0 like 0 dislike
2.7k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數),計算其總合。C語言不提供大數資料型態,但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.7k views

4 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char input[500],s1[500],s2[500],temp;

int i,space,sum[500],carry,temp2,flag=0;

int main(){
** ** ** * * * ** * ** ** * * * * * %s",&s1,&s2);
**** ** * ** ** ** ** * * *** *

///get space
** * * *** * *** **** * * * ***
* * ** *** ** * ** ** ** *** ** **** * ** * ** '){space=i;}
    }

///get s1
* * * * ** * ***** * ** * * * ';i++){
*** * * * * * ** * **** * * * * **** *
    }

* **** * *** **** ** ** ** * *** * ** ** *
///reverse input
* ** * ** * ** * * ** *** ** * *
* * * * ** * * ** ***** ****** ***** *** ** ** ** * * **
* * ** *** * *** ***** * * * * ** * ** * * ** * *** *** ** **
* *** * * ** ** * * * * ******* * ** * ** ** ** * * ** ***
    }

///get reversed s2
*** * * * ** **** ******* ****** ';i++){
* *** * * * *** * ** ***** * **** * * * ** ****
    }

///reverse s1

*** ** * ****** ***** ** **** **** ** * **
* * * * ** * * * ** ****** ** *** * *** * * * ** *** **

**** ** * * * ** * * * * ** * ** * * * **** ** ***
* * * * * *** * * * ** * ** * * * * ** ** *
    }

///sum s1 and s2
*** * ** ** * ** *
** * * * ** **** * * ** * * *** *
*** ** * * ** * * * *** ** * * ** * *** ** ** * * *****
* *** * *** * * ** ** ** * * **** ** *** ** *** * * ***
** * ** ** **** ** ** ** ** * * * ******* *** *** ** * ** * *
* *** * *** * ** * ** * * ** ** **** ** * * * ** **
** ** * * ** *** *** * * * ** * * ** ** ** ***

    }

* ** * ** * *** * ** * **** * rev:%s\n",input);
* *** ***** *** *** ** ** * ***** ** rev:%s\n",s1);
* * ** **** * ** * * ** **** * rev:%s\n",s2);
*** ** * * * ** ** * ** * * * * *** * *** * **** *** ** * ******** * **

///reverse output
* * ** * * * ** ** * * *** **
* ** ** ** * *** * * * * ******* * * * **

** *** ********** * **** * ** * * * *** **
* ** ** ** ** *** * *** ** ** * ***** ******* * **
    }

///print
*** ** * *** ** ** * ** *** ** * **
** * ** ** ***** * * *** ** ** ****** *** ** * * * **
* * * *** * * ** *** * **** *** ** *** *** ** * * ** * ** * ** * *** *
* *** *** ** ** *** * * * * *** * ** * ** ***** **** * * ** ** ** ** *** ** *** * * *** **** ***
**** *** ** * * ** ** * **** * * ** ** ***** * ** * * * * ** * *** * ** * * * * ***** * *
* * * * *** * **** * ** * ** * * ** ** *** ** * * * * ** * *

** **** ******** * ************** * **** *

    }
* ** ** * *** * ** * ** * * ***
    return 0;
}
answered by (-286 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
prog.c: In function 'main':
prog.c:80:12: warning: multi-character character constant [-Wmultichar]
     printf('10');
            ^~~~
prog.c:80:12: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:80:5: warning: format not a string literal and no format arguments [-Wformat-security]
     printf('10');
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** * ***** * ****** string1[50];
* **** * * * * * *** string2[50];

* ** * ** * **** * **** ***** ** string1);
** * ** * *** * * *** ** ****** string2);
* * * ***** * *** * **** * * arr[51]={0},i;

* ** *** ** * * * i<strlen(string1); i++)
* * * * * ** **** ** **
* * *** ** *** * ***** **** * ** * * ** * += string1[strlen(string1) - 1 - i] - 48;
    }

** * * ****** * * * * *** i<strlen(string2); i++)
* * ** ****
**** ***** * *** * ***** * *** ** * **** ** * * += string2[strlen(string2) - 1 - i] - 48;
*** ** ***** * ** **** ***

* * * ** * ** * * * i<50; i++)
** ** * ** * *
* * * **** ** * *** **** ** * * * *** * **** * *** * > 9)
* ** * * * * * *** * ****** ***** **
** * * * * * * **** ** ****** * *** *** * * * * *** ** * ** ** -= 10;
***** *** ***** **** * * * ** * * * * ** * **** ** ** * ***** * * **
** ** ** * * * ** * * ** * * **** ** *** *
* * ** ** * **** ** * **

** ****** **** *** ** **** * i>=0; i--)
* ** *** * ** ***** **
* **** *** **** * * * ** ** ** * ** * * != 0)
** **** ** * * ** * ****** **** ** ** ** ** *** * *** * * * *
*** ***** *** *** * ** **

** *** ** ** * ** * * ** * * * * i--)
** *** ** *** **** ** * * *** * **** ** * *** *** * ** arr[i]);
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main (){
int s1,s2,l1,l2;
int num1[50],num2[50],sum[50];
printf("enter input 1: ");
* ****** * * * ****
printf("enter input 2: ");
* * *** ** ** * *
for(l1=s1[l1]!='\0')
* ** ******* * *
for(l2=s2[l2]!='\0')
* ** ** * ** ** * **
int carry=0;
int k=0;
int i=l1-1;
int j=l2-1;
*** * * * * ** * * *
{
* * **** ** * *** *** * * ***
* * *** * ** * * *
* * **** * ********** ****** *** ** * ** * * *** ** *
* * ** * ***** *** * *** * ** *** ** * ** * **** * ** * * * * * **** ******
** **** **** ** * ** * *** * ** * * * * * ****** *** ** * * * **** *** ***
* * **** * ***** * **** if (j>=0)
** * * * *** * *** * * *** * * *** * ** *
** * * * ** ****** ** * * ** ** ** ** ** * * * * * ** * * *** ** *** ** * *
**** ********* **** ** * * * ** ** ******* * ******** * * ** * * * * ** * ***
* ** * ** ** **** *** * *** ** ** * * ***** **** *** if(carr>0)
** * * ** ***** ** ***** ** ** **** * * *
* * * ** ***** * * * * * * * * ** ** **** ** * * * ");
****** * * ** * ** * ** ** * * * ** * * *
}
for(k--;k>=0;k--)
* * * * * * ** * **
***** **** ** * **** * ** * ** ***** * *
* * * * * * * *
  return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:9:10: error: subscripted value is neither array nor pointer nor vector
 for(l1=s1[l1]!='\0')
          ^
prog.c:9:20: error: expected ';' before ')' token
 for(l1=s1[l1]!='\0')
                    ^
prog.c:9:20: error: expected expression before ')' token
prog.c:10:10: error: subscripted value is neither array nor pointer nor vector
   num1=s1[l1]-'0';
          ^
prog.c:11:10: error: subscripted value is neither array nor pointer nor vector
 for(l2=s2[l2]!='\0')
          ^
prog.c:11:20: error: expected ';' before ')' token
 for(l2=s2[l2]!='\0')
                    ^
prog.c:11:20: error: expected expression before ')' token
prog.c:12:12: error: subscripted value is neither array nor pointer nor vector
     num2=s2[l2]-'0';
            ^
prog.c:17:15: error: expected ')' before ';' token
 for(;i>=0;j>=0;i--;j--;k++)
               ^
prog.c:23:13: error: expected ';' before 'carry'
             carry=(num1[i--]+num2[j]+carry)/10;
             ^~~~~
prog.c:27:13: error: expected ';' before 'carry'
             carry=(num1[j--]+num2[j]+carry)/10;
             ^~~~~
prog.c:28:18: error: 'carr' undeclared (first use in this function)
         }else if(carr>0)
                  ^~~~
prog.c:28:18: note: each undeclared identifier is reported only once for each function it appears in
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int main()
{
* * * *** * *** ** *** ** a[50],b[50];
* *** **** ** *** * * * c[51]={0};
* * ** *** ** ** * * * i;
********* * **** ** * ** x=0;

* * * * * ** ** * **** * %s",a,b);

* *** * * * * * *** ** * **
    {
** *** *** * * * * * * * ***** ** ** * * ** * ** *
    }

** * * * * *** * ** * **** *****
** * *** ** * * ** *
** * * * ** * ** * * *** * * ** * * **** * ** ** **
* * ** * * * * * **


* ** * *** * ****** ** **** *
*** **** * * **** *******
* * ** ** * ** * *** ** * * * * ** *** **** * * *** * * ***
** ** * **** * * **** * ** ** * * * * * ** *
*** * * * * * ** * **** ** ****** * * * * * * * * ** * *** * **
*** * **** * ** * ** *** ***** * ** * ** ** *** * * ***** ** *****
* *** * ***** * *** ** ** ** *** ** *
    }

* ** * * * *** ** * * * * ***
* **** * * * ** * **
* ** * * * * * * * * * * * ** * **** *** != 0)
** * * * * ** ** ***** *** * **** * *
* **** ** ******* **** * * **** * ** * * * * ** * * ******* ** ****** *
** * * *** * **** * * * * *** *** ** * ******* * * ** *** * ** *
** * ** *** ** *** *** * * ** *** **
    }

** * **** * ** ** *** **
    {
** ****** ****** ** ****** * ** * * ** * * * *** *** * * **
    }


* * *** * ** ** ** *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.104
©2016-2025

Related questions

0 like 0 dislike
13 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43463 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 4.3k views
0 like 0 dislike
6 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43462 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.3k views
0 like 0 dislike
8 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.7k views
0 like 0 dislike
12 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43459 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 4.4k views
1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users