Final Exam 2 (20%)

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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Hidden content!
#include    ***   *  ** *
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int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

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}
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#include <stdio.h>
#include <string.h>

int main(){
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    }
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}
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Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
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*** **   * ****   * ** ** *
**  **  **  *   **  * *    0;
}
answered by (-284 points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
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Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
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    }


}
answered by (-329 points)
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prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
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Hidden content!
#include<stdio.h>
******* **    ** ****    
int main(void)
{

*  ***   **  **  ** *** ** ** ** pre[100];
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printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
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Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
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**   * *     **  ***  * *    *  * 0;
}
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Hidden content!
#include <stdio.h>
#include        ****** *
#include ***   *******

int main()
{
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 *     **  **  *   *  **   b[100];

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 ***   *     **  * * * 
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* ** **  **  * * * *    *  
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   *   *  ** ** *  *  * *  
           * ******    *  *** ***  0;
}
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Hidden content!
#include<stdio.h>
** *  ***  * ** * * *  
int main()
{
 **** *     **    ****   * **    * i,n;
  * *** * *  ***** * * ***  p[100],s[100],a[100]={};
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    * **** * * *  *  *   *****
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** ** ***  * **  **       * ** **  0;
}
answered by (54 points)
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
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* * ****  * * ***   *  **** **  *    * * * * *** * ** *
}
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Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
 * **   ****** * * *   ****** ** * * i;
*  *** *** *** ***   *   * ** **** * *  (a[0]!=b[0]){
** *      **  *** *  * * *  *  *   *** **   ****   * ***  0;
*** * * *    * ** **     **   **   
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** ***   *   * *  * ***  **       ****   * ** ** ** **
***   **     *  * *  * * ********* *  
 *  *    *  ** * ******* *    ** ** * 0;

}

int main(){
* *    *  *   *  **  *  ** ** * * c[n],d[n],e[n];
  ** *  *****    **   * *     **  i;
  *    *   ** * ******* ** ****     *   *** %s",c,d);

 ****  * * * *   *   *  **  * **   * 
** *   ** ** **  *** * *   ***  *  **  *  *** * **   *    * * is a prefix of %s",c,d);

 * * ** *  **  * ** *****   **** 
** * *   ***    *** * *    *    * **   *** **  **  ** **   *  ** * *  is not a prefix of %s",c,d);


}
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