Final Exam 2 (20%)

1 like 0 dislike
9.7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 9.7k views

37 Answers

0 like 0 dislike 
Hidden content!
#include   * *** * *  *
#include  *  * *  * * *  *
* *    * *   *   *  ** 
**   *    * *    

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ******  ****

  *     ***  ****** * * ** ***  ** ** * 
  ***** * **   ** ** ** *  *** == b[i]){
  * *   ** *  *  *   ** ** *** * * * **** ** *  *** 
* *    * *  ****  ***  *    *  

* * * ***  * * *    **    **
if (cnt == n){
  *****        **  ** * *  *** ******* * *****   **  **** 1;
 ** ** **      *  * ** * * *  **   ** **  *    *   
   * **** * ****        **  * *
***** **  * ** **  ****   *  * ** ***** *  ***  *  *  * 0;

}

int main()
{
   ***    **   * ******* s1[100], s2[100];
* *** ** *   *   **    *  i,j;

* ***  ******* **** *  **  *** * * *   s1);
* ** *****   * *  *     *  * * ***** *    ** s2);
 ** * ** *        ** * (prefix(s1, s2)){

 ******  ****  * ***   * *       ** * *******    * * ***** is a prefix of %s", s1,s2);
 *  * ******     *   ***  * *   ****    *** * *
* * *** *  * * ***  *****  * ***  ** ** ** * *** **
**   * * ***** *   **   **   ****  * * ** **     *  *   * **  **  ** *   * * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
  ** * *    **   *  **** * c;
** ****    ** ***  **      *  ** a[100],b[100];
**     **   * * *  ** **  ****** ** * %s",a,b);
    ** ***  * **** * *  *** * *** *****  *  
    **            *  **** * **  ** ***      ***  ***   *    ***** 0;
 *  **  ****    * *    *  ** * *  *** * * * %d",strlen(a),strlen(b));
     * * ***** *     **    *** ******* **   ** * 
*      *    **    *    **   ***  ***** ** * *** **  * **  **   **     ***     ** **** *  ***
   *  ** **     **** *   *    ***  * * ****** * ** ** *   *** ** * **  *** **   * * *  *  *   *    * ****** *   * *  * is not a prefix of %s",a,b);
    ** ** ****   *  ****  ** **  * **   *   ***** * * *  **  ***** * **     ** **        *   ***   * ****** ***     **
** * *  ** * **** *  * ********  * * ****  *   ***   ****   * **** ** ***  *   *
  ***  * ** * ***  ** ***     *****   *** *  *  *  ********** **  *  ****  **** ***  if(c==strlen(a)-1)
 ** **   * *   *    ** ** *  ***  * * **** *  ****    *  *      ***  **  * *   ****  *** *** * * *   *   *** ** * ******** is a prefix of %s",a,b);
    }
**   * ** *      *** **    **  *  0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*    *       ** * ***   *** * ***** n,count;
**  ***   ***      ******    *    *****   ** ****
*** *  ** *  * *  **      *     * ***   %s",a,b);
***   *    ** *  *** * ** *   *  * ***

 * * **** *** ** ********  **     * ****    **** * **
  * *** *   *** *  ***  **  
  * *** *   ***** * **   * ** ***      * *      ** ** * ****
** *** * *   *  *     * *****

   ****  **   ******** * *** * (strcmp(a,c)==0)
           * **  * * **  * 
*  * **** *  * * **  * * ** ** * * **   ***    *    *  ***    * * * *  is a prefix of %s",a,b);
***** * * ****    ****** *****  
 *** **** *******  * **  *  * *
 ** *    *** * * * * ****  ***
*** *******  * *   * *  *  ** * ****  *      ** * ** *    **   ***  is not a prefix of %s",a,b);
 *    ****  ** *  * ** ******
  ***  ***   * *** *  *** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * * **  ****   *  *     **  a[100],b[100];
  ****  *****        * * **  * ***   * *   *   *** ** *  
    int l1,l2;
* ***    ***    * * *  ** **
  * *  *  * *     *  *   *    *   
   **  ** **** *  ***     * *** * * ** *
  ****  **  * **  *  *  **  * * *  *** ****    *****    * ** ******   * is not a prefix of %s",a,b);

    }
*   ** ** *   ** ** *** ******  if(l1<=l2){
****         * **    * **** ***  ** * * * ***   *  *   **   prefix=1;
   * **  * **  *  **  *   *** * **     *     ******  * *  *  *** i=0;
 ** * *  **  ** ***** *  **  **** *  *  *** *****    *   ** ** ***  ** 
*****  ***  ***   *  ***  ******   *  * * **   * * *  ***  *  *   *** **       *  * (a[i]!=b[i]){
 ** *   * *  *** ***  * **  *  *****       ****   * * ******* * ** *  * *** *  *  **    *   * *  *****   *  **  ** ****  * **** 
 **    * *** ** **** *  ** ** *** **   ** ** *** * * ** ** * ** *********** **     *** *   *  *   ** * ***  *   ** 
**  **** ** *****  * ** *   *  ******   *  **** ** * *   **    ***  **    * 


* ** * *  ***     *  ** *** * **  *** **    *   ** **   *  *
 * *** * *** * *  ** **** * ***  **** **  * * ******* * *  *  * 
 *** *  **  *  **  *  *** * **  **     **   * ** ** * * *** *****  *** *  * * ****  * *** ** is not a prefix of %s",a,b);
*    * **    *  *    ** *  ****  * *****  **      *** * **
  **    ** *  * * ** ***  ***  *******    *  * ** *
* ***  * ****** ***** * ****   ****** ****   **    *     *****  * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
  **  ***  *****    
int main(void)
{

***  **** *    * ***** * pre[100];
  ** **   ***    *    * *** word[100];
**  **    **     ***  ***        *  *** **  %s",pre,word);
 * ***  ** ** **** **    *  ** * *** ** **
  **  * * * *    * *   ** ***   ** 

***  * ***** *****   ******* i;
* ***  * **  * *   *       ** *******  **** *
  ***   **    * *** * * *
*** * **   *** ** **  ** * **  *** *  *** ** ****    ** ***   *
* ***  **  *  **   * ****  ** *   * ***   **  ***  *  **
 *  ** * ** * *** * * * ***   **       ***  ***  * * * *  *  *     *****   * *** *     ***  * is not a prefix of %s",pre,word);
 *** * *    * * *  * **  **  ** * **    *  ***** * ** *  *   *** ** *   ** **   *  *  * * 0;
  * * * ***    ***** ** ****    ** *  ** *   ***   **

*   ****** **  * ** *** *** *  ** *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
  *  ****  * ** ** * * **** pre [100],a[100];
*    ** ****** * ** * **      n ,i;
* *****  *** ****   * * **** * **   ** *    *
*  ***  *  * * *   *   *   * *** *** *  ** 
** ****  *** ***** *** *     **  * * ****  **  **
**  *   ** ** **  *  * **  **
** ***    * *** **** * *  *  *   * *** * *       *  (n=0;n<strlen(pre);n++)
    ***** * ** * ***  ** *** *  ** *** **       *   *****  
   ***      * * *  *  * ***  *    *   ** * ** *****  *  *    **  *    * ** **  *** (pre[n]==a[n])
    **** *    * **** * **** *** ** **  **     ***   * ** ******      *     *    * * *****     **  is a prefix of %s",pre,a);
  ** *   *  * **** * ** **    * * *    ** *  * * * **  ** ***  *  *     * * *  ** *   **
****  ***** *****  **   ** * *** *  **     *  * * * * **  **  * ** **      * ** **** ****** **   *   *  is not a prefix of %s",pre,a);return 0;
* **    *** *** *   ** 
 **     *  ***  *  ****   * *        **** * * *********** *   * * *** **  **  

*  * **  *** **     ***  *  ***  * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *    ** ***  ** **
#include *  *  *** **  **

int main()
{
 * **  * **       ***** ** **  a[100];

 *  *  *    *   * *    *  ***  b[100];

** ********   *   ***        ** ** *  %s", a, b);

**      *   ** *   *** *   len_a = strlen(a);

**  *   ***  *****  * ** *  *  i = 0;

 * ** *** * ** * *  ** * flag = 1;

  **** * *  *   ***** *   **** ** = 0; i < len_a; i++)
 *** ***** *   * *****  * *
 *  **   *      * *    ****    **   * *    **  ** ***** ** * != b[i])
 ** **   **   * *   ** ***   * **   ** * **  *  ** *
***   *** ***  *   * **  ***   ******  ** *    * *** *** *   ** * *** = 0;
 **    **       ** ** ** ***** * **   **  *   *  *  *   *  ** 
 * **     * **   * *****     

**** *  *  *  *   *     *    == 0)
** *     *    *  **  *  *****  
  * **   **    * ** **  ****  *  **  ****   *        *   is not a prefix of %s", a, b);
  ** **  *  ** ***** * * * 
* *  *  **** *   ****  ** *
  *     **    * *    *    ** *
   ******* *  *  *** ***      *** **      **  * * **   **  **   * is a prefix of %s", a, b);
 **   ****       ** * ****  
*  *** ******  *   * *   **  ***  0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
*       **  ** **  
int main()
{
 ** * ***       * ***   *  i,n;
    **  ** ** * ***** *** p[100],s[100],a[100]={};
****  ***  ** *** ****  **  *   %s",p,s);
***  *****    * * * ** ** *     
 *  * ** * ***   **   * ****  * ***** **
** *** ***  *** ***       *** ***  **  ** * * **  
        ***** *  ** *   *** ***  * ** *   **
 *****  *     **   *     * ***   *  *  *** * * **  **   * *   **  * * * is a prefix of %s",p,s);
*   ***  *** ******  *  * 
  *  *  *  ** **  ***  ****
* *   *  **** ***   *  **** **   *  *  * *** * ********  * *     is not a prefix of %s",p,s);
 *  ** ****  * *        ** ** 
    ** **** *  ** *    *   ********    **    * * ** *
* * * *** **   * *  **   **     0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
**      ** *** ****** * ***    ** * ** ***  ** **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
 ** *  *  *  * **  ** **** ** ***  ****** *  *  **        
 *     *  ***  *   ***  * *     **  * * * ** * **  * **  *   **   *  * *   * ***    *** * != b[i])
  *  ****** ** ******* ***********   ***********    * ******  **  * ** * ** * *  *  * * * *****  ***  *** *** ***
  *   **  ******* *       ***  *  ******   ***   ** ** *  *    * * *  ***** **** * ** ***  ** ** **  ** **  **   *   **    *  ***  *** *** * * ****       *** is not a prefix of %s",a,b);
    **  ** **      *****   ***  * *** ***  ** ****  * *  *   *  * ***  *** ** *  * * ***  * **        *    *     ***   ***  ***  * *  ****  **  * *****
 * **     *   ***** *      *   *   ******  * *** *    ***** *** * *   ****   *  ** **   ***  * * * *
 *     * *      * *     ***** * *   ***** *   ** *   * **    ** **    ****  * *** * == b[strlen(a)-1])
**   * *   ** *   ****   **    *******    ** *    **** *  **   **  * **  * **      * *  * **** ** *** *    *
 *  *    *** ***  *   *   *****  *****    * **** * **    * *   **  * **** **** ****   ** **  *    *   ***** * * **  **  ** *  ****  *  ** * *  is a prefix of %s",a,b);
  *    ** *  ** **** **** **      * **** *** *  **  * ** ***    **   ** ** ****  * * * * *   * ****** **  *** ** *    *  **   * * *** *   * 
 ****  * *   ***** * * ***** ** * ***** ** ** *  *   ****** *** ***  * *  * * *  ** ***    *       * **  ***  *
  * ** * * * **  **** * ** ***** * ***  ********** * *  **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* **    **   **  **   **  ***   *   i;
  *  *    *  * **     *     * ****   (a[0]!=b[0]){
*  *** *** ** **    ** **** ***       *  * ** * * ** * 0;
*     * ** *******  **** **    * *
 *  *  ** *       ******  *   ******   * ******
*     * *  ***** *  *  * *       ** **    * * **     * *      a[i]==b[i])
** *  ***   *  *      ***   *  ** ***** *     ****   * 
**** *****     **     ** *  ***    **  **** *      * ** ** ***  *   *** *    * * * 1;
 * **      * **    *   *  * *  *   * **  **  ****** ** **   *   ****     * * *  ** ***  ** ***  *
    **    * ********  * *  *  *** ********        *  *  ** ** 
* **   * * *    **   *     *   *
*   *  **     **     * *   * * *  0;

}

int main(){
  *  ******     * ****   *  * c[n],d[n],e[n];
   *** *** **  **   **  **  i;
***** ****   ** * ****  * *   **    ****** %s",c,d);

  ** *** * * * *  *  ** ** *    **
*** * * ** ** **   ** *  **  * ***    ******* *****   ****  * is a prefix of %s",c,d);

  **    *** *****   ***  **
**   *   ******** *** *      ***    ** **  * * * *   *  * ** * * **** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.144
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 10k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 8.7k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 10.1k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.9k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 1.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users