1 like 0 dislike
16.4k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 16.4k views

37 Answers

0 like 0 dislike
Hidden content!
#include * ** * *
#include * *** * *
* ** ** * *
** * * * * **** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** * * ***

* * * ** * ** * ** ** **
** * ** *** ****** * ** * * * == b[i]){
**** * * * ********* * * * ** * * * * ***** *
* **** * ** *** * *** *

* * * *** ** *
if (cnt == n){
* ****** ** * ** * *** * *** * **** *** * * **** * 1;
**** * * ******* * ** *** * * * **** ** *
* ****** ** * *** ** ****
** ** * * * ** * * *** * * * * ** * ***** 0;

}

int main()
{
** * ** ** ** *** s1[100], s2[100];
* ** * ** ***** **** i,j;

* * * * **** * ** * * * * s1);
** ********* * * **** ** ** *** ** ** s2);
* ** **** *** ** (prefix(s1, s2)){

* * ***** * * ** * * ** *** *** * * ** * ** * * is a prefix of %s", s1,s2);
* * *** ***** * * * * * ** * **** **** **
* * * *** *** ** * ** ** * * * **
***** *** * * * *** * *** **** * ******* * * *** * ** * ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * * * ** * *** ** c;
*** ** ** * *** * ** *** a[100],b[100];
*** *** ******* *** *** ** ** * %s",a,b);
* * * *** * * * * ** * * ** ** *
** * * * * ** **** * * ** *** *** * * ** ** 0;
** * *** ** *** *** * * * *** *** * * %d",strlen(a),strlen(b));
**** ** * ** *** * *** * ** * ** * *
** ****** * ** *** ***** ** ** * * ** * ** * *** ** ** ******* *** * * **** *
***** *** * **** * * **** ** *** * ******* *** * * * * ** ** * ** * ******* ** * * is not a prefix of %s",a,b);
* * ** * * ** ** ****** ****** * *** *** ** ****** * ** * ** **** *** * ** * *
* * * * * * ** ** * **** ** *** *** * ** **** ** *
*** * *** * *** * * * * ** **** * * * *** * *** ** *** * * * ****** if(c==strlen(a)-1)
*** ** ******** * ** * * * ********** * * * * * ** ** * * * * * ** ** ** * ******* * * * * **** is a prefix of %s",a,b);
    }
*** * * **** * * * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* **** * * **** * * n,count;
* * ** *** *** * ** ** ** ****
** * ** *** *** * * ******* * * %s",a,b);
* * * *** ******* * ** * **

*** ** *** ** * ** * * ** ***** ** * ** **
** ** *** * ******* **
* ** *** * * ** *** * * * ***** ** ** * * **** *
** * ** ** *** ** * *****

** * * * * * * ** * (strcmp(a,c)==0)
** ** * * **** ** * *
* *** * * * * * * **** ** * * * ****** ******** ** is a prefix of %s",a,b);
* **** ** * * ** **
** ** ** *** ** * ****** **
**** ******** * * * * ***
**** * ** * * ** *** *** ******* * * * ** *** * is not a prefix of %s",a,b);
* **** * *** * * *
* * * * ***** * * * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** *** * * *** ** * * ** a[100],b[100];
* ** **** * ** * **** ** * * * * * *
    int l1,l2;
* **** * * * * ** ** *
* * * * * * * * ** * ****
* ** * * * * * ** ** *** **
* * ** *** * *** ** * * ***** ** * *** * ** **** * is not a prefix of %s",a,b);

    }
* **** * ** ** * * ** * if(l1<=l2){
*** * * * **** ** * * * *** ** * * ** * * * ** * prefix=1;
** **** * ** * ** * * *** ** i=0;
**** * ** ** ** ***** ****** * * * * * ** ** * * * * *
** *** ** * ** ** ******* * ** * ** * ** ** **** * * * * * *** (a[i]!=b[i]){
* ** ** **** * * ** ***** * * *** ** * * * * ** ****** **** * * *** * * * * * ***
* *** * ** * * * * ** * **** * * * * * ** *** * ** * * * * * ** * *** *** **** * *
* * ** ** *** * *** * * ***** * * ** * ***** ** * ** * ****** ** ***


* * *** * * * ** * * * * **** *** * * **** ** ***
* * * ** ****** *** * * ** * *** ** * ** * * ** * ** *
* * *** * * ** * ****** * ** **** * ****** **** * * * *** * **** * ** is not a prefix of %s",a,b);
* ** ** *** ** * * * *** * **** *
* ** ** * * * * * ****** * ** * * *** *
* * ** ******* * ** * * * ** * * ** ** *** ** * ** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * *** * * * *
int main(void)
{

* **** ** ** * * * * * pre[100];
** * *** *** ** word[100];
* * * * * * ** * * ** ****** ** %s",pre,word);
* ***** * ****** ** ** * * ** *
* * ** * * ************ **** ** ***

** * * * * * ** i;
**** *** * **** * *** * ** *** * *
** ** **** **** ***** ** *
* ** **** **** * ** *** *** * ** * ** * *** * *** ***
* ** * *** * *** * *** * * ** * *
** * *** ** ** ** ** * *** ** * *** * ** ** ***** ** ** * ** is not a prefix of %s",pre,word);
* * ** *** ***** *** *** * **** ** ****** ** * ** * ****** ** * ** * 0;
** * *** *** * * ** * * * ** ** * * * *

***** ** * ** * ** * **
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** * ** * *** * pre [100],a[100];
* * * ******* * ***** n ,i;
********* **** * *** * ** *** *
* ** * ** ****** * *** ***** *
* *** * ** * * * ***** * **
*** **** * * ** * * **
* * * *** * * *** * ** *** * ** (n=0;n<strlen(pre);n++)
* *** * * ****** * * * * * * *** *** * * ***
* ** *** * * ** * * * * * * **** * *** *** * * * ** **** * (pre[n]==a[n])
* ** * * ** * ******* * ** ** * ** * * **** *** * ***** * **** ** ** is a prefix of %s",pre,a);
* * *** ** ** * **** ***** * * *** *** **** * * **
** ** * ** * *** ***** ** ** **** * * * ** * * * * ****** **** **** * ** ** * * * **** ***** * is not a prefix of %s",pre,a);return 0;
**** ** * * * * *
*** ** **** ***** *** ** *** * * * * *** * ** * ** * ** * ***

** * ** ******* *** ***** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * *******
#include ** * * ** * **

int main()
{
* *** * * *** ** ** * ** a[100];

* * ** ****** * ***** * b[100];

** * ******** ** ** * ***** * ** *** * %s", a, b);

** * * ** ** ***** ** * * len_a = strlen(a);

**** * * * *** ** ** i = 0;

*** * * * * *** ** ** *** flag = 1;

** * *** * * * *** ** = 0; i < len_a; i++)
* ** ** * * * * *
*** * ** ******* *** ** ******* * ** * * != b[i])
***** ** * * * *** ** ** * * * * *** *** *
* * ** ** *** *** * * ** * ** ** * * * * * * * ** ** *** = 0;
* ***** * * * * ** * **** **** **** ***
** ** * *** ** * ***

** * ** ** ** *** * *** == 0)
***** * * *** ****** *
* * * * * ** **** * * * * ** ** * * ** * ** * * is not a prefix of %s", a, b);
**** ** * * *** * * ** * *
*** ** **** * * * ** * *** *
* **** ** * ***** *
* ** ** * ** *** **** * ** ***** ** * * * * * ** * is a prefix of %s", a, b);
* *** * ** * ** *** **
* ** ** * *** * * *** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * * * * ** ***
int main()
{
* *** * ** **** * * ****** i,n;
* * * *** ** *** ** p[100],s[100],a[100]={};
* * *** * **** * * * * *** %s",p,s);
* * ** **** ***** *** ** ** *
* *** ** * *** * **** * * * * *
** * * **** ***** *** ** * **** ** ** ** ** * *
* * ******** * * ** * * **** **
** * * * * *** * * * * ******* * * *** * * ** * *** ** ** is a prefix of %s",p,s);
** ** * *****
**** * ** * ** * * *** *
*** * * * ** * * ** * * ********* * *** ***** is not a prefix of %s",p,s);
******* ** ** * *
*** *** * * * ***** * ******** * * ** **
* * ** ** * * * * * * * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
*** ***** * *** * * * * ** * * * ****
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * * * ***** * * * *** ** *** * * * *******
*** ** * * ***** * * * * *** ** * * ***** **** *** * * * * ** * **** != b[i])
* * **** ** * **** * * ******** ** * ** * ** * * * * ** * ** ** * * **** **
*** ***** * ** ** ** **** *********** *** * **** * * * * *** ** *** * ** *** * * **** ** * ** ** ** * ** * ** is not a prefix of %s",a,b);
*** * ** ** * * * * ** ** *** **** ** * ** ***** **** * * * * *** * * *** * * * ****** * ** ** ** * * * * * * ** * **
* * * **** * * ** * *********** * *** ** * ** ** *** * * ** ** * *** *** * ** *
* ** ** ** * ** ***** ** * * * ** * * **** ** * *** * *** ** ** * ***** == b[strlen(a)-1])
* * * * * * *** * * * * *** * * * ** ** **** ** * * *** * ** * **** *** *** *
**** * * *** *** * *** * * * ** ** * ** * ** * * * * * ** ** ** * * ** ** * * * *** * * * * * ** ** * *** ** * * is a prefix of %s",a,b);
** *** * ** ******* *** * * * ** ***** ** *** * * * * ** ****** ** *** * ** * ** * **** **** ** * *** *** ** * ** **
* * ***** ***** * ** ** ** ** * * * *** ** **** ** * * * * *** ** * * * ** *
**** ** * * * *** * ** * **** * **** * * **** *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** ** ** *** * * * ******* * i;
*** ** * *** ******** ** * * ** (a[0]!=b[0]){
* * * * *** ********* * * ****** * ***** * 0;
* ** ** * **** * ** ****** * * *
*** * ** ** *** ***** * ** *** *** ***
** * ** * * ****** *** ** *** ** **** * a[i]==b[i])
* ** * * * * * ***** * ****** * * * ** * ** *
*** * **** ** ** ** * * ******** *** * **** * * * * **** * ****** 1;
** *** ** *** ** * * * *** * *** *** * * *** **** *** * ** **
*** * * * ** ** * *** * ** ** ** * * **
* ****** * * ** * * * ** *
** *** ** ** * * * * * ** ****** **** 0;

}

int main(){
** *** *** * **** ** * ** c[n],d[n],e[n];
*** * ** ** * **** * * i;
** ** ** *** * ** * * * * **** * * %s",c,d);

** ** * ** * ** ***** **
* ****** ** ** * **** * * * * * * * ** * ** ** ** is a prefix of %s",c,d);

* ** **** ** * * * ** * **
***** *** * * ** *** ** ** ***** * * ** * * **** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.10
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 15k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 14.2k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 17.6k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.2k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users