1 like 0 dislike
13k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 13k views

37 Answers

0 like 0 dislike
Hidden content!
#include **** ***** * *
#include ** * * * ** ***
*** ** *** * * **
** ** * * ** * *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * * ** ***

* **** * ** * * *
* *** * * * ** == b[i]){
** * ** **** *** * * * * *** * * **** * * *
* * ******* ** ** ******* ****

* * * * ***
if (cnt == n){
** * ** ** ** **** * * ** * ** * *** ** 1;
* ** ** ** ** * * *** * ** * ** *** *
* * * * * *** *** * **
** ** * ** ********** * *** * * * ** *** * * * *** 0;

}

int main()
{
*** * * ** * * * * s1[100], s2[100];
*** **** ** * * * i,j;

* * ** * ***** ** * * ** * * s1);
* * * *** ** * * * * ****** s2);
** *** ** * * (prefix(s1, s2)){

* * ** ** ** * * **** * * * * **** ** ** is a prefix of %s", s1,s2);
** ******* *** * ***** **** * **
******* * ** * * ** ** * * * * *
* ** *** * * * ** * ** *** * **** * * **** * ** *** * * * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
** ** * * *** * * * * * c;
* * ** * * ** ** a[100],b[100];
*** * ** ** * ** * * * **** %s",a,b);
** ** ** * ** * * **** ** * * * * **
***** * *** ** ** * * ** * * * * *** *** ** **** **** 0;
** ** * ** * * ** ******** * ** ** %d",strlen(a),strlen(b));
* *** ** * ** ** * * *** * * * * ***** ** **
***** *** * * * * * * *** * ****** *** * ** * * ***** ***
* * * * * ** ********* ** *** * * ** ** * * * ****** **** * * ** ** * ** * * ** ** * * * * is not a prefix of %s",a,b);
** **** * * **** ** ***** ** * ***** * * * * *** *** ** * * *** * * * ** * * ** * * ** **
* * ** * * * *** *** ** *** **** * ** * * * * ** * * * **** *** * **
* * *** ** * * * *** * * * * * * ******** * * ** * * * ** * ** * * if(c==strlen(a)-1)
* * * * * ** * ** ** * ***** *** * ** * ** * * * ** *** *** * * * ** * ** * * **** ** * ** ** is a prefix of %s",a,b);
    }
* * * *** * ***** ** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*** * *** ** * * ** **** n,count;
* * ** *** *** * * * *** **** ** * ** * *
***** *** *** ** ***** ** * %s",a,b);
* * * ****** * ******

***** ** ** * * * ** * ** *** * * *
** * * * ** **
* ** *********** * * ****** *** * ***** * * * *
* *** *** * **

**** * ** *** ***** (strcmp(a,c)==0)
* * ** * ** ** **** *
** * **** * * *** * ******* * ** * * ** ** * is a prefix of %s",a,b);
***** ******** * *** *
** *** * * * * * * **
*** * * *** ***** ** *
** * ** *** * * * * * * **** * *** * * * * ** is not a prefix of %s",a,b);
** *** **
***** * * * * ******** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * * * * * * **** a[100],b[100];
**** * * * * * * ** ** ** * ** *
    int l1,l2;
* * * ** ** **** ** * *** *
** * * ** * ** * * *** *
** * * * ***** **** * * **
** ******** * *** *** *** *** ** * * * * ***** ** * ** ** is not a prefix of %s",a,b);

    }
** * ** * * * ** ** if(l1<=l2){
**** * ** * *** ***** * * * * ** * * * ** prefix=1;
* ** * * *** *** ***** * * *** * **** ** * * i=0;
** ** * **** ** ** * * ** * ******** * * **** * * * *** * *
* **** ********* *** *** ** *** * ** ***** * *** ** ** * * * ***** * (a[i]!=b[i]){
* * * * * ***** ** **** ***** *** *** ************* **** ** * ** ** **** ** **** * ** *** * **
* * * ** **** * **** * ** * * *** * * * ***** ** * ** * ** ** * ** ** * ** * * *** **** * *
* *** ** * * ****** * ** * *** * ** **** * ** **


** ** * ** * * * *** *********** **** * * ** ** ***
*** * * *** ** * ** *** * ** ** * * ** ** * * **
* * ***** ** *** ***** *** * ** **** ** * ** *** ** * * ** is not a prefix of %s",a,b);
* *** *** * * ** * * ** *** * * * ** * * * *
** * *** *** * ********** * **** *** * * ** ** ** *
* * * ** *** **** ******* *** * ** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
******** * * * * *
int main(void)
{

* **** * **** ** * ** pre[100];
* **** * * ***** * word[100];
* *** ** ** * *** * * *** *** %s",pre,word);
** ** * * *** * * * * * ******
*** ** * ** *** ** ** * * *** ***

* **** ** ***** *** ** i;
* ***** ** * *** *** ****** **** ******
* * **** * ** *
* * ** ** * ** ** * * * * *** * ** *
**** * * * **** ** *** ***** *** ***** *
****** * *** * * * *** *** * * * * * ***** * * ***** ** ** ****** *** ** is not a prefix of %s",pre,word);
* *** *** ** ** * ** ** ** * ***** ******* * * * * * *** * ** ** ** 0;
** ** * *** ** **** **** **** *** *** * *

* * * *** * *** * ***
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * ***** *** * **** pre [100],a[100];
** ** *** *** ** ** **** * n ,i;
* * * * ** *** ** ** * * ** *
** * **** ** * * * * * * ** * *
* ** *** *** * * ** * **** * * *** **
* * ********** ***** *
** ** ** ** *** ** * *** ** * ***** ** * * * * * (n=0;n<strlen(pre);n++)
** * * ** * ** * *** * * * * *** * ****
** * ** * * * * * ** * * ** ** * ** *** ** * *** * *** * **** (pre[n]==a[n])
**** * ** ** ***** * ** * * * * * ** ** * * **** ** * ** ** *** ** * * is a prefix of %s",pre,a);
***** * *** * ** * **** ** * * * *** * * *** **** ** * * *
* * **** * * * ** * * * * ***** * *** * **** * **** * *** * ** *** * **** * ** * *** ** *** * is not a prefix of %s",pre,a);return 0;
* ***** ** ** ** ** * * **
*** *** *** ** ** * ***** * ** ** ** ** * *** *** * ** * * * ****

**** *** ** ** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * ** *** ** *
#include ***** * ** * *

int main()
{
* ** ** * * **** * ****** * a[100];

* ** * * * *** b[100];

* * **** ** ** * * * %s", a, b);

* * * *** * * * * len_a = strlen(a);

* * *** * **** * i = 0;

* *** *** *** * ** flag = 1;

****** *** * * ** * = 0; i < len_a; i++)
* **** * ** *** * **** *
** * * *** * ** * ****** * *** * ******* * != b[i])
** * ** * ** ** ** * * ** * * * * **** *** *
* * ** * **** ** ** *** * * * *** ** ** **** ** * * ** * *** ******* = 0;
* * * * * * ** * ********* * * *** *
** ****** * *** ** * *

** * ** * * ****** * **** * * == 0)
**** * ****
** ***** * ** * ****** ** * ** * ** *** * * * * * ** * * * ** is not a prefix of %s", a, b);
**** * * ** * * * * *
** * *** *
* * * * *** **** *
* ** ** * * ** * ***** ** * *** * ******* ***** is a prefix of %s", a, b);
* * ** * *** ****
* **** ** *** * * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** * * * * *
int main()
{
* * * * * * * * i,n;
** ** * * *** ** p[100],s[100],a[100]={};
**** * *** ** *** ** * * * * %s",p,s);
********** ** * *** * ** *
* ** * * *** ** * * ***
* * ** * ****** * * ** *** * **
* **** **** ** * ** ** * * **** *
** *** * ** * * **** *** ** * ****** ** *** * * ** ** is a prefix of %s",p,s);
* ** * ** * * * ***
* * **** ***** **** **
*** * * * * ** **** * ** ** * * * ** * **** is not a prefix of %s",p,s);
***** * * *** * ** * ****
** * * ** ** * * **** *** *** * *** *
* ** ** * ***** ****** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** *** * * ** * ** * ** **** * * *** * * *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
**** * * * ** ** * *** ** * * ** ** ** ****** *
** *** * ** * *** * ** * * * * *** * ** **** * * * ** * * != b[i])
** * * * * ** * * * ** * * *** *** * ** * *** *** * *** ** * ******* * * * *** * ** *
**** * * * ** * * * *** * *** * ** ***** * * ***** * *** **** *** * * ** * * ** * * * * * ** * ** * * **** * **** ** ** ** is not a prefix of %s",a,b);
* ** *** **** *** * ** **** ** * **** *** ** ***** *** ** * ****** ** * ******* * * * *** ** ***** * ******** *
* ** ** * * * * * * * * * * * * * ** ****** * *** * ****** * ** ** ** ** ** * * ****
* * ** * * ** * * * * ** * * ** ** ** *** ** ** ** * ** ***** *** ** ** == b[strlen(a)-1])
** * ** ******* ** *** * * * * * ** ** ** **** * *** * ** ** ******* ** * ** * **
** ** * *** *** ** * *** * * *** ********** *** * ** ** * *** ***** * * *** * ** *** * * * * **** ** * ** ** ** * is a prefix of %s",a,b);
** ** * * * ** ** * ** *** * * ** * *** * ** ** * *** *** * * * ** **** ** ** *** * ******* ** ** *** **
* * ** * * **** *** * * ** ** ** * ** **** **** ** * *** * ** * **
* * * * ** ** **** * *** * * ***** *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* * *** ** * *** *** i;
* * ** * * * ** * * * (a[0]!=b[0]){
** *** ** ** ***** * * ** ** **** * * * ****** * * ** 0;
* **** * * ** * ** **** *
*** * * *** ** * * *** **** * *
* * **** * **** * ** * * **** ** * *** * * a[i]==b[i])
**** ** **** * * * *** * * * * * ***
* *** *** ** * ***** ** ** *** ** **** * ** * ** ***** ** ** 1;
* * ** * ** * * * ** * * * *** * **** ****** * ** ** * * *
** **** ** * * *** * ****** * * * **** **
* ** * ** *** * **
* ** * *** * * * * **** 0;

}

int main(){
* *** ** ** * * * * * ***** * c[n],d[n],e[n];
*** * ** ** **** **** * ** i;
* ** * * ***** ** ** ** * ***** * %s",c,d);

* * **** * ** ****** * * **
** ** *** * **** ** * * * * ****** ** * **** *** * **** ** is a prefix of %s",c,d);

** ** * * *** * ** * *** *
* * ***** *** * * * * ** ** * ** * ** ** * * *** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.239
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.6k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.5k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.4k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.3k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users