1 like 0 dislike
17.4k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 17.4k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * * * ** ***
#include * *** ** ** *
** ** * * *** *
* * ****** ***

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= **** *

******* ** * ** ** ***** ***
**** * ***** * * * *** == b[i]){
*** * * ****** * **** *** ** ** * ** * ** * * *
* *** * * * * * ** *

** * * * * * *
if (cnt == n){
** *** ** * ** *** * ** ** * * ** * * 1;
***** *** * * * * **** * *** * * ***** *
* ** **** ** **** ***** **
** * * * *** * ** * * *** * * **** ** ** * ****** 0;

}

int main()
{
** ***** ** ** s1[100], s2[100];
*** ** ******* ** *** i,j;

* ** * ** * *** ** * * ***** s1);
* **** **** * * *** **** * * * ** s2);
** **** * ** * (prefix(s1, s2)){

* * ** * **** * * **** * * * ** ** * is a prefix of %s", s1,s2);
* * * ** * * * ** * ****** *
** * * **** ** ** * *** * * * * *** * * **** *
** ** * *** * * * ** *** * *** * * * ** ** ** ***** **** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* **** **** **** * c;
** *** *** *** ** * * a[100],b[100];
* * *** ***** ** ** ** ** * ***** %s",a,b);
* * ** * **** *** ** * *** * * **** *
** * ** **** * *** ** * ** * **** * * ** 0;
* ** ** **** *** ******* * %d",strlen(a),strlen(b));
** * * * ** * * * *** ***** ** * * *
* * ** * * * ** ************ ** *** **** * ****** ** * *
*** * * *** * ** **** ****** ** ****** ** ** *** * * * ** * ** * ** * * * * *** * ** is not a prefix of %s",a,b);
********* * *** ** ** ** * * * **** *** * ****** *** *** ** * * * ** * * * * * ** ** ** * **
******** * * * **** **** ** ******* ** *** * ** * ** * * * ** *** **
* * * ** ***** ***** ** *** * * ** ** ** *** ** * **** **** *** *** if(c==strlen(a)-1)
* * **** ** * * * ** * * * *** * *** * * * ****** * * ****** ****** ** ******* * * * * is a prefix of %s",a,b);
    }
* *** ** ** *** **** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
***** **** ***** * * * * n,count;
****** ***** * *** * **** * * * *****
* * * ** *** * * * ** * *** ** %s",a,b);
** ** * ***** * * * * * * * *

* * ****** **** ** ** * ** *** * ****
** * ** * ** ***
*** *** ** *** * * ** * **** * * *** ******* * * * *
* **** * * * * ***** * *

* * ** * * * ** ***** (strcmp(a,c)==0)
***** * ** **** * * ** *
* ** * * * * ** ** ** * * * * ** ******* * ** *** * * * is a prefix of %s",a,b);
**** * * *** ** *** **
** ** * * ** ** ***** *
* * * * ** * ** * * *
*** * ** * *** *** * ** **** * * ***** **** * is not a prefix of %s",a,b);
** * * * ** ***
* * * * * * * *** * * * * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* *** ** * ** ****** a[100],b[100];
* * *** * *** ** ******* ** * * *
    int l1,l2;
*** * * ** *** * * * * ** * **
* * **** *** * *** * ** * * *
* ** * ***** * * * ** ** *** *****
** * * * * *** * * * * * ** * *** **** ** *** **** * ** is not a prefix of %s",a,b);

    }
* ** * ** ** * ** ** ** * if(l1<=l2){
* ** ** * ****** * * **** **** ** * * prefix=1;
** * * * * * ** *** * * * * *** * * ** i=0;
* * ** ** ** * *** * ** * * ** * * *****
* ** * * * ** *** ** * * * * * * ***** * ** ** * (a[i]!=b[i]){
* * ** *** ** * ** * * ** * **** ** ** * ** ** * * * ** ****** * * *** **** ***** * * *
** * *** * * * *** * * ***** ** *** *** * ** * *** *** * *** **** * * ** ** * * ** * ** * * *** *** ***
* * ** * ** * * * * * ** **** * ** ** *** ** **


* * * * *** * ** * * * ** ****** * * * *
** * *** * ** ** *** * * **** * ** * * ***** * **
** ** ******* * ** *** ** ** * *** ** *** * * ***** ** * ** * * ** * is not a prefix of %s",a,b);
* ** * ** *** ****** * *** ** *
** *** * **** * * *** * ** * *** * **** ***
* * * * ** * * * ** ** ** * *** *** *** * * * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
****** * * ** **
int main(void)
{

* *** ** *** **** ** * * * * pre[100];
* ***** ** **** ** **** word[100];
** * ***** * *** * * * ** ** * ** %s",pre,word);
****** * ***** ** ** ** ** * **
*** ** *** ** * * * * *** ** ***

* ** ** * ** ***** ***** i;
**** * * * ** ***** ** *** * ** * *** * *
* **** ** * ** *******
* * ** ** * ** * * *** ** ** * * * * ** ***
* *** * ** * *** *** * * **** * *
**** * * * ** * * * * * * ** * * *** ** * ** * *** * * * ******** is not a prefix of %s",pre,word);
* ***** ** * ** * ** ** * * * * * * * * * *** * ***** **** * * * 0;
** ******** * ** * **** * * * * * **** * **

*** ** ***** ***** * ***
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * ** **** ** ****** ** * pre [100],a[100];
* * *** ** * * * ** ** n ,i;
* * * **** ** * * * ** **
** * ** ** * * *** * *** * ** *
** * ** *** *** **** *** ****** * **** ***
** * *** * * * * ** **
*** ****** ***** ** *** * ***** *** **** *** ** * (n=0;n<strlen(pre);n++)
*** *** * * ***** ** ** * * ** * * * * ***
*** * * * ** ** *** * *** ************ * * ** ** * * **** * (pre[n]==a[n])
* *** * * *** * * ** * ** ** * * **** ** * * * ***** * * * * ** * is a prefix of %s",pre,a);
* ** * * ***** ** * ** * * ** *** * ** ** *** * ** * * *
* * ** * ** **** * **** ** ** ** * * * ****** * **** * ***** ** **** ** * ***** *** * * * is not a prefix of %s",pre,a);return 0;
** * * * *** ** *
*** * * ** * ** * * * * * * * * * *** * * * ** ****** *

** * * ** *** ** *** * * ** * * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include *** ** * *
#include ** * * ** * * *

int main()
{
* * * **** *** * a[100];

* ** * ** ** b[100];

* **** ** * * ** ******* %s", a, b);

*** *** * * * ** * * ** len_a = strlen(a);

** * * ***** ** ** i = 0;

** ** ** * * ** * * * flag = 1;

** ** * * * * * ** * *** = 0; i < len_a; i++)
** * * *** * ** * * **
** *** * * **** * *** *** ** *** ** * * != b[i])
** **** * * * * ** * * * * **** **** **
** ** ********* * * ***** **** ** * ***** ****** *** * * * *** * ** = 0;
* * * * * ** * * **** ** *** * * ** * **
* ****** *** ** * ** * *

* * * * **** * == 0)
* * * ** * ** * * **
** * **** ***** * *** * * * * * * ** * * * ** ** is not a prefix of %s", a, b);
* * * ******* **** *
**** ********* ** * *
** * * ** *** * **
* *** * ** * ** * * * ** **** * * *** * * ** ** * is a prefix of %s", a, b);
*** **** ****** * *
* * ** * ***** * * * * * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** *** **
int main()
{
*** * ** **** ** *** i,n;
* **** **** * ** * * *** p[100],s[100],a[100]={};
* * * ** * * **** * * * %s",p,s);
** * * *** * * ** * **
**** * * **** ***** *** *
*** **** * *** * * ** ** **** * * **** *
** ****** * * * * * **** *** * **
**** * * * * ***** ** *** * * * *** * *** ** *** ** * * is a prefix of %s",p,s);
*** ****** *
* * * **** * * *** *
** *** * * * **** * * * * * ** * * * ** ** * * * *** is not a prefix of %s",p,s);
* * * * * * *** * *
** ***** * *** ** * * * * ** * *
** * **** *** *** ** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* * * ***** * *** ** *** ** * ***** * * *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
** * * * * ** ** ** ** * * *** ** * *
******** *** **** *** ** * *** * * * **** *** ** * * * * * * * * != b[i])
** ** * ** * * ** * * **** * ** * * ** ** *** ***** * ** ** * * * * ** * * * *** * * * ** * **
**** * *** * **** ** * *** * * **** ******* ** * *** ***** * * * * ** * * ** * *** * * *** *** * * * * is not a prefix of %s",a,b);
* ** * ** * * *** * * * * * ** **** * *** *** * *** ** * * *** * *** ***** * ** * * * * *
*** ** * * * * ** **** * * ** * * * *** ** * ** * * * ** * *** * * **** * * ***
*** ** ** * ** * * **** ** * ** ** * ** ** **** *** ** * == b[strlen(a)-1])
*** *** *** * * * ** * **** * * * * *** * *** ** ***** **** ** *** * * * * * ** ** * *
* * ** * * ** * ***** *** * * ** ** **** ** *** ** * * *** ** * * **** *** * * ** ***** * * ** * * * * * * *** is a prefix of %s",a,b);
** ** ***** *** **** * ** * * ****** * *** * *** ** * * *** * * * ** *** ** ** * * * ** * * * * * ** *** *
** * ***** ***** *** ** *** * *** * ** * * **** * ** * * * ** * * * *** ** *** * ***
* ** *** ** ***** ** * *** * *** *********
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* ** * * *** ** * ** **** i;
* ** ** *** * * * * **** *** * (a[0]!=b[0]){
* ** * *** * * * ** ****** ****** **** * ** * *** 0;
* ** * * * *** ** * ***
**** *** ** *** ***** ** * **** ** * *
** ** ** **** * ** * * * * * * ** *** *** ** *** * * a[i]==b[i])
*** * * * * * * * ** ** * * * *
* * * ** **** * * * * * * * *** ** ******* * * ** * * ***** ** *** 1;
** * * * * ** * ** ** **** ** * ***** *** * * * *** * * * ** *
**** ** ** ** ** * *** * * * ** * *** **
* ** ***** ** * * * ** *** *
* * * ** ** * * **** ***** 0;

}

int main(){
* * ** * ** ** * c[n],d[n],e[n];
* * * ** **** ***** ** i;
** **** ** * * * * * ** * %s",c,d);

**** ** ** * ** **** * ****
*** ** * * * **** ** *** ** * * * *** **** * * is a prefix of %s",c,d);

* ** ** **** ** * *** *
**** *** ****** ** * ** * ***** * *** ** * ** * ** ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.9
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 16k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 15k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 18.7k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users