1 like 0 dislike
9.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 9.1k views

37 Answers

0 like 0 dislike
Hidden content!
#include ** ** ** *
#include ** ** * *
* * * ** ** *
*** *** *** ** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * *** * * ***

* * ** ** * ** * ** * ***
***** * * * ****** * == b[i]){
* * * * * * * ** ** ** **** ** * *
* * ** **** *** * * * *

* ** * * ** ****
if (cnt == n){
* * * ** *** ** * ******* * **** ** * **** * 1;
* * * * *** ************ ** * * * ** *** ** *
** * *** ** *** ** * *
**** * * *** * ** ****** ** **** ** **** ** 0;

}

int main()
{
* ** * **** **** * *** s1[100], s2[100];
* * ** * * **** * i,j;

* ** * * **** * ***** * *** ** s1);
* * * * * ********* * **** *** * * *** s2);
** ** * ** * ** *** (prefix(s1, s2)){

** * * ** ** ** * * * * * **** *** ** * * ** *** ** ** ***** is a prefix of %s", s1,s2);
* *** * * **** **** * ** * * **** * **
***** * *********** **** ** ** * **
*** *** ** * * ** * * ** ** * * * ** * *** * * ** * * * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
**** ** ** * * * * ** * c;
*** **** ******** * * * a[100],b[100];
** ** ****** ** ** ** *** * ** %s",a,b);
* * * * ** ** ** *** * *** * * * ***
* **** ** * ** * *** ** * ***** * ** * ** 0;
** ******* ** * *** *** * *** %d",strlen(a),strlen(b));
* ** ** * * * * * * * *** * ** ***
** * ** ** * ** ** *** * * *** ** * * ** ** * ** * ** ** *** * ***
** *** * * ** *** * * ** *** **** ***** *** *** **** *** * * ** * * * * **** **** * * * is not a prefix of %s",a,b);
* * * ** * **** *** **** ****** * * * * ** * * *** * * ** * * **** ** * **** ** * ** * **** * *** * * *
******* * * * ** **** *** *** * * **** * * ** * * ****** * * *
* ***** *** ** ** **** *** ** ** ** * ** ** * ** * * * ** ** * * ***** * ** * if(c==strlen(a)-1)
* *** ** * ** *** *** ***** * **** * * ** * * * ** ***** *** ** ** *** *** is a prefix of %s",a,b);
    }
* ** ** *** ** * **** ** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
**** * ** ** * ******** * n,count;
* * * * * ** ** ** ** * * *
* ******* * ** ** * ** ** ********** %s",a,b);
* **** ** * ******** * * * *

* ** * * *** *** * * *** *** * ** * *
** * * * *** **** * **
* ***** * * * ** * * * * * * ** * ** ** ***** * **
* * * ***** ** * *** **

***** **** *** * * (strcmp(a,c)==0)
* ***** * * * *
** ** ***** * ******* * *** ** ******* **** * **** is a prefix of %s",a,b);
*** **** * **** * * ***
**** ** *** ** * * *
* ** * ** * **** *
* * * * ** **** ** * ** * * ** ***** is not a prefix of %s",a,b);
**** * * * * * *****
* ****** * * * ** ***** ** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** * * ** ***** * a[100],b[100];
* **** *** ***** * ** ***** ****
    int l1,l2;
* ***** * * * * **** ** *
* ** * * * **** * * * *
* * * * *** **** ** * * * * **
** ** ** *** * ***** * ** * **** *** ** * * ** ** * is not a prefix of %s",a,b);

    }
*** ** ** *** *** **** if(l1<=l2){
* * *** ** ** * *** ** * * * * * prefix=1;
** * **** **** **** ** ***** * * ** ** * * ** i=0;
* ** * *** *** * ** ** *** * * ** * * * * * ******
******** *** ** * * ** * ** ** *** * ********** ** ****** **** ** *** ** (a[i]!=b[i]){
* *** *** ** * **** * * * * ****** * * * * * * ** * ** * ** ******** * * * ** * * ** * *
* * * * * * * * * * * * ** *** ** ** ** * **** * * * *** ** * *** **** ** * **
*** * * * * ** ** ** * * *** * * *** ** ** ** * ** *


*** * ** * **** * * ** * *** *** *** ** *
* * **** * * ****** ** * **** * * ***** * * *
** * ** *** ** ** * ** *** * ** ******* ** ** * ** * * * * **** *** ** **** *** is not a prefix of %s",a,b);
* ** * * *** * * **** ** *** * ******* *
*** * ** * *** ** *** ** ** ***** ** * * ** **
*** ******** **** *** * ** ** ** *** ** ***** ** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** * *** ****
int main(void)
{

* * ** *** * ** pre[100];
** * * ** * * * word[100];
* ** * ** ** ** * *** ***** * %s",pre,word);
* ** ** * ** * * * * *** ** * * ** **
*** *** * * **** * ** ** **

* ** * ** ** * * * *** i;
* * ****** * * *** * *** ** **** **** * * * ** *
* *** **** ** *** *
* * *** **** * * ** ** * * *** ** * * ** *** **
* * ** ******* * ** ** * * * * * ** *** *** **
* *** ** *** **** * ** ***** ** * **** ** ** *** * ** *** **** * **** * ** ** is not a prefix of %s",pre,word);
*** **** * * *** * * ***** * ** *** *** * * * * 0;
* * * * * * * * * * * * ** * ** **

**** ** ** * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* ******* * * *** ** pre [100],a[100];
* * *** ** * ***** n ,i;
* ** **** *** **** ** * * ** ** *****
** * *** *** ** * * ** ***
** **** *** * * * * ** ** * ** **
* * ****** ** ** ****
* *** ** *** ****** ** * ** * ** ****** ***** (n=0;n<strlen(pre);n++)
*** * ***** ** ** * **** * * **
** * ** ** * * * * *** * **** ** * * * * * * *** * ** * * ** (pre[n]==a[n])
*** *** * *** * *** ** ** ** * * * ** * ** ** * **** *** * ** **** is a prefix of %s",pre,a);
* * *** ***** * *** ** * ***** *** * * *** *** **** ** *** * *
* ** * ***** ** * * ** * * ***** ** * ** * *********** * * ***** ** ** * * ** ** *** ** * is not a prefix of %s",pre,a);return 0;
* * ** ** * * ***
* *** *** * * * * * * **** * * * * ** * *** ** *

** * **** * ***** ****** ** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include *** * *** * * * *
#include **** **

int main()
{
** * ***** * **** * * a[100];

* **** ** * * ** * *** b[100];

** * ** ** *** * * * ** %s", a, b);

* * * * *** ** * *** * len_a = strlen(a);

* * * * * * * *** ** * ** i = 0;

* * ** ** * * flag = 1;

* *** * * * * = 0; i < len_a; i++)
** * * * * ***** * ** ***
*** * ****** * ***** *** *** * ***** * *** * * * != b[i])
* *** ** *** *** * ** * ******* *
***** * * * * *** * * * * * * * * * * *** * * * * * * * * * * * * * = 0;
**** * ** ** *** * *** *** * * * *** * ** *
*** ** * ** ** * * ****

** * *** ** * * ** *** == 0)
* * *** **** * * *
* * * ** * * * * **** **** * * **** ***** * * * * **** is not a prefix of %s", a, b);
****** * ** *** *****
*** *** * * *** * **
* * ***** ** **** * *
**** * ** * * * *** ** *** * * ** * ***** ***** * **** is a prefix of %s", a, b);
** * * ** * * * * **
* * * ** * * * * *** ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** * * *****
int main()
{
*** *** * ** **** * ** * i,n;
* ** ** **** ** *** ** ** * p[100],s[100],a[100]={};
* *** * * * * ** * ** ** * %s",p,s);
** *** * *** * ** * ****
* * *** ** * * ** *** * *
* ** ***** *** *** **** ** ** ** * *** *
* * * *** * ** * *** * ***** * * **
**** ** * *** * * * *** *** * * ****** * * * ***** is a prefix of %s",p,s);
* **** **** * * * *** **
*** *** ***** * * * ** *
***** **** *** * * * * *** * * * * * *** * ***** ** is not a prefix of %s",p,s);
* * * * *** ** * *******
* *** *** ** ** * * * ***** * ** *** **** ***
** * *** *** * ** * *** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* * * * *** * * * * * ** * * * ** ** *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
***** * * *** ** * * ***** * ****** * *
* *** *** **** **** *** ** ***** * * ** **** **** * * *** ** * * ** * * * != b[i])
* * ** ** * * * ** * **** ***** ** * ** **** * * *** ** ** *** ** * ** * * ** ** * * * *
* * * *** * ** * *** * * *** **** ** * * * * * * * * ** * *** ** *** * * * * ** *** *** ** ** ** ***** ** * ** * is not a prefix of %s",a,b);
** ** * * * ****** *** *** ** ** * ** * * **** * * * ** * * ** * * * *** * * *** ** * ** * * ** ******** **** ***
* **** * * * * *** * ***** ** *** * ****** ** * ** * * ** * * * ** **** *
** * * ** *** ** **** *** ** ** ** * * ** *** * *** ** * * * * * *** ** == b[strlen(a)-1])
** ** * ** * ** *** * *** * *** * * ** * ** * * ** ** * ** *** * * ** * * *
* ** * *** ** * * ****** * * * * ** * *** ** * ***** * ** ** ** * * * * * *** * ** ** ** * * is a prefix of %s",a,b);
***** * * * * ** * * * * ****** * * * *** *** * ** * ** * * * * * * * ** ***** * ** * * * * * ****
******** *** * * **** ** * * ** ** * ** **** **** * **** * * ***** *** * * **
** * ****** *** ** * * ***** *** * * ** * * *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** ******** * * **** ****** * i;
** * ** ** ******* *** ****** * *** (a[0]!=b[0]){
** * *** * ** * * ** ** ****** ** ** * *** **** 0;
** ** ** * * **** *
******** ** * * ** * * ** ***** * ** *
* * * * * ** ** * ** *** * ** * ** ***** * a[i]==b[i])
*** * **** * * * ** * ** * ** *
* * * * * *** * * * ** ** * **** ** * **** * ** ** * * *** 1;
***** ** *** *** * ***** ** ** ** * ********* * **** * * * * *
**** *** * ****** *** * *** * ** * * *******
*** ********** ** *** ** ******
** *** * * * *** * *** * ** 0;

}

int main(){
*** **** ** * * ** **** * * c[n],d[n],e[n];
* ** **** ** ** * * i;
** * * ** *** *** * * ******* %s",c,d);

* * ** ** * ** *** ****
* * *** * * ***** ***** * **** ** *** ** * * *** * is a prefix of %s",c,d);

** * ** * * *******
** * *** ** * * *** ** * ** * **** ** *** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.157
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 9.4k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.2k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 9.5k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.4k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users