1 like 0 dislike
10.4k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 10.4k views

37 Answers

0 like 0 dislike
Hidden content!
#include * *** * * *
#include *** * *** * * **
** * ** ** * * **
******** *** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** ** * *

* * ******** * * * * ** * * **
* ** * **** **** * * == b[i]){
*** * *** ** * * * *** *** * * * ** ** **
** **** ** * ** ** *

* * * *** * ** *
if (cnt == n){
****** ******* ** ** ** ** ** ** * *** * * 1;
* ** * *** * ** * ** **** * *** * * * ****
* **** ** * * * *** * * ***
** ** * * ** * * * ** * **** * ***** * 0;

}

int main()
{
** ******** * * *** s1[100], s2[100];
* * ** * * i,j;

* * ***** * ** * * * * ** ** s1);
*** * **** * *** * ** * ** * *** * * s2);
* *** ** ** * * * (prefix(s1, s2)){

**** *** * *** **** * *** ** ** * * * ** **** * is a prefix of %s", s1,s2);
****** * ** ** * *** * *** * ****
** ****** ** ** * ** *** * ** ***** ***
*** * * ***** ******** * ******** * *** *** ******* * * * * ***** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
** ** **** **** * * * c;
** ** * ***** * a[100],b[100];
*** ** *** *** * ** ** * *** ** %s",a,b);
*** * * * *** * ** * ***** *** * * *
****** * *** * ** ***** * ** * **** * * * *** * 0;
* * ** ** ** * ***** * * ****** ******** ** %d",strlen(a),strlen(b));
** *** ********** * * ** * * * ** *****
*** * * ** **** * * ** *** * * * * * * ** * * ** **** ** ** *** ** ** * **
* **** * ** * ** ** * ** ** ** * ** * **** ** **** ** * * * ** *** ******* * ** ** ** ** * ****** is not a prefix of %s",a,b);
* * ******** *** ** ** * *** * * ** **** * * * * *** * * * ** ** * * *****
* *** * * ** * * ** ** *** * ** * ** * ****** *** *** * **
** *** * ** * *** ** ** *** ** * * * * * ** *** * * *** * *** ** if(c==strlen(a)-1)
** ******** ** ** ** ** * *** * *** * ** *** * * * * * **** * * ** *** * *** ** ** * * * ** ** **** ** * is a prefix of %s",a,b);
    }
** *** * * ** *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* *** * ** ** * ** * *** * n,count;
**** ** *** ** ** * ** * * * ***
* ** ** *** ** **** ** ****** * ** %s",a,b);
* * * * * *** * * ** * *

** ** * * *** ****** * * **** * *
*** * * ** * ****
* **** * * * ** **** ****** * * * *** ** ** *** * ** * * ****** * *
** ** ***** * * *

*** * *** * * * * ** ** (strcmp(a,c)==0)
* ** * * ** ** * * ** *
** * * * * * * ***** * ** * * ** *** *** * is a prefix of %s",a,b);
* ********* ** **
** ** * * ** ****
* * ** * * ** * * *** * *
**** ** * **** *** ** *** **** ** * *** ** *** * ***** *** is not a prefix of %s",a,b);
* ** ***** ** **
** * ** ** ** * * * * **** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** * * * * * * ** ** ** a[100],b[100];
*** *** ** * * ** ** * * *** * ** *** * *
    int l1,l2;
**** ** *** * *** *
***** ***** * * * * * *
* **** * ****** ***** * * *
****** ***** ** * ** * ** ** ** ****** * ** * * * is not a prefix of %s",a,b);

    }
* ** * * * ** * * *** if(l1<=l2){
* **** * * ** ** ** *** *** **** * * * prefix=1;
***** ** ****** ** ***** * * * ****** ** i=0;
** * ** * * ***** * * ** **** * ** ** *** * * * *
*** ** * * ** ** *** ** ** * * ** ** ***** * * ***** ** *** * * (a[i]!=b[i]){
* ** * * * * * ** ** * ** * * * * * * ** * * * ***** ** ** ** * * * *** *** ***
* ***** ** ** ** ** * * * *** ** * ** * * ** *** *** * *** * ********** *** ** * ** * * *** * ** **
** * ** ** **** ** ** * ***** ** * ** * ** **


** *** * * ** ***** *** * * ** *** ** *
*** ** *** ** ** * * **** * * * * * ***** ** **
* ** * ****** ** **** *** * ** ** *** **** * **** ******* ******* * * * is not a prefix of %s",a,b);
*** * *** **** **** *** ** ** ** ** *** ***
* * *** * ** * ** **** * * * * *
*** * * * *** **** * **** *** * * * **** **** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** *** *** * * * * **
int main(void)
{

** ***** * ** * * * ** * ** pre[100];
*** * ** * ** *** * *** * word[100];
* * ** **** * * ***** ** %s",pre,word);
** * * *** * ** * *** * * * *
* *** * * ** ** ** * * ** * **

** ** * *** ** * * * i;
***** * ** **** *** * **** ***
** ** *** *** ** *** *
*********** *** * * ** * ** * * * * * * * ** * * *
* **** * * ** * ** * ** *** ** ***
* ** ** ** * * * ** * * *** * ** ** **** ***** ** **** ****** * * * **** ** * **** * is not a prefix of %s",pre,word);
** * * ** * * * * * * * ********** ***** * **** * ** * *** *** * 0;
* * * * ** * * ******* * * ** ****

***** **** * **** * **
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** ** ** * *** *** pre [100],a[100];
* *** ** * * * n ,i;
**** ** * *** * * * ** * * * * ***
*** * * ***** ** ** *** * ****
*** ** * * * * ** *** * ** **** * *
*** * ** * *** ** *
* **** ** * * *** * *** **** **** ** * ** (n=0;n<strlen(pre);n++)
* **** *** * ** ***** ******** ******* * ** **
* *** *** *** * * *** * * * * ** * * *** * **** * * * **** *** * * (pre[n]==a[n])
* * ** * * *** *** ** * ** * * * *** ** ** * * * * *** * ** is a prefix of %s",pre,a);
* * ** * * * * ** * * *** * *** *** * * ** * * ** ***** *** * *
*** ** * ****** * * * * ** * * * ** *** ******** ** **** ** * ** ** * * * * * * * is not a prefix of %s",pre,a);return 0;
** * * * ** ** ** *
* *** * * ** ** * ** ***** * * ** *** ** ** *

* **** ** *** **** * * * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** * * ** **
#include ****** * * *

int main()
{
*** * *** ***** ** * a[100];

* * *** * ** * ** ** * b[100];

* * **** *** * ** * * * ** %s", a, b);

*** * *** * * * len_a = strlen(a);

** * ** **** ** *** i = 0;

* ** * ** * ** **** * flag = 1;

* *** ** * * *** ***** * = 0; i < len_a; i++)
** ** * * *** **** ** **
* * * * * * * **** ** * * * * * *** * ** * != b[i])
* * * * ** * *** * ** *** * *** * * ** ** *** *
** ** * * * ** *** * * *** *** * * ** ** ** ** ** * * = 0;
* **** ** * * * * *** * * ****** *
* * *** *** * ** * * ***

** *** *** ** * ** ** * * == 0)
****** *** ***** *
* ** * * * * * ** * * ***** * * ** * * *** * is not a prefix of %s", a, b);
* * ** ***** * **
** * ***** *** ** ** ***
** ** ****** * ** * *** *
* ****** *** * ** * **** * * * * * ** ** *** *** * is a prefix of %s", a, b);
**** * *** *** * * *
* ***** * **** * *** * * ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * ** * ***
int main()
{
** **** * ** * * * *** * i,n;
* ****** ** * * *** * ** p[100],s[100],a[100]={};
***** ** *** *** ** * * %s",p,s);
**** ** **** * ** * * * ** ******
* * * * ******** ***** **
** **** **** * * * ** * * *** * * **
* *** * * * *** **** ** * ** *** *
* * * * * * ****** *** * * * ** * * *** *** * * is a prefix of %s",p,s);
****** **** * * * * ** *
* * ** ***** *** * * *
** * * **** ******* * **** * * ** ** ** * * ** **** is not a prefix of %s",p,s);
* ** ** ** *** * * **
*** ** ***** ** * *** ***** * * *** * **** *
** * * *** * ********** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
***** * * * ** *** * ** ***** *** **** *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
** ** ******** * * * * ** ** ** * * ** *
***** *** * * * * **** * **** * ** * * * * * ** * * ** * *** != b[i])
****** * *** *** * ****** * * ** ** **** **** * ** ** * * * * * * * ** *** ****
*** * * ** ***** * ** * **** **** * ** * ** *** ** * * * ****** * * ** ** * ** ******* * **** * * * * * *** * is not a prefix of %s",a,b);
**** ******** ** *** ** ** * * * *** ** ** ** ***** * *** *** * ***** * ** * * ** * * * * ** * * **
* * ** ** * ***** ** * ****** * * ***** *** * ** * * *** *** ** * * ** * * * ******* * * * ** **
** ** * * * ** * * ** ** * ** **** *** * * * ** * *** ** * * * * ****** * * == b[strlen(a)-1])
* ** * ** * ** ** * * * ** ** * ***** ******** ***** ** * * * ***** *** ***** **** * * * **
*** * * ** * ** ** ** *** **** * ** ** **** ** * * * * * * * *** * * ** * * * * * * * * ** * ** *** * **** is a prefix of %s",a,b);
* * ** * * * *** ** * * ** ** ****** ** * ** **** * * ** * * *** ** *** * * * * *** ** * ** * * *
*** * * **** ** * *** ** * ****** * * ** ** *** ** ** * ** *** * * * ** * * ***
********* **** *** * ** * * *** * ** *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* **** * ** * * ** *** ** *** i;
* * * * * * *** **** * *** ** (a[0]!=b[0]){
** *** * ** ** ** *** ** * * * * ** ** **** *** * *** 0;
** * ** ** ** * * ** **
**** * ** * *** * * * *** ** * * *
** ****** * * *** ** * * * ** ** * ***** ** *** a[i]==b[i])
* * * * * ** * ** * **** * *** * *** *** * * *
* * ** * * *** *** * * ** * ** * **** * *** *** * * * **** ** 1;
**** * ** *** * ** * ** * * * * ** * **** ** ** * ** ** ** ** ** * * *
* ** ** ** * * ** * *** ** *** * *
* **** * * ** * *** * **** *
* * * * ** ** ** *** ** * 0;

}

int main(){
* * *** *** * * c[n],d[n],e[n];
** ** * * ***** * * ** * * i;
* ** ***** * **** *** * ** %s",c,d);

** *** * * *** * ** *** * * *
*** * * **** * **** * ** *** *** * * * * ** * * is a prefix of %s",c,d);

****** ** ** ** ** ******
* * * * * * * ** * ****** ** * * ** * * * * *** **** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.67
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.8k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 9.4k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.9k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.5k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users