1 like 0 dislike
13k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 13k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** ****
#include ** ***** ** *
*** * * ** ** *
***** ** * *** **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** ** * ** *

*** *** ** * *** *** *** * *
* * ** * * *********** *** == b[i]){
** * *** * **** * ** **** * ** ** ** * *
*** *** *** * * **** ***

** * * * * ** ** ** *
if (cnt == n){
** *** ** * * *** ********* * ** * * *** ****** * * * 1;
** * ** * **** **** * *** ** * ** *
*** * **** ******* * * *
* * * *** **** * *** *** * *** *** *** *** ** 0;

}

int main()
{
* ** ******* ** s1[100], s2[100];
** ** * * ** * *** * i,j;

***** * * *** * * * ** * * s1);
* * * * *** *** * * * *** * ** s2);
* *** * * * * * (prefix(s1, s2)){

* * ** **** ****** ** * * ** ** *** * ***** is a prefix of %s", s1,s2);
** * ** *** * *** * *** * * * ***
** * * ** **** ** * *** ** *** *
* *** * ** *** ** * * **** * * **** * * * ** ** *** * * * * ** **** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * * * ** **** *** ** * c;
* * *** * * * * ** * ** *** a[100],b[100];
* ** *** * * * * ** *** ** * ** * %s",a,b);
*** ** * * ****** * * *** * * * *
*** * * ** ** **** ***** * * ** * * **** * * * 0;
* * **** *** * * ******** ** ***** **** ** %d",strlen(a),strlen(b));
**** * * * * * * * ***** * *** ** *
* * *** ** ** ** ** * *** * * * * ** ******** ** * * ** ** ***
*** *** ***** ** * * ** * ** ** * ******** ** ** * * ** * * ** * * * * ** ***** * is not a prefix of %s",a,b);
* * * **** ** *** * * * **** * * * * * * ** * **** * *** * ** * ********* * *** ***
** * ** * **** ** ** * **** * ** * ****** * **** * ***
* * * *** *** * * ** * ** * * * * * * * * **** * **** ** if(c==strlen(a)-1)
* *** * * ** * ** * ** ** * ******* ** * * * * * * ** * * * * ** **** ****** * ***** is a prefix of %s",a,b);
    }
* * * ******* ** * * ** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** * ** ** *** ** ** n,count;
*** * ***** ** * *** * * **** ***** * *
* * * *** * ** * ** * *** * %s",a,b);
*** ** *** ** ****** ** ** * *

* * * * * * **** * ** * *** * ** * *** **
* **** ** * *** * *
* ** * ***** *** * * *** * * * *** * ** * * *
** **** *** ** * * * ****

* ** * * * * (strcmp(a,c)==0)
** ***** ** *** **** ***** *
* * * * ***** ** ** *** **** * ** **** * ** * * * is a prefix of %s",a,b);
* * * ** ** ***
*** * * * ** * * * *
* * *** ** * * * * **
*** ***** * *** *** ** ** * *** ** * * *** *** * * is not a prefix of %s",a,b);
** * ***** * * * *
* *** ***** **** ** * * * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** * *** *** ***** * *** *** a[100],b[100];
** * ** **** *** **** * * ** * ** * ****** * *** *
    int l1,l2;
* * * * * ** * *** * ***
* * ** * ** * * * * *
** * * * * *** * ** * ***
** ***** ** * * *** * * * * ****** * ** ** * is not a prefix of %s",a,b);

    }
***** * ****** if(l1<=l2){
* * **** * * * * * ** * ** ** * **** * **** * ***** * * prefix=1;
* ** * ** **** * *** * * **** ** * * * ** i=0;
**** *** ****** * * *** * ** ** ** *** ** ** * * * ** *
** * *** *** ** * * * **** *** * * * *** ** ** ** *** ** (a[i]!=b[i]){
** * * ** ** ** * * **** * ** *** ****** * ** * * *** * * * * ** * * *** ** *
**** ** * **** ** * * ***** * **** * * ** * * * * * * *** * ** ** *** * * * * ** **** * ***** *
** * * ** * * ** ****** * *********** * ** ** ** * * * **


**** * * * *** ** * ** **** *** *** *** * ***
*** *** * * ** * * ** * * * * * * * * *** ***** **
**** * ** * * * * **** ** * *********** * * * *** * * * * ** * ***** is not a prefix of %s",a,b);
** **** ** *** * *** * * *** * * ** *
* * **** *** * **** * ** *** * *** **** *
* **** * * * * * * ** * **** ***** * * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** **** *** * *
int main(void)
{

** * * * * * * * * * *** pre[100];
* * * * * * * * * word[100];
** **** * * * ** *** * ** * * %s",pre,word);
** * * **** ** **** * *
*** * * ** * *** **** ** * *

*** * * *** * *** ** * i;
* **** * ** * *** *** * ** * ** ** *
**** *** *** ** ** *
* * * ** * * *** * **** * ** * ** * * ** *
** * * * * ** **** ** ** ** * ** * * ** ** * * *
** * *** * **** **** **** * *** *** ** * ****** ** * ***** ** * *** * ***** * ** is not a prefix of %s",pre,word);
** ***** ******** ** ** ** ** *** ** * ** **** * * *** ** * * * **** * * * 0;
* ** * ** *** ***** ** * * * * ***** * ** ** **

* *** * * **** **
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** ** * * *** * ** ** ** pre [100],a[100];
* * *** * **** ** ***** n ,i;
* ** * ** * **** *** **** *
* **** *** ** ** * *** * * *
* ** * * * ** * *** ** * * ** * * ** * ****
*** ** * ***** ** * **
** * * * * * ** ** * * ** ***** ** * **** * (n=0;n<strlen(pre);n++)
** * * *** * ** * ****** * *** **
** *** * ** * * * * **** *** * * *** * ** * * ** ** * ** * * ** (pre[n]==a[n])
*** ***** ** * ** ** * ** * ** * * * * * * * * * ** ** * * is a prefix of %s",pre,a);
* * * * ** * ** ** * * ** * *** **** ** ******* *** *** ** ** *
* * * * ** * ******* ** *** *** *** * * * * **** * ** * * * **** * * * ***** * ** * * * * is not a prefix of %s",pre,a);return 0;
** ** * **** * ** *
** ** * ***** ** * * * ** **** * * * ***** * ****** * ** * **** *

* ** ** ** * * * * *** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * *** * ***
#include ** * ** * *

int main()
{
*** * * * *** * * *** * a[100];

**** * **** *** ** ** ** * b[100];

* *** *** ** * * * * *** *** %s", a, b);

* * ** ** * * * * len_a = strlen(a);

** * * * * * * ***** *** i = 0;

***** * *** ** ** flag = 1;

** * ** ** ** * ** * = 0; i < len_a; i++)
*** ** * * * *** * ****
*** ** * ** * ** **** * ****** * *** ** != b[i])
** ** ** * * *** ** ** ** ******* * * * * * **
** * **** * ****** * * * * ** * *** * ** * * * ** ** * = 0;
* ** * * ** ** ***** ** * ** * * *** ** **
** * ** * *

* * * ** ****** **** == 0)
* ** * * ******* *
* ** * * * **** *** * *** ** ** ** *** ** ** *** is not a prefix of %s", a, b);
* ** * * * * *
* **** * ** * * *
* ** ** * **** ******* *
* * * * ** * ** ******** * * * *** ** ***** ** * is a prefix of %s", a, b);
** ** ** * * *** ***
** **** * *** * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * * *** * * *
int main()
{
*** * * **** * **** * * * i,n;
**** *** * ** * * * ** *** *** p[100],s[100],a[100]={};
** ** ******* ** ****** *** ****** %s",p,s);
*** * * *** ******* * * ** ** *
** **** ** * * * * ***
* * * ****** * * *** * * * ****** *** **
* * * ** **** * ** **
* ** * * * * *** ** ** *** ** * *** * * * * *** *** is a prefix of %s",p,s);
**** * * * **
** * * * ** ** ****** * ****
********** ** ****** **** * * * **** ** *** *** *** ** is not a prefix of %s",p,s);
* *** * * ****** **
*** ** * * * * ****** * * * * * * *
* * * ** *** ** * * * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* ** * ** ** * **** * ** ** * *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* ** * * *** ** *** ** *** ** ** * *** *
* **** ** * *** * ** **** * *** * ** **** * * * * ** * * * * * ** ** * != b[i])
** * **** * *** * ******* * * * * * * * * *** * ** ** *** ** ** ** * *** * ** *
* ** * ** *** * * ** ** * * * * * * * ** * * ** *** * ** * *** * * * ******** *** *** ** * * * * is not a prefix of %s",a,b);
** ** * * *** ** * ** ** *** * *** * *** * ** **** * * * ** * ** ** ******* * * ** ****** **** * * ** ** **
*** * * ** * ** ** ** *** * ** * *** **** * * * ** * * * ** ****** *** * * **
* ** ** ** ** * ** * * * * * *** * * ****** * * *** ** * == b[strlen(a)-1])
* * ** ***** * * *** ***** ** * ** * ** * ****** **** *** *** ** ****** **** *
* * ** **** **** **** * ** * * * *** * ****** * * * **** * * * * * ** *** * * * ***** * ** * * * * ** ** * **** * ****** * is a prefix of %s",a,b);
***** * ** ** **** **** * ***** **** * ** * * * *** * * ***** *** * * ***** ** * * ** * **** * * ** ****
* ** ** * ** ********** **** * * * * * ** ** **** *** ** ** *** *** * * * * * * ***
* *** * * **** * ** *** ****** * * ** * *****
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
*** * * ** * ** * **** i;
** **** ** ** ** ** * *** ** ***** (a[0]!=b[0]){
*** * *** * ** ** ******* * *** *** * * * * 0;
** * * * * * *** * ** ** ** * **
* * * ** * * * **** ** ** **** * ** *
* * * ** ** * ***** *** ** ****** ***** * * **** * a[i]==b[i])
* ** ** ** **** * *** * * ****** ** ** ** * **
** * *** * ** * * ** * * ** * ** * **** * ** *** *** * * *** ** * 1;
* * * ** ** ***** * **** ** *** * * ** * ** * *** * ** *
** * * ** * *** * ** ** ** * *** *** *** * * **
* *** * ******* ** ***** ** ****** **
** * ** ** ** * * ** * * 0;

}

int main(){
* * * ** *** ** *** c[n],d[n],e[n];
* ** * * ** * * i;
*** * * **** * ** ** ********* *** %s",c,d);

** * * ** ** ***** * *** **
* ** ******* * *** * ** ** ** * * ** ** ** * **** is a prefix of %s",c,d);

* ** * *** ** * *
** *** **** *** * **** * * **** **** * ** ** * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.197
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.6k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.6k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.4k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.3k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users