1 like 0 dislike
13k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 13k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** * ** ***
#include * **** *****
*** ** * * *** * ***
** * * ***

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * *** *

* ******** *** **** * **** * **
* * * * ** * * *** **** == b[i]){
* **** * * ** * * * *** ** * * ** ** *** * *** *
*** ** * *** * *

* ** ** * * *
if (cnt == n){
* * * * * **** ** * *** * ** * ** 1;
** **** * * ** ** * * * * * * *** * * ***
*** * * ** * **
** ** * * * * ** ** *** ** * * * ****** 0;

}

int main()
{
* * ** ** ** ** ** ** s1[100], s2[100];
* ** * ** i,j;

** * * ******* ** * * * **** * s1);
* * *** * * **** **** *** ***** **** s2);
** *** ** *** ** (prefix(s1, s2)){

* ** ** * * * * *** * **** *** ** ** * ** ** * * * is a prefix of %s", s1,s2);
** * **** ***** * * ** * * ****** **
****** * **** *** **** * * * * ** * *** * *
* * *** * * * ** **** * * * ** * * **** * ** **** **** *** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
***** ** ****** *** ** *** * c;
* **** * * * * * * a[100],b[100];
** * ** * ** ** *** ** *** * * * * %s",a,b);
* * ** *** * ** **** * *** * **
*** *** **** **** *** * **** ** * ** ** 0;
*** ** * * * **** ** * * ** ** %d",strlen(a),strlen(b));
** * ** *** ** ** **** * ** ** *
**** ** * ** ** *** * ** * * *** * * * ** *** *** * * * * * *
** *** * ** * ****** *** **** * *** * ******* * * * * ** ********** * * * * ** ** ** ** * * * * * ** is not a prefix of %s",a,b);
** ** * ** **** **** ** *********** * * **** ** * *** ** * * ** *** * * *** **
*** **** ** * ** ** *** **** ** **** * ** * * ** * * * * ***
** ** * *** ** ** ********* * ** ** * *** *** * * * * if(c==strlen(a)-1)
* ** *** ** ** *** * **** ** ** * * ** * * * * * ** *** * *** ** * ** * * * *** * * *** is a prefix of %s",a,b);
    }
**** * * *** * ** ****** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * * ** ** n,count;
* * * ******* * * * *** ** * * * **
** **** ********** * * * **** * %s",a,b);
*** *** ** * *** ** ** * * * *

* * * * **** * * * * * * ** * **** *
** * ** * ** ** * *
* * * ** * * * ** * * ******* ** * * **** *** *
* *** *** * * ***** *** **

* * * * * ** * * ** (strcmp(a,c)==0)
* **** ** ** **** *****
*** * * ** ** ** *** ** *** * * * * * * *** * * * is a prefix of %s",a,b);
* * ** ** * ** ** * * **
* ** ** ** * *
** * * ** ** * *** * ***
**** * * **** * * * ********** ***** ** * * * ** * ** * ** is not a prefix of %s",a,b);
* * * * * ** *** * *
* * ** * ***** * * * *** * * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * * * ** * **** a[100],b[100];
* ******* * * * * * ** * * ** ** *** ** * ** *
    int l1,l2;
** ** **** ** * **
* * * **** *** * *
* ** * * * * ** * ** *** * ** ****
* * ** * * * * * ** * * * * * * * * ** * **** * ** * * is not a prefix of %s",a,b);

    }
* * *** ** * ** *** *** ** if(l1<=l2){
** ** * * **** * **** * * * ** **** ** * * * prefix=1;
* ** ** * * * * * ** ** *********** *** **** ** i=0;
*** * *** ** * **** ****** * * * *** *
* **** ****** ******* * ** *** *** **** * * ** * ** * * * (a[i]!=b[i]){
*** * * * **** ** *** **** * * * ** * * * * ***** * * * ** *** *** ** * *** * *** ***
* * * *** ****** * ** ***** ***** *** * ** * ****** *** ** *** ** * **** ** *
* * ** ** ******* * ** * ** * * ** **** * * ** * *** *


* * *** * * *** * * ** **** * ****** ** * ** **
* * *** *** *** * * ** * *** * * * ** * * * ** **
** *** * ** ** **** ***** * * * * *** * * * **** * * *** * * *** * is not a prefix of %s",a,b);
* ******** * * ***** * * ******** * *
*** * ******* * * ***** * ** * * *** ** * ** ** **
* ** ** **** * * * ** * ***** ** **** ** * * *** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * *** * * ***** *
int main(void)
{

* * ** * * *** pre[100];
* ** ** ** ** * **** * word[100];
* * * ** * * ** **** ** * **** %s",pre,word);
**** * **** *** ** * * * *** *
*** **** *** * *** * * *** ** * **** **

****** * * * ** * * * ** * * i;
* * * * **** *** * *** * **** * * * *
* **** ***** * * * *****
* ** ** **** ** ** *** **** * ** ** * * *
* ** * ** * * * ** *** *** *** * * ***
* * ** * **** ** ** ** ** ** ** * ** ** * ** * **** * *** * * * ** * ** is not a prefix of %s",pre,word);
*** * * **** * *** ******* **** ******** * ** *** * * * **** * * *** * * 0;
* ** * * **** *** * * **** ** *****

* * *** ** **
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** **** ** ** * ** * *** ** pre [100],a[100];
* * * ** * ** * * *** ** n ,i;
****** ** *** *** * * ** * *** * **
* * * ** * *** ** * * * *
* * * **** *** * **** ** *** * * * * * *
******* ***** ** ** *
*** ** ******* *** ***** * ** ** * ******* * * * * (n=0;n<strlen(pre);n++)
** * **** *** *********** ** * * ****
* *** ** * *** * ** ** **** * ** ** **** * * * (pre[n]==a[n])
* * * ** *** ********** **** ** * * * ** * * * * * * **** * ** * ** is a prefix of %s",pre,a);
* * ** * ** * *** * * ** * * ** ** **** *** ** ***** * *** * *****
********* ** **** * * **** * ** *** * ** ** * **** * * **** *** ** * ** * ** **** *** * ** ** * *** is not a prefix of %s",pre,a);return 0;
* ** ** * **** **
****** * *** ** * * ** * * * * **** ***** * * * *** ** **

*** ** * * ** ** ** *** * ** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * *** *** ***
#include * * ** ** ***

int main()
{
** * *** * ** * * a[100];

** *** * * * * * * * b[100];

* *** * * * * ** *** * * %s", a, b);

* * * * ** * *** ** ** len_a = strlen(a);

*** ** * ** * **** * * *** i = 0;

** * * * ** ** * ** * **** flag = 1;

* * ***** *** * ** * = 0; i < len_a; i++)
* * * * **** * ** **** **
* * ** * * * * * **** ** * * ** != b[i])
* *** ** * * ***** * ****** * * * ** *** *
** *** * ** ** * ** * ** *** ** * * * ** *** ** ** * * * * * * *** * = 0;
* ** * * * ** * * ** * * * * * *
* * *** * * *** ******

* ** ** **** * * ** * ** * == 0)
* **** ***** * **** ****
** ** * * * *** * ******* * * **** * ** **** is not a prefix of %s", a, b);
** * ** *** * * * *
****** **** * * ** * *
* **** * * *** ****** ** ** *
* * ** ** * * * ***** * * * * * * ** ***** * * is a prefix of %s", a, b);
* * * * * * * **** *** *
* **** * * * * * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * * ****
int main()
{
* ***** ** ** * * * *** i,n;
* **** ** * ** * **** p[100],s[100],a[100]={};
* *** ******* *** * * * * %s",p,s);
*** ** ** ** * *** ** **
** **** ** ** * * * ** **
** *** ** ** * ** * **** * * ** *** * * * **
*** * ** ** * * ** ** ** ** * *** * * *
*** * ** ** * ** * * ***** * **** * *** * ** * ** * is a prefix of %s",p,s);
***** * * ** **** **
** ***** ** * * *
* * ** * * ** * *** **** ****** * * * ** ** ** * * *** * ** is not a prefix of %s",p,s);
** * * **** ** * * *
****** *** ** * * * ** * ** * *** ** **
* * * ** ** * ** ***** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* ** * * ** ** *** **** * * ** ** *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
***** ******** *** ** ***** * ** ****
* *** ** * * ** * *** * * ** * ***** * **** * * * ** **** ** != b[i])
* * ** ** * * ** *** ** *** *** *** * * * * * ** * *** * *** * * ** *
* *** * *** * **** ** * ** ** ** *** ** * * **** ** * ** ** * * * **** * **** ** ** * * ** *** ** *** ** ** ***** ** * is not a prefix of %s",a,b);
***** ** **** ***** *** ** * * * ** **** * ** **** * **** *** **** ** ** * * *** * ****** **
** *** * ** ** ** * *** ****** ** ***** **** ** * * ** ** *** ***** ***** ** *** * **
* * ** * ** * ***** ** ******* *** ** ** * * * * * **** **** ** ***** * * * * == b[strlen(a)-1])
** *** * * *** **** **** ** **** ** * ********** ** ** ** ** * * * * * * * ** ******* * *
*** * ** * * ** * * * * ** * ***** * **** * * * *** * * * * * * ** * ** * ** ** ******** * * *** *** ** is a prefix of %s",a,b);
** *** * * ** ****** ** ** *** ***** * * * *** *** * * * * ** * ***** ** * ******** ** ** * ** * ** ** * *
* ************ * ** ** * **** *** ******* ***** * *** **** * **** * ** ** ***** * * * **
** * *** ** ** **** ** ******* * * * ****** *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** * ** ** * ** *** * i;
* ** **** * *** ** *** ** ** * (a[0]!=b[0]){
** ** * * ** ** ** ** * * * * * ** * * * * *** * 0;
** ** ** * * * * ** *** ** * ***
*** * * *** * **** ** ** **** ** * * * ** ***
* ** * * * *** ******* **** * * * ***** **** * ** **** a[i]==b[i])
* * *** ** *** * **** *** * ***** * * *
* ** *** ** * ** * * * * **** * ** * *** ** ** * * ** * **** * 1;
*** * *** ** * **** * ** * **** ***** *** **** ** ** ** **
* * * ** ****** * * * ** * * ******* **
** * ** ** * * ** * * **
***** * *** ******** **** *** **** ** 0;

}

int main(){
*** ** * ** ** * * c[n],d[n],e[n];
** ** ****** * * **** * i;
*** ** * *** * ** * * %s",c,d);

*** * * * * * * *** * **
********* ****** *** * *** ** *** *** * * * * ** * * * is a prefix of %s",c,d);

* * * * *** ** *
* * *** ***** ****** * ** * * * * * * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.120.164
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.6k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.5k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.4k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.3k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users