1 like 0 dislike
7.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 7.2k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * * * * *
#include * *******
* *** * *** ** *** ***
* ** *** **** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** * *

* * **** ** * ** **** * **
* * * ** * * * ** * == b[i]){
** **** * * * * * * ** ***** * **** *** **
* ** ** * * ** * *

* * ****
if (cnt == n){
* * * * ** * ** **** * * ** * ***** ** *** 1;
** *** * * ** *** **** * * * * ** ***** *
** * * * * ** ** * *** *
* * ** * ** * ** * * * * *** * ** * * 0;

}

int main()
{
* * ** ** * ** s1[100], s2[100];
* ** ***** * ** i,j;

** ***** **** * * * ** s1);
** * * ***** *** *** ** * ** *** s2);
* ** ** * * ** ** (prefix(s1, s2)){

* ***** * *** ** ** *** * * ** **** *** * is a prefix of %s", s1,s2);
* **** ** * *** **** ** * ** * * *
* * ** * ******* ** * * * * **
* * ** ** * * * * **** ** * **** **** * ***** ** ** * ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
**** * * ***** ***** ** ** * * c;
*** * *** ** *** ** * * * * * a[100],b[100];
*** * ** ********** * * *** %s",a,b);
** * * * * ***** ****** * *** * *
* ** * * * * *** * ** * ** *** * ** *** * ** * 0;
* **** **** * * * **** * %d",strlen(a),strlen(b));
* * ** *** ** **** **** ** *** *
* * * * ** * * ** * * *** ** * * **** * ** **** *** ** ** * **
* *** ** * *** **** * * ****** * ** * * * * * ** * *** **** * ** *** **** * *** * is not a prefix of %s",a,b);
** ** *** ** * **** * * * * * *** ***** * ** * * * * * *** *** * * * *** * * * ** * **
** ****** * * ** * ****** * * * **** * *** **** ** * **** **** ** *
****** **** * **** *** ** ** *** ***** *** ** * ** * * * * ***** * *** if(c==strlen(a)-1)
* * ***** * * * ** * * ** * *** ** *** * * ** ** *** ***** * ** **** *** ***** * * **** **** * ** is a prefix of %s",a,b);
    }
*** ************ ** * ***** *** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** * * * * **** *** ** * n,count;
* * **** ****** * * ** * *** * * * * *
** ***** ** * * ** ** %s",a,b);
* * *** *** ** * *** * * **

** ** * ** * *** *** * ** * **** ***
* * * * *** * ***
* * * * **** * ** **** * ** ** ***** * * *** * *
* ** * *** * * * ***

** **** * **** * ***** **** (strcmp(a,c)==0)
** * * * ** ***** *
*** * ***** ** ** * *** * * * * * * * *** ** * * * *** is a prefix of %s",a,b);
* *** * * ** ** **
* * *** *** *** *** *
******** * * * **
**** * ***** ***** *** * * * *** ** * * *** * * * is not a prefix of %s",a,b);
** ** * ** * *** * * * *
** ** ***** *** ** *** **** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * ** * * * ** **** a[100],b[100];
* ** ** *** *** * * *** **** * * * * *
    int l1,l2;
** * ** **** * * * * * ** * *
* * ** ** * * *** * ***
* * *** *** ****** * ** *** **
*** * ** * * * ***** ** ** *** * ** * * *** * ** ****** is not a prefix of %s",a,b);

    }
* * * **** ** ** ** if(l1<=l2){
* **** ** ** * * * *** ** ** * * * * prefix=1;
* * * * * * ** ** * ** ***** * i=0;
* * **** * * * * *** *** * *** *** *** * ***
*** ** * * ** * * * *** ** **** ** **** * ** ** ** * ** * (a[i]!=b[i]){
**** *** *** * **** ** *** ** **** * * *** * ** * *** * * ** * * ** **** *** * * * *
**** ** * ** *** ** *** * ** **** * *** * *** *** **** * * * * *** ** * *** * *** ** *
** ***** *** * * ****** ** *** **** **** *** * * * **** ** ** ** * *


** * *** * ** *** *** ** ***** ******* * * *** *
** ** *** *** * * * * * * ***** **** * ***
* ** * ***** * ** * * ***** ** ** * ** *** ** ** ** *** ** ** * * ** ** * is not a prefix of %s",a,b);
** ** * ** * * * * ** **** * * * ******
* ** * **** * * **** * **** *
* ***** * * * ** ** *** ** *** * * * * ** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * ** * * * **
int main(void)
{

** * * ** * *** * *** * * * pre[100];
* * **** * ** **** * *** word[100];
**** * * * * * *** * ** *** %s",pre,word);
* ** ***** ** * *** * ** * * * * *
* * ****** * * ** ** * *** * ***

* * * * * * * *** ** *** i;
* **** * * **** * *** * * *** ** *
* * * **** * *** * **
* *** ***** * **** ** * * * **** ** ***** ****** ** *
* * * * * * * **** * ** *** * ** * ** * ** ******
*** ** *** * ** *** * *** *** * ** **** ** * ** ** **** * * * * * * * is not a prefix of %s",pre,word);
* ** * * *** **** * * * * * * *** **** * *** * ***** * * * ** * **** * 0;
**** ** **** * *** ****** ** ** * * ** ** ********

* ** ** * * ** ***
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** ** * * *** *** * * ** pre [100],a[100];
** * ** * *** * ********** * n ,i;
* * ***** *** ** * * ** *
* * * * * * * * ** *** ** ******
*** ** * ** **** * * ** * ******** ** **
*** **** * ** * * *
* * *** ** * ** ** ***** ** ** * * * **** *** (n=0;n<strlen(pre);n++)
* ** * * ** * *** * * * ***** * * * *
****** ***** * * * ******** * * * * * ** * ****** * *** * * * ********* (pre[n]==a[n])
** ** * ** * * * * **** *** * *** ** * * ** **** * ** * * * *** is a prefix of %s",pre,a);
* ** * * * ** * * * * **** **** * * * * * * * ** ** *
* ** * ** ** ** * * *** ** ** * *** * * *** ** * **** * * * ** * ** ** is not a prefix of %s",pre,a);return 0;
* * * * ** ** * *
** * * * *** *** ** ** ** * * * * ** * *** * ** **** ** *** *** ****

* * *** * * *** * ** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * * * **
#include ** * ********

int main()
{
* ** *** ** * ******** ** a[100];

* ****** ** ******** ** b[100];

* *** ****** ** ****** ** * *** %s", a, b);

** *** * * ** ** *** * * * len_a = strlen(a);

* ** *** * *** * * i = 0;

* * * *** * ** * **** *** * flag = 1;

* ** * *** * * * ** ** = 0; i < len_a; i++)
** * * ** ** * ** ***
* * * * *** * * ** * ** ** * ** * ** ** ** != b[i])
** * * ** ** * *** * * * **** * * *** *
** *** ** * * * ** * * *** ** * * * ** *** * * ***** = 0;
*** *** **** * ** * *** ** * ** *** * **** *
* * ** * *** * *********

** * * ** * *** * * ** == 0)
* ******** *** * *** *
*** *** *** ** ** ** ** **** * **** *** * ***** * * is not a prefix of %s", a, b);
* ** ** * *** ** ***** *
** **** ** ** *** ** ***
** ** * ***
* ** ****** * * *** * *** *** *** **** ** **** * ** is a prefix of %s", a, b);
* * * ** ** ** ** ***
*** ** ** * * * ** * * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** ** * * *
int main()
{
** * * * **** **** * ** ** i,n;
***** ** ** * * * p[100],s[100],a[100]={};
*** * ** * * ** * ** * *** * %s",p,s);
* * * * *** *** * * *** ****
* ** * *** * ** * **
******** * * * ** * *** ** * * * * * *** *
** *** * * * ** * * * *
*** ** * * *** ** ** * ** **** * * * * * * is a prefix of %s",p,s);
** * ** * * * ****
** * ***** * *
** ***** *** ***** * * *** * ** * * * ** ** ** ** * ** is not a prefix of %s",p,s);
* ** *** *** *** * *
** * * * * ** * ** * ** *** ****** * ***** **
*** *** * *** * * *** ** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** * * *** * ** ** ** * * * *** *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
*** ** * ****** * * ***** * * ** ** ** *
** * *** * * ** ** ***** * ** ** *** * * * ***** **** ** * * *** * * != b[i])
*********** ********** * * * * ** * * * ** * ** * **** * * ** * * ** **
***** *** * * *** ** ** * * ** ** ******* * * * ** ** ** **** ** ** **** ***** * * * * * * ****** *** ***** *** * * is not a prefix of %s",a,b);
*** ** * * *** ** * *** * * ***** ****** * * *** ** * ** * *** * * * ** * *** * * *** * ** * ** * * * *
*** * *** * * * * ****** * ** * * *** * * * * * *** *** * *** * * *** * * ** *
* * **** ** * * * * * *** * ** * * *** * ** * * * * ******** ** * == b[strlen(a)-1])
* ** **** * ** * ** * ** ** **** ** *** *** *** ** * *** ** ** ** * * **** * ** * * *
**** * * * * * **** ** **** * *** ******* ** *** * * * **** *** * * * ** ** **** * * * ** **** *** * ** * ** is a prefix of %s",a,b);
**** ** * * ** * * **** * ** * ** * * ** * ** ** * ** * * ** **** * * ** * ** * *** ** *
* * **** * ** ***** * **** *** **** * * * * *** * *** ** ** **** ** * * * *** ** *** *** ** **
** * * * * *** ***** *** * ** * * ****** * * *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* ******* *** ** ** ** ** ** i;
* ** * * *** *** * * * * * * (a[0]!=b[0]){
** * ** * * **** ** ** * *** *** * ** 0;
*** *** * ** * * * ***** **** * *
* * * *** * * * * * ***** ** * * ***** *** * **
** * ** **** * * * *** * ** * * **** ** * ** a[i]==b[i])
*** ** * * **** * * *** * * * * ***** ** * * **
* *** ** ** * * * * ****** * ** ***** *** * *** ****** ** * * ** ** * 1;
*** * * * * ** ** * * * * ***** ** *** *** ** * * ***** *** **
** ** ** * * * **** * ** * * * ** *
* *** ** ** ******** * * *
** ** * * * **** * **** 0;

}

int main(){
** ** * * * * ** c[n],d[n],e[n];
* ** *** ******** ** * ** i;
* *** *** * * * *** ** ** %s",c,d);

* * * * * * * ** * * ** ** **
* * * * *** **** * * ** * * **** ** ** * * * * * ** is a prefix of %s",c,d);

* ** ** * * * ** * **
** *** * * ** ** * * * ***** ** * *** * * * ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.84
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.5k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 6.5k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.5k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 5.8k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users