * ** * *** * **
** ** * ****** * **** * * * ******** *** * * *** is a prefix of %s",p,s);
*** * ** * * * ** ***
*** * * * * *** **
*** * ** * * ******* *** * ** * * * *** **** is not a prefix of %s",p,s);
** * * * ** * *** **
** * ** * * ** *** **** * * * * ** **** ** **
*** * * * ** * * ** ** * ** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
*** * ** ** ** * * * ** * *** ** ***** * *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * * **** ** * *** * ***** ** * ** * * * *
* ** ** *** * *** *** * ** * *** ** * * * * ***** * * *** *** * * != b[i])
***** * * ****** * * * * **** ** ** ** ****** ** * ** * * * * ** *** * ** ** * ** * * * **
* * ** **** * * ***** * * ***** ***** **** ** ** * * * ** * * * ** **** *** **** * * **** ** ** * **** is not a prefix of %s",a,b);
* ** * * ** * **** **** * * * ********* ***** * * * ** * ** * * *** *** * ** **** ** * *
*** ** ** * ** ** * * *** * * * ********** ****** * * * **** * ******** * ** **
**** ** * * *** * * * * * * * *** * ** * * *** * ** *** * * ** * * == b[strlen(a)-1])
**** *** ******* * * * *** *** * * ** * * ** * * * ** ****** **** ** *** ** * * * *** ** * **
*** **** * *** ****** *** * * *** *** *** ** *** ** ** *** * * * * ** * **** **** *** * ** * ** ** ** ** * is a prefix of %s",a,b);
**** *** * * ** ** * * * * * *** *** * * ** * * * * ****** ** * ** ** ** **** * ** * * **
* ** *** * *** * * ** *** ** * * * * ** **** * * ** ** ** * **** * * * * * **** * ****
* *** **** ** **** ***** ** * ** ** * * ** **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* * **** * ***** **** * ***** * ** i;
* * * ** ** * ** ****** * (a[0]!=b[0]){
* * * * * * *** * * *** * * * * * *** *** 0;
* **** * ** * *** ** ** ******
** * * ** ** * ** ***** ** *
*** * ** * * ** * * * ** * ****** *** *** * ****** * * a[i]==b[i])
* * ** ** * * ** ** * * * ****
** * * * *** ** ***** ** ** ** ** ** * *** **** * ** 1;
** *** ***** * * * *** * * * * * * * * * * ** * ***** ** **** * * *
** * * ** * * ** * ** ** ****** * **
* *** ** * * * **** * * * *
* * * ** *** * *** *** **** *** 0;

}

int main(){
* * *** ** * * ** *** * c[n],d[n],e[n];
* * * * *** *** * ** ** i;
** ** ** * * *** ** ******* * %s",c,d);

** **** ** * ** * *********
* * ** * *** * ***** **** **** *** ** ** * ** **** is a prefix of %s",c,d);

*** * * * ***
** ***** * * ** ** *** ** ** * * * ** ** ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.18
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.5k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.3k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.5k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 6.6k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users