Final Exam 2 (20%)

1 like 0 dislike
7.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 7.2k views

37 Answers

0 like 0 dislike 
Hidden content!
#include * * * *** **   
#include   ** ** *  **
* *** *** *  ** *
**  ***  **   *   * **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n=     ** ***  * **

 * ***    ****     ** ***  *     *  *  **
***  *   ** **  **      ***    * == b[i]){
****   * **   **  **  *   * *  * *  ****  *  *    *** **** 
 * ***  * **   *  ***  ** ** **

*  ** *** *   **** * ** **  
if (cnt == n){
 * **    * *  * **** ****  * ****  * **  *   *    ** *  1;
 *  *    * **** *   *  ***     **  * ***  ***   ***  
  *   *  *** ** * **** **   *    
  * ***     **** ***   * **  **  * * *  *  ** ***   ** 0;

}

int main()
{
****  ***  **    **    * s1[100], s2[100];
**     **** ** * *** *  i,j;

** ******  **  * *  **  **  ****  **  s1);
  * ** * * * ** * ****  *      *  * * s2);
 ** *  **  **   *** (prefix(s1, s2)){

* *    ****   **  **        **  **  *****  **** *  is a prefix of %s", s1,s2);
***    * **   ***   **     * ***** **** ** ****  *  
** *  *   *  ** ****** *  *   *  ****   * *  * *  * **  
*  ******  *     * ** *  **  *** * **    **** *  ** *** ***** **  * *   **   is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
*  ** ***  * ****     * **   * c;
* *** ****  * ***            **   a[100],b[100];
 * * **  *     * **  ** * **** * * * %s",a,b);
***     **   *****  ** *  * ** *   *      ** * *
*  *** *   * * **** * ***** *   * **   * ********* * ** ** 0;
** * *   * **   ** * **  * **   **   * %d",strlen(a),strlen(b));
* *  * ******  ****   ** * ** * ** ** ** **
 * ***   *** *  *** ***** ****  ****  * * *   * *** ** **  ************   * ****  **  ***    *
*  ** ** ** ***  * *** *  * *** * *   * ** *** * * ** ****  *  * **  * *** * ***   ******* ** **  * *** *** **** is not a prefix of %s",a,b);
 * *** *  ** * ****    ****** * *  *   *      *   *  *    ** ***  * ** **  * * *  ** ***      ***    * *  **      ** 
 *   ** *     *   ** ** * *  * **   ** **    **** **     * * ** * *     * **** *
**      *   * *   * ***   **    * *  ** ** *** * ** *  * * **  ** **    * **   * ** * ** if(c==strlen(a)-1)
*****  *  *** ** **** *** **** *** *  **  **    ****  * **  *  **    * * *  * * * **  *   * **   * ** **  ***  * * *  * *  **  *   is a prefix of %s",a,b);
    }
   * * ***  ****** **       **  * *  0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*   ****    * *** *   ***   *  ** n,count;
  * *    **      * * ******    *****  ** **      
       *    *   *   * ** *  * *  ** ** %s",a,b);
 ***  * ***   **** *    **   * **** *  

***   *   *  * *** * **    *  *** * * * *    *
  **   *  *** *  **  ****** 
 * **** ***    ****   *   * * ** ** ***   ***  *   ***  *   *   
 *  *** **  * ** * *  * * *   ** 

  **** *  *** *   ** *****   (strcmp(a,c)==0)
* ** ***** **  *** ***  *
           ** * *   *  **  ******* *  *  ** * *     ***  **  is a prefix of %s",a,b);
   ******** ** ***  * **  
 ** *     **  * **  **
 * *** * ** * * * * *  *
* ** * *   * *    ** * ****  ***** *     **  *****  *  ****** **  * ** is not a prefix of %s",a,b);
  ** ** *  * * ** **** * **
*    ** *  ** ** *   **** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* ******* **  *  *** * * * a[100],b[100];
* * *  ***   * * **  *   ****  *  ** **  * ***** 
    int l1,l2;
*   *   *** * * *  * *   *    *   ***
******  *   * ****   * **** * *   
  **  *** *  *  * **    ** **  **      **    ****
*  *** * *    * ****   *  *   * * *  **   ****  **   ** * * ** ** * *** is not a prefix of %s",a,b);

    }
 *  ** *   * ********  ****   if(l1<=l2){
*   * * **   * *** * *  * * ** ** *** *    * ****** * *  **     prefix=1;
* *** *  * *   **  ** ** *** ** ** ***  *    **    * i=0;
  ** * *    **  * *     *     * *** ***   *** ** *** *** *    *  * *  * ** * **
********       *   **  ***   * * * **  *** ******     *    *** *** *  *** * ** *   * * (a[i]!=b[i]){
*   *    *    **      *  **  *   *    *************      **  * ***  *   * **  ** *  * * **  ** ** * ** ***   **  *   ***
  *     ** * ****   * * *  * ******   *   **  * *** * *   **** *  * *  *     ** *******   ** **** *** **    * * *
**** *  *** ** * * ** *    *   *      * *   * ******** ***  *   **    **  *  


 *  **   *  *********  * **     ** * **  * ***   ** * *
*** ** * *  * **     ******   **  *  ** ** * * *  *  *  * *  **** ***
 * *** * *  **   *** ** * *****  ** *****    **  *  * * *   *  ***     * * * ***** ***   * **    is not a prefix of %s",a,b);
   *****  ***   *  *  * **** *   * *    * *         * 
* * *  ***     *    **  **   ** **   * *  *** * *
** ** *    **  **** ** * *  ***  **   **      ***  *** **    **   is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
    *      ****** * *
int main(void)
{

    ***   *  ******  *  *   ** pre[100];
    **** ** * ** * **  * ** * word[100];
* **  *     * ****  * *      * *******  %s",pre,word);
***** * **  *    * * *  *** *  * * ******** 
 ** *    *   *****  * ***  *  **  ** *** **

* *  *** ** *     * **  *  i;
**  *   *  ***     * *   ** **** * * ******  * **  
  ** *  ** ****  ** * * 
*      * * * *  ******** ** * **** **  *  *  * *  *   ** 
**   * ** ***      * ** * ***    * **  ** ** **  * * 
   **    *  * *** **  * **  ** ** * * **     ***  ****     *** ** **  * *** **   ** ****  * *  * ***   is not a prefix of %s",pre,word);
* * * * ** * **   * ** * * **  * *** *** *  ***   ***  *   * * *** ***   ** ** *** 0;
* **    **** * **** ***   ** ***   *   ** *   **

*  * **** ***        **  
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
*  ** *  **  ** **  ***   *** * pre [100],a[100];
*  ** *   ***    **  **   **    * n ,i;
   ** ****  ** ****    ** *    **  * ***     
  *     * *     * *  ***   * **  *
*     * *   ** **     * *  *     *   ***  ** * * **
   ** *** * *      *       
 *** **    ** ***    *      ***** **************  ***  (n=0;n<strlen(pre);n++)
* *** *   **** *    * * ***   *** *     *  ***  *****  
   * ***  ** * **   * **** ***  ** **  ** * * **     *    * * * *  ******   *** (pre[n]==a[n])
* *      *   *  **    *  *** ****   *  **  *  *   ***   *   **  *  *         **    ***  ** **** **** is a prefix of %s",pre,a);
* * **  ** **      *  ** * * **** *  *** ****** *******   * ** *   ***** *  ***  * 
    **  **  ***** * * * ** *     *      ***    **   * ****     *   ** *      *** ****   ***** * ****       * * *   * * *  **** * is not a prefix of %s",pre,a);return 0;
*** ** * ** *** *  ** **** * 
 **       * * *  *  **    *  * **   ******  *  *** *  **   ** * * ** ****  ****    

  * ** ** * * ****** *** * *  0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include       * * **   * 
#include  ***** ** * ** 

int main()
{
  *  *  **   * *******   * ** ** a[100];

***   **** * *  ** *****     b[100];

*****    ********   * ******   *  * * ** %s", a, b);

  * ** * *     *  * *  ***  len_a = strlen(a);

  * **  ** ** ** ** * ** *** ** i = 0;

 ******   **   *    *       **  flag = 1;

* *   *** **    **   * *   * *  = 0; i < len_a; i++)
**  ***   *  **  * * * *   *** ***
 ***** ** ** *  *  ** ***   *  *** **   *****  ***   != b[i])
* * * * **   *   * * ****     ** **** *  *   * ***     *
**  *   ** ****** ** *  *  *     *** *** ** ** *** ** *  * ****   *    *  **     *** ** = 0;
*  * *  * ** *  **    * ***  * *****   **   * **
*   *  **** * **  *** * ***

*** ***** * *  *    *** * * *** == 0)
 *    ** *** ********       ** 
*****   * * *   ** ***   *   ***     *** ****    * * **  ***    * *  is not a prefix of %s", a, b);
****    *  **  *  * 
** *   ********* ***  ** * **** 
 **  *  * *   * *     ***  **
*     *  ** * **  **** *   ** *** ** *   * **** * *    ****   * *   is a prefix of %s", a, b);
     ** ** **** * * *  *    * 
* *** * * ** ** **    *  * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
 ** ***  *  *****    * *
int main()
{
  ***** ** *   ** *** * *  * i,n;
   ***  * ** * ***** ** ***   p[100],s[100],a[100]={};
**     *** *  **  * * * * * *** **  %s",p,s);
*  **   *  * * *  *      **     * *  
 ** **     * *  ****   **     * * ** * 
***** **  **  *     *  ******* * ** *** ***  ** 
* * * *     * * ***      * ***  *** **  *
 ** ** ** **    ***  *   *   *       * *** *** *****  ** *** ** ***  is a prefix of %s",p,s);
*** *** *  ** **   ** * *
     ***   ** **** *       ** **
**** *** ****  ** **  *  *  *** *  ******  * * *  *******   * * * * is not a prefix of %s",p,s);
 *    ** * ****    * *  * 
**  * ** * ** ** ** *     * * * ***          *** ***  *** * *
***  ***  **       * ** ***  * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
***     *   *  ** **  * ** *    * *   *   **  
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
*  *** *  *    *  ****   **  *** ** *  * * **** *     * 
 * ** **      * **   * *     * **  *  *    ***   **  *  * *   ** *  ** * **** *** ***** **  != b[i])
* ********** * * **   * ***  ****    *  ** * * ***** **  * *     * ***      *     ***     * * *** ***  * ****  *  ** **  
 ****  **   ***  *  ** ***** *  *** ** **  ****   ***  *  ******** ***** *****   ** * * ** *  **  *** * ** * ***  *  **     ** **** ***** ** is not a prefix of %s",a,b);
       *      *** *  * ***    *    *   ** ***   ** **  * ** ** ***  * ** *   ******       *  **  *      *    * **  *** * *  * **** *  *
**     **    *** *   **     **** * *  **** * ** *** **** **  *** **   * *     *** *** ** ** *  ***    **  *
*  *  *  * * *  *  **** **** * * * * **   * *  *   * * *     * ***  ***  **  ** * **   * ** **   == b[strlen(a)-1])
** **  ****  ***   *   *    *  *****  *  *   *** *  **        * * **   **** * *  *** * *  * ** ***** ** **
** ****  ** ** *  * *  ** *  *  *  **  *  * *** **   * ***   *  *   ** *** ***    **  **   *  * **   **  **   * *    * * **     ****** *  * * * *    is a prefix of %s",a,b);
*   **   **    * ***   ** *** ** * *    * * * *      ** * * * *  *  * *    * * * * *   * * *    ***** * *   **** ** * ***** * **    *  ** 
  * *  **     * *  * * **  * * *  *   *    *  * ****       **  ***  *  *   ****       * * **** * * *  *  
* ** *** ** ** * * ***   *  **  * *  ** * * * ** * ** * 
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* *****   *  *  * ** * *   ** ****  *  i;
** ****  *   *   * * ****    (a[0]!=b[0]){
 ** ** * **  *  * *   ****  *  *   *** * **    * * *  * **  0;
   *    *  ***   **  *  * *** *  * **
***    * *  **   **  *   * ******   *  ***  **   * **** *
*** *** ******  ** **     ***       *   **** **  *  * *      * a[i]==b[i])
* *** *** *     ***   *** ** * * *** ** * ** *****   *   *   *  
**  *  ** *  * * *  ***  ****     * * * ** *   *  **    *  * *****     ****** ** 1;
 *** *** *     *   *** *  *****     *   *  ****** ******  * ** *  **  *  *** ** *    ***** *
* *** *  * **  ****   * *   * *   ** ** *** *******
* * *    **  *** ****   ** *  
 * ** **   * * * * *  *     * * ** * 0;

}

int main(){
   * * ****  *    *  **   *   c[n],d[n],e[n];
*  **    *** * ** * *  i;
  **  **  * ** **  *** * ** *** **   %s",c,d);

    ****      * ** * **    *    **  ***** *
* ****   *     *      ** *   * *    ** ******  *******    **  **** is a prefix of %s",c,d);

*  *  **  ****  ****** ****
    ***  **  **** ** *     ****  * ***  ******** ***   ***  is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.234
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.5k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 6.5k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.5k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 5.8k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 1.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users