1 like 0 dislike
8.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 8.1k views

37 Answers

0 like 0 dislike
Hidden content!
#include * **** * *
#include ***** * ****
*** *** * * *
* * ** **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * * * ***

*** ** * ** ** * ** ****** *
*** *** ** * * *** * **** == b[i]){
** **** ** ** * * * **** * * ** ** ** * *
***** ****** * ** * *

*** ** *****
if (cnt == n){
* ** * * *** ** *** ******** * *** ** ****** ** ***** 1;
** * *** ** * * *** ** *** ** * **** * ** * ** *
****** **** * * ** *
****** *** * ** ** * ***** ** * * * ** * * ** 0;

}

int main()
{
* * * *** **** * s1[100], s2[100];
** ** ** *** ** ** i,j;

*** *** ** ** ***** * ** *** * ** *** * s1);
**** * * ** * **** *** * * ** * s2);
* ** * * * (prefix(s1, s2)){

** *** * *** * ** ** ** * *** **** ** * * * *** is a prefix of %s", s1,s2);
* *** ** ** * ** ** ** * * * * * **
*** ***** ** ** * * ** ******** ***
***** *** * ** * **** * *** * * * * **** * ** ** ** * *** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
** *** * ****** *** ** * c;
* ** * * * * * * ********* * * ** a[100],b[100];
* * **** **** * * * ** * *** %s",a,b);
* * * *** * * * ****** ** * *** * * * ***** *
* * * * ** * * ** **** ** ** *** ** ** * * ** 0;
* * ********* * * * ***** %d",strlen(a),strlen(b));
* *** * * * * * * * * **** * *** ***
* * * ** ** **** * *** ** * * * * * **** * * **** * *** * * ***
* ** **** * * ** *** *** * *** ******* **** *** ** * *** **** * *** * * * ** **** is not a prefix of %s",a,b);
* * * * * **** **** * * *** *** **** * **** * * ** ** * * ***** *** ***** * ** * * **** * *
** ** ********* *** * **** * ** * *** * * ** **** * * * *** * *
** ** * ******* * ** * *** **** * * * * * *** *** * ** ** * if(c==strlen(a)-1)
** **** * * ** *** ** * ** * * * ** *** ***** * *** ** ******* ** * ** **** *** * * ***** is a prefix of %s",a,b);
    }
*** * ** * * *** * *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*** ** * ** ****** ** * * n,count;
* ** **** * * * ** ** **** ** ** *
***** ******* * * * ** * * %s",a,b);
* * * * * ** ** ** ** *

** * ** * **** ***** * * * ** * * * ** * ** **
* * * *** * * ** *
** ** ** **** * * * * ** * * * ****** ** * * * ***
**** ** ** *** ***

***** ** *** * (strcmp(a,c)==0)
*** * *** * ** **
* * ***** * ***** ** ** * * * * * ** * ** * *** * is a prefix of %s",a,b);
**** ** ** * * *
* * ** * * ***** *** * *
* * * * **** **** * ***
*** * * *** ** ****** *** * **** *** * * * * ** **** is not a prefix of %s",a,b);
* *** ** ***** ** *
* * * ***** * * ** ** * * * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
*** * * ** * * * * *** * a[100],b[100];
** *** * * *** * ** * *
    int l1,l2;
* *** * ** *** * *** **** * ** **
* **** * * ** ***** ** **** **
* * ** *** * * * * ** ** ****
* * * * * ****** * * **** * * *** * * ** ** * is not a prefix of %s",a,b);

    }
* * *** * * **** ** **** **** if(l1<=l2){
* ** * ****** * ** * * ** ** ** prefix=1;
*** * * ** * ***** * * *** * *** * * ** * i=0;
** ** ** * *** * ******* * * * * ** ** * * * * *
* ** ** * ** ** **** * ** * * * ** * ** * ** * ** ** * (a[i]!=b[i]){
* * **** * *** * * * ** * ** * * * * ***** ** **** * *** * * * *** ** * ******* ** *
*** * *** * ** ** * * ******* * ** * * ** ** * ** * * * * * * ** * * ** * ****
* ** * *** *** ** * ******* ***** *** ****** *** * * *


* ** ** * * * * ** * ** *** *** * *
** **** * * * *** ** *** * ** * **** * *
* * * * ** ***** ** * * ** **** * * ** * ********* *** * **** ** ** * * ** *** * * * ** * is not a prefix of %s",a,b);
******** * * * * * * *** *** * *
** * *** ** **** * * * * * **** * ** * * **
* ** * * * * ** *** * **** * ** *** * * * * * * *** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** ***** * **
int main(void)
{

** ** *** ** * * pre[100];
* * * ** * * * * ***** * word[100];
**** **** * ** ** * ** * %s",pre,word);
** * *** * * * * * ****** ** *
** ** ** *** * * * ** **** *****

** ** ** ** * ***** * * i;
** **** **** ** * * * * * * **** * *
** ** **** * * * * ** ** *
** ** ** *** * * * ** **** * ** * * *** ***
** ** ** **** ** * * ******* *** *** ***
* ** * * * * * ***** ** **** * * * * * **** **** * ** * ** * * * ** * * ** * *** * is not a prefix of %s",pre,word);
** *** ******* ** *** * * * ***** ** * * * * * * *** * ** * *** * 0;
** ** ** * **** ******* * * *** ** * * *****

**** * * ** * ** * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* ***** ** *** **** ** pre [100],a[100];
** * * ** * ****** ** n ,i;
* * * *** ** *** **** * *
* * * * * *** ** *** *********
* * * *** ****** **** * ** **** * * *** *
*** * * *** * * *
* ** ** **** ** * **** *** **** ** * * *** (n=0;n<strlen(pre);n++)
*** *** * * * **** * * * ** **** * **
* * ** * * *** * * *** * * * * * * ** * * * *** * (pre[n]==a[n])
** *** ** * ** * ** **** *** * *** * * * * * * **** *** * * * * * * * * is a prefix of %s",pre,a);
* * * * ** * * ** ** *** ** ** * * **** * ** ***** * ** * ** * ****
* *** * ** ** * * *** ** *** ** ** ***** ** * *** * ** ** * ** ** **** * ** *** ** is not a prefix of %s",pre,a);return 0;
** * * * *** ** * * ** **
** *** ** * ** * * * *** *** * * *** ***** * ** **** ** * *

** ** ** * * * ****** **** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include *** * **
#include * ** * * * *

int main()
{
* ** * * *** *** * ** a[100];

******* ** * * ******* *** b[100];

** ** ** *** ******* ** * **** ** %s", a, b);

**** ** ** *** ******** **** len_a = strlen(a);

* ** ***** * ****** * ** i = 0;

** * * * ** ** * flag = 1;

** ** ** * * *** * ** * ** = 0; i < len_a; i++)
* * ** ****** *
** * * ** * **** ********* * * ******* * ** ** != b[i])
* ** * ** ** * * ** *** *** * * ** *** *
* * * *** *** *** * * *** * *** * ** * *** **** *** * * * ** ** * = 0;
** * * * * * ******** * * *** * *
*** ** *** * * * * * **

* *** ** * * * *** == 0)
*** ** **** * *
*** * ****** * * *** *** **** * **** ** * ** **** * * is not a prefix of %s", a, b);
* **** * *** ** ** *** * * *
** * ** * *** * **
* ***** *** ***** ** * **
*** *** ** ***** * * *** * *** * * ** ** * is a prefix of %s", a, b);
** ** *** ** * *
* * * **** * **** **** ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * *** * ** * *
int main()
{
**** ** * ******** i,n;
** * * *** *** *** p[100],s[100],a[100]={};
* *** * ** **** ****** * * ** %s",p,s);
**** * * ** **** * *** * * ** * *
**** * * ** *** * ** ** ** * * **
* * * ** * *** * ** * * *** *** **
* ** * ** ****** *** *** ** *
* * * * ** ** ** ** * * * ** * *** *** * * *** ***** is a prefix of %s",p,s);
** ********* ** ***** * *
* ***** * * ** *** **** *
* * * * * *** * * *** ** * ****** ** * * * ** is not a prefix of %s",p,s);
* ** * * ** ** ***** *
* * * * * *** * ** **** **** ** ** * ** **** * *
* * ** * * * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** * * * * ** * * *** * * ** **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* **** * * * ** ** * *** * ** **** *
*** ** * **** * ***** ******* * *** * ** * * * * ** ** * * * * ** ** ** ** != b[i])
** ** * * * * ** ** ** ** ** * * **** * ** * **** * * *** * * *** *** ** ****** * * * **
**** ** * ****** ** * ** ** *** ** * *** ******* * ** *** ** ** * * ** * * * *** * ** ** *** ** * * ** ******* * ***** is not a prefix of %s",a,b);
* ** * ** *** * **** * ** * ***** * *** *** * * *** ** ** ** ** * * ** * * * *** * * *** ** * * *** * ***
**** ** ** * * * ** * * ** * * * * * * ** * ** * ** ****** ** ** ** *
* * * *** * ** *** *** ** * ** * ** ** ***** * * * * ** *** ** == b[strlen(a)-1])
** ** ***** *** **** ***** * **** ****** * * **** * *** * ***** ** * *** *
** ***** * * * * *** *** ** * * *** *** ** ** ** * ** ** ** * ***** * *** * * ** ***** * * * is a prefix of %s",a,b);
* * ** ** * * ** ** * * ** ** ****** ** * ** **** ** ***** *** *** ** * * *** * * *** ** **** *
****** * * **** ** * ***** ****** * * ** * * *** * *** ******* * ** * **** *** ** * **
* * ** * *** * * ***** *** * * * * * * * ***
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
*** ** *** ** ** ***** i;
** * * * ** * ** * ** (a[0]!=b[0]){
* ***** * ** * ** ** ** ** ** ******** * * * * * * * *** 0;
* ** *** ** **** ** * * *
* *** ***** * **** * ** * ** *** * *
* ******* * * *** * ** * ***** * *** * * * * *** * a[i]==b[i])
*** * ** ** **** *** ** ** ** * * * *
*** * * ** ****** * ***** *** ** * * * ** **** 1;
* * ** * **** *** *** ** ** * * ** ** * ***** * * *
* * * * **** ** * ******* * ** ** ** **
* ** * ** ** * * * ** * * *** * ** *
* ** *** **** * * * 0;

}

int main(){
** ** *** * * * *** * c[n],d[n],e[n];
**** * ** ** * ** **** i;
* * ***** ** * * * ** *** %s",c,d);

******* * * ** * *** * **** *
* * ** * * * * ** **** * * ****** ** * * * * is a prefix of %s",c,d);

** *** ** * * ** * *
*** * * * ** ** * * ***** ** ***** * * * * * * ** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.169
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.5k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.3k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.4k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 6.5k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users