1 like 0 dislike
8.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 8.5k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * * ** ***
#include * ** * * * ** ***
* ** * *** * * *
* ** * ** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * * * ****

**** * ** *** * **** *
** * * *** ** * * ** **** *** * == b[i]){
**** * * ** ** ****** * *** * ** **** ** ** *
* * **** * * * *** *

* ** * * ** * ***
if (cnt == n){
* * * *** **** * * * ** *** * *** * * 1;
******* * *** * ** ** * *** *** * * *** **
* *** * ***** ** ** *** *
** * * ** * **** * *** * * *** ** ** ** * ** * 0;

}

int main()
{
* ** * * *** s1[100], s2[100];
** * * * ***** i,j;

* * * * * * ** * * ***** s1);
* * ***** * ** * * *** **** * * s2);
** * * ** ** (prefix(s1, s2)){

**** **** ***** * *** ** * ** ** ** ***** **** * * is a prefix of %s", s1,s2);
* ** * * * *** *** ***** **** *** * *
** * * * ** * ** ** * * * ** *** *****
* ** ** * ** * ** * ** * * ** * * *** ****** * * *** *** ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
****** *** *** *** * * c;
** **** * **** * * * * ** a[100],b[100];
*** ** * ** * ****** *** * * * ** %s",a,b);
** ** * ** **** * * *** * * **
******* * * ****** *** * ** **** ** * **** ** 0;
* * ***** * * * * * * ** *** %d",strlen(a),strlen(b));
* ** * *** ** ** ** ** **** **** * * *****
* * ** **** ** * ** * *** ** *** * ** ** * * *** * *** **
** * ** ** * ** ** * * * ** * * * **** * * * * **** * *** **** * * * ** * ** * **** * *** ** *** is not a prefix of %s",a,b);
* * *** * * ******** * * ***** ** ** ***** * * *** * *** ** * *** ** * ** * ** ** ******* * *
* * * * * *** *** * * * ** ** *** *** *** *** *** *** * * **
* * ***** ****** **** * ***** * * * * * ** * * * ** * if(c==strlen(a)-1)
** *** * *** *** *** ** * * * * * ** * * *** *** * * *** ** ** **** **** * ***** *** ** * * * ** is a prefix of %s",a,b);
    }
* ** * ** ** * * ** *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*** ****** * * * * * ** n,count;
***** * *** * ** **** ** ** ***** ** * **
* ** ** *** * ** ** *** * %s",a,b);
* * * * ** *** ** *

** *** * * ** *** *** ** * * * **
*** * *** ** *** * **
* ** ** *** * * ** * *** ** *** *** * ** *** * * ** **
* ***** * **********

* * ** ** *** ** * * (strcmp(a,c)==0)
* ** * * * * * *
* ** **** * * * * * ** * ** ****** * * ** *** ***** *** ** * * ** is a prefix of %s",a,b);
* *** * *** * * *
* ** * * ** *
** * * * * * ** *
** * * * * * *** ** *** * * ** * * * ** * * is not a prefix of %s",a,b);
* **** * * ** * **
********* ****** * ** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
****** * * * * *** ** * * a[100],b[100];
**** * * * * * ** * * **** * * *** * **
    int l1,l2;
* * * * ***** ** ** * * *** *
** ******* *** * * *
* *** **** * ** * **** ****
** ** ** * **** ** * ** *** ** * **** * ** * is not a prefix of %s",a,b);

    }
*** ** ** * ** * ** * * * *** ** if(l1<=l2){
** *** *** ** * ** ***** *** ***** * ** prefix=1;
*** * * **** ** *** ** ** ** ** *** ** * i=0;
****** **** ** ** ** * * * * *** *** ** ** * *
** ** * * ** ** ******* * ***** * * * ** ** * * ** *** * (a[i]!=b[i]){
* ** * ** ** * ******* ***** *** ** * * * * **** *** ** * *** ** * * ** ** * ** * * ** * *
** * * * * *** **** ****** * * * ** ** * *** ** * * ** * ***** * * * * * * *******
* * ** **** * ** * ** ** * * * ** ** * **** ** **** * ** * ***


* * * * * ****** **** * ** * *** * ******** *
** * **** *** ** ** ****** **** ** * *** **
**** * ** * * * * * ** ** *********** * *** * * * ** *** ** * *** ** is not a prefix of %s",a,b);
**** * ** * * ** **** * * * * **** ** ** ** *
***** ** * * ** ** * *** * *** ** * * * ***** ** ***
* *** ** ** * ***** ** ** ** * ***** * * *** * ****** *** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * ***
int main(void)
{

* ** ** * ** * ** ** * pre[100];
**** ** ** ** *** **** word[100];
* * * ** ** ** * * * * **** %s",pre,word);
* **** ** * ** * * * * * ** **
* ******* * * * ** * * * * * *** * *

* **** ** ** * i;
**** * * *** ****** * ***** ** **** ** * *** * **
**** * * * **** *** *
*** ** * ** * *** * ** ** * *** * * * ***
** * ** * ** ** * * * *** * * * * * *
** * ** ** * * *** * * ** * *** * ****** * **** *** * ** * ***** ** *** is not a prefix of %s",pre,word);
* * ***** * **** * ** * * * * * ** ******* ****** * * * * * * ** * ** 0;
* **** ** *** *** * * *** *** ** ***** **

* *** ** ** * * ****
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** **** ** ** *** * * * * pre [100],a[100];
** ** ** * **** *** * * * * n ,i;
* * **** * * *** * * * ** ***
* **** * * * * ** * * * ** * **
***** **** ** * * *** * * * *** ** *
* * ** * * *
* ***** * * * * ***** * ** * * * * (n=0;n<strlen(pre);n++)
** *** ** * * ** **** * * ** *** * *
* * ** * * ** *** * ** * * ** ** **** ** *** * *** * * ** (pre[n]==a[n])
** * **** * ** ** ** * ********** * * * * ** * ***** ** ** *** *** * * ** is a prefix of %s",pre,a);
** *** * **** ****** * * ** * ** ** *** * * ** ** * ******** * **
* ** ** * ** * *** ****** ***** ** * * ** * ** * * ** ** * * *** * ** ** * * * ** **** is not a prefix of %s",pre,a);return 0;
*** ** ******** *
** *** * * * * * * * *** * *** * * * * ** * * * ********** *** * *

* ** ** ** * * ** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * *** * * ***
#include ** ***** ** **

int main()
{
** ***** * ** * **** * *** * a[100];

* ****** * ** *** * ** * b[100];

* * * ** ** **** ** * ** * ** * %s", a, b);

* *** ***** **** ** ** * * len_a = strlen(a);

* *** *** * ** ** * * ** ** i = 0;

* *** * * ** ** ** **** ** flag = 1;

* * * * ** ******* = 0; i < len_a; i++)
* **** * * ***** *
***** ***** * ***** ****** **** * ** ** *** *** *** != b[i])
* *** * * * * ** * * ** ** ****** * * *** ** *
* * **** ** * * *** * ** * * * ** * ** ** *** ** = 0;
* *** * ***** ***** * *** *** ** ** * ******* ********
** * * ***** ** *

** ** ** * ** ***** * == 0)
** ** * ** * * ** *
****** * ***** * * * * ***** *** **** ****** * *** * * is not a prefix of %s", a, b);
* ** * * ** **** * ***
********* * * ** **** * **** *
* ** * * * * ** * ** * **
* *** ***** * * *** ***** * * ** * * * ** ** is a prefix of %s", a, b);
* *** **** * *** * **
* * **** * * * * * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** *** * *
int main()
{
****** * * **** * ** * i,n;
*** ** ** * * ** ** *** p[100],s[100],a[100]={};
*** * * ***** ** * * * ** *** %s",p,s);
** ** * * *** * ******
*** * * *** * * *** * * * **
***** * ** *** *** ***** *** * * **
* * * * * ** ** * * ** ** ** **
** * **** ***** * * *** * * * * * * * * * ** * ** is a prefix of %s",p,s);
* **** * *** * * **** *
** * *** ******* * * *
** ** * * * *** ** ****** * *** * ** ****** ** * * is not a prefix of %s",p,s);
* ** ***** ** ** * *
** ** ** ** ** * * * *** * * * * * ** ** * *
* * * * * *** * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** * * * ** * * *** **** * * *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * * *** * ** * * ** ****** *** * *** ** * *
* * **** * ****** * ** *** * * * * * * * * **** ** * ** * * != b[i])
* * ***** * **** * ***** * *** ** * * * ** * * * ** ** ** **** ** *** * *** * **** * *
* ** *** *** * * * * * *** **** * * *** **** * ** * * * * ** * ** * ****** *** ** ** * *** * * * *** *** ** is not a prefix of %s",a,b);
**** ** ** ** ********* ** * ***** * ** *** ** ** **** * * ** * ** ** ***** **** * ******** * * ** **
** * * ** * * ** * * * * ** * * * ** *** * **** * * ** * * * *** * ***** * **
*** *** ***** * * ** * ** ** ** **** ****** * ** *** * * * ** ** * == b[strlen(a)-1])
*** * * *** * ** ** * * **** ** * ****** ** * * * ** ** * *** *** ***
*** ** * * * * *** ******** *** * ** **** * *** ********* * **** ** ** *** * *** ** *** * * ** ** **** * * * is a prefix of %s",a,b);
** * * * ******** ** ** *** **** ***** * * * * *** * * * ***** ** ** * * ** * * ** * * * * * * * *** **** **
* **** * * ******* *** * *** ** * * * ** ** * ** * * * ** ** * * ** **** ** * **
** * * **** **** * ***** ** ** *** *** ** **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** ** * *** * ** ** ****** ** ** i;
** ** * *** * * * ** **** (a[0]!=b[0]){
* * * * * * ** **** * * * *** * * * * * 0;
* * ****** * *** * *** *** *
* ** ** ** ** ** * * *** *** * * ** *
* ****** * ****** * * ** **** ** * * * **** * ** *** * a[i]==b[i])
* * ******* * * * ** ** **** * *** ** ** *
* ******** * * *** *** ** *** *** * * * ** * ** ********* * 1;
** ** * **** ** * * * * * **** *** * * ** * ** * * ** ** * * ** ** *
* * ** ** * ****** ** * * ** ** * *** *
* * ** * * ** *** * **** *
***** * * ***** ** * * *** ** * 0;

}

int main(){
* * * *********** ** * * * c[n],d[n],e[n];
* * * * ** * ** **** i;
* * ** ** * **** * ** *** **** * ***** %s",c,d);

* ***** * * *** * *** * * **
* ** * *** * **** * ** *** * * *** ** * * * * *** ** * * ** is a prefix of %s",c,d);

* **** * ***** ** * ** *** *
*** ** ** ** * * *** ** * ** * * * * * ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.76
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.8k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.7k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.9k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 6.9k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users