Final Exam 2 (20%)

1 like 0 dislike
7.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 7.2k views

37 Answers

0 like 0 dislike 
Hidden content!
#include * *** **** ****   
#include ****  ** * ** 
    **** *   *  *** 
  *   ****  *****    

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n=   * ****

***   *  **  **        ***     *****
   * **  ***   *****  * * * == b[i]){
**  * **    *  ** ** * *** ** * *****    *** ***  * ** 
**  * * ** * *   *  **      *  ***

*  *      **   *  *    *
if (cnt == n){
  *  **  *** ** ** ** ** ***** ** **   * ** **     *** * **** * 1;
  * *       ** ** ***** *  *  *       *    **    **  *
 ***** **  ** * ***   ****  **
  * ********  * ** *** ** ******* * **      * * **   *** * ****  0;

}

int main()
{
**** *  *****  ** *   s1[100], s2[100];
*       *  **  ****  i,j;

   * ** *** * *** **  ********* **  *  * ** s1);
 *         ****   **  *  ****   **** *******  ** * s2);
**        *** *   * *  * (prefix(s1, s2)){

** ** *  * *  * ****** *    *   **  * **** *****  *  ***  is a prefix of %s", s1,s2);
** *** *  *** * *** ** * *  *******        
**  *  *  *****    * ***** ******** *  *  ** ** *      *    *
** * *   ****** **** * *   * *  ** **** **  * * * **  * *   ****** **   * ***** **  is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
***  *** * ** ******* *** *  c;
*********  *    ** *   ***     *** a[100],b[100];
*  **  *  **  * ** **    **   ****      %s",a,b);
 **   *      *  **** ** *  ***  ****    *  * 
* ***  **** * **  *** ***   * *** *  ** * * *****   0;
 ****  *   ** * * *   *** ***  * ** *  *  ** %d",strlen(a),strlen(b));
*   ***  *  ** *** * * **  *  *  *   *** *  *
* * **** * ** * **  ** * *** *     **  *  **  ** * * *  ***  * ***** ****** **** **
 ***   *     **  ****  ** ****  **  ** *  *      ***** *  * *   **  *  ****** **  *  *****  * *  ****  * * **    is not a prefix of %s",a,b);
 **  **  * * *** * *  ***   * ** * **  *** * ****** ***  *** *       * *  ***   *        ***    **  ** **** *    **  * 
    **  *   *** * *** * **     *  *    ***  *  ******      * *  ***   * **** **  **   ***   
  * * ** *** ** ***  *   *       *** *** *  * *** *** **** **    * *      ******  if(c==strlen(a)-1)
    * **    *  * ** **    ** *    *  *   * * * *      ****** *  ** *  *** ***** *******  * *  *  *    * * *** * ****** ** ** is a prefix of %s",a,b);
    }
* **  * ***   ** * * ** ***** ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
    * *  *   ** ** * * *** * n,count;
**** *** * * *    **  *    *** *       * *  * * ** ** * 
  * * *** *   *****  *******  *****    %s",a,b);
*   *  *    * ** **   **    **  ***

    *** * *    **  **     ***  ****   * *** * * *  * * * *
      * *** *** ** ***   *  * * 
 *    *   ** * *** *  **   *  **    *  * ******  *   **  *    **   ** 
 *** **   **  ** ** * 

** ** * *  *     *** ***** (strcmp(a,c)==0)
 * **     * * **** ******  
* * ** ***   *        * *   ** *     **** *   *  ***    **   is a prefix of %s",a,b);
 *******  *    *** ** ** ****
 *   **** **   ***** *  ***** 
** ** *    * ****     **** **
** *** * ***    ** * * *    ***** ** ******     ****   ** *  is not a prefix of %s",a,b);
** **        * **       **
  ** * * * *******  * * ***   0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
 *  * *******   ****     ** ***  a[100],b[100];
****    **  *   *    ** **    * ** * *   ** **** ** *** 
    int l1,l2;
 *** *** * * * ** * **   **          
* * *     ** * ** *       * *       *  *** *
***   **  *  * *   *****  *    ***** * *** * 
** **   * ** *   ****  **  *  *      **  * *** ** ***  *  * *** ** * *  * is not a prefix of %s",a,b);

    }
 **** *   * *****    *    if(l1<=l2){
*** * *** * *   **   * * ** ** *    *   * **   **  prefix=1;
   *   * ** ** * **** ** ** **** * * **    *** *  **  * * i=0;
*   * *   *   * *   *** * *   * **   * ** *  **  ***  * *  *  *  
* **** *   **    *** * ***    *  ***    * *      *    ** **   *    **   ****  * * (a[i]!=b[i]){
* *** *     **    * **   *  ** *** *   *   ******    **  * ***   *      *   * ***   *  **  * * *   *       ** * * *  **    ***
*****      * * ** **   *  * * **   ** ** * *  * *  * *  ** ***  * * **  **** * ** *   **** *  ****    ***   **  * * *   * * 
* *  *  ***** **    * **  ** ***     * ***  * ***** **  * *  ** *  * *   *  


 *** ** * * *  *****   * ** *   **** ********    ** * **
 *  *  * **   * **   *      * * ****   * ***** *** *** * **** 
**   * * *    **   *    * *** * ** ******* **     *** *  *** *    *     *  * *** *** *  * * **  is not a prefix of %s",a,b);
*      * *****   * *** *  * **** *  **   *  *   ****  ***  
**  *** ** *** ***  ** ***   * *  *     * * **  ***  * ** * **
  ** * *    * *   *       * *   *  **   ** *  *    ** * *  ** ****  is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
**  ***      * **    
int main(void)
{

**  * * * *****   *        pre[100];
** * ** **  ***  *   *     ** *   word[100];
  ** ** *  * *  * * ** *    ******** * %s",pre,word);
***  **  * *** *****       * * ***  **     
    ***  * ******  * ****   *  *  *   **    ** 

   *      **  ******** **** ** i;
** **   * ***  ** *** ** *  ** *  ** ** ** *  *   *
 ***   *  * *   ***** 
 *   *****  * **  ** **  ** *    ** * *  ** ****  * *  *   **
  * * * ***   * * * ** ** **   *  *** * *    *   * 
** * * *  * **** **     *   *  *  **  ****  ***** **** ** **  *****   * ***** *   *   ***  is not a prefix of %s",pre,word);
* * *        *** * ** ** *** **   *  *  *   *  *   *   ******    * **   **  ** ****  ** 0;
 *  ******* ******   ****   * ** ** **  * * ****  

* * *  ** **  *  *   ***   
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
 * * **   *  ******  *  *  pre [100],a[100];
**      *    ** *   *   *  * n ,i;
* * * ****      *** *  **** **    *  *  **
**  ** ***    *   * *    *** ***   *  ****** * 
 ** **  * * *      **    *    **  ******    ** **
*        * * ***   *   
     *********    * ******  *   ********  **    *  ***** (n=0;n<strlen(pre);n++)
  ***** *  ****** *  ** ***  * ** * *** **** * **
  *     *** **** *  * **   ** ** *   ** ***    **  **** *  ** ****  * ******  (pre[n]==a[n])
  * *  ** *   *  *   *    **  *     ** * ** ** ** *   *         ***** ***  ** ***   * ** is a prefix of %s",pre,a);
*** ***  *  * *   *   **  * *****  **  ** ***** *   ***  **  **  * ***    *****
*   ******* * * * * *   * * * ****   * ***     **  * *   *   * *    **  *  *  ***  *  **   ********** *** * *    *   *   **  is not a prefix of %s",pre,a);return 0;
  *   **  ** **** *    * *
*    ***   **  *  *  ** ***   *      *  * ****  ********   * * **   * ** ** ***

 * ** **   * **    ** ** * **** * * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *  *   ****    
#include ** * **       

int main()
{
* *  **  * *  **   *  *    **  * a[100];

 *  ***      *** *  * ******  b[100];

*****  ***** *** *  **  *  * ** **    %s", a, b);

***     ****** ** ***  **** * * len_a = strlen(a);

 ***** *** * ** **  * * **** *  i = 0;

 *  * * ****  ** **  ** * flag = 1;

***   ** * * *   ****  ** * * = 0; i < len_a; i++)
****** **** ** * ** *********  
*  ***  * **  * ***    *  ***  ***  * **   *  ***   **  ** != b[i])
 ** * ***   *  ***** *  **     ** *   * ***   **   ** *
** * ***  *   *   *  *** *    ****** * *   ****      **   **  *  **   *  *   **  = 0;
* *    ********  ****  **  *  ** ***      ***********
 ** **  *    *****  * * * 

* *  *  * *** *  *** **        *** == 0)
*      * **     * * *   *
    ** *  ** *** ** ** *   ** ******  ***** *** * **  *      *    * is not a prefix of %s", a, b);
* *  *   ****  ***  * * *
 ***** *  *     * **  ****  *
     * ** *  *  *  *** *** *   
  * *  ***  * *  **** *  * * ***  ** * * *      ***  **  * *   * is a prefix of %s", a, b);
*  ** * ****  *   * *** *      *
*   *   * *** **   ****** * *  0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
 ** * * ***  *  *   
int main()
{
*    * * ***  * * *   ** * i,n;
 * *  * *  * * *      *   **  p[100],s[100],a[100]={};
   **  *       ****** **  ** * * *** ** %s",p,s);
**  **   **   *** *** ******** *    *
**  **   * ****  ** ** * * **  *  *** *
* *   * ** ***    * **   ** * * ** *** ** ******* *   * *  
 *     **   *** ****** * ***   ** *   ** *  * 
*  *   *  *   * * * ****  **         *** *  *** ** ** **  *  * * *  ** * is a prefix of %s",p,s);
*  * *  ****** * *  *  *  **
**  ****** *     * **** **** 
 ***  ******  ***    * *  *   ** **  ***  * * * * * **** *** ** **  * * is not a prefix of %s",p,s);
*   *** * *** *     *  **    
*  *  * * ***** ** * **  *    * * ****  **   * *  
 * * *  ** *  *  ****    ** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
**  * * * ****   **    * **  *      ** * *** 
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
*  ** ***      **    *** * **  ****     **** ***
*   ***** * ***** * *** * ***  **      ***        * **  * **  * ** *    * *  *      != b[i])
     *    *     *** *** *** * * * ****  * * *  * *** ***** *  * **    *  *   ***    ***  ******* ***  
 *** ** ***  ***  *   **** ** * ***  * ** ** *  ** *   ***** * * **  * ***   *** * *  *    *   *  *  ** ** **  *** ** * *** *   *****  ******* is not a prefix of %s",a,b);
******** **  * *   **  ** *  ***     * * * ** *  ******    * ***  **  *   *   * * **** *     **   *  * **   *  *  *   * *    **
* ** *** *  * **  **** * * ** **   ** *** ***** ****       *   *** ** *** *****   * *    **** **  *   ***** *   
    ***   **  *  ** *     ***   * **** ***  * * *    *  *   *     * **** **     **  == b[strlen(a)-1])
   *****  ****   *    *****   * ** *** *   *  ***  * **     ****    **    * *   *   * * *   *    * ****   *  *   
   * ** *  ** * *    *** **   ** * **** ***   *       ***      **** **     *    * ** **  *   *** * *** ****  ** ***         ** *  * * *  *      is a prefix of %s",a,b);
*     *   **   *  ** *  **  * ******** *     ***  *   ******* **  * *** ** * ** ***  **  **    *   *** ***  *  *  *  *******  *    *
* ***** ****** **  ** *   *** *****     *     ***  ** **       ******  * ****  * *** * *  * * *****
*******    *** *   *** **  * * **** **     *** ** **   *  *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
 ** ***     *  **  *** ** **   **   i;
* *  *** **   ****   * *  * * ***** (a[0]!=b[0]){
  *  * ** * **   *  *    * * *   * * ****** *     ** *   0;
 ***  ** **   *   ***  ***  ****
   *   *** * *  *   * *** * **  *  * ** ** * ** 
**    ** * **  * ** **  * **  ** ** * ******   **   * *  * **    a[i]==b[i])
***    * ** *  * * * **       *  ***** * *   *** **   ** *  * 
          **** **     *  * *    * *    **** ***  ***  *** * *   *       ***** *** 1;
** *     **   *   *** ***** * ***   * *  *** *    *** **  ****     ** *    ** *     **   *
 *      ****   **          *** *      * **   **   *
    *   *       *      *    **  *** **
*   *     * **    * *  **  *   *    0;

}

int main(){
 **   *  * ****    * ***  * *     c[n],d[n],e[n];
**  *  *****  * ****  **** i;
 ***  ****    **  * *** ***  ***  *   %s",c,d);

** ******  * *        ***   *  * **  **
  *   ** **  **  ***     ****  **** * *** * ** **    * ***   ** **  is a prefix of %s",c,d);

*  ***    ****** **   *    *
  *    *  **       * * ***    *     *** *  *** * * ** ** **    **  is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.199
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.5k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 6.5k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.5k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 5.8k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 1.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users