Final Exam 2 (20%)

1 like 0 dislike
7.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 7.2k views

37 Answers

0 like 0 dislike 
Hidden content!
#include  * ** *  * * 
#include  ***   *  ****
  **     ********  *   
 *     ***** * **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ***   * **** *

***  *  *  *  **** * * **** **  * 
 ** *    ***** ** ** *****  * == b[i]){
   **  ***** * **   ****   * * **     *** **  **   **** ****  *  
   ******* **  ***   ** * ** *

 *     * * *  *  
if (cnt == n){
 *   * * * ****   ***      ****   **  **** *  ***  ** * 1;
*     **  * *** **  * ********  ** ***** *   **  *** 
* *  * **********    ** *** ** 
*** * ****** ** ****  **  * **  *    *    ***    * ***  0;

}

int main()
{
* ****   * *  **  *     s1[100], s2[100];
*** **  ** * * ***  * ** i,j;

  **          ***    * ***   *  *   *   s1);
* * * ** *  ****    *** ** ****** *  * *     s2);
*    **  * * *    * **     (prefix(s1, s2)){

*    *   *   *** ** *   *   ******   * * ** **   * * ** * * is a prefix of %s", s1,s2);
 * *  * * * * * **   * * ** * ** ** **** *** * *
    ***   *  *** *  **** *** *   ** *  **  ********
**      **    ******  ******* ***   ** * *  * * *  ** * * * *   ****   *   is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
 ***  ****   * *** * **   c;
   *  *** * * ** * * * **  a[100],b[100];
  * *  *   *   *  ***     * * ** *     ***** * %s",a,b);
 ********* *  *   *     * **  * *    ** 
  ** ********* *** * * *    *  ****   * * *      **  *     0;
****   *******  ** * ******* ***       ****  %d",strlen(a),strlen(b));
*  **   ***      * * * * * *  *****  **  *  **
*  **** *      *** *  * ***  **  *  **  **  *  *  * *   * ***  ****  *****  *** *******
* ** **  *  **** * **   *** ** ***    *  * *     **  *  * * * ***   **  *     ***  ******   * * **  *     * is not a prefix of %s",a,b);
* ****  ****   * ** * ******** *   ***      ** ** **  * *  ***     *      * **  **        *   *** * ****  * * *
      *  *     **   ** **       **** ****  ***    * * *******  *** *     * *   * *
    ********    ** *  ****    ** ** *  * ****** *** * ******* *****   ** ** * * *  * if(c==strlen(a)-1)
*   **  ** * ***   *  **   *  ***  * **** **  * * ** *  *** * * * **  *  ********  * ******  *   **     ** *  * ****    * is a prefix of %s",a,b);
    }
* * *       **    **  **      0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*    ****  ***   *** ** *** * n,count;
    ***  *** **** * **** * * * *   *** *****   ** *   
  *******  *       * ****   *    * ****   %s",a,b);
 * ** ***  *   * *  ** **  * ***   ***  

 **  *  *  * *   *    *** * *  **      ** 
* *    * *    **    * ** 
  ** **   **  * *   *  * * * * * **** **        **          **   *
*  ** *   ****** *** * ** ***   *

***********    ***  * * ** *  *  (strcmp(a,c)==0)
 ** * * *  * ***  *   
* ***  ****  * *  **  *  *  *  * * **    * *  *      * ***  ***  ***  * * is a prefix of %s",a,b);
** ****  ** *  * ****   ***
** ***    * *   * *  ***  * 
**     *  * * **   ****  * ** 
 * * * * ***   * * **  *   ** ***    * *  ** *  *  *  **  * *****  **** * * **** is not a prefix of %s",a,b);
   **  * **  ***  ** ** **  **
    ***   ** * **    * * *     0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** *  * ** **  *     *   * * * a[100],b[100];
*  * ** * ** **     *  **   *** ***      *     ***
    int l1,l2;
 * *  * *******     * *  *    *
*    *  * * ****   * *  *  ***   * ** *  
 *  ** * * ***   *     **  ** ***  **    **  
   *  ***     ***  ** ** *  **  **  * * * **** * **   *     ** **** is not a prefix of %s",a,b);

    }
* ***       * * ***  ***  *** * if(l1<=l2){
 * **  ** *    **  ****    * ** * ***   **   **  * prefix=1;
*     * * *   *   ****** * *   *   *     *** * *     * *  i=0;
  **   *   *  **    *     ***   **  ** *  * *  ** **   * * * *  * ***  
****  *     **  ** *  *  ******   *     * *******  *  ** * *** * * ** *   ***  (a[i]!=b[i]){
      * *    *   ***   ** **** *    ***    *  ******  * *** * ****    * *   * *   *   ***   ** * *** ******  **    
* ******  *  *  **      ***   * ** * *** ****      ***   **   * *         *   * ** **** *  ****  **  *** ** * *** ** 
 *    *   * *  **  *  * *    * **  *****   * *** * *     *   * *** * ***  ** *** 


* **    ** * *  ** * *****  **    **   ***    *  ***  *
***  **  * **  ** ****** *** *  * *  *  ** **         ***  **   * **
***   *   *  ***  *    *  *   ****   *   *  *   *  ****      **** **  * **    *  **  *   * *      is not a prefix of %s",a,b);
****    *    *  * * * *   *******  **  * **  *  *    * *****
   *    *   ** *   * *   * **   ** ** * *  *    * 
 *** ** *** ** **** ** ***   **      * *** *******  * **** *  * *** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
   ******  *** ** *   * 
int main(void)
{

*** **    *  **  *  *  ** **   **  pre[100];
* *** * * *     **     *  ** ** word[100];
*  ** *      *** *   * *** *   **    *  %s",pre,word);
  *  ** ** * ***    *** * *  * ** *****    
* *** ***** *   **   * *****  * *       ****** *

   * *** ** * * * *** * * * * ** i;
**   * *  *     ***    *** * ** * ******  ** *  ** 
  *****  **    * * *  ** * **
 * *  * **  *  **  *** * *    ** *      * *     **   *** *    * **   *
 **   ***  *    *   **  *  *** *** *** **  * ****
      *   * * **  *** ****    *   *****     * * *   * * *      *     * * *  **** ** *   is not a prefix of %s",pre,word);
*  *   ** **   * *  * **  * *** *  *  ** **   **   * *  ** *  *** *  * * * 0;
*  *** *  ***  *  * ** ** *   * ***     ********* 

*** *  *   ** *** ***  * *** ** 
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
 ****  ** ******  **  ***  pre [100],a[100];
 *  *     * *  *** *   **  n ,i;
   *   ** * **   *****  * ****   * **** 
* **   * **  ** * ***** *   **  **   *    *
** ** **** *  **   **   * *     * **** * ** 
* ** *****  **  * *       *
** ***   * **** ** **   **  * * *** ** * **   *  *    (n=0;n<strlen(pre);n++)
** ** * * ****  ** ** ** ****** ****  * **** ** * * **
****   *  * * *  ** *   *** *             **  *    * ** ** **  *  *** *     *** *  (pre[n]==a[n])
  ******    **** * ** *  ****  ****  * **  ** * * * *     **   *  * **** ***     *  *** *  is a prefix of %s",pre,a);
** ***  *    **** * *  * ** **   * *   ** **    *** ***** **      * *  *   ** 
* * ** *** * ************  * *  *  * *  ** **   * * * ***    * * ***** *  ** *  ***  *  ** * * *    * ***** * * *   *** *****    ** is not a prefix of %s",pre,a);return 0;
* **** *  ** * ** ****     * 
**** * * *  * *   *** * * ***    **    * * **** *  ** *      * *    **     *

* * **   * **    * * ***** * *   0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  * *   ******* * 
#include  *  ** ***   

int main()
{
** * **   *  ** * **  ***  ** *** a[100];

** ****** * * ** **** * ***** *  b[100];

**    *** *  ** ** * ** * * *  *  *   %s", a, b);

* ** ***     *   **** **** len_a = strlen(a);

* *****   *   * * * * **** * * i = 0;

** * * *  * * * *** ** **   **  flag = 1;

 ****  ***      ** * ***  *    = 0; i < len_a; i++)
  *** ****  *********  * *** 
**  *  *   * * ** ** *  * ***  *  * *  ***   ** * **     != b[i])
   ** ***    *  **  * *      *  * *      * ** *   *   
*  * * * ***  * *****  * ******** * ** * **  ** **  **  ****  ***  *  ***  *  * *  * = 0;
  *     **    ***** *  ********  *  **   ** * *  * ***  
***  *   * **   ***** *** 

  * *** * **** ** * * ***    * *   == 0)
    * *   **** *    *  * * * *
*  * * * * * ** * * ***  * * * ****  *     **  * * *** ****  is not a prefix of %s", a, b);
**  * *  *  * ***     **  **
* **  **  * **** ** * *   ** **
 *   *****       *     *
** * ** *  **  *  *  **** * ****  *** *  ***   *  ** ***  **  **     is a prefix of %s", a, b);
  ***** ***** * **   *
*  * **    ***  *****   * * **   0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
** ** **  * *  **   * 
int main()
{
 * *    ** **      *        i,n;
  *   * *  * *  *** * ** * * p[100],s[100],a[100]={};
** * * ** *    *  * ** ***  * ** %s",p,s);
  *** *  * *  *    *  *     ** * *
* ***     ****** * *** * *****  ****  * *
 * *********   **   *** *****  **  *   **  * ******
***  ***   *   * *** *   ***  *    **** ** *  
*   **  *    ***** *    *  * *  *** ** * ** ** ***         ****     **   is a prefix of %s",p,s);
 ******* **   ***  *** *  
** *   * ***********  * ** *
**  **  *    *  ******** **** *  * ** *****    * *  **     *  * ** * is not a prefix of %s",p,s);
****  ***   ****  ***** * * *  ** 
 *  * *  ******* * **  *       * *  ** * * *** ** *   **     *    
 * *   ***   ******    *  * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
*  * *   *  ****** * *  **    * *  ***  ******** *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
**** *  *  *** *  ** *     *    *  *** * * *** *   
*     *****  * ***  *  * ** *   *    *  * *  **   *   * ****  **   * *** ** * *    != b[i])
******** *   * ** *      ** *  ***  ** * **   **   ** **     *  *   ****** *** * ** ** * * *  ***** *  *****   *  ** 
 ***  ***     **  * ******   * * *** * ***  * **** * **  ** ***    *****     ******** * *   *      * *  * *  *  *** * ** * *  * *   ** ***   is not a prefix of %s",a,b);
***** * **  *** *****  **     ** *** ** ** ** *   *  **       * *   *    *** *  * * *  * ***** ** ***** *** *  * ** ******* 
  ***  * ** *   *  **    ** * *      ** * **  ** *  *  *  * * ** **    *         * *    * *** *    ***  * ****
* * *  *  *  *  *  **  *  * ***  **   ** *     *  *    ** * **  * *   ***  **  **  ***   **    *   * == b[strlen(a)-1])
  **    **  **  *   * ** ***   *     ***   * * **   ** ***  ****  *   ****  **   * ***     * ** * ** **    **  *   *
      *** **  *   *    **  *      *** * *** *****  *  * * * * **  * *** *  * ***     **  **   * * *   **      * *  **   *  **   * ** *    * is a prefix of %s",a,b);
* * **  * ****  * ***       ***   ** * *    * *  * ** **** *** * *   *  *   **** *  ****   * * *** ** *  **  * *** ** ** *       * ** * *  **
 *  *******  *** **  *  ** *  **   *      **      * ****  ** ***** **  * *   ** * *   ***** *
 ** * *    * ** *  * **** *******    ******* ****** * *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
*    *      **  ***    * *  *** * i;
 *  * *  * * * *  **** **  * ** *** (a[0]!=b[0]){
  *   *     * * **** ** ****** *  *  * *****  **     * * 0;
   * * ** *   ** *  ** **   ****
****  ** * * * *   **   * *  ***   **    ** *  **  * *
** **   *  * *  **  **   ** * *   *  * * * ** *  *****  ** **** * a[i]==b[i])
 **** *  *  **  *      *    ** **    *  *  *   *** * *   
    ** ***** *   *  **  *    ** * * * *      ** * *****  *  ***   * *** *   *** * 1;
** *    *          *   ** **  ***** * ** ******** ** ***     * *  ** *  *** ** * *****
** *** ** ****   *  ***  *   ****  ***  **   **  * *  *   
** * * *  * ** ******     * *  ****
 *  *  ****  *  * *** * *  ** ***  * **** 0;

}

int main(){
**     ** * **  **** *     * *  c[n],d[n],e[n];
*** ******   * *  * *   * ***  i;
   ** **   *** *   *   *   * * *    **** %s",c,d);

  *    ****   *** ***      
    *    ***** * *** *  *********  *** ** *    **  *  * *  * * **  **     * is a prefix of %s",c,d);

 * ** ** *  *   * * **   *   *** 
    * * ** *  ****  *   * *    *   **    *      *** * * ** * **** **    is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.210
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.5k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 6.5k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.5k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 5.8k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 1.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users