1 like 0 dislike
17.4k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 17.4k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * * ** * *
#include * ** *
** * * * ** ***
*** * * * * ** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ***** ** *

* *** * *** * * ***** ** * **** * * **
* * * *** ** * **** * * ** == b[i]){
* ** ** * * * ***** ** ***** * * * * *** *
* * * * * * ** * **

* **** **** * ***
if (cnt == n){
*** * * *** ** * * * ******* * *** **** 1;
* **** ***** * ** ** * *** * ***** ******
* *** *** * * *
*** * * * *** * ** * ** ** * ** * ** 0;

}

int main()
{
* *** *** **** s1[100], s2[100];
** ** *** ****** i,j;

*** ** * * ******* * * * s1);
** **** ** **** * ***** * *** * ** *** * s2);
* * * * * * * ** * (prefix(s1, s2)){

* ** ** * ****** * * ** * **** ****** * * * ** is a prefix of %s", s1,s2);
*** **** ** * *** **** * ** * * ******
** *** * * * * ** ** ** * ** * ** ** * *
****** * ** ***** * ** ** *** ** * * * ** ***** * ** **** *** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
** * ** * ** **** * * c;
* * ** ** *** * ** ** a[100],b[100];
* ** * * ***** * ** ** ** %s",a,b);
** * * * ** * * ** * ** * * *** ** *
* **** * * ** *** * ** * * ** * * *** * ** * 0;
* * * **** **** ** * ** ** * ***** %d",strlen(a),strlen(b));
** * ** ** ** * ** ** *** * ** ** *
* * * *** * *** ****** * *** *** ** ** * ** ******* * *** * *** * **
* ** * * * *** * *** ** * ** * * ********* * ** **** * * * * **** ***** * * *** is not a prefix of %s",a,b);
* * * ** * ** * * *** ** ** ** ** * ** * ** * ** * ** ** ** * ** ** * *** * ** ******** ***
** * * ** ** *** ** * *** ** * **** ** * *** ** * * * ***
* ** * * * ** * ****** **** **** *** ** ******** * *** **** ** if(c==strlen(a)-1)
** ** * * * * * ** * ** *** ** ** ** * * * * *** * ******** * ** ***** ** ** * * * *** * is a prefix of %s",a,b);
    }
** * *** * ** ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* ** ** ** * *** * n,count;
** * * * * ** * * * **** ** *
* * * *** ** ** ** ** ********* %s",a,b);
*** * ** **** ***** * *** * * *

** * * * ***** * * * * * *** *** *
** **** ** * * * ** *
*** * * * ** ** * * * * * *** **** * *** ** **
* * * *** *** ****

** * * * * ** ** ** * *** (strcmp(a,c)==0)
*** ** * * ***** * ** * * ***
* **** * ** *** * *** * * ** ** ****** ** * *** ****** * is a prefix of %s",a,b);
** *** ** * ** *****
**** * ****** * * * *
** ** ** * ** * ***
** ***** ** **** * * ***** * * * * * ** ****** **** * ** * is not a prefix of %s",a,b);
* **** ** * *** * * * **
* * ** ***** ** **** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* ** * *** ** **** * * *** a[100],b[100];
**** ** * **** * * ** * ** ** ** ** * *** ***
    int l1,l2;
* * ** *** * ** * *** **
* * ****** * ** * * * ***
** ** * * * *** * * *** ** * *
* * ** * * * * * * * *** ** ** * * * * * is not a prefix of %s",a,b);

    }
****** ** ** * * * * *** if(l1<=l2){
** * *** *** * ** * * ******* * ****** ** ** * * prefix=1;
* * **** * **** * * ** * * * * * ** i=0;
**** * *** ** * ** * ** * *** ** *** ** * *** * * *** ***
* * * * **** *** * ** *** * ** * * ** ***** ** **** ** ** * ** (a[i]!=b[i]){
* * * * * *** ** ** **** ** * * * * ** ** * * ** *** *** * *** **** * ****** * *
* * * * ** * * **** * * **** * ** * *** * * * * * *** * ***** * * *** ** *** *** * *** ** ****
** * * **** * * ** * ** * *** * * * * * * * * *** * * * *


** * ** * ***** ** * ** ***** ** ** ** ** *
* ** * ** * *** ** *** * * ** *** * * * * **
*** * ****** * * ******* ** ** * * ****** * ** * * * * ** *** ** *** * * * is not a prefix of %s",a,b);
** ** ** * * * * * *** ** ** * * **
* * *** ******* * ** * * * ** ***** ** *
** ****** ** * * ** **** ******* * ** * *** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ** ****** * * ** *
int main(void)
{

* * ***** *** * * ** * pre[100];
* * **** * ** * * * * * word[100];
** ** * ** **** ** *** * * ** *** %s",pre,word);
****** * *** ** **** * ****** * *
* * * * * **** ** ** *** * * * * * * *

*** * ** ** i;
** * ** *** * * ** * ** ** * * * *** ****
* * * ** * * ****
**** *** * * * ** * **** ** ** * **** ** * * ** * * ***
* *** ** * **** ** * ****** * * * **** * ** *
* ** ** ** ** * ** ** **** ** * *** ** ** ****** * * ** * ********* is not a prefix of %s",pre,word);
* * * * * ****** * ** **** * ** ** ** * * ** ** ** * 0;
***** ** * *** *** * ****** ***** ** * **

* *** *** *** * * **
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * ** * * ** * ** pre [100],a[100];
** * * * ** * * * n ,i;
* ** ****** * ** * ** * * * *
** *** * * * ** * ** * * * * ** *
***** ** * * * * *** **** * *
*** * *** *** * *
** * * ** * * ** * * *** ********* (n=0;n<strlen(pre);n++)
* ** *** * ***** * * ***** ***** *** * *****
* *** * ***** *** ** * * * * * * *** ** ** ** *** **** **** * (pre[n]==a[n])
* * *** ****** * * * * * * *** *** *** * ** * *** * ** *** *** * *** is a prefix of %s",pre,a);
** ** *** * * ** * * * * * * *** * * *** * *** * *** *
* * *** ** *** * * * ****** * **** * *** *** * * *** * ** ***** * * *** * * ** ***** * * * ** * *** *** is not a prefix of %s",pre,a);return 0;
* * * * * ** ** *
* * ***** * * * * ****** * ** *** *** * ****** ** ** * *** ** ** ***** ** *

* ** * ** **** **** * * * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * ** *
#include *** **** *****

int main()
{
* * ** * ****** * a[100];

** **** ** ** * * ** * b[100];

*** ***** * * **** * ** *** * %s", a, b);

* *** * ** **** ** ** ** len_a = strlen(a);

**** *** *** * * * * **** * i = 0;

** * ** * ** * * * * flag = 1;

***** * * ** * * * * ** * = 0; i < len_a; i++)
** * * * *** **** ****
** * ** * ** ** * * * * * **** * **** * * *** ** ** != b[i])
* * * **** * ** ** ** ******** ***
** * **** * * * ***** ** ** ***** * ******* * * ***** * ** * ** * = 0;
* ** ** ** ** * ** * * * ***
* ** *** * ** ***** *

* * ****** ******* ** ** == 0)
* * ***** * * * **** **** *
******* ** ** * **** ** * * * ** * *** ** *** ***** * * * is not a prefix of %s", a, b);
** * * ****** * ******* *
** * ** * ** ***
* ****** * ** * ****
** ****** **** ** ** * * * ****** ** *** is a prefix of %s", a, b);
* ** * *** * * *** *
* ** * * * ** * ** ****** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * * ** ***
int main()
{
*** * * ** * ** *** * * i,n;
* * * * * * ** ** * * p[100],s[100],a[100]={};
** * ** *** *** * *** * ** * * * %s",p,s);
* ***** ****** *** ** *** ****
* ***** * *** ** ***** *
*** ********* ***** * * ** * ** * * * ***
* * * * * * * * * * * ** ** *
** ***** * ** ** * ****** ** ***** * * * ** * ** ** * * is a prefix of %s",p,s);
*** **** * * *** ** * *
*** * ** ** * * ** * * * *
** * *** * * * * ***** * * * * *** ** * ** ** ** is not a prefix of %s",p,s);
* * ** ** * **
***** ** ** ***** * *** ** *** * * ** ** *
* * *** ***** **** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** * ***** ** ***** * * ** * ** ** * ** *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * ** * * * * * * * ** * * ** * * *** ***
* *** * * * * * ***** ** ** ***** * * * ** * ** * ***** *** * * != b[i])
** * ** ** ** * * ** * ** * * * **** * ** **** ** * * * ** *** **** * * * * * * *
* * *** * * * ********** ** * ****** ** * * * * *** * * *** * ** * * * ***** * * * ***** * ** ** * **** ** *** is not a prefix of %s",a,b);
* *** * ** * * * ** * *** *** * * ** * * **** *** * * * * * ***** ** ** ******* * * **** ** * * ** **** * * *** * *
** ** * ** * * **** ** * ** * ******** *** ** *** * * * **** * * *** ** * * ** **
****** * * ** * *** *** ** * **** * ** * * ** *** ** * ** == b[strlen(a)-1])
**** *** ** * ***** * *** * ***** ** * * * * ** ** * ** * * * ** ** ** *
* ** ***** ** ** * ** * * * * **** * ** ** ** ** * ***** * ** ** ** ** *** ** ** * * ** *** *** * ** * * * *** * ** * is a prefix of %s",a,b);
* *** **** **** * *** ****** ** * * * * * * * ** * * *** ** * * * *** ********** * ** ** * *** ** * * * *** * * **
* ** * ***** * * *** * * * ** * ** * *** * * * ** * ** * ** ** ** * * * * * * ** *
* ** * * ** * * * ***
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* **** *** **** * * * ** i;
* * ** * * ******* * (a[0]!=b[0]){
* * * * ** * ** * *** ** ** * **** 0;
*** * * **** * **** ****
******* ** ***** *** * ** * *** ***
* *** ***** * * * ****** *** ** ** **** a[i]==b[i])
** * ** * ******* * * * *** * * *
* * * **** * * ** ** **** **** * *** *** *** ****** * ** 1;
* * *** ** * **** ** ** **** * ***** ****** ** * *** *** * *
* *** * * * * * * ** * *** * * * * * **
*** *** * ******* ** * ***
* * ***** ** * * * * * * 0;

}

int main(){
** * ** *** * *** * c[n],d[n],e[n];
*** *** ** * * * * * * * i;
* * * **** *** * * *** ** %s",c,d);

* * * * * * * ** *******
** * *** * **** **** *** **** ** * ** * ** * * is a prefix of %s",c,d);

*** * *** * * ** ** * * **
* * * * * * ***** * ** ** * ** ** * * ** ***** ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.9
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 16k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 15k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 18.7k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users